Dear All,I encountered a problem when I use RWeka for prediction.
Specifically, I use the following:
res=J48(X1~.,data=mydata);
predict(res), #it worked fine
but when I tried to use a different data set,
i.e. predict(res,newdata=mynewdata);
all the predictions I get is 0, which apparently is
Dear All,I encountered a problem when I use RWeka for prediction.
Specifically, I use the following:
res=J48(X1~.,data=mydata);
predict(res), #it worked fine
but when I tried to use a different data set,
i.e. predict(res,newdata=mynewdata);
all the predictions I get is 0, which apparently is
Hi,
I've performed an lda and obtained a classification table for some of my
data:
efa.dfa-lda(groups~.,efa.scores.8,CV=T)
str(efa.dfa)
List of 5
$ class: Factor w/ 2 levels 1,2: 1 2 1 2 1 1 2 2 1 2 ...
$ posterior: num [1:160, 1:2] 0.99083 0.00852 0.93983 0.23186 0.85931 ...
..-
Ok thanks Erik
Indeed, exclude in xtabs seems working whith character vectors:
x - c(rep(c(A,B,C), 2))
x
[1] A B C A B C
xtabs(~ x, exclude = B)
x
A C
2 2
and not directly with factors:
x - factor(rep(c(A,B,C), 2))
x
[1] A B C A B C
Levels: A B C
levels(x)
[1] A B C
xtabs(~ x,
On Fri, 2009-04-24 at 13:12 -0700, sjaffe wrote:
small example:
a-c(1.1, 2.1, 9.1)
b-cut(a,0:10)
c-data.frame(b,b)
d-table(c)
dim(d)
##result: c(10, 10)
But only 9 of the 100 cells are non-zero.
If there were 10 columns, the table have 10 dimensions each of length 10, so
have 10^10
On Sun, 26 Apr 2009, Dajiang Liu wrote:
Dear All,I encountered a problem when I use RWeka for prediction.
Specifically, I use the following:
res=J48(X1~.,data=mydata);
predict(res), #it worked fine
but when I tried to use a different data set,
i.e. predict(res,newdata=mynewdata);
all the
Dear Chris,
Changing
coord_cartesian(ylim = c(0, 5))
into
coord_cartesian() + scale_y_continuous(limits = c(0, 5))
That should solve your problem.
HTH,
Thierry
ir. Thierry Onkelinx
Ok thanks Erik
Indeed, exclude in xtabs seems working whith character vectors:
x - c(rep(c(A,B,C), 2))
x
[1] A B C A B C
xtabs(~ x, exclude = B)
x
A C
2 2
and not directly with factors:
x - factor(rep(c(A,B,C), 2))
x
[1] A B C A B C
Levels: A B C
levels(x)
[1] A B C
xtabs(~ x, exclude =
Hi all,
I'm trying to do multiple graphs in a window like this:
___ ___ ___
ylab |__| |__| |__|
___ ___ ___
ylab |__| |__| |__|
___ ___ ___
ylab |__| |__| |__|
xl xl xl
If I try to put the labels manually, some graphs become smaller
Hi,
I am trying to estimate a quantile regression using panel data. I am trying
to use the model that is described in Dr. Koenker's article. So I use the
code the that is posted in the following link:
http://www.econ.uiuc.edu/~roger/research/panel/rq.fit.panel.R
How to estimate the panel
Dear all
I'm realy new to R, so I hope you can help me, as I didn't find any solution in
the common books.
Since some days I'm trying to create the following plot: A scatterplott
showning two different groups side-by-side with according regression lines.
Both datasets only have the same five
Hello all,
Apologize for the newbie question. What's the easiest way to do a SQL inner
table join in R?
Say I have a table containing column names A, B, C and another which has
columns named C, D, E. I would like to do an inner table join on C and
produce a table A, B, C, D, E.
thanks a lot,
I am new in R.
I can simulate Arma, using Arima.sim
However, I want to simulate an Arima Model. Say (1-B)Zt=5+(1-B)at. I do not
know how to deal with 5 in this model.
Can any one could help me?
Thank you very much!
Regards,
--
View this message in context:
1. ?merge
2. sqldf package whose home page is at:
http://sqldf.googlecode.com
On Sat, Apr 25, 2009 at 9:15 PM, Nigel Birney na...@cam.ac.uk wrote:
Hello all,
Apologize for the newbie question. What's the easiest way to do a SQL inner
table join in R?
Say I have a table containing column
Hi. guys,
I am trying to write my own Stochastic Gradient Ascent for logistic
regression in R. But it seems that I am having convergence problem.
Am I doing anything wrong, or just the data is off?
Here is my code in R -
lbw -
Nigel Birney wrote:
Hello all,
Apologize for the newbie question. What's the easiest way to do a SQL inner
table join in R?
Say I have a table containing column names A, B, C and another which has
columns named C, D, E. I would like to do an inner table join on C and
produce a table A, B, C,
I'm sorry - I meant a median survival estimate, not a median risk.
I see - I didn't realize that by stratifying it would pool the levels of the
stratified variable. Hm, that is unfortunate, considering the stratified
variable is one that I would like to keep in the nomogram.
Thank you for your
This is a nontrivial problem. This comes up often on the Statalist
(-qreg- is for cross-section quantile regression):
You want to fit a plane through the origin using the L-1 norm.
This is not as easy as with L-2 norm (LS), as it is more
than a matter of dropping a constant predictor yet
Hi,
Have you considered using high-level plotting functions provided by
the ggplot2 or lattice package? Here's a dummy example,
x - seq(0, 10, length=100)
y1 - sin(x)
y2 - cos(x)
y3 - x^2/100
y4 - 1/x
d - data.frame(x, y1, y2, y3, y4)
library(reshape)
dm - melt(d, id=x)
dm$type1 -
Hi,
You could do this very easily using ggplot2,
#install.packages(ggplot2, dep=TRUE)
library(ggplot2)
c - ggplot(mtcars, aes(y=wt, x=mpg)) + facet_grid(. ~ cyl)
c + stat_smooth(method=lm) + geom_point()
See more examples on Hadley's website: http://had.co.nz/ggplot2/
Hope this helps,
Hello David,
Let me try again, I don't think this was the best post ever I've made :-)
Hopefully this is clearer, or otherwise I may break this up into
three separate simple queries as this may be too long.
== is not an assignment operator in R, so the answer is that it
would do neither. -
Dear User,
thank for the attention. I have a data.frame with 5 columns (ex:ID,
a1,a2,a3,a4) and 1000 rows. I wish to find the absolute max value for all
data.frame and save a new data.frame with the row where is that value. Ex:
ID: 1,2,3,4,5,6,7,8,9,10
a1:1,2,3,4,5,6,7,8,9,10
I have various objects defined but I am trying to remove a set of elements in
one vector from another and using the loops at the end of this post but I am
getting the error at the very end of this post.
str(x)
num [1:923, 1:923] 1 -0.00371 -0.00102 -0.00204 -0.00102 ...
- attr(*,
I want to generate some orthogonal tables in my experiment design.
I searched http://search.r-project.org/ (RSiteSearch) whith key words such as
orthogonal table, orthogonal design, latin square etc and get no useful
result. the same result get by searching via google's insite search in r-cran
Hi David,
Thanks! It looks much better now. but is there any way to add (x,y)
coordinates as labels to all the points in the graph? Best case if I can
enforce some conditions saying if (y10,000) label, else no label. Any
advice is appreciated.
Best,
Tony
-Original Message-
From: David
Dear Alessandro,
Here is one way:
DF - data.frame(ID,a1,a2,a3,a4)
Row - which( DF == max(DF[,-1]), arr.ind = TRUE)[1]
DF[Row,]
# ID a1 a2 a3 a4
# 10 10 10 20 30 40
See ?which and ?max for more details.
HTH,
Jorge
On Sun, Apr 26, 2009 at 8:02 AM, Alessandro
David Winsemius wrote:
On Apr 25, 2009, at 6:57 PM, reneepark wrote:
Hello,
I am using Dr. Harrell's design package to make a nomogram. I was able to
make a beautiful one without stratifying, however, I will need to
stratify
to meet PH assumptions. This is where I go wrong, but I'm not
On Apr 26, 2009, at 7:48 AM, Esmail wrote:
Hello David,
Let me try again, I don't think this was the best post ever I've
made :-)
Hopefully this is clearer, or otherwise I may break this up into
three separate simple queries as this may be too long.
== is not an assignment operator in
since 2.9.0 version I have a problem with installing packages:
install.packages(sp)
--- Please select a CRAN mirror for use in this session ---
Loading Tcl/Tk interface ... done
Warning: unable to access index for repository
http://piotrkosoft.net/pub/mirrors/CRAN/src/contrib
Warning messages:
Daryl Morris wrote:
Thanks for the various responses.
It was easier than I thought to get all the tools together and setup
Windows paths for the build process. I've been successful now on Windows.
BUT... how do I make a package which DOES NOT require R CMD INSTALL to
install? Obviously,
On Sun, 26 Apr 2009 09:29:39 + (GMT) nonu...@yahoo.de
nonu...@yahoo.de wrote:
ND I'm realy new to R, so I hope you can help me, as I didn't find any
ND solution in the common books.
Have a look at the online resources at:
http://cran.r-project.org/other-docs.html
There is also stuff on
David Winsemius wrote:
Yes. As I said before I am going to refrain from posting speculation
until you provide valid R code
that will create an object that can be the subject of operations.
The code I have provided works, here is a run that may prove helpful:
POP_SIZE = 6
LEN = 8
On Apr 26, 2009, at 8:02 AM, Alessandro wrote:
Dear User,
thank for the attention. I have a data.frame with 5 columns (ex:ID,
a1,a2,a3,a4) and 1000 rows. I wish to find the absolute max value
for all
data.frame and save a new data.frame with the row where is that
value. Ex:
ID:
Thank you.
Unluckily what makes the problem only apparenttly simple (for me) is that we
have not differentiable functions and the parameter space is not continuous ...
which reduces dramatically the number of choices.
I would be grateful to chat with anyone who has tackled a similar problem.
Dear Karin,
If I understand correctly what you want, the scatterplot function in the car
package isn't designed to produce it, but there are many ways to draw
side-by-side scatterplots. Here is one, using basic R graphics:
par(mfrow=c(1,2))
by(Data, Data$group,
function(x) {
Jarek Jasiewicz wrote:
since 2.9.0 version I have a problem with installing packages:
install.packages(sp)
--- Please select a CRAN mirror for use in this session ---
Loading Tcl/Tk interface ... done
Warning: unable to access index for repository
Caroline Wallis wrote:
Hi,
I'm using e1071 package to do fuzzy cluster analysis. My dataset (ra) has
5237 observations and 2 variables - depth and velocity. I used fuzzy cmeans
to create 6 fuzzy classes.
ra.flcust6-cmeans(ra,6,iter.max=100,verbose=F,dist=euclidean,method=cmea
WilDsc0p wrote:
Dear List,
I have a question regarding ipred package. Under 10-fold cv, for different
knn ( = 1,3,...25), I am getting same misclassification errors:
#
library(ipred)
data(iris)
cv.k = 10 ## 10-fold cross-validation
bwpredict.knn
Works for me with
library(MASS)
plot(lda(Species~., data=iris))
hence you may want to profide the data to enable us to reproduce your
problem...
Uwe Ligges
pgseye wrote:
Hi,
I've performed an lda and obtained a classification table for some of my
data:
Ken-JP wrote:
set.seed(1)
x - runif(100)
# I want to calculate y such that:
#
# 1. if x0.75, y - 1
# 2. else if x0.25, y - -1
# 3. else if y_prev==1 x0.5, y - 0
# 4. else if y_prev==-1 x0.5, y - 0
# 5. else y - y_prev
#
# 1. and 2. are directly doable without looping.
#
# How do I do 3.-5.
I tried several mirrors
Uwe Ligges pisze:
Jarek Jasiewicz wrote:
since 2.9.0 version I have a problem with installing packages:
install.packages(sp)
--- Please select a CRAN mirror for use in this session ---
Loading Tcl/Tk interface ... done
Warning: unable to access index for repository
On Apr 26, 2009, at 9:43 AM, Esmail wrote:
David Winsemius wrote:
Yes. As I said before I am going to refrain from posting
speculation until you provide valid R code
that will create an object that can be the subject of operations.
The code I have provided works, here is a run that may
I tried several mirrors
But, what may be more important.
This error was mentioned earlier on VISTA and WindowsXP, I use Ubuntu 8.04
Uwe Ligges pisze:
Jarek Jasiewicz wrote:
since 2.9.0 version I have a problem with installing packages:
install.packages(sp)
--- Please select a CRAN mirror
How do people deal with R and memory issues?
I have tried using gc() to see how much memory is used at each step.
Scanned Crawley R-Book and all other R books I have available and the FAQ
on-line but no help really found.
Running WinXP Pro (32 bit) with 4 GB RAM.
One SATA drive
I want to (1) create a deep copy of pop,
I have already said *I* do not know how to create a deep copy in R.
Creating a deep copy is easy, because all copies are deep copies.
You need to try very hard to create a reference in R.
Hadley
--
http://had.co.nz/
My understanding of the OP's request was for some sort of copy which
did change when entries in the original were changed; the sort of
behavior that might be seen in a spreadsheet that had a copy by
reference.
On Apr 26, 2009, at 11:28 AM, hadley wickham wrote:
I want to (1) create a
David,
Good news! It seems that R has deep copy by default. I ran this simplified
test and it seems I can change 'pop' without changing the saved version.
POP_SIZE = 4
LEN = 8
pop=create_pop_2(POP_SIZE, LEN)
cat('printing original pop\n')
print(pop)
keep_pop = pop
pop[1,1] = 99
cat('printing
hadley wickham wrote:
I want to (1) create a deep copy of pop,
I have already said *I* do not know how to create a deep copy in R.
Creating a deep copy is easy, because all copies are deep copies.
You need to try very hard to create a reference in R.
Hi Hadley
Right you are .. I discovered
In that case, you would want a shallow copy, and you'd need to jump
through a lot of hoops to do that in R.
Hadley
On Sun, Apr 26, 2009 at 10:35 AM, David Winsemius
dwinsem...@comcast.net wrote:
My understanding of the OP's request was for some sort of copy which did
change when entries in the
David Winsemius
dwinsem...@comcast.net wrote:
My understanding of the OP's request was for some sort of copy which did
change when entries in the original were changed; the sort of behavior that
might be seen in a spreadsheet that had a copy by reference.
You misunderstood (my phrasing
Hi Tim,
There are two main problems with your implementation of Stochastic gradient
algorithm:
1. You are only implementing one cycle of the algorithm, i.e. it cycles over
each data point only once. You need to do this several time, until convergence
of parameters is obtained.
2.
Jarek Jasiewicz wrote:
I tried several mirrors
But, what may be more important.
This error was mentioned earlier on VISTA and WindowsXP, I use Ubuntu 8.04
Unfortunately, I cannot reproduce this for sp on Windows XP.
Uwe
Uwe Ligges pisze:
Jarek Jasiewicz wrote:
since 2.9.0 version I
On Apr 26, 2009, at 11:20 AM, Neotropical bat risk assessments wrote:
How do people deal with R and memory issues?
They should read the R-FAQ and the Windows FAQ as you say you have.
On Sun, 26 Apr 2009 09:20:12 -0600 Neotropical bat risk assessments
neotropical.b...@gmail.com wrote:
NBRA
NBRAHow do people deal with R and memory issues?
NBRAI have tried using gc() to see how much memory is used at each
NBRA step. Scanned Crawley R-Book and all other R books I have
Dear R users,
I am trying to do exact matching on a large dataset (500.000 obs), about equal
size of treatment and controll group, with replacement: As for the moment I use
the Match function of the Matching library. I match on 2 covariates and all
observations in the treatment group have at
On Sun, 26 Apr 2009, Uwe Ligges wrote:
Works for me with
library(MASS)
plot(lda(Species~., data=iris))
hence you may want to profide the data to enable us to reproduce your
problem...
He is trying to plot the results from a cross-validation. As the help
page clearly states, that is a
Seems that the latest version R version 2.9.0 (2009-04-17)
has a glitch and will not install packages. Issue with unzipping?
Works fine with R version 2.8.1 (2008-12-22)
install.packages(ff)
--- Please select a CRAN mirror for use in this session ---
trying URL
Neotropical bat risk assessments wrote:
Seems that the latest version R version 2.9.0 (2009-04-17)
has a glitch and will not install packages. Issue with unzipping?
Works fine with R version 2.8.1 (2008-12-22)
install.packages(ff)
--- Please select a CRAN mirror for use in this session
I'm trying to compare two matrices made up of bits.
doing a simple comparison of
matA == matB
yields this sort of output.
[,1] [,2] [,3] [,4] [,5] [,6]
[1,] FALSE TRUE FALSE TRUE TRUE FALSE
[2,] TRUE TRUE TRUE TRUE TRUE TRUE
[3,] FALSE TRUE FALSE FALSE FALSE TRUE
Hello,
I have a specific question regarding figure layout. I am tryng to make a 2
by 1 figure but I would like to make the bottom figure slightly larger than
the top figure. I have read through the help posts and have tried to use
fig=c(),new=T and have also tried to use split.screen and
i am using vglm for multiple logistic regression.
i have 1 response variable (total 4 category)
and 5 predictor.
Call:
vglm(formula = class ~ PC1 + PC2 + PC3 + PC4 + PC5, family = multinomial(),
na.action = na.pass)
Coefficients:
(Intercept):1 (Intercept):2 PC1:1 PC1:2
I have a small database (file csv):
'District';'HouseType';'Income';'PreviousCustomer';'Outcome'
'Suburban';'Detached';'High';'No';'Nothing'
'Suburban';'Detached';'High';'Yes';'Nothing'
'Rural';'Detached';'High';'No';'Responded' ... itd.
After instruction str() as a result I get:
Hello again,
In my situation, I have three variables: pretest, posttest, and cohesion.
I want to work out the correlation between postest and cohesion.
I looked at multiple sets of data and created ANOVA tables of them. However,
as pretest and postest are sometimes correlated (with a
Then post the material that would make sense for Windows.
What _does_ memory.limits() return? This _was_ asked and you did not
answer.
How many other objects do you have in your workspace?
How big are they?
Jim Holtman offered this function that displays memory occupation by
object and
Have a look at all.equal
matA - matrix(1:4, ncol = 2)
matB - matA
all.equal(matA, matB)
matB[1,1] - -10
all.equal(matA, matB)
HTH,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research
Peter Dalgaard wrote:
Nigel Birney wrote:
Hello all,
Apologize for the newbie question. What's the easiest way to do a SQL
inner
table join in R?
Say I have a table containing column names A, B, C and another which has
columns named C, D, E. I would like to do an inner table join on C and
I'm not sure I'm following you but have you tried,
identical(matrix(c(1,1,1,1),ncol=2), matrix(c(1,1,1,1),ncol=2))
?all.equal
?isTRUE
?identical
and possibly the compare package,
compare(matrix(c(1,1,1,1),ncol=2),matrix(c(1,1,1,1),ncol=2))
HTH,
baptiste
On 26 Apr 2009, at 18:02, Esmail
unfortunately this problem is difficult do reproduce. If no, it would be
mentioned and removed earlier.
It probably heppens in some specific cirumstances. I I look for that
Jarek
Uwe Ligges pisze:
Jarek Jasiewicz wrote:
I tried several mirrors
But, what may be more important.
This error
On Apr 26, 2009, at 1:02 PM, Esmail wrote:
I'm trying to compare two matrices made up of bits.
doing a simple comparison of
matA == matB
identical( matrix((1:4), ncol=2), matrix((1:4), nrow=2))
[1] TRUE
identical( matrix((1:4), ncol=2), matrix((2:5), nrow=2))
[1] FALSE
yields
baptiste auguie wrote:
I'm not sure I'm following you but have you tried,
identical(matrix(c(1,1,1,1),ncol=2), matrix(c(1,1,1,1),ncol=2))
?all.equal
?isTRUE
?identical
and possibly the compare package,
compare(matrix(c(1,1,1,1),ncol=2),matrix(c(1,1,1,1),ncol=2))
HTH,
baptiste
Hi
ONKELINX, Thierry wrote:
Have a look at all.equal
matA - matrix(1:4, ncol = 2)
matB - matA
all.equal(matA, matB)
matB[1,1] - -10
all.equal(matA, matB)
Hi Thierry,
Thanks, all.equal does indicate if it's all equal so that
works great!
Much nicer than my hack - thanks,
Esmail
hesicaia a écrit :
Hello,
I have a specific question regarding figure layout. I am tryng to make a 2
by 1 figure but I would like to make the bottom figure slightly larger than
the top figure. I have read through the help posts and have tried to use
fig=c(),new=T and have also tried to
After a year my R programming style is still very C like.
I am still writing a lot of for loops and finding it difficult to recognize
where, in place of loops, I could just do the
same with one line of code, using sapply, lapply, or the like.
On-line examples for such high level function do not
I think you can replace your 'for' loop with vectorized operations:
if(NW 0){
Rnorm - Rnorm + sum(abs(Y[Nstart:(Nstart + NW - 1)]) ^ 2)
}
On Sun, Apr 26, 2009 at 1:42 PM, mau...@alice.it wrote:
After a year my R programming style is still very C like.
I am still writing a lot of
drmh douglasrmhol...@googlemail.com wrote
Hello again,
In my situation, I have three variables: pretest, posttest, and cohesion.
I want to work out the correlation between postest and cohesion.
cor(cohesion, posttest) gives you this.
I looked at multiple sets of data and created ANOVA
Also you don't need the abs since you are
squaring it anyways and seq with length
argument is a bit cleaner:
ix - seq(Nstart, length = NW)
sum(Y[ix]^ 2)
Also please read the last line on every
message to r-help. The code in your
post lacks all 4 of the asked for
ingredients: 1. there are no
On 4/26/09, Qifei Zhu zhu_qi...@yahoo.com.sg wrote:
Hi David,
Thanks! It looks much better now. but is there any way to add (x,y)
coordinates as labels to all the points in the graph? Best case if I can
enforce some conditions saying if (y10,000) label, else no label. Any
advice is
Hello,
I would like to generate ramified structures like plant root systems, river
networks or trees and save the generated structure as an image. Does anyone
knows if there is a way to do that with R?
Thank you in advance,
Talita
[[alternative HTML version deleted]]
On FC10 with openmpi and mpich2 installed, the command R CMD INSTALL
Rmpi_0.5-7.tar.gz --configure-args=--with-mpi=/usr/lib64/openmpi (or
/usr/lib64/mpich2) fails with the error ''cannot find mpi.h. Doing a
(s)locate indicates no header file labeled as such. Would appreciate
any trailheads.
TIA,
Hi,
I'm trying to use Information Gain for feature selection.
There is a InfoGain implementation in Weka:
*weka.attributeSelection.InfoGainAttributeEval*
Is it possible to use this function with RWeka? If yes how?
list_Weka_interfaces doesn't show it and there is no make function for
On 26/04/2009, at 3:56 PM, Rebecca1117 wrote:
I am new in R.
I can simulate Arma, using Arima.sim
However, I want to simulate an Arima Model. Say (1-B)Zt=5+(1-B)at.
I do not
know how to deal with 5 in this model.
Can any one could help me?
Thank you very much!
If this is a homework
Hi there,
I have one problem calculating an linear mixed model.
I have a repeated measurement project for several gases. These were measured in
3 different altitudes (sites) and three different positions within these sites
(plot). each I now wanted to find out if the gasfluxes rather depend
I was trying to resist responding to this question since the original
questioner
had already been admonished twice last october about asking questions
on R-help about posted code that was not only not a part of R-base,
but not even a part of an R package. But the quoted comment about
Stata is
I just installed Ubuntu 9.04 but there does not seem to be repository for
binaries for this version. Are there going to be such repositories set up in
the near future?
Tom
--
View this message in context:
http://www.nabble.com/R-64-bit-for-Ubuntu-9.04-64-bit-tp23246229p23246229.html
Sent
Hello,
my first attempt at installing version 2.9.0 failed
because I got an error
Error in library(pspline) : there is no package called 'pspline'
Later I realised that this comes from HOME/.RProfil, and removing
that files solves that problem.
However, I'm actually glad that this error
Tena koe Ken
Would something along the following lines do what you require:
set.seed(1)
x - runif(100)
y - rep(NA, length(x))
y[x0.25] - -1
y[x0.75] - 1
y[-1][y[-length(y)]%in%1 (x[-1]=0.25 x[-1]0.5)] - 0
# etc
HTH
Peter Alspach
-Original Message-
From:
On 26 April 2009 at 13:25, Tom La Bone wrote:
| I just installed Ubuntu 9.04 but there does not seem to be repository for
| binaries for this version. Are there going to be such repositories set up in
| the near future?
As I understand it Michael and Vincent are working on it right now.
This
On 26 April 2009 at 14:50, Vince Fulco wrote:
| On FC10 with openmpi and mpich2 installed, the command R CMD INSTALL
| Rmpi_0.5-7.tar.gz --configure-args=--with-mpi=/usr/lib64/openmpi (or
| /usr/lib64/mpich2) fails with the error ''cannot find mpi.h. Doing a
| (s)locate indicates no header file
Agreed on the redirect to SIG. mpich2-devel and -libs are installed.
V.
On Sun, Apr 26, 2009 at 4:51 PM, Dirk Eddelbuettel e...@debian.org wrote:
On 26 April 2009 at 14:50, Vince Fulco wrote:
| On FC10 with openmpi and mpich2 installed, the command R CMD INSTALL
| Rmpi_0.5-7.tar.gz
Thanks for your replies. I ended up using the following:
df = data.frame(year
=c(1991,1991,1992,1992,1993,1993,1992,1991),x=rnorm(8),y=rnorm(8))
df
year x y
1 1991 0.5565083 -1.31364232
2 1991 0.1686598 -0.20344656
3 1992 -0.1010090 -0.65681852
4 1992 0.6130324
Hi there,
I would like to make a 'bumps chart' like the ones described e.g.
here: http://junkcharts.typepad.com/junk_charts/bumps_chart/
Purpose: I'd like to plot the proportion of people in select countries
living for less then one USD pr day in 1994 and 2004 respectively. I
have already
Have a look at the plyr package and associated documentation -
http://had.co.nz/plyr
Hadley
On Sun, Apr 26, 2009 at 12:42 PM, mau...@alice.it wrote:
After a year my R programming style is still very C like.
I am still writing a lot of for loops and finding it difficult to recognize
where,
In statistics, a bumps chart is more commonly called a parallel
coordinates plot.
Hadley
On Sun, Apr 26, 2009 at 5:45 PM, Andreas Christoffersen
achristoffer...@gmail.com wrote:
Hi there,
I would like to make a 'bumps chart' like the ones described e.g.
here:
Have a look at plotweb in the bipartite package.
On Sun, Apr 26, 2009 at 6:45 PM, Andreas Christoffersen
achristoffer...@gmail.com wrote:
Hi there,
I would like to make a 'bumps chart' like the ones described e.g.
here: http://junkcharts.typepad.com/junk_charts/bumps_chart/
Purpose: I'd
Hi!
I'm manipulating XLSX data using RODBC, however a limitation which appears
to be driver based is that you can't clear or drop sheets from the XLSX
files, as per the following example:
library(RODBC)
xlsx-odbcDriverConnect(DRIVER=Microsoft Excel Driver (*.xls, *.xlsx,
*.xlsm,
The code below shows what I'm trying to get rid of.
If there is no way to get rid of the loop, I will try to use package( inline
).
I'm just curious as to whether there is a vector way of doing this
algorithm.
#
Here's a ggplot2 based solution:
#load the ggplot2 library
library(ggplot2)
#here's the data provided by Andreas
countries - c(U-lande, Afrika syd for sahara, Europa og
Centralasien, Lantinamerika og Caribien,Mellemøstenog
Nordafrika,Sydasien,ØStasien og stillehaveet, Kina,
Brasilien)
poor_1990
I all,
I want to create a graph layout in a 3x3 matrix like this:
ylab |__| |__| |__|
___ ___ ___
ylab |__| |__| |__|
___ ___ ___
ylab |__| |__| |__|
xl xl xl
With this layout, then I'll insert the 9 plots. How ca I create it?
--
CdeB
Hi.
Is there an analog to abline() that can be used to plot a polynomial fit?
For example, I can draw the straight-line fit
fit - lm(y ~ x)
via
abline(coef=fit$coef)
but I'm not sure how to draw the polynomial fit
fit - lm(y ~ poly(x,2))
I do see the function curve(), but not
Try using RDCOMClient or rcom:
library(RDCOMClient)
xl - COMCreate(Excel.Application)
# next line optional
xl[[Visible]] - TRUE
wb - xl[[Workbooks]]$Open(/mydir/sample.xlsx)
sheet - wb$Sheets(Sheet2)
xl[[DisplayAlerts]] - FALSE
1 - 100 of 112 matches
Mail list logo
