On Wed, Nov 03, 2010 at 11:02:12AM +0000, Dave Malham wrote: > Something else - are you solving for face mounted or vertices mounted > speakers?
There are 20 speakers, positions correspond to the faces of an icosahedron or the vertices of a dodecahedron. 12 wouldn't work for 3rd order, you need more speakers than channels. Since there are 4 more speakers than channels, and this layout is regular, I'd expect this to work. As it does for 2nd order (12 speakers, faces of a dedocahedron), or 1st order (8 speakers, vertices of a cube), Or for any order horizontal only with 2 * (order + 1) speakers. I'll send a picture later, don't have them on this PC. Ciao, -- FA There are three of them, and Alleline. _______________________________________________ Sursound mailing list Sursound@music.vt.edu https://mail.music.vt.edu/mailman/listinfo/sursound
