Fair enough.
I have little time to give a complete course on parse so I went for
the shortest version. I expected to see a few other responses to this
thread as well and sure enough the old-time REBOL-masters of the
outside world give a more full answer than us insiders have time for.
Take it easy guys,
Sterling
> Hi Sterling,
>
> one little detail: your approach works well enough with this particular
> example because space is one of the desired delimiters.
>
> Conceivably Tim may want a more universal solution that enables him to
> determine whether or not he wants to include spaces in his parse rule. In
> that case IMHO it would be more appropriate to use parse's all refinement
> and - for the sake of this particular example - include space explicitly as
> a delimiter in the rule:
>
> With space:
> >> parse/all "one#two%three four" "%# "
> == ["one" "two" "three" "four"]
>
> Without space
> >> parse/all "one#two%three four" "%#"
> == ["one" "two" "three four"]
>
> Note that the second version returns "three four" as one string because
> space is not included in the rule.
>
