400 Bad Request when URL contains %
Hi bakers! :-) I'm pretty surprised I haven't come across this one before. The following URL generated by the pagination helper causes a 400 Bad Request response: http://localhost/projects/jisc_pims_19/outputs/index/page:2/find:a% Remove the '%' from the URL and its all fine If you change the url to http://localhost/projects/jisc_pims_19/% or http://localhost/projects/jisc_pims_19/programmes/view/% you also get a bad request. The following URL works as expected: http://localhost/projects/jisc_pims_19/outputs?find=a%25 I've check back to a bunch of other CakePHP apps I've written and they all exhibit the same behaviour :-( After a bit more of a dig, it seems most CakePHP sites suffer the same problem too: http://cheesecake-photoblog.org/demo/view/% http://overheard.it/people/% http://snook.ca/archives/cakephp/% How do I (and everyone else) fix this? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: isn't a form in the view supposed to find the correct action?
Sindey, Marcelo is right. The default action for a form is to post to
the $controller-add() method. You have to override it for other
actions
On Feb 18, 12:00 am, Sidney aussiealthomp...@gmail.com wrote:
I think the default action is to self-post i.e. the form post/get goes
to the same controller/action that served the view with the form on
it. This is a normal design convention and seems logical to me
(although quite a noob myself). Perhaps I misunderstand your question?
On Feb 17, 8:01 am, Marcelo Andrade mfandr...@gmail.com wrote:
Hi there,
By the CakePHP conventions, the view's name must be the same
as an action in a controller. A common mistake for the newbies is
when creating a form in the view is that the
echo $form-create('MyModel');
defaults to generate a form for the add action. But I think that
should be more intuitive that it's defaults to the action with the
same name as the view. Isn' it?
Best regards.
--
MARCELO DE F. ANDRADE (aka eleKtron)
Belem, PA, Amazonia, Brazil
Linux User #221105
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Re: EasySoft MS SQL Drive with unixODBC
I'd start with a blank (non-cake) php page and try and get that working to make sure your odbc driver is set up correctly. Haven't used ODBC with cake but I can tell you the Easysoft stuff is very good (caveat: I used to work at Easysoft :-) ) On Feb 12, 4:37 pm, Stinkbug justink...@gmail.com wrote: We're trying to connect to sql server and we've installed the EasySoft MS SQL Driver and I'm told that the connection is working (I'm not the one that installed it and test it), but we can't get it to work in Cake. Has anyone tried using this driver and if so, what did you have to do to get it to work? Our database config looks something like this. var $webserver = array( 'driver' = 'odbc', 'connect' = 'webserver', 'persistent' = false, 'host' = 'webserver', 'login' = 'saweb', 'password' = '54web', 'database' = 'webserver', 'prefix' = '', ); --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: deprecation of useful functions
You could always add your own wrappers to your AppModel :-) On Feb 16, 3:52 pm, leo ponton@gmail.com wrote: I could never remember the order of the many many arguments to find and had to look them up at least once a day. Putting them info an associative array helps me a lot because I don't have to remember pointless index-numbers. I have the same problem the new way round. The associative array is good, but too often the documentation in the API lists options. What options? And when it actually tells you what they are, they're not necessarily all there, as with neighbours (in its non-English version of the spelling, neighbors). Also, I suffer bracket-and-comma blindness, so when I see more than one consecutive array, I can't see whether or not it is nested. I shouldn't have to delve into the code to find the correct args. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Catching PHP/MySQL errors with query()
Hi All :-)
How do you trap errors that may be the result of a custom query? For
example:
$results = $model-query($sql);
In my case, some of the custom sql queries creates such a large
dataset that the script exceeds the memory allocated to php.
I would like to catch these errors and present something a bit more
friendly to the user.
I've tried wrapping the code in a try/catch block as I would normally
do:
try {
$results = $model-query($sql);
}
catch (Exception $e) {
// handle error here
}
but the error is still raised and the try/catch is ignored.
While trying out this approach I noticed that if I do:
try {
echo 1/0; // generate a divide be zero error to test
}
catch (Exception $e) {
// handle error here
}
The error message is still displayed! I'm guessing that CakePHP is
already trapping these errors, so ultimately my question is:
How do I stop Cake from trapping errors so I can use my own error
handler, and how do I re-enable Cake error handling after the bit of
code I want to check has finished?
Thanks in advance.
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Re: how to set css for internet explorer
Conditional comments are the way forward. The user agent can be spoofed. On Feb 13, 11:37 am, Marcelo Andrade mfandr...@gmail.com wrote: On Fri, Feb 13, 2009 at 7:17 AM, mona poojapinj...@gmail.com wrote: hi viewers i have one serious problem i have to set the page layout in such a way that my website should perfectly viewed in internet explorer . It is working fine in firefox but in IE it is not so can anybody tell me how to call two different css for two different browsers or any other solution for that so that is should be correctly displayed in internet explorer With PHP, you can check the browser using the user agent in the $_SERVER superglobal variable[1]. In another way, you can use css hacks for IE ou even the conditional comments[2]. [1]http://php.about.com/od/learnphp/p/http_user_agent.htm [2]http://haslayout.net/condcom Best regards. -- MARCELO DE F. ANDRADE (aka eleKtron) Belem, PA, Amazonia, Brazil Linux User #221105 [...@pará ~]# linkshttp://pa.slackwarebrasil.org/ --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: DebugKit plugin: not available for Windows users?
Another vote here for Chaw needing a download link! On Feb 6, 7:43 pm, Matt Curry m...@mcurry.net wrote: The Git link Brandon referenced does work once you get everything setup. I did it yesterday so I could download the API Plugin. It would be nice if TheChaw had a download link like GitHub. I assume it's forthcoming. Most of the changes from my forked version have been merged back into the official one. I think the last few will be added eventually. I probably won't keep my version up to date after that, but right now it should be *relatively* close to the official one. -Matthttp://www.pseudocoder.com On Feb 6, 1:56 pm, BrendonKoz brendon...@hotmail.com wrote: Git installer for Windows:http://code.google.com/p/msysgit/ Allows you to run Git from the Windows' command line. There's probably another way to get access to it as well, but I'm not really familiar with Git or TheChaw. Matt Curry's forked version (pseudocoder.com) is on GitHub which offers a download, but I'd highly recommend sticking with the official source, I only mention this as a possible temporary alternative until you can get access to the real source. On Feb 6, 11:48 am, rcurzon s...@interlog.com wrote: I guess it would work fine in Windows... but you can't get it without git... which isn't ready for Windows? Let me know if I missed something please! -R --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Quick Question about Chaw
I think the Chaw repository is an excellent idea. Are there plans to include a download link? If don't have SVN or GIT set up, how do I download projects? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: ERD recommendation
I've been using MySQL Workbench. Does everything I need. http://dev.mysql.com/workbench/ On Feb 4, 7:13 am, Wayne Fay wayne...@gmail.com wrote: I was wondering if anyone has any recommendations for a database design tool. I was hoping to use an OSS product. I generally use Squirrel SQL, or a DB editor in Eclipse/Netbeans IDE which can connect to any database that has a JDBC driver. For postgres, I also use pgAdmin. This page has more info about pg-specific tools:http://postgresql.openmirrors.org/docs/techdocs-9.html Wayne --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Use the dreaded requestAction()... or use something else?
Request action isn't *that* bad ;-)
In this case request action should be fine as you wont be calling it
very often (as opposed to say from in an element that is displayed on
every page).
That said, Graham's suggestion is a better solution.
Note, to get the best performance from requestAction you should use
the following syntax:
$this-requestAction(array(controller=sites, action=add));
On Feb 2, 12:14 pm, Turgs timb@gmail.com wrote:
Hello all
What's an appropriate use of requestAction()?
I have 3 controllers:
* UsersController
* SiteController
* SitePagesController
Within the add() function of UsersController, I want to (a) create a
new user (b) create a new site for that user with (c) one new page for
that site.
What's the best way to do this?
I was thinking of:
##
if ($this-User-save($this-data))
{
# create site
$this-requestAction('/sites/add');
# add a page (homepage) for this site
$this-requestAction('/sitepages/add');
# Login the user and redirect to the dashboard
// login code here
$this-Session-setFlash(SOTF_MSG_USER_WELCOME);
$this-redirect(array('controller' = 'users' ,'action' =
'dashboard'));
}
##
While the code for this looks clean, what I've read seems to indicate
this isn't such a good idea due to performance issues.
What else would I do?
Thanks
Turgs
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Re: $form-dateTime() field name breaks with 4 or more levels
Found the solution. Documenting it here in case anyone else stumbles
into this issue:
You need to use an alternative format to specify the model/field
names:
? echo $form-dateTime([a][b][c][d]) ?
Thanks to the person on IRC who hinted at this solution :-)
On Jan 24, 4:17 pm, RichardAtHome richardath...@gmail.com wrote:
Hate to do this, but... Bump!
Is this a bug in CakePHP (I'd be surprised if it was as I can't fault
the rest of CakePHP's code) or expected behaviour?
On Jan 23, 3:39 pm, RichardAtHome richardath...@gmail.com wrote:
Hi all
I've hit a snag I'm hoping someone can help with. Perhaps one of the
devs can explain this behaviour?
? echo $form-dateTime(a.b.c) ?
generates (as expected):
select name=data[a][b][c][day] id=abCDay...
whereas:
? echo $form-dateTime(a.b.c.d) ?
generates:
select name=data[a] id=a...
and
? echo $form-dateTime(a.b.c.d.e) ?
generates
select name=data[] id=...
Unfortunately, I'm building a dynamic search form and my code needs 4
levels:
$form-dateTime({$model}.nextIndex.{$field_id}.value, DMY, NONE)
(nextIndex is replaced with a number at runtime)
I've just tried this with a basic text field ?echo $form-text
(a.b.c.d.e) ? and got the same results as above.
What do I do?
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Re: Calling $html-css() from inside an element
If the element is being rendered in the layout, why not add the $html- css to the header as normal in the layout? Is the element optional in the layout? ie. is it only displayed on some pages and not others? If so, I think the minor overhead of including the CSS on every page (and therefore cached by the browser) would outway the overhead of using an additional helper. On Jan 27, 2:58 pm, Gonzalo Servat gser...@gmail.com wrote: On Tue, Jan 27, 2009 at 12:51 PM, RichardAtHome richardath...@gmail.comwrote: Try it from a layout. ...but your question is about calling it from inside an element :-S ... or do you mean an element that's linked from a layout and not a view? Right! An element called from a layout that has a call to $html-css() in it (with inline set to false). Like I said, the way I fixed it was by creating a helper which I call from the element to add the custom CSS file and called from the layout inside the head/head section to print it out. - Gonzalo --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: twitter users?
Aye, I've noticed hashtags was missing a few posts too. On Jan 27, 8:55 am, p...@otaqui.com p...@otaqui.com wrote: I've found Hastags.org to be quite unreliable (going offline regularly, missing tagged posts, that kind of thing). Another option is just to search twitter itself: http://search.twitter.com/search?q=%23cakephp On Jan 27, 8:23 am, RichardAtHome richardath...@gmail.com wrote: There's also a #cakephp hashtag: http://hashtags.org/search?query=cakephpsubmit=Search On Jan 26, 5:42 pm, gerhardsletten gerhardslet...@gmail.com wrote: http://www.twitter.com/gerhardsletten A salty mix of cake, ez publish, triathlon, food and live. Code stuff mostly in english, but some norwegian now and than On Jan 25, 5:33 pm, Marcelo Andrade mfandr...@gmail.com wrote: http://twitter.com/mfandrade Mainly in portuguese. -- MARCELO DE F. ANDRADE (aka eleKtron) Belem, PA, Amazonia, Brazil Linux User #221105 [...@pará ~]# linkshttp://pa.slackwarebrasil.org/ For Libby's backstory be told on Losthttp://www.petitiononline.com/libby423/petition.html --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: CakePHP In A Subdirectory?
Did you reboot the web server yet. This sounds exactly like the issue I was having. Also, check your web server error log files just in case. On Jan 27, 7:56 am, leo ponton@gmail.com wrote: I tried doing phpinfo() from the index.php file and nothing was displayed Doesn't this ring any alarm bells? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: twitter users?
There's also a #cakephp hashtag: http://hashtags.org/search?query=cakephpsubmit=Search On Jan 26, 5:42 pm, gerhardsletten gerhardslet...@gmail.com wrote: http://www.twitter.com/gerhardsletten A salty mix of cake, ez publish, triathlon, food and live. Code stuff mostly in english, but some norwegian now and than On Jan 25, 5:33 pm, Marcelo Andrade mfandr...@gmail.com wrote: http://twitter.com/mfandrade Mainly in portuguese. -- MARCELO DE F. ANDRADE (aka eleKtron) Belem, PA, Amazonia, Brazil Linux User #221105 [...@pará ~]# linkshttp://pa.slackwarebrasil.org/ For Libby's backstory be told on Losthttp://www.petitiononline.com/libby423/petition.html --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Calling $html-css() from inside an element
Try it from a layout. ...but your question is about calling it from inside an element :-S ... or do you mean an element that's linked from a layout and not a view? On Jan 26, 2:19 pm, Gonzalo Servat gser...@gmail.com wrote: On Mon, Jan 26, 2009 at 12:17 PM, RichardAtHome richardath...@gmail.comwrote: Sorry AD7six, just tried it in an element and the code IS injected into the header: view.ctp ?php echo $this-element(test) ? elements\test.ctp ?php echo $html-css(test, array(), null, false) ? I'm using the latest stable build of Cake Try it from a layout. - Gonzalo --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: What is the advised way to call a function from another controller?
or you could put the function in your AppController
On Jan 27, 2:17 pm, leo ponton@gmail.com wrote:
I'm not suggesting this is the correct way to do it, but I would put
those methods in the model definitions to which they relate. Then they
are accessible from any controller that 'uses' that model in addition
to its own. Then you can say something like:
$organisations= $this-Person-Organisation-formData();
$genders = $this-Person-Gender-formData();
...and so on...
On Jan 27, 2:07 pm, WebbedIT p...@webbedit.co.uk wrote:
Are you sure a component would be correct for this as again the
CookBook states To access/use a model in a component is not generally
recommended and my __formData() functions are made to access models:
function formData() {
$organisations= $this-Person-Organisation-find('list', array(
'order'='Organisation.name ASC'
));
$this-set(compact('organisations'));
$users = $this-Person-User-find('list', array
('fields'='User.username'));
$this-set(compact('users'));
$ethnicities = $this-Person-Ethnicity-find('list', array(
'conditions'=array('Ethnicity.option_list_id'='13'),
'fields'=array('Ethnicity.value'),
'order'='Ethnicity.value ASC'
));
$this-set(compact('ethnicities'));
$sexualities = $this-Person-Sexuality-find('list', array(
'conditions'=array('Sexuality.option_list_id'='18'),
'fields'=array('Sexuality.value'),
'order'='Sexuality.value ASC'
));
$this-set(compact('sexualities'));
$religions = $this-Person-Religion-find('list', array(
'conditions'=array('Religion.option_list_id'='30'),
'fields'=array('Religion.value'),
'order'='Religion.value ASC'
));
$this-set(compact('religions'));
$genders = $this-Person-Gender-find('list', array(
'conditions'=array('Gender.option_list_id'='12'),
'fields'=array('Gender.value'),
'order'='Gender.value ASC'
));
$this-set(compact('genders'));
}
Also I would still have to create a lot of logic or duplicate
functions within the component so that the find calls were made via
the right associations, i.e. the above function would work fine when
the referencing controller was PeopleController but when called from
ClientController the find calls would have to start $this-Client-
Person... and from Staff $this-Staff-Person... etc.
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Re: CakePHP In A Subdirectory?
You also need to delete the contents off the app/tmp directory. Leave the file structure intact and just remove any files. This is rapidly becoming my stock answer :-S On Jan 26, 5:49 am, Paolo Stancato paolodo...@gmail.com wrote: Find .htaccess files (there are two) and add RewriteBase /myapp into mod_rewrite section. Regards 2009/1/26 inVINCable invinceable...@gmail.com: Hey all, Very simply question but cannot seem to find the answer. I have the directory structure and everything in tact in the normal way. However, on my server I put the entire structure in the /myapp folder in the document root. Now, everything is all mest up and there is no CSS and files are missing and such. Surely cake has a simple variable to reflect these changes? Any advice? I have already looked at the book and the bakery and have tried things but they have not worked, such as messing with the variables in the index.php file. I am using version 1.2 Thank you for any advice/pointers. Regards --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Performing a Query using a curdate as condition, help asap?
$this-Event-find('all',array(
'conditions' =array(
'event_category_id'=$catId,
'DATE(Event.event_date) getdate()'
),
'order'=array('Event.event_date ASC',
'Event.event_time ASC'
)
) ) ;
On Jan 26, 9:38 am, Martin Westin martin.westin...@gmail.com wrote:
There are lots of goodies you can use (for MySQL at least).
Datediff is my preferred comparison since it does not fail on leap-
years and things like that.
DATEDIFF(date1,date2) 0
- true or false
To construct modified versions of today I sometimes use Addate adn
Subdate
ADDDATE(CURDATE(), INTERVAL 4 HOUR)
- 2009-01-26 04:00:00
/Martin
On Jan 26, 12:53 am, Parris presid...@parrisstudios.com wrote:
Hi Everyone,
I am just trying to perform a simple query using cakephp. In the
conditions array I am trying to filter by dates. The results should be
all 'events' that will be today or greater (in other words, any date
in the future).
$this-Event-find('all',array( 'conditions' =array
('event_category_id'=$catId,'DATE(Event.event_date)'='getdate
()'),'order'=array('Event.event_date ASC','Event.event_time
ASC') ) ) ;
That is what i have so far. The first condition is just to filter by
category. The part I need help with is 'DATE
(Event.event_date)'='getdate()'). There are no errors. So i guess its
kind of working. Also how can i adjust 'today' by 4 hours ?
Thanks!
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Re: Calling $html-css() from inside an element
Syntax should be: echo $html-css( 'right_column', array( 'media' = 'screen' ), null, false ); On Jan 24, 6:45 pm, Gonzalo Servat gser...@gmail.com wrote: Hi All, I never had the need to do this, but I've come across a situation where it comes in handy. I'd like to add a stylesheet for inclusion in head/head from an element. This is because the element I'm including is called right_column.ctp and the CSS to-be-included modifies a few of the styles on the main page to accomodate for it. There are probably better ways of doing this, and I'd love to hear your suggestions and ways of doing this, but for the time being I'd like to find out why I can't include a stylesheet from an element. My code looks like this: $html-css( 'right_column', null, array( 'media' = 'screen' ), false ); I started looking into cake/libs/view/view.php and it looks like the layout is rendered before the elements which explains why it doesn't work ($this-__scripts is empty at the time that the layout is being rendered). Anyone? Thanks! Gonzalo --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: CakePHP In A Subdirectory?
Might be worth re-starting the (web) server. It fixed a 500 error I was getting a while back. Been fine every since (even after uploading source updates). On Jan 26, 1:38 pm, inVINCable invinceable...@gmail.com wrote: Hey, Ok, I found both of the .htacess files and added RewriteBase /myapp so my .htacess file looks like: IfModule mod_rewrite.c RewriteEngine on RewriteBase /myapp RewriteRule ^$ webroot/ [L] RewriteRule (.*) webroot/$1 [L] /IfModule I also deleted the cache (just the files) and now I am getting a 500 Internal Server Error. I have tried this both on my local machine and a live server and the same thing happens. Anyone know what I might be doing wrong? On Jan 25, 9:49 pm, Paolo Stancato paolodo...@gmail.com wrote: Find .htaccess files (there are two) and add RewriteBase /myapp into mod_rewrite section. Regards 2009/1/26 inVINCable invinceable...@gmail.com: Hey all, Very simply question but cannot seem to find the answer. I have the directory structure and everything in tact in the normal way. However, on my server I put the entire structure in the /myapp folder in the document root. Now, everything is all mest up and there is no CSS and files are missing and such. Surely cake has a simple variable to reflect these changes? Any advice? I have already looked at the book and the bakery and have tried things but they have not worked, such as messing with the variables in the index.php file. I am using version 1.2 Thank you for any advice/pointers. Regards --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Calling $html-css() from inside an element
Sorry AD7six, just tried it in an element and the code IS injected into the header: view.ctp ?php echo $this-element(test) ? elements\test.ctp ?php echo $html-css(test, array(), null, false) ? I'm using the latest stable build of Cake On Jan 26, 11:33 am, Gonzalo Servat gser...@gmail.com wrote: On Mon, Jan 26, 2009 at 9:24 AM, RichardAtHome richardath...@gmail.comwrote: Syntax should be: echo $html-css( 'right_column', array( 'media' = 'screen' ), null, false ); Not if you're using the last parameter as false. It just adds it to an array which later gets printed in the $scripts_for_layout section so there's no need to print it out. That wasn't the problem though. After speaking with AD7six, basically what happens is that the head scripts section is already processed by the time it gets to the elements in the layout so I can't use that array unless I want to re-work the order in which things are processed in CakePHP (which would surely break lots of other stuff). What I had to do was create a head helper (AD7six's suggestion) which I would call to add CSS (from the element) and later get the CSS (from the layout in the head section). If anyone wants to see an example of how to include a custom CSS file from an element, let me know and I'll do a quick blog on it. - Gonzalo --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Problem to use Ajax layout.
I think you'll need to post some code before anyone can help you with this... On Jan 27, 12:49 am, Mahesh Sutar maheshsuta...@gmail.com wrote: I am using ajax in ctp page to populate table. number of rows I am reading from text box and passing to view action I am able to get table structure, but Its overlapping on footer which is present in default layout. Any one has solution for this? Thanks in advance. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Problem with routing using Javascript's location.href
I'd wager its not your code, but CakePHP's security settings. In app/
config/core.php change
Configure::write('Security.level', 'high');
To
Configure::write('Security.level', 'low');
and see if that clears up the problem.
On Jan 27, 2:14 am, MichTex bill.cav...@gmail.com wrote:
I have been working for a number of months on an application using
CakePHP, and have for the most part found it to be a very congenial
development environment. However, for the last few weeks I've been
struggling with what looks to be some peculiar CakePHP behavior.
Basically, I am trying to implement keyboard shortcuts (hotkeys) using
simple Javascript event handling to capture keycodes, and then, via
the browser's location.href property, route the user to the
appropriate page. This approach works great most of the time. However,
there are a couple of users for whom this approach causes the browser
to route them to the login page rather than the desired page. I have
rummaged through hundreds of postings here in the CakePHP Google
group, and done dozens of Google searches through CakePHP
documentation and numerous relevant blogs, but so far have turned up
no clues to what the problem is.
Let me expand on the details a little bit:
-The application I am working on mostly provides a few basic screens
which present blocks of text followed either by simple forms, or by
sets of link-type or button-type navigation choices. This part of the
system works very well.
-Recently, the product director wanted me to add hotkeys to speed up
navigation. For example, in cases where the navigation consists of a
short list of choices, he wants the user to be able to type a single
digit associated with each choice. Thus, if there were 5 navigation
choices, numbered 1 to 5, the user could either use the mouse to click
on any of the 5 links for those choices, or type the individual digits
1 to 5 on the keyboard to select the corresponding link. In another
case, there is an informational screen with a big Next button at the
bottom. The product director wants the user to be able to go to the
next page either by clicking on the Next button with the mouse, or by
typing either the letter 'n' or a carriage return.
-In order to implement the hotkey idea, I wrote some CakePHP code to
generate simple Javascript to capture keycodes from keypress events,
and then execute for particular characters a Javascript line of the
form
location.href = 'http://mysite.com/controller/action/arg';
which would cause the browser to switch to the specified page. [I used
the Event class from the Prototype Javascript library together with
CakePHP's Javascript Helper. I've attached an example of the kind of
Javascript that gets generated to the end of this posting.]
-When I wrote the hotkey-handling code several weeks ago, it appeared
to work fine. In fact, it continues to work perfectly for me. Here's
where it gets weird, though. About 90% of the time, when the product
director himself tries a hotkey, he ends up on a login screen, as if
he had been logged out. However, if he hits the back button, and then
uses the mouse to make a choice on the screen he had been on, that
works fine. So, he had not in fact been logged out.
-The product director has so far tried this with 3 different browsers
(IE, Firefox and Chrome) on 5 different machines in 2 different
locations, and gotten the same bad behavior in roughly the same 90/10
bad/good behavior split. There are two other people involved with this
project, as well. For one of them, like me, the hotkeys have never
failed, while for the other user hotkey navigation has almost always
worked, but has in fact failed a few times.
So, can anyone provide some insight into this situation? Is there any
reason why routing to a CakePHP page using Javascript's location.href
should always work for some users, most of the time for other users,
and rarely for yet others? Is there an alternative way to route to a
CakePHP page from Javascript? Or is there some other way to implement
a hotkey capability?
Thanks in advance for any help or advice you can give.
BillCavnar
-
Example of the generated Javascript code for handling hotkeys:
script type=text/javascript src=/js/prototype.js/script
script type=text/javascript
//![CDATA[
Event.observe(window, 'load', function() {
Event.observe(document, 'keypress', function(e){
var code;
if (!e) {
var e = window.event;
}
if (e.keyCode) {
code = e.keyCode;
} else if (e.which) {
code = e.which;
}
var character = String.fromCharCode(code);
switch(character) {
case '1':
location.href = 'http://http://mysite.com/worksheet/
show_answer/1';
break;
case '2':
location.href = 'http://http://mysite.com/worksheet/
show_answer/2';
break;
case '3':
location.href =
Re: $form-dateTime() field name breaks with 4 or more levels
Hate to do this, but... Bump!
Is this a bug in CakePHP (I'd be surprised if it was as I can't fault
the rest of CakePHP's code) or expected behaviour?
On Jan 23, 3:39 pm, RichardAtHome richardath...@gmail.com wrote:
Hi all
I've hit a snag I'm hoping someone can help with. Perhaps one of the
devs can explain this behaviour?
? echo $form-dateTime(a.b.c) ?
generates (as expected):
select name=data[a][b][c][day] id=abCDay...
whereas:
? echo $form-dateTime(a.b.c.d) ?
generates:
select name=data[a] id=a...
and
? echo $form-dateTime(a.b.c.d.e) ?
generates
select name=data[] id=...
Unfortunately, I'm building a dynamic search form and my code needs 4
levels:
$form-dateTime({$model}.nextIndex.{$field_id}.value, DMY, NONE)
(nextIndex is replaced with a number at runtime)
I've just tried this with a basic text field ?echo $form-text
(a.b.c.d.e) ? and got the same results as above.
What do I do?
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$form-dateTime() field name breaks with 4 or more levels
Hi all
I've hit a snag I'm hoping someone can help with. Perhaps one of the
devs can explain this behaviour?
? echo $form-dateTime(a.b.c) ?
generates (as expected):
select name=data[a][b][c][day] id=abCDay...
whereas:
? echo $form-dateTime(a.b.c.d) ?
generates:
select name=data[a] id=a...
and
? echo $form-dateTime(a.b.c.d.e) ?
generates
select name=data[] id=...
Unfortunately, I'm building a dynamic search form and my code needs 4
levels:
$form-dateTime({$model}.nextIndex.{$field_id}.value, DMY, NONE)
(nextIndex is replaced with a number at runtime)
I've just tried this with a basic text field ?echo $form-text
(a.b.c.d.e) ? and got the same results as above.
What do I do?
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Re: Fatal error: CakePHP core could not be found
You will need to clear our the files in your app/tmp directory. Leave the directories intact, just remove the files. On Jan 23, 1:42 pm, Mono sirmonit...@gmail.com wrote: Hello!! My Cake-App works perfect on my localhost, but after i uploaded it i become the error msg: Warning: Failed opening 'cake/bootstrap.php' for inclusion (include_path='/mnt/web2/13/38/51150638/htdocs/plPATH_SEPARATOR/mnt/ web2/13/38/51150638/htdocs/pl/app/PATH_SEPARATOR.:') in /mnt/ web2/13/38/51150638/htdocs/pl/app/webroot/index.php on line 84 Fatal error: CakePHP core could not be found. Check the value of CAKE_CORE_INCLUDE_PATH in APP/webroot/index.php. It should point to the directory containing your /cake core directory and your /vendors root directory. in /mnt/web2/13/38/51150638/htdocs/pl/app/webroot/ index.php on line 85 ...and i dont know why. if i do a var_dump on the define CAKE_CORE_INCLUDE_PATH in the file app/webroot/index.php i get: string(34) /mnt/web2/13/38/51150638/htdocs/pl ... and that looks ok. The url to my app is:http://cbmono.de/pl/ similar as on my localhost:http://localhost/pl/ Could anyone help me pls? Best regards! claudio. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Counting Tags. What is the find() syntax?
@Webweave. That's the article I was struggling with. I'll drink a few more cups of coffee and have another look. I'll use your select field tip in the meantime. On Jan 18, 3:46 pm, Webweave webwe...@gmail.com wrote: Easiest way I've found is just to include a select field in the query like: $data = $this-find(all, array( fields=array( Tag.id, Tag.name, (select COUNT(Article.id) from articles Article where Article.tag_id = Tag.id and Article.published = 1) AS tag_count ))); Here's an example of using the finderQuery:http://groups.google.com/group/cake-php/msg/c10840be78a34df0 On Jan 17, 12:55 am, RichardAtHome richardath...@gmail.com wrote: Given the following Model relations: article -- HABTM (articles_tags) -- tag How do I fetch back a list of Tags with the count of associated Articles? I've tried (in the Tag Model): $data = $this-find(all, array( fields=array( Tag.id, Tag.name, COUNT(Article.id) AS tag_count ), conditions=array( Article.published = 1 ), group = Tag.id )); But that doesn't generate the HABTM join in the SQL: SQL Error: 1054: Unknown column 'Article.id' in 'field list' SELECT `Tag`.`id`, `Tag`.`name`, COUNT(`Article`.`id`) AS tag_count FROM `tags` AS `Tag` WHERE `Article`.`published` = 1 GROUP BY `Tag`.`id` Thanks in advance :-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Counting Tags. What is the find() syntax?
I couldn't see the point in a separate tags table
What about 2 articles that share the same tags? You run the risk of
tagging either with one or 1 (for example) or CakePHP,
cakephp, Cakephp, cakePHP...
There's an awful lot of processing happening in your foreach loop.
What happens when you get 10,000 records? or 100,000? A relational
database eats this kind of aggregation for breakfast :-)
On Jan 19, 4:20 pm, leo ponton@gmail.com wrote:
I couldn't see the point in a separate tags table, so I have a tags
column on the table that requires it.
To retrieve the tags and tag count, I do this:
function getTagsWithCounts($conditions = array())
{
// Return assoc_array(tags) for all records in
database. Keyed on tagword,
// value = tagcount
$tagCounts = array();
$tagRows = $this-findAll($conditions, 'tags');
foreach ($tagRows as $row):
$tags = explode(',',$row['Event']['tags']);
foreach ($tags as $tag):
$tag = trim($tag);
if (array_key_exists($tag, $tagCounts)):
$tagCounts[$tag]++;
else:
$tagCounts[$tag] = 1;
endif;
endforeach;
endforeach;
return $tagCounts;
}
It's simple and it is working on two commercial sites, soon to be four.
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Re: Counting Tags. What is the find() syntax?
@Miles: Do you have a link to some example code that illustrates finderQuery. The stuff I've seen online was a bit impenetrable :-( @Amit: Yes, I *could* write the SQL by hand, but I was hoping there was a more 'cakey' way :-) On Jan 17, 10:34 am, Amit Badkas amitrb...@gmail.com wrote: For our photoblog, athttp://cheesecake-photoblog.org/demo/tags/, we use something like following query SELECT tags.*, COUNT(photos_tags.tag_id) AS totalPhotos FROM tags LEFT JOIN photos_tags ON tags.id = photos_tags.tag_id GROUP BY tags.id ORDER BY tags.tag ASC to generate tag cloud Hope this helps 2009/1/17 RichardAtHome richardath...@gmail.com Given the following Model relations: article -- HABTM (articles_tags) -- tag How do I fetch back a list of Tags with the count of associated Articles? I've tried (in the Tag Model): $data = $this-find(all, array( fields=array( Tag.id, Tag.name, COUNT(Article.id) AS tag_count ), conditions=array( Article.published = 1 ), group = Tag.id )); But that doesn't generate the HABTM join in the SQL: SQL Error: 1054: Unknown column 'Article.id' in 'field list' SELECT `Tag`.`id`, `Tag`.`name`, COUNT(`Article`.`id`) AS tag_count FROM `tags` AS `Tag` WHERE `Article`.`published` = 1 GROUP BY `Tag`.`id` Thanks in advance :-) -- Amit http://amitrb.wordpress.com/http://coppermine-gallery.net/http://cheesecake-photoblog.org/http://www.sanisoft.com/blog/author/amitbadkas --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: beginner: single view for index and add?
The simplest solution is to copy the code from the add method of the
controller to the index method.
Not looked at the blog code for quite a while, but it would go
something like this:
function index() {
if ($this-data) {
// add form submitted
$this-Model-create();
if ($this-Model-save($this-data)) {
// data saved
}
else {
// data failed to save
}
// rest of index code
$this-set(data, $this-Model-find(all));
}
On Jan 18, 10:39 am, Zach zachr...@gmail.com wrote:
Hi All. I've gone through the blog tutorial and i'm trying to make my
first cake site. My site is more or less the same as the blog
tutorial, except I want the add view and the index view to be the same
thing (one page that collects and displays posts, like a comment
thread).
Do i have to have an add view? Can I redirect somehow?
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Re: edit function is not working
Are you including the Model.id field in your edit form view?
?php echo $form-create(Model); ?
?php echo $form-input(Model.id); ? -- important line
?php ... rest of fields in your form ?
?php echo $form-end(Submit); ?
On Jan 16, 4:37 pm, mona poojapinj...@gmail.com wrote:
Here is my edit function code i don't know where i mistaken if i edit
my record it added automatically one new record and i didn't get
validation messages also below is my edit function code
function edit($id = null){
$this-set('sections', $this-Entry-Section-find
('list',array
('fields'='Section.section','Section.id','recursive' = 1,'page' =
1,)));
if (empty($this-data)){
if (!$id){
$this-Session-setFlash('Invalid id for Entry');
$this-redirect('/entries/index');
}
$this-data = $this-Entry-read(null, $id);
}
else{
$query=mysql_query(select max(counter) from entries);
$row=mysql_fetch_array($query);
$co=$row[0]+1;
$q=mysql_query(update entries set counter=$co where id=$id);
if ($this-Entry-save($this-data)){
$this-Session-setFlash('The Entry has been saved');
$this-redirect('/entries/index');
}
else{
$this-Session-setFlash('Please correct errors below.');
}
}
}
can anybody tell me where i m mistaken this function doesn't edit my
record instead of that it will added one new record in my table
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Re: Quote marks in model names and Use of undefined constant notices
It's for this very reason I keep championing the case to have ALL
source code on a web page to be presented in a plain text textarea!
And don't get me started on 'smart quotes'! ;-)
On Jan 16, 8:49 pm, clarkphp clark.evere...@gmail.com wrote:
Figured it out, with the help of a sharper pair of eyes than mine. It
turns out that the original code did in fact come from a web page -
the CakePHP manual (I copied, pasted, and edited the table name and
other code). When I pasted into my text editor, I didn't notice that
the quote marks were not the regular single quotes. All is good now.
Thanks,
Clark-
On Jan 16, 7:45 am, clarkphp clark.evere...@gmail.com wrote:
Hello Martin,
Thanks for your reply. My files are all UTF-8. And, no - never touch
MS Word - pasted in from browser. Running Linux on dev and production
boxes.
I also looked at Firefox View Source. The leading mysterious quote
mark is the upward curving opening quote, and the trailing one is the
downward curving closing quote mark - I'm looking for the character
numbers. My source file is using the regular single quote found on
the keyboard (not the backtick).
See how these characters are inserted inside my vanilla-flavored
single-quoted string containing the model name, which the inflector is
converting to a table name? All references to the model name in my
source files are using the regular single quote character. It appears
that the undesired characters are being inserted before and after the
contents of that string by Cake. I've traced with a debugger to find
where the transformation is happening, but am only close to it;
haven't nailed it yet.
One thing I've found is that with PHP error_reporting set high enough,
Cake generates a fair number of E_NOTICES regarding undefined
constants - the ticket system shows these being fixed on a case-by-
case basis. I think those errors are not necessarily related to this
problem.
Thanks again. Does this generate any ideas from you or other readers?
- Clark
On Jan 16, 2:30 am, Martin Westin martin.westin...@gmail.com wrote:
Hi Clark,
Looks to me like the thing you are missing is the small problem your
source-file has with its quotes.
Use of undefined constant â Organizationâ
This suggests that your modelname is not in fact enclosed by single
quotes but some other glyph that looks like it but really has another
ASCII code. You may have pasted the line of code from a browser or
(god forbid) Word and got the strange character in your file that way.
If the quotes are not real quotes then PHP will interpret this as
you trying to use a constant.
While you are at it make sure the charset of the php file is not
something strange.
/Martin
On Jan 16, 12:35 am, clarkphp clark.evere...@gmail.com wrote:
Check out the extra quotes in the model name in the WHERE clause
below:
SELECT `Organization`.`name`, `Organization`.`description` FROM
`organizations` AS `Organization` WHERE `‘Organization’`.`status` =
'inactive' ORDER BY `Organization`.`name` asc
I've used SimpleTest before, but am now beginning to use it in the
context of CakePHP's testing framework. All test cases that involving
a model are failing because the model names are getting enclosed with
single quotes, which produces table names in database queries that of
course don't exist. For example:
App::import('Model', 'Organization');
class OrganizationTestCase extends CakeTestCase
{
public $useTable = 'organizations';
public $fixtures = array('app.organization');
public function testInactive()
{
$this-Organization = ClassRegistry::init('Organization');
$result = $this-Organization-inactive(array('name',
'description'));
$expected = array(
array('Organization' = array('name' = 'Test Company
Name', 'description' = 'Mortgages'))
);
$this-assertEqual($result, $expected);
}
}
results in a failed assertion and two E_NOTICES.
The failed assertion:
Equal expectation fails as [Boolean: false] does not match [Array: 1
items] at [/usr/local/apache2/vhosts/dev-obfuscated.com/app/tests/
cases/models/organization.test.php line 19]
The Errors:
Unexpected PHP error [Use of undefined constant â Organizationâ -
assumed 'â Organizationâ '] severity [E_NOTICE] in [/usr/local/
apache2/vhosts/dev-obfuscated.com/cake/libs/class_registry.php line
134]
Unexpected PHP error [span style = color:Red;text-align:leftbSQL
Error:/b 1054: Unknown column 'Ã¢â ¬Ë Organizationâ⠬⠢.status'
in 'where clause'/span] severity [E_USER_WARNING] in [/usr/local/
apache2/vhosts/dev-obfuscated.com/cake/libs/model/datasources/
dbo_source.php line 514]
The use (or lack of) $useTable in the app/models or tests/cases/models
code
Re: How to avoid repetition with dynamic content
Here's how I break it down: 1) Anything thats on *every* page goes in the layout 2) Anything thats repeated on more than one page but not on all, goes in an element (and imported into the view with echo $this-element (foo)) 3) Anything that's unique to a page goes in the view. So, as an example. Take a blog article page with a header, footer, article and a sidebar with a tag cloud that displayed on the index view pages: 1) Header footer goes in the layout 2) Tag cloud goes in an element and is imported in the index and view views. 3) The article itself goes in the view. Hope this helps :-) On Jan 18, 3:06 pm, Bankai hgnelso...@gmail.com wrote: So, I have all the html laid out. I want to make it so that I don't have to copy and paste all the html every time I create a new page or change the layout in each and every page every time I make a change in the html code. I used to do that in the past with just plain PHP, but I want to make it using cakephp. I am having a hard time doing it with cakephp. Could somebody guide me in right direction? maybe some tutorial anywhere? I tried some Dynamic Content tutorials but it doesn't work. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Counting Tags. What is the find() syntax?
Given the following Model relations: article -- HABTM (articles_tags) -- tag How do I fetch back a list of Tags with the count of associated Articles? I've tried (in the Tag Model): $data = $this-find(all, array( fields=array( Tag.id, Tag.name, COUNT(Article.id) AS tag_count ), conditions=array( Article.published = 1 ), group = Tag.id )); But that doesn't generate the HABTM join in the SQL: SQL Error: 1054: Unknown column 'Article.id' in 'field list' SELECT `Tag`.`id`, `Tag`.`name`, COUNT(`Article`.`id`) AS tag_count FROM `tags` AS `Tag` WHERE `Article`.`published` = 1 GROUP BY `Tag`.`id` Thanks in advance :-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Help needed with an error
Just come across this when I renamed my web root folder. I think this is to do with me using APC and isn't a CakePHP issue (now that you have deleted the cache). Restart Apache. This will clear the APC cache. On Sep 26, 2:17 pm, Eemerge [EMAIL PROTECTED] wrote: just cleared them, same thing. still not working. I read somewhere i should define the CAKE_INCLUDE_PATH (or something like this) manually... to what should it point? what path? On Sep 26, 2:02 pm, grigri [EMAIL PROTECTED] wrote: Have you tried emptying the cache files? If the directory names have changed since cake's cache was built then this is what would happen. On Sep 26, 11:27 am, Eemerge [EMAIL PROTECTED] wrote: Hello, I would like some help with the following error: Warning: require(cake/bootstrap.php) [function.require]: failed to open stream: No such file or directory in /home/mainfram/public_html/ shoplog/app/webroot/index.php on line 79 Fatal error: require() [function.require]: Failed opening required 'cake/bootstrap.php' (include_path='.:/usr/lib/php:/usr/local/lib/php:/ home/mainfram/php') in /home/mainfram/public_html/shoplog/app/webroot/ index.php on line 79 The strange thing about is that, 2 weeks ago it was working , everything was ok, there were some problems on the hosting server, and now it stopped working. If anyone cane help, i'd really appreciate it. Thanks --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: flood control?
or... redirect to another page (a thank you page perhaps presuming
this is a contact form) after you have sent the mail.
On Sep 26, 8:42 am, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
Looking at some of the web-mail apps I use many seem to handle this
using a combination of very clear visual indicators, disabling of
submit-buttons and sending with ajax.
Ajax also help prevent back-button accidents which is nice.
On Sep 26, 7:45 am, rocket [EMAIL PROTECTED] wrote:
mktime.. good idea.
thanks
On Sep 26, 1:23 am, Marcelius [EMAIL PROTECTED] wrote:
You can't make sessions count down. Instead of setting 30sec in your
session,store mktime() for the current time. Next time a user hits
the send button you check the current time with the time you allready
had stored in your session. Note that if a user deletes the browsers
cookie, session get lost so they can pass that check.
On 26 sep, 06:26, rocket [EMAIL PROTECTED] wrote:
hey guys
i implemented a simple mail system in my site and was wondering what i
ought to do for flood control. I dont' want people to keep hitting
refresh after they hit send thus spamming...
I was thinking of doing something like
$this-Session-write('Timeout', 30);
To simulate a 30 second countdown then just checking this timout
before another post is allowed... but I dont know how to make sessions
count down.
any ideas are appriciated!
rocket
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Re: Parameter passing in URL
or store the id in the session? On Sep 26, 12:17 pm, Daniel Süpke [EMAIL PROTECTED] wrote: Thank you very much, I'll have a look at that! Best Regards, Daniel Süpke [EMAIL PROTECTED] wrote: I haven't done exactly that but I think you could set all urls and links using the array notation. The array could then also be pre- populated with the parameter you want to keep in each request. (Pre- populated in some central place like AppController::beforeFilter before any links are generated) On Sep 25, 1:23 pm, Daniel Süpke [EMAIL PROTECTED] wrote: Hi, we are using CakePHP 1.2 and I was wondering how it could be achieved to pass a parameter along every URL. We have a parameter set to an ID and it needs to be included in every URL in the application. Now, the first solution was to create a LinkHelper which added the location via $_GET, but this is not working when forms are validated by Cake, since then the url is not going via the LinkHelper. So, is there any easy way to pass around a parameter in the URL in the entire application? Best Regards, Daniel Süpke --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: PLease help, 3 days struggle with 'simple' authentication
$this-Auth-deny('admin', 'accnt', 'faq'); // does not work
This doesn't work because the 'action' for all views in the pages
controller is 'display' not 'admin', 'accnt'
$this-Auth-deny(display) would work, but it would deny ALL views
handled by the pages controller.
Your workaround is a good compromise. Or you could make your own
dedicated MyPagesController to group all these pages together.
On Sep 24, 11:12 am, Gabriel Kolbe [EMAIL PROTECTED] wrote:
S'ok, I created 'fake' functions in the user controller, then added
the views to the users views, then take the Authentication process
from the app_controller to the users_controller..
On Wed, Sep 24, 2008 at 10:54 AM, gabriel [EMAIL PROTECTED] wrote:
This is my current code:
class AppController extends Controller {
var $components = array('Auth');
function beforeFilter() {
$this-Auth-authorize = 'controller';
$this-Auth-allow('*');
$this-Auth-deny('admin', 'accnt', 'faq'); // does not work
}
function isAuthorized() {
if ($this-Auth-user('role') == 'admin') {
$this-Auth-allow('admin');
}
}
}
What I want to do is something like the following:
function beforeFilter() {
$this-Auth-authorize = 'controller';
$this-Auth-allow('pages/faq', 'pages/aboutus', 'users/
register');
$this-Auth-deny('pages/accnt', 'pages/admin', 'categories/
edit');
}
function isAuthorized() {
if ($this-Auth-user('role') == 'admin') {
$this-Auth-allow('pages/admin', 'categories/edit');
}
$this-Auth-allow('pages/accnt');
}
}
NOTE: the pages does not have a model or controller..I HAVE read the
cookbooks severaltimes, served the Cakegroup, posted several message,
got different replies, but just can' t seem to find a answer to
this... I would be grateful if someone can actually show me ..
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Re: bulk load data into CakePHP?
If this is a once only import (populate initial db), I'd stick to
using mysql's data import command line tool and move onto something
more fun.
If it's something that needs to be run repeatedly e.g. a user uploads
a file that needs to be imported then write a custom method in the
Model that uses mysql's LOAD DATA INFILE sql:
http://dev.mysql.com/doc/refman/5.0/en/load-data.html
e.g.
function importCsv($csv_filename) {
sql$ = LOAD DATA INFILE '{$csv}' INTO TABLE {$this-alias};
$this-query($sql);
}
...code typed straight into google groups, may need tweaking ;-)
It might be advisable to wrap the query() call with a setTimeout if
its going to take a while...
You would call it from your controller with:
$this-Model-importCsv($filename);
On Sep 24, 7:25 am, Mike [EMAIL PROTECTED] wrote:
Thanks for the tip! In the previous, non-Cake version of the app, I
did that exactly, so it shouldn't be too too tough to get it up and
running again. I was kinda avoiding SQL b/c it seemed like the Cake
way should be to push it through the Cake layer let CakePHP make it
automagically happen. Hearing that raw SQL is actually the right way
is actually really helpful :)
If you don't mind my asking a couple more questions - how does one
know where the boundary should be? I mean, aside from exceeding
max_execution time and/or running out of memory - how would I know
where to draw the boundary between 'small enough for Cake' vs. 'needs
raw SQL' when designing my app? (And what does a normal app do if a
user happens to show up with an unexpectedly huge data set?)
Also, what sort of data sets is Cake intended to support? I'm writing
the app to support my teaching, so having 30 people in a class, with
10-20 homeworks/exercise sets to hand in (each of which might have 2-3
versions stored), so it's conceivable that Cake might auto-magically
pull 600-1,200 records (even if fairly few / none of them are used in
any given view). One of the things I really liked about Cake was that
I could set recursive = 2 (or 3), and have it magically pull
everything I needed out of the DB (in my raw PHP app, I figured it was
time to look at a framework when I started to move towards an OOP-y
iterator approach for dealing with all my lists of data :) )
Thanks again for the quick reply - I appreciate the 'ok' from someone
who knows more about this than I do! :)
--Mike
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Re: cakephp application templates
To be honest, you would be much better if you created your own. All the components are there already in Cake, you just have to learn how to glue them together. If you don't, you'll come unstuck when it comes to something a little more challenging. Happy Baking! On Sep 23, 11:24 am, forrestgump [EMAIL PROTECTED] wrote: Hey, I was wondering if anyones got any good sites for application templates for cakephp...like templates having pre-programmed login/ logout/sessions maintainancemenu creation role based management etc... Thanks, Forrestgump --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: To model or not to model
Also worth noting: A controller can have multiple Models.
Which model would $this-find() use?
On Sep 23, 12:28 pm, dr. Hannibal Lecter [EMAIL PROTECTED]
wrote:
Well, calling find() in a controller is not a violation, but not the
best practice if overused.
Of course, calling find() from a controller is the fastest way to get
your data, but usually, the find() call has other stuff around it,
stuff that might be common to each call. The idea is to make fat
models, thin controllers, meaning that you put as much as you can in
your models.
Maybe an example is better. Let's say you have a certain criteria for
getting an article from the Article model. You can call this from a
controller each time you want to get an article:
$article = $this-Article-find
(
'first',
array
(
'conditions' = array('Article.slug' = $slug),
'contain' = array('ArticleCategory', 'Rating')
)
);
or you can make it cleaner and easier by declaring a function in your
model, for example getArticle:
function getArticle($slug)
{
$_slug = Sanitize::escape($slug);
return $this-find
(
'first',
array
(
'conditions' = array('Article.slug' =
$_slug),
'contain' = array('ArticleCategory',
'Rating')
)
);
}
this makes your controller much thinner and easier to follow:
$article = $this-Article-getSingle($slug);
All you have to remember is that all apps work with some sort of data,
and in Cake, models work with data, not controllers.
I hope that helps a bit. ;)
On Sep 23, 11:33 am, forrestgump [EMAIL PROTECTED] wrote:
Hey guys,
Considering the fact that CakePhp follows the MVC architecture, id
like to know...y we dont make function calls such as $this-find(where
id=xyz) from function blocks typed out in Models rather
than controllersim sure there is a logical reason to it...but
someone asked me this question and i could not give her a good enuf
answerdoes making function calls to queries like find(), save()
work better in models or controllers?.and is it good practice to
pass conditions in your function call while using it in a controller?
eg find(where id=1) ;
Does using $this-find() in controller violate the MVC architecture in
any manner?
Can someone please clarify these question for us?
Thanks in advance,
forrestgump
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Form type='get' and date fields
I'm trying to create a bookmarkable search results page. I have the following form so I am using 'get' search form: ?php echo $form-create(Event, array(action=search, type=get)) ? ?php echo $form-input(Event.start_date) ? ?php echo $form-end(search) ? When the form is posted, the URL looks like this: http://www.example.com/events/search?event_name=location_name=start_date=09start_date=22start_date=2008start_date=02start_date=33start_date=pm Which makes it impossible to work out the date that was submitted because the last query parameter overwrites the previous ones! $this-params['url']: [url] = events/search [start_date] = pm If I use 'post' as the form type, Cake separates the date fields correctly, but the search result page isn't bookmarkable (the url becomes http://www.example.com/events/search). Is there a workaround for this? Or am I doing it completely wrong? :-S --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Form type='get' and date fields
Note: this groups post: http://groups.google.com/group/cake-php/browse_thread/thread/c05c03e397549dde/57f2e4d6b3f7fb0e?lnk=gstq=form+get+date#57f2e4d6b3f7fb0e Sounds like the same problem, but has no replies... On Sep 22, 2:41 pm, RichardAtHome [EMAIL PROTECTED] wrote: I'm trying to create a bookmarkable search results page. I have the following form so I am using 'get' search form: ?php echo $form-create(Event, array(action=search, type=get)) ? ?php echo $form-input(Event.start_date) ? ?php echo $form-end(search) ? When the form is posted, the URL looks like this: http://www.example.com/events/search?event_name=location_name=start... Which makes it impossible to work out the date that was submitted because the last query parameter overwrites the previous ones! $this-params['url']: [url] = events/search [start_date] = pm If I use 'post' as the form type, Cake separates the date fields correctly, but the search result page isn't bookmarkable (the url becomeshttp://www.example.com/events/search). Is there a workaround for this? Or am I doing it completely wrong? :-S --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Simply aligning form-input fields and labels nicely....
Note:
div class=labelSomething/div
div class=inputfieldinput type=text //div
div class=labelSomething2/div
div class=inputfieldinput type=text //div
..will create an invalid form: You MUST have a label linked to every
input element.
Here's a snippet from my own cake.generic.css:
/*
* forms
*/
#content form {
padding: 16px;
background-color: #DDD;
-moz-border-radius: 16px;
}
#content fieldset {
border: 0;
}
#content legend {
color: #06C;
font-size: 3em;
line-height: 1.2em; color : #06C;
font-weight: bold;
}
#content form div.input {
clear: both;
margin: 8px 0;
background-color: #EEE;
padding: 2px;
-moz-border-radius: 4px;
border: 1px solid #EEE;
}
#content form div.input.required {
font-weight: bold;
}
#content form div.input.error {
border-color: #900;
background-color: #FCC;
color: #900;
}
#content form div.input label {
float: left;
width: 14em;
margin-right: .5em;
}
#content form div.text input,
#content form div.password input,
#content form div.select select,
#content form div.datetime select,
#content form div.textarea textarea {
border: 1px solid #CCC;
padding: 2px;
font-size: 1.2em;
font-family: verdana, sans-serif;
}
#content form div.textarea textarea {
width: 40em;
height: 20em;
}
#content form option {
padding-right: .5em;
}
#content form div.input.error div.error-message {
margin-left: 14.5em;
padding: 2px 2px 2px 22px;
background: url(../img/icons/error.png) no-repeat 2px center;
}
#content form div.input input.form-error {
border-color: #C00;
}
#content form div.submit input {
margin-left: 7.25em;
border: 4px solid #FFF;
padding: 2px 4px;
background: #06C none no-repeat 4px center;
color: #FFF;
font-weight: bold;
font-size: 2em;
cursor: pointer;
-moz-border-radius: 8px;
}
#content form div.submit input:hover {
background-color: #9C9;
color: #333;
text-decoration: none;
}
I'm preparing an article for the Bakery about styling Cake layouts and
views as we speak...
On Sep 22, 2:57 pm, toby78 [EMAIL PROTECTED] wrote:
Thanks, this works.
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Re: cakephp email component
I suspect you are trying to SMTP to gmail or something similar.
CakePHP doesn't support the encyption required to connect to these
types of SMTP server.
The Bakery has some useful articles for using 3rd party mail
components that support encrypted SMTP
On Sep 22, 10:35 am, Predominant [EMAIL PROTECTED] wrote:
Hey base64,
This message 220-We do not authorize .. is being produced by one of
the mail servers charged with delivering your mail message.
Try using a mail server you have authority to use.
Cheers,
Predom.
On Sep 22, 3:32 am, base64 [EMAIL PROTECTED] wrote:
Dear all,
I'm using CakePHP Email component, when i sent email and i set smtp_errors;
$this-set('smtp-errors', $this-Email-smtpError);
the variable *smtp-errors* return : *220-We do not authorize the use of this
system to transport unsolicited, *and my email did'not sent.*
*how to solved this problem?, and what can I do to send email using CakePHP
email component?. I had follow this instruction step by step :
*http://book.cakephp.org/view/176/Email*
Thanks
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Re: Form type='get' and date fields
Aye, I thought of that but it feels a bit 'messy' :-( On Sep 22, 3:23 pm, Daniel Hofstetter [EMAIL PROTECTED] wrote: Hi Richard, I'm trying to create a bookmarkable search results page. I have the following form so I am using 'get' search form: ?php echo $form-create(Event, array(action=search, type=get)) ? ?php echo $form-input(Event.start_date) ? ?php echo $form-end(search) ? When the form is posted, the URL looks like this: http://www.example.com/events/search?event_name=location_name=start... Which makes it impossible to work out the date that was submitted because the last query parameter overwrites the previous ones! $this-params['url']: [url] = events/search [start_date] = pm If I use 'post' as the form type, Cake separates the date fields correctly, but the search result page isn't bookmarkable (the url becomeshttp://www.example.com/events/search). Is there a workaround for this? Or am I doing it completely wrong? :-S You could post your form to an action which then uses the form data to create the url of the result page and redirects to it. Hope that helps! -- Daniel Hofstetterhttp://cakebaker.42dh.com --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Accessing multiple databases within a single Mysql instance in a single query.
Have you checked out Easysoft's SQLEngine? It allows heterogeneous joins across databases and even across different RDBMs? As an alternative, you could always use $this-model-query(); and enter the SQL by hand. You'll loose a lot of cakey goodness though :-( On Sep 22, 3:19 pm, Bookrock [EMAIL PROTECTED] wrote: I am facing same problem On Sep 21, 5:56 pm, Rick [EMAIL PROTECTED] wrote: I tried that technique but it did not work. It appears that you can't havemultipleuseDBConfigs in a single query. This seems reasonable since you also can't do a raw select usingmultipleconnections which is what the useDBConfigs give you (I think). Richard On Sep 20, 5:56 pm, Adam Royle [EMAIL PROTECTED] wrote: What you need to do is set $useDBConfig for each model. var $useDBConfig = 'A'; then in your DATABASE_CONFIG you would use var $A = array( 'driver' = 'mysql', 'persistent' = false, 'host' = 'localhost', 'login' = 'username', 'password' = 'password', 'database' = 'A', 'prefix' = '', ); Adam On Sep 21, 4:24 am, Rick [EMAIL PROTECTED] wrote: I've got an existing MySql instance that contains 4 databases (lets call them A, B, C D). Each has tables as you would expect. For this post lets say tables are named like table1, table2 etc.. in each database. My single user/password has access to all databases in the instance. My problem is I need to query across several databases. This is the way I would do this with a raw query: select * from A.table1 as t1, B.table2 as t2 where t1.id = t2.id I haven't been able to do this through any combination of model attributes. Naturally I thought that var $useTable = A.table1 in The table1 model and var $useTable =B.table2 in the table2 model would work - alas no it does not. I've also tried using the prefix attribute and that doesn't do it either. Is there some way to do this in Cake or do I need to forget the models and just do raw sql queries in the controllers? It seems to me this is just an arbitrary restriction in the model code. Richard --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Using Views in database over a legacy database
You can set up your models to use any non-cake table structures and naming styles. See http://book.cakephp.org/view/71/Model-Attributes for more details. On Sep 18, 9:31 am, Laurent Bois [EMAIL PROTECTED] wrote: Hi We currently have a data model with table names that don't follow CakePHP conventions. As we do with Rails, one technique to use (when application is read- only, and that's our case) is to create views in database over this legacy tables. First i did this. Then i wanted to unit test my new renamed data model. - i've recreated my models using renamed keys in my views. - i've recreated my test cases. After first test launched, what i see for the first model, is that the Testing framework create my test tables with the keys of the table, mapped by my view. And fixtures couldn't be loaded, and test is not run. here my legacy table : SL01 : N_NUME_CLIE varchar(6) L_CONN_NOM varchar(40) L_CONN_PASS varchar(40) Here my view Users Create view Users as select n_nume_clie id, l_conn_nom, l_conn_pass from sl01; Here the trace in my test case (creation of the table for testing): CREATE TABLE `test_utilisateur_tests` ( `N_NUME_CLIE` varchar(6) NOT NULL, `L_CONN_NOM` varchar(40) NOT NULL, `L_CONN_PASS` varchar(40) NOT NULL ); It seems to be a problem with the SimpleTest framework Does CakePHP support Models mapping database Views? Thanks Laurent --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Association question
In exactly the same way :-) You join table (products_sizes) would hold the stock field id (PK) product_id (FK) size_id (FK) stock (INT) On Sep 17, 9:27 pm, VitillO [EMAIL PROTECTED] wrote: Hi, i have the following structure for a tshirt online store: Product HABTM Size Size HABTM Product Association table: products_sizes The problem is, i need a stocks system. For example, say i have 50 pieces of S (size) for a particular tshirt, before using cake i had a column 'stock' in the association table, so i could retrieve the particular stock of that size, for that product, but now with cake i dont know how i should make the association. Any help? Thanks! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: problem using find method in cakephp with conditions contains 'LIKE'
'conditions' = array('Book.title LIKE' = 'A%'),
The condition has been moved to the left hand side as a security
measure.
On Sep 17, 8:14 am, jittos [EMAIL PROTECTED] wrote:
i am a new comer in cakephp.. i am going through some tutorials in
cakephp.. i found one problem i want to write find method for the
following query
SELECT `Book`.`isbn`, `Book`.`title`, `Book`.`author_name`
FROM `books` AS `Book`
WHERE `Book`.`title` LIKE 'A%'
ORDER BY `Book`.`isbn` DESC
LIMIT 2;
i wrote
find(
'all',
array(
'conditions' = array('Book.title' = 'LIKE A%'),
'fields' = array(
'Book.isbn',
'Book.title',
'Book.author_name'
),
'order' = 'Book.isbn DESC',
'limit'=2
)
);
but it create a query like this..
SELECT `Book`.`isbn`, `Book`.`title`, `Book`.`author_name`
FROM `books` AS `Book`
WHERE `Book`.`title` = 'LIKE A%
ORDER BY `Book`.`isbn` DESC
LIMIT 2;
i.e, LIKE keyword is not working properly... did i do anything
wrong?...
plz help me if anybody have any idea about it...
thanks,
jittos
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Re: $html-link default titles
Which accessibilty checkpoint requires you to have a title attribute on every hyperlink? The nearest I can find is checkpoint 13.1: http://www.w3.org/TR/WCAG10/wai-pageauth.html#tech-meaningful-links 13.1 Clearly identify the target of each link. [Priority 2] Link text should be meaningful enough to make sense when read out of context -- either on its own or as part of a sequence of links. Link text should also be terse. For example, in HTML, write Information about version 4.3 instead of click here. In addition to clear link text, content developers may further clarify the target of a link with an informative link title (e.g., in HTML, the title attribute). 'may' does not mean 'must' ;-) On Sep 12, 3:10 am, AussieFreelancer [EMAIL PROTECTED] wrote: I can see your point about repeating it twice, I don't understand how different accessibility applications work, but I know that it is part of the WAI and Section 508 accessibility standards that all href elements should have the title attribute, and all images should have an alt tag, even if it is empty. This is what has made me think of this, as I am a website developer, and to pass these accessibility tests, I need to include the title in every link - which is not too much of a problem, just that I figure having it as a default would reduce the amount of code I need to write :D Also, most links will have the same title text as the link text anyway, wouldn't they? Certainly with navigation, Home is Home, About Us is About us... As I say, I don't understand how the applications work exactly, I just want to be able to do what I can to ensure that my websites are accessible to as many people as possible. Thanks Patrick On Sep 12, 9:52 am, Adam Royle [EMAIL PROTECTED] wrote: You can override cakephp's defualt functionality in your AppHelper if you want to do this. I don't think it should be the standard, as there are situations where you might not want this. Additionally, why do you need to repeat the link text in the link title? Won't this effectively cause the screenreader to speak the link text twice? Cheers, Adam On Sep 12, 11:38 am, AussieFreelancer [EMAIL PROTECTED] wrote: I have just done a quick google search, and can't seem to see anything about this, but I have been thinking for some time now, that for accessibility reasons, wouldn't it make sense for the links to have a default title, and even images have an empty alt tag by default? The link title could default to the link text, unless a title was specified in the options. Any thoughts on this, or reasons as to why cakephp doesn't currently work like this? Thanks Patrick --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Yorkshire cakers
I'm relatively close by in Sheffield. On Sep 10, 11:55 pm, simonb [EMAIL PROTECTED] wrote: Anyone in the dewsbury, England, West Yorkshire area who has used cake? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Problem with MySQL query
Probably in your OptionsController?. Check out the function that matches the name of your action, ie, http://www.example.com/options/ or http://www.example.com/options/index can be found in your OptionsController (/app/controllers/ options_controller.php) and look for the function index() Also, post the code in your model too (/app/models/option.php); On Sep 11, 9:56 am, krzysztofor [EMAIL PROTECTED] wrote: but i don't know where it is genereted :/ where can it be? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: CakePHP 1.2: Layout and views design issue
I'll answer b) /app/views/layouts/default.ctp: html head title?php echo $title_for_layout; ?/title /head body div id='header' header markup goes here /div div id='menu' menu markup goes here /div div class='content' ?php echo $content_for_layout; ? /div div id='footer' markup for footer /div /body /html if(session) print hello $user else show login link. That's correct :-) Why do you not think this should go in the layout? You could paste the code into an element (note, i'm using your pseudocode here, check out the manual on the Auth component for some real code): /app/views/element/session_links.ctp: if(session) print hello $user else show login link. and in your layout: ?php echo $this-render(session_links); ? On Sep 10, 10:19 am, jkritikos [EMAIL PROTECTED] wrote: Hi there, I would like to ask 2 questions, both regarding the layout and views. a) After installing cake 1.2 and accessing my localhost domain, I get to see the cake info page and everything works fine. If i access a url that is lacking the underlying controller or view, I get to see cake's error message about the corresponding view file missing etc. When I create my own template under /app/views/layout/default.ctp, it all works fine but whenever I hit invalid urls (as above) nothing happens (i.e. i still get to see my default template but without the error messages). I read somewhere that by overriding the default.ctp layout file, you are effectively changing every page that cake would render, so perhaps I'm missing some variables in my layout? (e.g $content_for_layout, $title_for_layout etc?) b) I have been given all the templates for an application by a web designer. Let's say that the default layout consists of a header, a menu, the 'main body' and a footer. What is the correct approach for breaking this down in cake ? I assume that my default layout should contain the common elements that are always present (i.e header, menu, footer), and all other views will be rendered within the 'main body' section of the layout. However if this is the case, it would mean that the actual layout, in the header section should also contain code like: if(session) print hello $user else show login link. This somehow feels wrong. Should i have code like that in my layout ? What is the best practice for using a default template and some views? thanks a lot, jason --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Need help on Install
First off read this: http://en.wikipedia.org/wiki/Example.com Example.com is a test domain that you cannot use ;-) On Sep 10, 4:09 am, Jerry Ross [EMAIL PROTECTED] wrote: Ooopps! It was a false positive. What I actually accidentally got up and running washttp://myexample.com http://www.example.com and http://www.example.com/cake_1.1.19.6305/ are still not working. However, on the positive side, http://localhost/cake_1.1.19.6305/ is working and I have a CAKE RAPID DEVELOPMENT screen telling me It found my database config file and that cake is able to connect to my database. But can someone tell me what I am supposed to see whenhttp://www.example.comstarts to work? All I get is this: You have reached this web page by typing example.com, example.net, or example.org into your web browser. These domain names are reserved for use in documentation and are not available for registration. See RFC 2606, Section 3. I am supposing that was NOT what I was suposed to get. Any suggestions? Pittore - Original Message - From: Jerry Ross [EMAIL PROTECTED] To: cake-php@googlegroups.com Sent: Tuesday, September 09, 2008 7:57 PM Subject: Re: Need help on Install Thanks for all your help...I now have example.com up and running and it looks good. Now onto programming. Pittore - Original Message - From: Donkeybob [EMAIL PROTECTED] To: CakePHP cake-php@googlegroups.com Sent: Tuesday, September 09, 2008 6:48 AM Subject: Re: Need help on Install one word . . . .xampp. for xp, it is the beez kneez . . . set up is easy and everything is done for you. apache, mysql, php . . . .then edit the httpd.conf to add a virtual host. i run many development sites from this configuration On Sep 8, 8:09 pm, Pittore [EMAIL PROTECTED] wrote: I have apache2 up and running on my Windows XP Pro laptop I have established the following directory structure: Apache2 htdocs cake When I typehttp://www.example.com/cakeorhttp://www.example.com/ I get Page not found some kind soul sent me these suggestions: 1. Create a simple static VirtualHost under Apache based on the simplehost example configuration file C:\www\Apache22\conf\extra\vhosts\_static\simplehost.com.conf a. Resave file as mydomain.com.conf, in the same folder, to duplicate it. b. Update all occurrences of 'simplehost.com' to 'mydomain.com' within. c. Create folder C:\www\Apache22\conf\extra\vhosts\_static\mydomain.com \ d. Create folder C:\www\vhosts\_static\mydomain.com\ to be used as the container for this VirtualHost. e. Create log folder C:\Apache22\logs\mydomain.com\ 2. Unpack cakephp as folder C:\www\vhosts\_static\mydomain.com\cake\ 3. Modify this VirtualHost's configuration [mydomain.com.conf] and change DocumentRoot from... DocumentRoot C:/www/vhosts/_static/mydomain.com To... DocumentRoot C:/www/vhosts/_static/mydomain.com/cake/app/webroot 4. Restart Apache. However, I am stuck on step 1a and b...I don't know where to find the file: 'simplehost.com' any suggestions? Help...I have been trying to configure cake now for 4 days am getting frustrated. -- Pittore --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Problem with MySQL query
Post your query code :-) On Sep 10, 3:17 pm, krzysztofor [EMAIL PROTECTED] wrote: Hello everybody. I'm begginer with CakePHP. The MySQL query is genereting in a wrong way: Query: SELECT `Option`.`id`, `Option`.`menu_id`, `Option`.`parent_id`, `Option`.`page_id`, `Option`.`order`, `Option`.`extension_name`, `Option`.`extension_args`, `Option`.`menu` FROM `fk3_options` AS `Option` WHERE `Option`.`pageid` = 41 LIMIT 1 The problem is in the 'WHERE clause'. The record 'pageid' doesn't exist, instead of it should be 'page_id'. Warning (512): SQL Error: 1054: Unknown column 'Option.pageid' in 'where clause' [ROOT/system/cake/libs/model/datasources/ dbo_source.php, line 440] There is no problem on localhost, but it is on the external server :(. Please help me if you can. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Best profiler for cake php?
I'd also like this info. XDebug crashes my apache (on windows) too :-( On Sep 9, 5:42 am, Dianne van Dulken [EMAIL PROTECTED] wrote: Hi, I was just wondering what profiler everyone else was using. I'm having trouble finding one that will work with my cakephp setup. Xdebug causes my apache to crash, and I'm having similar issues with some other ones. My setup is Cake version: 1.2.0.5427 Apache 2.2.4 PHP: 5.2.4 If anyone could tell me what they are using, I'd really appreciate it Di --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Find: conditions and fields
What David said.
You have to add your conditions to the paginate call.
Check out the google groups FAQ: http://groups.google.com/group/cake-php/web/faq
Scroll down to: How to add paginate support for custom queries?
On Sep 9, 9:13 am, David C. Zentgraf [EMAIL PROTECTED] wrote:
See:http://groups.google.com/group/cake-php/msg/7d17a42d764ccce4?hl=en
Your problem is not in your conditions, it's right here:
$this-set('textmasters', $this-paginate());
Yes, this in fact does give you *everything*.
On 9 Sep 2008, at 17:04, Liebermann, Anja Carolin wrote:
Hello,
I still have some problems with the parameters for find
I have two different sets of parameters but I have the impression the
result doesn't react on them, but simply gives me a list with nearly
all
of my datasets:
Version 1:
$params = array(
'conditions' = array('Textmaster.katalogobjekt_id' = 1,
'Textmaster.sprache_id' = 1,
'Textmaster.textinhalt LIKE' =
'%'.trim($this-data['Textmaster']['textinhalt']).'%',
'Textmaster.suchkriterium LIKE' =
'%'.trim($this-data['Textmaster']['suchkriterium']).'%'),
'fields' =
array
('Textmaster.id','Textmaster.suchkriterium','Textmaster.textinhalt'
),
'order' = 'Textmaster.suchkriterium ASC',
'recursive' = -1
);
Version 2:
$params = array(
'conditions' = array('Textmaster.katalogobjekt_id' = 1,
'Textmaster.sprache_id' = 1),
'fields' =
array
('Textmaster.id','Textmaster.suchkriterium','Textmaster.textinhalt'
),
'order' = 'suchkriterium ASC',
'recursive' = -1
);
$textmasters = $this-Textmaster-find('all',$params);
$this-set('textmasters', $this-paginate());
Question 1: What does 'fields' do? I thought it would load only those
fields, but my dataset seems to load completely because in the view
every column is populated
Question 2: the 'order' criteria is being ignored. Do I have the wrong
syntax? The result is still sorted by 'id'.
Question 3: the like condition is also ignored, although it arraives
in the parameter array:
E.g.:
Array
(
[conditions] = Array
(
[Textmaster.katalogobjekt_id] = 1
[Textmaster.sprache_id] = 1
[Textmaster.textinhalt LIKE] = %Modern%
[Textmaster.suchkriterium LIKE] = %ACE109%
)
[fields] = Array
(
[0] = Textmaster.id
[1] = Textmaster.suchkriterium
[2] = Textmaster.textinhalt
)
[order] = Textmaster.suchkriterium ASC
[recursive] = -1
)
Any hints on what is going wrong are appreciated.
Anja C. Liebermann
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Re: Can't seem to do an update when calling save() on model
First value for auto_increment id in mysql == 1 Unless you tell it differently. You can have an autoincrementing field that starts at 21 and increments in 6's if you like :-) On Sep 9, 12:20 pm, Adam Royle [EMAIL PROTECTED] wrote: It is intended functionality. First value for auto_increment id in mysql == 1 Not sure about all other dbs, but on others I have worked with it is the same. On Sep 9, 9:06 pm, John Jackson [EMAIL PROTECTED] wrote: Thanks for the reply, but I now know that is the correct way to perform an update as I have just figured out what the problem was. Apparently, I can not use an id of 0. Changing the user's id to another value greater than 0 fixed the problem. Is this a bug or intended functionality? On Sep 9, 11:58 am, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote: Hi John, When calling save the id should be part of the data. Setting it on the Model before saving does not work as you expect it to. Are you sure the id is in the data array? /Martin On Sep 9, 12:34 pm, John Jackson [EMAIL PROTECTED] wrote: Pretty sure the code I'm using should be causing the save() function to do a MySQL update instead of insert: $this-User-id = 0; // static here for this example $this-User-save($this-data); But this is resulting in an insert, according to the output from debug level 2. What I'm trying to do is update a user's details for their account, including name, email and password. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: RE sometimes I wonder if cakeph is worth all the trouble - seems like very steep learning curve.
if every employee have to spend months learning this new platform then , must as well code directly in PHP ! If you don't want to learn a (new) framework, don't. A couple of months learning CakePHP will pay itself back in no time due to increased productivity ;-) On Sep 8, 6:29 am, James Chua [EMAIL PROTECTED] wrote: if every employee have to spend months learning this new platform then , must as well code directly in PHP ! Date: Mon, 8 Sep 2008 02:02:41 +0530 From: [EMAIL PROTECTED] To: cake-php@googlegroups.com Subject: Re: dropdown with country,state,city I know that , iwant drop down with pach country,state,city. On Mon, Sep 8, 2008 at 1:58 AM, Bernhard J. M. Gr黱 [EMAIL PROTECTED] wrote: Yes it is possible. Look into the manual (FormHelper - input (select box)). There are many examples you can look at. 2008/9/7 Ranju [EMAIL PROTECTED] I want implement dropdown with country ,state,city.It is possible on cakephp .pls help me. _ Manage multiple email accounts with Windows Live Mail effortlessly.http://www.get.live.com/wl/all --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Scaffolding doesn't work with themes?
Using CakePHP 1.2.0.7296 RC2
I've been having a dabble with the built in support for themes
( http://book.cakephp.org/view/488/Themes )
I've set up a theme using the instructions in the CakePHP docs above
and updated AppModel to use themes:
class AppController extends Controller {
var $view = Theme;
var $theme = my_theme;
}
I have a simple controller set up to produce scaffolding views:
function EventsController extends AppController {
var $scaffold;
}
but when I visit the events index page I get the following error:
Missing View
Error: The view for EventsController::index() was not found.
Error: Confirm you have created the file: D:\webroot\projects\cake_css
\app\views\themed\my_theme\events\index.ctp
Why is it looking for an events index view and not scaffolding one as
expected?
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Re: how can I see all the postings I ever posted in this user group ?
You can find a complete posting history on your google groups profile: http://groups.google.com/groups/profile?myprofile On Sep 6, 11:40 pm, xfh [EMAIL PROTECTED] wrote: how can I see all the postings I ever posted in this user group ? If I search this group with my user name only 2 of some more postings will show up multiply, but I wanted to see all my postings, so I can see if someone has replied to them. Also, when finished posting, I didn't see where I get a link to my posting so I could copy paste that for docu. Haven't found a help or manual etc. function for this user group yet. Does someone know how these things work ? thx, f --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: using javascript with form element
More info please :-) On Aug 31, 3:50 pm, assaggaf [EMAIL PROTECTED] wrote: i wanna to know how to make event for simple input --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: $this-element() and Model:$_schema
bump?
On Aug 24, 1:52 pm, RichardAtHome [EMAIL PROTECTED] wrote:
Also (may be related), in the element, why doesn't the following work?
?php
echo $html-css(array(
element.site_search
), null, array(), false);
?
(the CSS file isn't being linked in the head)
It works if the last param is true, but the code is embeded in the
page and not the head.
On Aug 24, 11:27 am, RichardAtHome [EMAIL PROTECTED] wrote:
I have a simple element:
site_search.ctp:
?php echo $form-create(Search) ?
?php echo $form-inputs() ?
?php echo $form-end(Search) ?
Model Search is a tableless model which I manually create the schema
for:
search.php:
class Search extends AppModel {
var $useTable = false;
var $_schema = array(
search_for=array(
type=string,
length=128
)
);
}
Problem: The inputs() call in the element is coming back blank. It
works fine if I point the form at a model (ie. it generates the
inputs) with a real database table behind it, but not for one with a
$_schema.
I tried adding:
App:Imort(model, Search);
to the element, but that didn't help.
How do I get an element to 'see' a model in this way?
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Re: it would be helpfull if you could post the solution
CakePHP is very clever, but it doesn't have a mind reading module (yet). Give us some details please :-) On Aug 30, 12:04 pm, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote: I read the manual and the ibm code and they are the same. How did you solve the problem ? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: CakePHP on IIS 6 - open_basedir restriction in effect
After more digging, I've managed to get rid of the open base dir error
(comment out open_basedir setting in php.ini)
Now I have another issue...
Under Apache, the following code:
?php echo Router::url(/user_muses/foo.jpg/
produces the following output:
/app/webroot/user_muses/foo.jpg
Under IIS, it breaks because the output is:
/index.php/app/webroot/user_muses/foo.jpg
And the images are broken.
Note: This only happens when I use Router::url(). If I use the built
in $html-image() to display images the urls are correct.
Obviously, I can't use $html-image() in this case as the images are
stored in a different location.
I get a similar problem when I try an embed a flash application too.
How do I remove index.php from the urls on IIS?
On Aug 26, 5:23 pm, RichardAtHome [EMAIL PROTECTED] wrote:
After a bit of struggling, I've managed to get a CakePHP app running
on IIS.
I've running it without mod_rewrite so I followed the instructions in
core.php and removed .htaccess files and uncommented the line:
Configure::write('App.baseUrl', env('SCRIPT_NAME'));
I've installed my cake app into:
c:\Inetpub\php_test\
I'm getting an error in a couple of places in my code, along the lines
of:
Warning (2): file_exists() [function.file-exists]: open_basedir
restriction in effect. File(/index.php/app/webroot/user_backgrounds/
1.xml) is not within the allowed path(s): (c:\Inetpub) [APP\views
\elements\painter.ctp, line 133]
Reading a bit further I've made the changes to /app/webroot/index.php
/**
* The full path to the directory which holds app, WITHOUT a
trailing DS.
*
*/
if (!defined('ROOT')) {
define('ROOT', \\Inetpub\\php_test);
}
/**
* The actual directory name for the app.
*
*/
if (!defined('APP_DIR')) {
define('APP_DIR', \\Inetpub\\php_test\\app\\);
}
/**
* The absolute path to the cake directory, WITHOUT a trailing DS.
*
*/
if (!defined('CAKE_CORE_INCLUDE_PATH')) {
define('CAKE_CORE_INCLUDE_PATH', \\Inetpub\\php_test);
}
What am I missing/doing wrong?
Thanks in advance :-)
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Re: How do you specify custom properties in a CakePHP model?
A CakePHP Model is just a PHP class. You can still use all of PHP's
class abilities.
for example:
class MyModel extends AppModel {
var $myCustomPropery = w00t!;
}
in controller:
echo $this-MyModel-myCustomProperty;
On Aug 28, 2:19 pm, Dardo Sordi Bogado [EMAIL PROTECTED] wrote:
I don't get what you mean with custom properties. Maybe it's just me
but, can you elaborate a bit more please?
On Thu, Aug 28, 2008 at 2:03 AM, trustfundbaby [EMAIL PROTECTED] wrote:
How do you specify custom properties in a CakePHP model?
I'm trying to do this, but there is no sample code any where that
shows how its done, can someone point me in the right direction?
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Re: Simple is Hard, talked by Rasmus Lerdorf @ FrOSCon 2008
Just my two cents: CakePHP is fast enough for me :-) That's not to say you shouldn't optimize for speed at some point in the future. I just mean, it shouldn't be a priority. Keep doing what your doing Cake dev's. Cake hasn't become one of the most popular PHP frameworks because of its speed ;-) On Aug 28, 4:11 pm, kiang [EMAIL PROTECTED] wrote: Maybe there could be one page like 'Read first before benchmarking' in home page since there exists many mis-understandings around the world. :) --- kiang On Aug 28, 10:41 pm, Gwoo [EMAIL PROTECTED] wrote: One thing we know for sure is that we can always work to improve the speed. However, we will not do it in earnest until the time is right. We have been here before, seen similar things, and come up with the answers. While the hello world is pretty silly, a couple of things strike me right off the bat. For one, var $helpers = array() will still load 3 files, while setting it to null will stop all loading. So, in a lot of ways Cake shows up slower because it does more from the start. The other major place is the session handling. We have no idea what his settings were in this regard. In any case, now that we are deeper into the RC cycle you will see in the timeline many efforts to improve and optimize the responsiveness of the framework. If you would like the historical perspective have a look at what happened in 1.1 between the 1.1.13 and 1.1.17 releases. We have a history of squeezing speed out of this language and framework and we prepared to do it again. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: help with 'updated' and 'created' fields: Do I need to manually unset these fields in the data array?
The automagic fields should be called created and modified (not updated). You don't need to do anything else. On Aug 27, 8:29 am, MarcS [EMAIL PROTECTED] wrote: Hi, I just noticed that my 'updated' field won't update when I update data. I tried around for a while and then noticed that it won't update when the 'update' field is included in the Model's data array. But when I load data using Model::read(null,$id) the date fields are obviously always included in the Model's data. Do I then need to always manually unset them before saving? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: radio buttons with form helper - lots of problems?
What tram said... change the field to an Int. Mysql tinyint datatype
has traditionally been used to store boolean data as MySQL doesn't
have a boolean datatype.
Alternatively, use a 1 byte char field.
Or change your options to be
null = Pending (the database default)
0 = Disapprove
1 = Approve
Or use an enum. Note: enums are mysql specific and are not directly
supported by cake. This doesn't mean you can't use them though (cake
treats them as a standard varchar field). There are some behaviours
out there that can help with enums.
As to the white screen of death, check out the httpd error logs and
the cake error logs (app/tmp/logs/error.log)
On Aug 26, 11:45 pm, [EMAIL PROTECTED] wrote:
oh cmon you dont expect good anwers when you're bashing the fw like that ?
cake interprets int(1) as bool , its a design choice. you are welcome
to update the book.cakephp.org to reflect that.
white screen of death - sorry im not getting it with your code, you
sure the radio call is causing it ?
On 8/27/08, Mark (Germany) [EMAIL PROTECTED] wrote:
oh my gosh
cake again.. typical
by using TINYINT(1) it is assumed that you have a checkbox toggle with
0 and 1 as values i guess.
anyway, after changing it to TINYINT(2), this automagic correction is
no longer active
and my value now is -1 in the Database
Where in the documentation did i miss that?
Are there more of these automatic corrections where a normal cake user
would not assume it?
PS: about the white screen of death - anyway - are there any solutions
to it?
other than having to use a dummy default?
thx mark
On 26 Aug., 23:37, Mark (Germany) [EMAIL PROTECTED]
wrote:
Well - CakePHP and Rapid Development can be two things that dont get
along with each other sometimes.. :)
i try for hours now...
first of all if you do not set a default value cake crashes completely
- white screen of death all of the sudden:
$form-input('status',array('type'='radio','options'=array(1=Disapprove',
1='Approve'),'legend'=false));
so i was forced (i really hate that - if i am forced to workaround
something) to add a dummy pending one:
$form-input('status',array('type'='radio','options'=array(0='Pending',-1=Disapprove',
1='Approve'),'legend'=false));
ok, so far so good, but
in the second code sample (i tried with both integer -1 0 1 and '-1'
'0' '-1'), the -1 always gets changed to 1 when saved to the database
- i debugged it and found out, that it is (inside of $this-data)
still -1 after validation and - i did not believe it - after having
saved the fields. so cake transformes it wrongly or something when
saving it.
the DB table setting is:
`status` tinyint(1) NOT NULL default '0' COMMENT '-1 dissap. 1
approved',
so neg. values should be no problem...
and the query clearly shows that it is cake's fault:
UPDATE `role_applications` SET `id` = 2, `status` = 1, `check_text` =
'somehting', `adminonly_text` = 'whatever', `checked_by` = 1,
`check_date` = '2008-08-26 23:34:29' WHERE `role_applications`.`id` =
2
anyone an idea what is going on?
how can i use negative values for radio buttons then?
if this goes on, i wont have any project done by the end of next
year..
mark
--
Marcin Domanskihttp://kabturek.info
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Re: How to test the database connection?
This is how Cake does it in the scaffold home page:
?php
if (isset($filePresent)):
uses('model' . DS . 'connection_manager');
$db = ConnectionManager::getInstance();
$connected = $db-getDataSource('default');
?
p
?php
if ($connected-isConnected()):
echo 'span class=notice success';
__('Cake is able to connect to the database.');
echo '/span';
else:
echo 'span class=notice';
__('Cake is NOT able to connect to the
database.');
echo '/span';
endif;
?
/p
?php endif;?
On Aug 26, 8:33 pm, aranworld [EMAIL PROTECTED] wrote:
I wonder if we have the same web host ... Hostway perhaps?
I am just in the middle of figuring this out as well and I came across
the following code that I believe still works, however, I must warn
you that I have not tested this out fully, but maybe this will at
least put you in the right direction?
$db = ConnectionManager::getDataSource('default');
if(empty($db-connection)){
// you don't have a connection
}
On Aug 26, 10:55 am, Samuel DeVore [EMAIL PROTECTED] wrote:
I use the php functions for connecting to the database and then
redirect if it fails to a static page, usually from bootstrap.php if I
find that it becomes a problem on a host.
Sam D
--
(the old fart) the advice is free, the lack of crankiness will cost you
- its a fine line between a real question and an idiot
http://blog.samdevore.com/archives/2007/03/05/when-open-source-bugs-m...
On Tue, Aug 26, 2008 at 10:51 AM, bbf [EMAIL PROTECTED] wrote:
My flaky webhost's MySQL process goes down randomly every few weeks.
Cake doesn't throw an error, but instead gives a Missing Table error
and displays a weird page (the layout nested 4 times).
How and where would I test the db connection myself?
(I want to show my own pretty Temporarily down for maintenance msg
-- I know how to throw and show the error, I just don't know where to
put the code that tests the connection)
Thanks!
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Re: Forms not associated to models - alternative to the Form core helper?
You may not think it now but your form IS related to a model ;-)
See Jonathan snooks example of a contact form:
http://snook.ca/archives/cakephp/contact_form_cakephp/
Jonathan creates a tableless model and defines the schema by hand.
That way you get all the benefit of cake's helpers (validation etc.)
On Aug 26, 5:29 pm, Enrique Delgado [EMAIL PROTECTED] wrote:
Thanks Samuel and validkeys.
Samuel, very true, I do like extending the functionality of CakePHP,
that is probably one of the best ways to go when we need something
more custom.
This time, I had totally overlooked the regular Form helper methods
like text(), password(), etc. Thanks validkeys for pointing this out.
I was getting too caught up and spoiled by the input() automagic
method, my bad.
Using the regular methods works just fine.
Thanks!
On Aug 26, 11:15 am, validkeys [EMAIL PROTECTED]
wrote:
Hey Enrique,
You could still use the regular forms:
?php echo $form-create('Search',array('url' = '/search','type' =
'get')) ?
?php echo $form-text('query',array('type' = 'textarea')) ?
?php echo $form-end('Search!') ?
On Aug 26, 11:45 am, Enrique Delgado [EMAIL PROTECTED]
wrote:
Hi All,
The core Form helper works great as long as you have a model behind
it, but what about forms that are not related to a model?
Is there any helpers that I can use in the view? Or do I just code
plain HTML?
Thanks!
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Re: three level deep belongsTo
@wisecounselor
never mind, sorry to bother you, knew this was a waste of time
Um, AD7six answered your question later on in his post. That is why he
asked you if you'd continued reading...
On Aug 25, 7:49 pm, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
never mind, sorry to bother you, knew this was a waste of time.
On Aug 25, 1:18 pm, AD7six [EMAIL PROTECTED] wrote:
On Aug 25, 8:13 pm, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
sorry, I think I follow, maybe more specific objects will help, I have
Patient - Diet Plans - Diet Calendar Day
So Patient hasMany diet plans with each Diet Plan having many Diet
Calendar Days
I need to draw a screen of all patients and loop through 2 weeks of
the calendar, filling in details of each day for each patient, but I
need to be able to filter this at times by Patient last name,
sometimes by a field in Diet Calendar Days and other times in a field
in the Diet Plan. So they way I have it, I can't do Patient-
find('all',array('condition' = 'DietPlan.active' = 1));
or
Patient-find('all',array('condition' = 'DietPlanDay.exception' =
1));
Did you stop reading at why the abstract names? ?
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Re: Auth Component on Zeus Hosting
I had exactly this issue before but setting the security setting from High to Medium fixed it for me. Check your httpd error logs for any warnings about missing files/ images etc. On Aug 27, 11:23 am, AussieFreelancer [EMAIL PROTECTED] wrote: ok, so no whitespace, but still not sure what is causing it.. still the same issue, doesn't seem to like the sessions very much and kicks me out randomly... has no-one had this before? On Aug 7, 9:46 pm, Dardo Sordi Bogado [EMAIL PROTECTED] wrote: Also check for whitespace:http://bin.cakephp.org/view/1837474952 On Thu, Aug 7, 2008 at 4:35 AM, AussieFreelancer [EMAIL PROTECTED] wrote: Hmm, I changed it from High to Medium with no effect, and also to Low without having any effect either... I will double check the links for non-existent files, this could be something to do with it, as if i press refresh a couple of times quickly it logs me out, not sure this is what is happening every time, but I know that refreshing twice fast certainly does it... So no known issues with sessions and Zeus or anything like that? Thanks Patrick On Aug 6, 6:46 pm, acoustic_overdrive [EMAIL PROTECTED] wrote: This is probably not server-specific, but on one application I was building it took me ages to realise why sometimes I was getting logged out and other times not. I eventually realised that I had a CSS link that was pointing at a non-existent file, and this caused the page to continue trying to load it in the background. If I cancelled the page loading prematurely by clicking on a link and visiting another page, I would stay logged in. But if I allowed the page to complete its loading, it would log me out. When I corrected the broken link it behaved fine again. That was not using the latest release so perhaps newer versions are OK. On Aug 6, 3:21 am, AussieFreelancer [EMAIL PROTECTED] wrote: Hello, I have a client who's website is hosted on a server powered by zeus instead of apache. I have already run into issues with the rewrite which are now resolved, but there seems to also be an issue with the Auth components... I have an administration panel as a plugin, which works on other sites, but for some reason, on this particular site, it randomly kicks the user out. Sometimes I can't even get to one page without it kicking me out, other times i can update 5 things and then it will kick me out... does anyone know why this is? I have security set to low, I thought that maybe it was to do with that but doesn't seem to have made a difference... Would love to hear any suggestions on how to resolve this as the admin panel isnt really usable until it is fixed.. Thanks Patrick --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: auth-loginError
Have you added the code to your view to display the error?
http://book.cakephp.org/view/564/displaying-auth-error-messages
On Aug 27, 10:22 am, luigi7up [EMAIL PROTECTED] wrote:
My
$this-Auth-loginError ='Invalid username or password';
won't show on login.ctp view
This is what I have in app_controller:
var $components = array('Acl','Auth');
function beforeFilter(){
//Mijenja hash funkciju auth komponente iz defaultne
u md5
Security::setHash('md5');
$this-Auth-fields = array('username' = 'username',
'password' =
'password');
$this-Auth-loginAction = array('controller' =
'users', 'action'
= 'login');
//$this-Auth-loginRedirect = array('controller' =
'users',
'action' = 'index');
$this-Auth-loginError ='Invalid username or
password';
$this-Auth-logoutRedirect = '/';
$this-Auth-authorize = 'controller';
}
/*When authorize is set to 'controller',
you'll need to add a method called isAuthorized() to your
controller.
This method allows you to do some more
authentication checks and then return either true or false.*/
function isAuthorized() {
return true;
}
In users_controller my login() is empty because Auth component
automagic
and when I debug my session with debug($_SESSION); I see that error is
sent, but it si always set - even when I call users/login action for
the first time (I mean without submiting wrong data)?!?!:
Array
(
[Config] = Array
(
[userAgent] = 0f8a6ac2e2c891dce1f3f114fdaad715
[time] = 1219830026
[rand] = 32701
[timeout] = 10
)
[Message] = Array
(
[auth] = Array
(
[message] = Invalid username or password
[layout] = default
[params] = Array
(
)
)
)
How can I get this login error working?
thanks
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Re: help with 'updated' and 'created' fields: Do I need to manually unset these fields in the data array?
Quote: One thing I came across was the fact that the columns for created updated should be of the type datetime and Null should be set to 'null' and not 'not null' Oops, forgot to mention that :-( On Aug 27, 4:21 pm, teknoid [EMAIL PROTECTED] wrote: Makes sense that it works like that... how/where are you modifying the data if you are just doing a read()? On Aug 27, 5:02 am, Marc Schuetze [EMAIL PROTECTED] wrote: According to the docs 'modified' and 'updated' are both ok. I tried this with 'modified' as well and it was the same result When I do $this-create(array(.)) and that array doesn't contain an update field then everything is fine and cake sets the update field properly. However, when I do $this-read(null,$id) the model's data array will contain the update field and it seems like I'll then have to manually unset it if I want to update the time in the field. If I don't do that cake will not fill the update field with a new value but will use the value that is is the model's data array On Wed, Aug 27, 2008 at 10:58 AM, RichardAtHome [EMAIL PROTECTED] wrote: The automagic fields should be called created and modified (not updated). You don't need to do anything else. On Aug 27, 8:29 am, MarcS [EMAIL PROTECTED] wrote: Hi, I just noticed that my 'updated' field won't update when I update data. I tried around for a while and then noticed that it won't update when the 'update' field is included in the Model's data array. But when I load data using Model::read(null,$id) the date fields are obviously always included in the Model's data. Do I then need to always manually unset them before saving? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Auth Component - I'm going crazy
Sounds like the Auth component is redirecting you away from a
protected page, to another protected page - hence the loop.
In your Users controller do you have a login action?
On Aug 26, 9:19 am, luigi7up [EMAIL PROTECTED] wrote:
I'll try this. I read about this but I thought they were talking about
other databases and not MySql.
thx...
On Aug 26, 8:57 am, aranworld [EMAIL PROTECTED] wrote:
I have had situations in which I was unable to use a column named
password and had to instead use something like passwd. I believe
it is a reserved keyword issue with MySQL? Not sure if it was just
related to an older version, but you might at least try changing the
column name.
-Aran
On Aug 25, 12:32 pm, luigi7up [EMAIL PROTECTED] wrote:
Ola, everyone...
//Using RC2 version of CakePHP
I'm building simple application that allows users to write articles.
So there are their corresponding models and controllers.
Few days ago I made custom Login/register part of application that
writes username to session etc. but now I decided to use Auth
component for this purpose.
As soon as I define:
var $components = array('Auth');
in my users_controller or app_controller, application stops working.
Firefox gives following error: Firefox has detected that the server
is redirecting the request for this address in a way that will never
complete. So, some infinite loop occured definitely and I'm quite
sure that I didn't cause it :)
I found few posts about this problem but none of them resolves my
problem.
The weirdest thing,to me, is that error occurs as soon as I include
Auth component; I don't even use one method of that class ?!?
Also another confusing part with this problem is that my other
controllers also stop working with same output eventhough component
Auth is included only in users_controller. User model is in
association with articles model but I think that articles_controller
shoud with or without component Auth included in users_controller. Am
I wrong?
My database is USERS and has fields username and password and also
there is a model for users table.
Thanks in advance
Luka
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CakePHP on IIS 6 - open_basedir restriction in effect
After a bit of struggling, I've managed to get a CakePHP app running
on IIS.
I've running it without mod_rewrite so I followed the instructions in
core.php and removed .htaccess files and uncommented the line:
Configure::write('App.baseUrl', env('SCRIPT_NAME'));
I've installed my cake app into:
c:\Inetpub\php_test\
I'm getting an error in a couple of places in my code, along the lines
of:
Warning (2): file_exists() [function.file-exists]: open_basedir
restriction in effect. File(/index.php/app/webroot/user_backgrounds/
1.xml) is not within the allowed path(s): (c:\Inetpub) [APP\views
\elements\painter.ctp, line 133]
Reading a bit further I've made the changes to /app/webroot/index.php
/**
* The full path to the directory which holds app, WITHOUT a
trailing DS.
*
*/
if (!defined('ROOT')) {
define('ROOT', \\Inetpub\\php_test);
}
/**
* The actual directory name for the app.
*
*/
if (!defined('APP_DIR')) {
define('APP_DIR', \\Inetpub\\php_test\\app\\);
}
/**
* The absolute path to the cake directory, WITHOUT a trailing DS.
*
*/
if (!defined('CAKE_CORE_INCLUDE_PATH')) {
define('CAKE_CORE_INCLUDE_PATH', \\Inetpub\\php_test);
}
What am I missing/doing wrong?
Thanks in advance :-)
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Re: Allowing entire controllers with Auth component
I'd do it this way round:
parent::beforeFilter();
$this-Auth-allow(array('display'));
So the controllers can override settings in AppController
On Aug 24, 8:44 am, tekomp [EMAIL PROTECTED] wrote:
Thanks Sam. Got it to work after realizing that display is a built-
in action to the built-in pages controller.
On Aug 23, 8:22 pm, Sam Sherlock [EMAIL PROTECTED] wrote:
try
$this-Auth-allow(array('display'));
parent::beforeFilter();
2008/8/23 tekomp [EMAIL PROTECTED]
I'm using the Auth Component in my app_controller.php in the
beforeFilter function, which is great for making people login, but I'm
having a hard time allowing certain pages. I want all pages in my
Pages controller to not require authorization, so I added $this-
Auth-allow('*') in my beforeFilter in pages_controller.php.
Problem with that is that it overrides the beforeFilter in
app_controller.php and I cannot access $this-Auth. I tried adding
parent::beforeFilter in pages_controller.php, but it then does not
recognize my $this-Auth-allow('*').
I've tried a number of things and read all the tutorials I could find,
but still can't find a way to allow an entire controller while
maintaining this-Auth. It doesn't seem right that I'd have to add
the Auth code to each individual controller.
Any ideas?
Thanks.
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Re: Database relationships etc
Nothing to add apart from props to Rafael for an excellent answer.
On Aug 23, 2:05 am, Rafael Bandeira aka rafaelbandeira3
[EMAIL PROTECTED] wrote:
Oh, I almost slept, you should try to more clear and less verborragic,
so many explanation just messed up things more and more...
And you should do 2 things when you can't speak a language : 1) look
for groups with the same language of yours and 2) say your
nacionality, so members from the same country can get sensible with
you and try to help you more
stop the bullshit and answer me...
OK, answers :
1) Do I have to manually set up Foreign keys for tables?
it depends, did you sitcked to conventions?
Your CarAd Model has the following scheme and linking convention:
id - primaryKey
car_type_id - className = CarType, uses table -
car_types
car_brand_id - className = CarBrand, uses table -
car_brands
car_fuel_id - className = CarFuel, uses table
- car_fuels
car_transmission_id - className = CarTransmission, uses
table - car_transmissions
year
ad_county_id - className = AdCountry, uses table
- ad_countries
ad_borough_id - className = AdBorough, uses table -
ad_boroughs (?)
info
price
car_ad_type_id - className = CarAdType, uses tabl -
car_ad_types
added - tip : is this field meant to hold the
datetime of row creation? if yes, rename it to created and cakePHP
will handle it for you
Said that all this foreign keys says : this CarAd belongs to this
CarType, and to this CarBrand, and to that CarFuel... so you should
have in your model class:
class CarAd extends AppModel {
var $belongsTo = array (
'CarType', 'CarBrand', 'CarFuel', 'CarType',
'CarTransmission', 'AdCountry', 'AdBorough',
)
}
now CakePHP will map all your model's foreign keys and you will be
able to access this relateds models as a property of your CarAd
model :
// inside your model
$this-CarType-find([...]);
inside your controller
$this-CarAd-CarType-find([...]);
answered? moving on...
2) Do I have to build model for each table I need to get id's
from..even if the table itself will stay static ? (model for
car_transmissions, car_fuels_id... tables)
No, actually CakePHP map table names for you too.
http://www.littlehart.net/atthekeyboard/2008/08/05/dynamic-models-in-...
By static I mean that I don't need to add or delete data from it
because probably there will not be any new transmission types
coming. I only need to read info from it.
I know 100% that I have to build model for tables which will have
dynamic content...like table car_brand. (new car brand comes.. for ex.
BMW-Jaguar..and I need to add it to table from site...not manually)
you should avoid this kind of thinking...
So my main table at this time is car_ads and I have controller for
it... and it also gives me it's table contents with simple index():
function index() {
$this-set('carads',$this-CarAd-find('all'));
}
But I want to see text in the list..not that number which I have on
car_transmission_id field. (Instead of number 1 I would like to see
text: Automatic)
Currently line looks like this: Brand: 5 Year: 2000 Transmission: 1
Gas: 2
But it should look like this: Brand: Chevrolet Astro Year: 2000
Transmission: Automatic Gas: Benzine
No actually it shouldn't, what is happening is the normal and expected
behavior.
I'll explain what is already in the manual about cakePHP's data
scheme, I'll wont reproduce arrays here because it would be very ugly
and painfull for me so take this as example
:http://book.cakephp.org/view/448/findall
- the grey box at the bottom of the content...
that's how your data will return but with the your model names...
back to your CarAdsController::index() :
function index() {
$this-set('carads',$this-CarAd-find('all'));
}
in your view you will have a var named 'carads', and you'll be able to
access data as the array in the link shows :
// first entry's CarTransmission.transmission wil be accessed like
this
echo $carads[0]['CarTransmission']['transmission'];
// the nth entry/row CarBrand.name will be accessed like this
echo $carads[$num]['CarBrand']['name'];
for a dynamic list or table generation, you would do something like
this:
foreach($carads as $entryNum = $entryData)
{
echo 'Transmission: ' . $entryData['CarTransmission']
['transmission'];
echo 'Brand : ' . $entryData['CarBrand']['name'];
echo 'Country : a href=/view/country/' . $entryData['CarCountry']
['id'] . ' title=view country:' . $entryData['CarCountry']
['name'] . ' ' . $entryData['CarCountry']['name'] . '/a';
}
I'll try to explain it once more..maybe it helps to clear things out:
you actually didn't explain
$this-element() and Model:$_schema
I have a simple element:
site_search.ctp:
?php echo $form-create(Search) ?
?php echo $form-inputs() ?
?php echo $form-end(Search) ?
Model Search is a tableless model which I manually create the schema
for:
search.php:
class Search extends AppModel {
var $useTable = false;
var $_schema = array(
search_for=array(
type=string,
length=128
)
);
}
Problem: The inputs() call in the element is coming back blank. It
works fine if I point the form at a model (ie. it generates the
inputs) with a real database table behind it, but not for one with a
$_schema.
I tried adding:
App:Imort(model, Search);
to the element, but that didn't help.
How do I get an element to 'see' a model in this way?
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Re: $this-element() and Model:$_schema
Also (may be related), in the element, why doesn't the following work?
?php
echo $html-css(array(
element.site_search
), null, array(), false);
?
(the CSS file isn't being linked in the head)
It works if the last param is true, but the code is embeded in the
page and not the head.
On Aug 24, 11:27 am, RichardAtHome [EMAIL PROTECTED] wrote:
I have a simple element:
site_search.ctp:
?php echo $form-create(Search) ?
?php echo $form-inputs() ?
?php echo $form-end(Search) ?
Model Search is a tableless model which I manually create the schema
for:
search.php:
class Search extends AppModel {
var $useTable = false;
var $_schema = array(
search_for=array(
type=string,
length=128
)
);
}
Problem: The inputs() call in the element is coming back blank. It
works fine if I point the form at a model (ie. it generates the
inputs) with a real database table behind it, but not for one with a
$_schema.
I tried adding:
App:Imort(model, Search);
to the element, but that didn't help.
How do I get an element to 'see' a model in this way?
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Re: Focus On cake Validation
A quick bit of jQuery: $(#content form:first div.error:first input:first).focus(); Will focus the first errored input field on the first form in the #content div. It will fail silently if the first input element on the forum is not a input control (a textarea for example). [EMAIL PROTECTED] wrote: hello guys in my cakephp project i uses the cake validation witch uses server side validation , i need it to focus on the error field after detecting it so how can i do something like this ?? since the focus can be done with a client side validation , so im wondiring if there is any way in cake to do that in the same validation process . --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Focus On cake Validation
Typo: It will fail silently if the first errored input element on the form is not a input control (a textarea for example). Might be possible to expand the rule to include other input element types... On Aug 24, 10:14 pm, RichardAtHome [EMAIL PROTECTED] wrote: A quick bit of jQuery: $(#content form:first div.error:first input:first).focus(); Will focus the first errored input field on the first form in the #content div. It will fail silently if the first input element on the forum is not a input control (a textarea for example). [EMAIL PROTECTED] wrote: hello guys in my cakephp project i uses the cake validation witch uses server side validation , i need it to focus on the error field after detecting it so how can i do something like this ?? since the focus can be done with a client side validation , so im wondiring if there is any way in cake to do that in the same validation process . --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Should I be using a custom query?
$contacts = $this-Contact-find('first',
array(
'conditions' =
array('Contact.jobType' = 'main)
)
);
Note the 'first' parameter.
On Aug 22, 12:40 am, eagle [EMAIL PROTECTED] wrote:
Hi,
First of I'm new to Cake and tryign it out for the first time - I've
searched here and on Google to solve what I suspect will be an
idiotically simple question
Two tables:
VENUES hasmany CONTACTS
all linked in the models correctly
On my default view of the venues table I want to filter the contacts
to display only one of the potentially many based on a field value of
'main'.
venues_controller::index() is
$this-Venue-recursive = 1;
$this-set('venues',$this-paginate('Venue'));
$venues = $this-Venue-find('all');
and contacts_controller::index() is
$this-Contact-recursive = 1;
$contacts = $this-Contact-find('all',
array(
'conditions' = array('Contact.jobType' =
'main)
)
);
$this-set('contacts', $contacts);
I can retrieve all contacts for a venue on the index view for venues,
but I only want the 'main' one.
Should I set up a custom query in the venues_controller to do this? Or
am I missing somehting more obvious?
Thanks for any guidance.
Eagle
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Re: how to do multiple hasmany
You need to combine them both into 1 hasMany array:
var $hasMany = array(
'Childclass1' = array(
'className' = 'Childclass1'
),
'Childclass2' = array(
'className' = 'Childclass2'
)
);
On Aug 22, 12:43 am, robert123 [EMAIL PROTECTED] wrote:
i have parent model, it has two hasmany child model,
in the model class, I tried to model this relation by writing two time
in the parent model class
var $hasMany = array('Childclass1' =
array('className' =
'Childclass1');
var $hasMany = array('Childclass2' =
array('className' =
'Childclass2');
but it giving me the below error
Cannot redeclare Childclass2::$hasMany
anyone can let me know, how to solve this, thank you
http://www.generics.ws/jpn/レビトラ（塩酸バルデナフィルHCL_）に20_MGについて-p-115.htmlhttp://www.generics.ws/jpn/プロペシア（フィナステライド）-p-4.htmlhttp://www.generics.ws/jpn/バイアグラ（クエン酸シルデナフィル）-p-2.html
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Re: User Authentication Methods
In a nutshell: Auth tells you who they are ACL tells you what they can do once you know who they are On Aug 21, 10:01 am, Penfold [EMAIL PROTECTED] wrote: Hi cem, have a look at http://bakery.cakephp.org/articles/view/authext-a-small-auth-extensio... this is a good out the box acl/auth component. it will get you up and running and is easy to follow. On 21 Aug, 09:23, cem [EMAIL PROTECTED] wrote: Thank you very much . But I have an example which really confuses me . Auth component is used for user login authentication and logout. And adding the auth components beforefilter method to the AppController which runs all the authentication proces . So where do we need the ACL ? Thats why I am confused . I am reading articles about the ACL and in the articlesthey never use Auth component for permission authentication . --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: need help with passing into Element
What Fahmi said.
with
echo $this-renderElement('post_element', $post);
You are creating a variable in the element called $post_element (with
the value of $post)
The only reason its working for you at the moment is that you have
already created a variable in the view called $post:
foreach($posts as $post)
As all the variables share the same namespace, I would recommend:
echo $this-renderElement('post_element', $post);
and in the element, use $post_element to avoid confusion/overwriting
the $post in the view.
On Aug 21, 8:59 am, Fahmi Adib [EMAIL PROTECTED] wrote:
i think you should use an array,
array('post' = $post)
On Aug 21, 2008, at 2:56 PM, rocket wrote:
hey guys im passing this:
foreach($posts as $post)
echo $this-renderElement('post_element', $post);
}
but in my post_element i try to use
$post['title']
and it throws me this problem Notice: Undefined variable:
Am i missing something? i'm real confused and have spent like 1 hour
trying to debug this...
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Re: Multiple Inserts without a loop
I think the 1000 was for illustration only. I'd run a few quick benchmarks to see what the real difference between 1 insert with 1000 values() and 1000 queries would be. I'm betting it wont be much... On Aug 20, 11:04 pm, teknoid [EMAIL PROTECTED] wrote: AFAIK, the syntax you are proposing is MySQL (or at least DB vendor) specific. So, it won't be supported by cake. And do you really insert 1001 rows? On Aug 20, 5:51 pm, seth [EMAIL PROTECTED] wrote: Right, but how many inserts does this perform? - As many inserts as required Yes, but my whole point is that if you are inserting 1000 questions, this could be done in 2 interests or 1001... Is cake currently smart enough to do it in 2? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Clean urls in search form
Dunno about 'best', but this works:
In your view (search.ctp)
?php echo $form-create(Model, array(action=search,
type=get) ?
?php echo $form-input(search_for) ?
?php echo $form-end(Search) ?
?php foreach($results as $result) : ?
... output your result here
?php endif; ?
In your controller:
function search() {
if (isset($this-params['url']['search_for'])) {
$scope = array(@[EMAIL PROTECTED] LIKE
'.$this-params['url']
['search_for'].%');
}
else {
$scope = array();
}
$results = $this-Paginate(@Model, $scope);
$this-set(results, $results);
}
Replace @Model and @field with the name of the model and field you
want to search on.
On Aug 21, 1:10 pm, bitkidoku [EMAIL PROTECTED] wrote:
Hello everyone,
I am implementing a search form. But I want to make search results
linkable like: http://somehost/products/search/keyword; (keyword is
the word that is being searched).
What is the best practise to achieve this? And what if the user could
search defining many parameters like title, content, ingredients etc.?
I googled this but I couldn't find any meaningful results.
Thank you very much for your answers.
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Re: Problem with Cake and Vista
Did you reboot apache after you made changes to httpd.conf? And, btw, Cake with Apache PHP on Vista is entirely possible - I'm doing it right now :-) On Aug 19, 7:49 am, giulio [EMAIL PROTECTED] wrote: Hi, I'm new of cake php. I'm trying to install cakephp in windows vista, i downloaded and installed xampp and all seems to be fine. I've followed the instructions for cake php and it goes well. I've only some problems: 1- I can't see the graphic of the default cake php page, i read that it depends of configuratione of httpd.conf so i set the options FollowSyLinks to AllowOverride All and the correct path, but i've not solved the problem 2- I tried with a simple cake php application made by other (a todolist application ) but when i write the controllerhttp://localhost/todo/items i can see only the result Object not found... maybe are there problems with htaccess? I able mod rewrite. If someone has a file httpd.conf please send me this file to me, so i can solve all the configurations problems. Thanks Giulio --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: configure cake 1.2
Assuming you are using Apache 2.2: In apache.conf uncomment this line: LoadModule rewrite_module modules/mod_rewrite.so This will enable mod_rewrite You then need to allow cakephp .htaccess file to take over control of your webroot: In your Directory section for your webroot folder (mine is c: \htdocs): Directory C:/htdocs # # Possible values for the Options directive are None, All, # or any combination of: # Indexes Includes FollowSymLinks SymLinksifOwnerMatch ExecCGI MultiViews # # Note that MultiViews must be named *explicitly* --- Options All # doesn't give it to you. # # The Options directive is both complicated and important. Please see # http://httpd.apache.org/docs/2.2/mod/core.html#options # for more information. # Options Indexes FollowSymLinks # # AllowOverride controls what directives may be placed in .htaccess files. # It can be All, None, or any combination of the keywords: # Options FileInfo AuthConfig Limit # AllowOverride All # # Controls who can get stuff from this server. # Order allow,deny Allow from all /Directory Hope this helps :-) On Jul 17, 8:53 am, Russell [EMAIL PROTECTED] wrote: Hello, I m very new struggling with cake 1.2. Now I've 2 problems. 1) I m using wamp server in local host. After install cake1.2 in localhost, I m not getting cake default page (I mean with some color css etc), but I can get my page after routing from route.php file. Perhaps mod_rewrite is not enable in my httpd.conf file, In there on ly lines exist: LoadModule rewrite_module modules/mod_rewrite.so #AddModule mod_rewrite.c But, how can I enable mod_rewrite? 2) I m working with my own index page, where I started a simple blog. I create a link nameed add create add.thtml page. but, I m getting the page can not found error 404 after clicking the link!!! But it's working with cake 1.19... So, wheres the problem with cake1.2??? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: $this-Auth-user not refreshing after edit
The $this-Auth-reload() solution looks like a winner to me. No unnecessary database reads, and you can keep the Auth user up to date in responce to changes made by the user. Thanks for all the great feedback folks :-) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: table name directories created problems
Folder? On Jul 17, 2:53 pm, Jonathan Snook [EMAIL PROTECTED] wrote: This wasn't easy to track down but apparently there are 5 reserved class names in PHP: __PHP_Incomplete_Class, stdClass, exception, php_user_filter and. Directory!! http://ca3.php.net/manual/en/reserved.classes.php So, use another name. On Thu, Jul 17, 2008 at 7:11 AM, web [EMAIL PROTECTED] wrote: It is not the code that i was written, just write for this copy anyone please try to create a table named 'directories' and try to access it by accessing the controller and model according to the cake rules and conventions ... am sure you can not access . --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: redirect and header error but no white space
You can save yourself a *lot* of heartache with this issue by leaving
off the closing ? in your php files :-)
--- snip ---
?php
class TestController extends AppController {
function index() {
}
}
---end snip---
is enough, the closing ? is optional
On Jul 17, 2:20 pm, haj [EMAIL PROTECTED] wrote:
I'm using this editor on windows:
http://www.emeditor.com/
There is a checkbox in config menu if to add BOM or not for UTF-8.
Some editor may not have this feature.
On Jul 16, 1:07 pm, Stinkbug [EMAIL PROTECTED] wrote:
Excuse my stupidity on this topic, but I don't really understand
encoding at all. So how exactly do I save a a file without the BOM?
Does it require special software, or what? I'm on windows.
On Jul 14, 11:39 pm, haj [EMAIL PROTECTED] wrote:
So, I basically saved all UTF-8 files without BOM and now things works
beautifully.
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Re: Cake bake does not recognize relationships?
Try putting some data in your groups table. Cake will change the
textbox to a drop down select list.
On Jul 15, 10:35 pm, Renan Gonçalves [EMAIL PROTECTED] wrote:
Recognize relationships based on InnoDB relationships is planned to CakePHP
2.0.https://trac.cakephp.org/wiki/Proposals/2.0ToDoList
[]'s
On Tue, Jul 15, 2008 at 4:07 PM, Mech7 [EMAIL PROTECTED] wrote:
Does anybody know what could be wrong.. if I would bake my model /
controllers / views for users
it will just put a input text box for usergroup_id and in the model it
just says:
?php
class Users extends AppModel {
var $name = 'Users';
}
?
Here is the table setup..
---
CREATE TABLE `usergroups` (
`id` int(11) NOT NULL auto_increment,
`name` varchar(120) NOT NULL,
`created` datetime NOT NULL,
`modified` datetime NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
CREATE TABLE `users` (
`id` int(11) NOT NULL auto_increment,
`username` varchar(120) NOT NULL,
`password` varchar(120) NOT NULL,
`usergroup_id` int(11) NOT NULL,
`created` datetime NOT NULL,
`modified` datetime NOT NULL,
PRIMARY KEY (`id`),
KEY `fk_usergroup_id` (`usergroup_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
---
Does anybody know why it would not recognize the other table?
--
Renan Gonçalves - Software Engineer
Cell Phone: +55 11 8633 6018
MSN: [EMAIL PROTECTED]
São Paulo - SP/Brazil
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Re: Customizing the output of Form Helpers
Also, you can manually add the html tags and not rely on the helper. That said, the helper is *very* flexible and can accommodate a lot of customisations :-) On Jul 15, 12:33 pm, Dardo Sordi Bogado [EMAIL PROTECTED] wrote: HtmlHelper::tags could be a posibility. On Tue, Jul 15, 2008 at 12:20 AM, Jonathan Snook [EMAIL PROTECTED] wrote: Probably your best bet is to create your own helper that uses the base elements like $form-text and $form-error. Wrap your own HTML around those. Take a look at how $form-input does it and model yours around it. -Jonathan On 7/14/08, Tallbrick [EMAIL PROTECTED] wrote: I have been hitting Google hard for any tutorials on customizing the output of Cake's form helpers. Namely adjusting the output of radio and checkbox arrays using the 'automagic' form helpers. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: $this-Auth-user not refreshing after edit
How can this be the preferred behaviour?
What do you do if you get a 'bad' user? Even if you delete his user
record you are helpless to stop him until he voluntarily logs out!
Or, what if you have a regular user who needs his 'role' changing?
Granted, profile edits and changes in roles are required less often,
but the security issue alone is enough to warant a refresh on every
page. A quick read of the database is hardly going to kill the system.
On Jul 14, 2:50 am, Jonathan Snook [EMAIL PROTECTED] wrote:
On 7/13/08, RichardAtHome [EMAIL PROTECTED] wrote:
It looks like the Users model is only being read once at login and the
details stored in a session (not checked the cake code, but that would
match the behaviour I am experiencing).
Basically, the edit is working (ie, database gets updated), but the
$this-Auth-user() isn't.
I contend that this is the preferred behaviour. Refreshing the user
object stored in the session is unnecessary on 99% of the page views
(I suspect most users don't edit their profiles on a regular basis).
I suspect that it's just a simple storing of the current user in the
session (in Session-read('User')) but it'd be nice to have an
Auth-refreshSession() method that would refresh the current user in
the session. Maybe submit a ticket for that...
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Re: $this-Auth-user not refreshing after edit
Yes, but that 1% where it IS needed is critical ;-) I agree that a refresh method would be useful, and if present would allow me to add it to the App Controller to get the effect I'm after. That way everyone is happy :-) Anyone know how to refresh the user record? Is it simply a case of setting the Auth Session User var? On Jul 14, 9:58 am, AD7six [EMAIL PROTECTED] wrote: On Jul 14, 10:24 am, RichardAtHome [EMAIL PROTECTED] wrote: How can this be the preferred behaviour? What do you do if you get a 'bad' user? Even if you delete his user record you are helpless to stop him until he voluntarily logs out! Or, what if you have a regular user who needs his 'role' changing? Granted, profile edits and changes in roles are required less often, but the security issue alone is enough to warant a refresh on every page. A quick read of the database is hardly going to kill the system. And is, as Jonathan Snook pointed out, needless 99% of the time. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
