Re: [Vo]:Corrections to "heat after death" calculations
Horace Heffner wrote: My first reaction is: did it not occur to anyone in 18 hours to reduce the > flow by a factor of 10 so as to get more reliable numbers? I would not recommend that: 1. The machine went bonkers when they started the run, producing very high heat. I think it is safer to leave the cooling water flow high. 2. A 5°C temperature difference is huge and easily measured. 3. You should not change experimental parameters midway through the run. Other reports refer to the reactor chamber as being about 50 ml. Photos seem > to confirm this. This must have been a special device for this test. > This was the larger device shown in the photos and used in the first set of tests. > Jed uses 3000 L/h, or 0.83 liter/sec. Not that a 20% difference is > significant. > They told me it was 3000 L/h. with that kind of flowmeter I trust the cumulative total more than the instantaneous reading. A more recent report says it was just under 1 L per second. > Since we don't know the geometry of the device, we don't know where and how > the output thermometer was located. Yes we do. It is shown in some photos. > If it is in a metal well, it is possible that it was heated slightly via > the high thermal conductivity of copper between the resistance heater and > the thermometer. > With a 5°C temperature difference this would be insignificant. During the first phase when it went bonkers this might have been a factor, causing the output heat to seem larger than it was. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
On Fri, Sep 2, 2011 at 6:48 AM, Horace Heffner wrote: > My first reaction is: did it not occur to anyone in 18 hours to reduce the > flow by a factor of 10 so as to get more reliable numbers? The restriction > would not have to be precise. Everything depends on the flow meter anyway. > It would just be a matter of turning the faucet down, or inserting a flow > restrictor. This does not negate the ou results however. Some flow meters give erroneous results if the pipe is not filled. T
Re: [Vo]:Corrections to "heat after death" calculations
On Sep 1, 2011, at 10:24 AM, Jed Rothwell wrote: Horace Heffner wrote: Here is what all the opinions in the world cannot change: liquid flow test proves that the machine is producing 12 to 16 kW of excess heat. Period. Again, where is the data for this test. http://lenr-canr.org/News.htm#Rossi18HourTest (with links to NyTeknik) And do not tell me this data is incomplete. It is all you need to know, contrary to what Lomax asserts. Well, that apparently is all you need to know. I need to know more. [snip] My first reaction is: did it not occur to anyone in 18 hours to reduce the flow by a factor of 10 so as to get more reliable numbers? The restriction would not have to be precise. Everything depends on the flow meter anyway. It would just be a matter of turning the faucet down, or inserting a flow restrictor. This does not negate the ou results however. This quote strikes me a strange: "He [Levi] confirmed that the reactor chamber, supposedly containing nickel powder, the secret catalysts and hydrogen gas, had a volume of around one liter." http://lenr-canr.org/acrobat/LeviGreportonhe.pdf Other reports refer to the reactor chamber as being about 50 ml. Photos seem to confirm this. This must have been a special device for this test. It was interesting, with regard to "heat after death" computations, that "30 kg is due to lead". Lewan states (quotes without quotes?): "Initially, the temperature of the inflowing water was seven degrees Celsius and for a while the outlet temperature was 40 degrees Celsius. A flow rate of about one liter per second, equates to a peak power of 130 kilowatts. The power output was later stabilized at 15 to 20 kilowatts." Jed uses 3000 L/ h, or 0.83 liter/sec. Not that a 20% difference is significant. The above comments are not germane, but just seem noteworthy. Since we don't know the geometry of the device, we don't know where and how the output thermometer was located. If it is in a metal well, it is possible that it was heated slightly via the high thermal conductivity of copper between the resistance heater and the thermometer. It is an obvious question with regard to the heat excursion as to whether it might have been due to a momentary hose kink, or a momentary drop in city water pressure. We don't know how often the flow meter was read. If the "surge" lasted one tenth the time interval between flow meter readings then the apparent flow reduction would be 10% while the thermometer was registering a 40°C jump, leaving the impression there was a huge power output when there was not. It seems to me surprising there was no follow up public test using this protocol. The test was run in February. You would think there would have been some attempt to capitalize on these improved results. It is of interest that a 5°C rise has no commercial use, while a 50°C or even 20°C has much practical use - preheating water fed to a building heat pump. It is notable that no control efforts were mentioned. Perhaps they were done, but there is no mention. If I had a test like that I would have been all over it after a few hours run time looking for ways I might be fooling myself. I would have tried a thermal pulse to check calorimetry. I would have measured the flow by independent means, e.g. weighing a timed bucket. I would have varied the flow rate, and inserted a separate thermometer in the hose output. An 18 hour run provides a lot of time for thinking about what is happening and taking steps to confirm the observations. There was talk of analyzing the fuel. Nothing seems to have come of that. It seems strange the device operates continuously at such a low temperature. This is inconsistent with the concept of quenching the reaction by introducing cold water, or by controlling the reaction using auxiliary heat. This test, as reported, is indeed very interesting, but not totally convincing as presented. It would be a failure to exercise due diligence to invest large sums of money, without independent tests, in a project where the key data in the public demonstrations, the calorimetry, was so flawed. They are not flawed. This is a figment of your imagination, just as the objections to Fleischmann's experiment were. Repeatedly asserting that something is flawed does not actually make it flawed. If the calorimetry had been flawed the second test with cooling water would have revealed this. It is fundamental to the scientific method that if you suspect there may be a problem you do a second experiment with different instrument types of different procedures to either confirm or disprove the results. That is the only way to settle the issue. Arguing, hypothesizing and debating get you nowhere. You do a test. Levi et al. did a test. They proved their point. There is nothing more to be done, nothing left to argue about, and
Re: [Vo]:Corrections to "heat after death" calculations
On Thu, Sep 1, 2011 at 6:38 PM, Nick Palmer wrote: > Obviously, > Catania does not realise this but, like so many in the past, shoots from the > hip to fill up the forum with dubious logic, false assertions and acres of > attacking prose. These types go away in the end. I love the poetry of assonance, alliteration and truth in the same post. T
Re: [Vo]:Corrections to "heat after death" calculations
This Catania bloke didn't take the hint. "Jed appears to be pursued by demons. What else would induce a Japlish translator to take up residence in a cold fusion forum." Apart from the actual researchers, Jed is, and always has been since 1989, one of the most significant figures in the "cold fusion" field. Obviously, Catania does not realise this but, like so many in the past, shoots from the hip to fill up the forum with dubious logic, false assertions and acres of attacking prose. These types go away in the end. Nick Palmer On the side of the Planet - and the people - because they're worth it Blogspot - Sustainability and stuff according to Nick Palmer http://nickpalmer.blogspot.com
Re: [Vo]:Corrections to "heat after death" calculations
Horace Heffner wrote: Here is what all the opinions in the world cannot change: liquid flow test proves that the machine is producing 12 to 16 kW of excess heat. Period. Again, where is the data for this test. http://lenr-canr.org/News.htm#Rossi18HourTest (with links to NyTeknik) And do not tell me this data is incomplete. It is all you need to know, contrary to what Lomax asserts. Fleischmann did an inventory of the lithium remaining in the cell and showed this is not the case. A terabyte of blather on the Internet cannot refute this simple test. This is irrelevant. Fleischmann did boil-off tests. There was not more mass of water flowing over the side of his beaker and onto the floor (or down a drain) than produced as steam. It is similar insofar as people continued to raise an objection long after it was decisively proved invalid, by experiment. That's ridiculous. Once the experiment proves you are wrong, you should admit that, shut up, and move on. When people ignore experimental results no progress will be made and no question will be settled. The public tests were not good enough to prove that *any* nuclear energy was created. This is your opinion. Many experts disagree, as do I. Lying is not an important issue with the public tests. The issue is whether the calorimetry showed anything at all. People who know a great deal about calorimetry agree that it did. The fact that the second test with a different calorimetric technique gave the same result proves that it did. This cannot be a coincidence. It would be a failure to exercise due diligence to invest large sums of money, without independent tests, in a project where the key data in the public demonstrations, the calorimetry, was so flawed. They are not flawed. This is a figment of your imagination, just as the objections to Fleischmann's experiment were. Repeatedly asserting that something is flawed does not actually make it flawed. If the calorimetry had been flawed the second test with cooling water would have revealed this. It is fundamental to the scientific method that if you suspect there may be a problem you do a second experiment with different instrument types of different procedures to either confirm or disprove the results. That is the only way to settle the issue. Arguing, hypothesizing and debating get you nowhere. You do a test. Levi et al. did a test. They proved their point. There is nothing more to be done, nothing left to argue about, and nothing more to be said. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
You should measure the increase in your sparging more accurately for instance in a graduated cylinder. - Original Message - From: "Jouni Valkonen" To: Sent: Thursday, September 01, 2011 1:07 PM Subject: Re: [Vo]:Corrections to "heat after death" calculations 2011/9/1 Horace Heffner : Lying is not an important issue with the public tests. What if there was a hidden hydrogen bottle? 200 grams of hydrogen is enough. The issue is whether the calorimetry showed anything at all. Indeed, it showed. I will return this issue tomorrow. The issue is a relative humidity probe does not measure steam quality, or sense whether large amounts of water are overflowing. This silly measurement has nothing to do with Rossi, but all to do with Galantini. The issue is the use of a set-up that is perfect for self delusion and erroneous results, and proves nothing. This is untrue. It is almost trivial to measure enthalpy from steam by sparging. See my recent experiment in other threat. Therefore experimental setup was correct. Such major flaws are not an indication of an appropriate level of science being applied. You should tell this to Levi, Passerini, Bianchini, Galantini, Kullander, Essén, Lewan and various other persons who all failed with calorimetry. Frankly I am stunned when I realized how simple science calorimetry is and how poorly it was conducted during the demonstrations AND in various discussion forums. Lewan had extensive public discussion what to measure before he went to Bologna. He even measured electromagnetic radiation for heat transfer but no one suggested for him to do simple steam sparging calorimetry. This is what surprises me the most. And also Rossi was only passive observer when scientist made all the measurements what they thought to be necessary. Therefore no-one cannot state any objections for Rossi if the level of science was poor. –Jouni
Re: [Vo]:Corrections to "heat after death" calculations
2011/9/1 Horace Heffner : > Lying is not an important issue with the public tests. What if there was a hidden hydrogen bottle? 200 grams of hydrogen is enough. > The issue is whether > the calorimetry showed anything at all. Indeed, it showed. I will return this issue tomorrow. > The issue is a relative humidity > probe does not measure steam quality, or sense whether large amounts of > water are overflowing. This silly measurement has nothing to do with Rossi, but all to do with Galantini. > The issue is the use of a set-up that is perfect for > self delusion and erroneous results, and proves nothing. > This is untrue. It is almost trivial to measure enthalpy from steam by sparging. See my recent experiment in other threat. Therefore experimental setup was correct. > Such major flaws are > not an indication of an appropriate level of science being > applied. > You should tell this to Levi, Passerini, Bianchini, Galantini, Kullander, Essén, Lewan and various other persons who all failed with calorimetry. Frankly I am stunned when I realized how simple science calorimetry is and how poorly it was conducted during the demonstrations AND in various discussion forums. Lewan had extensive public discussion what to measure before he went to Bologna. He even measured electromagnetic radiation for heat transfer but no one suggested for him to do simple steam sparging calorimetry. This is what surprises me the most. And also Rossi was only passive observer when scientist made all the measurements what they thought to be necessary. Therefore no-one cannot state any objections for Rossi if the level of science was poor. –Jouni
Re: [Vo]:Corrections to "heat after death" calculations
On Sep 1, 2011, at 6:17 AM, Jed Rothwell wrote: Horace Heffner wrote: All the opinions in the world can not change the fact that water was probably coming out of the device in large mass proportions, whither or not the device produced some nuclear heat. Here is what all the opinions in the world cannot change: liquid flow test proves that the machine is producing 12 to 16 kW of excess heat. Period. Again, where is the data for this test. Years ago when Fleischmann published the boil off experiments there was a great deal of debate similar to this. Many people claim that droplets of on world water might be leaving the cell, which would reduce the total enthalpy. Fleischmann did an inventory of the lithium remaining in the cell and showed this is not the case. A terabyte of blather on the Internet cannot refute this simple test. This is irrelevant. Fleischmann did boil-off tests. There was not more mass of water flowing over the side of his beaker and onto the floor (or down a drain) than produced as steam. Blather, Speculations and opinion do not count. The only thing that counts is actual test results and these results prove that Levi and Rossi are correct. Where is the evidence for this? No one disputes that the tests could be better but given the input and output ratios and the high level of heat these results are good enough to prove the point. The public tests were not good enough to prove that *any* nuclear energy was created. As I stated previously these tests would not be good enough for an investor to put millions of dollars into the device. More rigorous tests are needed there because it is possible that Levi et al. are lying. Lying is not an important issue with the public tests. The issue is whether the calorimetry showed anything at all. The issue is a relative humidity probe does not measure steam quality, or sense whether large amounts of water are overflowing. The issue is the use of a set-up that is perfect for self delusion and erroneous results, and proves nothing. There would be no point to betting large sums of money that they are honest when the question can easily be resolved with independent tests. - Jed It would be a failure to exercise due diligence to invest large sums of money, without independent tests, in a project where the key data in the public demonstrations, the calorimetry, was so flawed. Such major flaws are not an indication of an appropriate level of science being applied. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 31, 2011, at 10:33 PM, Jouni Valkonen wrote: 2011/9/1 Horace Heffner : If you want to see wet steam as I have described it, as generated by the peroclator effect Your description is wrong, because percolator effect does not produce wet steam, but hot water and little dry steam (steam quality ca. 98%). What you are here saying that coffee maker produces ultra wet steam instead of hot water, what is as a concept silly. Using such a silly concepts like "wet steam" in context where they do not belong gives quite clear message that you are not familiar with the field you are trying to analyze. It is not good sign that you give own definitions for the physical concepts. (I know this, because I have done this also some times) What existing technical name would you provide for the concept that water is being blown out of the device on a continual basis as long as the power is applied and input flow is constant. I used an analogous concept to name the effect. This I think is effective, certainly for writing purposes. It is a lot better than BWODOCBWPAIFC. It is not a good sign that you are setting up a straw man argument that the steam being "dry" when, massive amounts of water are blown out with it, somehow validates the "calorimetry" performed. When people resort to straw man arguments it means either they can not think clearly or they know they are wrong and are seeking a diversion. But instead of calling percolator effect, you should calculate what portion of inlet water is evaporated. It is quite clear that the whole E-Cat is quite quickly emptied from water due to percolator effect. I simply do not know what to say to such a statement when I provided such clear numbers that show this percolator effect is a continuous process when the device operates in steady state, equilibrium state. Do you have objections to the numbers I have produced? It is as if you don't understand anything at all about what I have posted or the numbers provided. The E-Cat does not dry out in the various scenarios shown to date. In steady state operation the percolator effect is continuous. Water is continually supplied, some boiled and some *continually* blown out of the device by percolator effect. This *continual* process invalidates any steady state calorimetry with the assumptions made by Rossi that the steam was "dry", that all water is converted to steam. This is obviously an erroneous *assumption*, not measurement, that invalidates the public tests even if a large COP of nuclear heat is actually being produced. The measurements required for even an amateur level of calorimetry were not taken. The products that went into the hose went down the drain. This leaves us with guesswork at best. That it is untrue. In December demonstration there was measured 100 kPa excess steam pressure. Please provide the URLs for this data and any analysis provided in the test reports. This is more than enough to estimate quite accurately the total enthalpy. If your data is flawed in many ways, then you need to be creative and try to reconstruct as much as you can. As I showed quite clearly, that there are several methods to try to calculate the total enthalpy. None of them is alone accurate, but together they may be significant. And ... they may not be significant. This is why it is useless to relay on expert knowledge, because we are in the situation that no expert knowledge is available, because situation is unique. In unique situations, we must be creative. This is nonsensical. It is the responsibility of the demonstrator to provide a meaningful demonstration. It is not incumbent upon observers to be creative to find meaning in a demonstration. But Horace, why do you constantly ignore the fact that steam generation in closed container is always generating excess pressure? And in this case, excess pressure was 100 kPa. Here are the three creative methods for calculating total enthalpy. And please do not just ignore them: –There was 100 kPa overpressure, and from Mats Lewan E-Cat we get one reference point (there was 32 kPa overpressure). Therfore 6-9kW is likely explanation for 100 kPa. Steam engineers could also calculate directly the amount of steam needed for generating 100 kPa excess pressure. Pressure alone means little without flow quantities. If your steam flow numbers are off, due to most being water flow, then pressure alone is meaningless. For example, if you insulate a pressure cooker it does not take much heat to maintain 100 kPa, about 1 atmosphere pressure. Also, I assume you mean here gauge pressure and not absolute pressure. –During the two approximately 6min power surge at 17:30 and 17:50 temperature rose approximately 1.5 times more than during the first 30 minutes when only 1.2 kW electric heater was active. Therefore total heating power when E-Cat was producing excess heat, was approximatel
Re: [Vo]:Corrections to "heat after death" calculations
Horace Heffner wrote: All the opinions in the world can not change the fact that water was probably coming out of the device in large mass proportions, whither or not the device produced some nuclear heat. Here is what all the opinions in the world cannot change: liquid flow test proves that the machine is producing 12 to 16 kW of excess heat. Period. Years ago when Fleischmann published the boil off experiments there was a great deal of debate similar to this. Many people claim that droplets of on world water might be leaving the cell, which would reduce the total enthalpy. Fleischmann did an inventory of the lithium remaining in the cell and showed this is not the case. A terabyte of blather on the Internet cannot refute this simple test. Blather, Speculations and opinion do not count. The only thing that counts is actual test results and these results prove that Levi and Rossi are correct. No one disputes that the tests could be better but given the input and output ratios and the high level of heat these results are good enough to prove the point. As I stated previously these tests would not be good enough for an investor to put millions of dollars into the device. More rigorous tests are needed there because it is possible that Levi et al. are lying. There would be no point to betting large sums of money that they are honest when the question can easily be resolved with independent tests. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
2011/9/1 Jouni Valkonen : > But Horace, why do you constantly ignore the fact that steam > generation in closed container is always generating excess pressure? > And in this case, excess pressure was 100 kPa. > oops, here was a mistake. Excess pressure was of course 10 kPa and in April demonstrations it was 3.2 kPa. –Jouni
Re: [Vo]:Corrections to "heat after death" calculations
2011/9/1 Horace Heffner : > If you want to see wet steam as I have described it, as generated by the > peroclator effect Your description is wrong, because percolator effect does not produce wet steam, but hot water and little dry steam (steam quality ca. 98%). What you are here saying that coffee maker produces ultra wet steam instead of hot water, what is as a concept silly. Using such a silly concepts like "wet steam" in context where they do not belong gives quite clear message that you are not familiar with the field you are trying to analyze. It is not good sign that you give own definitions for the physical concepts. (I know this, because I have done this also some times) But instead of calling percolator effect, you should calculate what portion of inlet water is evaporated. It is quite clear that the whole E-Cat is quite quickly emptied from water due to percolator effect. > The measurements required for even an amateur level of calorimetry were not > taken. The products that went into the hose went down the drain. This > leaves us with guesswork at best. > That it is untrue. In December demonstration there was measured 100 kPa excess steam pressure. This is more than enough to estimate quite accurately the total enthalpy. If your data is flawed in many ways, then you need to be creative and try to reconstruct as much as you can. As I showed quite clearly, that there are several methods to try to calculate the total enthalpy. None of them is alone accurate, but together they may be significant. This is why it is useless to relay on expert knowledge, because we are in the situation that no expert knowledge is available, because situation is unique. In unique situations, we must be creative. But Horace, why do you constantly ignore the fact that steam generation in closed container is always generating excess pressure? And in this case, excess pressure was 100 kPa. Here are the three creative methods for calculating total enthalpy. And please do not just ignore them: –There was 100 kPa overpressure, and from Mats Lewan E-Cat we get one reference point (there was 32 kPa overpressure). Therfore 6-9kW is likely explanation for 100 kPa. Steam engineers could also calculate directly the amount of steam needed for generating 100 kPa excess pressure. –During the two approximately 6min power surge at 17:30 and 17:50 temperature rose approximately 1.5 times more than during the first 30 minutes when only 1.2 kW electric heater was active. Therefore total heating power when E-Cat was producing excess heat, was approximately 9kW. (This is most reliable estimation, because it calculates the enthalpy in sub-boiling temperatures. and data all necessary data is measured.) http://2.bp.blogspot.com/_852Sj2_TNC4/TTwDi8cYrtI/E1E/TT603dSfpzs/s1600/report3.jpg –And for third method, the enthalpy can be calculated using an estimation of total thermal mass of E-Cat. This is where I got that 6 kW for minimum possible power output.
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 31, 2011, at 6:03 PM, Jouni Valkonen wrote: Horace wrote: «What you say might be true if the public tests were reasonably well done. They weren't. There is thus no reason to believe closed door results were done any more competently unless sufficient information is published to make that determination.» This is not the case. There was nothing wrong with the experimental setup, because they were done in open manner that Rossi invited independ scientists to do the measurements, but non of them thought that calorimetry is necessary. Even Mats Lewan failed to do this although he had all the resources to do proper calorimetri. Also Lewan had careful preparatio, unlike Kullander and Essén, who did not know what to expect. Actually I asked less than a month ago and Lewan still thinks that calorimery was not necessary and his method was sound. All the opinions in the world can not change the fact that water was probably coming out of the device in large mass proportions, whither or not the device produced some nuclear heat. If a large proportion of the water, by mass, came out as liquid then the calorimetry was ineffective. That Jed's "expert" was not expert at all that he would have expert knowledge from E-Cat. He just stated general and obvious fact that all water boilers on Earth produce dry steam, because there is now such physical concept as "wet steam" in steam physics that is anyway relevant with E-Cat. Expert was just asked does he think that steam was very wet and he replied that it was not wet steam because wet steam is not stable physical state of water in close to normal pressures. (Frankly I still wonder who was the first crack potter who introduced the concept Wet Steam, because it is physically inaccurate concept. At least if someone could provide a reference that descripes experimental setup that produces wet steam, because no one here at vortex has ever seen wet steam, but they just assume it.) If you want to see wet steam as I have described it, as generated by the peroclator effect, just take the hose off the demo device when it is in equilibrium in the operating range showed here: http://www.mtaonline.net/~hheffner/KrivitFilm.pdf which is around 748 W in, and water flow of 1.94 gm/s at 2°C. Keep your body protected lest you get scalded! Oh I forgot, you are not actually Rossi ... or are you? 8^) If there is no nuclear heat produced then the steam flow should be 83 ml/s, the water flow out the exit 1.89 ml/s. This output is steam which is about 2% "wet" by volume. It will likely *not* be wet in the form of suspended water droplets to which Palm referred, however. Almost no energy is going into providing 83 ml/s steam, only 120.6 W out of 748 W, while 627.4 W goes into simply heating the flowing water to boiling. If nuclear heat is present then the water out will be less but the ejection velocity will be much higher. Point is that you are wrong along with Krivit that we would not have any means to do calorimetry retrospectively. The measurements required for even an amateur level of calorimetry were not taken. The products that went into the hose went down the drain. This leaves us with guesswork at best. Please review my last post. Also you should review the report for December test and ignore what Levi did calculate and make your own proper calculations. If you cannot come up with method of calculating enthalpy in creative way, then it is your problem. But you are in the situation that no expert knowledge does help you, but you need to come up something creative. Although, being creative is not that easy. In summary, Rossi is completely innocent for lack of calorimetry. He did not have any influence on enthalpy measurements, because measuring enthalpy was task assigned for independent scientists such as Levi and Lewan. Who is determined to be at fault is irrelevant to the extent it can not change the fact the Rossi demonstrations proved nothing because the calorimetry was so flawed. Calorimetry on the what came out of the output port was not done, nor was that output even observed visually. My calculations show that water came out even at power levels where large amount of nuclear power might have been generated. Rossi's assertion that the steam was "dry" is thus simply wishful thinking, without any physical evidence. —Jouni Ps. I agree, that 18 hour test gave probably too high power output. It is probably off the mark by factor of two. There is simple physics that 130kW output would have lead into core melt down, because stailess steal is not fast enough heat conductor. I agree with Jed: On Aug 25, 2011, at 9:14 AM, Jed Rothwell wrote: Brief public demos have been repeated 4 times in 8 months, I think. That is a small number. Anyone would invest in this based on those demos would be insane, in my opini
Re: [Vo]:Corrections to "heat after death" calculations
Horace wrote: «What you say might be true if the public tests were reasonably well done. They weren't. There is thus no reason to believe closed door results were done any more competently unless sufficient information is published to make that determination.» This is not the case. There was nothing wrong with the experimental setup, because they were done in open manner that Rossi invited independ scientists to do the measurements, but non of them thought that calorimetry is necessary. Even Mats Lewan failed to do this although he had all the resources to do proper calorimetri. Also Lewan had careful preparatio, unlike Kullander and Essén, who did not know what to expect. Actually I asked less than a month ago and Lewan still thinks that calorimery was not necessary and his method was sound. That Jed's "expert" was not expert at all that he would have expert knowledge from E-Cat. He just stated general and obvious fact that all water boilers on Earth produce dry steam, because there is now such physical concept as "wet steam" in steam physics that is anyway relevant with E-Cat. Expert was just asked does he think that steam was very wet and he replied that it was not wet steam because wet steam is not stable physical state of water in close to normal pressures. (Frankly I still wonder who was the first crack potter who introduced the concept Wet Steam, because it is physically inaccurate concept. At least if someone could provide a reference that descripes experimental setup that produces wet steam, because no one here at vortex has ever seen wet steam, but they just assume it.) Point is that you are wrong along with Krivit that we would not have any means to do calorimetry retrospectively. Please review my last post. Also you should review the report for December test and ignore what Levi did calculate and make your own proper calculations. If you cannot come up with method of calculating enthalpy in creative way, then it is your problem. But you are in the situation that no expert knowledge does help you, but you need to come up something creative. Although, being creative is not that easy. In summary, Rossi is completely innocent for lack of calorimetry. He did not have any influence on enthalpy measurements, because measuring enthalpy was task assigned for independent scientists such as Levi and Lewan. —Jouni Ps. I agree, that 18 hour test gave probably too high power output. It is probably off the mark by factor of two. There is simple physics that 130kW output would have lead into core melt down, because stailess steal is not fast enough heat conductor.
Re: [Vo]:Corrections to "heat after death" calculations
I wrote: "I don't know of any two serious theorists that agree!" That should have said: "I don't know of any two serious theorists that agree with theories they didn't help develop themselves". Some obvious exceptions to the first statement are Windom & Larsen, and Chubb & Chubb. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 31, 2011, at 11:30 AM, Jed Rothwell wrote: Horace Heffner wrote: The flowing water test was not public as far as I know. Where is the report showing the data etc.? The data is in NyTeknik and LENR-CANR.org. If you do not trust Levi et al. to report the results of the flow test honestly and accurately, then you cannot trust them to report any results, or to conduct a test without cheating. It would be very easy to make a fake test with a hidden wire. It would be even easier to pretend they have done a test and to publish fake data. If you do not believe that Levi et al. are credible, honest scientists you should dismiss all of these claims. You need only say "I don't believe them." The discussion ends there. Nothing more can be said, or needs to be said. If your standard is that we can only trust "public tests" then you can throw out the whole of cold fusion and the rest of modern science, because public tests are rare and they seldom prove anything. - Jed What you say might be true if the public tests were reasonably well done. They weren't. There is thus no reason to believe closed door results were done any more competently unless sufficient information is published to make that determination. What are the URLs? I was under the impression the details of the non- boiling flowing water test were kept confidential. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 31, 2011, at 1:45 PM, Joe Catania wrote: You're the one that believes they are demonstrations. I stated they were not. Yiu also failed to convince anyone they were (but did try). Why you believe in this nonsense is beyond me. Did Rossi make a large cash contribution? I sense much academic dishonesty in you. Feeble puffs of condensed water out of Rossi's hose were his undoing and has turned CF back into the farse you're tryig to convince us it isn't. Apparently you aren't even up to the challenge. Cold fusion is a serious scientific issue. Surely any scientist who spends sufficient time reviewing the LENR literature, e.g.: http://www.lenr-canr.org/ realizes there is an abundance of evidence from highly credible scientists indicating anomalous behavior of matter when hydrogen is absorbed. There can be no doubt at this point there is important knowledge to be gained from study in the field. Considering research in the field is such small science, compared to Mars missions, supercolliders, and tokamaks, and considering there is so much potential for humanity: http://www.lenr-canr.org/acrobat/RothwellJcoldfusiona.pdf the potential cost/benefit of research in this field makes funding it highly justified on a scientific research basis. I have seen no public evidence provided that indicates CF is ready for commercialization, for commercial investment with the expectation of quick profits. Others may disagree of course. Rossi is not engaged in serious science. He is engaged in a business venture. His integrity is possibly not that of a scientist. He could indeed set the field back seriously. This does not make CF a farce any more than one bad cop makes law enforcement a farce. What would make the field a farce is the blind acceptance by everyone in the field of any claim anyone in the field makes. This is certainly not what happens in the case of LENR theory! I don't know of any two serious theorists that agree! We who work in the field have the obligation to be our own harshest critics. We also have some obligation to examine whatever evidence is put forth, pro and con, and make an effort to logically determine its truth, meaning, relevance, and implications. It seems to me this group does a pretty good job of this, and not just for LENR, but for anomalous science in general. It is a great place to hang out. You never know for sure what you are going to see going on here when you get up in the morning. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
And you would do well to study Sun Tzu for you do not know your adversary. I have never left the fence in discussions about Andy Smith and his Stanley Steamer. You clearly confuse me with someone else. Warmest Regards, T On Wed, Aug 31, 2011 at 5:45 PM, Joe Catania wrote: > You're the one that believes they are demonstrations. I stated they were > not. Yiu also failed to convince anyone they were (but did try). Why you > believe in this nonsense is beyond me. Did Rossi make a large cash > contribution? I sense much academic dishonesty in you. Feeble puffs of > condensed water out of Rossi's hose were his undoing and has turned CF back > into the farse you're tryig to convince us it isn't. Apparently you aren't > even up to the challenge. > - Original Message - From: "Terry Blanton" > To: > Sent: Wednesday, August 31, 2011 5:42 PM > Subject: Re: [Vo]:Corrections to "heat after death" calculations > > >> On Wed, Aug 31, 2011 at 5:03 PM, Joe Catania wrote: >> >>> Jed appears to be pursued by demons. What else would induce a Japlish >>> translator to take up residence in a cold fusion forum. >> >> Joe appears to be pursued by demonstrations. What else would induce a >> pseudoskeptic to take up residence in a cold fusion forum? >> >> T >> >> > >
Re: [Vo]:Corrections to "heat after death" calculations
I begin to see you can be gracious where Mother Nature isn't. - Original Message - From: Jed Rothwell To: vortex-l@eskimo.com Sent: Wednesday, August 31, 2011 5:57 PM Subject: Re: [Vo]:Corrections to "heat after death" calculations Joe Catania wrote: > Mother Nature has authorized me act on Her behalf, as Her agent. I am authorized to forgive these insults. But also to warn you people to Watch Your Step. Next time >She may not be so magnanimous. >- Jed Jed appears to be pursued by demons. What else would induce a Japlish translator to take up residence in a cold fusion forum. The answer should be obvious. Mother Nature is Japanese. Why do you think she picked me to be her "minister and interpreter," as Bacon put it? What do you think an interpreter does? Hey, I'm not proud of this. There's no profit in being a prophet. It is basically an S&M relationship. Just as Bacon said, it features chains and submission, very kinky: "For man, as the minister and interpreter of nature does, and understands, as much as he has observed of the order, operation, and mind of nature; and neither knows nor is able to do more. Neither is it possible for any power to loosen or burst the chain of causes, nor is nature to be overcome except by submission." - Jed
Re: [Vo]:Corrections to "heat after death" calculations
Joe Catania wrote: > Mother Nature has authorized me act on Her behalf, as Her agent. I am authorized to forgive these insults. But also to warn you people to Watch Your Step. Next time >She may not be so magnanimous. >- Jed Jed appears to be pursued by demons. What else would induce a Japlish translator to take up residence in a cold fusion forum. The answer should be obvious. Mother Nature is Japanese. Why do you think she picked _me_ to be her "minister and interpreter," as Bacon put it? What do you think an interpreter does? Hey, I'm not proud of this. There's no profit in being a prophet. It is basically an S&M relationship. Just as Bacon said, it features chains and submission, very kinky: "For man, as the minister and interpreter of nature does, and understands, as much as he has observed of the order, operation, and mind of nature; and neither knows nor is able to do more. Neither is it possible for any power to loosen or burst the chain of causes, nor is nature to be overcome except by submission." - Jed
Re: [Vo]:Corrections to "heat after death" calculations
You're the one that believes they are demonstrations. I stated they were not. Yiu also failed to convince anyone they were (but did try). Why you believe in this nonsense is beyond me. Did Rossi make a large cash contribution? I sense much academic dishonesty in you. Feeble puffs of condensed water out of Rossi's hose were his undoing and has turned CF back into the farse you're tryig to convince us it isn't. Apparently you aren't even up to the challenge. - Original Message - From: "Terry Blanton" To: Sent: Wednesday, August 31, 2011 5:42 PM Subject: Re: [Vo]:Corrections to "heat after death" calculations On Wed, Aug 31, 2011 at 5:03 PM, Joe Catania wrote: Jed appears to be pursued by demons. What else would induce a Japlish translator to take up residence in a cold fusion forum. Joe appears to be pursued by demonstrations. What else would induce a pseudoskeptic to take up residence in a cold fusion forum? T
Re: [Vo]:Corrections to "heat after death" calculations
On Wed, Aug 31, 2011 at 5:03 PM, Joe Catania wrote: > Jed appears to be pursued by demons. What else would induce a Japlish > translator to take up residence in a cold fusion forum. Joe appears to be pursued by demonstrations. What else would induce a pseudoskeptic to take up residence in a cold fusion forum? T
Re: [Vo]:Corrections to "heat after death" calculations
> Mother Nature has authorized me act on Her behalf, as Her agent. I am >authorized to forgive these insults. But also to warn you people to Watch Your >Step. Next time >She may not be so magnanimous. >- Jed Jed appears to be pursued by demons. What else would induce a Japlish translator to take up residence in a cold fusion forum. - Original Message - From: Jed Rothwell To: vortex-l@eskimo.com Sent: Wednesday, August 31, 2011 4:25 PM Subject: Re: [Vo]:Corrections to "heat after death" calculations Joe Catania wrote: Not only have I been the subject of ad hominems for a presentaion that is obvious by the very nature of what is being discussed, there have been false allegations and insults to nature Mother Nature has authorized me act on Her behalf, as Her agent. I am authorized to forgive these insults. But also to warn you people to Watch Your Step. Next time She may not be so magnanimous. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
Joe Catania wrote: > Not only have I been the subject of ad hominems for a presentaion that is > obvious by the very nature of what is being discussed, there have been false > allegations and insults to nature > Mother Nature has authorized me act on Her behalf, as Her agent. I am authorized to forgive these insults. But also to warn you people to Watch Your Step. Next time She may not be so magnanimous. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
I didn't know it was possible to insult nature with just words. You can insult the Pope with just words. Harry From: Joe Catania >To: vortex-l@eskimo.com >Sent: Tuesday, August 30, 2011 12:35:15 PM >Subject: Re: [Vo]:Corrections to "heat after death" calculations > > > >Not only have I been the subject of ad hominems for a presentaion that is obvious by the very nature of what is being discussed, there have been false allegations and insults to nature. > > >
Re: [Vo]:Corrections to "heat after death" calculations
Horace Heffner wrote: > The flowing water test was not public as far as I know. Where is the > report showing the data etc.? > The data is in NyTeknik and LENR-CANR.org. If you do not trust Levi et al. to report the results of the flow test honestly and accurately, then you cannot trust them to report any results, or to conduct a test without cheating. It would be very easy to make a fake test with a hidden wire. It would be even easier to pretend they have done a test and to publish fake data. If you do not believe that Levi et al. are credible, honest scientists you should dismiss all of these claims. You need only say "I don't believe them." The discussion ends there. Nothing more can be said, or needs to be said. If your standard is that we can only trust "public tests" then you can throw out the whole of cold fusion and the rest of modern science, because public tests are rare and they seldom prove anything. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 31, 2011, at 10:38 AM, Jed Rothwell wrote: Horace Heffner wrote: The public demonstrations to date prove nothing because the methods used are so flawed. That is incorrect. As Rossi and I have pointed out many times, if there were flaws in the steam test, the flowing water test would have revealed them. Since it showed even more heat than the steam test with this same device, that proves the steam test methodology is sound. - Jed Under which shell is that pea? The flowing water test was not public as far as I know. Where is the report showing the data etc.? Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
Sigh. I can't seem to get anything right the first time. Some typos corrected below. On Aug 31, 2011, at 9:43 AM, Jed Rothwell wrote: Horace Heffner wrote: Of course Rossi has "perfect control" operating in the range chosen. All he has to do is provide enough sustained power to heat the water flow to boiling temperature, call it Pb, or a enogh above that for a momentary "steam" demonstration. It isn't momentary. The steam lasts indefinitely. Well, yes of course the steam lasts indefinitely, if the power provided is above Pb, which is my assumption.However, my point here is if the long term operating power is Po, Pb < Podoes not give an interesting steam demonstration, it is merely necessary to raise Po to P2, the demonstration power, Pbto show very good steam production, and yet for the overall run have the appearance of a good COP (coefficient of power, the ratio of power out to power in). Chimney temperature will remain at all times at the boiling point. Rossi does not have to manually raise Po to Pd, because the controllers have the capability to vary the power, and do vary the power if they are of any use at all. If the power variation occurs in long enough time segments, then it is possible to know when to demonstrate steam at the higher power P2 by merely knowing from the sound of the device whether it is operating at Po or P2 power. However, in all cases, if the output thermal power produced remains in the range Pb to Pd, then pure water is coming out of the device, not just droplets in the steam. This is not condensation in the hose. It is coming directly out of the steam exit port. The "steam quality" indicated by the relative humidity probe will remain at all times at 100%. If one keeps his head in the sand and does not do calorimetry on the output, or even take the hose off and to see what is happening, and assumes all water is converted to steam , then greatly inflated estimates of thermal output will result. These estimates can be off by roughly an order of magnitude. They prove nothing at all. The device could produce some nuclear heat, or none at all. The steam can not be dry in equilibrium operation in this power range, Pb to Pd, even if a significant amount of power comes from a nuclear reaction. If operating in this power range water is obviously coming out and the "calorimetry" method used is worthless. Not according to experts in steam such as Bjorn Palm, Head of the Energy Technology Division at the Royal Institute of Technology, quoted here: http://www.nyteknik.se/nyheter/energi_miljo/energi/article3228376.ece It is possible you know more about these systems than they do, but I doubt it. - Jed You have not interpreted Palm's remarks in a valid manner. The problem is therefore yours and not Palm's. Palm's credentials therefore are irrelevant. Quote from referenced article: - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Ny Teknik turned to Professor Björn Palm, Head of the Energy Technology Division at the Royal Institute of Technology, doing research on heat transfer by evaporation. Based on the given dimensions and geometry, he gave his assessment of the situation: “Any air in the tube is driven out of the flowing steam. This means that at the outlet there is pure steam, possibly with a little water droplets that come with the flow from the liquid surface. However, I cannot imagine that this would affect the 'effective' enthalpy of vaporization. From other cases with evaporation in tubes I would guess that the steam quality is at least 90%. “ - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - "I cannot imagine" is *not* an analysis of the data. It is an offhand remark. It is a "guess" as to how much heat can be carried away in droplets entrained in steam, and even based on other cases at that. My points, regarding the flow of pure water, and the percolator effect, have nothing to do at all with how much heat can be carried by water droplets suspended in the steam. Palm's comments have nothing to do with my points at all. His comments are irrelevant to the points I have made. I believe the analysis I have made is numerically accurate. It is based on conservation of energy. It does not show one way or another whether nuclear heat is or is not being produced. It is entirely possible nuclear heat is being produced in addition to power in, yet Po = (nuclear thermal power) plus (electric heating power) is still in the range Pbbeing ejected from the exit port, thus completely invalidating the "calorimetry" used. The public demonstrations to date prove nothing because the methods used are so flawed. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
Horace Heffner wrote: > The public demonstrations to date prove nothing because the methods used > are so flawed. > That is incorrect. As Rossi and I have pointed out many times, if there were flaws in the steam test, the flowing water test would have revealed them. Since it showed even more heat than the steam test with this same device, that proves the steam test methodology is sound. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 31, 2011, at 9:43 AM, Jed Rothwell wrote: Horace Heffner wrote: Of course Rossi has "perfect control" operating in the range chosen. All he has to do is provide enough sustained power to heat the water flow to boiling temperature, call it Pb, or a enogh above that for a momentary "steam" demonstration. It isn't momentary. The steam lasts indefinitely. Well, yes of course the steam lasts indefinitely, if the power provided is above Pb, which is my assumption.However, my point here is if the long term operating power is Po, Pb < Podoes not give an interesting steam demonstration, it is merely necessary to raise Po to Pd, the demonstration power, Pbshow very good steam production, and yet for the overall run have the appearance of a good COP (coefficient of power, the ratio of power in to power out. Chimney temperature will remain at all times at the boiling point. Rossi does not have to manually raise Po to Pd, because the controllers have the capability to vary the power, and do vary the power if they are of any use at all. If the power variation occurs in long enough time segments, then it is possible to know when to demonstrate steam at the higher power Pd by merely knowing from the sound of the device whether it is operating at Po or Pd power. However, in all cases, if the output thermal power produced remains in the range Pb to Pd, then pure water is coming out of the device, not just droplets in the steam. This is not condensation in the hose. It is coming directly out of the steam exit port. The "steam quality" indicated by the relative humidity probe will remain at all times at 100%. If one keeps his head in the sand and does not do calorimetry on the output, or even take the hose off and see what is happening, and assumes all water is converted to steam , then greatly inflated estimates of thermal output will result. These can be off by roughly an order of magnitude. They prove nothing at all. The device could produce some nuclear heat, or none at all. The steam can not be dry in equilibrium operation in this power range, Pb to Pd, even if a significant amount of power comes from a nuclear reaction. If operating in this power range water is obviously coming out and the "calorimetry" method used is worthless. Not according to experts in steam such as Bjorn Palm, Head of the Energy Technology Division at the Royal Institute of Technology, quoted here: http://www.nyteknik.se/nyheter/energi_miljo/energi/article3228376.ece It is possible you know more about these systems than they do, but I doubt it. - Jed You have not interpreted Palm's remarks in a valid manner. The problem is therefore yours and not Palm's. Palm's credentials therefore are irrelevant. Quote from referenced article: - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Ny Teknik turned to Professor Björn Palm, Head of the Energy Technology Division at the Royal Institute of Technology, doing research on heat transfer by evaporation. Based on the given dimensions and geometry, he gave his assessment of the situation: “Any air in the tube is driven out of the flowing steam. This means that at the outlet there is pure steam, possibly with a little water droplets that come with the flow from the liquid surface. However, I cannot imagine that this would affect the 'effective' enthalpy of vaporization. From other cases with evaporation in tubes I would guess that the steam quality is at least 90%. “ - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - "I cannot imagine" is *not* an analysis of the data. It is an offhand remark. It is a "guess" as to how much heat can be carried away in droplets entrained in steam, and even based on other cases at that. My points, regarding the flow of pure water, and the percolator effect, have nothing to do at all with how much heat can be carried by water droplets suspended in the steam. Palm's comments have nothing to do with my points at all. His comments are irrelevant to the points I have made. I believe the analysis I have made is numerically accurate. It is based on conservation of energy. It does not show one way or another whether nuclear heat is or is not being produced. It is entirely possible nuclear heat is being produced in addition to power in, yet Po = (nuclear thermal power) plus (electric heating power) is still in the range Pbbeing ejected from the exit port, thus completely invalidating the "calorimetry" used. The public demonstrations to date prove nothing because the methods used are so flawed. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 31, 2011, at 6:23 AM, Jed Rothwell wrote: Jouni Valkonen wrote: I am sure that Rossi was quite well familiar with the real power of E-Cat, because water inflow rate was adjusted in right level. I believe he does it the other way. He leaves the water inflow rate steady and adjusts the power output to vaporize all of the water. In the videos you can see him adjusting the controls of the eCat, but I have not seen him change the pump controller. In calorimetry it is good practice to make conditions uniform and unvarying as much as you can. Rather than changing the flow to keep the outlet temperature stable, it is better to increase or decrease power. Rossi has much better control over the power of his cell than in any previous cold fusion experiment. - Jed Some typos corrected and clarifying language added: This conversation seems nonsensical in light of recent discussion. Rossi has "perfect control" operating in the range chosen, due to not examining the output products. All he has to do is provide enough sustained power to heat the water flow to boiling temperature, call it Pb, or enough above that for a momentary "steam" demonstration. I haven't seen any test where thermal power reached significantly above the dryout point, call that Pd, where all water input is converted to steam. If power had ever reached above Pd then the steam temperature would be way above boiling point for a sustained period. If operating above Pb then the flue temperature will remain at or above boiling temperature, as Cantwell demonstrated by experiment. So, in sustained stable equilibrium mode, Rossi is typically operating in the power range between Pb and Pd. Pb and Pd are determined by the flow rate. As I demonstrated earlier, if you operate continually in the power range Pb to Pd then water overflow necessarily occurs. See: http://www.mtaonline.net/~hheffner/KrivitFilm.pdf http://www.mtaonline.net/~hheffner/Cantwell2.pdf Rossi says the steam is dry. All Rossi has to do to check this is to operate at equilibrium in this Pb to Pd output power range for a long period and then remove the hose, or provide a transparent hose. He will then see that water is gushing forth out the exit port. That condition I consider to be well beyond just a "wet steam" or a "steam quality" issue. The steam can not be "dry" in equilibrium operation in this output power range, Pb to Pd, even if a significant amount of power comes from a nuclear reaction. If operating in this power range water is obviously coming out and the "calorimetry" method used is worthless. This method is perfect for self delusion. The dynamic situation is far more difficult to analyze because insufficient information about the thermodynamic properties of the device is available. Also, an effort to analyze the device dynamics would be far more time consuming and less convincing than simply providing good calorimetry. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
Horace Heffner wrote: > Of course Rossi has "perfect control" operating in the range chosen. All > he has to do is provide enough sustained power to heat the water flow to > boiling temperature, call it Pb, or a enogh above that for a momentary > "steam" demonstration. It isn't momentary. The steam lasts indefinitely. The steam can not be dry in equilibrium operation in this power range, Pb to > Pd, even if a significant amount of power comes from a nuclear reaction. If > operating in this power range water is obviously coming out and the > "calorimetry" method used is worthless. Not according to experts in steam such as Bjorn Palm, Head of the Energy Technology Division at the Royal Institute of Technology, quoted here: http://www.nyteknik.se/nyheter/energi_miljo/energi/article3228376.ece It is possible you know more about these systems than they do, but I doubt it. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 31, 2011, at 6:23 AM, Jed Rothwell wrote: Jouni Valkonen wrote: I am sure that Rossi was quite well familiar with the real power of E-Cat, because water inflow rate was adjusted in right level. I believe he does it the other way. He leaves the water inflow rate steady and adjusts the power output to vaporize all of the water. In the videos you can see him adjusting the controls of the eCat, but I have not seen him change the pump controller. In calorimetry it is good practice to make conditions uniform and unvarying as much as you can. Rather than changing the flow to keep the outlet temperature stable, it is better to increase or decrease power. Rossi has much better control over the power of his cell than in any previous cold fusion experiment. - Jed This conversation seems nonsensical in light of recent discussion. Of course Rossi has "perfect control" operating in the range chosen. All he has to do is provide enough sustained power to heat the water flow to boiling temperature, call it Pb, or a enogh above that for a momentary "steam" demonstration. I haven't seen any test where thermal power reached significantly above the dryout point, call that Pd, where all water input is converted to steam. If power had ever reached above Pb then the steam temperature would be way above boiling point for a sustained period. If operating above Pb then the flue temperature will remain at or above boiling temperature, as Cantwell demonstrated. So, Rossi is typically operating in the power range between Pb and Pd. Pb and Pd are determined by the flow rate. As I demonstrated earlier, if you operated in the power range Pb to Pd then water overflow necessarily occurs. See: http://www.mtaonline.net/~hheffner/KrivitFilm.pdf http://www.mtaonline.net/~hheffner/Cantwell2.pdf Rossi says the steam is dry. All Rossi has to do to see this is operate at equilibrium in this Pb to Pd range for a long period and then remove the hose, or provide a transparent hose. He will then see that water is gushing forth out the exit port. That condition I consider to be well beyond just wet steam. The steam can not be dry in equilibrium operation in this power range, Pb to Pd, even if a significant amount of power comes from a nuclear reaction. If operating in this power range water is obviously coming out and the "calorimetry" method used is worthless. This method is perfect for self delusion. The dynamic situation is far more difficult to analyze because insufficient information about the thermodynamic properties of the device is available. Also, an effort to analyze the device dynamics would be far more time consuming and less convincing than simply providing good calorimetry. Despite all this, and limited personal time, I'll continue to see I any sense or improved intuition can be made from what we know by using an overly simplistic black box model. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
Jouni Valkonen wrote: I am sure that Rossi was quite well familiar with the real power of E-Cat, because water inflow rate was adjusted in right level. I believe he does it the other way. He leaves the water inflow rate steady and adjusts the power output to vaporize all of the water. In the videos you can see him adjusting the controls of the eCat, but I have not seen him change the pump controller. In calorimetry it is good practice to make conditions uniform and unvarying as much as you can. Rather than changing the flow to keep the outlet temperature stable, it is better to increase or decrease power. Rossi has much better control over the power of his cell than in any previous cold fusion experiment. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
One final addition considering December E-Cat. This value of total heating power of 6-9 kW is reliable, because it is calculated using three different data sets and three distinct methods. –There was 100 kPa overpressure, and from Mats Lewan E-Cat we get one reference point (there was 32 kPa overpressure). Therfore 6-9kW is likely explanation for 100 kPa. –During the two approximately 6min power surge at 17:30 and 17:50 temperature rose approximately 1.5 times more than during the first 30 minutes when only 1.2 kW electric heater was active. Therefore total heating power when E-Cat was producing excess heat, was approximately 9kW. –And for third method can be calculated using an estimation of total thermal mass of E-Cat. This where I got that 6 kW for minimum possible power outpu. It is good to notice, that what Levi was calculating in the preliminary report was irrelevant and it was just mere luck that he arrived similar result. I will explain this why Levi's calculations were irrelevant in detail, if it is requested. I am sure that Rossi was quite well familiar with the real power of E-Cat, because water inflow rate was adjusted in right level. But he just did not want to correct Levi's calculations, or propose straight forward calorimetry, what Levi forgot to do. –Jouni 2011/8/31 Jouni Valkonen : > Actually I took still another look for the graph: > > http://2.bp.blogspot.com/_852Sj2_TNC4/TTwDi8cYrtI/E1E/TT603dSfpzs/s1600/report3.jpg > > It is really difficult to try to estimate temperatures from this graph. > > However it looks that my estimations were somewhat inaccurate. But it > looks that ΔT was 1.5 times higher during the last 6 minutes before > boiling than the first 30 minutes, when only 1.2 kW heating element > was active. Therefore likely output power was 9kW. > > Therefore I estimate with 90% confidence that the heating power of > December E-Cat was between 6kW and 9 kW. And heat after death was > 2-8kW, but this is really difficult to estimate, but it was rather > constant. My hunch is that power drop was only 1.2 kW, when E-Cat was > disconnected from external power source. > > –Jouni > > 2011/8/31 Jouni Valkonen : >> Small addition, this 6kW figure is minimum possible heating power. We >> have also empirical way for calculating total enthalphy, that gives >> higher value than 6 kW. If it is assumed that E-Cat was full of water >> when 1.2kW heating element was turned on, then 1.2kW was enough to >> cause ΔT to be 20°C in 30 minutes. This means that during the 6min >> power surge heating power was 10 × 1.2kW = 12kW. >> >> If it is assumed that E-Cat was not full of water when power was >> turned on, then heating power during the power surge was even more >> than 12kW. However I think this unlikely, because steam overperssure >> was only 100 kPa and this is difficult to explain even for 12 kW >> heating power. 100kPa overpressure should be more close for 6-9 kW >> heating power. >> >> –Jouni >> >> >> 2011/8/31 Jouni Valkonen : >>> 2011/8/30 Jed Rothwell : Jouni Valkonen wrote: > Ps. I do not know what model of E-Cat we are talking about. Does we have > pictures? Or is it just some mythical test what was seen by nobody. > The 15 minute heat-after-death event was with the large eCat used in the January and February tests. This produces 12 kW to 16 kW output (depending on how you measure it) with about 400 W input. As far as I know, this is the only eCat that Levi et al. tested in December, which is when the event occurred. The flow rate was typically ~300 ml/min I believe. >>> >>> Ah, now I know exactly what is going on. >>> >>> Here is the premilinary report (Test1): >>> http://22passi.blogspot.com/2011/01/report-ufficiale-esperimento-della.html?m=1 >>> >>> Ok, I am amazed how far from reality Joe was, because it was >>> impossible try to make proper conclusions in what test he was >>> referring. >>> >>> But anyways, it is now very clear. >>> >>> –Input power was turned on 16.55 and it was around 1200 Watts. >>> –This caused slight temperature rise during first 30 minutes.(ΔT 20°C) >>> –After that reaction partially ignited and temperature rose to 60°C. >>> This took about 20 minutes >>> –Then full ignition happened 17.50. Temperature rose quickly to >>> 101.6°C and steam overpressure was ca. 100 kPa. >>> –Then the power was cut 10 minutes later and reactor still continued >>> producing steam for 15 minutes >>> –Finally reactor was shut down 17.15 by increasing water flow >>> >>> We do not have good data what was the momentary output power during >>> the 10minute powersurge. Also, in order to make any calculations, we >>> should have some information how much E-Cat can store liquid water >>> inside. >>> >>> However, as the temperature stayed over 100, it means that there was >>> some steam production. We do not know exactly how much, because there >>> was visible temperature drop after power was cut and this means tha
Re: [Vo]:Corrections to "heat after death" calculations
Actually I took still another look for the graph: http://2.bp.blogspot.com/_852Sj2_TNC4/TTwDi8cYrtI/E1E/TT603dSfpzs/s1600/report3.jpg It is really difficult to try to estimate temperatures from this graph. However it looks that my estimations were somewhat inaccurate. But it looks that ΔT was 1.5 times higher during the last 6 minutes before boiling than the first 30 minutes, when only 1.2 kW heating element was active. Therefore likely output power was 9kW. Therefore I estimate with 90% confidence that the heating power of December E-Cat was between 6kW and 9 kW. And heat after death was 2-8kW, but this is really difficult to estimate, but it was rather constant. My hunch is that power drop was only 1.2 kW, when E-Cat was disconnected from external power source. –Jouni 2011/8/31 Jouni Valkonen : > Small addition, this 6kW figure is minimum possible heating power. We > have also empirical way for calculating total enthalphy, that gives > higher value than 6 kW. If it is assumed that E-Cat was full of water > when 1.2kW heating element was turned on, then 1.2kW was enough to > cause ΔT to be 20°C in 30 minutes. This means that during the 6min > power surge heating power was 10 × 1.2kW = 12kW. > > If it is assumed that E-Cat was not full of water when power was > turned on, then heating power during the power surge was even more > than 12kW. However I think this unlikely, because steam overperssure > was only 100 kPa and this is difficult to explain even for 12 kW > heating power. 100kPa overpressure should be more close for 6-9 kW > heating power. > > –Jouni > > > 2011/8/31 Jouni Valkonen : >> 2011/8/30 Jed Rothwell : >>> Jouni Valkonen wrote: >>> Ps. I do not know what model of E-Cat we are talking about. Does we have pictures? Or is it just some mythical test what was seen by nobody. >>> >>> The 15 minute heat-after-death event was with the large eCat used in the >>> January and February tests. This produces 12 kW to 16 kW output (depending >>> on how you measure it) with about 400 W input. As far as I know, this is the >>> only eCat that Levi et al. tested in December, which is when the event >>> occurred. The flow rate was typically ~300 ml/min I believe. >>> >> >> Ah, now I know exactly what is going on. >> >> Here is the premilinary report (Test1): >> http://22passi.blogspot.com/2011/01/report-ufficiale-esperimento-della.html?m=1 >> >> Ok, I am amazed how far from reality Joe was, because it was >> impossible try to make proper conclusions in what test he was >> referring. >> >> But anyways, it is now very clear. >> >> –Input power was turned on 16.55 and it was around 1200 Watts. >> –This caused slight temperature rise during first 30 minutes.(ΔT 20°C) >> –After that reaction partially ignited and temperature rose to 60°C. >> This took about 20 minutes >> –Then full ignition happened 17.50. Temperature rose quickly to >> 101.6°C and steam overpressure was ca. 100 kPa. >> –Then the power was cut 10 minutes later and reactor still continued >> producing steam for 15 minutes >> –Finally reactor was shut down 17.15 by increasing water flow >> >> We do not have good data what was the momentary output power during >> the 10minute powersurge. Also, in order to make any calculations, we >> should have some information how much E-Cat can store liquid water >> inside. >> >> However, as the temperature stayed over 100, it means that there was >> some steam production. We do not know exactly how much, because there >> was visible temperature drop after power was cut and this means that >> steam overpressure decreased somewhat from that 100kPa, in the >> self-sustaining mode. Therefore total heating power in self-sustaining >> mode was at least 3 kW, probably more. But what is important is that >> there was not visible decreasing of heating power during the 15 min >> self-sustaining mode and it was artificially cancelled by shutting >> down the reactor. Therefore it is fair to assume, that it would have >> continued indefinitely without shutting down the self-sustaining mode. >> >> Also as we know that the volume of reactor chamber was ca. 1 liter, >> therefore the maximum metal mass for storing thermal energy was >> probably 5 kg. Same logic applies here that only the reactor chamber >> can store residual heat energy.Therefore rest of the E-Cat can be >> ignored, because it does not exceed significantly 100°C. >> >> Also some estimations about what was the total heating power during >> the 10min powersurge. We know that in that time, inside E-Cat, there >> was at least 10 kg of water. Therefore total heating power during 6min >> power surge was 4.6kW (water stored inside the E-Cat) + 1.5kW (cool >> water flux) + 1.0kW (metal components of E-Cat) = _6kW_, in order to >> rise ΔT by 40°C in 6min. >> >> This is also the most likely excess heating power of December E-Cat, >> i.e. 4.7kW excess heat was produced for 25 minutes. >> >> In summary, water flow was 14 kg/h, core mass was 5kg, he
Re: [Vo]:Corrections to "heat after death" calculations
Small addition, this 6kW figure is minimum possible heating power. We have also empirical way for calculating total enthalphy, that gives higher value than 6 kW. If it is assumed that E-Cat was full of water when 1.2kW heating element was turned on, then 1.2kW was enough to cause ΔT to be 20°C in 30 minutes. This means that during the 6min power surge heating power was 10 × 1.2kW = 12kW. If it is assumed that E-Cat was not full of water when power was turned on, then heating power during the power surge was even more than 12kW. However I think this unlikely, because steam overperssure was only 100 kPa and this is difficult to explain even for 12 kW heating power. 100kPa overpressure should be more close for 6-9 kW heating power. –Jouni 2011/8/31 Jouni Valkonen : > 2011/8/30 Jed Rothwell : >> Jouni Valkonen wrote: >> >>> Ps. I do not know what model of E-Cat we are talking about. Does we have >>> pictures? Or is it just some mythical test what was seen by nobody. >>> >> >> The 15 minute heat-after-death event was with the large eCat used in the >> January and February tests. This produces 12 kW to 16 kW output (depending >> on how you measure it) with about 400 W input. As far as I know, this is the >> only eCat that Levi et al. tested in December, which is when the event >> occurred. The flow rate was typically ~300 ml/min I believe. >> > > Ah, now I know exactly what is going on. > > Here is the premilinary report (Test1): > http://22passi.blogspot.com/2011/01/report-ufficiale-esperimento-della.html?m=1 > > Ok, I am amazed how far from reality Joe was, because it was > impossible try to make proper conclusions in what test he was > referring. > > But anyways, it is now very clear. > > –Input power was turned on 16.55 and it was around 1200 Watts. > –This caused slight temperature rise during first 30 minutes.(ΔT 20°C) > –After that reaction partially ignited and temperature rose to 60°C. > This took about 20 minutes > –Then full ignition happened 17.50. Temperature rose quickly to > 101.6°C and steam overpressure was ca. 100 kPa. > –Then the power was cut 10 minutes later and reactor still continued > producing steam for 15 minutes > –Finally reactor was shut down 17.15 by increasing water flow > > We do not have good data what was the momentary output power during > the 10minute powersurge. Also, in order to make any calculations, we > should have some information how much E-Cat can store liquid water > inside. > > However, as the temperature stayed over 100, it means that there was > some steam production. We do not know exactly how much, because there > was visible temperature drop after power was cut and this means that > steam overpressure decreased somewhat from that 100kPa, in the > self-sustaining mode. Therefore total heating power in self-sustaining > mode was at least 3 kW, probably more. But what is important is that > there was not visible decreasing of heating power during the 15 min > self-sustaining mode and it was artificially cancelled by shutting > down the reactor. Therefore it is fair to assume, that it would have > continued indefinitely without shutting down the self-sustaining mode. > > Also as we know that the volume of reactor chamber was ca. 1 liter, > therefore the maximum metal mass for storing thermal energy was > probably 5 kg. Same logic applies here that only the reactor chamber > can store residual heat energy.Therefore rest of the E-Cat can be > ignored, because it does not exceed significantly 100°C. > > Also some estimations about what was the total heating power during > the 10min powersurge. We know that in that time, inside E-Cat, there > was at least 10 kg of water. Therefore total heating power during 6min > power surge was 4.6kW (water stored inside the E-Cat) + 1.5kW (cool > water flux) + 1.0kW (metal components of E-Cat) = _6kW_, in order to > rise ΔT by 40°C in 6min. > > This is also the most likely excess heating power of December E-Cat, > i.e. 4.7kW excess heat was produced for 25 minutes. > > In summary, water flow was 14 kg/h, core mass was 5kg, heating power > in self-sustaining mode was 3-5kW (but it was constant). Max core > temperature 1000°C. > > –Jouni >
Re: [Vo]:Corrections to "heat after death" calculations
2011/8/30 Jed Rothwell : > Jouni Valkonen wrote: > >> Ps. I do not know what model of E-Cat we are talking about. Does we have >> pictures? Or is it just some mythical test what was seen by nobody. >> > > The 15 minute heat-after-death event was with the large eCat used in the > January and February tests. This produces 12 kW to 16 kW output (depending > on how you measure it) with about 400 W input. As far as I know, this is the > only eCat that Levi et al. tested in December, which is when the event > occurred. The flow rate was typically ~300 ml/min I believe. > Ah, now I know exactly what is going on. Here is the premilinary report (Test1): http://22passi.blogspot.com/2011/01/report-ufficiale-esperimento-della.html?m=1 Ok, I am amazed how far from reality Joe was, because it was impossible try to make proper conclusions in what test he was referring. But anyways, it is now very clear. –Input power was turned on 16.55 and it was around 1200 Watts. –This caused slight temperature rise during first 30 minutes.(ΔT 20°C) –After that reaction partially ignited and temperature rose to 60°C. This took about 20 minutes –Then full ignition happened 17.50. Temperature rose quickly to 101.6°C and steam overpressure was ca. 100 kPa. –Then the power was cut 10 minutes later and reactor still continued producing steam for 15 minutes –Finally reactor was shut down 17.15 by increasing water flow We do not have good data what was the momentary output power during the 10minute powersurge. Also, in order to make any calculations, we should have some information how much E-Cat can store liquid water inside. However, as the temperature stayed over 100, it means that there was some steam production. We do not know exactly how much, because there was visible temperature drop after power was cut and this means that steam overpressure decreased somewhat from that 100kPa, in the self-sustaining mode. Therefore total heating power in self-sustaining mode was at least 3 kW, probably more. But what is important is that there was not visible decreasing of heating power during the 15 min self-sustaining mode and it was artificially cancelled by shutting down the reactor. Therefore it is fair to assume, that it would have continued indefinitely without shutting down the self-sustaining mode. Also as we know that the volume of reactor chamber was ca. 1 liter, therefore the maximum metal mass for storing thermal energy was probably 5 kg. Same logic applies here that only the reactor chamber can store residual heat energy.Therefore rest of the E-Cat can be ignored, because it does not exceed significantly 100°C. Also some estimations about what was the total heating power during the 10min powersurge. We know that in that time, inside E-Cat, there was at least 10 kg of water. Therefore total heating power during 6min power surge was 4.6kW (water stored inside the E-Cat) + 1.5kW (cool water flux) + 1.0kW (metal components of E-Cat) = _6kW_, in order to rise ΔT by 40°C in 6min. This is also the most likely excess heating power of December E-Cat, i.e. 4.7kW excess heat was produced for 25 minutes. In summary, water flow was 14 kg/h, core mass was 5kg, heating power in self-sustaining mode was 3-5kW (but it was constant). Max core temperature 1000°C. –Jouni
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 30, 2011, at 4:15 PM, Man on Bridges wrote: Hi, On 31-8-2011 0:01, Horace Heffner wrote: On Aug 30, 2011, at 12:12 PM, Jed Rothwell wrote: If the only source of heat was electricity, two things are certain: 1. It could not be 12 kW in the first place. The wire would melt. You can't possibly conduct that much electricity over an ordinary wire. This is false. If the flow is 3 ml/s then any input power above 1617 W will provide a flue temperature at boiling point. If no one measures the output of the hose, but rather assumes dry steam, then the apparent power is over 12000 W. Just a reality check to see how thick a (VDE-approved) single copper wire you need at least to transfer 12 kW of power through. Copper resistivity / m = 0.0175 wire thickness theoretically possible "approved (norm)" Imax (A)230V 1 phase A (mm2) D (mm) R/m (Ω) Imax (A)Pmax (W)Pmax (W) 8.0 3.190.00219 53.33 12267 53.00 12250 As far as I can see from the photos of the Rossi reactor, the wires to the heating resistors are a lot smaller than the 3.19 mm diameter (= approx. AWG 8 !) Kind regards, MoB You have missed the point entirely. An electric power input of 1617 W will look like 12000 W if the flow is 5 ml/s and no one bothers to see what is coming out of the hose and exit port. The outlet temperature will remain stable at boiling point. This flaw in Rossi's "calorimetry" was hopefully clearly demonstrated by Cantwell's experiment and my analysis here: http://www.mtaonline.net/~hheffner/Cantwell2.pdf You don't have to actually input 12000 W electrical because the calorimetry can be off by an order of magnitude. If the flow rate is 5 ml/s then 1617 W will provide fake results, if a flow of 0.3 ml/s is used then 970 W will do. If the flow is 0.83 ml/s, as calculated by Mattia Rizzi for one run, then 268 W will do to fake the 12000 kW results. The problem is the need to measure the flow and all other key variables at all times In Cantwell's case, where the power was 800 W, water should overflow at *all* flows under 3 ml/s. Looking for this overflow has been avoided by Rossi (and Cantwell.) In short you don't need to provide a lot of power if you don't look at the water output. If Rossi is so sure his device produces dry steam then he could simply continually track power in and remove the hose to demonstrate that no water is pouring out of his device by the percolator effect I hopefully explained clearly here. He could simply use a transparent hose section. He could do actual calorimetry on the stuff going to the hose. Rossi and associates should not (have to) resort to using a relative humidity meter that even the manufacturer even says is not capable of measuring steam quality. If enough power is provided to heat the flowing water to at minimum boiling point (way less than 12000 W in all cases demonstrated), and a relative humidity probe and flue thermometer are your only windows into what is happening at the exit port, then you have no means to determine within a wide margin what the thermal output actually is. Without quality measurement and integration of the the power input and thermal power output, in order to compute an energy balance, no assertion of excess heat can be made with reasonable certainty. Power within the stated capability of the controller and power leads is sufficient to simulate large (kW order) heat flows, depending on the water flow rate. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
Hi, On 31-8-2011 0:01, Horace Heffner wrote: On Aug 30, 2011, at 12:12 PM, Jed Rothwell wrote: If the only source of heat was electricity, two things are certain: 1. It could not be 12 kW in the first place. The wire would melt. You can't possibly conduct that much electricity over an ordinary wire. This is false. If the flow is 3 ml/s then any input power above 1617 W will provide a flue temperature at boiling point. If no one measures the output of the hose, but rather assumes dry steam, then the apparent power is over 12000 W. Just a reality check to see how thick a (VDE-approved) single copper wire you need at least to transfer 12 kW of power through. Copper resistivity / m = 0.0175 wire thickness theoretically possible "approved (norm)" I_max (A) 230V 1 phase A (mm^2 ) D (mm) R/_m (?)I_max (A) P_max (W) P_max (W) 8.0 3.190.00219 53.33 12267 53.00 12250 As far as I can see from the photos of the Rossi reactor, the wires to the heating resistors are a lot smaller than the 3.19 mm diameter (= approx. AWG 8 !) Kind regards, MoB
Re: [Vo]:Corrections to "heat after death" calculations
Jed its more a violation of the 1st law to have steam production without extraction from the metal. No the temperature would not drop to zero. Sounds like you're admitting defeat. - Original Message - From: "Jed Rothwell" To: Sent: Tuesday, August 30, 2011 6:26 PM Subject: Re: [Vo]:Corrections to "heat after death" calculations Horace Heffner wrote: How else could it work? It would run out of water. Very little fits into the cell. You cannot do flow calorimetry without a flow. It would be like trying to do it without measuring the temperature. Obviously my question is are you sure that *precise magnitude* of flow rate, 300 ml/min, 5 ml/sec, 18 liters per hour, was present at the time of the heat after death observation? Ah. I see. Dunno. Ask Krivit to put the video back on line, or ask Levi or Rossi. Anyway, I am sure they thought it was showing significant, stable excess heat or they wouldn't put it in heat after death mode, would they? That would be pointless. The reason people do this is to eliminate input from the equation, to confirm that the output is not input accidentally magnified. You wouldn't do it if the calorimetry did not already indicate significant anomalous heat. That's why the "stored up heat" hypothesis does not work with Fleischmann's boil off heat after death, or in this instance. There is no storing up. It is producing more output than input continuously up to the moment heat after death begins (for a week, in Fleischmann's case). If they are "extracting heat" from the metal as Catania claims, the metal would be way below absolute zero by the time heat after death begins. I believe it is difficult to extract heat from metal in that condition. Something about the Second Law. When people such as Lonchampt turn off the power to blank cells in which there is only electrical or electrochemical heating, the heat immediately falls, according to Newton's law of cooling. It is readily apparent. It does not look a bit like heat after death. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
Horace Heffner wrote: How else could it work? It would run out of water. Very little fits into the cell. You cannot do flow calorimetry without a flow. It would be like trying to do it without measuring the temperature. Obviously my question is are you sure that *precise magnitude* of flow rate, 300 ml/min, 5 ml/sec, 18 liters per hour, was present at the time of the heat after death observation? Ah. I see. Dunno. Ask Krivit to put the video back on line, or ask Levi or Rossi. Anyway, I am sure they thought it was showing significant, stable excess heat or they wouldn't put it in heat after death mode, would they? That would be pointless. The reason people do this is to eliminate input from the equation, to confirm that the output is not input accidentally magnified. You wouldn't do it if the calorimetry did not already indicate significant anomalous heat. That's why the "stored up heat" hypothesis does not work with Fleischmann's boil off heat after death, or in this instance. There is no storing up. It is producing more output than input continuously up to the moment heat after death begins (for a week, in Fleischmann's case). If they are "extracting heat" from the metal as Catania claims, the metal would be way below absolute zero by the time heat after death begins. I believe it is difficult to extract heat from metal in that condition. Something about the Second Law. When people such as Lonchampt turn off the power to blank cells in which there is only electrical or electrochemical heating, the heat immediately falls, according to Newton's law of cooling. It is readily apparent. It does not look a bit like heat after death. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
Again your the only one who is imagining flow calorimetry without a flow. I can assure you I'm imagining no such thing. But of course you would not be able to tell me if there was or wasn't flow in any case you say you knew about. That's whats unique about you Jed. Your "science" is completely imaginary and you know it yet you can still turn around and say it was my imagination all along. If someone else saying the best they can do in terms of data is to tell you they've been working with it for more than a month most people would sense a total lie coming. Not you Jed. You'd tell us that's what makes it reliable. Ah... but there's no it as far as I can tell. Show the data. And no flawed flow calorimetry (however precious that may be to you) is going to be able to produce reliable data. Perhaps what you meant is what I've been telling you- don't use flow calorimetry. If you think the liquid test is better show us the results. Why did Rossi make so much of the steam tests? If Rossi's steam is dry you'd better believe there's no liquid flow. And if so why is the temp 100C? No superheat. Rossi must be a master of control! Yes, you've been imaginig everything you've said Jed. "Experts say," is a redundant statement. You should know that by now Jed. Why do company spokespeople deny that steam quality can be measured this way. Of course you know it can't. I've never heard of a boiler man doing any such thing. We all know its more difficult to measure steam quality. Still don't know why your ranting about flow calorimetry using a flow of water. Are you trying to say a flow of water is justification in itself? As a matter of fact the probe that Levi uses to measure RH has an attachment for velocity. Its one of the easiest things to measure. - Original Message ----- From: "Jed Rothwell" To: Sent: Tuesday, August 30, 2011 5:55 PM Subject: Re: [Vo]:Corrections to "heat after death" calculations Joe Catania wrote: Until I see the data you refer to all I can say is its seems like more of a guess. Okay. Ask Krivit to show it to you again. It was there before. It seems like a pretty good guess to me, since they told me they worked with the gadget for a month before demonstrating it. They did not say "we worked with one gadget for four weeks and then arbitrarily decided to use another one on the day of the test." I do not have your vivid imagination so I am not good at guessing or coming up with mind-boggling scenarios such as this, or people doing flow calorimetry without a flow. Why dosen't Rossi verify steam quality. He does. He uses a Delta Ohm RH meter or another brand. Experts tell me this is a perfectly good method. Self-appointed experts here say it is not, but all the real world experts I've heard from are confident that Rossi's steam is dry. They say it has to be, given the geometry of his device, the temperatures and the pressure (1 atm). I do not know enough to judge but I tend to assume that experts know what they're talking about, and I'm sure that this method cannot be as wrong as people here imagine it might be. I'm also sure that everyone who does flow calorimetry does use a flow of water. Hence the name: "flow calorimetry." But that's just me. I take things literally. When someone says "I drove from Atlanta to Washington" I assume they meant they have a car with four wheels and inflated tires, rather than a magic carpet or a herd of buffalo attached to skateboards. I suppose I am making a lot of assumptions and you could be right that people do flow calorimetry without a flow or that the machine is several hundred degrees and incandescent but no one has noticed and the insulating tape did not burn because it is special ordered from the Russian Space Agency for patching up reentry vehicle nosecones. Anything is possible and life is full of mysteries, but alas most of the mysteries escape my attention because -- as I said -- I have prosaic imagination, I read the manual, and I assume that people mean what they say. A simple steam velocity would verify steam quality yet I see no attempt being made to do so. And how does one measure steam velocity, simply? Or in a complicated way, for that matter? You should get together with Lomax on this. With your imagination I am sure you can suggest a method. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 30, 2011, at 12:12 PM, Jed Rothwell wrote: Horace Heffner wrote: As far as I know, this is the only eCat that Levi et al. tested in December, which is when the event occurred. The flow rate was typically ~300 ml/min I believe. Are you sure about that flow rate being present in the heat after death observation? How else could it work? It would run out of water. Very little fits into the cell. You cannot do flow calorimetry without a flow. It would be like trying to do it without measuring the temperature. Obviously my question is are you sure that *precise magnitude* of flow rate, 300 ml/min, 5 ml/sec, 18 liters per hour, was present at the time of the heat after death observation? It does correspond roughly to 12 kW boiling power. Of course, it could also mean water was pushed out of the top of the device during the run merely giving the appearance of 12 kW output when it is assumed all water is boiled. If that happened, the temperature would drop. You can see that easily. Well, yes of course, if 300 ml/s was indeed the flow rate. The thermal power applied would have to be above 1617 W to heat that flow to boiling point. It would be of interest to go back to the film and count the click rate. Also useful to know what the maximum flow rate for the pump would be at that click rate. My impression was that 7 liters per hour was the pump rate, but my memory is admittedly very bad. At 7 liters an hour the water heating power is 630.6 watts, not too far from 400 watts input, so it becomes very important to establish with great certainty just what the electric power input was. If all is as you say was presented, then it is true it would be possible to detect momentary heat after death by the flue temperature. However, there seems to be some doubt as to the credibility of any numbers that are from the demos. The good thing about the first *public* test is that there were multiple scientists present. Still, calorimetry was not performed, and no energy balance determined, so nothing clear was determined by the demo. For that matter, if you cannot tell when there is steam by the temperature, the method would not work at any time, under any conditions, whether there is input power or not. The data would be meaningless; all of the results would be in error. This error would have been revealed during the 18-hour flowing water test, as Rossi and I have pointed out many times. Well, if there is no continued inspection of what is going out of the hose then it is not known what the thermal power is at many moments, and certainly an overall energy balance can not be taken. The input power is 80 to 400 W, which is small fraction of the output power, so cutting it off entirely has little effect on the total output. Obviously, reducing overall output from ~12 kW to ~11.2 kW will not stop the thing from boiling! Yes obviously true, *provided* the thermal output really was 12000 W, and provided the input flow really was 5 ml/sec. A calorimetric error mistaking 400 W for 12,000 W is out of the question. The worst flow calorimeter imaginable would not produce such a large error. Well, no calorimetry was actually done on the output. The problem is it is easy to mistake 1700 W for 12000 W with the methodology used. We have good reason to think Rossi has misstated flow on at least one occasion. There is some evidence he has tinker with controls during at least one demo. There are active controllers in the box. Who knows what kind of input power was actually applied at any specific minute? I am curious as to how the steam was observed if the hose was in the drain. If the steam stopped then water pouring out of the hose should have followed immediately if the 5 ml/s pump rate was maintained. If the steam was stopped, the temperature would drop immediately. There is a constant flow of water into the cell. It takes little time to replace all of the water with cold water. Yes, and thus water should almost immediately come out of the hose, as I said. That was *my* point. If the only source of heat was electricity, two things are certain: 1. It could not be 12 kW in the first place. The wire would melt. You can't possibly conduct that much electricity over an ordinary wire. This is false. If the flow is 3 ml/s then any input power above 1617 W will provide a flue temperature at boiling point. If no one measures the output of the hose, but rather assumes dry steam, then the apparent power is over 12000 W. 2. Boiling would stop within seconds, and the temperature would drop. If there is no steam then boiling *has* stopped. As soon as the temperature has decayed to the point there is no steam water should be coming out of the hose. THis should have been observed if there really was an observation of the heat after death steam. It is
Re: [Vo]:Corrections to "heat after death" calculations
Joe Catania wrote: Until I see the data you refer to all I can say is its seems like more of a guess. Okay. Ask Krivit to show it to you again. It was there before. It seems like a pretty good guess to me, since they told me they worked with the gadget for a month before demonstrating it. They did not say "we worked with one gadget for four weeks and then arbitrarily decided to use another one on the day of the test." I do not have your vivid imagination so I am not good at guessing or coming up with mind-boggling scenarios such as this, or people doing flow calorimetry without a flow. Why dosen't Rossi verify steam quality. He does. He uses a Delta Ohm RH meter or another brand. Experts tell me this is a perfectly good method. Self-appointed experts here say it is not, but all the real world experts I've heard from are confident that Rossi's steam is dry. They say it has to be, given the geometry of his device, the temperatures and the pressure (1 atm). I do not know enough to judge but I tend to assume that experts know what they're talking about, and I'm sure that this method cannot be as wrong as people here imagine it might be. I'm also sure that everyone who does flow calorimetry does use a flow of water. Hence the name: "flow calorimetry." But that's just me. I take things literally. When someone says "I drove from Atlanta to Washington" I assume they meant they have a car with four wheels and inflated tires, rather than a magic carpet or a herd of buffalo attached to skateboards. I suppose I am making a lot of assumptions and you could be right that people do flow calorimetry without a flow or that the machine is several hundred degrees and incandescent but no one has noticed and the insulating tape did not burn because it is special ordered from the Russian Space Agency for patching up reentry vehicle nosecones. Anything is possible and life is full of mysteries, but alas most of the mysteries escape my attention because -- as I said -- I have prosaic imagination, I read the manual, and I assume that people mean what they say. A simple steam velocity would verify steam quality yet I see no attempt being made to do so. And how does one measure steam velocity, simply? Or in a complicated way, for that matter? You should get together with Lomax on this. With your imagination I am sure you can suggest a method. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
Until I see the data you refer to all I can say is its seems like more of a guess. Why dosen't Rossi verify syeam quality. A simple steam velocity would verify steam quality yet I see no attemp being made to do so. An error in flow rate has already been noted and there is no way the steam could be dry. Coupled with the fact that Levi has attested to 50% of steam being condensed in the hose and we have that power is probably not even 1/4 of what Rossi says. How can steam be condensing at 50% rate in the hose when the heat transfer through the hose isn't sufficient. This makes me nervous and suspicious of the calorimetry. Rosii's cavalier dismissal of important issues like steam quality. His insistance that relative humidity will measure it, his refusal to measure quality, and a seeming lack of knowledge of the enthalpy of hydride formation and thernal inertia are screaming for independent calorimetry (preferably not flow calorimetry). Even with 50% of steam condensed in the hose the velocity of steam from the hose should be noticeably higher than is observed. I must conclude that he has nothing. - Original Message - From: "Jed Rothwell" To: Sent: Tuesday, August 30, 2011 4:12 PM Subject: Re: [Vo]:Corrections to "heat after death" calculations Horace Heffner wrote: As far as I know, this is the only eCat that Levi et al. tested in December, which is when the event occurred. The flow rate was typically ~300 ml/min I believe. Are you sure about that flow rate being present in the heat after death observation? How else could it work? It would run out of water. Very little fits into the cell. You cannot do flow calorimetry without a flow. It would be like trying to do it without measuring the temperature. It does correspond roughly to 12 kW boiling power. Of course, it could also mean water was pushed out of the top of the device during the run merely giving the appearance of 12 kW output when it is assumed all water is boiled. If that happened, the temperature would drop. You can see that easily. For that matter, if you cannot tell when there is steam by the temperature, the method would not work at any time, under any conditions, whether there is input power or not. The data would be meaningless; all of the results would be in error. This error would have been revealed during the 18-hour flowing water test, as Rossi and I have pointed out many times. The input power is 80 to 400 W, which is small fraction of the output power, so cutting it off entirely has little effect on the total output. Obviously, reducing overall output from ~12 kW to ~11.2 kW will not stop the thing from boiling! A calorimetric error mistaking 400 W for 12,000 W is out of the question. The worst flow calorimeter imaginable would not produce such a large error. I am curious as to how the steam was observed if the hose was in the drain. If the steam stopped then water pouring out of the hose should have followed immediately if the 5 ml/s pump rate was maintained. If the steam was stopped, the temperature would drop immediately. There is a constant flow of water into the cell. It takes little time to replace all of the water with cold water. If the only source of heat was electricity, two things are certain: 1. It could not be 12 kW in the first place. The wire would melt. You can't possibly conduct that much electricity over an ordinary wire. 2. Boiling would stop within seconds, and the temperature would drop. It is notable that in the right conditions "steam" will be seen coming off a hot bowl of soup, or even a cool river. You can't actually see steam of course, only condensation. Too bad there is no video of this event. You cannot tell much about steam by looking at a photo or video. You cannot discern the quality of the steam. Lomax claimed here that he can determine the velocity of the steam by looking, but he did not describe his method. I do not think that is possible. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
Horace Heffner wrote: You are providing the input data so you should know which test you are talking about. Jed says the first test. No, I said it was the device used in the first public test. The large eCat, shown in many photos. As far as I know this was the only eCat they used in December, January and February. The event occurred in December. Levi et al. spent a lot of time in December and January testing the machine before they did a public test. Getting ready for the test. One of the things they did was run without input for 15 min. (heat after death mode). I assume it was about the same power output as the January and February tests because they say performance is stable and predictable with this machine. It works the same way every time. Focardi emphasize that in his video interview with Krivit. It is not always stable. Input power seems to vary for some reason, and during the 18-hour test it went bonkers at first, producing a great deal of heat and frightening Rossi, according to Levi in his comments in the video interview with Levi. I assume it was the same device because they never mentioned having more than one, and why would you spend a month getting ready to do a test with one machine and then do the test with another one? The graph from the heat after death event is shown in the video #3 (I think it is). Unfortunately, it appears Krivit has withdrawn this one from public access. He does that kind of thing. It is annoying. Anyway, this is not terribly important. There is no question that gas loaded devices work in heat after death mode. It is ridiculous to doubt that since most of them are inherently in that mode all the time. See Arata's cells, for example. The mystery is not that it runs without power, but rather why any heating power is needed after the critical operating temperature is reached. I have no idea why it needs input power, and how that input power controls the reaction (assuming it does). Even though I have no idea why it works this way, it does not surprise me. Temperature, heat flux and temperature differences have often been shown to be critical to cold fusion effects. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
Horace Heffner wrote: As far as I know, this is the only eCat that Levi et al. tested in December, which is when the event occurred. The flow rate was typically ~300 ml/min I believe. Are you sure about that flow rate being present in the heat after death observation? How else could it work? It would run out of water. Very little fits into the cell. You cannot do flow calorimetry without a flow. It would be like trying to do it without measuring the temperature. It does correspond roughly to 12 kW boiling power. Of course, it could also mean water was pushed out of the top of the device during the run merely giving the appearance of 12 kW output when it is assumed all water is boiled. If that happened, the temperature would drop. You can see that easily. For that matter, if you cannot tell when there is steam by the temperature, the method would not work at any time, under any conditions, whether there is input power or not. The data would be meaningless; all of the results would be in error. This error would have been revealed during the 18-hour flowing water test, as Rossi and I have pointed out many times. The input power is 80 to 400 W, which is small fraction of the output power, so cutting it off entirely has little effect on the total output. Obviously, reducing overall output from ~12 kW to ~11.2 kW will not stop the thing from boiling! A calorimetric error mistaking 400 W for 12,000 W is out of the question. The worst flow calorimeter imaginable would not produce such a large error. I am curious as to how the steam was observed if the hose was in the drain. If the steam stopped then water pouring out of the hose should have followed immediately if the 5 ml/s pump rate was maintained. If the steam was stopped, the temperature would drop immediately. There is a constant flow of water into the cell. It takes little time to replace all of the water with cold water. If the only source of heat was electricity, two things are certain: 1. It could not be 12 kW in the first place. The wire would melt. You can't possibly conduct that much electricity over an ordinary wire. 2. Boiling would stop within seconds, and the temperature would drop. It is notable that in the right conditions "steam" will be seen coming off a hot bowl of soup, or even a cool river. You can't actually see steam of course, only condensation. Too bad there is no video of this event. You cannot tell much about steam by looking at a photo or video. You cannot discern the quality of the steam. Lomax claimed here that he can determine the velocity of the steam by looking, but he did not describe his method. I do not think that is possible. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 30, 2011, at 6:02 AM, Jouni Valkonen wrote: Horace wrote: «If you provide numbers for Mass, Thermal Power (before shutoff), Inlet Temp., Mass Temp., and Inlet Flow then I will then be happy to provide the corresponding data.» Perhaps 500 grams was too small value. I re-estimated that if the outer volume of core chamber is 50cc, then perhaps 2kg is maximum value for thermal mass in the core. But we know very few details. The copper tubing does not contain much thermal mass, as it is in contact with steam/water, thus temperature is less than 100°C. Anyways my estimationes. The mass of the core (for storing thermal energy) 500g-2kg. Max core temperature 1000°C Thermal power 2-3kW Inlet: 25°C / 5kg/h Steam overpressure: 3.2 kPa. Notice that if core temperature is high (such as during the power surge in 18h experiment), then only small portion of the core is in that temperature, but there is temperature gradient. However it is unlikely that core temperature is high during normal operation. Unfortunately we (or I?) do not have any data what is the core temperature in normal operation. But it is odd that we discuss this because all Rossi's reactors are currently selfsustaining indefinitely, because he can manage them adjusting hydrogen pressure and cooling water inflow rate. —Jouni Ps. I do not know what model of E-Cat we are talking about. Does we have pictures? Or is it just some mythical test what was seen by nobody. You are providing the input data so you should know which test you are talking about. Jed says the first test. In any case I provided some output based on your range of inputs: http://www.mtaonline.net/~hheffner/RossiThermal3.pdf Mode 1 was all at 0.83 gm/s, Mode 2 was at 1.94 gm/s. I added some data at 748 W and 1000 just to consider no nuclear heat options. Based on the input values a 15 minute decay is only feasible in the low water flow conditions. It is also feasible that 748 W input, similar to Krivit's video test, could produce 15 minutes of steam at 2 kg mass. However, this might imply too high a thermal resistance to be feasible. It would be interesting to run Jed's numbers, if there is a reasonable thermal mass number available. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
The imagination is all yours. If you read K&E they essentially seem to imply it, which I found rather disturbing. I can't make heads or tails of their report as written. - Original Message - From: "Jed Rothwell" To: Sent: Tuesday, August 30, 2011 3:40 PM Subject: Re: [Vo]:Corrections to "heat after death" calculations Joe Catania wrote: Oops! I assumed that there actually was outflow water at this stage but there does not seem to be evidence of that. You have an extraordinary imagination, thinking that people run flow calorimeters without a flow. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 30, 2011, at 6:18 AM, Jed Rothwell wrote: As far as I know, this is the only eCat that Levi et al. tested in December, which is when the event occurred. The flow rate was typically ~300 ml/min I believe. Are you sure about that flow rate being present in the heat after death observation? It does correspond roughly to 12 kW boiling power. Of course, it could also mean water was pushed out of the top of the device during the run merely giving the appearance of 12 kW output when it is assumed all water is boiled. I am curious as to how the steam was observed if the hose was in the drain. If the steam stopped then water pouring out of the hose should have followed immediately if the 5 ml/s pump rate was maintained. It is notable that in the right conditions "steam" will be seen coming off a hot bowl of soup, or even a cool river. You can't actually see steam of course, only condensation. Too bad there is no video of this event. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
Joe Catania wrote: Oops! I assumed that there actually was outflow water at this stage but there does not seem to be evidence of that. You have an extraordinary imagination, thinking that people run flow calorimeters without a flow. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
Its not my reasoning but the nature of the beast which I assumed everyone was familiar with and rightly so. Not only have I been the subject of ad hominems for a presentaion that is obvious by the very nature of what is being discussed, there have been false allegations and insults to nature. This doesn't matter as its is easy to see that even during powered operation of E-Cat thermal inertia is what controls heat transfer through the metal surface to the water - Original Message - From: Mark Iverson-ZeroPoint To: vortex-l@eskimo.com Sent: Tuesday, August 30, 2011 12:17 PM Subject: RE: [Vo]:Corrections to "heat after death" calculations Perhaps someone can provide specific reference to a statement by one of the participants in the E-Cat demos that the water flow was maintained during the heat-after-death tests. Joe Catania: Your post below is what you should have started with: 1) It contains a detailed explanation of your reasoning, which gives us enough information to understand the basis of your argument. 2) There are no personal attacks in it. We are talking two completely different scenarios for the heat-after-death test. You are assuming that the water flow was turned OFF, and I think most of us are assuming that the flow was unchanged from the power-on operation. I think the whole point of the 'heat-after-death' test is that water flow is still going on during that part of the test. -M From: Joe Catania [mailto:zrosumg...@aol.com] Sent: Tuesday, August 30, 2011 8:08 AM To: vortex-l@eskimo.com Subject: Re: [Vo]:Corrections to "heat after death" calculations Until we know whether Levi turned the flow off along with the heater we will not know how to calculate this for sure. I also have suspicion that the metal may get hotter than 550C according to several staments by Rossi and I believe Defkalion. If the flow is turned off or is only 1g/s it looks like 15 min can easily be justified. Also even if it 2g/sec steam can still be produced since metal surfaces will still be at 100C. If there is steam wetness it will appear that more steam is being produced than really is. But as long as there's heat transfer from metal at >100C to 100C water there will be some steam produced (maybe not as much as at power off but some). I took Levi to mean some steam was produced for 15 min and I accepted he used his judgment to determine when that ended. So its very possible that all he may have been observing was thermal inertia. On the other hand, if there's something else going on- some other heat source, as looks to be evident in K&E demo then the thermal inertia source may coincide with the anomalous source. For instance if the hydriding reaction is what is causing the increased slope to temperature rise in the K&E graph you might get ~1MJ of hydride caused heat being released (~200,000J/mol and ~1 mol/9g). The reason I wanted to be understood about the thermal inertia is that good calorimetry will need to take it into account. I believe it has already been posted to Vortex that time history is important- this is roughly the same. It will be difficult for us to determine the exact goings-on in Rossi's device even armed with this since we don't know if he keeps the flow on (I'm guessing he does), what the rate is (Rizzi may be right about it being at least halved), the steam is not thoroughly dry, and we don't react have details of the reactor construction. I have to say that from the K&E report it seems Rossi might not even be aware that the hydriding that occurs in metals when packing hydrogen into the lattice is not the chemical hydriding that K&E quote the enthalpy to but the physical hydriding which releases much more energy. So now its not clear if that was detected at all. If Rossi understood physical hydriding and merely hired Levi as an independent, University associated researcher to try to detect the "self-sustaining nuclear" reaction that would be observed upon cutting the power he may have baited Levi and hinted that there might be such a phenomenon relying on Levi's innocence to report continued steam production. From watching the interviews with Levi it seems he is not aware of thermal inertia or physical hydriding that contribute to this "extra steam" and may have been forced to attribute it to a successful cold fusion demo.
RE: [Vo]:Corrections to "heat after death" calculations
Perhaps someone can provide specific reference to a statement by one of the participants in the E-Cat demos that the water flow was maintained during the heat-after-death tests. Joe Catania: Your post below is what you should have started with: 1) It contains a detailed explanation of your reasoning, which gives us enough information to understand the basis of your argument. 2) There are no personal attacks in it. We are talking two completely different scenarios for the heat-after-death test. You are assuming that the water flow was turned OFF, and I think most of us are assuming that the flow was unchanged from the power-on operation. I think the whole point of the 'heat-after-death' test is that water flow is still going on during that part of the test. -M From: Joe Catania [mailto:zrosumg...@aol.com] Sent: Tuesday, August 30, 2011 8:08 AM To: vortex-l@eskimo.com Subject: Re: [Vo]:Corrections to "heat after death" calculations Until we know whether Levi turned the flow off along with the heater we will not know how to calculate this for sure. I also have suspicion that the metal may get hotter than 550C according to several staments by Rossi and I believe Defkalion. If the flow is turned off or is only 1g/s it looks like 15 min can easily be justified. Also even if it 2g/sec steam can still be produced since metal surfaces will still be at 100C. If there is steam wetness it will appear that more steam is being produced than really is. But as long as there's heat transfer from metal at >100C to 100C water there will be some steam produced (maybe not as much as at power off but some). I took Levi to mean some steam was produced for 15 min and I accepted he used his judgment to determine when that ended. So its very possible that all he may have been observing was thermal inertia. On the other hand, if there's something else going on- some other heat source, as looks to be evident in K&E demo then the thermal inertia source may coincide with the anomalous source. For instance if the hydriding reaction is what is causing the increased slope to temperature rise in the K&E graph you might get ~1MJ of hydride caused heat being released (~200,000J/mol and ~1 mol/9g). The reason I wanted to be understood about the thermal inertia is that good calorimetry will need to take it into account. I believe it has already been posted to Vortex that time history is important- this is roughly the same. It will be difficult for us to determine the exact goings-on in Rossi's device even armed with this since we don't know if he keeps the flow on (I'm guessing he does), what the rate is (Rizzi may be right about it being at least halved), the steam is not thoroughly dry, and we don't react have details of the reactor construction. I have to say that from the K&E report it seems Rossi might not even be aware that the hydriding that occurs in metals when packing hydrogen into the lattice is not the chemical hydriding that K&E quote the enthalpy to but the physical hydriding which releases much more energy. So now its not clear if that was detected at all. If Rossi understood physical hydriding and merely hired Levi as an independent, University associated researcher to try to detect the "self-sustaining nuclear" reaction that would be observed upon cutting the power he may have baited Levi and hinted that there might be such a phenomenon relying on Levi's innocence to report continued steam production. From watching the interviews with Levi it seems he is not aware of thermal inertia or physical hydriding that contribute to this "extra steam" and may have been forced to attribute it to a successful cold fusion demo.
Re: [Vo]:Corrections to "heat after death" calculations
Oops! I assumed that there actually was outflow water at this stage but there does not seem to be evidence of that. Perhaps the water is retained in the E-Cat and the temperaure is monitored. In any case it seems the E-Cat is not producing steam yet. There would also be heat stored in E-Cat water although this does not contribute directly to steam. - Original Message - From: "Joe Catania" To: Sent: Tuesday, August 30, 2011 11:20 AM Subject: Re: [Vo]:Corrections to "heat after death" calculations I belive you are saying the heating mantle alone is 500g. Also the water never exceeds 100C so why should the insulation? I assume Rossi construction does not allow metal potentially hot enough to destroy insulation to contact insulation. If he saw that happen he would rework the insulation. Also the temperature of metal would decline as we move from the core. For instance in K&E, figure 6 graph, for over 10 minutes (600 sec) the 300W heater runs producing ~2MW of heat at least half of which are not measured as flowing out in outlet water thus establishing that at least 1MW was stored in the metal in this way. The hdriding reaction which I postulate as the reason for the increased slope at 60C will add even more. - Original Message - From: "Jouni Valkonen" To: Sent: Tuesday, August 30, 2011 8:52 AM Subject: Re: [Vo]:Corrections to "heat after death" calculations 2011/8/30 Horace Heffner : Note especially in RossiThermal2.pdf, in Mode 2, that a mass of between 5 and 10 kg, at initial Mass Temp. of 300*C, provides a 15 minute thermal decline curve with no nuclear energy involved. Good thinking, expect that the total metal weight of the E-Cat is ca. 5kg. Perhaps quite bit less. And we still need to worry that insulation material cannot withstand high temperatures and also the parts of E-Cat that are in direct contact with water cannot exceed 100°C. Therefore total mass that can store thermal energy (i.e. heating element or the core) cannot weight more than 500 grams. Therefore I suggest you slight revision of calculations. –Jouni
Re: [Vo]:Corrections to "heat after death" calculations
I belive you are saying the heating mantle alone is 500g. Also the water never exceeds 100C so why should the insulation? I assume Rossi construction does not allow metal potentially hot enough to destroy insulation to contact insulation. If he saw that happen he would rework the insulation. Also the temperature of metal would decline as we move from the core. For instance in K&E, figure 6 graph, for over 10 minutes (600 sec) the 300W heater runs producing ~2MW of heat at least half of which are not measured as flowing out in outlet water thus establishing that at least 1MW was stored in the metal in this way. The hdriding reaction which I postulate as the reason for the increased slope at 60C will add even more. - Original Message - From: "Jouni Valkonen" To: Sent: Tuesday, August 30, 2011 8:52 AM Subject: Re: [Vo]:Corrections to "heat after death" calculations 2011/8/30 Horace Heffner : Note especially in RossiThermal2.pdf, in Mode 2, that a mass of between 5 and 10 kg, at initial Mass Temp. of 300*C, provides a 15 minute thermal decline curve with no nuclear energy involved. Good thinking, expect that the total metal weight of the E-Cat is ca. 5kg. Perhaps quite bit less. And we still need to worry that insulation material cannot withstand high temperatures and also the parts of E-Cat that are in direct contact with water cannot exceed 100°C. Therefore total mass that can store thermal energy (i.e. heating element or the core) cannot weight more than 500 grams. Therefore I suggest you slight revision of calculations. –Jouni
RE: [Vo]:Corrections to "heat after death" calculations
Yes, Jed, thanks for pointing that out, but, I was incorporating into my figures (and didn't write it down) the additional energy going into the heat of vaporization that would be necessary for the E-Cat to continue to produce steam as Joe is claiming. after the power is turned off. -M From: Jed Rothwell [mailto:jedrothw...@gmail.com] Sent: Tuesday, August 30, 2011 7:00 AM To: vortex-l@eskimo.com Subject: Re: [Vo]:Corrections to "heat after death" calculations Mark Iverson-ZeroPoint wrote: Compare the heat capacity of any metal with water and you will see that water can store 100 to 1000 times more heat per mass than any metal. It is a factor of 10 for most metals, per unit of mass. Not 100 or 1000. The eCat is mostly steel which is 0.49 kJ/kg K. Water is 4.19 kJ/kg K. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
Until we know whether Levi turned the flow off along with the heater we will not know how to calculate this for sure. I also have suspicion that the metal may get hotter than 550C according to several staments by Rossi and I believe Defkalion. If the flow is turned off or is only 1g/s it looks like 15 min can easily be justified. Also even if it 2g/sec steam can still be produced since metal surfaces will still be at 100C. If there is steam wetness it will appear that more steam is being produced than really is. But as long as there's heat transfer from metal at >100C to 100C water there will be some steam produced (maybe not as much as at power off but some). I took Levi to mean some steam was produced for 15 min and I accepted he used his judgment to determine when that ended. So its very possible that all he may have been observing was thermal inertia. On the other hand, if there's something else going on- some other heat source, as looks to be evident in K&E demo then the thermal inertia source may coincide with the anomalous source. For instance if the hydriding reaction is what is causing the increased slope to temperature rise in the K&E graph you might get ~1MJ of hydride caused heat being released (~200,000J/mol and ~1 mol/9g). The reason I wanted to be understood about the thermal inertia is that good calorimetry will need to take it into account. I believe it has already been posted to Vortex that time history is important- this is roughly the same. It will be difficult for us to determine the exact goings-on in Rossi's device even armed with this since we don't know if he keeps the flow on (I'm guessing he does), what the rate is (Rizzi may be right about it being at least halved), the steam is not thoroughly dry, and we don't react have details of the reactor construction. I have to say that from the K&E report it seems Rossi might not even be aware that the hydriding that occurs in metals when packing hydrogen into the lattice is not the chemical hydriding that K&E quote the enthalpy to but the physical hydriding which releases much more energy. So now its not clear if that was detected at all. If Rossi understood physical hydriding and merely hired Levi as an independent, University associated researcher to try to detect the "self-sustaining nuclear" reaction that would be observed upon cutting the power he may have baited Levi and hinted that there might be such a phenomenon relying on Levi's innocence to report continued steam production. From watching the interviews with Levi it seems he is not aware of thermal inertia or physical hydriding that contribute to this "extra steam" and may have been forced to attribute it to a successful cold fusion demo. - Original Message - From: Horace Heffner To: vortex-l@eskimo.com Sent: Tuesday, August 30, 2011 8:36 AM Subject: Re: [Vo]:Corrections to "heat after death" calculations Hi Joe, I found an error in my calculation of the critical temperature, the temperature at which all energy merely goes into heating the water to 100°C, with none left to produce steam. You will probably like the improvements. I have reposted: http://www.mtaonline.net/~hheffner/RossiThermal.pdf http://www.mtaonline.net/~hheffner/RossiThermal2.pdf http://www.mtaonline.net/~hheffner/DecayCurve1.pdf The old formula for Critical Temp. was: (Critical Temp.) = (Thermal Resistance) * (Water Heating) +100 The current formula for Critical Temp. is: (Critical Temp.) = (Water Heating)*(Thermal Resistance)+(Inlet Temp.) I also added a "Thermal Power" column to the decay curve data to show the thermal power applied to the water as the temperature decays. Note that at the critical temperature Tcrit in the decay curve the power applied to the water is equal to that required to heat it to 100°C, namely 268.3 W. This is also the critical time 23.73 minutes. Note especially in RossiThermal2.pdf, in Mode 2, that a mass of between 5 and 10 kg, at initial Mass Temp. of 300*C, provides a 15 minute thermal decline curve with no nuclear energy involved. However, the flow rate used is that suggested by Mattia Rizzi, 3 liters per second, not 7 liters per second. Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
Terry Blanton wrote: I concur, Nick. These are violations of forum rules. Perhaps, but let us not be too thin-skinned. Or politically correct. Let's not ban anyone. If someone irritates you, just add the name to your own auto-delete list. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
You have no idea what I'm talking about. If I say water flow is not what you need to get on square one with this then its true. Your posts are completely of topic and show a total lack of competence. I never said there was no water flow. I said it is not relevant. One does grasp therma inertia by understanding there is a water flow. Also it is not certain that Levi leaves the flow on. In either case your calculations have prooven to be incorrect. As this has been stated many times you must accept that your are being ignoramus. The heat capacity of water is irrelevant. The heat capacity of water is nowhere near 100 to 1000 times a metal. In fact on a volume basis they are about equal. The time of production of steam has to do with the time it takes the hot metals temperature to decay to 100C. With good insulation and no water flow (but allowing steam flow) its impossible for the temperature of the metal to decay beow 100C. You need to understand that it will produce steam for on the order of 15 minutes not 1 minute. Water flow will not drastically change the situation. Remember this is an order of mag calculation. There are no practical measurements available. Any numbers you suggest are totally biased. Also the calculations you believers suggest do not jibe with length of steam production using those numbers. You are all running away from the truth. There is little point in this since any anomalous heat has already been ascribed to hydride formation. - Original Message - From: Mark Iverson-ZeroPoint To: vortex-l@eskimo.com Sent: Tuesday, August 30, 2011 3:30 AM Subject: RE: [Vo]:Corrections to "heat after death" calculations Joe: Water flow is most certainly pertinent to any energy calculations concerning the E-Cat. Your statement that "we aren't discussing water flow" seems to indicate that either we are talking about two completely different calculations or you have no idea what you're talking about. All demonstrations of the E-Cat have had a high quality pump pumping water thru the E-Cat - where do you think the steam comes from? There is some disagreement as to the 'claimed' flowrates which might be in conflict with the apparent flowrate based on the number of 'strokes' per minute, but no one has ever claimed that there is no water flow thru the E-Cat. Given that and the fact that there are few substances that have a higher heat capacity than water, make me seriously question your understanding of the device and/or the physics involved here. Compare the heat capacity of any metal with water and you will see that water can store 100 to 1000 times more heat per mass than any metal. Since the mass of water in the E-Cat and the mass of the metal structure are at least similar, how long the E-Cat could continue to produce steam once the power was turned off is MOST CERTAINLY dependent on the water flow and the temperature of that water. probably much more so than the metal structure. PS: Horace was probably doing these kinds of energy calculations when you were still pissing in your diapers, so I'd suggest that you calm down and stop insisting that all others are wrong and you are right. If you want to gain any credibility on this discussion list then I'd suggest that you stick to facts and figures and calculations to support your points, and stop the personal attacks. -Mark From: Horace Heffner [mailto:hheff...@mtaonline.net] Sent: Monday, August 29, 2011 7:59 PM To: vortex-l@eskimo.com Subject: Re: [Vo]:Corrections to "heat after death" calculations On Aug 29, 2011, at 5:14 PM, Joe Catania wrote: [snip ad hominem and continued mistakes] We aren't discussing water flow. [snip ad hominem and continued mistakes] Of course we are discussing water flow. The device had water pumped into it at a constant rate. If you chose to ignore that then you chose to ignore reality. Looking back, I do see that you simply chose to ignore reality in your discussion with Jed. Joe On Aug 26, 2011, at 5:37 AM, Jed Rothwell wrote: Joe Catania wrote: No, its not out of the question at all. Since we don't know the flow rate of water (whether its flowing or not) and since it isn't particularly relevant I neglect it. The water is always flowing. This is a flow calorimeter. It is completely unrealistic to suppose that you can boil water in device this size, save up heat in metal, and then continue boiling at any observable rate for more than a few seconds after the power goes off. That is out of the question. The temperature of the metal would be far above the melting point. The metal would be incandescent. - Jed Instead of talking imaginary things I suggest a quantitative analysis to see what kinds of
Re: [Vo]:Corrections to "heat after death" calculations
Water flow is irrelevant to what I'm discussing. It is not a certainty that Levi keeps the flow on during his power out. Clearly your grasp of physics is limited. Insulting mother nature won't clinch proof of CF. If the best you have is a dream you may as well join the rational thinkers. - Original Message - From: Horace Heffner To: vortex-l@eskimo.com Sent: Monday, August 29, 2011 10:59 PM Subject: Re: [Vo]:Corrections to "heat after death" calculations On Aug 29, 2011, at 5:14 PM, Joe Catania wrote: [snip ad hominem and continued mistakes] We aren't discussing water flow. [snip ad hominem and continued mistakes] Of course we are discussing water flow. The device had water pumped into it at a constant rate. If you chose to ignore that then you chose to ignore reality. Looking back, I do see that you simply chose to ignore reality in your discussion with Jed. Joe On Aug 26, 2011, at 5:37 AM, Jed Rothwell wrote: Joe Catania wrote: No, its not out of the question at all. Since we don't know the flow rate of water (whether its flowing or not) and since it isn't particularly relevant I neglect it. The water is always flowing. This is a flow calorimeter. It is completely unrealistic to suppose that you can boil water in device this size, save up heat in metal, and then continue boiling at any observable rate for more than a few seconds after the power goes off. That is out of the question. The temperature of the metal would be far above the melting point. The metal would be incandescent. - Jed Instead of talking imaginary things I suggest a quantitative analysis to see what kinds of numbers make sense. I have taken no position on the reality of input t this point except to say it looks to me that 1 MJ of stored energy seems to be too high to be real. Still, I ran some numbers that support that proposition. Applying logic to a proposition is *not* accepting the proposition as true. The statement: If x then y is not the same as: x is true. It merely provides the opportunity to examine y to see if it is feasibly true. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
Jouni Valkonen wrote: Ps. I do not know what model of E-Cat we are talking about. Does we have pictures? Or is it just some mythical test what was seen by nobody. The 15 minute heat-after-death event was with the large eCat used in the January and February tests. This produces 12 kW to 16 kW output (depending on how you measure it) with about 400 W input. As far as I know, this is the only eCat that Levi et al. tested in December, which is when the event occurred. The flow rate was typically ~300 ml/min I believe. It is not mythical. Levi described it in NyTeknik I think. This is not a bit surprising. Nearly all cold fusion reactions will continue without input power. There is no one-for-one ratio or direct correspondence between input power and output power. The effect is not some sort of conversion or amplification. Input power with electrolysis is needed to form the NAE and keep it from dissipating (degassing), but dissipation happens slowly so when the heat is robust, there is plenty of time after you turn off electrolysis before the heat starts to fade. I do not know what the role of the input power is with the Rossi device, but clearly there is no one-for-one correspondence or fixed ratio. When you turn off input power, output is not likely to fade. On the contrary, the cell is likely to heat up and perhaps go out of control and explode according to Rossi. I expect he is telling the truth about that. It does not surprise me. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
Horace wrote: «If you provide numbers for Mass, Thermal Power (before shutoff), Inlet Temp., Mass Temp., and Inlet Flow then I will then be happy to provide the corresponding data.» Perhaps 500 grams was too small value. I re-estimated that if the outer volume of core chamber is 50cc, then perhaps 2kg is maximum value for thermal mass in the core. But we know very few details. The copper tubing does not contain much thermal mass, as it is in contact with steam/water, thus temperature is less than 100°C. Anyways my estimationes. The mass of the core (for storing thermal energy) 500g-2kg. Max core temperature 1000°C Thermal power 2-3kW Inlet: 25°C / 5kg/h Steam overpressure: 3.2 kPa. Notice that if core temperature is high (such as during the power surge in 18h experiment), then only small portion of the core is in that temperature, but there is temperature gradient. However it is unlikely that core temperature is high during normal operation. Unfortunately we (or I?) do not have any data what is the core temperature in normal operation. But it is odd that we discuss this because all Rossi's reactors are currently selfsustaining indefinitely, because he can manage them adjusting hydrogen pressure and cooling water inflow rate. —Jouni Ps. I do not know what model of E-Cat we are talking about. Does we have pictures? Or is it just some mythical test what was seen by nobody.
Re: [Vo]:Corrections to "heat after death" calculations
Mark Iverson-ZeroPoint wrote: Compare the heat capacity of any metal with water and you will see that water can store 100 to 1000 times more heat per mass than any metal. It is a factor of 10 for most metals, per unit of mass. Not 100 or 1000. The eCat is mostly steel which is 0.49 kJ/kg K. Water is 4.19 kJ/kg K. - Jed
Re: [Vo]:Corrections to "heat after death" calculations
I concur, Nick. These are violations of forum rules. Amazing how we can go for years on Vortex with no bannings; then, a controversial issue comes along and we have to ban those children who cannot act like human beings. I think Catania will be the third Rossi fatality. :) T On Tue, Aug 30, 2011 at 2:43 AM, Nick Palmer wrote: > I think Catania needs to be banned.. > > Talking about Horace he wrote "You just don't have the patience, are > incompetent or are plain ignorant" and "You're nuts ". > > Pay attention to this, Catania. Both Horace and Jed, in different ways, are > mental giants. You are a midget and a very rude incorrigible one too. > > Nick Palmer > > On the side of the Planet - and the people - because they're worth it > > Blogspot - Sustainability and stuff according to Nick Palmer > http://nickpalmer.blogspot.com >
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 30, 2011, at 4:52 AM, Jouni Valkonen wrote: 2011/8/30 Horace Heffner : Note especially in RossiThermal2.pdf, in Mode 2, that a mass of between 5 and 10 kg, at initial Mass Temp. of 300*C, provides a 15 minute thermal decline curve with no nuclear energy involved. Good thinking, expect that the total metal weight of the E-Cat is ca. 5kg. Perhaps quite bit less. And we still need to worry that insulation material cannot withstand high temperatures and also the parts of E-Cat that are in direct contact with water cannot exceed 100°C. This demonstrates the importance of calculating the thermal resistance of the device, even in this simple model. The temperature of the surface adjacent to the water will be near the temperature of the water. A thermal differential, a gradient, exists between the catalyst surface and the water surface, or heater surface and water surface. The magnitude of the differential is dependent on the thermal resistance of the material. The main thermal mass can be extremely hot provided the thermal resistance is adequate. Of course a finite element analysis would be best, but my simple model hopefully provides much more insight into the problems involved than one can obtain from a non-quantitative discussion. One of the items clearly identified for discussion by my model is what reasonable values are for the effective thermal resistance of the device. If an assumed set of input data produces an impossible thermal resistance, then the input data can be rejected as self- inconsistent. Therefore total mass that can store thermal energy (i.e. heating element or the core) cannot weight more than 500 grams. On what do you base this claim? All the mass of the device is involved. Therefore I suggest you slight revision of calculations. –Jouni It appears you are suggesting a revision of the input data. If you provide numbers for Mass, Thermal Power (before shutoff), Inlet Temp., Mass Temp., and Inlet Flow then I will then be happy to provide the corresponding data. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
2011/8/30 Horace Heffner : > Note especially in RossiThermal2.pdf, in Mode 2, that a mass of between 5 > and 10 kg, at initial Mass Temp. of 300*C, provides a 15 minute thermal > decline curve with no nuclear energy involved. Good thinking, expect that the total metal weight of the E-Cat is ca. 5kg. Perhaps quite bit less. And we still need to worry that insulation material cannot withstand high temperatures and also the parts of E-Cat that are in direct contact with water cannot exceed 100°C. Therefore total mass that can store thermal energy (i.e. heating element or the core) cannot weight more than 500 grams. Therefore I suggest you slight revision of calculations. –Jouni
Re: [Vo]:Corrections to "heat after death" calculations
Hi Joe, I found an error in my calculation of the critical temperature, the temperature at which all energy merely goes into heating the water to 100°C, with none left to produce steam. You will probably like the improvements. I have reposted: http://www.mtaonline.net/~hheffner/RossiThermal.pdf http://www.mtaonline.net/~hheffner/RossiThermal2.pdf http://www.mtaonline.net/~hheffner/DecayCurve1.pdf The old formula for Critical Temp. was: (Critical Temp.) = (Thermal Resistance) * (Water Heating) +100 The current formula for Critical Temp. is: (Critical Temp.) = (Water Heating)*(Thermal Resistance)+(Inlet Temp.) I also added a "Thermal Power" column to the decay curve data to show the thermal power applied to the water as the temperature decays. Note that at the critical temperature Tcrit in the decay curve the power applied to the water is equal to that required to heat it to 100°C, namely 268.3 W. This is also the critical time 23.73 minutes. Note especially in RossiThermal2.pdf, in Mode 2, that a mass of between 5 and 10 kg, at initial Mass Temp. of 300*C, provides a 15 minute thermal decline curve with no nuclear energy involved. However, the flow rate used is that suggested by Mattia Rizzi, 3 liters per second, not 7 liters per second. Horace Heffner http://www.mtaonline.net/~hheffner/
RE: [Vo]:Corrections to "heat after death" calculations
Joe: Water flow is most certainly pertinent to any energy calculations concerning the E-Cat. Your statement that "we aren't discussing water flow" seems to indicate that either we are talking about two completely different calculations or you have no idea what you're talking about. All demonstrations of the E-Cat have had a high quality pump pumping water thru the E-Cat - where do you think the steam comes from? There is some disagreement as to the 'claimed' flowrates which might be in conflict with the apparent flowrate based on the number of 'strokes' per minute, but no one has ever claimed that there is no water flow thru the E-Cat. Given that and the fact that there are few substances that have a higher heat capacity than water, make me seriously question your understanding of the device and/or the physics involved here. Compare the heat capacity of any metal with water and you will see that water can store 100 to 1000 times more heat per mass than any metal. Since the mass of water in the E-Cat and the mass of the metal structure are at least similar, how long the E-Cat could continue to produce steam once the power was turned off is MOST CERTAINLY dependent on the water flow and the temperature of that water. probably much more so than the metal structure. PS: Horace was probably doing these kinds of energy calculations when you were still pissing in your diapers, so I'd suggest that you calm down and stop insisting that all others are wrong and you are right. If you want to gain any credibility on this discussion list then I'd suggest that you stick to facts and figures and calculations to support your points, and stop the personal attacks. -Mark From: Horace Heffner [mailto:hheff...@mtaonline.net] Sent: Monday, August 29, 2011 7:59 PM To: vortex-l@eskimo.com Subject: Re: [Vo]:Corrections to "heat after death" calculations On Aug 29, 2011, at 5:14 PM, Joe Catania wrote: [snip ad hominem and continued mistakes] We aren't discussing water flow. [snip ad hominem and continued mistakes] Of course we are discussing water flow. The device had water pumped into it at a constant rate. If you chose to ignore that then you chose to ignore reality. Looking back, I do see that you simply chose to ignore reality in your discussion with Jed. Joe On Aug 26, 2011, at 5:37 AM, Jed Rothwell wrote: Joe Catania wrote: No, its not out of the question at all. Since we don't know the flow rate of water (whether its flowing or not) and since it isn't particularly relevant I neglect it. The water is always flowing. This is a flow calorimeter. It is completely unrealistic to suppose that you can boil water in device this size, save up heat in metal, and then continue boiling at any observable rate for more than a few seconds after the power goes off. That is out of the question. The temperature of the metal would be far above the melting point. The metal would be incandescent. - Jed Instead of talking imaginary things I suggest a quantitative analysis to see what kinds of numbers make sense. I have taken no position on the reality of input t this point except to say it looks to me that 1 MJ of stored energy seems to be too high to be real. Still, I ran some numbers that support that proposition. Applying logic to a proposition is *not* accepting the proposition as true. The statement: If x then y is not the same as: x is true. It merely provides the opportunity to examine y to see if it is feasibly true. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
I think Catania needs to be banned.. Talking about Horace he wrote "You just don't have the patience, are incompetent or are plain ignorant" and "You're nuts ". Pay attention to this, Catania. Both Horace and Jed, in different ways, are mental giants. You are a midget and a very rude incorrigible one too. Nick Palmer On the side of the Planet - and the people - because they're worth it Blogspot - Sustainability and stuff according to Nick Palmer http://nickpalmer.blogspot.com
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 29, 2011, at 5:14 PM, Joe Catania wrote: [snip ad hominem and continued mistakes] We aren't discussing water flow. [snip ad hominem and continued mistakes] Of course we are discussing water flow. The device had water pumped into it at a constant rate. If you chose to ignore that then you chose to ignore reality. Looking back, I do see that you simply chose to ignore reality in your discussion with Jed. Joe On Aug 26, 2011, at 5:37 AM, Jed Rothwell wrote: Joe Catania wrote: No, its not out of the question at all. Since we don't know the flow rate of water (whether its flowing or not) and since it isn't particularly relevant I neglect it. The water is always flowing. This is a flow calorimeter. It is completely unrealistic to suppose that you can boil water in device this size, save up heat in metal, and then continue boiling at any observable rate for more than a few seconds after the power goes off. That is out of the question. The temperature of the metal would be far above the melting point. The metal would be incandescent. - Jed Instead of talking imaginary things I suggest a quantitative analysis to see what kinds of numbers make sense. I have taken no position on the reality of input t this point except to say it looks to me that 1 MJ of stored energy seems to be too high to be real. Still, I ran some numbers that support that proposition. Applying logic to a proposition is *not* accepting the proposition as true. The statement: If x then y is not the same as: x is true. It merely provides the opportunity to examine y to see if it is feasibly true. Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
In order to walk you must first crawl. If you can't understand what I written you will never make the required progress. Yes you can model what I'm talking about mathematically. You just don't have the patience, are incompetent or are plain ignorant. 1MJ is not a wild guess. Even if it was it would not be wrong. You are the one insisting on numbers for illustrative purposes. If you can't see a line then you aren't going to be able to see a line drawing. Yes you can simply subtract 1000 from one million as many times as you like. We aren't discussing water flow. There is 1MJ only and a certain amount of cooling. If we assume 1kW steady then we produce 1kW steam for 1000 seconds. It makes me laugh that you aren't able to see that esp. when you told me that 5kW steady was your assumption. You're calculation involving 1.11MJ is unacceptable. Now your telling me 1 MJ is ok? You're nuts. To say .5467MJ is not available to form steam is wishful thinking only. Nevertheless it does not mean steam will not be produced for 15 minutes. Since your result is in conflict with this it is wrong. You need to start again. A good place to begin is with a steady 1000J decrement from 1MJ per sec. If you can solve that you may be ready to proceed to non-steady cooling. - Original Message - From: Horace Heffner To: vortex-l@eskimo.com Sent: Monday, August 29, 2011 8:43 PM Subject: Re: [Vo]:Corrections to "heat after death" calculations On Aug 29, 2011, at 10:00 AM, Joe Catania wrote: Try to understand there is no way that the temperature can decay in only a few minutes. If you start with 1MJ and subtracted 1kJ/sec you'd get 1000sec. This is woefully wrong on two counts, (a) the 1 MJ number is a wild guess on your part and probably wrong, way too high, and (b) you can not simply subtract 1 kJ/sec until reaching zero, even if that is the thermal demand at some point. There is flowing water coming in at 23°C or thereabouts. The temperature required to warm that water up to 100°C is substantially above 100°C, as I have clearly shown: http://www.mail-archive.com/vortex-l%40eskimo.com/msg50831.html http://www.mtaonline.net/~hheffner/DecayCurve1.pdf For example, note in the above pdf, to which I have added a "Stored Energy" column, that even though the initial stored energy is 1.11 MJ, that steam generation stops when stored energy is 0.5467 MJ. All the 1.11 MJ is thus *not available* to generate steam. Note in: http://www.mtaonline.net/~hheffner/RossiThermal2.pdf Mode 3, line 3, that, given all the assumptions in that line, a minimum mass temperature of 307°C is required to heat the incoming water to 100°C. This is due to a need to be consistent with the Thermal Resistance that is required by the assumptions. This is in part what I mean when I say this kind of model can iron out internal inconsistencies in the choice of input parameters. Now understand that we don't stay at 1kJ, we decrease in accordance with a decline in temperature. Yes, I provided a thermal decline curve, and, for your convenience I added a column providing the the Thermal Energy of the mass by time: http://www.mtaonline.net/~hheffner/DecayCurve1.pdf Nothing further is required since it is obvious that steam will be produced for more than 15 minutes. The only thing obvious to me is that your conclusion is based on an over simplistic and erroneous analysis, and is also based on an assumption without a good foundation. You have yet to acknowledge this. Listen to me, not to yourself. I've been hearing obvious nonsense like "the temperature will decline very fast therefore steam will be produced for only a couple minutes." This is absurd. Again, this assertion of less than 2 minute decay was based on one of 30 assumption data sets I have provided. I did not supply the 1 MJ number. It was suggested on this list. Further, I don't believe the 1 MJ number is correct and never did. It is merely a *sample* assumption "for the sake of discussion" based on the postings of others, your postings perhaps. Again, I don't think we have communicated. Please explain what the following comments, taken from my post and quoted by you, meant to you: "My two cents on this is it is a typical one of a kind anecdote - with no solid measurements to back it up. We don't really know if the device was initially outputting 5000 W or just the input wattage, for example." "For the sake of discussion, let's just assume ... " "So, if all is as assumed above (very unlikely!) the device should not be able to output steam for 15 minutes, or even more than 2 minutes, unless a source of heat was present after the power was cut off. The problem is we just do not have enough data t
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 29, 2011, at 10:00 AM, Joe Catania wrote: Try to understand there is no way that the temperature can decay in only a few minutes. If you start with 1MJ and subtracted 1kJ/sec you'd get 1000sec. This is woefully wrong on two counts, (a) the 1 MJ number is a wild guess on your part and probably wrong, way too high, and (b) you can not simply subtract 1 kJ/sec until reaching zero, even if that is the thermal demand at some point. There is flowing water coming in at 23° C or thereabouts. The temperature required to warm that water up to 100°C is substantially above 100°C, as I have clearly shown: http://www.mail-archive.com/vortex-l%40eskimo.com/msg50831.html http://www.mtaonline.net/~hheffner/DecayCurve1.pdf For example, note in the above pdf, to which I have added a "Stored Energy" column, that even though the initial stored energy is 1.11 MJ, that steam generation stops when stored energy is 0.5467 MJ. All the 1.11 MJ is thus *not available* to generate steam. Note in: http://www.mtaonline.net/~hheffner/RossiThermal2.pdf Mode 3, line 3, that, given all the assumptions in that line, a minimum mass temperature of 307°C is required to heat the incoming water to 100°C. This is due to a need to be consistent with the Thermal Resistance that is required by the assumptions. This is in part what I mean when I say this kind of model can iron out internal inconsistencies in the choice of input parameters. Now understand that we don't stay at 1kJ, we decrease in accordance with a decline in temperature. Yes, I provided a thermal decline curve, and, for your convenience I added a column providing the the Thermal Energy of the mass by time: http://www.mtaonline.net/~hheffner/DecayCurve1.pdf Nothing further is required since it is obvious that steam will be produced for more than 15 minutes. The only thing obvious to me is that your conclusion is based on an over simplistic and erroneous analysis, and is also based on an assumption without a good foundation. You have yet to acknowledge this. Listen to me, not to yourself. I've been hearing obvious nonsense like "the temperature will decline very fast therefore steam will be produced for only a couple minutes." This is absurd. Again, this assertion of less than 2 minute decay was based on one of 30 assumption data sets I have provided. I did not supply the 1 MJ number. It was suggested on this list. Further, I don't believe the 1 MJ number is correct and never did. It is merely a *sample* assumption "for the sake of discussion" based on the postings of others, your postings perhaps. Again, I don't think we have communicated. Please explain what the following comments, taken from my post and quoted by you, meant to you: "My two cents on this is it is a typical one of a kind anecdote - with no solid measurements to back it up. We don't really know if the device was initially outputting 5000 W or just the input wattage, for example." "For the sake of discussion, let's just assume ... " "So, if all is as assumed above (very unlikely!) the device should not be able to output steam for 15 minutes, or even more than 2 minutes, unless a source of heat was present after the power was cut off. The problem is we just do not have enough data to make the above calculation credibly. This is not a new kind of problem with regard to the E-Cat." What do you think my statements, quoted above, mean? Do you think they mean I am asserting the device mass stores a MJ of energy? Do you think I am asserting therefore there is a 2 minute time limit until no steam? This is not what this means at all. In fact I explicitly stated why that calculation was provided. Your straw man argument simply is not valid. Again I say, if you don't like my assumed numbers feel free to tell me what your assumed numbers are for Mass, Thermal Power (before shutoff), Inlet Temp., Mass Temp., and Inlet Flow. However, it should be self evident that the results can be made to look as you please with regard to decay time, by choice of assumptions. The required data is simply not available to make a true determination of decay time. That said, discussion based on quantitative analysis should be more meaningful than discussion based on personal feelings and arbitrary assumptions. At least some of the inconsistent assumptions might be ruled out. You need to take a more serious look at this. I'll gladly do this. You have certainly rested on your 1970 laurels. I would not say that I am resting. 8^) I do tend to take daily afternoon naps though! 8^) Assumed numbers are meaningless. My point exactly. You do not proceed from first principles. This is what I have done, proceed from basic principles with regard to analysis, even though the model is simplistic. Your mental model, however, is even more simplistic, to the point of ar
Re: [Vo]:Corrections to "heat after death" calculations
Try to understand there is no way that the temperature can decay in only a few minutes. If you start with 1MJ and subtracted 1kJ/sec you'd get 1000sec. Now understand that we don't stay at 1kJ, we decrease in accordance with a decline in temperature. Nothing further is required since it is obvious that steam will be produced for more than 15 minutes. You have yet to acknowledge this. Listen to me, not to yourself. I've been hearing obvious nonsense like "the temperature will decline very fast therefore steam will be produced for only a couple minutes." This is absurd. You need to take a more serious look at this. You have certainly rested on your 1970 laurels. Assumed numbers are meaningless. You do not proceed from first principles. I've already shown steam will be produced for over 15 minutes. I've said this many times. I will not consider your numbers since they are obviously flawed as well as you calculation. It is obvious to the most rank amateur that steam will be produced for over 15 minutes. Your errors have been pointed out. - Original Message - From: Horace Heffner To: vortex-l@eskimo.com Sent: Monday, August 29, 2011 12:41 PM Subject: Re: [Vo]:Corrections to "heat after death" calculations On Aug 29, 2011, at 6:48 AM, Joe Catania wrote: > I can not see how the above remark is relevant in any way. Did you not see that I am providing the standard logarithmic decay function? The cutoff time for the logarithmic decay is intended to set a *boundary time* on when there is no more steam. If the temperature of the mass is below boiling point then it can not generate steam. Your exponential (not log) function is not correct as it does not allow for exponential decay in energy. That is correct - it is called an exponential decay function. I am an old guy with some memory problems. I forget simple words and sometimes it takes me a long time to write because I have to find the words. As anyone knows who has read my posts here for the last 15 years, I am also prone to clerical errors, arithmetic errors, and seldom get things right the first pass. However I wrote my first thermal transfer finite element code in the 1970's, so I am no stranger to these issues. You should note the function used/provided is correct, namely: T(t) = T0 * e^-(t/tau) There is no need to hash this out. There is no need to discuss Rossi at all, since there is insufficient data provided by him to determine anything. All such discussion is at best hypothetical, if not even based on obvious untruths. However, this has not stopped either you or Jed from repeatedly taking positions without foundation in fact. I think it is clear an analysis can rule out some assumption sets as self-inconsistent. That is more useful than repeated useless argument based on differing assumptions. My original presentation and conclusions are correct. Your calculations are not correct, nevertheless they do show 15 minutes is possible. There's nothing hypothetical about thermal inertia. Perhaps you are referring to your errant guesswork. We don't need to second guess mother nature. I mentioned ~ 1MJ not exactly 1 MJ and of course the amount will vary with mass, specific heat and temperature. The problem is that you used it without understanding it. This is not a plug-in. Again I say, if you don't like my assumed numbers feel free to tell me what your assumed numbers are for Mass, Thermal Power (before shutoff), Inlet Temp., Mass Temp., and Inlet Flow. However, it should be self evident that the *results* can be made to look as you please by choice of assumptions. The required data is simply not available to make a determination. However, discussion based on quantitative analysis should be more meaningful than discussion based on personal feelings and arbitrary assumptions. At least some of the inconsistent assumptions might be ruled out. If you think I have arithmetic or analytical errors, calculation errors, please point them out specifically. - Original Message - From: Horace Heffner To: vortex-l@eskimo.com Sent: Monday, August 29, 2011 2:53 AM Subject: Re: [Vo]:Corrections to "heat after death" calculations On Aug 28, 2011, at 5:37 PM, Joe Catania wrote: No one to my knowledge is showing data that the heat after pulling the plug continues at the rate it had before power-off for a full 15 minutes. I can not see how the above remark is relevant in any way. Did you not see that I am providing the standard logarithmic decay function? The cutoff time for the logarithmic decay is intended to set a *boundary time* on when there is no more steam. If the temperature of the mass is below boiling point then it can not generate steam. My in
Re: [Vo]:Corrections to "heat after death" calculations
On Aug 29, 2011, at 6:48 AM, Joe Catania wrote: > I can not see how the above remark is relevant in any way. Did you not see that I am providing the standard logarithmic decay function? The cutoff time for the logarithmic decay is intended to set a *boundary time* on when there is no more steam. If the temperature of the mass is below boiling point then it can not generate steam. Your exponential (not log) function is not correct as it does not allow for exponential decay in energy. That is correct - it is called an exponential decay function. I am an old guy with some memory problems. I forget simple words and sometimes it takes me a long time to write because I have to find the words. As anyone knows who has read my posts here for the last 15 years, I am also prone to clerical errors, arithmetic errors, and seldom get things right the first pass. However I wrote my first thermal transfer finite element code in the 1970's, so I am no stranger to these issues. You should note the function used/provided is correct, namely: T(t) = T0 * e^-(t/tau) There is no need to hash this out. There is no need to discuss Rossi at all, since there is insufficient data provided by him to determine anything. All such discussion is at best hypothetical, if not even based on obvious untruths. However, this has not stopped either you or Jed from repeatedly taking positions without foundation in fact. I think it is clear an analysis can rule out some assumption sets as self-inconsistent. That is more useful than repeated useless argument based on differing assumptions. My original presentation and conclusions are correct. Your calculations are not correct, nevertheless they do show 15 minutes is possible. There's nothing hypothetical about thermal inertia. Perhaps you are referring to your errant guesswork. We don't need to second guess mother nature. I mentioned ~ 1MJ not exactly 1 MJ and of course the amount will vary with mass, specific heat and temperature. The problem is that you used it without understanding it. This is not a plug-in. Again I say, if you don't like my assumed numbers feel free to tell me what your assumed numbers are for Mass, Thermal Power (before shutoff), Inlet Temp., Mass Temp., and Inlet Flow. However, it should be self evident that the *results* can be made to look as you please by choice of assumptions. The required data is simply not available to make a determination. However, discussion based on quantitative analysis should be more meaningful than discussion based on personal feelings and arbitrary assumptions. At least some of the inconsistent assumptions might be ruled out. If you think I have arithmetic or analytical errors, calculation errors, please point them out specifically. - Original Message - From: Horace Heffner To: vortex-l@eskimo.com Sent: Monday, August 29, 2011 2:53 AM Subject: Re: [Vo]:Corrections to "heat after death" calculations On Aug 28, 2011, at 5:37 PM, Joe Catania wrote: No one to my knowledge is showing data that the heat after pulling the plug continues at the rate it had before power-off for a full 15 minutes. I can not see how the above remark is relevant in any way. Did you not see that I am providing the standard logarithmic decay function? The cutoff time for the logarithmic decay is intended to set a *boundary time* on when there is no more steam. If the temperature of the mass is below boiling point then it can not generate steam. My interpretation of Levu's comment in Part 3 of the Krivit video is that the rate natually declines until after 15 minutes it was judged that steam production had ceased. Either way thermal inertia plays a role. You're really stretch credulity to ask me to believe you calculation shows only a few minutes is possible. My calculations do not show that "only a few minutes is possible." My calculations show the decay time *for some assumed conditions*. *Under those conditions* only a very short time is possible. I explicitly stated this. I am providing a model to assist others in make such calculations based upon their own assumptions. It is important to keep in mind such an approach is purely hypothetical, but might shed some light on boundaries to the experimental conditions. You haven't set it up carefully enough, i.e. it is flawed. For one thing it would appear that more than 1 MJ would be stored in the case you discuss. I did not supply the 1 MJ number. It was suggested on this list. Further, I don't believe 1 MJ number is correct and never did. It is merely a *sample* assumption based on the postings of others, your postings perhaps. Your temperature seems low. The temperature is a result of the *assumptions*, specifically the assumption of a 1 MJ energy s
Re: [Vo]:Corrections to "heat after death" calculations
> I can not see how the above remark is relevant in any way. Did you not see > that I am providing the standard logarithmic decay function? The cutoff > time for the logarithmic decay is intended to set a *boundary time* on when > there is no more steam. If the temperature of the mass is below boiling > point then it can not generate steam. Your exponential (not log) function is not correct as it does not allow for exponential decay in energy. There is no need to hash this out. My original presentation and conclusions are correct. Your calculations are not correct, nevertheless they do show 15 minutes is possible. There's nothing hypothetical about thermal inertia. Perhaps you are referring to your errant guesswork. We don't need to second guess mother nature. I mentioned ~ 1MJ not exactly 1 MJ and of course the amount will vary with mass, specific heat and temperature. The problem is that you used it without understanding it. This is not a plug-in. - Original Message - From: Horace Heffner To: vortex-l@eskimo.com Sent: Monday, August 29, 2011 2:53 AM Subject: Re: [Vo]:Corrections to "heat after death" calculations On Aug 28, 2011, at 5:37 PM, Joe Catania wrote: No one to my knowledge is showing data that the heat after pulling the plug continues at the rate it had before power-off for a full 15 minutes. I can not see how the above remark is relevant in any way. Did you not see that I am providing the standard logarithmic decay function? The cutoff time for the logarithmic decay is intended to set a *boundary time* on when there is no more steam. If the temperature of the mass is below boiling point then it can not generate steam. My interpretation of Levu's comment in Part 3 of the Krivit video is that the rate natually declines until after 15 minutes it was judged that steam production had ceased. Either way thermal inertia plays a role. You're really stretch credulity to ask me to believe you calculation shows only a few minutes is possible. My calculations do not show that "only a few minutes is possible." My calculations show the decay time *for some assumed conditions*. *Under those conditions* only a very short time is possible. I explicitly stated this. I am providing a model to assist others in make such calculations based upon their own assumptions. It is important to keep in mind such an approach is purely hypothetical, but might shed some light on boundaries to the experimental conditions. You haven't set it up carefully enough, i.e. it is flawed. For one thing it would appear that more than 1 MJ would be stored in the case you discuss. I did not supply the 1 MJ number. It was suggested on this list. Further, I don't believe 1 MJ number is correct and never did. It is merely a *sample* assumption based on the postings of others, your postings perhaps. Your temperature seems low. The temperature is a result of the *assumptions*, specifically the assumption of a 1 MJ energy storage, and the assumed power input. I set up the the spread sheet so that temperature is specified and stored energy is computed, instead of vice versa as was done in the manual calc. below. I remember Rossi saying he was able to heat a working fluid to 450C so the thermal mass would seem to get hotter than that. Your calculation of time constant is clearly unacceptable as heat output cannot remain constant. Have you not heard of logarithmic decay curves? Their shape is based on a decay constant lambda, or half life, etc. Did you even read my post? The analysis, if done properly, leaves no doubt about the correct conclusion. To say its all off for a factor of 3 is laughable in my judgment, esp. when you've underestimated values and overestimated outout and failed to understand the decay of output. I don't think we have communicated. Please explain what the following comments, taken from my post quoted below by you, meant to you: "My two cents on this is it is a typical one of a kind anecdote - with no solid measurements to back it up. We don't really know if the device was initially outputting 5000 W or just the input wattage, for example." "For the sake of discussion, let's just assume ... " "So, if all is as assumed above (very unlikely!) the device should not be able to output steam for 15 minutes, or even more than 2 minutes, unless a source of heat was present after the power was cut off. The problem is we just do not have enough data to make the above calculation credibly. This is not a new kind of problem with regard to the E-Cat." Also it seems hydride formation probably explains any anomalous heat produced- that is if it can be determined that its produced and how much. So far this has b
Re: [Vo]:Corrections to "heat after death" calculations
eaningful than discussion based on personal feelings and arbitrary assumptions. At least some of the inconsistent assumptions might be ruled out. - Original Message - From: Horace Heffner To: vortex-l@eskimo.com Sent: Sunday, August 28, 2011 8:58 AM Subject: [Vo]:Corrections to "heat after death" calculations On Aug 27, 2011, at 12:51 PM, Joe Catania wrote: For the umpteenth time it is not an assertion. The thermal mass of the reactor is about 1MJ (based on specific heat), the energy outflow is a mere fraction (~1kW). OK? There has been no demonstration that output is higher than inout. Steam quality is not measured, therma; inertia not accounted for. and there is Rizzi's determination that flow is over estimated. I hope I don't have to repeat these facts again. The source of heat in the 15 minutes is thermal inertia since it would account for all steam produced. Cold fusion is not indicated by what Levi has said. I have not seen the graphs you speak of and I'm not sure they are coincident with cutting the power but thermal inertia needs to be accounted for. So show me the data. And all I can say is one does not assume cold fusion to prove cold fusion. CF proof is totally elusive by the means exploited. Its more likely a flaw in technique of measurement. But if there is proof of anomalous heat it has eluded my detection so far. The properway to do the calorimetry is not with flow as I've detailed before. Levi said steam stopped after 15 minutes so it seems you need to get on the same page. My two cents on this is it is a typical one of a kind anecdote - with no solid measurements to back it up. We don't really know if the device was initially outputting 5000 W or just the input wattage, for example. For the sake of discussion, let's just assume the story is correct and the device was outputting 5 kW as advertised. Let's also be generous with regard to mass, and assume it was equivalent to 20 kg of copper, and stored 1 MJ of energy as specified above. Using a heat capacity of copper, 0.385 J/(gm K), a 20 kg mass requires delta T = (10^6 J)/((0.385 J/(gm °C))*(2*10^4 gm)) = 130 °C to store the 1 MJ thermal energy. If we assume inlet temperature of 23°C then this is an absolute temperature of 153°C. The thermal mass, Cth, is given by: Cth = (0.385 J/(gm °C)*(2*10^4 gm) = 7700 J/°C Assume the device transfers 5 kW of output heat when the internal temperature is 153°C and inlet temperature is 23°C, i.e. delta T is 130°C. This gives a thermal resistance of R = (130°C)/(5^10^3 W) = 2.6x10^-2 °C/W. The decay time constant, tau, for the 1 MJ thermal mass, C, is is given by: tau = R*Cth = (2.6x10^-2 °C/W)*(7700 J/°C) = 200 s We now have the thermal decline curve: T(t) = T0 * e^-(t/tau) = (153 °C) * 1/e^(t/tau) If we want steam to disappear at time t, then T(t) = 100°C. So: (100°C) = (153 °C) * 1/e^(t/tau) (t/tau) = ln((153°C) /(100 °C) t = ln((153°C) /(100 °C)) * (200 s) t = 85 s So, if all is as assumed above (very unlikely!) the device should not be able to output steam for 15 minutes, or even more than 2 minutes, unless asource of heat was present after the power was cut off. The problem is we just do not have enough data to make the above calculation credibly. This is not a new kind of problem with regard to the E-Cat. Hopefully in any case the above example is useful to others for theorizing. We just have to wait until October to see what happens. I hope for the best. I hope we don't see non-credible delays and moving target objectives as we have seen before in similar situations. I wish Rossi great success. Even the most minor technical success for Rossi would be one of the greatest scientific breakthroughs ever, and have great importance for all mankind. Rossi is not a young man. I hope he considers howlimited his time on earth is and makes the right decisions. Horace Heffner http://www.mtaonline.net/~hheffner/ Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
Re: [Vo]:Corrections to "heat after death" calculations
Joe, I think that you are enormous fiasco yourself, because you are making aggressive asumptions that does not have any rational basis. For example you fail to understand even the basics, because metal temperature cannot exceed 160°C because insulation rubber starts to melt and burn. This phenomenom is hard to not to notice if there are poisonous fumes in the surroundings. Other thing what you fail to understand, is that Krivit's demonstration has nothing to do with anything, because there was completely different type of E-Cat used in heat after death experiments. That in June demonstration was old and discarded prototype, because it's efficiency was very bad and could not be commercially viable reactor type. (This was probably the reason why Rossi showed to Krivit this old type module as a dummy with no excess heat at all.) What else what you seem to fail to understand, that metal is extremely good thermal conductor. Therefore if we assume your 450°C temperature (sic), then there cannot be any wet steam, but system produces hot steam with temperature of 150-300°C. Your reasoning is full of flaws, so please do not try to present your speculations as facts. If you do not believe E-Cat, please assume that there is a hidden power source. There has not been done any public actions to seek and exclude hidden power sources, such as hydrogenperoxide, hidden hydrogen bottle, lithium-ion battery, hidden wires and I am sure that David Copperfield can come up even more clever illusions for excess heat. I just fail completely understand why critics think that measurements must be flawed, but they do not present simplest explanation that E-Cat may be a honest fraud. It is trivial to fake excess heat! —Jouni
Re: [Vo]:Corrections to "heat after death" calculations
No one to my knowledge is showing data that the heat after pulling the plug continues at the rate it had before power-off for a full 15 minutes. My interpretation of Levu's comment in Part 3 of the Krivit video is that the rate natually declines until after 15 minutes it was judged that steam production had ceased. Either way thermal inertia plays a role. You're really stretch credulity to ask me to believe you calculation shows only a few minutes is possible. You haven't set it up carefully enough, i.e. it is flawed. For one thing it would appear that more than 1 MJ would be stored in the case you discuss. Your temperature seems low. I remember Rossi saying he was able to heat a working fluid to 450C so the thermal mass would seem to get hotter than that. Your calculation of time constant is clearly unacceptable as heat output cannot remain constant. The analysis, if done properly, leaves no doubt about the correct conclusion. To say its all off for a factor of 3 is laughable in my judgment, esp. when you've underestimated values and overestimated outout and failed to understand the decay of output. Also it seems hydride formation probably explains any anomalous heat produced- that is if it can be determined that its produced and how much. So far this has been an enormous fiasco. - Original Message - From: Horace Heffner To: vortex-l@eskimo.com Sent: Sunday, August 28, 2011 8:58 AM Subject: [Vo]:Corrections to "heat after death" calculations On Aug 27, 2011, at 12:51 PM, Joe Catania wrote: For the umpteenth time it is not an assertion. The thermal mass of the reactor is about 1MJ (based on specific heat), the energy outflow is a mere fraction (~1kW). OK? There has been no demonstration that output is higher than inout. Steam quality is not measured, therma; inertia not accounted for. and there is Rizzi's determination that flow is over estimated. I hope I don't have to repeat these facts again. The source of heat in the 15 minutes is thermal inertia since it would account for all steam produced. Cold fusion is not indicated by what Levi has said. I have not seen the graphs you speak of and I'm not sure they are coincident with cutting the power but thermal inertia needs to be accounted for. So show me the data. And all I can say is one does not assume cold fusion to prove cold fusion. CF proof is totally elusive by the means exploited. Its more likely a flaw in technique of measurement. But if there is proof of anomalous heat it has eluded my detection so far. The properway to do the calorimetry is not with flow as I've detailed before. Levi said steam stopped after 15 minutes so it seems you need to get on the same page. My two cents on this is it is a typical one of a kind anecdote - with no solid measurements to back it up. We don't really know if the device was initially outputting 5000 W or just the input wattage, for example. For the sake of discussion, let's just assume the story is correct and the device was outputting 5 kW as advertised. Let's also be generous with regard to mass, and assume it was equivalent to 20 kg of copper, and stored 1 MJ of energy as specified above. Using a heat capacity of copper, 0.385 J/(gm K), a 20 kg mass requires delta T = (10^6 J)/((0.385 J/(gm °C))*(2*10^4 gm)) = 130 °C to store the 1 MJ thermal energy. If we assume inlet temperature of 23°C then this is an absolute temperature of 153°C. The thermal mass, Cth, is given by: Cth = (0.385 J/(gm °C)*(2*10^4 gm) = 7700 J/°C Assume the device transfers 5 kW of output heat when the internal temperature is 153°C and inlet temperature is 23°C, i.e. delta T is 130°C. This gives a thermal resistance of R = (130°C)/(5^10^3 W) = 2.6x10^-2 °C/W. The decay time constant, tau, for the 1 MJ thermal mass, C, is is given by: tau = R*Cth = (2.6x10^-2 °C/W)*(7700 J/°C) = 200 s We now have the thermal decline curve: T(t) = T0 * e^-(t/tau) = (153 °C) * 1/e^(t/tau) If we want steam to disappear at time t, then T(t) = 100°C. So: (100°C) = (153 °C) * 1/e^(t/tau) (t/tau) = ln((153°C) /(100 °C) t = ln((153°C) /(100 °C)) * (200 s) t = 85 s So, if all is as assumed above (very unlikely!) the device should not be able to output steam for 15 minutes, or even more than 2 minutes, unless a source of heat was present after the power was cut off. The problem is we just do not have enough data to make the above calculation credibly. This is not a new kind of problem with regard to the E-Cat. Hopefully in any case the above example is useful to others for theorizing. We just have to wait until October to see what happens. I hope for the best. I hope we don't see non-credible delays and moving target objectives as we have seen before in similar situations.
[Vo]:Corrections to "heat after death" calculations
On Aug 27, 2011, at 12:51 PM, Joe Catania wrote: For the umpteenth time it is not an assertion. The thermal mass of the reactor is about 1MJ (based on specific heat), the energy outflow is a mere fraction (~1kW). OK? There has been no demonstration that output is higher than inout. Steam quality is not measured, therma; inertia not accounted for. and there is Rizzi's determination that flow is over estimated. I hope I don't have to repeat these facts again. The source of heat in the 15 minutes is thermal inertia since it would account for all steam produced. Cold fusion is not indicated by what Levi has said. I have not seen the graphs you speak of and I'm not sure they are coincident with cutting the power but thermal inertia needs to be accounted for. So show me the data. And all I can say is one does not assume cold fusion to prove cold fusion. CF proof is totally elusive by the means exploited. Its more likely a flaw in technique of measurement. But if there is proof of anomalous heat it has eluded my detection so far. The properway to do the calorimetry is not with flow as I've detailed before. Levi said steam stopped after 15 minutes so it seems you need to get on the same page. My two cents on this is it is a typical one of a kind anecdote - with no solid measurements to back it up. We don't really know if the device was initially outputting 5000 W or just the input wattage, for example. For the sake of discussion, let's just assume the story is correct and the device was outputting 5 kW as advertised. Let's also be generous with regard to mass, and assume it was equivalent to 20 kg of copper, and stored 1 MJ of energy as specified above. Using a heat capacity of copper, 0.385 J/(gm K), a 20 kg mass requires delta T = (10^6 J)/((0.385 J/(gm °C))*(2*10^4 gm)) = 130 °C to store the 1 MJ thermal energy. If we assume inlet temperature of 23°C then this is an absolute temperature of 153°C. The thermal mass, Cth, is given by: Cth = (0.385 J/(gm °C)*(2*10^4 gm) = 7700 J/°C Assume the device transfers 5 kW of output heat when the internal temperature is 153°C and inlet temperature is 23°C, i.e. delta T is 130°C. This gives a thermal resistance of R = (130°C)/(5^10^3 W) = 2.6x10^-2 °C/W. The decay time constant, tau, for the 1 MJ thermal mass, C, is is given by: tau = R*Cth = (2.6x10^-2 °C/W)*(7700 J/°C) = 200 s We now have the thermal decline curve: T(t) = T0 * e^-(t/tau) = (153 °C) * 1/e^(t/tau) If we want steam to disappear at time t, then T(t) = 100°C. So: (100°C) = (153 °C) * 1/e^(t/tau) (t/tau) = ln((153°C) /(100 °C) t = ln((153°C) /(100 °C)) * (200 s) t = 85 s So, if all is as assumed above (very unlikely!) the device should not be able to output steam for 15 minutes, or even more than 2 minutes, unless a source of heat was present after the power was cut off. The problem is we just do not have enough data to make the above calculation credibly. This is not a new kind of problem with regard to the E-Cat. Hopefully in any case the above example is useful to others for theorizing. We just have to wait until October to see what happens. I hope for the best. I hope we don't see non-credible delays and moving target objectives as we have seen before in similar situations. I wish Rossi great success. Even the most minor technical success for Rossi would be one of the greatest scientific breakthroughs ever, and have great importance for all mankind. Rossi is not a young man. I hope he considers how limited his time on earth is and makes the right decisions. Horace Heffner http://www.mtaonline.net/~hheffner/