In reply to Jürg Wyttenbach's message of Sun, 21 Jul 2019 18:39:48 +0200: Hi, [snip] >Bob > >One reason why the D* path is working like adding +2p/2e could be that >the internal electron from the neutron only needs to do a little push to >get to the k-shell. Thus no need to emit an electron!
K shells are not usually vacant, so such an electron would still upset things. Regards, Robin van Spaandonk local asymmetry = temporary success
