In reply to  Axil Axil's message of Fri, 16 Oct 2015 21:11:02 -0400:
Hi,
[snip]
>The energy from muon decay leaves electrons and the remainder of this
>energy is reabsorbed back into the SPP soliton. 

I would expect a fair amount to be lost in neutrinos. Only that which remained
with the electrons would be retrieved.

>All the while more muons
>are generated in a continuing cycle from the SPPs. The Solitons are also
>slowly decaying through the emission of hawking radiation in the infrared
>range, This is part of the thermalization of high energy radiation. Also,
>these SPPs explode in a bosenova when they reach energy storage capacity,
>they then release XUV and soft x-rays which will also thermalize.

You still haven't mentioned how you came by the figure of 64 GeV.

BTW are you also assuming that the muons remain trapped?
If so, why bother with them at all?  (...since they would then behave as though
they were virtual particles). In the Hawking radiation decay, you already have a
mechanism for converting the reaction energy into thermal photons.

How have you determined that said photons should be in the infrared?

>
>On Fri, Oct 16, 2015 at 8:40 PM, <[email protected]> wrote:
>
>> In reply to  Axil Axil's message of Fri, 16 Oct 2015 20:14:29 -0400:
>> Hi,
>> [snip]
>> >This is called super-absorption. The energy release would be spread
>> equally
>> >throughout a BEC of a billon coherent solitons each getting a few hundred
>> >thousand electron volts. These solitons store energy. Their energy holding
>> >capacity is 64 GeV each but most hold far less.
>>
>> I'm curious how you come by this figure?
>>
>> >Then there is the energy
>> >that produce subatomic particles such as muon and mesons. These particles
>> >need a lot of energy devoted to their creation. The release of energy is
>> >buffered by these subatomic particles because they have a relatively long
>> >lifetime.  Muons decay over a very long time and release their energy
>> >content very slowly.
>>
>> Even assuming all the energy is converted into muons, a 2 micro-second
>> half-life
>> means that they are almost all gone within 10-20 micro-seconds. That's
>> still an
>> explosion (unless they all leave the reactor before they decay, but in
>> that case
>> the reactor produces no usable energy).
>> Regards,
>>
>> Robin van Spaandonk
>>
>> http://rvanspaa.freehostia.com/project.html
>>
>>
Regards,

Robin van Spaandonk

http://rvanspaa.freehostia.com/project.html

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