How to load SQL views in Fixtures for unit tests in Cakephp 3?
My application has some sql views to perform complex queries in the database and be better able to filter the results based on these values. One problem I encountered when running the unit tests is that Cake do not import sql views, just tables, breaking the application tests. *- How can I solve this problem?* *- Is there any other way to replace the SQL Views within the application?* -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups "CakePHP" group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/d/optout.
Controller Integration Testing not catching exceptions in Cake 3.x
Hi,
I'm having problems with integration tests in my json API in moment of
catch an exception thrown by the application.
In my *UsersController*:
request->allowMethod('get');
// ...
throw new \Cake\Core\Exception\Exception('catch me');
// ...
}
}
In my *UsersIntegrationTest*:
get('/users');
$this->assertResponseError();
}
}
The *$this->assertResponseError();* throws an Exception during the test run,
failing all other tests.
I've trying using:
$this->setExpectedException('\Cake\Core\Exception\Exception');
but I can't catch anything.
*How can I solve this?*
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CakePHP 3 - foreign_key - bin/cake bake all --plugin
Hi,
I have these two tables:
*- Articles*
-- id
-- title
-- body
-- type_id (foreign_key)
*- Types*
-- id
-- title
If i generate che scaffold code for the base application all is perfect,
controller, model and view.
bin/cake bake all Typesbin/cake bake all Articles
The *foreign key* is properly insert in the code.
*Articles Controller *-* Index example*
...
public function index()
{
$this-paginate = [
'contain' = ['Types']
];
$this-set('articles', $this-paginate($this-Articles));
$this-set('_serialize', ['articles']);
}
...
but if I decide to do the same for a plugin the foreign_key is not
recognized,
bin/cake bake all --plugin ExamplePlugin Typesbin/cake bake all --plugin
ExamplePlugin Articles
*PLUGIN - Articles Controller* - *Index example*
...
public function index()
{
$this-set('articles', $this-paginate($this-Articles));
$this-set('_serialize', ['articles']);
}
...
There is no reference to the foreign_key. It would seem only for the
*controllers*.
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CakePHP 3.X - Creating Reusable Validators
Hi everyone,
I'm studying *CakePHP 3.x.*
I have a form with three fields to change the password:
- *OLD Password*
- *NEW Password*
- *Confirmation NEW Password*
I would like to implement a validation for the *Old Password.*
To do this *I think it is necessary to create a custom Validators that
interacts with the ORM*.
The code on the manual suggests doing so:
*Creating Reusable Validators*
*example:*
// In src/Model/Validation/ContactValidator.phpnamespace App\Model\Validation;
use Cake\Validation\Validator;
class ContactValidator extends Validator{
public function __construct()
{
parent::__construct();
// Add validation rules here.
}}
Is this the procedure to follow?
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Re: Online baking tool for CakePHP
Brilliant !! excellent work. Makes my life so much easier as I am only developing online and not locally, and don't use the command line... Thanks On Wednesday, 10 April 2013 14:19:04 UTC+1, Christian Cadéré wrote: Petit Four is an online application dedicated to speed up the design and code generation of CakePHP projects. It allows to design the models of an application: fields, validation rules and relations, with a simple user interface. Then with one clic it generates: - a SQL database - Model files with all validation rules and relations - Standard CakePHP Controllers files - Standard CakePHP view files It has just been released so it is still a bit basic and may contain some bugs, but we are working to improve it and would be glad to receive comments and suggestions ! You can use it here : http://patisserie.keensoftware.com/en/cakes -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups CakePHP group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/d/optout.
Re: Access $this-Session from a model
Hi i have the same problem with the
plugin https://github.com/robwilkerson/CakePHP-Audit-Log-Plugin, i put the
method in my Model (AppModel) so it can be used in others models, my
solution was:
function currentUser()
{
//pr($this-Session-read('Auth.User'));
//pr($this-Auth-user());
//pr(AuthComponent::user());
//die();
$user=AuthComponent::user();
return $user;
}
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Exception output issue
Hello people, I realized recently that when an exception is triggered through a view (calling a nonexistent helper, for example), the error message along with the error layout (if customized) are displayed after the contents of the view in that the error is being generated (before the DOCTYPE). Is there any way to display only the error output without this content view? -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups CakePHP group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/d/optout.
Displaying error messages without the content of the current view.
Hi folks, how can i display error messages without the content of the current view? For example: If a vendor file throws a PDOException, the error message is displayed inside my current view. First, the content of my current view is displayed (without any layout, just the content), then the error message with the error layout is appended to the output. -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups CakePHP group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php. For more options, visit https://groups.google.com/groups/opt_out.
Models indirect association, how to retrieve data?
How's it going?
I have a problem with cakePHP, I'm new to it and struggling with it. Let me
pour onto you guys my situation:
I'm developing a system for a University here in Brazil. In this sytem I've
got the following models: - Country; - State; - City; - University; - Unit;
- Class;
Ok. and the relations are: - State belongs to Country; - City belongs to
State; - University belongs to Country (because, in my database, not every
country has states registered to it and not every state has citys
registered to it, so I could not demand from the user to register a
University to a City); - Unit belongsTo university; - Class belongs to
University (because not every University has Units registered to it);
Ok. I guess now I've set a good background for you guys to understand my
situation. Now onto the question itself:
In the Views of my Model Class I wanna display the Country and (IF there
are State City). And I may have the need to display such content in other
Model views such as Unit and University.
But when I try to do that in my Class model I can only display the
country_id. The foreign key in my university database table. And why is
that, that is because my Class model belongs to University, so it's pretty
easy to access my University's properties. However I do not wish to access
the id of the Country, I want it's Name. And maybe in the future I might
want other properties, who knows?
HOW DO I DO THAT? How do I access the properties of the Model Country when
my Model Class has NO direct relation to it?
many thx hugs and kisses. Hope someone can help me with this one.
p.S: I've managed a kinda loser solution: In my Class Controller I've done
the following (so I can access variables of the Models Country, State and
City):
In the View function I've loaded the Models for State and City (the country
Model I can access by the relation Class-University-Country);
Then I used a find method to find the respective country, state and city
for the Class in question I wanna display in view.ctp. The code follows:
*CODE*public function view($id = null) {
$this-Class-id = $id; $this-set('class', $this-Class-read());
$this-loadModel('State');
$this-loadModel('City');
$country = $this-Class-Universsity-Country-find('first',
array('conditions' = array('Country.id' =
$this-Class-data['University']['country_id']),));
$state = $this-State-find('first', array('conditions' = array('State.id'
= $this-Class-data['University']['state_id']),));
$city = $this-City-find('first', array('conditions' = array('City.id' =
$this-Class-data['University']['city_id']),));
$this-set('country',$country['Country']);$this-set('city',$city);
$this-set('state',$state);
}
And it kinda works...In my Wiew.ctp I get an array for Country data, and
array for State data and an array for City data. And in the view I check to
see if the state and city arrays are not length = 0 to display them and
all...but I think there HAS to be a better way to do This.
CAN ANYONE HELP ME???
P.P.S:
The other question is...what about the Index.ctp? How will I do that if I
do not know which Class I'm working with? Will I have to have logic and
find methods in the View? Isin't that just messing up the code?
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Re: Cake is NOT able to connect to the database. Database connection Mysql is missing, or could not be created.
I fixed it. Chenan Patel helped me. Thank you, Chenan :) On Thursday, May 16, 2013 9:58:37 PM UTC+3, Gabriel Saulescu wrote: I am trying to install cakephp on my laptop. I received this error. My SO is a WindowsVista in 32 b. I changed this: extension=php_mssql.dll. I need your help, please. What I have to do? Thank you in advance. Gabriel -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups CakePHP group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: Cake is NOT able to connect to the database. Database connection Mysql is missing, or could not be created.
On Thursday, May 16, 2013 9:58:37 PM UTC+3, Gabriel Saulescu wrote: I am trying to install cakephp on my laptop. I received this error. My SO is a WindowsVista in 32 b. I changed this: extension=php_mssql.dll. I need your help, please. What I have to do? Thank you in advance. Gabriel -- Like Us on FaceBook https://www.facebook.com/CakePHP Find us on Twitter http://twitter.com/CakePHP --- You received this message because you are subscribed to the Google Groups CakePHP group. To unsubscribe from this group and stop receiving emails from it, send an email to cake-php+unsubscr...@googlegroups.com. To post to this group, send email to cake-php@googlegroups.com. Visit this group at http://groups.google.com/group/cake-php?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
Re: Cake is NOT able to connect to the database. Database connection Mysql is missing, or could not be created.
Hello again,
I installed XAMP for PHP.
APACHE and MYSQL are working ok.
I installed CAKEPHP. And I changed files required by Cake, php.ini,
database.php. core.php
I received the following message:
Your version of PHP is 5.2.8 or higher.
Your tmp directory is writable.
The FileEngine is being used for core caching. To change the config
edit APP/Config/core.php
Your database configuration file is present.
Cake is NOT able to connect to the database.
Database connection Mysql is missing, or could not be created.
DebugKit plugin is present
Database.php looks like:
class DATABASE_CONFIG {
public $default = array(
'datasource' = 'Database/Mysql',
'persistent' = false,
'host' = 'localhost',
'login' = 'gabriel',
'password' = 'gabi62#',
'database' = 'cake',
'prefix' = '',
//'encoding' = 'utf8',
);
public $test = array(
'datasource' = 'Database/Mysql',
'persistent' = false,
'host' = 'localhost',
'login' = 'gabriel',
'password' = 'gabi62#',
'database' = 'test_cake',
'prefix' = '',
//'encoding' = 'utf8',
);
}
php.ini looks like:
extension=php_bz2.dll
extension=php_curl.dll
extension=php_mbstring.dll
extension=php_exif.dll
;extension=php_fileinfo.dll
extension=php_gd2.dll
extension=php_gettext.dll
;extension=msql.dll
;extension=php_gmp.dll
;extension=php_intl.dll
;extension=php_imap.dll
;extension=php_interbase.dll
;extension=php_ldap.dll
extension=php_mssql.dll
;extension=php_mbstring.dll
;extension=php_exif.dll ; Must be after mbstring as it depends on
it
extension=php_mysql.dll
extension=php_mysqli.dll
;extension=php_oci8.dll ; Use with Oracle 10gR2 Instant Client
;extension=php_oci8_11g.dll ; Use with Oracle 11gR2 Instant Client
;extension=php_openssl.dll
;extension=php_pdo_firebird.
dll
extension=php_pdo_mysql.dll
extension=php_pdo.dll
;extension=php_pdo_mssql.dll
;extension=php_pdo_oci.dll
;extension=php_pdo_odbc.dll
;extension=php_pdo_pgsql.dll
extension=php_pdo_sqlite.dll
;extension=php_pdo_sqlite_external.dll
;extension=php_pgsql.dll
;extension=php_pspell.dll
;extension=php_shmop.dll
I set up the rights in Mysql for the user gabriel
Please, tell me where I am wrong?
Thank you in advance
On Thursday, May 16, 2013 9:58:37 PM UTC+3, Gabriel Saulescu wrote:
I am trying to install cakephp on my laptop.
I received this error.
My SO is a WindowsVista in 32 b.
I changed this:
extension=php_mssql.dll.
I need your help, please. What I have to do?
Thank you in advance. Gabriel
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Cake is NOT able to connect to the database. Database connection Mysql is missing, or could not be created.
Hello again,
I installed XAMP for PHP.
APACHE and MYSQL are working ok.
I installed CAKEPHP. And I changed files required by Cake, php.ini,
database.php. core.php
I received the following message:
Your version of PHP is 5.2.8 or higher.
Your tmp directory is writable.
The FileEngine is being used for core caching. To change the config
edit APP/Config/core.php
Your database configuration file is present.
Cake is NOT able to connect to the database.
Database connection Mysql is missing, or could not be created.
DebugKit plugin is present
Database.php looks like:
class DATABASE_CONFIG {
public $default = array(
'datasource' = 'Database/Mysql',
'persistent' = false,
'host' = 'localhost',
'login' = 'gabriel',
'password' = 'gabi62#',
'database' = 'cake',
'prefix' = '',
//'encoding' = 'utf8',
);
public $test = array(
'datasource' = 'Database/Mysql',
'persistent' = false,
'host' = 'localhost',
'login' = 'gabriel',
'password' = 'gabi62#',
'database' = 'test_cake',
'prefix' = '',
//'encoding' = 'utf8',
);
}
php.ini looks like:
extension=php_bz2.dll
extension=php_curl.dll
extension=php_mbstring.dll
extension=php_exif.dll
;extension=php_fileinfo.dll
extension=php_gd2.dll
extension=php_gettext.dll
;extension=msql.dll
;extension=php_gmp.dll
;extension=php_intl.dll
;extension=php_imap.dll
;extension=php_interbase.dll
;extension=php_ldap.dll
extension=php_mssql.dll
;extension=php_mbstring.dll
;extension=php_exif.dll ; Must be after mbstring as it depends on
it
extension=php_mysql.dll
extension=php_mysqli.dll
;extension=php_oci8.dll ; Use with Oracle 10gR2 Instant Client
;extension=php_oci8_11g.dll ; Use with Oracle 11gR2 Instant Client
;extension=php_openssl.dll
;extension=php_pdo_firebird.dll
extension=php_pdo_mysql.dll
extension=php_pdo.dll
;extension=php_pdo_mssql.dll
;extension=php_pdo_oci.dll
;extension=php_pdo_odbc.dll
;extension=php_pdo_pgsql.dll
extension=php_pdo_sqlite.dll
;extension=php_pdo_sqlite_external.dll
;extension=php_pgsql.dll
;extension=php_pspell.dll
;extension=php_shmop.dll
I set up the rights in Mysql for the user gabriel
Please, tell me where I am wrong?
Thank you in advance
--
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Re: Doubt regarding sessions in cakephp
Hi Litto It looks like some php.ini configuration has to be done. Compare your local php.ini file with production php.ini file, and check the session configurations. -- Gabriel Vila Real On Thu, Mar 29, 2012 at 02:39, LITTO CHACKO li...@axtecindia.com wrote: hai, buddies iam currently working in a project which contains as many forms.. so i have to attach captcha to each form for ensuring security... so the problem is that... actually captcha is working with help of sessions... u all know.. whwn iam testing it on local server it works fine with captcha and submitting form.. but whwn i do the same in main server.. i didn't get the value of captcha stored in session??? pls anyone clear this doubt by giving effective solutions??? beacuse of this pblm by project is in vain -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php -- Our newest site for the community: CakePHP Video Tutorials http://tv.cakephp.org Check out the new CakePHP Questions site http://ask.cakephp.org and help others with their CakePHP related questions. To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php
Re: Cahe Helper: Cached Render Time
Thanks. Since i'm using jquery to get the json data, solved the
problem using the dataFilter callback to remove that info before
parsing the json.
On 12 nov, 01:25, Amit Badkas amitrb...@gmail.com wrote:
Hi,
If you look at renderCache() method of class View, in file
cake/libs/view/view.php, it uses following code to append the cache render
time in HTML comment
if (Configure::read() 0 $this-layout != 'xml') {
echo !-- Cached Render Time: . round(getMicrotime() - $timeStart, 4)
. s --;
}
So, either you need to set the debug level to 0 or need to use your own View
class by extending CakePHP's built-in and to override the renderCache()
method to add the code as needed. The non-recommended way is to modify
CakePHP's built-in View::renderCache() method.
Amit
PHP Applications for E-Biz:http://www.sanisoft.com
On Fri, Nov 12, 2010 at 12:57 AM, Gabriel gbrl...@gmail.com wrote:
Hi, i'm having some problems with the Cache Helper, i have some cached
json responses, and the cache helper adds at the end of the json data
stats like this: !-- Cached Render Time: 0.0467s --, that screwup
the javascript json parser. How i could remove that info?
Thanks
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Cahe Helper: Cached Render Time
Hi, i'm having some problems with the Cache Helper, i have some cached json responses, and the cache helper adds at the end of the json data stats like this: !-- Cached Render Time: 0.0467s --, that screwup the javascript json parser. How i could remove that info? Thanks Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Using multiple domains on one app to create four seperate sites
Yes, it's possible. I do that in a dreamhost's account. With a single user i have 2 domains with folders like this: /home/username/domain1.com (app1) /home/username/domain2.com (app2) /home/username/cake (CakePHP Core) There is no need to modify apache config o htaccess files. On 2 oct, 16:00, Jacob jacobsteri...@gmail.com wrote: That is exactly what I thought of. But is this possible on a shared webhost, because thats where the app lives? Is there way to do it without changing any apache settings? Forgive my lack of knowledge about Apache I am not an expert user of it. On 1 okt, 14:42, Bernardo Vieira bvieira.li...@gmail.com wrote: You can use apache's namevirtualhost directive plus server aliases to point all the domains to the same web root. After that all you have to do is inspect the hostname in the $SERVER super global and use that to switch the app's theme (this gives you the flexibility to have domain specific layouts, views and elements) or just switch the layout. A good place to deal with this is the beforefilter callback. On Oct 1, 2010, at 9:26 AM, Jacob jacobsteri...@gmail.com wrote: Hello all, I am working on a website for a company, which needs five different websites. The five websites use the same database and mostly the same records. For site specific records there is a 'company' column in the table. With a parameter a function will know what records to get. The current setup exists of one app on the webroot en 4 others in a sub directory. This was the easiest way to solve the problem, but it has a down site. As the development is in a final stage, the controllers and views are modified a lot. For every change the other four apps need to be changed also. My question is: Is there a way to create the illusion of five different websites while it is actually one app? For example, based on the domainname used, the layout changes? (that would be the best solution I think) But is it possible en how should this be done? Best regards, Jacob Check out the new CakePHP Questions sitehttp://cakeqs.organdhelp others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group athttp://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Using multiple domains on one app to create four seperate sites
Sorry for my previous answer. I misunderstand the question. Maybe you could use one app and set a value with Configure in bootstrap, and according to that value, load specifics layous, records, etc. Even can set conditions in the models class for the model and the relations and let cake do the magic. On 3 oct, 10:16, Gabriel gbrl...@gmail.com wrote: Yes, it's possible. I do that in a dreamhost's account. With a single user i have 2 domains with folders like this: /home/username/domain1.com (app1) /home/username/domain2.com (app2) /home/username/cake (CakePHP Core) There is no need to modify apache config o htaccess files. On 2 oct, 16:00, Jacob jacobsteri...@gmail.com wrote: That is exactly what I thought of. But is this possible on a shared webhost, because thats where the app lives? Is there way to do it without changing any apache settings? Forgive my lack of knowledge about Apache I am not an expert user of it. On 1 okt, 14:42, Bernardo Vieira bvieira.li...@gmail.com wrote: You can use apache's namevirtualhost directive plus server aliases to point all the domains to the same web root. After that all you have to do is inspect the hostname in the $SERVER super global and use that to switch the app's theme (this gives you the flexibility to have domain specific layouts, views and elements) or just switch the layout. A good place to deal with this is the beforefilter callback. On Oct 1, 2010, at 9:26 AM, Jacob jacobsteri...@gmail.com wrote: Hello all, I am working on a website for a company, which needs five different websites. The five websites use the same database and mostly the same records. For site specific records there is a 'company' column in the table. With a parameter a function will know what records to get. The current setup exists of one app on the webroot en 4 others in a sub directory. This was the easiest way to solve the problem, but it has a down site. As the development is in a final stage, the controllers and views are modified a lot. For every change the other four apps need to be changed also. My question is: Is there a way to create the illusion of five different websites while it is actually one app? For example, based on the domainname used, the layout changes? (that would be the best solution I think) But is it possible en how should this be done? Best regards, Jacob Check out the new CakePHP Questions sitehttp://cakeqs.organdhelpothers with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group athttp://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: how to create forms
Here a good tutorial for a contact form! http://snook.ca/archives/cakephp/contact_form_cakephp On Jul 19, 4:14 pm, amr_AJ ramruth...@gmail.com wrote: how to create forms Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: Structure of data returned by $this-Model-find
Hi,
In order to make a node system with a standard way, check this
ressource :
http://dev.mysql.com/tech-resources/articles/hierarchical-data.html
The exemple is specifique to mysql but you can make change to fit your
needs.
Cheers!
Gabriel
On 4 mai, 10:26, Roland B feedback2...@eudoxos.de wrote:
Hi,
is there a way to change the structure of data returned by a model's
find call? Or should I use a different call? IMHO, the default seems
to be inconsistent in the way it handles associations:
Given this model:
//---
class Querycategory extends AppModel
{
var $recursive = 10;
var $hasMany = array(
'Querycategory' = array('order' = 'name ASC'),
'Querygroup' = array('order' = 'name ASC'));}
//---
A call to $this-Querycategory-find('all') yields something like
this:
Array
(
[0] = Array
(
[Querycategory] = Array
(
[id] = 70
[querycategory_id] = 34
[0] = Array
(
[id] = 71
[querycategory_id] = 70
[Querygroup] = Array
(
[0] = Array
(
[id] = 43
[querycategory_id] = 71
)
)
)
)
[Querygroup] = Array
(
)
)
)
A Querygroup belonging to the Root-Querycategory is at the same level
as the root node and it is called Querygroup.
A Querygroup belonging to a child category is inside that child node
and it is called Querygroup.
A Querycategory belonging to any other category is inside its parent
and unnamed, unless there is also a Querygroup at the same level: then
it is called 'Querycategory'
I would prefer:
Querygroup is always contained in it's parent, always being called
'Querygroup'.
Querycategory is always contained in its parent, always being called
'Querycategory'.
Is there a standard way to achieve this?
Using cake-1.2.
Thank you very much in advance,
Roland
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Re: PHP CodeSniffer
Hi, I want to use coding standards with my cake app too. The default coding standard is pear. You can change default standard see the Code Sniffer doc. If you use netbeans there's a plugin to check your code. http://www.amaxus.com/cms-blog/coding-standards-netbeans-php-codesniffer I don't find a coding wich match with cake so i try make my own... then i give up :-( If you make one or have more information about, i can be interested. Thanks. On 30 avr, 13:34, Braindead markus.he...@gmail.com wrote: Hi all is there anybody out there who uses PHP CodeSniffer with his Cake app? I tried PHP CodeSniffer for the first time and used the build in coding standards to sniff my code. Actually I get warnings because of Cake conventions. Method name PostsController::admin_edit is not on camel caps format Just to mention one warning. So can anybody lead me the way to use PHP CodeSniffer with CakePHP? Cheers, Markus Check out the new CakePHP Questions sitehttp://cakeqs.organd help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group athttp://groups.google.com/group/cake-php?hl=en Check out the new CakePHP Questions site http://cakeqs.org and help others with their CakePHP related questions. You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en
Re: How can I configure the value of CAKE_CORE_INCLUDE_PATH?
Hi, you can do that in app/webroot/index.php and test.php
This is the code i use to switch the core path depending on the server name:
if (!defined('CAKE_CORE_INCLUDE_PATH')) {
$srvname = $_SERVER['SERVER_NAME'];
if( $srvname == 'localhost' || $srvname == '127.0.0.1' || $srvname
== ''){ // Dev Path
// PATH: D:\sharedlibs\libs\cakephp\1.2.x.x
define('CAKE_CORE_INCLUDE_PATH',
'D:'.DS.'sharedlibs'.DS.'libs'.DS.'cakephp'.DS.'1.2.x.x');
}else{ // Prod Path
// PATH: /home/sharedlibs/libs/cakephp/1.2.x.x
define('CAKE_CORE_INCLUDE_PATH',
DS.'home'.DS.'sharedlibs'.DS.'libs'.DS.'cakephp'.DS.'1.2.x.x');
}
}
simon...@gmail.com escribió:
Hi,
I did a website using CakePHP, I need to configure the
CAKE_CORE_INCLUDE_PATH (app/webroot/index.php).
How can I do that?
Someone has an example?
I need to know the complete path of my server to be able to do that?
Using phpinfo()?
Regards,
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Add actions to model dinamically in behavior
I'm working with an image behavior, that stores resized images for the specified fields. Thats work fine. To get the images i have to define an action in the controller for each image field... i'm wonder if can i add these actions dinamically in the behavior? Thanks in advance and sorry by mi english. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Poll: what do you hate about CakePHP?
Totaly agree with avairet's comment about the site design... Some clients want to know what tools we use, and when they search about cakephp thinks that is a software for kids. avairet escribió: Thank you for this ironic but serious message Nate! To respect your humoristic formulation, here is my hateful contribution! And sorry for my simple English… hope it's understandable. ;) I hate the lack of rigor with relational model and SQL norm. I think compound primary keys, sub-queries, multi-level JOIN should be implemented. It will permit to avoid artificial id in HABTM for example and thus tons of intermediate queries. More data types should be available too (like ENUM and SET for MySQL). I hate contributions constraints like: Make a Unit Test when I report a bug or like: Fork the project and use Git when I just want to update the .po file for CookBook. I hate the instability of official documentation. Yes CookBook is better than ever, but there are still a lot of sections without explanations, some with obsolete explanations, others that are frequently modified… it's difficult for both newcomers and translators to navigate through it and find the good information. A PDF export – global or partial - would be useful too I hate translation tool and process for CookBook, it is complex, heavy to manipulate, frequently modified and debugged. Ok, there were new features recently developed (thanks to AD7six, Gwoo and others for this work), but is not enough to attract and motivate new translators… Two little suggestions for the moment: give validation rights to locale community AND/OR let us write our own documentation, inspired by, but not a perfect clone of the original. I hate the multi-communicational channels of community : Bakery, official website, Ohloh journal, multiple IRC's chans, multiple GoogleGroups, Trac, TheChaw, CakeFest, unofficial forum, core developpers and contributors blogs… it's like a puzzle! The heterogeneity of designs between those different websites of the Cake's galaxy make it even more disorganized. In the same way, I hate Cake's logo (this cake is more like a cheese 时 ) and official website design (not clear enough, too funny and not enough serious for deciders in comparison to Symfony and ZF designs). I hate methods with more than 4 parameters or with mixed parameters (a string or an array or null). I hate Cake's shortcuts that just embbed PHP native functions like e (), up(), low()… (for the majority of PHP's IDE, autocomplete works well for that). I hate the limited internationalisation of core methods like Validate::alphanumeric() or Inflector::slug(). Accented and special chars should be available and mb_ functions might be used, maybe by including localized chars files (setting a var in config/core.php for example). More internationalisation for Validate::phone() or Validate::ssn() would be great too. We can help you to do that: please delegate some responsibilities to the numerous dynamic international communities! Other opinions that I'm supporting too: ++ PHP 4 to full PHP5 syntax ++ ACL more flexibility (e.g. user attached to two groups) ++ Objects instead arrays, especially for find's returns ++ GUI for Bake, because we're not all CLI gurus… hmmm, ok, we should be! 时 ++ More complete Bake ++ Plugins management ++ Form::error messages ++ Jquery ++ automagic slug field That's all... for the moment! OK, I know that a framework can NOT make the coffee and that I can create my own logic when needed. But I would like to say that in my point of view, the more Cake will be professional, industrial and rigorous, the more it will be adopted by PHP users and deciders who currently look at Symfony or Zend Framework side, even if Cake is more fun and easy to use. I like Cake and its philosophy, I want to develop its usage and recognition around the World, so let’s work together to make a better Cake! ;) --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: losing action parameters after submit
Hola, creo que hablas español.
En realidad funciona como es de esperarse. Llamas a la accion pasando el
id de la empresa que la accion lo utiliza para obtener los datos pero
luego al generar la vista y enviar el formulario es logico que se pierda
el id de la empresa ya que no figura en ningun lado y vuelves a mandar
al controlador solo los datos del formulario... Deberias hacer algo asi:
Agregar al formulario el siguiente campo oculto con el id de la empresa:
?php echo $form-create('Local',array('action'='agregar'));?
input type=hidden name=*data[Empresa][id]* value=?php echo
$empresa[Empresa][id]; ? /
...
...
Y luego en la accion usar:
if (!empty($this-data)) {
if ($this-Local-save($this-data)) {
$this-Session-setFlash('Un nuevo local ha sido agregado al
sistema.');
$this-redirect(array('action' = 'lista',
*$this-data[Empresa][id]*));
}
}
Espero que te sirva.
Frannie escribió:
Hello. I want to thank you in advance for your time.
I am trying to make a form and the action that uses has a parameter,
but when I submit the form the parameter disappears
*this is my form:
?php echo $form-create('Local',array('action'='agregar'));?
table
tr
thNombre/th
td?php echo $form-input('Local.nombre',
array('label'='')); ?/
td
/tr
tr
thTipo/th
td?php echo $form-input('Local.tipo', array
('label'='','type'='select')); ?/td
/tr
tr
thRegioacute;n/th
td?php echo $form-input('region',
array('label'='','options'=
$regiones)); ?/td
/tr
tr
thComuna/th
td?php echo $form-input('Local.comuna_id', array
('label'='','type'='select')); ?/td
/tr
tr
thDireccioacute;n/th
td?php echo $form-input('Local.direccion',
array('label'='')); ?
/td
/tr
tr
thTeleacute;fono/th
td?php echo $form-input('Local.telefono',
array('label'='')); ?
/td
/tr
tr
thE-mail/th
td?php echo $form-input('Local.email', array('label'=''));
?/
td
/tr
tr
thPatente/th
td?php echo $form-input('Local.patente',
array('label'='')); ?
/td
/tr
/table
?php echo $form-end('Guardar');?
***this is the action:
function agregar($empresa_id){
$this-set('CSS','estilo');
$this-set('empresas_list',$this-Nav-showEmpresas());
$this-set('empresa',$this-Empresa-find('first', array
('conditions' = array('Empresa.id' = $empresa_id;
$this-set('comunas', $this-Local-Comuna-find('list'));
$this-set('regiones',
$this-Local-Comuna-Region-find('list'));
$this-set('tipos', $this-Local-Catalogo-find('list', array
('conditions'= array('Catalogo.grupo'='tipo_local';
if (!empty($this-data)) {
if ($this-Local-save($this-data)) {
$this-Session-setFlash('Un nuevo local ha
sido agregado al
sistema.');
$this-redirect(array('action' = 'lista',
$empresa_id));
}
}
}
I load the view with an url like this: localhost/myroot/mycontroller/
agregar/1
then I fill the fields of the form and I submit, and then I lose my
parameter. Does anybody know why this could be?
I'm sorry, english is not my first language, if you have any questions
about my problem just tell me.
I really will appreciate your help.
Francisca.
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Re: losing action parameters after submit
O creo que podria simplificarse mas usando:
?php echo
$form-create('Local',array('action'='agregar/'.$empresa['Empresa']['id']));?
Ya que en la accion del formulario no pones el parametro.
Y olvide las comillas en el mensaje anterior, seria:
input type=hidden name=*data[Empresa][id]* value=?php echo
$empresa['Empresa']['id']; ? /
y
this-redirect(array('action' = 'lista', *$this-data['Empresa']['id']*));
Frannie escribió:
Hello. I want to thank you in advance for your time.
I am trying to make a form and the action that uses has a parameter,
but when I submit the form the parameter disappears
*this is my form:
?php echo $form-create('Local',array('action'='agregar'));?
table
tr
thNombre/th
td?php echo $form-input('Local.nombre',
array('label'='')); ?/
td
/tr
tr
thTipo/th
td?php echo $form-input('Local.tipo', array
('label'='','type'='select')); ?/td
/tr
tr
thRegioacute;n/th
td?php echo $form-input('region',
array('label'='','options'=
$regiones)); ?/td
/tr
tr
thComuna/th
td?php echo $form-input('Local.comuna_id', array
('label'='','type'='select')); ?/td
/tr
tr
thDireccioacute;n/th
td?php echo $form-input('Local.direccion',
array('label'='')); ?
/td
/tr
tr
thTeleacute;fono/th
td?php echo $form-input('Local.telefono',
array('label'='')); ?
/td
/tr
tr
thE-mail/th
td?php echo $form-input('Local.email', array('label'=''));
?/
td
/tr
tr
thPatente/th
td?php echo $form-input('Local.patente',
array('label'='')); ?
/td
/tr
/table
?php echo $form-end('Guardar');?
***this is the action:
function agregar($empresa_id){
$this-set('CSS','estilo');
$this-set('empresas_list',$this-Nav-showEmpresas());
$this-set('empresa',$this-Empresa-find('first', array
('conditions' = array('Empresa.id' = $empresa_id;
$this-set('comunas', $this-Local-Comuna-find('list'));
$this-set('regiones',
$this-Local-Comuna-Region-find('list'));
$this-set('tipos', $this-Local-Catalogo-find('list', array
('conditions'= array('Catalogo.grupo'='tipo_local';
if (!empty($this-data)) {
if ($this-Local-save($this-data)) {
$this-Session-setFlash('Un nuevo local ha
sido agregado al
sistema.');
$this-redirect(array('action' = 'lista',
$empresa_id));
}
}
}
I load the view with an url like this: localhost/myroot/mycontroller/
agregar/1
then I fill the fields of the form and I submit, and then I lose my
parameter. Does anybody know why this could be?
I'm sorry, english is not my first language, if you have any questions
about my problem just tell me.
I really will appreciate your help.
Francisca.
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Custom php.ini and .htaccess
Hi guys!
I using a custom php configuration on dreamhost and works fine with
standalone php files.
But i can't get it working with cakephp(Cakephp works fine without the
custom php.ini but i need it to increase te max upload size)
The thing is when i try to use the custom config with mod_rewrite I get
a internal error.
in my .htaccess i have:
---
IfModule mod_rewrite.c
RewriteEngine On
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule ^(.*)$ index.php?url=$1 [QSA,L]
/IfModule
Options ExecCGI
AddHandler php5-cgi .php
Action php5-cgi /php5/php5.cgi
---
And the errors is:
--
Internal Server Error
The server encountered an internal error or misconfiguration and was
unable to complete your request.
Please contact the server administrator, webmas...@domain.com and inform
them of the time the error occurred, and anything you might have done
that may have caused the error.
More information about this error may be available in the server error log.
Additionally, a 500 Internal Server Error error was encountered while
trying to use an ErrorDocument to handle the request.
--
And in the log get:
--
Request exceeded the limit of 10 internal redirects due to probable
configuration error. Use 'LimitInternalRecursion' to increase the limit
if necessary. Use 'LogLevel debug' to get a backtrace.
--
Probably is an error in the .htaccess config, but I can't solved it...
any ideas?
Thanks a lot and sorry by mi english...
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Re: Forcing user to access her data only
Hi Brian, i assume that each course have an user_id right? so when you
list, edit or view the courses just use a condition to search all the
courses of the current user... ex:
$cond = array('Course.user_id' = $Current_user_id);
$this-set('courses', $this-paginate('Course', $cond));
Brian Lee escribió:
So, here is how my application works:
1. I have users (just like any other apps)
2. I have courses that each user can create
Upon login, user will view the list of courses that she created.
I got that to work.
However, now the problem is, I don't know the simple, neat way to
block user from accessing classes that she did not create. For
instance, Bob created courses that have IDs of 1, 2, 3. Jane has
courses with IDs of 4, 5, 6. How do I stop Bob from doing something
like localhost/courses/view/4 (trying to view Jane's course)? and
prevent Jane from doing the same for Bob's courses?
I am sure that there is very neat way to do it, because this is a
problem often comes up when developing web applications. I just want
to know the CakePHP way of doing this.
Thanks!
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-~--~~~~--~~--~--~---
Re: Datetime difference
You could calculate the time difference on the fly with mysql TIMEDIFF function [http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html#function_timediff] instead of store it in the db And this [http://www.gidnetwork.com/b-16.html] may help to store the time difference. Céryl escribió: Hej all! Since my good advice just ago, I got to another bottleneck. I have a form in which the user selects two times (a start- and an end- time). The form works perfectly and the times get stored in the table as hh:mm:ss. However, I have a 3th row in the database that must hold the elapsed time between the two form-inputted times. I want the computer to calculate this. I figured I must do this in in the controller, I can of course even do after the $this-Model-save() action with a saveField, just before the redirect. However, I cannot seem to find a good example of making that function. I'm not sure how i get my timestamp back from the form, if they are simply substractable and how to store it back in the table. If it makes matters easier, elapsed time can be stored as an integer holding seconds between times in the table, I can probably calculate those back in elapsed minutes/hours in a later view of the table. Any idea's or links to examples of working with Timestamps? It always boggles me! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Submit/Cancel problem
Use reset or button NOT submit type for the cancel button. input name=Cancel value=cancel type=reset or input name=Cancel value=cancel type=button Nancy escribió: So, I added a submit and a cancel button to my ajax form and it doesn't matter which you press, it always returns the submit button, not the cancel. The view code has this at the bottom (I stopped using helpers to see if raw HTML would help, it didn't): input name=Submit value=submit type=submit input name=Cancel value=cancel type=submit In the controller (admin_edit) function, I'm dumping out the contents of $this-params['form'] and it always shows Array ( [Submit] = submit ) Even if you press the cancel button. Am I doing something wrong? Thanks! Nancy --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to cake-php+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Calling a Cake Shell Script from controller
Hi list, I'm having a little trouble here trying to call a script from the controller, and keep it running in background while flush the output to the client. Dreamhost inhibits the use o flush() and alikes by turning mod_deflate on by default. I obviously don't want to turn gzipping off in my site, so I'm looking for a workaround. So, what I would like to know is if there's a Cake-way of calling a Shell script, and if not, whether there is a way to exec it and keep it running on the server-side when the client goes away from that page. Thanks in advance. Cheers -- Gabriel Gilini --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Jquery or Scriptalicious?
the lesser the codes the lesser the debugging time oh, that's so not true [snip] Gabriel Gilini www.usosim.com.br [EMAIL PROTECTED] [EMAIL PROTECTED] --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Jquery or Scriptalicious?
I mean that there is a hell lot of people learning jQuery, not JavaScript these days. Every allegedly javascript developer should, at least, read the ECMA-262. Gabriel Gilini www.usosim.com.br [EMAIL PROTECTED] [EMAIL PROTECTED] On Sun, Nov 2, 2008 at 10:08 PM, 703designs [EMAIL PROTECTED] wrote: I'm not sure what you mean by that. jQuery is written in JavaScript (not like MochiKit, which tries to make JavaScript look like Python). On Oct 31, 2:43 pm, Gabriel Gilini [EMAIL PROTECTED] wrote: The right answers is: learn real javascript Yes, the learning curve with jQuery is way lower, but when you really know javascript, take a look in proto ;) Gabriel Gilini www.usosim.com.br [EMAIL PROTECTED] [EMAIL PROTECTED] On Fri, Oct 31, 2008 at 4:37 PM, Samuel DeVore [EMAIL PROTECTED] wrote: Here's my take for what little it's worth (note I use scripa/proto) if you want to use the ajax helper at this point you are tied to scripta/proto. now given that the stated plans in unofficial channels is that the helper is either being migrated to jQuery or being driving to a javascript _framwork_ agnostic place, it really doesn't matter. If on the otherhand you see yourself not feeling like the helper as it exists now will meet your needs and you will be wanting insight and help from people on this list on integrating javascript _framework_ into your project, then I would say that the responses to your question indicate, to me, that jQuery is a more of the current 'hotness' and you are likely to get more help from people jazzed up on jQuery. To me it is a question of who is going to help you if you need it and what do you think your projected needs are. See totally unhelpful answer ;) Sam D On Fri, Oct 31, 2008 at 12:16 PM, Gabriel Gilini [EMAIL PROTECTED] wrote: Sorry, mate, but prototype also supports all CSS3 selectors. ps: I never use cakephp's ajax helpers, and I love writing javascript Cheers Gabriel Gilini www.usosim.com.br [EMAIL PROTECTED] [EMAIL PROTECTED] On Fri, Oct 31, 2008 at 10:45 AM, Josey [EMAIL PROTECTED] wrote: I perfer jQuery as well. Many Bakers like prototype due to the javascript and ajax helpers that come with CakePHP. These make baking with JS quite a bit easier, not to mention faster however many Javascript experts would cringe to think that developers are using php helpers for the behavioral portion of their sites because the scripts are no longer unobtrusive. jQuery is very easy to learn and uses many of the same selectors that CSS 2 and 3 use making it incredibly easy to develop around. However, if you require a JS helper there is a jQuery helper for CakePHP called pQuery. http://www.ngcoders.com/php/pquery-php-and-jquery If not then spend some time at the jQuery API and read through the tutorials. http://docs.jquery.com/Main_Page I love jQuery. On Oct 30, 5:49 pm, Matthieu [EMAIL PROTECTED] wrote: Hello, I'm gonna create a web app using CakePHP but I'm confused about chosing between Jquery or Scriptalious? Which one should I choose? Does it really matter? What's the differences between them? tks --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Post Data
Are you building your form with the Form Helper? Because it seems to me that there are no naming conventions at all there. Cheers Gabriel Gilini www.usosim.com.br [EMAIL PROTECTED] [EMAIL PROTECTED] On Fri, Oct 31, 2008 at 9:46 AM, MDB [EMAIL PROTECTED] wrote: The form values do not show up when I do that, they do when I do a debug($this) and appear like this: [form] = Array ( [Test1] = 04 [Test2] = 05 ) How do I access these values? I have tried $this-form and $_POST['Test1'] however I always get an undefined index or property error. On Oct 30, 9:21 pm, thatsgreat2345 [EMAIL PROTECTED] wrote: add debug($this-data); to your controller that is receiving the submitted data. It will display the structure of $this-data On Oct 30, 6:59 am, MDB [EMAIL PROTECTED] wrote: How do you get form data that is not part of a controller? I have a select / drop down box called dobDay, then in the controller, I have tried $this-data['dobDay'], $_POST['dobDay'] and $this-data['Customer']['dobDay'] (customer = name of form) and nothing works. Can someone please help? TIA- Hide quoted text - - Show quoted text - --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Jquery or Scriptalicious?
Looks like I'm the only one who loves prototype here :) Gabriel Gilini www.usosim.com.br [EMAIL PROTECTED] [EMAIL PROTECTED] On Fri, Oct 31, 2008 at 10:27 AM, Marcelius [EMAIL PROTECTED] wrote: @Anupom: Any arguments? Anupom schreef: I think PHP helper for writing Javascript is a very bad idea. On Fri, Oct 31, 2008 at 3:23 PM, martinp [EMAIL PROTECTED] wrote: Despite the fact that CakePHP comes with a Scriptaculous-powered AJAX Helper, I find JQuery so much easier to use that you don't really need a helper. On Oct 31, 9:30 am, Gianluca Gentile [EMAIL PROTECTED] wrote: jQuery . On Oct 30, 11:49 pm, Matthieu [EMAIL PROTECTED] wrote: Hello, I'm gonna create a web app using CakePHP but I'm confused about chosing between Jquery or Scriptalious? Which one should I choose? Does it really matter? What's the differences between them? tks -- Anupom Syam http://syamantics.com/ --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Jquery or Scriptalicious?
Sorry, mate, but prototype also supports all CSS3 selectors. ps: I never use cakephp's ajax helpers, and I love writing javascript Cheers Gabriel Gilini www.usosim.com.br [EMAIL PROTECTED] [EMAIL PROTECTED] On Fri, Oct 31, 2008 at 10:45 AM, Josey [EMAIL PROTECTED] wrote: I perfer jQuery as well. Many Bakers like prototype due to the javascript and ajax helpers that come with CakePHP. These make baking with JS quite a bit easier, not to mention faster however many Javascript experts would cringe to think that developers are using php helpers for the behavioral portion of their sites because the scripts are no longer unobtrusive. jQuery is very easy to learn and uses many of the same selectors that CSS 2 and 3 use making it incredibly easy to develop around. However, if you require a JS helper there is a jQuery helper for CakePHP called pQuery. http://www.ngcoders.com/php/pquery-php-and-jquery If not then spend some time at the jQuery API and read through the tutorials. http://docs.jquery.com/Main_Page I love jQuery. On Oct 30, 5:49 pm, Matthieu [EMAIL PROTECTED] wrote: Hello, I'm gonna create a web app using CakePHP but I'm confused about chosing between Jquery or Scriptalious? Which one should I choose? Does it really matter? What's the differences between them? tks --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Jquery or Scriptalicious?
The right answers is: learn real javascript Yes, the learning curve with jQuery is way lower, but when you really know javascript, take a look in proto ;) Gabriel Gilini www.usosim.com.br [EMAIL PROTECTED] [EMAIL PROTECTED] On Fri, Oct 31, 2008 at 4:37 PM, Samuel DeVore [EMAIL PROTECTED] wrote: Here's my take for what little it's worth (note I use scripa/proto) if you want to use the ajax helper at this point you are tied to scripta/proto. now given that the stated plans in unofficial channels is that the helper is either being migrated to jQuery or being driving to a javascript _framwork_ agnostic place, it really doesn't matter. If on the otherhand you see yourself not feeling like the helper as it exists now will meet your needs and you will be wanting insight and help from people on this list on integrating javascript _framework_ into your project, then I would say that the responses to your question indicate, to me, that jQuery is a more of the current 'hotness' and you are likely to get more help from people jazzed up on jQuery. To me it is a question of who is going to help you if you need it and what do you think your projected needs are. See totally unhelpful answer ;) Sam D On Fri, Oct 31, 2008 at 12:16 PM, Gabriel Gilini [EMAIL PROTECTED] wrote: Sorry, mate, but prototype also supports all CSS3 selectors. ps: I never use cakephp's ajax helpers, and I love writing javascript Cheers Gabriel Gilini www.usosim.com.br [EMAIL PROTECTED] [EMAIL PROTECTED] On Fri, Oct 31, 2008 at 10:45 AM, Josey [EMAIL PROTECTED] wrote: I perfer jQuery as well. Many Bakers like prototype due to the javascript and ajax helpers that come with CakePHP. These make baking with JS quite a bit easier, not to mention faster however many Javascript experts would cringe to think that developers are using php helpers for the behavioral portion of their sites because the scripts are no longer unobtrusive. jQuery is very easy to learn and uses many of the same selectors that CSS 2 and 3 use making it incredibly easy to develop around. However, if you require a JS helper there is a jQuery helper for CakePHP called pQuery. http://www.ngcoders.com/php/pquery-php-and-jquery If not then spend some time at the jQuery API and read through the tutorials. http://docs.jquery.com/Main_Page I love jQuery. On Oct 30, 5:49 pm, Matthieu [EMAIL PROTECTED] wrote: Hello, I'm gonna create a web app using CakePHP but I'm confused about chosing between Jquery or Scriptalious? Which one should I choose? Does it really matter? What's the differences between them? tks --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Few errors I found so far.
On Mon, Oct 27, 2008 at 11:36 AM, [EMAIL PROTECTED] [EMAIL PROTECTED]
wrote:
hi all,
Hi.
Just a few errors I found so far, if anyone can help, it would be much
appreciated.
1. Having multiple conditions on find:
post.php Model
$this-find('all', array('conditions' = array('DATE(Post.date)' = '
'.$date, 'Date(Post.date)' = ' '.$end_date)));
SQL generated:
SELECT `Post`.`id`, `Post`.`name`, `Post`.`date`, `Post`.`content`,
`Post`.`user_id`, `User`.`id`, `User`.`name`, `User`.`email`,
`User`.`firstname`, `User`.`lastname` FROM `posts` AS `Post` LEFT JOIN
`users` AS `User` ON (`Post`.`user_id` = `User`.`id`) WHERE
DATE(`Post`.`date`) = ' 2008-01-01 00:00:00' AND Date(`Post`.`date`)
= ' 2008-12-31 23:59:59'
Results:
None, but I know there are 2 results.
That's because the and signs should be in the array key, not value. Try
changing your conditions to something like this
array(
'conditions' = array(
'DATE(Post.date) ' = $date,
'DATE(Post.date) ' = $end_date
)
)
2. Htaccess issue?
view.ctp for posts:
?=$ajax-form('/comments/add', 'post', array('update'='comments')); ?
Code generated for the form:
action=/workspace/cake/posts/comments/add
Results:
Should this not be:
action=/workspace/cake/comments/add ?
Try to set 'model' = 'comments' in the options array.
Kind Regards,
Martin
Cheers,
Gabriel Gilini
www.usosim.com.br
[EMAIL PROTECTED]
[EMAIL PROTECTED]
--~--~-~--~~~---~--~~
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Re: Few errors I found so far.
Try to set 'model' = 'comments' in the options array.
Sorry, I meant 'model' = 'Comment'.
Gabriel Gilini
www.usosim.com.br
[EMAIL PROTECTED]
[EMAIL PROTECTED]
On Mon, Oct 27, 2008 at 12:50 PM, Gabriel Gilini [EMAIL PROTECTED]wrote:
On Mon, Oct 27, 2008 at 11:36 AM, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
hi all,
Hi.
Just a few errors I found so far, if anyone can help, it would be much
appreciated.
1. Having multiple conditions on find:
post.php Model
$this-find('all', array('conditions' = array('DATE(Post.date)' = '
'.$date, 'Date(Post.date)' = ' '.$end_date)));
SQL generated:
SELECT `Post`.`id`, `Post`.`name`, `Post`.`date`, `Post`.`content`,
`Post`.`user_id`, `User`.`id`, `User`.`name`, `User`.`email`,
`User`.`firstname`, `User`.`lastname` FROM `posts` AS `Post` LEFT JOIN
`users` AS `User` ON (`Post`.`user_id` = `User`.`id`) WHERE
DATE(`Post`.`date`) = ' 2008-01-01 00:00:00' AND Date(`Post`.`date`)
= ' 2008-12-31 23:59:59'
Results:
None, but I know there are 2 results.
That's because the and signs should be in the array key, not value. Try
changing your conditions to something like this
array(
'conditions' = array(
'DATE(Post.date) ' = $date,
'DATE(Post.date) ' = $end_date
)
)
2. Htaccess issue?
view.ctp for posts:
?=$ajax-form('/comments/add', 'post', array('update'='comments')); ?
Code generated for the form:
action=/workspace/cake/posts/comments/add
Results:
Should this not be:
action=/workspace/cake/comments/add ?
Try to set 'model' = 'comments' in the options array.
Kind Regards,
Martin
Cheers,
Gabriel Gilini
www.usosim.com.br
[EMAIL PROTECTED]
[EMAIL PROTECTED]
--~--~-~--~~~---~--~~
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Re: cakeapp.com
Nevermind, I found it. http://ondras.zarovi.cz/sql/ Gabriel Gilini www.usosim.com.br [EMAIL PROTECTED] [EMAIL PROTECTED] On Tue, Oct 21, 2008 at 10:32 AM, Gabriel Gilini [EMAIL PROTECTED]wrote: Hi, Nice app, keep up the good job! That SQL Designer, did you develop it? I found it very interesting. Gabriel Gilini www.usosim.com.br [EMAIL PROTECTED] [EMAIL PROTECTED] On Mon, Oct 20, 2008 at 1:13 PM, teknoid [EMAIL PROTECTED]wrote: I've posted the reply on the blog, but wanted to add here as well... It would be nice to provide an option of working with models (as well as tables) to setup validation rules per field and model association types. Are you planning to open source this project? On Oct 20, 10:44 am, powtac [EMAIL PROTECTED] wrote: Thank you. - Download will come - I will remove updated - SQL editor will come in english by default... On 20 Okt., 16:33, Daniel Hofstetter [EMAIL PROTECTED] wrote: Hi, I just started to build a WYSIWYG cake application builder: http://cakeapp.com. Here you find a screencast how it works: http://cakeapp.com/pages/screencast/ If you want, give me some feedback, here at this message/thread or by email: powtac at gmx dot de. Nice app. Here some feedback: - When creating a new table it is redundant to have both columns modified and updated - I would load the SQL designer in English by default - It would be useful if you could download the generated files/app Hope that's useful for you! -- Daniel Hofstetterhttp://cakebaker.42dh.com --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: cakeapp.com
Hi, Nice app, keep up the good job! That SQL Designer, did you develop it? I found it very interesting. Gabriel Gilini www.usosim.com.br [EMAIL PROTECTED] [EMAIL PROTECTED] On Mon, Oct 20, 2008 at 1:13 PM, teknoid [EMAIL PROTECTED] wrote: I've posted the reply on the blog, but wanted to add here as well... It would be nice to provide an option of working with models (as well as tables) to setup validation rules per field and model association types. Are you planning to open source this project? On Oct 20, 10:44 am, powtac [EMAIL PROTECTED] wrote: Thank you. - Download will come - I will remove updated - SQL editor will come in english by default... On 20 Okt., 16:33, Daniel Hofstetter [EMAIL PROTECTED] wrote: Hi, I just started to build a WYSIWYG cake application builder: http://cakeapp.com. Here you find a screencast how it works: http://cakeapp.com/pages/screencast/ If you want, give me some feedback, here at this message/thread or by email: powtac at gmx dot de. Nice app. Here some feedback: - When creating a new table it is redundant to have both columns modified and updated - I would load the SQL designer in English by default - It would be useful if you could download the generated files/app Hope that's useful for you! -- Daniel Hofstetterhttp://cakebaker.42dh.com --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
how to display users' country from country table in product list
Hi, I have no idea where to start with this so I would appreciate it
if someone can point me in the right direction:
I have a products (controller, model, view)
In it I display a list of products, in the products table there is a
user_id, in the user table there is a country_id.
Question: how do I display the country of a user on a view, which
comes from the products controller?
so far here is the controller code for my view.
function view() {
$products = $this-Product-recursive = 0;
$this-set('products',$products);
$this-set('products',$this-paginate());
}
pfew!
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Re: how to display users' country from country table in product list
Thanks Dan. Everyday we learn.
On Wed, Oct 15, 2008 at 4:08 PM, Dan Bair [EMAIL PROTECTED] wrote:
Hi Gabriel,
You'll have to set the recursive property of the Product model to
fetch the associated countries. You should also make sure that the
correct relations are set in your three models ( Product, User,
Country).
Here's a quick overview of how recursion works with CakePHP's models:
http://book.cakephp.org/view/439/recursive
You could also leverage the handy containable behavior built-in with
CakePHP 1.2:
http://book.cakephp.org/view/474/Containable
On Oct 15, 7:15 am, gabriel [EMAIL PROTECTED] wrote:
Hi, I have no idea where to start with this so I would appreciate it
if someone can point me in the right direction:
I have a products (controller, model, view)
In it I display a list of products, in the products table there is a
user_id, in the user table there is a country_id.
Question: how do I display the country of a user on a view, which
comes from the products controller?
so far here is the controller code for my view.
function view() {
$products = $this-Product-recursive = 0;
$this-set('products',$products);
$this-set('products',$this-paginate());
}
pfew!
--~--~-~--~~~---~--~~
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To unsubscribe from this group, send email to [EMAIL PROTECTED]
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Re: Installing Magento w/ CakePHP
Hi Kyle just a few questions... why use cake and magento together if they do the same thing, I know magento is a instant fix, for an ecommerce website, but you can use bakesale and customise it if a ecommerce website is what you want - and have it all cake. Secondly, if you want to go with magento why no then you with the zend frame work, since magento is done in zend if I am not mistaken.. Regards On Wed, Oct 15, 2008 at 11:34 AM, Kyle Decot [EMAIL PROTECTED] wrote: I am attempting to integrate Magento with CakePHP but I'm having some problems. I put the Magento files into a folder I created in the webroot directory. I uploaded all that(which took forever) but then found out that I needed to run PHP 5. My hosting is with Godaddy(which I am beginning to hate more and more each day) and they only have PHP 4. So I found a article on Magento's website(http://www.magentocommerce.com/knowledge-base/entry/installing- magento-on-a-php4-server) about using the cgi-bin to use a PHP5 Binary. The problem I am having is where do I put the cgi-bin folder? I tried it inside of the Magento folder, the webroot folder, the App folder, and my root folder and none of these seemed to work. When I navigate to http://www.affinityskateboards.com/store/ CakePHP tells me Error: Missing.htmlController could not be found. Has anyone successfully done what I am attempting to do or does anyone have any suggestions(other then leaving GoDaddy)? Thank you. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
email body/message does not come through
Hi My emails works, but the message/body/content part of the email
does not come through, the $this-Email-template = 'thanks'; does
not come through...can anyone please help.
?php
class ContactsController extends AppController
{
var $name = Contacts;
var $uses = 'Contact';
var $components = array('Email');
//-
function index(){
$this-set('title_for_layout', 'Contacts');
if(isset($this-data)) {
if($this-Contact-create($this-data) $this-Contact-
validates()){
//send e-mail
$this-_sendMail();
}
else {
$this-Session-setFlash('Please correct the underlying errors');
$this-redirect('/contacts/');
}
}
}
function _sendMail() {
$senderEmail = $this-data['Contact']['mail'];
$this-Email-to = $this-Session-read('Auth.User.email');
$this-Email-subject = $this-data['Contact']['subject'];
$this-Email-from = $senderEmail;
$this-Email-replyTo = $this-Session-read('Auth.User.email');
$this-Email-template = 'thanks';
//Send as 'html', 'text' or 'both' (default is 'text')
$this-Email-sendAs = 'text';
//Set view variables as normal
$this-set('fname', ucfirst($this-data['Contact']['fname']));
$this-set('lname', ucfirst($this-data['Contact'] ['lname']));
$this-set('mail', $senderEmail);
$this-set('subject', $this-data['Contact']['subject']);
//$this-$body=$this-data['Contact']['message']. Email info: First
Name: . ucfirst($this-data['Contact']['fname']). Last
Name .ucfirst($this-data['Contact'] ['lname']);
//$this-set('message', $this-body);
$this-set('content', $this-data['Contact']['content']);
//Do not pass any args to send()
if ( $this-Email-send() {
$this-Session-setFlash('Your email was send successfully');
$this-redirect('/contacts/');
exit;
} else {
$this-Session-setFlash(There was error
in sending the email. Please try again);
$this-redirect('/contacts/');
exit;
}
}
}
?
model
?php
class Contact extends AppModel {
var $name = 'Contact';
var $useTable = false;
var $validate = array(
'fname' = array('required' = VALID_NOT_EMPTY),
'lname' = array('required' = VALID_NOT_EMPTY),
'mail' = array('required' = VALID_NOT_EMPTY,
'validEmail'=VALID_EMAIL),
'subject' = array('required' = VALID_NOT_EMPTY),
'content' = array('required' = VALID_NOT_EMPTY)
);
}
?
###view
h1Contact Us/h1
?php echo $form-create('Contact', array('url'='/contacts'));?
?php
echo $form-input('fname', array('label' = 'First Name', 'error' =
array('required' = 'Please specify your First name')));
echo $form-input('lname', array('label' = 'Last Name', 'error' =
array('required' = 'Please specify your Last name')));
echo $form-input('mail', array('label' = 'Email', 'error' =
array('required' = 'Please specify your email address', 'validEmail'
= 'Insert a valid email')));
echo $form-input('subject', array('label' = 'Subject', 'error' =
array('required' = 'Insert email subject')));
echo $form-input('content', array('label' = 'Message', 'error' =
array('required' ='Insert your message here'), 'type'='textarea',
'cols'=30));
?
div class=submitinput type=submit value=Send //div
/form
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Re: email body/message does not come through
found the answer... in the elements/email/text/thanks.cpt do this
?php echo $this-data['Contact']['content']; ?
On Tue, Oct 14, 2008 at 1:46 PM, gabriel [EMAIL PROTECTED] wrote:
Hi My emails works, but the message/body/content part of the email
does not come through, the $this-Email-template = 'thanks'; does
not come through...can anyone please help.
?php
class ContactsController extends AppController
{
var $name = Contacts;
var $uses = 'Contact';
var $components = array('Email');
//-
function index(){
$this-set('title_for_layout', 'Contacts');
if(isset($this-data)) {
if($this-Contact-create($this-data) $this-Contact-
validates()){
//send e-mail
$this-_sendMail();
}
else {
$this-Session-setFlash('Please correct the underlying errors');
$this-redirect('/contacts/');
}
}
}
function _sendMail() {
$senderEmail = $this-data['Contact']['mail'];
$this-Email-to = $this-Session-read('Auth.User.email');
$this-Email-subject = $this-data['Contact']['subject'];
$this-Email-from = $senderEmail;
$this-Email-replyTo = $this-Session-read('Auth.User.email');
$this-Email-template = 'thanks';
//Send as 'html', 'text' or 'both' (default is 'text')
$this-Email-sendAs = 'text';
//Set view variables as normal
$this-set('fname', ucfirst($this-data['Contact']['fname']));
$this-set('lname', ucfirst($this-data['Contact'] ['lname']));
$this-set('mail', $senderEmail);
$this-set('subject', $this-data['Contact']['subject']);
//$this-$body=$this-data['Contact']['message']. Email info: First
Name: . ucfirst($this-data['Contact']['fname']). Last
Name .ucfirst($this-data['Contact'] ['lname']);
//$this-set('message', $this-body);
$this-set('content', $this-data['Contact']['content']);
//Do not pass any args to send()
if ( $this-Email-send() {
$this-Session-setFlash('Your email was send successfully');
$this-redirect('/contacts/');
exit;
} else {
$this-Session-setFlash(There was error
in sending the email. Please try again);
$this-redirect('/contacts/');
exit;
}
}
}
?
model
?php
class Contact extends AppModel {
var $name = 'Contact';
var $useTable = false;
var $validate = array(
'fname' = array('required' = VALID_NOT_EMPTY),
'lname' = array('required' = VALID_NOT_EMPTY),
'mail' = array('required' = VALID_NOT_EMPTY,
'validEmail'=VALID_EMAIL),
'subject' = array('required' = VALID_NOT_EMPTY),
'content' = array('required' = VALID_NOT_EMPTY)
);
}
?
###view
h1Contact Us/h1
?php echo $form-create('Contact', array('url'='/contacts'));?
?php
echo $form-input('fname', array('label' = 'First Name', 'error' =
array('required' = 'Please specify your First name')));
echo $form-input('lname', array('label' = 'Last Name', 'error' =
array('required' = 'Please specify your Last name')));
echo $form-input('mail', array('label' = 'Email', 'error' =
array('required' = 'Please specify your email address', 'validEmail'
= 'Insert a valid email')));
echo $form-input('subject', array('label' = 'Subject', 'error' =
array('required' = 'Insert email subject')));
echo $form-input('content', array('label' = 'Message', 'error' =
array('required' ='Insert your message here'), 'type'='textarea',
'cols'=30));
?
div class=submitinput type=submit value=Send //div
/form
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help with get product by user, function in products controller
Hi, i hope someone can help me here please, I need help with my
controller function, I want to get products by user_id, unfortunately
I have no idea where to start, help will be greatfully received.
Here is my code so far...
class ProductsController extends AppController {
var $name = 'Products';
var $uses = array('Product', 'Category', 'User');
var $components = array('Search','Files');
function view() {
$this-Product-recursive = 0;
$this-set('products', $this-paginate());
$this-set('users', $this-User-read(null, $id));
}
Thanks
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Re: help with get product by user, function in products controller
Thanks Marcus, I will try it, you are a star.
On Tue, Oct 14, 2008 at 10:33 PM, Marcus Silva
[EMAIL PROTECTED] wrote:
Ok,
You might be able to do this:
Add a relationship in your user model; example: User hasMany Product
etc...
Then in you controller you can do the following:
$this-User-id = $id; //Passed in the function
$userProducts = $this-User-Product-find('all',$params =
array( 'conditions' = add any extra condition in here , it can be
an array as well. ));
//then set the data to be available int he view.
Better yet, you could write a custom function in the User model to get
products for the user, that would save typying etc..
in user.php //model
function getProduct(){
//The model must be associated before trying to do this.
return $this-Product-find();
}
in the controller you do:
$userProducts = $this-User-getProduct(); //SImple
Hope it helps...
Cheers
gabriel wrote:
Hi, i hope someone can help me here please, I need help with my
controller function, I want to get products by user_id, unfortunately
I have no idea where to start, help will be greatfully received.
Here is my code so far...
class ProductsController extends AppController {
var $name = 'Products';
var $uses = array('Product', 'Category', 'User');
var $components = array('Search','Files');
function view() {
$this-Product-recursive = 0;
$this-set('products', $this-paginate());
$this-set('users', $this-User-read(null, $id));
}
Thanks
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Re: help with get product by user, function in products controller
Hi Marcus
I have done the following, but it returns ALL the products NOT just
the user's is it possible to point out my error?
Thanks
My model (user)
var $hasMany = array(
'Product' = array('className' = 'Product',
'foreignKey' = 'product_id',
product controller
function viewbyuser() {
$products = $this-User-Product-find('all' , array('conditions' =
array('user_id' = $this-Session-read('Auth.User.id') )));
$this-set('products', $this-paginate());
}
On Tue, Oct 14, 2008 at 10:33 PM, Marcus Silva
[EMAIL PROTECTED] wrote:
Ok,
You might be able to do this:
Add a relationship in your user model; example: User hasMany Product
etc...
Then in you controller you can do the following:
$this-User-id = $id; //Passed in the function
$userProducts = $this-User-Product-find('all',$params =
array( 'conditions' = add any extra condition in here , it can be
an array as well. ));
//then set the data to be available int he view.
Better yet, you could write a custom function in the User model to get
products for the user, that would save typying etc..
in user.php //model
function getProduct(){
//The model must be associated before trying to do this.
return $this-Product-find();
}
in the controller you do:
$userProducts = $this-User-getProduct(); //SImple
Hope it helps...
Cheers
gabriel wrote:
Hi, i hope someone can help me here please, I need help with my
controller function, I want to get products by user_id, unfortunately
I have no idea where to start, help will be greatfully received.
Here is my code so far...
class ProductsController extends AppController {
var $name = 'Products';
var $uses = array('Product', 'Category', 'User');
var $components = array('Search','Files');
function view() {
$this-Product-recursive = 0;
$this-set('products', $this-paginate());
$this-set('users', $this-User-read(null, $id));
}
Thanks
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Re: Yet another site powered by Cakephp
Hi, my name is Gabriel, I did respond to your email on cake groups. As I said I am working on a similar site - for the UK market. I am using Bakesale as a basis which I edit. I know this is very bold of me to ask you this, but it would save me a lot of time if I could buy your code and edit it to my own needs. I don't want to offend you, but would you be willing to sell the code? After I am finished personalising and taking away and adding stuff to it, it would look very different to what you have now, but some of what you have I need to do too and it would save me much time if I don't have to do everything from scratch. I can also work on some ' modules' which you might be interested in to add to your website. Hope to hear from you soon. Kind Regards On Sun, Oct 12, 2008 at 10:50 PM, Sayhello [EMAIL PROTECTED] wrote: Thank you all for the feedback so far. I am not using bakesale right now, but perhaps that can be a feature for v1.5. Thanks www.sayhello.me On Oct 12, 2:36 pm, Gabriel Kolbe [EMAIL PROTECTED] wrote: Hi did you use Bakesale and customized it a bit? regards On Sat, Oct 11, 2008 at 8:28 AM, Sayhello [EMAIL PROTECTED] wrote: Hello all, Just wanted to introduce yet another site built with CakePHP 1.2 RC3 - www.sayhello.me. Sayhello is a new classified ads site to help you buy and sell. We are initially launching in the Los Angeles market. Check it out. Any suggestions and feedback are welcome. Thank you! www.sayhello.me- Hide quoted text - - Show quoted text - --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Yet another site powered by Cakephp
Hi did you use Bakesale and customized it a bit? regards On Sat, Oct 11, 2008 at 8:28 AM, Sayhello [EMAIL PROTECTED] wrote: Hello all, Just wanted to introduce yet another site built with CakePHP 1.2 RC3 - www.sayhello.me. Sayhello is a new classified ads site to help you buy and sell. We are initially launching in the Los Angeles market. Check it out. Any suggestions and feedback are welcome. Thank you! www.sayhello.me --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Recursive Association in Model
Hi there,
If you play around with Set::combine and Set::extract a bit you could
achieve the desired results. As I know for a fact that you're a fellow
brazilian, take a look at this blog post:
http://kiss.souagil.com.br/2008/08/manipulando-arrays-associativas/
I hope it'll help you.
Cheers,
Gabriel Gilini
www.usosim.com.br
[EMAIL PROTECTED]
[EMAIL PROTECTED]
On Thu, Oct 9, 2008 at 10:41 AM, SamuraiDio [EMAIL PROTECTED] wrote:
Hi...
A friend of mine is developing an application with uses a recursive
hasMany association in a Model.
Everything is working fine, except that the obtained data array is
ugly, and dificult to work on.
This is the Model definition:
class PlanoConta extends AppModel {
var $name = 'PlanoConta';
var $displayField = 'nome';
var $hasMany = array(
'PlanoContaFilho' = array(
'className' = 'PlanoConta',
'foreignKey' = 'parent_id'
)
);
}
Using a
find('all' array('recursive' = 3)); //omiting irrelevant option...
The resultset is like this:
http://pastebin.com/m354d1d17
But it would be better to obtain something like this:
http://pastebin.com/f31071d88
Is it possible to obtain a resultset like this?
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Re: how to unit test a shell script
So, are there any guidelines to write a Shell Test Case?
On 16 set, 18:05, mark_story [EMAIL PROTECTED] wrote:
Jeurgen, Testingshellclasses is a bit tricky right now
App::import() currently does not let you target shells so you have to
include them regular php style. We are working on ways of improving
this though, as testing shells is a big pain right now.
-Mark
On Sep 16, 9:45 am, JuergenRiemer [EMAIL PROTECTED] wrote:
Hi,
I do the following to unittestashellscript
[ learn.test.php ] put in a folder tests/cases/shells (that I
created)
?php
App::import( 'Shell', 'Learn' );
class LearnShellTest extends CakeTestCase {
function setUp(){
$this-LearnShell = new LearnShell();
}
function testOne(){
$this-LearnShell-testFunc();
}}
?
how ever it does not find the Class LearnShell.
Now before I get deeper into it... can anyone point me to the proper
solution?
thx
Jeurgen
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anyone know why this session check does not work like it suppose to
I login, then want to check the session if a person has admin rights
If I login as an 'admin' where the role = admin or if I login as a non-
admin where the role=0, it displays in both situations the admin area
link...
the script: if ($session-check('Auth.User.role') == 'admin') {
echo $html-link('Admin Area', '/admin/');
} else {
echo $html-link('My Account', '/accnt/');
}
In the debug the 'role' is set to '0'
in the debug I get :
[Auth] = Array
(
[User] = Array
(
[id] = 3
[username] = gab
[fname] =
[lname] = sdf
[email] = [EMAIL PROTECTED]
[tell] = sdf
[cell] =
[hnum] =
[street] =
[city] = 0
[county_id] = 0
[country_id] = 0
[pcode] =
[maillist] = 0
[created] = 2008-10-01 13:52:50
[role] = 0
[ip] =
[lastvisit] = -00-00 00:00:00
[emailssend] = 0
[browser] = 0
[screen] =
)
)
any help
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Re: Site powered by CakePHP
Looks good, how do you join the project? By registering in the site? On Wed, Oct 8, 2008 at 8:58 PM, dezpo [EMAIL PROTECTED] wrote: Hello bakers, Just wanted to show you what I have did in the past 2 months using cakephp. This is my new site about car fans. If you have time please try to test it or even join this project. Thank you. www.autolive.org --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: anyone know why this session check does not work like it suppose to
ha-ha, thanks, so obvious! On Thu, Oct 9, 2008 at 2:07 PM, 3lancer.eu [EMAIL PROTECTED] wrote: Hi, There is essential difference between read() and check() methods of the Session class. However, you should rather use the following convention: http://book.cakephp.org/view/247/AuthComponent-Methods#user-387 Regards, Piotr --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: newbie question
I user Xampp, and it works like a dream !! On Thu, Oct 9, 2008 at 4:09 AM, [EMAIL PROTECTED] wrote: I think it may be best if you use a real server! On 10/08/2008, JRough [EMAIL PROTECTED] wrote: I want to try out Cakephp. Do you know if I can use it with XXAMP on Windows just for testing or do I have to install it on a real server? thanks, -- Xavier A. Mathews Student/Developer/Web-Master GG Client Based Tech Support Specialist Hazel Crest Illinois [EMAIL PROTECTED] Fear of a name, only increases fear of the thing itself. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: How do i upload images using cakephp
Hi I don't know how too but.. you can steal some ideas how to handles images at http://www.bakesalehq.com/ since it is a ecommerce site/template that uses images On Fri, Oct 3, 2008 at 12:43 PM, AceStudio [EMAIL PROTECTED] wrote: I am developing a social community and would like members profile to show their pictures or avatar. Cake documentation doesn't deal with this at all. Please i'd appreciate if someone treated this --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Add user_id from session to db when adding a product
Hi, I am busy reworking a bakesale script based on cake, my OOP php is
not that good. Maybe someone can point me here in the right direction.
I want to change a script the add a product and in sert in the db the
user_id in the product table - which should come from the User.id
function admin_add($category_id = 0) {
if(isset($this-data['Product'])) {
$this-redirect(array('action' = 'edit', 'id' = $this-
Product-bsAdd($this-data)));
} else {
$this-set('data', $this-Category-read(null,
$category_id));
}
}
function bsAdd($data = array()) {
$this-create();
$this-data = $data;
$this-save($this-data);
return $this-getLastInsertID();
}
Any help will be most greatful !!
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Re: Add user_id from session to db when adding a product
Hi I would prefer to get the value from the session.
When I do
if(isset($this-data['Product']['user_id'] = $user_id)) {
if(isset($this-data['Product']['user_id'] = $this-Auth-user('id');) {
I get this error
Parse error: syntax error, unexpected '=', expecting ',' or ')' in
C:\xampp\htdocs\bakesale\app\controllers\products_controller.php on
line 96
Seems like it does not like the ' = ' I don't want to be a bother, but
any idea how to fix it?
Regards
On Fri, Oct 3, 2008 at 4:18 PM, Mathew [EMAIL PROTECTED] wrote:
Assuming you want the currently logged in administrator.
$this-data['Product']['user_id'] = $this-Auth-user('id');
Otherwise, you'll need a belongsTo association in your Product model,
and allow scaffolding to show a user drop down list.
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trying to add new pages and use same layout page in Bakesale
Hi All. I am trying to edit the Bakesale library I downloaded from the
internet, which runs on cake. BakeSale uses, to layouts - admin, and
show. I have added 2 new sets of controllers, views, models. If I type
in users/register , it keeps opening up in the 'CakePHP: the rapid
development php framework' default page, and NOT in the show - layout.
I have been looking everywhere, and can not findout where they 'force'
the views to open up in the specific layout. ( I have created a
'default' layout - and this kind of work) but this is not what I want
to do. Does anyone have any ideas, it would be grate - the only code I
find that might explain it is in the app_controller, posted below.
function beforeFilter() {
$this-_checkLogin();
if (!isset($this-params['requested'])) {
Configure::load('custom/bakesale_config');
Configure::write('Config.language',
Configure::read('Site.locale'));
$this-theme = Configure::read('Site.theme');
$this-_setDefaults();
$this-addUrl();
}
}
function _setDefaults() {
$bodyClass = $checked = $selected = '';
$extraCss = array();
$isAdmin = $simpleLayout = false;
if($this-Session-check('Auth.User.role')== 'role') {
$isAdmin = true;
}
$this-set(compact('bodyClass', 'checked', 'selected',
'isAdmin',
'extraCss', 'simpleLayout'));
if(!isset($this-params['admin'])) {
$this-layout = 'shop';
} else {
$this-Session-write('Admin.id', '1');
$this-layout = 'admin';
}
}
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Re: trying to add new pages and use same layout page in Bakesale
I also found some code in the routes.php which I copied and changed
for users, but it does not help yet . ( I have renamed the index views
and functions - show ) trying to replicate the other senarious.
// SEO setting for products
Router::connect('/:myvar/p/*',
array('myvar' = null, 'controller' = 'products', 'action' = 'show'),
array('myvar' = '.*')
);
Router::connect(
'/:slug-p-:id.html',
array('controller' = 'products', 'action' = 'show'),
array(
'pass' = array('id', 'slug'),
'slug' = '.*',
'id' = '[\d]+'
)
);
// SEO setting for users
Router::connect('/:myvar/u/*',
array('myvar' = null, 'controller' = 'users', 'action' = 'show'),
array('myvar' = '.*')
);
Router::connect(
'/:slug-p-:id.html',
array('controller' = 'users', 'action' = 'show'),
array(
'pass' = array('id', 'slug'),
'slug' = '.*',
'id' = '[\d]+'
)
);
On Thu, Oct 2, 2008 at 6:52 PM, gabriel [EMAIL PROTECTED] wrote:
Hi All. I am trying to edit the Bakesale library I downloaded from the
internet, which runs on cake. BakeSale uses, to layouts - admin, and
show. I have added 2 new sets of controllers, views, models. If I type
in users/register , it keeps opening up in the 'CakePHP: the rapid
development php framework' default page, and NOT in the show - layout.
I have been looking everywhere, and can not findout where they 'force'
the views to open up in the specific layout. ( I have created a
'default' layout - and this kind of work) but this is not what I want
to do. Does anyone have any ideas, it would be grate - the only code I
find that might explain it is in the app_controller, posted below.
function beforeFilter() {
$this-_checkLogin();
if (!isset($this-params['requested'])) {
Configure::load('custom/bakesale_config');
Configure::write('Config.language',
Configure::read('Site.locale'));
$this-theme = Configure::read('Site.theme');
$this-_setDefaults();
$this-addUrl();
}
}
function _setDefaults() {
$bodyClass = $checked = $selected = '';
$extraCss = array();
$isAdmin = $simpleLayout = false;
if($this-Session-check('Auth.User.role')== 'role') {
$isAdmin = true;
}
$this-set(compact('bodyClass', 'checked', 'selected',
'isAdmin',
'extraCss', 'simpleLayout'));
if(!isset($this-params['admin'])) {
$this-layout = 'shop';
} else {
$this-Session-write('Admin.id', '1');
$this-layout = 'admin';
}
}
--~--~-~--~~~---~--~~
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-~--~~~~--~~--~--~---
Crumbs - crumbs - crumbs
I could probably do this easily in sessions BUT I don't want to
reinvent Cakes wheels. So, I have added
?=$html-addCrumb('Register', '/users/register');? in the
register.ctp view. and added the the ?=$html-getCrumbs();? in the
default.ctp layout. It only displays the current view and does not
remember the path like page1page2page3. ect.
Does any one know what do I do wrong?
Obvoiusly I will bless you if you can.;)
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Re: Adding to db without going to view..?
Hi Rich
Thanks for that !! One more question..
If I want to change the
($this-UserFavourite-save($this-data)) {
where the controller gets the info from the view..
echo $form-input('user_id');
echo $form-input('item_id');
I want the controller not to go the the 'add' view but just add user
(in the session)($session-read('Auth.User.id')), to db, and also the
item_id which will be given in the URL like so:
testsite/user_favourites/add/2
Any idea how to do this??
Regards
On Fri, Sep 26, 2008 at 7:02 PM, Donkeybob [EMAIL PROTECTED] wrote:
You use it the way you have it and just change the section in the add
function to redirect . . .
- $this-redirect(array('action'='view'));
Every function should have a related view file unless you state
otherwise with a layout call.
if your action is add then you have to have an add function in the
controller, which uses the add view. . . .just redirect it in your
statement.
function add() {
if (!empty($this-data)) {
$this-UserFavourite-create();
if ($this-UserFavourite-save($this-data)) {
$this-Session-setFlash(__('The
UserFavourite has been saved', true));
$this-
redirect(array('action'='view'));
} else {
$this-Session-setFlash(__('The
UserFavourite could not be saved. Please, try again.', true));
$this-
redirect(array('action'='view'));
}
}
}
hope this is a start
rich
On Sep 26, 10:59 am, gabriel [EMAIL PROTECTED] wrote:
Hi, does anyone know how I can add (like a favourite to a db table)
without going to the add view?
I have a link
testsite/user_favourites/add/2
IF I click on it it, it takes me to the add view (which has a model
and controller)
I DON'T want to go to the add view, but the 'view' view which shows
the favourite that had just been added... here is the add controller
and view and model
controller /
function add() {
if (!empty($this-data)) {
$this-UserFavourite-create();
if ($this-UserFavourite-save($this-data)) {
$this-Session-setFlash(__('The
UserFavourite has been saved',
true));
$this-redirect(array('action'='index'));
} else {
$this-Session-setFlash(__('The
UserFavourite could not be saved.
Please, try again.', true));
}
}
$users = $this-UserFavourite-User-find('list');
$this-set(compact('users'));
}
model//
class UserFavourite extends AppModel {
var $name = 'UserFavourite';
var $validate = array(
'id' = array('numeric'),
'user_id' = array('numeric'),
'item_id' = array('numeric')
);
//The Associations below have been created with all possible keys,
those that are not needed can be removed
var $belongsTo = array(
'User' = array('className' = 'User',
'foreignKey'
= 'user_id',
'conditions'
= '',
'fields' =
'',
'order' = ''
)
);
}
///
view//
div class=userFavourites form
?php echo $form-create('UserFavourite');?
fieldset
legend?php __('Add UserFavourite');?/legend
?php
echo $form-input('user_id');
echo $form-input('item_id');
?
/fieldset
?php echo $form-end('Submit');?
/div
div class=actions
ul
li?php echo $html-link(__('List UserFavourites', true),
array('action'='index'));?/li
li?php echo $html-link(__('List Users', true),
array('controller'= 'users', 'action'='index')); ? /li
li?php echo $html-link(__('New User', true),
array('controller'= 'users', 'action'='add')); ? /li
/ul
/div
--~--~-~--~~~---~--~~
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For more options, visit
Adding to db without going to view..?
Hi, does anyone know how I can add (like a favourite to a db table)
without going to the add view?
I have a link
testsite/user_favourites/add/2
IF I click on it it, it takes me to the add view (which has a model
and controller)
I DON'T want to go to the add view, but the 'view' view which shows
the favourite that had just been added... here is the add controller
and view and model
controller /
function add() {
if (!empty($this-data)) {
$this-UserFavourite-create();
if ($this-UserFavourite-save($this-data)) {
$this-Session-setFlash(__('The UserFavourite
has been saved',
true));
$this-redirect(array('action'='index'));
} else {
$this-Session-setFlash(__('The UserFavourite
could not be saved.
Please, try again.', true));
}
}
$users = $this-UserFavourite-User-find('list');
$this-set(compact('users'));
}
model//
class UserFavourite extends AppModel {
var $name = 'UserFavourite';
var $validate = array(
'id' = array('numeric'),
'user_id' = array('numeric'),
'item_id' = array('numeric')
);
//The Associations below have been created with all possible keys,
those that are not needed can be removed
var $belongsTo = array(
'User' = array('className' = 'User',
'foreignKey' =
'user_id',
'conditions' =
'',
'fields' = '',
'order' = ''
)
);
}
///
view//
div class=userFavourites form
?php echo $form-create('UserFavourite');?
fieldset
legend?php __('Add UserFavourite');?/legend
?php
echo $form-input('user_id');
echo $form-input('item_id');
?
/fieldset
?php echo $form-end('Submit');?
/div
div class=actions
ul
li?php echo $html-link(__('List UserFavourites', true),
array('action'='index'));?/li
li?php echo $html-link(__('List Users', true),
array('controller'= 'users', 'action'='index')); ? /li
li?php echo $html-link(__('New User', true),
array('controller'= 'users', 'action'='add')); ? /li
/ul
/div
--~--~-~--~~~---~--~~
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-~--~~~~--~~--~--~---
Linking to the admin area?
Hi, I have to functions in the user_controller. One is admin_accnt, the other is accnt. How do I link to the admin_accnt ? My link echo $html-link(Admin, array(controller = users, action = admin_accnt)); IF I just do echo $html-link(Admin, array(controller = users, action = accnt)); I go the the accnt function/view IF I go the the admin_accnt I get Error: UsersController::admin_accnt() cannot be accessed directly. Help will be appreciated!! --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Linking to the admin area?
S'ok, found the answer..
echo $html-link('Admin Area', '/admin/users/accnt');
On Fri, Sep 26, 2008 at 4:14 PM, gabriel [EMAIL PROTECTED] wrote:
Hi, I have to functions in the user_controller.
One is admin_accnt, the other is accnt.
How do I link to the admin_accnt ?
My link
echo $html-link(Admin, array(controller = users, action =
admin_accnt));
IF I just do
echo $html-link(Admin, array(controller = users, action =
accnt));
I go the the accnt function/view
IF I go the the admin_accnt I get
Error: UsersController::admin_accnt() cannot be accessed directly.
Help will be appreciated!!
--~--~-~--~~~---~--~~
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-~--~~~~--~~--~--~---
PLease help, 3 days struggle with 'simple' authentication
This is my current code:
class AppController extends Controller {
var $components = array('Auth');
function beforeFilter() {
$this-Auth-authorize = 'controller';
$this-Auth-allow('*');
$this-Auth-deny('admin', 'accnt', 'faq'); // does not work
}
function isAuthorized() {
if ($this-Auth-user('role') == 'admin') {
$this-Auth-allow('admin');
}
}
}
What I want to do is something like the following:
function beforeFilter() {
$this-Auth-authorize = 'controller';
$this-Auth-allow('pages/faq', 'pages/aboutus', 'users/
register');
$this-Auth-deny('pages/accnt', 'pages/admin', 'categories/
edit');
}
function isAuthorized() {
if ($this-Auth-user('role') == 'admin') {
$this-Auth-allow('pages/admin', 'categories/edit');
}
$this-Auth-allow('pages/accnt');
}
}
NOTE: the pages does not have a model or controller..I HAVE read the
cookbooks severaltimes, served the Cakegroup, posted several message,
got different replies, but just can' t seem to find a answer to
this... I would be grateful if someone can actually show me ..
--~--~-~--~~~---~--~~
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-~--~~~~--~~--~--~---
Re: PLease help, 3 days struggle with 'simple' authentication
S'ok, I created 'fake' functions in the user controller, then added
the views to the users views, then take the Authentication process
from the app_controller to the users_controller..
On Wed, Sep 24, 2008 at 10:54 AM, gabriel [EMAIL PROTECTED] wrote:
This is my current code:
class AppController extends Controller {
var $components = array('Auth');
function beforeFilter() {
$this-Auth-authorize = 'controller';
$this-Auth-allow('*');
$this-Auth-deny('admin', 'accnt', 'faq'); // does not work
}
function isAuthorized() {
if ($this-Auth-user('role') == 'admin') {
$this-Auth-allow('admin');
}
}
}
What I want to do is something like the following:
function beforeFilter() {
$this-Auth-authorize = 'controller';
$this-Auth-allow('pages/faq', 'pages/aboutus', 'users/
register');
$this-Auth-deny('pages/accnt', 'pages/admin', 'categories/
edit');
}
function isAuthorized() {
if ($this-Auth-user('role') == 'admin') {
$this-Auth-allow('pages/admin', 'categories/edit');
}
$this-Auth-allow('pages/accnt');
}
}
NOTE: the pages does not have a model or controller..I HAVE read the
cookbooks severaltimes, served the Cakegroup, posted several message,
got different replies, but just can' t seem to find a answer to
this... I would be grateful if someone can actually show me ..
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
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-~--~~~~--~~--~--~---
Re: PLease help, 3 days struggle with 'simple' authentication
ta
On Wed, Sep 24, 2008 at 1:17 PM, RichardAtHome [EMAIL PROTECTED] wrote:
$this-Auth-deny('admin', 'accnt', 'faq'); // does not work
This doesn't work because the 'action' for all views in the pages
controller is 'display' not 'admin', 'accnt'
$this-Auth-deny(display) would work, but it would deny ALL views
handled by the pages controller.
Your workaround is a good compromise. Or you could make your own
dedicated MyPagesController to group all these pages together.
On Sep 24, 11:12 am, Gabriel Kolbe [EMAIL PROTECTED] wrote:
S'ok, I created 'fake' functions in the user controller, then added
the views to the users views, then take the Authentication process
from the app_controller to the users_controller..
On Wed, Sep 24, 2008 at 10:54 AM, gabriel [EMAIL PROTECTED] wrote:
This is my current code:
class AppController extends Controller {
var $components = array('Auth');
function beforeFilter() {
$this-Auth-authorize = 'controller';
$this-Auth-allow('*');
$this-Auth-deny('admin', 'accnt', 'faq'); // does not work
}
function isAuthorized() {
if ($this-Auth-user('role') == 'admin') {
$this-Auth-allow('admin');
}
}
}
What I want to do is something like the following:
function beforeFilter() {
$this-Auth-authorize = 'controller';
$this-Auth-allow('pages/faq', 'pages/aboutus', 'users/
register');
$this-Auth-deny('pages/accnt', 'pages/admin', 'categories/
edit');
}
function isAuthorized() {
if ($this-Auth-user('role') == 'admin') {
$this-Auth-allow('pages/admin', 'categories/edit');
}
$this-Auth-allow('pages/accnt');
}
}
NOTE: the pages does not have a model or controller..I HAVE read the
cookbooks severaltimes, served the Cakegroup, posted several message,
got different replies, but just can' t seem to find a answer to
this... I would be grateful if someone can actually show me ..
--~--~-~--~~~---~--~~
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CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
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-~--~~~~--~~--~--~---
Wouldn't it be great if cake adds a straight PHP equivalent on it's manual pages e.g redirection
Wouldn't it be great if cake adds a straight PHP equivalent on it's manual pages, for instance I want to redirect a page in straight PHP it would be ' header(Location: index.php); ' does any one know how to do this in CAKE ? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Wouldn't it be great if cake adds a straight PHP equivalent on it's manual pages e.g redirection
Hi doc Thanks for the reply, but how do I redirect in a view which does not have a model or controller? On Tue, Sep 23, 2008 at 1:26 PM, dr. Hannibal Lecter [EMAIL PROTECTED] wrote: Of course, why not :) http://api.cakephp.org/class_controller.html#903188d3de83bd65c78bb676f61b3039 On Sep 23, 2:00 pm, gabriel [EMAIL PROTECTED] wrote: Wouldn't it be great if cake adds a straight PHP equivalent on it's manual pages, for instance I want to redirect a page in straight PHP it would be ' header(Location: index.php); ' does any one know how to do this in CAKE ? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: Wouldn't it be great if cake adds a straight PHP equivalent on it's manual pages e.g redirection
Hi, my situation is the following:
// check if user is logged in...
? if ($session-check('Auth.User.id')) { ?
do your thing
? } else { ?
redirect page somewhere else
?
}
?
is is done in a view how, do you mean I have to check the login in the
function in the controller ?
Regards
On Tue, Sep 23, 2008 at 4:34 PM, dr. Hannibal Lecter
[EMAIL PROTECTED] wrote:
Hi again,
as teknoid said, don't redirect from a view.
If you've come to a point where you redirect from a view, you should
seriously reconsider you coding strategy. Views are supposed to
display data, define the look of your app and input forms; but never
handle any business or application logic.
The name itself implies it - view ;)
On Sep 23, 4:53 pm, Gabriel Kolbe [EMAIL PROTECTED] wrote:
Hi doc
Thanks for the reply, but how do I redirect in a view which does not
have a model or controller?
On Tue, Sep 23, 2008 at 1:26 PM, dr. Hannibal Lecter
[EMAIL PROTECTED] wrote:
Of course, why not :)
http://api.cakephp.org/class_controller.html#903188d3de83bd65c78bb676...
On Sep 23, 2:00 pm, gabriel [EMAIL PROTECTED] wrote:
Wouldn't it be great if cake adds a straight PHP equivalent on it's
manual pages, for instance I want to redirect a page in straight PHP
it would be ' header(Location: index.php); ' does any one know how
to do this in CAKE ?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
http://groups.google.com/group/cake-php?hl=en
-~--~~~~--~~--~--~---
Re: Wouldn't it be great if cake adds a straight PHP equivalent on it's manual pages e.g redirection
Sorry, just to add to the info below, the view DOES not have a
controller or a model, not I don't want to place it in the
app_controller, because some page accessable even if you are not
logged in.. my problem is I am unexperienced and it is mega
frastrating !!
On Tue, Sep 23, 2008 at 7:09 PM, Gabriel Kolbe [EMAIL PROTECTED] wrote:
Hi, my situation is the following:
// check if user is logged in...
? if ($session-check('Auth.User.id')) { ?
do your thing
? } else { ?
redirect page somewhere else
?
}
?
is is done in a view how, do you mean I have to check the login in the
function in the controller ?
Regards
On Tue, Sep 23, 2008 at 4:34 PM, dr. Hannibal Lecter
[EMAIL PROTECTED] wrote:
Hi again,
as teknoid said, don't redirect from a view.
If you've come to a point where you redirect from a view, you should
seriously reconsider you coding strategy. Views are supposed to
display data, define the look of your app and input forms; but never
handle any business or application logic.
The name itself implies it - view ;)
On Sep 23, 4:53 pm, Gabriel Kolbe [EMAIL PROTECTED] wrote:
Hi doc
Thanks for the reply, but how do I redirect in a view which does not
have a model or controller?
On Tue, Sep 23, 2008 at 1:26 PM, dr. Hannibal Lecter
[EMAIL PROTECTED] wrote:
Of course, why not :)
http://api.cakephp.org/class_controller.html#903188d3de83bd65c78bb676...
On Sep 23, 2:00 pm, gabriel [EMAIL PROTECTED] wrote:
Wouldn't it be great if cake adds a straight PHP equivalent on it's
manual pages, for instance I want to redirect a page in straight PHP
it would be ' header(Location: index.php); ' does any one know how
to do this in CAKE ?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
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-~--~~~~--~~--~--~---
Re: Wouldn't it be great if cake adds a straight PHP equivalent on it's manual pages e.g redirection
thanks
On Tue, Sep 23, 2008 at 7:26 PM, teknoid [EMAIL PROTECTED] wrote:
Again, this approach is not correct.
Checking for user status, should always be done in the controller.
Take a look at the auth component in the manual to see how you can
restrict access to certain resources/pages.
On Sep 23, 2:14 pm, Gabriel Kolbe [EMAIL PROTECTED] wrote:
Sorry, just to add to the info below, the view DOES not have a
controller or a model, not I don't want to place it in the
app_controller, because some page accessable even if you are not
logged in.. my problem is I am unexperienced and it is mega
frastrating !!
On Tue, Sep 23, 2008 at 7:09 PM, Gabriel Kolbe [EMAIL PROTECTED] wrote:
Hi, my situation is the following:
// check if user is logged in...
? if ($session-check('Auth.User.id')) { ?
do your thing
? } else { ?
redirect page somewhere else
?
}
?
is is done in a view how, do you mean I have to check the login in the
function in the controller ?
Regards
On Tue, Sep 23, 2008 at 4:34 PM, dr. Hannibal Lecter
[EMAIL PROTECTED] wrote:
Hi again,
as teknoid said, don't redirect from a view.
If you've come to a point where you redirect from a view, you should
seriously reconsider you coding strategy. Views are supposed to
display data, define the look of your app and input forms; but never
handle any business or application logic.
The name itself implies it - view ;)
On Sep 23, 4:53 pm, Gabriel Kolbe [EMAIL PROTECTED] wrote:
Hi doc
Thanks for the reply, but how do I redirect in a view which does not
have a model or controller?
On Tue, Sep 23, 2008 at 1:26 PM, dr. Hannibal Lecter
[EMAIL PROTECTED] wrote:
Of course, why not :)
http://api.cakephp.org/class_controller.html#903188d3de83bd65c78bb676...
On Sep 23, 2:00 pm, gabriel [EMAIL PROTECTED] wrote:
Wouldn't it be great if cake adds a straight PHP equivalent on it's
manual pages, for instance I want to redirect a page in straight PHP
it would be ' header(Location: index.php); ' does any one know how
to do this in CAKE ?
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
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-~--~~~~--~~--~--~---
Getting the session user_id, when login
Hi, I have created an authentication according to the cookbook. I login and check the sessions, I can get the user_id like $_SESSION['Auth']['User']['id'], is there any better way of getting the session value ? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
dealing with sessions - should be a simple answer..
Hi, I have a reasonable simple question for an experienced person..
I did authentication according to the cookbook, I want to access the
user id via session.
I do this in the user controller...
function login() {
$userid = $this-Auth-user('id');
$this-Session-write('id', $userid );
}
Then I want to do this in the view..
? pr($session-read('id')); ?
to see if I get the value, but it does not seems to work in the login
function, if you place it in the view function it works, but I need
the values to be set to the session at login.
Help will be greatly appreciated. thanks
--~--~-~--~~~---~--~~
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simple session question - for Authentication
Hi, I have followed the Authentication in the Cookbook. I have a few
problems, maybe someone can help me. Firstly to 'allow' certain pages,
I place the $this-Auth-allow('add'); in the Users controller and
get and error, I have also tried to include it in the add and login
functions, but it does not seems to work, the error is
Parse error: syntax error, unexpected T_VARIABLE, expecting T_FUNCTION
in C:\xampp\htdocs\testsite\app\controllers\users_controller.php on
line 8
class UsersController extends AppController {
var $name = 'Users';
var $helpers = array('Html', 'Form', 'Session');
// var $components = array('Auth'); //declared in app_controller.php
$this-Auth-allow('add');
SECONDLY: I am trying to do a on sessions, if I do pr($_SESSION); I
get all the sessions - see below..I want the user_id, I have tried
print_r($_SESSION['Config']['User']['id']) which works but when I put
in the
?php echo $html-link(My classified adds , array(controller =
items, action =
view, .$_SESSION['Config']['User']['id']).)); ?
it does not work, any ideas, anyone??? I have tried $session-
read('id'), which does not work..( in the view)
Array
(
[User] = Array
(
[id] = 3
[username] = test
[name] = piet
[lname] = test
[email] = [EMAIL PROTECTED]
[tell] = 123
[cell] = 321
[hnum] = 2
[street] = car
[city_id] = 1
[county_id] = 2
[country_id] = 3
[pcode] = mnh
[admin] = 7
[maillist] = 0
[created] = -00-00 00:00:00
[modified] = -00-00 00:00:00
[ip] = 1
[last_visit] = 2011-11-01 00:00:00
[group_id] = 1
[active] = 0
[emailssend] = 0
[browser_id] = 1
[screen] = 11
)
)
Array
(
[Config] = Array
(
[userAgent] = a8c0ddfcbb06197967f6ae13f3fdd732
[time] = 1221835585
[rand] = 21704
[timeout] = 10
)
[Message] = Array
(
)
[Auth] = Array
(
[User] = Array
(
[id] = 3
[username] = test
[name] = piet
[lname] = test
[email] = [EMAIL PROTECTED]
[tell] = 123
[cell] = 321
[hnum] = 2
[street] = car
[city_id] = 1
[county_id] = 2
[country_id] = 3
[pcode] = mnh
[admin] = 7
[maillist] = 0
[created] = -00-00 00:00:00
[modified] = -00-00 00:00:00
[ip] = 1
[last_visit] = 2011-11-01 00:00:00
[group_id] = 1
[active] = 0
[emailssend] = 0
[browser_id] = 1
[screen] = 11
)
)
)
v
--~--~-~--~~~---~--~~
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CakePHP group.
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Re: simple session question - for Authentication
Hi, Yes!! just figured it out as well
function beforeFilter(){
$this-Auth-allow('add', '');
}
How do you 'allow' page which is not in a controler??
~AND Any ideas on ...
SECONDLY: I am trying to do a on sessions, if I do pr($_SESSION); I
get all the sessions - see below..I want the user_id, I have tried
print_r($_SESSION['Config']['User']['id']) which works but when I put
in the
?php echo $html-link(My classified adds , array(controller =
items, action =
view, .$_SESSION['Config']['User']['id']).)); ?
it does not work, any ideas, anyone??? I have tried $session-
read('id'), which does not work..( in the view)
On 19 Sep, 15:39, avairet [EMAIL PROTECTED] wrote:
Hi,
Just an idea for the first issue: put $this-Auth-allow('add') in
your beforeFilter() function!
On 19 sep, 16:31, gabriel [EMAIL PROTECTED] wrote:
Hi, I have followed the Authentication in the Cookbook. I have a few
problems, maybe someone can help me. Firstly to 'allow' certain pages,
I place the $this-Auth-allow('add'); in the Users controller and
get and error, I have also tried to include it in the add and login
functions, but it does not seems to work, the error is
Parse error: syntax error, unexpected T_VARIABLE, expecting T_FUNCTION
in C:\xampp\htdocs\testsite\app\controllers\users_controller.php on
line 8
class UsersController extends AppController {
var $name = 'Users';
var $helpers = array('Html', 'Form', 'Session');
// var $components = array('Auth'); //declared in app_controller.php
$this-Auth-allow('add');
SECONDLY: I am trying to do a on sessions, if I do pr($_SESSION); I
get all the sessions - see below..I want the user_id, I have tried
print_r($_SESSION['Config']['User']['id']) which works but when I put
in the
?php echo $html-link(My classified adds , array(controller =
items, action =
view, .$_SESSION['Config']['User']['id']).)); ?
it does not work, any ideas, anyone??? I have tried $session-
read('id'), which does not work..( in the view)
Array
(
[User] = Array
(
[id] = 3
[username] = test
[name] = piet
[lname] = test
[email] = [EMAIL PROTECTED]
[tell] = 123
[cell] = 321
[hnum] = 2
[street] = car
[city_id] = 1
[county_id] = 2
[country_id] = 3
[pcode] = mnh
[admin] = 7
[maillist] = 0
[created] = -00-00 00:00:00
[modified] = -00-00 00:00:00
[ip] = 1
[last_visit] = 2011-11-01 00:00:00
[group_id] = 1
[active] = 0
[emailssend] = 0
[browser_id] = 1
[screen] = 11
)
)
Array
(
[Config] = Array
(
[userAgent] = a8c0ddfcbb06197967f6ae13f3fdd732
[time] = 1221835585
[rand] = 21704
[timeout] = 10
)
[Message] = Array
(
)
[Auth] = Array
(
[User] = Array
(
[id] = 3
[username] = test
[name] = piet
[lname] = test
[email] = [EMAIL PROTECTED]
[tell] = 123
[cell] = 321
[hnum] = 2
[street] = car
[city_id] = 1
[county_id] = 2
[country_id] = 3
[pcode] = mnh
[admin] = 7
[maillist] = 0
[created] = -00-00 00:00:00
[modified] = -00-00 00:00:00
[ip] = 1
[last_visit] = 2011-11-01 00:00:00
[group_id] = 1
[active] = 0
[emailssend] = 0
[browser_id] = 1
[screen] = 11
)
)
)
v- Hide quoted text -
- Show quoted text -
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
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-~--~~~~--~~--~--~---
Re: simple session question - for Authentication
Hi, sorry..found the solution to allow pages without a controller -
stick it in the app_controller.. which only leaves me know with the
question..
SECONDLY: I am trying to do a on sessions, if I do pr($_SESSION); I
get all the sessions - see below..I want the user_id, I have tried
print_r($_SESSION['Config']['User']['id']) which works but when I put
in the
?php echo $html-link(My classified adds , array(controller =
items, action =
view, .$_SESSION['Config']['User']['id']).)); ?
it does not work, any ideas, anyone??? I have tried $session-
read('id'), which does not work..( in the view)
On 19 Sep, 16:45, gabriel [EMAIL PROTECTED] wrote:
Hi, Yes!! just figured it out as well
function beforeFilter(){
$this-Auth-allow('add', '');
}
How do you 'allow' page which is not in a controler??
~AND Any ideas on ...
SECONDLY: I am trying to do a on sessions, if I do pr($_SESSION); I
get all the sessions - see below..I want the user_id, I have tried
print_r($_SESSION['Config']['User']['id']) which works but when I put
in the
?php echo $html-link(My classified adds , array(controller =
items, action =
view, .$_SESSION['Config']['User']['id']).)); ?
it does not work, any ideas, anyone??? I have tried $session-
read('id'), which does not work..( in the view)
On 19 Sep, 15:39, avairet [EMAIL PROTECTED] wrote:
Hi,
Just an idea for the first issue: put $this-Auth-allow('add') in
your beforeFilter() function!
On 19 sep, 16:31, gabriel [EMAIL PROTECTED] wrote:
Hi, I have followed the Authentication in the Cookbook. I have a few
problems, maybe someone can help me. Firstly to 'allow' certain pages,
I place the $this-Auth-allow('add'); in the Users controller and
get and error, I have also tried to include it in the add and login
functions, but it does not seems to work, the error is
Parse error: syntax error, unexpected T_VARIABLE, expecting T_FUNCTION
in C:\xampp\htdocs\testsite\app\controllers\users_controller.php on
line 8
class UsersController extends AppController {
var $name = 'Users';
var $helpers = array('Html', 'Form', 'Session');
// var $components = array('Auth'); //declared in app_controller.php
$this-Auth-allow('add');
SECONDLY: I am trying to do a on sessions, if I do pr($_SESSION); I
get all the sessions - see below..I want the user_id, I have tried
print_r($_SESSION['Config']['User']['id']) which works but when I put
in the
?php echo $html-link(My classified adds , array(controller =
items, action =
view, .$_SESSION['Config']['User']['id']).)); ?
it does not work, any ideas, anyone??? I have tried $session-
read('id'), which does not work..( in the view)
Array
(
[User] = Array
(
[id] = 3
[username] = test
[name] = piet
[lname] = test
[email] = [EMAIL PROTECTED]
[tell] = 123
[cell] = 321
[hnum] = 2
[street] = car
[city_id] = 1
[county_id] = 2
[country_id] = 3
[pcode] = mnh
[admin] = 7
[maillist] = 0
[created] = -00-00 00:00:00
[modified] = -00-00 00:00:00
[ip] = 1
[last_visit] = 2011-11-01 00:00:00
[group_id] = 1
[active] = 0
[emailssend] = 0
[browser_id] = 1
[screen] = 11
)
)
Array
(
[Config] = Array
(
[userAgent] = a8c0ddfcbb06197967f6ae13f3fdd732
[time] = 1221835585
[rand] = 21704
[timeout] = 10
)
[Message] = Array
(
)
[Auth] = Array
(
[User] = Array
(
[id] = 3
[username] = test
[name] = piet
[lname] = test
[email] = [EMAIL PROTECTED]
[tell] = 123
[cell] = 321
[hnum] = 2
[street] = car
[city_id] = 1
[county_id] = 2
[country_id] = 3
[pcode] = mnh
[admin] = 7
[maillist] = 0
[created] = -00-00 00:00:00
[modified] = -00-00 00:00:00
[ip] = 1
[last_visit] = 2011-11-01 00:00:00
[group_id] = 1
[active] = 0
[emailssend] = 0
[browser_id] = 1
[screen] = 11
)
)
)
v- Hide quoted text -
- Show quoted
Re: simple session question - for Authentication
NOPE !!! sorry made a mistake, can't stick the $this-Auth-allow in
the app_controller...
On Fri, Sep 19, 2008 at 4:51 PM, gabriel [EMAIL PROTECTED] wrote:
Hi, sorry..found the solution to allow pages without a controller -
stick it in the app_controller.. which only leaves me know with the
question..
SECONDLY: I am trying to do a on sessions, if I do pr($_SESSION); I
get all the sessions - see below..I want the user_id, I have tried
print_r($_SESSION['Config']['User']['id']) which works but when I put
in the
?php echo $html-link(My classified adds , array(controller =
items, action =
view, .$_SESSION['Config']['User']['id']).)); ?
it does not work, any ideas, anyone??? I have tried $session-
read('id'), which does not work..( in the view)
On 19 Sep, 16:45, gabriel [EMAIL PROTECTED] wrote:
Hi, Yes!! just figured it out as well
function beforeFilter(){
$this-Auth-allow('add', '');
}
How do you 'allow' page which is not in a controler??
~AND Any ideas on ...
SECONDLY: I am trying to do a on sessions, if I do pr($_SESSION); I
get all the sessions - see below..I want the user_id, I have tried
print_r($_SESSION['Config']['User']['id']) which works but when I put
in the
?php echo $html-link(My classified adds , array(controller =
items, action =
view, .$_SESSION['Config']['User']['id']).)); ?
it does not work, any ideas, anyone??? I have tried $session-
read('id'), which does not work..( in the view)
On 19 Sep, 15:39, avairet [EMAIL PROTECTED] wrote:
Hi,
Just an idea for the first issue: put $this-Auth-allow('add') in
your beforeFilter() function!
On 19 sep, 16:31, gabriel [EMAIL PROTECTED] wrote:
Hi, I have followed the Authentication in the Cookbook. I have a few
problems, maybe someone can help me. Firstly to 'allow' certain pages,
I place the $this-Auth-allow('add'); in the Users controller and
get and error, I have also tried to include it in the add and login
functions, but it does not seems to work, the error is
Parse error: syntax error, unexpected T_VARIABLE, expecting T_FUNCTION
in C:\xampp\htdocs\testsite\app\controllers\users_controller.php on
line 8
class UsersController extends AppController {
var $name = 'Users';
var $helpers = array('Html', 'Form', 'Session');
// var $components = array('Auth'); //declared in app_controller.php
$this-Auth-allow('add');
SECONDLY: I am trying to do a on sessions, if I do pr($_SESSION); I
get all the sessions - see below..I want the user_id, I have tried
print_r($_SESSION['Config']['User']['id']) which works but when I put
in the
?php echo $html-link(My classified adds , array(controller =
items, action =
view, .$_SESSION['Config']['User']['id']).)); ?
it does not work, any ideas, anyone??? I have tried $session-
read('id'), which does not work..( in the view)
Array
(
[User] = Array
(
[id] = 3
[username] = test
[name] = piet
[lname] = test
[email] = [EMAIL PROTECTED]
[tell] = 123
[cell] = 321
[hnum] = 2
[street] = car
[city_id] = 1
[county_id] = 2
[country_id] = 3
[pcode] = mnh
[admin] = 7
[maillist] = 0
[created] = -00-00 00:00:00
[modified] = -00-00 00:00:00
[ip] = 1
[last_visit] = 2011-11-01 00:00:00
[group_id] = 1
[active] = 0
[emailssend] = 0
[browser_id] = 1
[screen] = 11
)
)
Array
(
[Config] = Array
(
[userAgent] = a8c0ddfcbb06197967f6ae13f3fdd732
[time] = 1221835585
[rand] = 21704
[timeout] = 10
)
[Message] = Array
(
)
[Auth] = Array
(
[User] = Array
(
[id] = 3
[username] = test
[name] = piet
[lname] = test
[email] = [EMAIL PROTECTED]
[tell] = 123
[cell] = 321
[hnum] = 2
[street] = car
[city_id] = 1
[county_id] = 2
[country_id] = 3
[pcode] = mnh
[admin] = 7
[maillist] = 0
[created] = -00-00 00:00:00
[modified] = -00-00 00:00:00
[ip] = 1
[last_visit] = 2011-11-01 00:00:00
[group_id] = 1
[active] = 0
Re: Auth component not working for me
$this-Auth-allow('display','index','register');
you don't have a 'display' funtion in your controller..don't know much
maybe this is it.
On 15 Sep, 06:51, Golam Kibria [EMAIL PROTECTED] wrote:
hello i have triedauthcomponent and is not working for me.
here is my code
?php
class UsersController extends AppController {
var $name = 'Users';
var $helpers = array('Html', 'Form', 'Time', 'Javascript');
var $components = array('Auth');
var $ext = '.php';
function beforeFilter(){
//Security::setHash('md5');
$this-Auth-fields = array('username'='username',
'password'='password');
$this-Auth-loginAction = array('controller' = 'users',
'action'
= 'login');
$this-Auth-loginRedirect = array('controller' = 'users',
'action' = 'index');
$this-Auth-allow('display','index','register');
$this-Auth-authorize = 'controller';
$this-Auth-userScope = array('User.status'=1);
}
function isAuthorized() {
return true;
}
//var $uses = array('Group');
//var $layout='tadmin';
function index() {
$this-User-recursive = 0;
$this-set('users', $this-paginate());
//$this-Group-
//print_r($this-paginate());
}
function view($id = null) {
if (!$id) {
$this-Session-setFlash(__('Invalid User.', true));
$this-redirect(array('action'='index'));
}
$this-set('user', $this-User-read(null, $id));
}
function add() {
if (!empty($this-data)) {
$this-data['User']['password']=$this-Auth-password($this-data['User']['password']);
$this-User-create();
if ($this-User-save($this-data)) {
$this-Session-setFlash(__('The User has
been saved', true));
$this-redirect(array('action'='index'));
} else {
$this-Session-setFlash(__('The User could
not be saved. Please,
try again.', true));
}
}
$groups=$this-User-Group-find('list');
//$groups=$this-User-Group-generateList(null, 'name ASC',
null,
'{n}.Group.id', '{n}.Group.name');
$this-set('groups',$groups);
//print_r($groups);
}
function edit($id = null) {
if (!$id empty($this-data)) {
$this-Session-setFlash(__('Invalid User', true));
$this-redirect(array('action'='index'));
}
if (!empty($this-data)) {
if ($this-User-save($this-data)) {
$this-Session-setFlash(__('The User has
been saved', true));
$this-redirect(array('action'='index'));
} else {
$this-Session-setFlash(__('The User could
not be saved. Please,
try again.', true));
}
}
if (empty($this-data)) {
$this-data = $this-User-read(null, $id);
}
$groups=$this-User-Group-find('list');
$this-set('groups',$groups);
}
function delete($id = null) {
if (!$id) {
$this-Session-setFlash(__('Invalid id for User',
true));
$this-redirect(array('action'='index'));
}
if ($this-User-del($id)) {
$this-Session-setFlash(__('User deleted', true));
$this-redirect(array('action'='index'));
}
}
function register(){
if(!empty($this-data)){
$this-data['User']['status']=1;
$this-data['User']['group_id']=3;
$this-data['User']['password']=
$this-Auth-password($this-data['User']['password']);
$this-User-create();
if($this-User-save($this-data)){
$this-Session-setFlash(__('User
Registration Complete',true));
$this-redirect(array('action'='index'));
}else{
$this-Session-setFlash(__('Problem found.
Please, try again.', true));
}
}
}
function login(){
}
function logout(){
$this-redirect($this-Auth-logout());
}
}
?
i
Warning 512 - cache problem
Hi!, I hava a serious problem with recent 1.2 RC-2 - I use svn to control my projects - at som,e point I decided to try out a new cake - when I uploaded my app (from a windows machine) and checked it out on a linux (debian+apache) machine it showed me an error saying that fiel engine is not configured properly Warning 512 - I searched the forum and found out that it is beacuse of cake's problem with urls - I commented out one line in core.php and it dissapeared but since then none of the urls works - it displays this url can not be found on the server - I wqould like to use cake 1.2 as I consider it being more advanced than 1.1 but it is now a pain for me? Why is that happening? Anyone knows? Regards, Gabriel --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
trying to make othAuth login process work
Hi, I have carefully followed the othAuth doc
http://bakery.cakephp.org/articles/view/othauth-0-5-documentation,
trying to get it to work, bur when I go to
http://127.0.0.1/testsite/users/login,
I get the following errors..
Username
Warning (512): Method HtmlHelper::input does not exist [CORE\cake\libs
\view\helper.php, line
(512): Method HtmlHelper::tagErrorMsg does
Warning (512): Method HtmlHelper::checkbox does not exist [CORE\cake
\libs\view\helper.php, line 148]
Any ideas..
here is the login.ctp view..
h1Log In:/h1
form action=?php echo $html-url('/users/login'); ?
method=post
div class=required
label for=user_usernameUsername/label
?php echo $html-input('User/username', array('id' =
'user_username', 'size' = '50')) ?
?php echo $html-tagErrorMsg('User/username', 'Please enter your
username') ?
/div
div class=required
label for=user_passwordPassword/label
?php echo $html-input('User/passwd', array('id' =
'user_passwd', 'size' = '32', 'type'=password)) ?
?php echo $html-tagErrorMsg('User/passwd', 'Please enter your
password!') ?
/div
?php echo $html-checkbox(User/cookie);?
div class=submitinput type=submit value=Login //div
/form
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
CakePHP group.
To post to this group, send email to cake-php@googlegroups.com
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at
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-~--~~~~--~~--~--~---
getting cake bake to work on vista, xampp..
hi, I would like to know if anyone can help me.. I am trying to get cake bake to work on vista, xampp, I have also installed cygwin.. I have included in my advanced-Enviroment Variables-path (edit) C:\xamp\php\php4\phpcli.exe;C:\xamp\htdocs\testsite\cake\console \cake.bat yet when I type in ' cake bake ' in the command prompt - 'cake' is not recognized as an internal or external command operable program or batch file or cygwin prompt it says bash: cake: command not found Thanks for your help in advance --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: getting cake bake to work on vista, xampp..
Thanks a mil, got it working !! On Wed, Sep 17, 2008 at 3:16 PM, Donkeybob [EMAIL PROTECTED] wrote: I got this to work on my vista machine but I didn't use the direct file name in the path, just try C:\xampp\php; C:\xamp\htdocs\testsite\cake\console It works like a charm for me On Sep 17, 9:25 am, gabriel [EMAIL PROTECTED] wrote: hi, I would like to know if anyone can help me.. I am trying to get cake bake to work on vista, xampp, I have also installed cygwin.. I have included in my advanced-Enviroment Variables-path (edit) C:\xamp\php\php4\phpcli.exe;C:\xamp\htdocs\testsite\cake\console \cake.bat yet when I type in ' cake bake ' in the command prompt - 'cake' is not recognized as an internal or external command operable program or batch file or cygwin prompt it says bash: cake: command not found Thanks for your help in advance --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
making a view without a controller or model
Hi, I am new, as you might guess.., I have created an (HTML) view in the pages folder in views, called account.ctp. It doesn't have a controller or model. But is looking for a controller. How do I get around this? Thanks and blessings to the person who helps me. --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Re: making a view without a controller or model
~Thanks !!
On 12 Sep, 15:28, grigri [EMAIL PROTECTED] wrote:
The url you want is : /pages/account - that will get it to display
If you want to access it via /account then add this line to app/config/
routes.php:
Router::connect('/account', array('controller' = 'pages', 'action' =
'view', 'account'));
hth
grigri
On Sep 12, 2:59 pm, gabriel [EMAIL PROTECTED] wrote:
Hi, I am new, as you might guess.., I have created an (HTML) view in
the pages folder in views, called account.ctp. It doesn't have a
controller or model. But is looking for a controller. How do I get
around this?
Thanks and blessings to the person who helps me.- Hide quoted text -
- Show quoted text -
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Making a simple link to another page
I would like to make a simple link to a view which does not have a controller and model, can anyone help me. REgards --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
Help with installation cakephp on xamp package
Hi, all. I have been reading a book by APRESS, called 'Beginning CakePHP from novice to Professional' in it, it says that if you have installed cake, and get the starting up screen without the fonts and colours on the page working then, there is an error. Cake will work but the scaffolding and other things might get errors.. I have tried EVERTHING, I have uncommented the 'LoadModule rewrite_module modules/mod_rewrite.so', I have shared (in Vista) the app folder, I have included the following Directory /caketest Options Indexes FollowSymLinks AllowOverride ALL /Directory in the httpd.conf folder... And restarted the server, and it does not seems to fix the problem, I have been going on with CAke and all seems fine, but sometimes I get errors, then I doubt myself, I don't know if it is my configuration or my coding...I would just like to know that everything works the way it is suppose to.. hope is all make sense, and someone can help.. Thanks --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
missing view
Hi, I am new to cake and are really frustrated with the basics. I have created a default.thml in layouts, with the code ?PHP echo $content_for_layout; ?, then I created a test.thtml in pages, I point the server to it and get a missing view error - anyone any ideas? --~--~-~--~~~---~--~~ You received this message because you are subscribed to the Google Groups CakePHP group. To post to this group, send email to cake-php@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/cake-php?hl=en -~--~~~~--~~--~--~---
