Stainless Steel Rat wrote:
> * Magic <[EMAIL PROTECTED]> on Thu, 14 Oct 1999
> | No, the LSB gets dropped and you still end up with a signal that will not
> | overflow the register. All that happens is you lose the extra 1 bit
> | resolution from the LSB end.
>
> And this is significantly different from "clipping" in what way? Loss of
> data is loss of data, no matter how you try to spin it.
Clipping is when the value is too high for representation and so it gets squared
off. Feeding a 17bit number into a 16 bit register wont clip it, it truncates it.
The difference is no squaring off of the signal, you just loose a small amount of
resolution.
--
Magic
Location : Portsmouth, England, UK
Homepage : http://www.mattnet.freeserve.co.uk
EMail : mailto:[EMAIL PROTECTED]
"A book judged by it's cover makes for a very shallow read."
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