Re: Need help installing PHP (Linux) with MySQL and Apache

2002-10-22 Thread John Coder
On Mon, 2002-10-21 at 13:07, Chip Rose wrote:
 I can't get PHP-4.2.3 compiled to work with MySQL and Apache, despite months 
 of trying.  Apache compiled ok, and so did MySQL -both work, on my Debian 
 Linux box.
 
 I've tried various combos of installing the Deb packages, compiling from 
 source, and various combinations thereto.  I started out using 
 http://hotwired.lycos.com/webmonkey/00/44/index4a_page4.html?tw=programming 
 as a guide, in efforts to create a way of accessing MySQL via PHP Gui of some 
 sort.  I've been trying for months, on and off, using Redhat, Mandrake, and 
 now Debian3.0.  I've tried getting Escapade installed, but pages won't load 
 unless I change a line in httpd.conf, and then Apache won't run because it 
 complains of the changed line in httpd.conf, which was supposedly necessary 
 to get Escapade to run.
 
 Typing ./httpd -l in my Apache bin directory shows that mod_so.c is an 
 enabled module.  My attempt to compile PHP-4.2.3 by typing 
 ./configure --with-mysql=/usr/bin/  resulted in the following error message
 configure: error: Cannot find header files under /usr/bin/
 
 I've tried changing the path to MySQL headers, but still get same error msg.  
 I really don't know how to find these MySQL headers since I wouldn't know one 
 if I saw it.
 
 Can someone help with a pointer/link?  I'd very greatly appreciate it..
 if Mysql was installed by rpm try pointing it to /var/lib/mysql. 
if compiled by yourself it's the directory you untarred and ran make/
make install.

John


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re: need help mysql-server lost the tcp/ip-connection

2002-10-16 Thread Egor Egorov

Hello jantos,

Tuesday, October 15, 2002, 2:03:50 PM, you wrote:

jamdd when I'm connecting to mysql-server via tcp/ip then the mysql-server
jamdd cuts the connection and it restarts the mysql-server. 
jamdd when I don't make connections from other hosts than it's running well 
jamdd until i make connections via tcp/ip from other hosts.

jamdd on the client site:
jamdd mysql -h Mymysql-server
jamdd and I allways get:
jamdd ERROR 2013: Lost connection to MySQL server during query

jamdd on the server-host I get the message:
jamdd  bin/safe_mysqld: line 273: 11987 Segmentation fault  
$NOHUP_NICENESS $ledir/$MYSQLD $defaults --basedir=$MY_BASEDIR_VERSION 
--datadir=$DATADIR $USER_OPTION
jamdd --pid-file=$pid_file --skip-locking $err_log 21

jamdd Number of processes running now: 1
jamdd mysqld process hanging, pid 11990 - killed
jamdd 021015 12:37:53  mysqld restarted

Release:   mysql-3.23.53-max (Official MySQL-max binary)


As this is the official MySQL binary statically linked, I would first
try to upgrade the kernel, but just to be sure that the kernel is not
the source of a problem.

Then I'd go with the hardware as often such things happens because of
broken memory, kernel panics and such. Try to see what dmesg
outputs - maybe there are a clue on hardware failures?..



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Re: Need help with simple problem... I think

2002-09-27 Thread Clayburn W. Juniel, III

On Thursday, September 26, 2002, at 10:46 AM, Darrell A. Sullivan, II 
wrote:

 I am sure I am going to feel ignorant when I get the answer to this 
 question
 because it will be something simple that I have overlooked, but here 
 goes
 anyhow.

 I am using MySQL Version 3.23.51-max.

 I am developing an N-tier application using Java on the server side
 accessing MySQL through JDBC.

 On one of my tables whenever someone makes a change to the record, 
 what I
 actually need to do is create a new record that is an exact copy of the
 existing record and apply the changes to it and set a deactivation 
 date on
 the original record so that it can later be viewed and we can see when 
 it
 was active and when it was deactivated.

 My problem is that I can't seem to put the SQL together to do this. You
 can't do an Insert...Into where the destination table also appears 
 in the
 From clause.

 What I need is something like insert into t1 select * from t1 where
 t1.ID=x. I have looked into the Select statement to see if there 
 was a
 way to do a Select t1.* into t2 temp from t1 where t1.id=x to create 
 a
 temporary table and then do an insert into t1 select * from t2, but 
 so far
 I can't see any way of doing this.

 It could be done in code by doing a select and rounding up all the 
 names of
 the fields except for the primary key and then creating an insert
 statement using the field names and values, but if there is a simpler 
 and
 less convoluted way of going about it I would prefer it.

Try this:

Create Temporary Table temp_table Select * From t1 Where ID = 'x';
Update temp_table Set ActivationDate = Now() where ID = 'x';
Insert into ti select * from temp_table where ID = 'x';

When I tried this a got a table already exist error on the first line, 
but the table was created correctly.  I also got an error on the third 
line but again it was entered correctly.

--
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Phone: (602) 326-7707Mobile: (602)326-7707
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Re: need help on DROP.

2002-09-10 Thread Paul DuBois

At 16:26 -0700 9/10/02, Daniel Curry wrote:
   I am unable to find the specific DROP command to remove only test@%,
test\_%@%,
snort@localhost, and snort@%.

I think you want DELETE, not DROP.

DELETE FROM db WHERE Db='test' AND Host='%';
DELETE FROM db WHERE Db='test\_' AND Host='%';
DELETE FROM db WHERE Db='snort' AND Host='localhost';
DELETE FROM db WHERE Db='snort' AND Host='%';


   I am trying to clean up my db information.

Thank you.


mysql select * from db;
+---+--++-+-+-+-+-+---++-+++
| Host  | Db   | User   | Select_priv | Insert_priv |
Update_priv | Delete_priv | Create_priv | Drop_priv | Grant_priv |
References_priv | Index_priv | Alter_priv |
+---+--++-+-+-+-+-+---++-+++
| % | test || Y   | Y   |
Y   | Y   | Y   | Y | N  |
Y   | Y  | Y  |
| % | test\_%  || Y   | Y   |
Y   | Y   | Y   | Y | N  |
Y   | Y  | Y  |
| localhost | snort| snort  | Y   | Y   |
Y   | Y   | Y   | N | N  |
N   | N  | N  |
| % | snort| snort  | Y   | Y   |
Y   | Y   | Y   | N | N  |
N   | N  | N  |
| localhost | snort_db | snort  | Y   | Y   |
Y   | Y   | N   | N | N  |
N   | N  | N  |
| % | snort_db | snort  | Y   | Y   |
Y   | Y   | N   | N | N  |
N   | N  | N  |
+---+--++-+-+-+-+-+---++-+++
6 rows in set (0.00 sec)

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Re: need help on DROP.

2002-09-10 Thread Daniel Curry

Paul,
  Thank you.  That did it.
You are correct I needed to DELETE.


Paul DuBois wrote:
 
 At 16:26 -0700 9/10/02, Daniel Curry wrote:
I am unable to find the specific DROP command to remove only test@%,
 test\_%@%,
 snort@localhost, and snort@%.
 
 I think you want DELETE, not DROP.
 
 DELETE FROM db WHERE Db='test' AND Host='%';
 DELETE FROM db WHERE Db='test\_' AND Host='%';
 DELETE FROM db WHERE Db='snort' AND Host='localhost';
 DELETE FROM db WHERE Db='snort' AND Host='%';
 
 
I am trying to clean up my db information.
 
 Thank you.
 
 
 mysql select * from db;
 
+---+--++-+-+-+-+-+---++-+++
 | Host  | Db   | User   | Select_priv | Insert_priv |
 Update_priv | Delete_priv | Create_priv | Drop_priv | Grant_priv |
 References_priv | Index_priv | Alter_priv |
 
+---+--++-+-+-+-+-+---++-+++
 | % | test || Y   | Y   |
 Y   | Y   | Y   | Y | N  |
 Y   | Y  | Y  |
 | % | test\_%  || Y   | Y   |
 Y   | Y   | Y   | Y | N  |
 Y   | Y  | Y  |
 | localhost | snort| snort  | Y   | Y   |
 Y   | Y   | Y   | N | N  |
 N   | N  | N  |
 | % | snort| snort  | Y   | Y   |
 Y   | Y   | Y   | N | N  |
 N   | N  | N  |
 | localhost | snort_db | snort  | Y   | Y   |
 Y   | Y   | N   | N | N  |
 N   | N  | N  |
 | % | snort_db | snort  | Y   | Y   |
 Y   | Y   | N   | N | N  |
 N   | N  | N  |
 
+---+--++-+-+-+-+-+---++-+++
 6 rows in set (0.00 sec)
 
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Re: need help on DROP.

2002-09-10 Thread Gerald R. Jensen

Clarify your question ... are you trying to drop TABLES, DATABASES, or
modify user privileges?

If you are trying to modify user privileges, use GRANT or REVOKE.

- Original Message -
From: Daniel Curry [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, September 10, 2002 6:26 PM
Subject: need help on DROP.



  I am unable to find the specific DROP command to remove only test@%,
test\_%@%,
snort@localhost, and snort@%.

  I am trying to clean up my db information.

Thank you.


mysql select * from db;
+---+--++-+-+---
--+-+-+---++-+--
--++
| Host  | Db   | User   | Select_priv | Insert_priv |
Update_priv | Delete_priv | Create_priv | Drop_priv | Grant_priv |
References_priv | Index_priv | Alter_priv |
+---+--++-+-+---
--+-+-+---++-+--
--++
| % | test || Y   | Y   |
Y   | Y   | Y   | Y | N  |
Y   | Y  | Y  |
| % | test\_%  || Y   | Y   |
Y   | Y   | Y   | Y | N  |
Y   | Y  | Y  |
| localhost | snort| snort  | Y   | Y   |
Y   | Y   | Y   | N | N  |
N   | N  | N  |
| % | snort| snort  | Y   | Y   |
Y   | Y   | Y   | N | N  |
N   | N  | N  |
| localhost | snort_db | snort  | Y   | Y   |
Y   | Y   | N   | N | N  |
N   | N  | N  |
| % | snort_db | snort  | Y   | Y   |
Y   | Y   | N   | N | N  |
N   | N  | N  |
+---+--++-+-+---
--+-+-+---++-+--
--++
6 rows in set (0.00 sec)

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Re: need help on a SQL query: need LEFT JOIN?

2002-09-07 Thread Luís Fernando

You wrote:

 I apologize for asking such a basic SQL question, but I am failing in
finding
 the solution...
 Consider the following table:

 id | option
 ---
 1  | a
 2  | a
 2  | b

 I want to find the ids with only a specific set of options.
 For example, if I wanted to get the ids which have option a only, the
query
 should give me 1 as a result, not 1 and 2.

 I suspect I need to use a LEFT JOIN on the same table, but I have failed
 miserably so far...

 Many thanks in advance to the SQL experts ;-).

 Jean-Luc (http://jfontain.free.fr/moodss/)


There are no need to use the left join in this query. The best way to do
what you wanna is within the following query:

SELECT id FROM table GROUP BY id HAVING COUNT(option) = 1;

You can change the count value to take the ids that have
specified number of options.

Luís Fernando


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Re: need help on a SQL query: need LEFT JOIN?

2002-09-06 Thread jfontain

I wrote:
I apologize for asking such a basic SQL question, but I am failing in finding 
the solution...
Consider the following table:
id | option
---
1  | a
2  | a
2  | b
I want to find the ids with only a specific set of options.
For example, if I wanted to get the ids which have option a only, the query 
should give me 1 as a result, not 1 and 2.
I suspect I need to use a LEFT JOIN on the same table, but I have failed 
miserably so far...
Many thanks in advance to the SQL experts ;-).

Thank you very much to all for your responses: it led me to the solution and in 
the process improved my SQL level:

select id
from t left join t as u
on (t.id = u.id) and (t.option = u.option) and (
  (t.option = 'a') or (t.option = 'b') or ...
)
group by t.id
having (count(*) = count(u.id)) and (count(*) = N)

* with N = number of options to match

Thanks again!

Jean-Luc (http://jfontain.free.fr/moodss/)


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Re: need help on a SQL query: need LEFT JOIN?

2002-09-05 Thread Jed Verity

Does this work?

select t.id,t.option,t2.option from tableName t left join tableName t2 on
t.id=t2.id and t2.option!=t.option where t.option=a and isnull(t2.option);

HTH,
Jed

On the threshold of genius, [EMAIL PROTECTED] wrote:

 I apologize for asking such a basic SQL question, but I am failing in finding
 the solution...
 Consider the following table:
 
 id | option
 ---
 1  | a
 2  | a
 2  | b
 
 I want to find the ids with only a specific set of options.
 For example, if I wanted to get the ids which have option a only, the query
 should give me 1 as a result, not 1 and 2.
 
 I suspect I need to use a LEFT JOIN on the same table, but I have failed
 miserably so far...
 
 Many thanks in advance to the SQL experts ;-).
 
 Jean-Luc (http://jfontain.free.fr/moodss/)
 
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Re: Need help with Statically Compiled MySQLGUI 1.7.5-1

2002-09-05 Thread Egor Egorov

PathFinder,
Wednesday, September 04, 2002, 10:25:46 PM, you wrote:

PS I am a not yet that experienced with System Administration and
PS need a little holding hand here if possible.

PS I am running Red Hat 6.2 with MySQL installed and running.

PS Frankly I have read the README and HELP and still not sure as to
PS what I am suppose to do with the my.cnf.

PS When I try to run it with the ./my.cnf from the directory where
PS MySQLGUI 1.7.5-1 is installed here is the error message I get:

PS [root@mail mysqlgui-1.7.5-1-linux-static]# ./my.cnf

PS ./my.cnf: [client]: command not found
PS ./my.cnf: port: command not found
PS Using domain server:
PS Name: localhost.track2you.com
PS Address: 127.0.0.1
PS Aliases:

PS Host not found.
PS ./my.cnf: [client_fltk]: command not found
PS ./my.cnf: database: command not found

Where can my.cnf be located read here:
  http://www.mysql.com/doc/en/Option_files.html





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Re: Need help with Statically Compiled MySQLGUI 1.7.5-1

2002-09-05 Thread Gerald Clark

It is just a config file.
You don't run it.

PathFinder Software wrote:

Hi,

I am a not yet that experienced with System Administration and
need a little holding hand here if possible.

I am running Red Hat 6.2 with MySQL installed and running.

Frankly I have read the README and HELP and still not sure as to
what I am suppose to do with the my.cnf.

When I try to run it with the ./my.cnf from the directory where
MySQLGUI 1.7.5-1 is installed here is the error message I get:

[root@mail mysqlgui-1.7.5-1-linux-static]# ./my.cnf

./my.cnf: [client]: command not found
./my.cnf: port: command not found
Using domain server:
Name: localhost.track2you.com
Address: 127.0.0.1
Aliases:

Host not found.
./my.cnf: [client_fltk]: command not found
./my.cnf: database: command not found



Can you walk me though with what to do and perhaps how to
configure the my.cnf?

Your time is appreciatted.

Regards,

Normand J. Charette
PathFinder Software/Affiliate Software
[EMAIL PROTECTED]
[EMAIL PROTECTED]
http://www.PathFinderSoftware.com
http://www.AffiliateTrackingSoftware.com


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Re: Need help how to make Directory system in MySQL with 6.5 mill subscribers ?

2002-08-14 Thread Tod Harter

On Tuesday 13 August 2002 06:50 pm, Steinar Kolnes wrote:

Just create indexes on first and last, that should improve the speed of your 
query drastically. It will of course be a BIG index. You might experiment 
with only making the width of the index small, like maybe 8 or 10 characters 
might be enough to get 99% of the benefit with a lot less size. You might 
experiment with only indexing last names as well, the query optimizer should 
then use that index first and will thus only have to do linear search through 
the resulting candidate records.

I think the design of your table is fine. Note that adding NOT NULL to a 
column's definition saves you a small amount of space per row, and you 
probably don't want nulls anyway. 

 Hi there,

 I have to make a large 6.5 million names and numbers database in
 MySql(maybe not so
 large for some of you). Yet it is very simple, here is my sql file:

 create table subscriber
 (
 idbigint unsigned not null auto_increment 
primary key,
 subscr_id bigint unsigned,
 telco_id  int unsigned,
 first char (80),
 last  char (40),
 address   char (40),
 postcodeint unsigned
 );

 NB I also merged first and middle names into one first;

 All the above should be searchable.
 I have a separate table that take cares of postcodes and post names.

 However the search is very slow. It takes more than 3 minutes for a query
 to search for
 first and last name;

 Example:
 select * from subscriber where first like 'steinar%' and last like
 'kolnes%';


 Is there any out there that have an suggestion how I can speed things up,
 even if I increases the size to more than 10 mill.

 I planned to have separate tables for first, last and street addresses,
 however is this a good idea ?

 Rgs
 Steinar Kolnes




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Re: Need help how to make Directory system in MySQL with 6.5 millsubscribers ?

2002-08-14 Thread Joseph Bueno

Hi,

The best way to speed up your query would be to create a compound index 
on (first,last):
create index first_last on subscriber(first,last);
In this case, mysql will use it for both fields instead of doing a 
linear search for the second one.

In order to reduce index size without loosing too much speed, you can 
also index a subset of each field:
create index first_last on subscriber(first(8),last(8));

Hope this helps
-- 
Joseph Bueno

Tod Harter wrote:
 On Tuesday 13 August 2002 06:50 pm, Steinar Kolnes wrote:
 
 Just create indexes on first and last, that should improve the speed of your 
 query drastically. It will of course be a BIG index. You might experiment 
 with only making the width of the index small, like maybe 8 or 10 characters 
 might be enough to get 99% of the benefit with a lot less size. You might 
 experiment with only indexing last names as well, the query optimizer should 
 then use that index first and will thus only have to do linear search through 
 the resulting candidate records.
 
 I think the design of your table is fine. Note that adding NOT NULL to a 
 column's definition saves you a small amount of space per row, and you 
 probably don't want nulls anyway. 
 
 
Hi there,

I have to make a large 6.5 million names and numbers database in
MySql(maybe not so
large for some of you). Yet it is very simple, here is my sql file:

create table subscriber
(
idbigint unsigned not null auto_increment 
primary key,
subscr_id bigint unsigned,
telco_id  int unsigned,
first char (80),
last  char (40),
address   char (40),
postcodeint unsigned
);

NB I also merged first and middle names into one first;

All the above should be searchable.
I have a separate table that take cares of postcodes and post names.

However the search is very slow. It takes more than 3 minutes for a query
to search for
first and last name;

Example:
select * from subscriber where first like 'steinar%' and last like
'kolnes%';


Is there any out there that have an suggestion how I can speed things up,
even if I increases the size to more than 10 mill.

I planned to have separate tables for first, last and street addresses,
however is this a good idea ?

Rgs
Steinar Kolnes





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RE: Need help how to make Directory system in MySQL with 6.5 mill subscribers ?

2002-08-13 Thread Mike Hillyer

You need an index, it should drastically cut the query time. See:
http://www.mysql.com/doc/en/CREATE_INDEX.html#IDX1466

Mike Hillyer
Dynamergy Software


-Original Message-
From: Steinar Kolnes [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, August 13, 2002 4:50 PM
To: Mysql List
Subject: Need help how to make Directory system in MySQL with 6.5 mill
subscribers ?


Hi there,

I have to make a large 6.5 million names and numbers database in MySql(maybe
not so
large for some of you). Yet it is very simple, here is my sql file:

create table subscriber
(
id  bigint unsigned not null auto_increment primary key,
subscr_id   bigint unsigned,
telco_idint unsigned,
first   char (80),
lastchar (40),
address char (40),
postcode  int unsigned
);

NB I also merged first and middle names into one first;

All the above should be searchable.
I have a separate table that take cares of postcodes and post names.

However the search is very slow. It takes more than 3 minutes for a query to
search for
first and last name;

Example:
select * from subscriber where first like 'steinar%' and last like
'kolnes%';


Is there any out there that have an suggestion how I can speed things up,
even if I increases the size to more than 10 mill.

I planned to have separate tables for first, last and street addresses,
however is this a good idea ?

Rgs
Steinar Kolnes




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Re: Need help how to make Directory system in MySQL with 6.5 mill subscribers ?

2002-08-13 Thread Dan Nelson

In the last episode (Aug 14), Steinar Kolnes said:
 I have to make a large 6.5 million names and numbers database in
 MySql(maybe not so large for some of you). Yet it is very simple,
 here is my sql file:
 
 create table subscriber
 (
 id bigint unsigned not null auto_increment primary key,
 subscr_id  bigint unsigned,
 telco_id   int unsigned,
 first  char (80),
 last   char (40),
 addresschar (40),
 postcode   int unsigned
 );
 
 NB I also merged first and middle names into one first;

You'll probably want to split them back out.  That means you can't
index the middle name all by itself (if you ever needed to), and it
means that even if you only want to index the first name, you have to
pull in all the middle-name data as well.

Also change your CHARs to VARCHAR; you're probably wasting a lot of
space in the table.  What percentage of first names are over 15
characters, let alone 40?
 
 All the above should be searchable. I have a separate table that take
 cares of postcodes and post names.
 
 However the search is very slow. It takes more than 3 minutes for a
 query to search for first and last name;
 
 Example:
 select * from subscriber where first like 'steinar%' and last like 'kolnes%';

That's because you're doing a full table scan of a table that's at
minimum 6.5MB * 180 = 1.1gb :)  Although that only comes out to a data
rate of 7MB/sec; mysql should have been able to scan much faster than
that.

If most of your searches are likeyour example, try creating an index on
the first 5 characters of first and last.  Also create a separate
index on last.  Searches on firstname or first+last will use the
combined index; searches on lastname will use the lastname index.

ALTER TABLE mytable 
ADD KEY ( first(5), last(5) ), 
ADD KEY ( last(5) );

Also run EXPLAIN on some test queries.  Tf the 'rows' column is still
too large or the 'key' column is NULL, try indexing the entire
first+last field (i.e. drop the (5) from the ADD KEY clause).

 Is there any out there that have an suggestion how I can speed things
 up, even if I increases the size to more than 10 mill.
 
 I planned to have separate tables for first, last and street
 addresses, however is this a good idea ?

You mean separate lookup tables?  That would definitely save space
since you will have a lot of duplicate entries.  It will complicate
searches, though, since you will have to join your primary, first, and
last tables together for the search.  It also makes modification of a
single record a lot harder (since you may have to add records to the
secondary tables if a name changes).  I'd say leave it as one table.

-- 
Dan Nelson
[EMAIL PROTECTED]

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Re: Need help with Tables/Attributes

2002-07-27 Thread Francisco Reinaldo

Hello Nitesh,

You can find that and more at...

http://www.mysql.com/doc/A/L/ALTER_TABLE.html

Good Luck,
--- Nitesh Divecha [EMAIL PROTECTED] wrote:
 Hello All,
 
 I need help with tables. I have created my table
 with some attributes in
 it. 
 
 I need to modify my table attributes, can any one
 help me with the
 modify command or can give me the short cut to the
 web.
 
 Example:
 Mysql create table test(ID int(4), Name
 varchar(20), Sex varchar(1));
 
 Now I need to change the attribute NAME TO Full
 name, HOW?
 
 Please help, Thanking in Advance.
 
 Regards
 Nitesh
 
 
 

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Re: Need help with Tables/Attributes

2002-07-27 Thread Diana Soares

Hi, 
I suppose that what you want would be something like:

Mysql create table test(ID int(4), Name varchar(20), Sex varchar(1));
Mysql alter table test change Name FullName varchar(40);

You should read this for more information about ALTER TABLE:
http://www.mysql.com/doc/A/L/ALTER_TABLE.html


On Thu, 2002-07-25 at 23:45, Nitesh Divecha wrote:
 Hello All,
 
 I need help with tables. I have created my table with some attributes in
 it. 
 
 I need to modify my table attributes, can any one help me with the
 modify command or can give me the short cut to the web.
 
 Example:
 Mysql create table test(ID int(4), Name varchar(20), Sex varchar(1));
 
 Now I need to change the attribute NAME TO Full name, HOW?
 
 Please help, Thanking in Advance.
 
 Regards
 Nitesh
-- 
Diana Soares


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Re: Need help with Tables/Attributes

2002-07-27 Thread Victoria Reznichenko

Nitesh,
Friday, July 26, 2002, 1:45:35 AM, you wrote:

ND I need help with tables. I have created my table with some attributes in
ND it. 

ND I need to modify my table attributes, can any one help me with the
ND modify command or can give me the short cut to the web.

ND Example:
ND mysql create table test(ID int(4), Name varchar(20), Sex varchar(1));

ND Now I need to change the attribute NAME TO Full name, HOW?

Use ALTER TABLE:
http://www.mysql.com/doc/A/L/ALTER_TABLE.html




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Re: Need help with Tables/Attributes

2002-07-26 Thread Ralf Narozny

Hello!

Nitesh Divecha wrote:

Hello All,

I need help with tables. I have created my table with some attributes in
it. 

I need to modify my table attributes, can any one help me with the
modify command or can give me the short cut to the web.

Example:
Mysql create table test(ID int(4), Name varchar(20), Sex varchar(1));

Now I need to change the attribute NAME TO Full name, HOW?

Please help, Thanking in Advance.
  


As far as I understood the ALTER TABLE syntax, this cannot be done that 
easily, try:

ALTER TABLE test ADD COLUMN Full_name int AFTER ID;
UPDATE test SET Full_name = Name;
ALTER TABLE test DROP COLUMN Name;

Greetings
 Ralf

sql query

-- 
Ralf Narozny
SPLENDID Internet GmbH  Co KG
Skandinaviendamm 212, 24109 Kiel, Germany
fon: +49 431 660 97 0, fax: +49 431 660 97 20
mailto:[EMAIL PROTECTED], http://www.splendid.de




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Re: Need Help with mysqlimport please-urgent!

2002-07-17 Thread Gerald R. Jensen

Don't use 'root' ... create a new user, and make sure you GRANT the proper
privs (i.e.:
USE mysql;
GRANT ALL PRIVILEGES ON *.* TO username@localhost IDENTIFIED BY
'password';
GRANT ALL PRIVILEGES ON *.* TO username@% IDENTIFIED BY 'password'
WITH GRANT OPTION;


- Original Message -
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]; [EMAIL PROTECTED]; [EMAIL PROTECTED];
[EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, July 17, 2002 5:42 AM
Subject: Need Help with mysqlimport please-urgent!


Hello,
Here is my problem, I would like to use mysqlimport (which i
have compiled as a batch file to run) from a client side to load data onto
the database on a server side, meaning that I would normally access my
server through the pc and running the batch file. Problem is that there are
no errors but the tables on the server side does not get updated but
instead points to updating my local database, data are loaded into my
tables instead (i have the exact replica database on my own pc). Here is a
sample command line from my batch file

@h:\mysql\bin\MYSQLI~1.EXE --replace --host=host_name --user=root
--fields-terminated-by=, --fields-enclosed-by=\ --lines-terminated-by
=\r\n BO h:\mysql\data\BO\outnum

i've mapped h:\ as pointing to the c:\ of my server..is that possible?
[The error relates to 'access denied for @pc_id (i think its the same
network id used for login to a NT domain) to BO database' or at times 'the
mysql does not support this version']

P.S. My table name is outnum which is the same as the file name, MySQL
version is 3.23.51.

What am i doing wrong here? Need help please (could someone guide me what
to do from the very beginning. I need to run mysqlimport as if i'm running
any program from the console itself but only from a remote terminal). To
simplify, what i need here is a way to run mysqlimport from my pc to pump
data into the tables on the MySQL server instead of the data being thrown
in my local  MySQL server.Urgent! Thank you.

Regards,
Eric Loe.

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Re: Need help on Matching MySQL, Apache PHP

2002-07-07 Thread Dicky Wahyu Purnomo

Pada Sat, 06 Jul 2002 15:10:43 +
duo fu [EMAIL PROTECTED] menulis :

 Dear Friends:
 I have installed Apache 1.3.26, MySQL.3.23.51 successfully. However, I 
 failed to install tarball versions of PHP4.21 with Apache1.3.26 under my 
 REDHAT 6.2. I always got the error message when I tried to start the APache.
 -
 [root@broekhoven libexec]# /usr/local/apache/bin/apachectl start
 Syntax error on line 205 of /usr/local/apache/conf/httpd.conf:
 Cannot load /usr/local/apache/libexec/libphp4.so into server:
 /usr/local/apache/libexec/libphp4.so: undefined symbol: pcre_malloc
 /usr/local/apache/bin/apachectl start: httpd could not be started
 
--

try to use your PHP as cgi rather than as module (change the config on httpd.conf) ... 
it should be easier if you don't want/avoid installing all from source (again) :D 

-- 
printk(??? No FDIV bug? Lucky you...\n);
2.2.16 /usr/src/linux/include/asm-i386/bugs.h
 
MySQL 3.23.51 : up 16 days, Queries : 368.312 per second (avg).

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Re: Need help on Matching MySQL, Apache PHP

2002-07-06 Thread dan radom

I would suggest you build apache and php from source.  instructions can be found at 
http://www.php.net/manual/en/install.apache.php.

dan

* duo fu ([EMAIL PROTECTED]) wrote:
 Dear Friends:
 I have installed Apache 1.3.26, MySQL.3.23.51 successfully. However, I 
 failed to install tarball versions of PHP4.21 with Apache1.3.26 under my 
 REDHAT 6.2. I always got the error message when I tried to start the APache.
 -
 [root@broekhoven libexec]# /usr/local/apache/bin/apachectl start
 Syntax error on line 205 of /usr/local/apache/conf/httpd.conf:
 Cannot load /usr/local/apache/libexec/libphp4.so into server:
 /usr/local/apache/libexec/libphp4.so: undefined symbol: pcre_malloc
 /usr/local/apache/bin/apachectl start: httpd could not be started
 
--
 
 Should I use the RPM instead of tar ball? Must I use PHP3. instead of PHP4.
 under RedHat6.2?
 Could anyone help me with this problem?
 THank you very much!
 
 Duo

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Re: Need help with a complex query

2002-06-18 Thread Jamie Tibbetts

 Try - and I mean *try* :-)
 
 SELECT Customers.* FROM Customers, Subscriptions
 LEFT JOIN Orders ON (Orders.customerid=Customer.CustomerID)
 LEFT JOIN Ordered_Items ON (Ordered_Items.orderid=Orders.id 
 (Ordered_Items.productid = '23'))
 WHERE Customers.id=Subscriptions.customerid
 AND Subscriptions.listid='2'
 AND Ordered_Items.orderid IS NULL
 AND Orders.customerid IS NULL
 AND NOT Customers.bad_email;
 
 Well, MySQL has been chugging on this one for about 15 minutes now, and
 it's
 still going. So I'm not sure if it is a problem with the query or the
 optimization of my MySQL databases. There are 30,000+ records in the
 Customers database, but the query should have finished by now, right?
 
 Well, my best guess is that you should consider indexing your tables...
 If you haven't done so already, indexing will cause dramatic effect on
 the speed of the queries...
 
 Peter Normann

Okay. I've indexed all fields involved, and I've gotten the query time down
to under 3 seconds! However, I've discovered a flaw in the query. A customer
can order multiple times. The above query still includes customers that have
ordered product #23, but have also ordered other products on separate
orders.

Example:

Customers: Subscriptions:
+--+---+   +++
| id   | bad_email |   | customerid | listid |
+--+---+   +++
| 1001 | 0 |   | 1001   | 2  |
+--+---+   +++

Orders:   Ordered_Items:
+++   +-+---+
| id | customerid |   | orderid | productid |
+++   +-+---+
| 1  | 1001   |   | 1   | 23|
| 2  | 1001   |   | 2   | 98|
+++   +-+---+

Customer #1001 would be included in the found set of the query above. He
would be removed because he ordered product #23 on order #1, but he would
also be included because he didn't order product #23 on order #2.

Any ideas on how to exclude these multi-order customers?

Jamie

Jamie Tibbetts.[EMAIL PROTECTED]
Epigroove .http://www.epigroove.com/


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RE: Need help with a complex query

2002-06-18 Thread Peter Normann

I don't know if it would be possible to use something like this, but
maybe it's worth a try...

SELECT Customers.*,  SUM(IF(IFNULL(Orders_Items.productid, 0)='23',1,0))
BINGO FROM Customers
LEFT JOIN Orders ON (Orders.customerid=Customer.CustomerID)
LEFT JOIN Ordered_Items ON (Ordered_Items.orderid=Orders.id 
(Ordered_Items.productid = '23'))
WHERE Customers.id=Subscriptions.customerid
AND Subscriptions.listid='2'
AND Ordered_Items.orderid IS NULL
AND Orders.customerid IS NULL
AND NOT Customers.bad_email
GROUP BY Customer.email
HAVING BINGO = 0;


Jeez either I should be getting some coffee or some sleep

Peter Normann


-Original Message-
From: Jamie Tibbetts [mailto:[EMAIL PROTECTED]] 
Sent: 18. juni 2002 22:21
To: Peter Normann; [EMAIL PROTECTED]
Subject: Re: Need help with a complex query


 Try - and I mean *try* :-)
 
 SELECT Customers.* FROM Customers, Subscriptions
 LEFT JOIN Orders ON (Orders.customerid=Customer.CustomerID)
 LEFT JOIN Ordered_Items ON (Ordered_Items.orderid=Orders.id 
 (Ordered_Items.productid = '23'))
 WHERE Customers.id=Subscriptions.customerid
 AND Subscriptions.listid='2'
 AND Ordered_Items.orderid IS NULL
 AND Orders.customerid IS NULL
 AND NOT Customers.bad_email;
 
 Well, MySQL has been chugging on this one for about 15 minutes now,
and
 it's
 still going. So I'm not sure if it is a problem with the query or the
 optimization of my MySQL databases. There are 30,000+ records in the
 Customers database, but the query should have finished by now, right?
 
 Well, my best guess is that you should consider indexing your
tables...
 If you haven't done so already, indexing will cause dramatic effect on
 the speed of the queries...
 
 Peter Normann

Okay. I've indexed all fields involved, and I've gotten the query time
down
to under 3 seconds! However, I've discovered a flaw in the query. A
customer
can order multiple times. The above query still includes customers that
have
ordered product #23, but have also ordered other products on separate
orders.

Example:

Customers: Subscriptions:
+--+---+   +++
| id   | bad_email |   | customerid | listid |
+--+---+   +++
| 1001 | 0 |   | 1001   | 2  |
+--+---+   +++

Orders:   Ordered_Items:
+++   +-+---+
| id | customerid |   | orderid | productid |
+++   +-+---+
| 1  | 1001   |   | 1   | 23|
| 2  | 1001   |   | 2   | 98|
+++   +-+---+

Customer #1001 would be included in the found set of the query above. He
would be removed because he ordered product #23 on order #1, but he
would
also be included because he didn't order product #23 on order #2.

Any ideas on how to exclude these multi-order customers?

Jamie

Jamie Tibbetts.[EMAIL PROTECTED]
Epigroove .http://www.epigroove.com/


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RE: Need help with a complex query

2002-06-16 Thread Peter Normann

Try - and I mean *try* :-)

SELECT Customers.* FROM Customers, Subscriptions
LEFT JOIN Orders ON (Orders.customerid=Customer.CustomerID)
LEFT JOIN Ordered_Items ON (Ordered_Items.orderid=Orders.id 
(Ordered_Items.productid = '23'))
WHERE Customers.id=Subscriptions.customerid
AND Subscriptions.listid='2'
AND Ordered_Items.orderid IS NULL
AND Orders.customerid IS NULL
AND NOT Customers.bad_email;

Peter Normann



-Original Message-
From: Jamie Tibbetts [mailto:[EMAIL PROTECTED]] 
Sent: 16. juni 2002 18:23
To: [EMAIL PROTECTED]
Subject: Need help with a complex query


I am currently a web designer who's taught himself the necessary basics
of PHP and MySQL. I've reached a point where I can't figure out a
complex query.

I have a mailing list that customers can sign up for if they want to
receive Special Offer mailings when products go on sale. So when it's
time to send out a mailing on a sale product, I need to select all
customers who have signed up for list #2. However, (and here's the big
problem) I need to filter out the customers that have bad email
addresses marked in their customer record, *and* I need to filter out
the customers who have already purchased the sale product.

Customers: Subscriptions:
+--+---+   +++
| id   | bad_email |   | customerid | listid |
+--+---+   +++
| 1001 | 1 |   | 1001   | 2  |
| 1002 | 0 |   | 1002   | 1  |
| 1003 | 0 |   | 1003   | 2  |
| 1004 | 0 |   | 1004   | 2  |
| 1005 | 0 |   | 1005   | 2  |
+--+---+   +++

Orders:   Ordered_Items:
+++   +-+---+
| id | customerid |   | orderid | productid |
+++   +-+---+
| 1  | 1001   |   | 1   | 24|
| 2  | 1002   |   | 2   | 98|
| 3  | 1003   |   | 3   | 23|
| 4  | 1004   |   | 4   | 56|
+++   +-+---+

For example: I want to send out a mailing on product #23

A) Customer 1001 has a bad email address, so he shouldn't be selected
B) Customer 1002 has a good email address, but he's not signed up for
list #2, so he shouldn't be selected
C) Customer 1003 has a good email address, he's signed up for list #2,
but he's ordered product #23 before, so he shouldn't be selected
D) Customer 1004 has a good email address, he's signed up for list #2,
and he's ordered a product that isn't #23, so he *should* be selected
E) Customer 1005 has a good email address, he's signed up for list #2,
and he's never ordered, so he *should* be selected

Summary:
 Not Selected: 1001,1002,1003
 Selected: 1004,1005

Can anyone create a query that will return the results I need. Keep in
mind that I am far from being a MySQL expert, so if you start using too
much technical specifics, my head might explode. ;)

Thanks in advance!

Jamie

Jamie Tibbetts.[EMAIL PROTECTED]
Epigroove .http://www.epigroove.com/
Success   .http://www.success.com/


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Re: Need help with a complex query

2002-06-16 Thread Jamie Tibbetts

 Try - and I mean *try* :-)
 
 SELECT Customers.* FROM Customers, Subscriptions
 LEFT JOIN Orders ON (Orders.customerid=Customer.CustomerID)
 LEFT JOIN Ordered_Items ON (Ordered_Items.orderid=Orders.id 
 (Ordered_Items.productid = '23'))
 WHERE Customers.id=Subscriptions.customerid
 AND Subscriptions.listid='2'
 AND Ordered_Items.orderid IS NULL
 AND Orders.customerid IS NULL
 AND NOT Customers.bad_email;

Well, MySQL has been chugging on this one for about 15 minutes now, and it's
still going. So I'm not sure if it is a problem with the query or the
optimization of my MySQL databases. There are 30,000+ records in the
Customers database, but the query should have finished by now, right?

Jamie

Jamie Tibbetts.[EMAIL PROTECTED]
Epigroove .http://www.epigroove.com/


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RE: Need help with a complex query

2002-06-16 Thread Peter Normann

Well, my best guess is that you should consider indexing your tables...
If you haven't done so already, indexing will cause dramatic effect on
the speed of the queries...

Peter Normann

-Original Message-
From: Jamie Tibbetts [mailto:[EMAIL PROTECTED]] 
Sent: 16. juni 2002 19:18
To: Peter Normann; [EMAIL PROTECTED]
Subject: Re: Need help with a complex query


 Try - and I mean *try* :-)
 
 SELECT Customers.* FROM Customers, Subscriptions
 LEFT JOIN Orders ON (Orders.customerid=Customer.CustomerID)
 LEFT JOIN Ordered_Items ON (Ordered_Items.orderid=Orders.id 
 (Ordered_Items.productid = '23'))
 WHERE Customers.id=Subscriptions.customerid
 AND Subscriptions.listid='2'
 AND Ordered_Items.orderid IS NULL
 AND Orders.customerid IS NULL
 AND NOT Customers.bad_email;

Well, MySQL has been chugging on this one for about 15 minutes now, and
it's
still going. So I'm not sure if it is a problem with the query or the
optimization of my MySQL databases. There are 30,000+ records in the
Customers database, but the query should have finished by now, right?

Jamie

Jamie Tibbetts.[EMAIL PROTECTED]
Epigroove .http://www.epigroove.com/


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Re: Need Help with JOIN

2002-06-13 Thread Harrison C. Fisk

Mike,

With the way you have it written below,  all of the pic1_id, pic2_id, 
pic3_id, and pic4_id must be equal (because they all equal pic.pic_id). 
 Since this wasn't true for any of the rows, that is why you were 
getting no results.
To get each picture value seperately, you will have to do one join for 
each pic#_id, which will give you something like:

SELECT * 
FROM pics AS p1, pics AS p2, pics AS p3, pics AS p4 , outings AS o
WHERE o.pic1_id=p1.pic_id 
AND o.pic2_id=p2.pic_id 
AND o.pic3_id=p3.pic_id
AND o.pic4_id=p4.pic_id;

Or as you had it written before using INNER JOIN's:

SELECT *
FROM outings as o INNER JOIN pics AS p1 ON o.pic1_id=p1.pic_id
INNER JOIN pics AS p2 ON o.pic2_id=p2.pic_id
INNER JOIN pics AS p3 ON o.pic3_id=p3.pic_id
INNER JOIN pics AS p4 ON o.pic4_id=p4.pic_id;

Either of those should work fairly well.  Hope that helps some.

Harrison


Mike wrote:

Hello,

I have 2 tables(pics and outings)

pics
pic_id, tinyint
path, varchar

outings
outings_id, tinyint
pic1_id, tinyint
pic2_id, tinyint
pic3_id, tinyint
pic4_id, tinyint

When i try to do a join like this

mysql_query(SELECT * FROM pics inner join outings on
outings.pic1_id=pic.pic_id and outings.pic2_id=pic.pic_id and
outings.pic3_id=pic.pic_id,$db) or die(mysql_error());

Nothing is returned. The query runs ok(nothing from mysql_error). When I
drop outings.pic2_id=pic.pic_id and outings.pic3_id=pic.pic_id from the
query works and returns the path of the pic.

I'm fairly certain that the above returns nothing because of the multiple
pic.pic_id's in the query.  But I don't know what to do get it
working(Redesign? or Is there something I could change in the query?)

Thanks in advance for any help,
Mike
sql,mysql


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Re: Need Help with JOIN

2002-06-13 Thread Mike

Thanks for the help. Got that to work no problem.



Mike
- Original Message -
From: Harrison C. Fisk [EMAIL PROTECTED]
To: Mike [EMAIL PROTECTED]
Cc: mysql list [EMAIL PROTECTED]
Sent: Thursday, June 13, 2002 5:48 PM
Subject: Re: Need Help with JOIN


 Mike,

 With the way you have it written below,  all of the pic1_id, pic2_id,
 pic3_id, and pic4_id must be equal (because they all equal pic.pic_id).
  Since this wasn't true for any of the rows, that is why you were
 getting no results.
 To get each picture value seperately, you will have to do one join for
 each pic#_id, which will give you something like:

 SELECT *
 FROM pics AS p1, pics AS p2, pics AS p3, pics AS p4 , outings AS o
 WHERE o.pic1_id=p1.pic_id
 AND o.pic2_id=p2.pic_id
 AND o.pic3_id=p3.pic_id
 AND o.pic4_id=p4.pic_id;

 Or as you had it written before using INNER JOIN's:

 SELECT *
 FROM outings as o INNER JOIN pics AS p1 ON o.pic1_id=p1.pic_id
 INNER JOIN pics AS p2 ON o.pic2_id=p2.pic_id
 INNER JOIN pics AS p3 ON o.pic3_id=p3.pic_id
 INNER JOIN pics AS p4 ON o.pic4_id=p4.pic_id;

 Either of those should work fairly well.  Hope that helps some.

 Harrison


 Mike wrote:

 Hello,
 
 I have 2 tables(pics and outings)
 
 pics
 pic_id, tinyint
 path, varchar
 
 outings
 outings_id, tinyint
 pic1_id, tinyint
 pic2_id, tinyint
 pic3_id, tinyint
 pic4_id, tinyint
 
 When i try to do a join like this
 
 mysql_query(SELECT * FROM pics inner join outings on
 outings.pic1_id=pic.pic_id and outings.pic2_id=pic.pic_id and
 outings.pic3_id=pic.pic_id,$db) or die(mysql_error());
 
 Nothing is returned. The query runs ok(nothing from mysql_error). When I
 drop outings.pic2_id=pic.pic_id and outings.pic3_id=pic.pic_id from the
 query works and returns the path of the pic.
 
 I'm fairly certain that the above returns nothing because of the multiple
 pic.pic_id's in the query.  But I don't know what to do get it
 working(Redesign? or Is there something I could change in the query?)
 
 Thanks in advance for any help,
 Mike
 sql,mysql
 
 
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Re: Need help.

2002-05-22 Thread Gelu Gogancea

Hi,
Any problem is an effect of the cause
so...

 I keep getting errors involving resolveip when I install, or it just don't
 work.  When I try to run the ./configure command in Linux (7.1-7.3), it
 kicks me back an error.
 What error?

 If I use the rpm installation, it seems to install
 fine, but when I go to access the db from anywhere, it never works.
For sure you must set  privileges for the user which must connected from
other host.


 I've followed the directions on the web site, other web sites and even
from
 a book that I bought (MySQL and mSQL from O'Reilly), none of the
directions
 seem to work.  What the heck am I doing wrong?

 BTW, we need the supported commands in 4.0.x and 4.1.x, so we're trying to
 start with 4.0.1-2 right now, so that the changes we have to make will be
 minimal when 4.0.x becomes stable and 4.1.x becomes stable.

 Any help would be appreciated.

 Thanks,
 Matt
Regards,
Gelu



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Re: Need help

2002-05-21 Thread Bertrand TACHAGO

 Hi,
 I have a MySQL database with a table named CONNEXION. When i'm trying to do
 something with the specific table, i have the following error:
 ERROR1016:Can't open file: 'CONNEXION.MYD'. (errno: 145)
 Please can anybody help me?
 Thanks in advance


-- 
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Bertrand TACHAGOE_mails: [EMAIL PROTECTED] / [EMAIL PROTECTED]
Network / information specialist 
SDNP SchoolNet Cameroon Phone: (237)221 25 53
Web site: www.sdnp.cm/tachago
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RE: Need help

2002-05-21 Thread Gurhan Ozen

Use perror program to see what the error code means..

perror 145
Error code 145:  Unknown error 145
145 = Table was marked as crashed and should be repaired

Repair your table..
see: http://www.mysql.com/doc/R/E/REPAIR_TABLE.html

Gurhan

-Original Message-
From: Bertrand TACHAGO [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, May 21, 2002 9:16 AM
To: [EMAIL PROTECTED]
Subject: Re: Need help


 Hi,
 I have a MySQL database with a table named CONNEXION. When i'm trying to do
 something with the specific table, i have the following error:
 ERROR1016:Can't open file: 'CONNEXION.MYD'. (errno: 145)
 Please can anybody help me?
 Thanks in advance


--

**
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SDNP SchoolNet Cameroon Phone: (237)221 25 53
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Re: Re: Need help

2002-05-21 Thread Egor Egorov

Bertrand,
Tuesday, May 21, 2002, 4:15:37 PM, you wrote:

BT  I have a MySQL database with a table named CONNEXION. When i'm trying to do
BT  something with the specific table, i have the following error:
BT  ERROR1016:Can't open file: 'CONNEXION.MYD'. (errno: 145)
BT  Please can anybody help me?
BT  Thanks in advance

# perror 145
Error code 145:  Unknown error 145
145 = Table was marked as crashed and should be repaired

Try to repair table using myisamchk or REPAIR TABLE. Look at:
  http://www.mysql.com/doc/R/e/Repair.html





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RE: Need help

2002-05-21 Thread Bertrand TACHAGO

Thanks, i had check and had already solve the problem.

Gurhan Ozen [EMAIL PROTECTED] a dit :

 Use perror program to see what the error code means..
 
 perror 145
 Error code 145:  Unknown error 145
 145 = Table was marked as crashed and should be repaired
 
 Repair your table..
 see: http://www.mysql.com/doc/R/E/REPAIR_TABLE.html
 
 Gurhan
 
 -Original Message-
 From: Bertrand TACHAGO [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, May 21, 2002 9:16 AM
 To: [EMAIL PROTECTED]
 Subject: Re: Need help
 
 
  Hi,
  I have a MySQL database with a table named CONNEXION. When i'm trying to do
  something with the specific table, i have the following error:
  ERROR1016:Can't open file: 'CONNEXION.MYD'. (errno: 145)
  Please can anybody help me?
  Thanks in advance
 
 
 --
 
 **
 Bertrand TACHAGO  E_mails: [EMAIL PROTECTED] / [EMAIL PROTECTED]
 Network / information specialist
 SDNP SchoolNet Cameroon   Phone: (237)221 25 53
 Web site: www.sdnp.cm/tachago
 
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Re: need help debugging!

2002-03-01 Thread Uma Shankari T.


Hello Alex,


  If the mysql query returns 0 then it will display the message like this


-Uma


On Fri, 1 Mar 2002, Alex Behrens wrote:

ABHey All,
AB
ABI am new to mysql and I need help debugging this peice of code for my site:
AB
AB?php
AB$db = mysql_connect(db30.pair.com, net3dual, rosevilleX1);
ABmysql_select_db(rahs,$db);
AB$search = mysql_query(SELECT * FROM rahs);
ABwhile($num=mysql_fetch_array($search)) {
ABprintf (div align='center'centertable border='0' cellpadding='0'
ABcellspacing='0' width=\40%\trtd
ABwidth=\70%\Name:%snbsp;nbsp;nbsp;nbsp; #%s/tdtd
ABwidth=\30%\Team: %s/td/trtrtd width=\100%\ colspan='2'Penalty:
AB%s/td/trtrtd width=\50%\Groundballs: %s/tdtd
ABwidth=\50%\Shots: %s/td/trtrtd width=\50%\Faceoffs
ABWon:%s/tdtd width=\50%\Faceoffs Lost: %s/td/trtrtd
ABwidth=\100%\ colspan='2'p
ABalign='center'Date:%s/td/tr/table/center/div,$num[name],$num[
ABnumber],$num[team],$num[penalty],$num[groundballs],$num[shots],$num
AB[faceoffs_won],$num[faceoffs_lost],$num[date]);
AB}
AB?
AB
ABit says this error:
ABWarning: Supplied argument is not a valid MySQL result resource on line 17
ABline 17 would be this line:
ABwhile($num=mysql_fetch_array($search)) {
AB
ABwhat is wrong with my code?
AB
AB
ABThanks!
AB
AB-Alex Big Al Behrens
ABE-mail: [EMAIL PROTECTED]
ABUrgent E-mail: [EMAIL PROTECTED] (Please be brief!)
ABPhone: 651-482-8779
ABCell: 651-329-4187
ABFax: 651-482-1391
ABICQ: 3969599
ABOwner of the 3D-Unlimited Network:
ABhttp://www.3d-unlimited.com
ABSend News:
AB[EMAIL PROTECTED]
AB
AB
AB-
ABBefore posting, please check:
AB   http://www.mysql.com/manual.php   (the manual)
AB   http://lists.mysql.com/   (the list archive)
AB
ABTo request this thread, e-mail [EMAIL PROTECTED]
ABTo unsubscribe, e-mail 
[EMAIL PROTECTED]
ABTrouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
AB

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Re: need help debugging!

2002-03-01 Thread Alex Behrens

how do I fix it so mysql doesn't returns a 0? is my syntax wrong somewhere?

Thanks!

-Alex Big Al Behrens
E-mail: [EMAIL PROTECTED]
Urgent E-mail: [EMAIL PROTECTED] (Please be brief!)
Phone: 651-482-8779
Cell: 651-329-4187
Fax: 651-482-1391
ICQ: 3969599
Owner of the 3D-Unlimited Network:
http://www.3d-unlimited.com
Send News:
[EMAIL PROTECTED]
- Original Message -
From: Uma Shankari T. [EMAIL PROTECTED]
To: Alex Behrens [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Friday, March 01, 2002 7:35 PM
Subject: Re: need help debugging!



 Hello Alex,


   If the mysql query returns 0 then it will display the message like this


 -Uma


 On Fri, 1 Mar 2002, Alex Behrens wrote:

 ABHey All,
 AB
 ABI am new to mysql and I need help debugging this peice of code for my
site:
 AB
 AB?php
 AB$db = mysql_connect(db30.pair.com, net3dual, rosevilleX1);
 ABmysql_select_db(rahs,$db);
 AB$search = mysql_query(SELECT * FROM rahs);
 ABwhile($num=mysql_fetch_array($search)) {
 ABprintf (div align='center'centertable border='0' cellpadding='0'
 ABcellspacing='0' width=\40%\trtd
 ABwidth=\70%\Name:%snbsp;nbsp;nbsp;nbsp; #%s/tdtd
 ABwidth=\30%\Team: %s/td/trtrtd width=\100%\
colspan='2'Penalty:
 AB%s/td/trtrtd width=\50%\Groundballs: %s/tdtd
 ABwidth=\50%\Shots: %s/td/trtrtd width=\50%\Faceoffs
 ABWon:%s/tdtd width=\50%\Faceoffs Lost: %s/td/trtrtd
 ABwidth=\100%\ colspan='2'p

ABalign='center'Date:%s/td/tr/table/center/div,$num[name],$nu
m[

ABnumber],$num[team],$num[penalty],$num[groundballs],$num[shots],$
num
 AB[faceoffs_won],$num[faceoffs_lost],$num[date]);
 AB}
 AB?
 AB
 ABit says this error:
 ABWarning: Supplied argument is not a valid MySQL result resource on line
17
 ABline 17 would be this line:
 ABwhile($num=mysql_fetch_array($search)) {
 AB
 ABwhat is wrong with my code?
 AB
 AB
 ABThanks!
 AB
 AB-Alex Big Al Behrens
 ABE-mail: [EMAIL PROTECTED]
 ABUrgent E-mail: [EMAIL PROTECTED] (Please be brief!)
 ABPhone: 651-482-8779
 ABCell: 651-329-4187
 ABFax: 651-482-1391
 ABICQ: 3969599
 ABOwner of the 3D-Unlimited Network:
 ABhttp://www.3d-unlimited.com
 ABSend News:
 AB[EMAIL PROTECTED]
 AB
 AB
 AB-
 ABBefore posting, please check:
 AB   http://www.mysql.com/manual.php   (the manual)
 AB   http://lists.mysql.com/   (the list archive)
 AB
 ABTo request this thread, e-mail [EMAIL PROTECTED]
 ABTo unsubscribe, e-mail
[EMAIL PROTECTED]
 ABTrouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
 AB

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 Love and you shall be loved by others




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Re: need help debugging!

2002-03-01 Thread Uma Shankari T.


Hello Alex,


  Check it manually wheather ur query returns any row.


-Uma




On Fri, 1 Mar 2002, Alex Behrens wrote:

ABhow do I fix it so mysql doesn't returns a 0? is my syntax wrong somewhere?
AB
ABThanks!
AB
AB-Alex Big Al Behrens
ABE-mail: [EMAIL PROTECTED]
ABUrgent E-mail: [EMAIL PROTECTED] (Please be brief!)
ABPhone: 651-482-8779
ABCell: 651-329-4187
ABFax: 651-482-1391
ABICQ: 3969599
ABOwner of the 3D-Unlimited Network:
ABhttp://www.3d-unlimited.com
ABSend News:
AB[EMAIL PROTECTED]
AB- Original Message -
ABFrom: Uma Shankari T. [EMAIL PROTECTED]
ABTo: Alex Behrens [EMAIL PROTECTED]
ABCc: [EMAIL PROTECTED]
ABSent: Friday, March 01, 2002 7:35 PM
ABSubject: Re: need help debugging!
AB
AB
AB
AB Hello Alex,
AB
AB
AB   If the mysql query returns 0 then it will display the message like this
AB
AB
AB -Uma
AB
AB
AB On Fri, 1 Mar 2002, Alex Behrens wrote:
AB
AB ABHey All,
AB AB
AB ABI am new to mysql and I need help debugging this peice of code for my
ABsite:
AB AB
AB AB?php
AB AB$db = mysql_connect(db30.pair.com, net3dual, rosevilleX1);
AB ABmysql_select_db(rahs,$db);
AB AB$search = mysql_query(SELECT * FROM rahs);
AB ABwhile($num=mysql_fetch_array($search)) {
AB ABprintf (div align='center'centertable border='0' cellpadding='0'
AB ABcellspacing='0' width=\40%\trtd
AB ABwidth=\70%\Name:%snbsp;nbsp;nbsp;nbsp; #%s/tdtd
AB ABwidth=\30%\Team: %s/td/trtrtd width=\100%\
ABcolspan='2'Penalty:
AB AB%s/td/trtrtd width=\50%\Groundballs: %s/tdtd
AB ABwidth=\50%\Shots: %s/td/trtrtd width=\50%\Faceoffs
AB ABWon:%s/tdtd width=\50%\Faceoffs Lost: %s/td/trtrtd
AB ABwidth=\100%\ colspan='2'p
AB
ABABalign='center'Date:%s/td/tr/table/center/div,$num[name],$nu
ABm[
AB
ABABnumber],$num[team],$num[penalty],$num[groundballs],$num[shots],$
ABnum
AB AB[faceoffs_won],$num[faceoffs_lost],$num[date]);
AB AB}
AB AB?
AB AB
AB ABit says this error:
AB ABWarning: Supplied argument is not a valid MySQL result resource on line
AB17
AB ABline 17 would be this line:
AB ABwhile($num=mysql_fetch_array($search)) {
AB AB
AB ABwhat is wrong with my code?
AB AB
AB AB
AB ABThanks!
AB AB
AB AB-Alex Big Al Behrens
AB ABE-mail: [EMAIL PROTECTED]
AB ABUrgent E-mail: [EMAIL PROTECTED] (Please be brief!)
AB ABPhone: 651-482-8779
AB ABCell: 651-329-4187
AB ABFax: 651-482-1391
AB ABICQ: 3969599
AB ABOwner of the 3D-Unlimited Network:
AB ABhttp://www.3d-unlimited.com
AB ABSend News:
AB AB[EMAIL PROTECTED]
AB AB
AB AB
AB AB-
AB ABBefore posting, please check:
AB AB   http://www.mysql.com/manual.php   (the manual)
AB AB   http://lists.mysql.com/   (the list archive)
AB AB
AB ABTo request this thread, e-mail [EMAIL PROTECTED]
AB ABTo unsubscribe, e-mail
AB[EMAIL PROTECTED]
AB ABTrouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
AB AB
AB
AB --
AB
AB Love and you shall be loved by others
AB
AB
AB
AB
AB-
ABBefore posting, please check:
AB   http://www.mysql.com/manual.php   (the manual)
AB   http://lists.mysql.com/   (the list archive)
AB
ABTo request this thread, e-mail [EMAIL PROTECTED]
ABTo unsubscribe, e-mail 
[EMAIL PROTECTED]
ABTrouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
AB

-- 

Love and you shall be loved by others


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Re: need help debugging!

2002-03-01 Thread Alex Behrens

what do you mean by checking each query manually? how do I do this?

Thanks!

-Alex Big Al Behrens
E-mail: [EMAIL PROTECTED]
Urgent E-mail: [EMAIL PROTECTED] (Please be brief!)
Phone: 651-482-8779
Cell: 651-329-4187
Fax: 651-482-1391
ICQ: 3969599
Owner of the 3D-Unlimited Network:
http://www.3d-unlimited.com
Send News:
[EMAIL PROTECTED]
- Original Message -
From: Uma Shankari T. [EMAIL PROTECTED]
To: Alex Behrens [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Friday, March 01, 2002 7:59 PM
Subject: Re: need help debugging!



 Hello Alex,


   Check it manually wheather ur query returns any row.


 -Uma




 On Fri, 1 Mar 2002, Alex Behrens wrote:

 ABhow do I fix it so mysql doesn't returns a 0? is my syntax wrong
somewhere?
 AB
 ABThanks!
 AB
 AB-Alex Big Al Behrens
 ABE-mail: [EMAIL PROTECTED]
 ABUrgent E-mail: [EMAIL PROTECTED] (Please be brief!)
 ABPhone: 651-482-8779
 ABCell: 651-329-4187
 ABFax: 651-482-1391
 ABICQ: 3969599
 ABOwner of the 3D-Unlimited Network:
 ABhttp://www.3d-unlimited.com
 ABSend News:
 AB[EMAIL PROTECTED]
 AB- Original Message -
 ABFrom: Uma Shankari T. [EMAIL PROTECTED]
 ABTo: Alex Behrens [EMAIL PROTECTED]
 ABCc: [EMAIL PROTECTED]
 ABSent: Friday, March 01, 2002 7:35 PM
 ABSubject: Re: need help debugging!
 AB
 AB
 AB
 AB Hello Alex,
 AB
 AB
 AB   If the mysql query returns 0 then it will display the message like
this
 AB
 AB
 AB -Uma
 AB
 AB
 AB On Fri, 1 Mar 2002, Alex Behrens wrote:
 AB
 AB ABHey All,
 AB AB
 AB ABI am new to mysql and I need help debugging this peice of code for
my
 ABsite:
 AB AB
 AB AB?php
 AB AB$db = mysql_connect(db30.pair.com, net3dual, rosevilleX1);
 AB ABmysql_select_db(rahs,$db);
 AB AB$search = mysql_query(SELECT * FROM rahs);
 AB ABwhile($num=mysql_fetch_array($search)) {
 AB ABprintf (div align='center'centertable border='0'
cellpadding='0'
 AB ABcellspacing='0' width=\40%\trtd
 AB ABwidth=\70%\Name:%snbsp;nbsp;nbsp;nbsp; #%s/tdtd
 AB ABwidth=\30%\Team: %s/td/trtrtd width=\100%\
 ABcolspan='2'Penalty:
 AB AB%s/td/trtrtd width=\50%\Groundballs: %s/tdtd
 AB ABwidth=\50%\Shots: %s/td/trtrtd width=\50%\Faceoffs
 AB ABWon:%s/tdtd width=\50%\Faceoffs Lost: %s/td/trtrtd
 AB ABwidth=\100%\ colspan='2'p
 AB

ABABalign='center'Date:%s/td/tr/table/center/div,$num[name],
$nu
 ABm[
 AB

ABABnumber],$num[team],$num[penalty],$num[groundballs],$num[shots
],$
 ABnum
 AB AB[faceoffs_won],$num[faceoffs_lost],$num[date]);
 AB AB}
 AB AB?
 AB AB
 AB ABit says this error:
 AB ABWarning: Supplied argument is not a valid MySQL result resource on
line
 AB17
 AB ABline 17 would be this line:
 AB ABwhile($num=mysql_fetch_array($search)) {
 AB AB
 AB ABwhat is wrong with my code?
 AB AB
 AB AB
 AB ABThanks!
 AB AB
 AB AB-Alex Big Al Behrens
 AB ABE-mail: [EMAIL PROTECTED]
 AB ABUrgent E-mail: [EMAIL PROTECTED] (Please be brief!)
 AB ABPhone: 651-482-8779
 AB ABCell: 651-329-4187
 AB ABFax: 651-482-1391
 AB ABICQ: 3969599
 AB ABOwner of the 3D-Unlimited Network:
 AB ABhttp://www.3d-unlimited.com
 AB ABSend News:
 AB AB[EMAIL PROTECTED]
 AB AB
 AB AB
 AB
AB-
 AB ABBefore posting, please check:
 AB AB   http://www.mysql.com/manual.php   (the manual)
 AB AB   http://lists.mysql.com/   (the list archive)
 AB AB
 AB ABTo request this thread, e-mail
[EMAIL PROTECTED]
 AB ABTo unsubscribe, e-mail
 AB[EMAIL PROTECTED]
 AB ABTrouble unsubscribing? Try:
http://lists.mysql.com/php/unsubscribe.php
 AB AB
 AB
 AB --
 AB
 AB Love and you shall be loved by others
 AB
 AB
 AB
 AB
 AB-
 ABBefore posting, please check:
 AB   http://www.mysql.com/manual.php   (the manual)
 AB   http://lists.mysql.com/   (the list archive)
 AB
 ABTo request this thread, e-mail [EMAIL PROTECTED]
 ABTo unsubscribe, e-mail
[EMAIL PROTECTED]
 ABTrouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
 AB

 --

 Love and you shall be loved by others




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Re: need help debugging!

2002-03-01 Thread Michael Stassen


rahs is the name of your db and your table?

It's a good idea to check for errors as you go.  Try something like:

?php  
   
$db = mysql_connect(db30.pair.com, net3dual, rosevilleX1) or
die(Couldn't connect: .mysql_error());
mysql_select_db(rahs,$db) or die(Couldn't select db: .mysql_error());
$search = mysql_query(SELECT * FROM rahs) or die(Query failed
:.mysql_error());
while($num=mysql_fetch_array($search)) { ...

Also, if that's your real user and password in the mysql_connect, you
should change it now, as this is an open list.

Michael

On Fri, 1 Mar 2002, Alex Behrens wrote:

 how do I fix it so mysql doesn't returns a 0? is my syntax wrong somewhere?
 
 Thanks!
 
 -Alex Big Al Behrens
 
 - Original Message -
 From: Uma Shankari T. [EMAIL PROTECTED]
 
  Hello Alex,
 
 
If the mysql query returns 0 then it will display the message like this
 
 
  -Uma
 
 
  On Fri, 1 Mar 2002, Alex Behrens wrote:
 
  ABHey All,
  AB
  ABI am new to mysql and I need help debugging this peice of code for my
 site:
  AB
  AB?php
  AB$db = mysql_connect(db30.pair.com, net3dual, rosevilleX1);
  ABmysql_select_db(rahs,$db);
  AB$search = mysql_query(SELECT * FROM rahs);
  ABwhile($num=mysql_fetch_array($search)) {
  ABprintf (div align='center'centertable border='0' cellpadding='0'
  ABcellspacing='0' width=\40%\trtd
  ABwidth=\70%\Name:%snbsp;nbsp;nbsp;nbsp; #%s/tdtd
  ABwidth=\30%\Team: %s/td/trtrtd width=\100%\
 colspan='2'Penalty:
  AB%s/td/trtrtd width=\50%\Groundballs: %s/tdtd
  ABwidth=\50%\Shots: %s/td/trtrtd width=\50%\Faceoffs
  ABWon:%s/tdtd width=\50%\Faceoffs Lost: %s/td/trtrtd
  ABwidth=\100%\ colspan='2'p
 
 ABalign='center'Date:%s/td/tr/table/center/div,$num[name],$nu
 m[
 
 ABnumber],$num[team],$num[penalty],$num[groundballs],$num[shots],$
 num
  AB[faceoffs_won],$num[faceoffs_lost],$num[date]);
  AB}
  AB?
  AB
  ABit says this error:
  ABWarning: Supplied argument is not a valid MySQL result resource on line
 17
  ABline 17 would be this line:
  ABwhile($num=mysql_fetch_array($search)) {
  AB
  ABwhat is wrong with my code?
  AB
  AB
  ABThanks!

Michael Stassen
University Information Technology Services
Indiana University Bloomington
[EMAIL PROTECTED]


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Re: need help debugging!

2002-03-01 Thread Jim Lucas [jimmysql]

Try adding this to your mysql_query() function.

$search = mysql_query()
or die(ERROR: . mysql_error() . ( . mysql_errno(). ));

this will tell you whether or not the query is dieing for one reason or
another.
if it doesn't return the die() statement then you must assume that it was
successfull.

the best way to catch whether or not the result pointer is empty, is to run
a mysql_num_rows() on the pointer.

this will return to you the total number of rows returned by the select
statement.

if you wrap your while clause with an if statement and have the condition be
whether or not the returned value of the mysql_num_rows() is greater then
zero. upon failing, returning zero results, it will never run the while
loop, therefor never give you the error that it's tring to use an invalid
result pointer.

So, try this

?php
$db = mysql_connect(db30.pair.com, net3dual, rosevilleX1);
$db = mysql_select_db(rahs,$db);
$search = mysql_query(SELECT * FROM rahs) or die(ERROR: . mysql_error()
. ( . mysql_errno(). ));
if(mysql_num_rows($search))
{
while($num = mysql_fetch_array($search))
{
echo div align='center'
table border='0' cellpadding='0'
cellspacing='0' width=\40%\ align='center'
tr
td width=\70%\Name: .$num[name].
nbsp;nbsp;nbsp;nbsp; #.$num[number]./td
td width=\30%\Team:
.$num[team]./td
/tr
tr
td width=\100%\
colspan='2'Penalty.$num[penalty]./td
/tr
tr
td width=\50%\Groundballs:
.$num[groundballs]./td
td width=\50%\Shots:
.$num[shots]./td
/tr
tr
td width=\50%\Faceoffs Won:
.$num[faceoffs_won]./td
td width=\50%\Faceoffs Lost:
.$num[faceoffs_lost]./td
/tr
tr
td width=\100%\ colspan='2'p
align='center'Date .$num[date]./p/td
/tr
/table
/div;
}
} else {
die(didn't find any results);
}

?
- Original Message -
From: Alex Behrens [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, March 01, 2002 5:25 PM
Subject: need help debugging!


 Hey All,

 I am new to mysql and I need help debugging this peice of code for my
site:

 ?php
 $db = mysql_connect(db30.pair.com, net3dual, rosevilleX1);
 mysql_select_db(rahs,$db);
 $search = mysql_query(SELECT * FROM rahs);
 while($num=mysql_fetch_array($search)) {
 printf (div align='center'centertable border='0' cellpadding='0'
 cellspacing='0' width=\40%\trtd
 width=\70%\Name:%snbsp;nbsp;nbsp;nbsp; #%s/tdtd
 width=\30%\Team: %s/td/trtrtd width=\100%\
colspan='2'Penalty:
 %s/td/trtrtd width=\50%\Groundballs: %s/tdtd
 width=\50%\Shots: %s/td/trtrtd width=\50%\Faceoffs
 Won:%s/tdtd width=\50%\Faceoffs Lost: %s/td/trtrtd
 width=\100%\ colspan='2'p

align='center'Date:%s/td/tr/table/center/div,$num[name],$num[

number],$num[team],$num[penalty],$num[groundballs],$num[shots],$num
 [faceoffs_won],$num[faceoffs_lost],$num[date]);
 }
 ?

 it says this error:
 Warning: Supplied argument is not a valid MySQL result resource on line 17
 line 17 would be this line:
 while($num=mysql_fetch_array($search)) {

 what is wrong with my code?


 Thanks!
 
 -Alex Big Al Behrens
 E-mail: [EMAIL PROTECTED]
 Urgent E-mail: [EMAIL PROTECTED] (Please be brief!)
 Phone: 651-482-8779
 Cell: 651-329-4187
 Fax: 651-482-1391
 ICQ: 3969599
 Owner of the 3D-Unlimited Network:
 http://www.3d-unlimited.com
 Send News:
 [EMAIL PROTECTED]


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 To request this thread, e-mail [EMAIL PROTECTED]
 To unsubscribe, e-mail
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Re: need help debugging! (more!)

2002-03-01 Thread Alex Behrens

Actually I figured out the problem my db name was wrong, however I am
getting a new code, here is my code now tho and the error (with the pass
this time!):

?php
$db = mysql_connect(db, ***, ***);
mysql_select_db(net3dual_lax,$db);
$search = mysql_query(SELECT * FROM rahs);
echo div align='center'centertable border='0' cellpadding='0'
cellspacing='0' width=\40%\\n;
while($num=mysql_fetch_array($search)) {
printf (trtd width=\70%\Name:%snbsp;nbsp;nbsp;nbsp;
Number:%s/tdtd width=\30%\Team: %s/td/trtrtd width=\100%\
colspan='2'Penalty: %s/td/trtrtd width=\50%\Groundballs:
%s/tdtd width=\50%\Shots: %s/td/trtrtd width=\50%\Faceoffs
Won:%s/tdtd width=\50%\Faceoffs Lost: %s/td/trtrtd
width=\100%\ colspan='2'p
align='center'Date:%s/td/tr/table/center/div,$num[name],$num[
number],$num[team],$num[penalty],$num[groundballs],$num[shots],$num
[faceoffs_won],$num[faceoffs_lost],$num[date]);
}
?

it gives me this error:
  Warning: printf(): too few arguments

how do I fix this? I checked the number of %s and the number of $num
arguments and they shuld match. what am I doing wrong?

Thanks!

-Alex Big Al Behrens
E-mail: [EMAIL PROTECTED]
Urgent E-mail: [EMAIL PROTECTED] (Please be brief!)
Phone: 651-482-8779
Cell: 651-329-4187
Fax: 651-482-1391
ICQ: 3969599
Owner of the 3D-Unlimited Network:
http://www.3d-unlimited.com
Send News:
[EMAIL PROTECTED]
- Original Message -
From: Jim Lucas [jimmysql] [EMAIL PROTECTED]
To: Alex Behrens [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Friday, March 01, 2002 10:19 PM
Subject: Re: need help debugging!


 Try adding this to your mysql_query() function.

 $search = mysql_query()
 or die(ERROR: . mysql_error() . ( . mysql_errno(). ));

 this will tell you whether or not the query is dieing for one reason or
 another.
 if it doesn't return the die() statement then you must assume that it was
 successfull.

 the best way to catch whether or not the result pointer is empty, is to
run
 a mysql_num_rows() on the pointer.

 this will return to you the total number of rows returned by the select
 statement.

 if you wrap your while clause with an if statement and have the condition
be
 whether or not the returned value of the mysql_num_rows() is greater then
 zero. upon failing, returning zero results, it will never run the while
 loop, therefor never give you the error that it's tring to use an invalid
 result pointer.

 So, try this

 ?php
 $db = mysql_connect(db30.pair.com, net3dual, rosevilleX1);
 $db = mysql_select_db(rahs,$db);
 $search = mysql_query(SELECT * FROM rahs) or die(ERROR: .
mysql_error()
 . ( . mysql_errno(). ));
 if(mysql_num_rows($search))
 {
 while($num = mysql_fetch_array($search))
 {
 echo div align='center'
 table border='0' cellpadding='0'
 cellspacing='0' width=\40%\ align='center'
 tr
 td width=\70%\Name:
.$num[name].
 nbsp;nbsp;nbsp;nbsp; #.$num[number]./td
 td width=\30%\Team:
 .$num[team]./td
 /tr
 tr
 td width=\100%\
 colspan='2'Penalty.$num[penalty]./td
 /tr
 tr
 td width=\50%\Groundballs:
 .$num[groundballs]./td
 td width=\50%\Shots:
 .$num[shots]./td
 /tr
 tr
 td width=\50%\Faceoffs Won:
 .$num[faceoffs_won]./td
 td width=\50%\Faceoffs Lost:
 .$num[faceoffs_lost]./td
 /tr
 tr
 td width=\100%\ colspan='2'p
 align='center'Date .$num[date]./p/td
 /tr
 /table
 /div;
 }
 } else {
 die(didn't find any results);
 }

 ?
 - Original Message -
 From: Alex Behrens [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Sent: Friday, March 01, 2002 5:25 PM
 Subject: need help debugging!


  Hey All,
 
  I am new to mysql and I need help debugging this peice of code for my
 site:
 
  ?php
  $db = mysql_connect(db30.pair.com, net3dual, rosevilleX1);
  mysql_select_db(rahs,$db);
  $search = mysql_query(SELECT * FROM rahs);
  while($num=mysql_fetch_array($search)) {
  printf (div align='center'centertable border='0' cellpadding='0'
  cellspacing='0' width=\40%\trtd
  width=\70%\Name:%snbsp;nbsp;nbsp;nbsp; #%s/tdtd
  width=\30%\Team: %s/td/trtrtd width=\100%\
 colspan='2'Penalty:
  %s/td/trtrtd width=\50%\Groundballs: %s/tdtd
  width=\50%\Shots: %s/td/trtrtd width=\50%\Faceoffs
  Won:%s/tdtd width=\50%\Faceoffs Lost: %s/td/trtrtd
  width=\100%\ colspan='2'p
 

align='center'Date:%s/td/tr/table/center/div,$num[name],$num[
 

number

Re: Need help about mysql order and index....

2002-02-15 Thread Jean-Francois Dionne

Okay is not a reply for myself :) is only for add a question... :)

I read that mysql 4 will fix this, but mysql 4 is stable? I mean i'm on
production, i'm not selling mysql :) I mean I have a big projet in test
using mysql.. so if it crash it will be very bad for me... someone had test
mysql 4? stable or not? :)

Jean-Francois Dionne

- Original Message -
From: Jean-Francois Dionne [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, February 14, 2002 7:25 PM
Subject: Need help about mysql order and index


 Hi there, I hope someone will can help me... First, sorry for bad english
:)
 i'm french
 First all I have those index in my table

+---+---+-++
 --+-++--++
--
 +
 | Table | Non_unique | Key_name  | Seq_in_index | Column_name | Collation
|
 Cardinality | Sub_part | Packed | Comment |

+---+---+-++
 --+-++--++
--
 +
 | Stats |  0   | PRIMARY   |1| ID
 | A  | 4568748 | NULL  | NULL|   |
 | Stats |  1   | Port_ID   |1| Port_ID
 | A  |   1  | NULL  | NULL|   |
 | Stats |  1   | Timestamp  |1| Timestamp
 | A  |   49126   | NULL  | NULL|   |

+---+---+-++
 --+-++--++
--
 +

 You have to know I have 4 500 000 in my db

 Okay I have this query:
 select Timestamp from Stats use index (Timestamp) where Timestamp =
 '2002-01-01' and Timestamp  '2002-02-01' order by Timestamp limit 1;
 this one is jsut doing fine.. it take 0.00 sec to do it...

 but
 select Timestamp from Stats use index (Timestamp) where Timestamp =
 '2002-01-01' and Timestamp  '2002-02-01' order by Timestamp desc limit 1;
 this one take sometime 10 sec to do I understand is the desc the
prob..
 because my index is in asc (collation=A)
 my question is... is there a way for maiking a index in desc? or maybe
 something else?

 Jean-Francois Dionne
 Yard


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Re: Need help about mysql order and index....

2002-02-15 Thread Ken Menzel

Bonjour Jean-françois,
   Le DESC qui utilise l'INDEX est un fonction de MySQL 4.0.  Il y a
un bug en la version 4.0.1 (Quelque fois il n'utilise pas l'index
descendre ) mais pour la plus part ça marche bien.  En autre il y a un
forum de MySQL en français à:
Liens utils :
  Poster un message: [EMAIL PROTECTED]
  S'abonner: [EMAIL PROTECTED]
  Se désabonner :  [EMAIL PROTECTED]
  Ecrire au proprio :   [EMAIL PROTECTED]

URL sur Onelist :
  http://www.onelist.com/community/mysql-france

Bonne chance,  Amicalement,
Ken
- Original Message -
From: Jean-Francois Dionne [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, February 14, 2002 7:25 PM
Subject: Need help about mysql order and index


 Hi there, I hope someone will can help me... First, sorry for bad
english :)
 i'm french
 First all I have those index in my table

+---+---+-++--
--
 --+-++--+---
-+--
 +
 | Table | Non_unique | Key_name  | Seq_in_index | Column_name |
Collation |
 Cardinality | Sub_part | Packed | Comment |

+---+---+-++--
--
 --+-++--+---
-+--
 +
 | Stats |  0   | PRIMARY   |1| ID
 | A  | 4568748 | NULL  | NULL|   |
 | Stats |  1   | Port_ID   |1|
Port_ID
 | A  |   1  | NULL  | NULL|
|
 | Stats |  1   | Timestamp  |1|
Timestamp
 | A  |   49126   | NULL  | NULL|   |

+---+---+-++--
--
 --+-++--+---
-+--
 +

 You have to know I have 4 500 000 in my db

 Okay I have this query:
 select Timestamp from Stats use index (Timestamp) where Timestamp =
 '2002-01-01' and Timestamp  '2002-02-01' order by Timestamp limit
1;
 this one is jsut doing fine.. it take 0.00 sec to do it...

 but
 select Timestamp from Stats use index (Timestamp) where Timestamp =
 '2002-01-01' and Timestamp  '2002-02-01' order by Timestamp desc
limit 1;
 this one take sometime 10 sec to do I understand is the desc the
prob..
 because my index is in asc (collation=A)
 my question is... is there a way for maiking a index in desc? or
maybe
 something else?

 Jean-Francois Dionne
 Yard


 
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Re: Need help please!

2002-02-14 Thread Brian Reichert

On Thu, Feb 14, 2002 at 01:05:24PM -0500, Richard C Rossy wrote:
  
 Ok I can't seem to get this. Now is it possible to have MySQL on a other
 computer and run the script.
 In other words  the perl script is on foo.com and MySQL database is on
 foo2.com. What is need to make the script work. What I have in the
 script is:

Have you actually read the perl docs for DBI?

   DBI Class Methods

   ...

   connect

 $dbh = DBI-connect($data_source, $username, $password)
   or die $DBI::errstr;

   ...

   Examples of $data_source values are:

 dbi:DriverName:database_name
 dbi:DriverName:database_name@hostname:port
 dbi:DriverName:database=database_name;host=hostname;port=port

   There is no standard for the text following the driver
   name. Each driver is free to use whatever syntax it
   wants.

So - compare the documentation with what your effort was, and note
the difference:

 $dbh = DBI-connect(DBI:mysql:$mysqldatabase,
 $mysqlhost,$mysqlusername, $mysqlpassword) || die(Couldn't
 connect to database!\n);

-- 
Brian 'you Bastard' Reichert[EMAIL PROTECTED]
37 Crystal Ave. #303Daytime number: (603) 434-6842
Derry NH 03038-1713 USA Intel architecture: the left-hand path

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Re: Need Help bad!.. today.. of all days!

2001-12-26 Thread B. van Ouwerkerk


hope you version came out better thn mine.. in my mail it was all out of 
shape.. maybe could attach a text file.. doubt the list allows that 
thoough alot dont

Upload it as your_code_name.txt to your website and send an URL to the list.

filter: mysql query sql

Bye,



B.


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Re: Need Help bad!.. today.. of all days!

2001-12-25 Thread Justin Farnsworth

I think you need to post the code.  The description of the
problem is a bit ambiguous.

_justin

Webmaster wrote:
 
 Hello.. of all days i have a project thats to be shown tomorrow.
 
 i cannot get the dam thing to work
 it should be simple i'd think
 
 i would post code and all and if asked will
 
 but it comes down to this.. i am using php 4 and mysql.. and doing math
 i have say 40 entries in the database, 20 for two differant surveys.. anytime anew 
person fills out the survey they get a unique id
 i have it set to grabe the results from each unigue id for each question through 
mysql.. but it seems to stop shot about 4 questions..
 i even tried dropped the while loop 4 questions shorter -4 and it still stop the 
same place.. of all days for this to occure.. i know
 but if anyone has a clue please offer suggestions.. also plase cc [EMAIL PROTECTED] 
with your reply.. thanks
 
 --
 Your Guardian Angel... find out here http://www.angelhaven.com/aodmail/
 Come Cruisin with the Angels http://www.AngelCruise.com
 Sign up for your free AngelHaven E-mail Today http://www.angelhaven.com/mail/
 
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-- 
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321 South Evans - Suite 203
Greenville, NC 27858 | Tel: (252) 353-0722

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Re: Need Help bad!.. today.. of all days!

2001-12-25 Thread Webmaster

the code is huge i'll post whats relevant. there may be a few irrelevant things in 
there... but hell... if your willing to look i'm willing to post

i know what works so will skip down lower to prevent wasting your time
and if ya could please cc your responce to [EMAIL PROTECTED], though if to much trouble 
i understand

i thought i was close.. but then compared the data and it doesnt match.. for instance 
its spitting out the right subcluters.. and untill i asked for the coomparison it was 
fine.. i cant do a percentage match or trial till it gives right info..



  while($i_sub$num_sub){
 $sub_id = 
@mysql_result($result_sub,$i_sub,subcluster_id);
 $result_per = 
mysql_query(select ques_ans from data_1 where ass_id=$ass_id AND user_id=$user_id AND 
subcluster_id='$sub_id',$db);
 $num_per = 
mysql_num_rows($result_per); 
 $i_per=0;   //this 
seems wrong but will count all subclusters equally 1 at a time through the while 
should
 $i_per1 = 0; // need 
a double count so need two seperate
 $cper = 0;
   
while($i_per$num_per){
// so we 
need to run the while, probably need to cut the ending out here to add to end of total
 //gonna 
change this into an include so its not listed 3 times here-maybe
  // do 
math function
 $nper = 
$num_per;
 $nper2 = 
($nper*5);  // max reading to devide by
 //answer 
= // need to add all the answers here
 
while($i_per1$num_per){
   
 $cper = $cper;
   
 $cper1 = @mysql_result($result_per,$i_per1,ques_ans);
   
 $i_per1++;
   
 $cper2 = @mysql_result($result_per,$i_per1,ques_ans);
   
 $cper = ($cper+$cper1+$cper2);
   
// $cper3 = $cper; // this is just an easy extraction
// i think this actualy might work

   echo 
sub=$sub_id = $cperp;
   
 $i_per1++;};  // this should loop through output to count the results total   
//TEST
//echo cper3 = $cper3;
   
 $i_per++;
 };
   $i_sub++;};

i know theres some redundant code in there etc.. but hey.. till it works i dont like 
to delete



-- Original Message --
From: Justin Farnsworth [EMAIL PROTECTED]
Date: Tue, 25 Dec 2001 09:28:53 -0500

I think you need to post the code.  The description of the
problem is a bit ambiguous.

_justin

Webmaster wrote:
 
 Hello.. of all days i have a project thats to be shown tomorrow.
 
 i cannot get the dam thing to work
 it should be simple i'd think
 
 i would post code and all and if asked will
 
 but it comes down to this.. i am using php 4 and mysql.. and doing math
 i have say 40 entries in the database, 20 for two differant surveys.. anytime anew 
person fills out the survey they get a unique id
 i have it set to grabe the results from each unigue id for each question through 
mysql.. but it seems to stop shot about 4 questions..
 i even tried dropped the while loop 4 questions shorter -4 and it still stop the 
same place.. of all days for this to occure.. i know
 but if anyone has a clue please offer suggestions.. also plase cc [EMAIL PROTECTED] 
with your reply.. thanks
 
 

Re: Need Help bad!.. today.. of all days!

2001-12-25 Thread Webmaster


hope you version came out better thn mine.. in my mail it was all out of shape.. maybe 
could attach a text file.. doubt the list allows that thoough alot dont

-- Original Message --
From: Webmaster [EMAIL PROTECTED]
Reply-To: [EMAIL PROTECTED]
Date: Tue, 25 Dec 2001 09:53:50 -0500

the code is huge i'll post whats relevant. there may be a few irrelevant things 
in there... but hell... if your willing to look i'm willing to post

i know what works so will skip down lower to prevent wasting your time
and if ya could please cc your responce to [EMAIL PROTECTED], though if to much trouble 
i understand

i thought i was close.. but then compared the data and it doesnt match.. for instance 
its spitting out the right subcluters.. and untill i asked for the coomparison it was 
fine.. i cant do a percentage match or trial till it gives right info..



  while($i_sub$num_sub){
 $sub_id = 
@mysql_result($result_sub,$i_sub,subcluster_id);
$result_per = 
mysql_query(select ques_ans from data_1 where ass_id=$ass_id AND user_id=$user_id 
AND subcluster_id='$sub_id',$db);
 $num_per = 
mysql_num_rows($result_per); 
 $i_per=0;   //this 
seems wrong but will count all subclusters equally 1 at a time through the while 
should
 $i_per1 = 0; // need 
a double count so need two seperate
 $cper = 0;
   
while($i_per$num_per){
// so we 
need to run the while, probably need to cut the ending out here to add to end of total
 //gonna 
change this into an include so its not listed 3 times here-maybe
  // do 
math function
 $nper = 
$num_per;
 $nper2 = 
($nper*5);  // max reading to devide by
 //answer 
= // need to add all the answers here
 
while($i_per1$num_per){
  
  $cper = $cper;
  
  $cper1 = @mysql_result($result_per,$i_per1,ques_ans);
  
  $i_per1++;
  
  $cper2 = @mysql_result($result_per,$i_per1,ques_ans);
  
  $cper = ($cper+$cper1+$cper2);
  
 // $cper3 = $cper; // this is just an easy extraction
// i think this actualy might work

   echo 
sub=$sub_id = $cperp;
  
  $i_per1++;};  // this should loop through output to count the results total   
//TEST
//echo cper3 = $cper3;
   
 $i_per++;
 };
   $i_sub++;};

i know theres some redundant code in there etc.. but hey.. till it works i dont like 
to delete



-- Original Message --
From: Justin Farnsworth [EMAIL PROTECTED]
Date: Tue, 25 Dec 2001 09:28:53 -0500

I think you need to post the code.  The description of the
problem is a bit ambiguous.

_justin

Webmaster wrote:
 
 Hello.. of all days i have a project thats to be shown tomorrow.
 
 i cannot get the dam thing to work
 it should be simple i'd think
 
 i would post code and all and if asked will
 
 but it comes down to this.. i am using php 4 and mysql.. and doing math
 i have say 40 entries in the database, 20 for two differant surveys.. anytime anew 
person fills out the survey they get a unique id
 i have it set to grabe the results from each unigue id for each question through 
mysql.. but it seems to 

Re: Need Help bad!.. today.. of all days!

2001-12-25 Thread Brad Beaubien

Hello.. of all days i have a project thats to be shown tomorrow.

i cannot get the dam thing to work
it should be simple i'd think

i would post code and all and if asked will
[snip]

Is the performance of your code data independent?
That is to say, if you remove (from the database) the set of data where 
it currently stops, does it stop there again?
Does the code stop in the same place with different data?

Brad

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Re: need help with mysql rpms

2001-12-10 Thread Kelly Firkins

try just upgrading the RPMs using rpm -ivh

--
Kelly Firkins
[EMAIL PROTECTED]


I need to remove a previous version of mysql and install the newest. When
trying to remove the previous version it complains about dependencies . I
don't know what to do about it, so I end up with a successful install of 
the
new version. Any help would be appreciated

rpm -e mysql-3.23.36-1
error: removing these packages would break dependencies:
mysql = 3.23.36 is needed by mysql-devel-3.23.36-1
mysql = 3.23.36 is needed by mysql-server-3.23.36-1
mysql is needed by php-mysql-4.0.4pl1-9
libmysqlclient.so.10 is needed by mysql-server-3.23.36-1
libmysqlclient.so.10 is needed by perl-DBD-MySQL-1.2215-1
libmysqlclient.so.10 is needed by php-mysql-4.0.4pl1-9
libmysqlclient.so.10 is needed by rpm2html-1.5-4


Raymond


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Re: need help with mysql rpms

2001-12-10 Thread Raymond Norton

This is what I get
rpm -ivh 3.23.46-1.i386.rpm

error: failed dependencies:

 MySQL conflicts with mysql-3.23.36-1

 MySQL-server conflicts with mysql-server-3.23.36-1


- Original Message -
From: Kelly Firkins [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, December 10, 2001 4:20 PM
Subject: Re: need help with mysql rpms


 try just upgrading the RPMs using rpm -ivh

 --
 Kelly Firkins
 [EMAIL PROTECTED]


 I need to remove a previous version of mysql and install the newest. When
 trying to remove the previous version it complains about dependencies . I
 don't know what to do about it, so I end up with a successful install of
 the
 new version. Any help would be appreciated
 
 rpm -e mysql-3.23.36-1
 error: removing these packages would break dependencies:
 mysql = 3.23.36 is needed by mysql-devel-3.23.36-1
 mysql = 3.23.36 is needed by mysql-server-3.23.36-1
 mysql is needed by php-mysql-4.0.4pl1-9
 libmysqlclient.so.10 is needed by mysql-server-3.23.36-1
 libmysqlclient.so.10 is needed by perl-DBD-MySQL-1.2215-1
 libmysqlclient.so.10 is needed by php-mysql-4.0.4pl1-9
 libmysqlclient.so.10 is needed by rpm2html-1.5-4
 
 
 Raymond


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Re: need help with mysql rpms

2001-12-10 Thread Kelly Firkins

I don't have a Linux box around, so I'll have to check the specific order 
you can do it... in the meantime, have you tried
rpm -ivh *.rpm
from that directory?

Kelly

--
Kelly Firkins
[EMAIL PROTECTED]

This is what I get
rpm -ivh 3.23.46-1.i386.rpm

error: failed dependencies:

  MySQL conflicts with mysql-3.23.36-1

  MySQL-server conflicts with mysql-server-3.23.36-1


- Original Message -
From: Kelly Firkins [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Monday, December 10, 2001 4:20 PM
Subject: Re: need help with mysql rpms


  try just upgrading the RPMs using rpm -ivh
 
  --
  Kelly Firkins
  [EMAIL PROTECTED]
 
 
  I need to remove a previous version of mysql and install the newest. 
When
  trying to remove the previous version it complains about dependencies . 
I
  don't know what to do about it, so I end up with a successful install 
of
  the
  new version. Any help would be appreciated
  
  rpm -e mysql-3.23.36-1
  error: removing these packages would break dependencies:
  mysql = 3.23.36 is needed by mysql-devel-3.23.36-1
  mysql = 3.23.36 is needed by mysql-server-3.23.36-1
  mysql is needed by php-mysql-4.0.4pl1-9
  libmysqlclient.so.10 is needed by mysql-server-3.23.36-1
  libmysqlclient.so.10 is needed by perl-DBD-MySQL-1.2215-1
  libmysqlclient.so.10 is needed by php-mysql-4.0.4pl1-9
  libmysqlclient.so.10 is needed by rpm2html-1.5-4
  
  
  Raymond
 
 
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Re: need help with mysql rpms

2001-12-10 Thread Shankar Unni

Raymond Norton wrote:

 error: failed dependencies:
 
  MySQL conflicts with mysql-3.23.36-1
 
  MySQL-server conflicts with mysql-server-3.23.36-1


Yeah, the MySQL rpms are incompatible with the mysql rpms (which are done 
by RedHat). Apparently the two camps each think the other's file system 
layout and package organization is weird :-).  My last question on the 
topic never brought out a response from anyone concerned..

Unfortunately, the solution isn't as simple as just delete mysql* and 
install MySQL*, because RedHat has other packages that depend on the 
mysql RPMs, so you have to nuke those, too, and there aren't any 
replacement packages for those at the MySQL site.

The best solutions for you, if you don't feel like dealing with the 
problems, are:

1. Go ahead and delete the rest of the dependent packages of mysql (like 
php-mysql-4.0.4pl1-9), and rebuild those from source if you need them,

OR

1a. Remove just the mysql-* packages, but use the --nodeps option to 
disable the dependency checks for the other packages that depend on mysql.

OR

2. Upgrade using the latest RedHat-build RPMs (the latest one I could find 
is the one with the RH 7.2 distribution, which is 3.23.41.  Depending on 
how recent your libc, etc., are, this may well work with your distribution..
--
Shankar.



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Re: Need help with SELECT and JOIN pls

2001-12-07 Thread Mikel King

I'm no expert in this in fact I just recently started playing with 
joins, but here's one that I actually used for a recent shopprt cart 
piece. I appologise if it wraps but the output is long...content 
conatins the basic content info but product contains the list of prices. 
Yes I could have just as easily put the price in the content tbl, but I 
wanted the admin to pull the predefined prices from one source and make 
a selectable option rather than a type in value. I also figured from a 
maintenance standpoint when the price goes up it's one change etc... Ok 
so in any even I joined the two tbls on c.product_id and p.id. If I read 
you question correctly you should be able to perform smething similar on 
eventlog.id and crossref.id...

mysql select c.*, p.cost from content as c, product as p where 
c.product_id = p.id  ;
++-+-+---+--++-+--+
| id | filename| thumbnail   | sdescr| 
ldescr   | product_id | publish | cost |
++-+-+---+--++-+--+
|  3 | sample.mov  | OCSLogo.png | Silly Apple Comercial |  came with 
the streaming server. |  1 | y   | 5.95 |
|  1 | sample2.mov | OCSLogo.png | Silly Apple Comercial |  came with 
the streaming server. |  2 | y   | 2.95 |
|  2 | sample.mov  | OCSLogo.png | Silly Apple Comercial |  came with 
the streaming server. |  2 | y   | 2.95 |
++-+-+---+--++-+--+
3 rows in set (0.00 sec)


I hope this helps...

cheers,
Mikel

Jaime Teng wrote:

Hi,

I have two tables:

mysql describe eventlog;
+-+--+--+-+-++
| Field   | Type | Null | Key | Default | Extra  |
+-+--+--+-+-++
| id  | int(10) unsigned |  | PRI | NULL| auto_increment |
| timestamp   | int(10) unsigned |  | MUL | 0   ||
| description | char(100)|  | MUL | ||
+-+--+--+-+-++

mysql describe crossref;
+-+--+--+-+-++
| Field   | Type | Null | Key | Default | Extra  |
+-+--+--+-+-++
| word| char(20) |  | MUL | ||
| id  | int(10) unsigned |  | MUL | ||
+-+--+--+-+-++

Table 'eventlog' is a table of sentence and a unique 'id'. Table crossref 
is simply a table of single words and an index 'id'. an entry contains a 
word and an id where said word can be found on the table 'eventlog'. 

It is common that a: SELECT * from crossref where word = 'HELLO'; would
have multiple results.

My question here is I would like to do a search wherein I would like
to know which sentence contains the words 'HELLO' and 'DAY' and 'WORLD'.
take note that the sentence SHOULD contain ALL the three words not just
one or two.

I think this is a 'JOIN' question but I am not familiar how to use JOIN.
can you show me the syntax?

thanks for your help.
Jaime


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RE: need help

2001-12-05 Thread David Niu

Hi,All:
I need your help, When I compile the Msql-Mysql-Modules, I got errors, I am
running Redhat7.1 with perl5.6.1, the whole process is just as follows:

[root@wappy local]# cd Msql-Mysql-modules-1.2218
[root@wappy Msql-Mysql-modules-1.2218]# perl Makefile.PL
Which drivers do you want to install?

1)  MySQL only
2)  mSQL only (either of mSQL 1 or mSQL 2)
3)  MySQL and mSQL (either of mSQL 1 or mSQL 2)

4)  mSQL 1 and mSQL 2
5)  MySQL, mSQL 1 and mSQL 2

Enter the appropriate number:  [3] 1


Do you want to install the MysqlPerl emulation? You might keep your old
Mysql module (to be distinguished from DBD::mysql!) if you are concerned
about compatibility to existing applications! [n]
Where is your MySQL installed? Please tell me the directory that
contains the subdir 'include'. [/usr]
Which database should I use for testing the MySQL drivers? [test]
On which host is database test running (hostname, ip address
or host:port) [localhost]
User name for connecting to database test? [undef]
Password for connecting to database test? [undef]
Creating files for MySQL 
Checking if your kit is complete...
Looks good
Note (probably harmless): No library found for -lgz
Using DBI 1.18 installed in
/usr/local/lib/perl5/site_perl/5.6.1/i686-linux/auto/DBI
Writing Makefile for DBD::mysql
Writing Makefile for Msql-Mysql-modules
[root@wappy Msql-Mysql-modules-1.2218]# make
/usr/local/bin/pod2text mysql/lib/DBD/mysql.pm README
make[1]: Entering directory `/usr/local/Msql-Mysql-modules-1.2218/mysql'
cp lib/DBD/mysql.pm ../blib/lib/DBD/mysql.pm
cp lib/Bundle/DBD/mysql.pm ../blib/lib/Bundle/DBD/mysql.pm
cp lib/Mysql/Statement.pm ../blib/lib/Mysql/Statement.pm
cp lib/Mysql.pm ../blib/lib/Mysql.pm
cc -c -I/usr/local/lib/perl5/site_perl/5.6.1/i686-linux/auto/DBI -I/usr/incl
ude/mysql -I../dbd -I/usr/local/lib/perl5/site_perl/5.6.1/i686-linux/auto/DB
I -I/usr/local/lib/perl5/5.6.1/i686-linux -fno-strict-aliasing -D_LARGEFILE_
SOURCE -D_FILE_OFFSET_BITS=64 -O2   -DVERSION=\2.0418\ -DXS_VERSION=\2.04
18\ -fpic -I/usr/local/lib/perl5/5.6.1/i686-linux/CORE -DDBD_MYSQL dbdimp.c
dbdimp.c: In function `MysqlReconnect':
dbdimp.c:2157: warning: assignment from incompatible pointer type
/usr/local/bin/perl -p -e s/~DRIVER~/mysql/g 
/usr/local/lib/perl5/site_perl/5.6.1/i686-linux/auto/DBI/Driver.xst 
mysql.xsi
/usr/local/bin/perl -I/usr/local/lib/perl5/5.6.1/i686-linux -I/usr/local/lib
/perl5/5.6.1 /usr/local/lib/perl5/5.6.1/ExtUtils/xsubpp  -typemap
/usr/local/lib/perl5/5.6.1/ExtUtils/typemap mysql.xs  mysql.xsc  mv
mysql.xsc mysql.c
Warning: duplicate function definition 'rows' detected in mysql.xs, line 407
cc -c -I/usr/local/lib/perl5/site_perl/5.6.1/i686-linux/auto/DBI -I/usr/incl
ude/mysql -I../dbd -I/usr/local/lib/perl5/site_perl/5.6.1/i686-linux/auto/DB
I -I/usr/local/lib/perl5/5.6.1/i686-linux -fno-strict-aliasing -D_LARGEFILE_
SOURCE -D_FILE_OFFSET_BITS=64 -O2   -DVERSION=\2.0418\ -DXS_VERSION=\2.04
18\ -fpic -I/usr/local/lib/perl5/5.6.1/i686-linux/CORE -DDBD_MYSQL mysql.c
Running Mkbootstrap for DBD::mysql ()
chmod 644 mysql.bs
rm -f ../blib/arch/auto/DBD/mysql/mysql.so
LD_RUN_PATH=/usr/lib/mysql:/lib:/usr/lib:/usr/lib/gcc-lib/i386-redhat-linux
/2.96 cc  -shared -L/usr/local/lib dbdimp.o mysql.o -L/usr/lib/mysql  -o
../blib/arch/auto/DBD/mysql/mysql.so   -L/usr/lib/mysql -lmysqlclient -lm -l
z -L/usr/lib/gcc-lib/i386-redhat-linux/2.96 -lgcc
/usr/bin/ld: cannot find -lz
collect2: ld returned 1 exit status
make[1]: *** [../blib/arch/auto/DBD/mysql/mysql.so] Error 1
make[1]: Leaving directory `/usr/local/Msql-Mysql-modules-1.2218/mysql'
make: *** [subdirs] Error 2
[root@wappy Msql-Mysql-modules-1.2218]#


Could somebody tell me what's wrong.

Thanks a lot.

David Niu

Dec.5th


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Re: Need help with SELECT 2 tables from choice of 3

2001-11-21 Thread Thomas S. Iversen

 OldMembers
 Memebers
 Data

Why no have 3 tables:

Members
Data
TheseMembersAreOld

Members and Data are as you have them defined. TheseMembersAreOld
contains only the Member_ID field.

You then make the Member_ID field primary key on TheseMembersAreOld and
Members. You can then perform a very fast joins.

Thomas, Denmark


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Re: Need help with SELECT 2 tables from choice of 3

2001-11-21 Thread Jerry

Why no have 3 tables:

Members
Data
TheseMembersAreOld

Members and Data are as you have them defined. TheseMembersAreOld
contains only the Member_ID field.

You then make the Member_ID field primary key on TheseMembersAreOld and
Members. You can then perform a very fast joins.

Hm, thank you for the idea... I think my problem is the OLD members and
members are not the same people. That is why I have renamed them (added
10 number to every one of them), so Data table now has

numbers from 1-1000 (my new members)
numbers from 10 to 101000 (my old members).

From old members I only need the name, nothing else! From new members I need
all the data.

Now because in the forum topic (yes, I am builing a custom forum) there must
be a member, I need

1. If this is an old member from the old forum to disply only name
2. If member is new to display all the data.

Now I have a problem of joining the 3 tables because obviously in Data field
Member_ID there is a number that represents a member OR a number that
represents a old member, never both (none is the same). In SQL I can not do
the AND and compare both MEMBER_ID's because it would never return anything.
If I use or I do get data, but not one, but multiplied number od times (every
new member is then resulted or every old member, depending on in which table
SQL finds the data).

Yours

Jerry
Slovenia


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Re: Need help migrating MSSQL to MySQL...

2001-11-17 Thread Benjamin Pflugmann

Hi.

On Tue, Nov 06, 2001 at 12:34:26AM -0700, [EMAIL PROTECTED] wrote:
 In MSSQL I can aggregate various fields like the [totalRev] field listed
 below:
 
 Does anyone know if or how to do this in MySQL?

You can't. You only can do this in the SELECT clause or make a column
that your application keeps current on INSERT/UPDATE.

Bye,

Benjamin.

 
 CREATE TABLE [dbo].[Financials] (
[...]
 [revM11] [float] NULL ,
 [revM12] [float] NULL ,
 [totalRev] AS ([revM1] + [revM2] + [revM3] + [revM4] + [revM5] + [revM6] +
 [revM7] + [revM8] + [revM9] + [revM10] + [revM11] + [revM12])
 ON [PRIMARY]
[...]

-- 
[EMAIL PROTECTED]

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Re: Need help with mysqldump

2001-11-14 Thread Aleksandar Bradaric

Hi,

 I'm running MySQL ver 3.23.38 on Win98 platform and am trying to learn
 to do backups. I'm trying the mysqldump command but I'm getting the
 error:

 Access denied for user '@localhost'

 How do I specify a user for mysqldump?


mysqldump  --user=username ... Try mysqldump --help for more
:)


Regards,
Sasa



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Re: Need help with a query ...

2001-11-04 Thread Anvar Hussain K.M.

Hi John Kelly,

This is not a perfect solution but may be useful to you. But still with two 
queries!
 From Mysql prompt issue these two queries.

SELECT  @maxcat := max(Category) FROM table
WHERE category = 'Sports:Football:Players' OR
category = 'Sports:Football' OR category = 'Sports';

Select * from table where category = @maxcat;

Note that abc is greater than ab
This will not be affected by the depth of category.
Anvar.

At 06:15 PM 02/11/2001 -0800, you wrote:
Hi, I have a MySQL table with a column that contains some of a web site
directory's category names in the format:

Sports:Football:Players

I am trying to build a query that that locates all records that match the
above category name OR if none exist its parent Sports:Football OR if none
exist its parent Sports. The top level category, in this case Sports,
will always have at least one matching record.

I know I can do this with multiple queries by checking the previous query's
result, but I am trying to build a query that does it all in one lookup to
avoid lots of lookups in deep categories. Something along the logical lines
of ...

SELECT * FROM table WHERE category = 'Sports:Football:Players' OR IF NONE
category = 'Sports:Football' OR IF NONE category = 'Sports'

... of course the above query does not work but if anyone knows of how to
accomplish something similar in one query I would much appreciate it.

Thanks!



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Re: Need help with a query ...

2001-11-02 Thread Michael

You need to use the LIKE command I think. The MySQL manual should give you
all the details. If you need further help I can just write the whole query
out for you. Or was the problem that you only want to worry about the
if..then stuff if needed? If so could you tell what your pulling back from
that table?

The principal mark of genius is not perfection but originality, the
opening of new frontiers.
   -- Arthur Koestler

*^*^*^*
Michael McGlothlin [EMAIL PROTECTED]
http://mlug.missouri.edu/~mogmios/projects/

On Fri, 2 Nov 2001, John Kelly wrote:

 Hi, I have a MySQL table with a column that contains some of a web site
 directory's category names in the format:
 
 Sports:Football:Players
 
 I am trying to build a query that that locates all records that match the
 above category name OR if none exist its parent Sports:Football OR if none
 exist its parent Sports. The top level category, in this case Sports,
 will always have at least one matching record.
 
 I know I can do this with multiple queries by checking the previous query's
 result, but I am trying to build a query that does it all in one lookup to
 avoid lots of lookups in deep categories. Something along the logical lines
 of ...
 
 SELECT * FROM table WHERE category = 'Sports:Football:Players' OR IF NONE
 category = 'Sports:Football' OR IF NONE category = 'Sports'
 
 ... of course the above query does not work but if anyone knows of how to
 accomplish something similar in one query I would much appreciate it.
 
 Thanks!
 
 
 
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Re: Need help with a query ...

2001-11-02 Thread John Kelly

Hi, thanks for your response.  I don't see how the LIKE command would help
me pull records that matched the category name or its parent category if
none exist, or its parent category if none exists. Perhaps you could provide
a example. I want something that follows this logic ...

SELECT * FROM table WHERE category = 'Sports:Football:Players' OR IF NONE
category = 'Sports:Football' OR IF NONE category = 'Sports'

Regarding the purpose of this query, it will be performed in every
page/category in a web site directory looking to see if an advertisement is
available for the current category, if not, it needs to look for one
assigned to the parent category, so on and so on until it reaches the top
level category for which there will always be an ad.

Any suggestions/examples appreciated!

John

- Original Message -
From: Michael [EMAIL PROTECTED]
To: John Kelly [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Friday, November 02, 2001 7:09 PM
Subject: Re: Need help with a query ...


 You need to use the LIKE command I think. The MySQL manual should give you
 all the details. If you need further help I can just write the whole query
 out for you. Or was the problem that you only want to worry about the
 if..then stuff if needed? If so could you tell what your pulling back from
 that table?

 The principal mark of genius is not perfection but originality, the
 opening of new frontiers.
-- Arthur Koestler

 *^*^*^*
 Michael McGlothlin [EMAIL PROTECTED]
 http://mlug.missouri.edu/~mogmios/projects/

 On Fri, 2 Nov 2001, John Kelly wrote:

  Hi, I have a MySQL table with a column that contains some of a web site
  directory's category names in the format:
 
  Sports:Football:Players
 
  I am trying to build a query that that locates all records that match
the
  above category name OR if none exist its parent Sports:Football OR if
none
  exist its parent Sports. The top level category, in this case
Sports,
  will always have at least one matching record.
 
  I know I can do this with multiple queries by checking the previous
query's
  result, but I am trying to build a query that does it all in one lookup
to
  avoid lots of lookups in deep categories. Something along the logical
lines
  of ...
 
  SELECT * FROM table WHERE category = 'Sports:Football:Players' OR IF
NONE
  category = 'Sports:Football' OR IF NONE category = 'Sports'
 
  ... of course the above query does not work but if anyone knows of how
to
  accomplish something similar in one query I would much appreciate it.
 
  Thanks!
 
 
 
  -
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 http://lists.mysql.com/   (the list archive)
 
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Re: Need help with a query ...

2001-11-02 Thread Bob Hall

On Fri, Nov 02, 2001 at 06:15:08PM -0800, John Kelly wrote:
 Hi, I have a MySQL table with a column that contains some of a web site
 directory's category names in the format:
 
 Sports:Football:Players
 
 I am trying to build a query that that locates all records that match the
 above category name OR if none exist its parent Sports:Football OR if none
 exist its parent Sports. The top level category, in this case Sports,
 will always have at least one matching record.
 
 I know I can do this with multiple queries by checking the previous query's
 result, but I am trying to build a query that does it all in one lookup to
 avoid lots of lookups in deep categories. Something along the logical lines
 of ...
 
 SELECT * FROM table WHERE category = 'Sports:Football:Players' OR IF NONE
 category = 'Sports:Football' OR IF NONE category = 'Sports'
 
 ... of course the above query does not work but if anyone knows of how to
 accomplish something similar in one query I would much appreciate it.

Sir, the problem is that relational databases use set logic, and you 
are trying to find a solution in sequential logic.

You need three tables. I'll call them Cat1, Cat2, and Cat3, but you 
should rename them to whatever makes sense to you. They will hold, 
respectively, 'Sports', 'Football', and 'Players'. (Or 'Business', 
'Industry', and 'Firms'. Or whatever.)

The table structure would be something like:
Cat1(Cat1ID, Category)
Cat2(Cat1ID, Cat2ID, Category)
Cat3(Cat2ID, Cat3ID, Category)

A sample row in Cat1 would be (1, 'Sports')
A sample row in Cat2 would be (1, 1, 'Football')
A sample row in Cat3 would be (1, 1, 'Players')

(If you're not concerned about economizing on storage, you could
eliminate the IDs and have each child record refer to the parent 
category instead of the parent ID. In that case, you don't need 
the Cat1 table, which serves only to match a category with its
ID.)

The query would be
SELECT Cat1.Category, Cat2.Category, Cat3.Category
FROM (Cat1 LEFT JOIN Cat2 ON Cat1.Cat1ID = Cat2.Cat1ID)
 LEFT JOIN Cat3 ON Cat2.Cat2ID = Cat3.Cat2ID
WHERE Cat1.Category = 'Sports' 
  AND (Cat2.Category = 'Football' OR Cat2.Category IS NULL) 
  AND (Cat3.Category = 'Players' OR Cat3.Category IS NULL);

If you want the output in the 'Sports:Football:Players' form, you 
can rewrite the SELECT clause as
SELECT Concat(Cat1.Category, 
  If(IsNull(Cat2.Category), '', ':'), Cat2.Category,
  If(IsNull(Cat3.Category), '', ':'), Cat3.Category)

Disclaimer: I haven't run this, so I might have gotten some of the 
details wrong.

Bob Hall

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Re: need help setting up and rinning mysql server

2001-10-04 Thread Carl Troein


jesse junsay writes:

 Then this error occurs.
 
 starting mysqld daemon with databases from XX
 mysql daemon ended
 
 The manual didn't say anything on how to solve this
 problem. So I hope this will help.

That's not an error message. Error messages can be
found in the error log, which the manual discusses here:
http://www.mysql.com/doc/E/r/Error_log.html

-- 
 Carl Troein - Círdan / Istari-PixelMagic - UIN 16353280
 [EMAIL PROTECTED] | http://pixelmagic.dyndns.org/~cirdan/
 Amiga user since '89, and damned proud of it too.


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Re: need help setting up and rinning mysql server

2001-10-04 Thread Gerald Clark

Unless you ran it as
mysql_install_db --user=mysql
mysql does not own the databases.
do
chown -R mysql /usr/local/mysql
chown -R /var/lib/mysql
( Or whereever your database directory is )

jesse junsay wrote:

 Hi..
 
 I have a problem running my MySQL server. After
 running shellmysql_install_db when everything runs
 fine then I tried to start the server with this
 command shellsafe_mysqld 
 
 Then this error occurs.
 
 starting mysqld daemon with databases from XX
 mysql daemon ended
 
 The manual didn't say anything on how to solve this
 problem. So I hope this will help.
 
 Please send your response to [EMAIL PROTECTED]
 
 
 thanks...
 
 
 __
 Do You Yahoo!?
 NEW from Yahoo! GeoCities - quick and easy web site hosting, just $8.95/month.
 http://geocities.yahoo.com/ps/info1
 
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-- 
Gerald L. Clark
[EMAIL PROTECTED]


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Re: need help to uninstall mysql

2001-09-18 Thread Chris


I had a similar problem on a win2k system when I started using mySQL. I
changed the user and password in phpmyadmin's config.inc.php. Or you can
change it in the my.ini file.

This might be alot more complicated with a unix system.

- Original Message -
From: GUYOT Carole [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, September 18, 2001 15:21
Subject: need help to uninstall mysql


 I've changed root's password via netscape with phpmyadmin and then
 reloaded.
 It's not possible to connect anymore. The system asked for a new
 password but didn't accept the new one.

 So, I've tryed to re-install mysql again
 version : MySQL-3.23.38-1.i386.rpm on redhat Linux.
 Now, when I try to connect, I have
 ERROR 2002: Can't connect to local MySQL server through socket
 '/var/lib/mysql/mysql.sock' (111)
 Things are getting worse and worse!
 How can I completely uninstall and get clean all files linked to mysql?

 Need urgent help please !


 NTMail K12 - the Mail Server for Education

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***

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Re: need help to uninstall mysql

2001-09-18 Thread Dana Powers

First, there is no need to reinstall.
For future reference, if you forget your password - check the manual for an
easy way to fix:  http://www.mysql.com/doc/R/e/Resetting_permissions.html

For a mysql that wont start, check the error log and isolate what the
problem is ( it probably isnt that hard to fix ). The log is probably
/var/lib/mysql/hostname.err , but Im not familiar with redhat so that is
just a guess.

dpk

- Original Message -
From: GUYOT Carole [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, September 18, 2001 6:21 AM
Subject: need help to uninstall mysql


 I've changed root's password via netscape with phpmyadmin and then
 reloaded.
 It's not possible to connect anymore. The system asked for a new
 password but didn't accept the new one.

 So, I've tryed to re-install mysql again
 version : MySQL-3.23.38-1.i386.rpm on redhat Linux.
 Now, when I try to connect, I have
 ERROR 2002: Can't connect to local MySQL server through socket
 '/var/lib/mysql/mysql.sock' (111)
 Things are getting worse and worse!
 How can I completely uninstall and get clean all files linked to mysql?

 Need urgent help please !


 NTMail K12 - the Mail Server for Education

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Re: need help with select statements

2001-08-30 Thread Ian Barwick

On Thursday 30 August 2001 15:28, Andre Konopka wrote:
 Hi,

 I have, three tables (one,two, three) with the rows id/value. id is the
 key for all the tables.


 with


 select value from one where id=xx;
 select value from two where id=xx;
 select value from three where id=xx;


 I can select all values from the tables with the id=xx.

 How can I do this with one select statement. Notice, it's possible that
 there is an entry for id=xx in table one, but
 not in table two, or three. Of course ist's possible that there is only
 a value in table three.

 The output could be

 id one.value two.value three.value
 x1  233  2342   NULL
 x2  NULL 998NULL
 x3  33   232 23

 Clear enough?

A couple of LEFT JOINs should probably do the trick

HTH

Ian Barwick


-- 
Ian Barwick - Developer - [EMAIL PROTECTED]
akademie.de asp GmbH - http://www.akademie.de

To query tables in a MySQL database is more fun than eating spam

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Re: Need Help Setting Up MySQL on Win98

2001-08-28 Thread Grigory Bakunov

Date |Mon, 27 Aug 2001 12:54:25 -0700 (PDT)
From |S K Bryan [EMAIL PROTECTED]

Hello!

SKB Hello -

SKB I'm very new at this, so please pardon the very beginner questions...

SKB I'm attemtping to install MySQL to my local machine running Win98. The
SKB install seems to go alright, but when I try mysqld--standalone it
SKB gives me an error. Then I tried mysqld -standalone, which seemed to
SKB work.

SKB Then I entered, mysqladmin create testDB and I got the error message
SKB Can't connect to MySQL Server on 'localhost'. I tried telnetting to
SKB telnet localhost 3306 and got an error that it couldn't connect.

SKB Can anyone offer help?

You need to use just
c:\mysql\bin\mysqld
command to start mysqld

Also note that you need to have winsock 2 installed on your 
Win.

http://www.mysql.com/doc/W/i/Win95_start.html


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Re: Need Help Setting Up MySQL on Win98

2001-08-27 Thread John Meyer

At 12:54 PM 8/27/01 -0700, you wrote:
Hello -

I'm very new at this, so please pardon the very beginner questions...

I'm attemtping to install MySQL to my local machine running Win98. The
install seems to go alright, but when I try mysqld--standalone it
gives me an error. Then I tried mysqld -standalone, which seemed to
work.

Then I entered, mysqladmin create testDB and I got the error message
Can't connect to MySQL Server on 'localhost'. I tried telnetting to
telnet localhost 3306 and got an error that it couldn't connect.

Can anyone offer help?


Yeah, try double clicking on the winmysqladmin.exe icon.


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Re: Need Help Setting Up MySQL on Win98

2001-08-27 Thread Gerald R. Jensen

Try putting a space between mysqld and --standalone (mysqld --standalone)

- Original Message -
From: S K Bryan [EMAIL PROTECTED]
To: MySQL [EMAIL PROTECTED]
Sent: Monday, August 27, 2001 2:54 PM
Subject: Need Help Setting Up MySQL on Win98


Hello -

I'm very new at this, so please pardon the very beginner questions...

I'm attemtping to install MySQL to my local machine running Win98. The
install seems to go alright, but when I try mysqld--standalone it
gives me an error. Then I tried mysqld -standalone, which seemed to
work.

Then I entered, mysqladmin create testDB and I got the error message
Can't connect to MySQL Server on 'localhost'. I tried telnetting to
telnet localhost 3306 and got an error that it couldn't connect.

Can anyone offer help?

Thanks -

Shawn
[EMAIL PROTECTED]

__
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Make international calls for as low as $.04/minute with Yahoo! Messenger
http://phonecard.yahoo.com/

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RE: need help

2001-08-19 Thread Venu

Hi !!

)-Original Message-
)From: qball cow [mailto:[EMAIL PROTECTED]]
)Sent: Sunday, August 19, 2001 10:50 AM
)To: [EMAIL PROTECTED]
)Subject: Fw: need help
)
)
)I have made a mysql server on my linux box. and via Myobdc I
)access it from a C++ programm I made.. I can see the records.. but
)If I change one.. I get the error:
)
)No Cursor name availible
)
)I dont know whats wrong.. so I hope anybody can help me.
)

Did you tried with the latest .38 MyODBC driver ? Also, the error message
says you are trying to do some cursor operation, without setting the cursor
name through SQLSetCursorName prior to the execution.

Is it possible for you to send the ODBC trace, so that we can guess what
exactly is going wrong ?

Thanks in advance
Venu
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Re: Need help with mysql

2001-06-16 Thread Trond Eivind Glomsrød

Malkhaz Mangoshvili [EMAIL PROTECTED] writes:

 Hello. I installed on my computer Red Hat Linux 7.0. After that I started 
configuring  
 mysql. I upgraded  mysql, added all necessary packages and I wanted to run mysql 
server.  
 Whenever I type mysql it gives me such an error message: ERROR
 2002: Can't connect to MYSQL server through socket
 /var/lib/mysql/mysql.sock . I found out from the internet that I
 needed to change permission for the mysql.socket by typing chmod 777
 mysql.socket. For the first time this file didn't even exist, then
 it was created when I typed mysql_install_db, but it is
 empty. Version of this mysql is: 3.23.22-beta.

1) Remove /var/lib/mysql (shouldn't be necesarry, but just to be safe
2) Get the updated rpms (you can get them with up2date). The version
   of these are mysql-3.23.32-1.7
3) Start mysql with service mysqld start - don't do safe_mysqld,
   mysql_install_db:  The database is initialized automatically the
   first time it's run 

-- 
Trond Eivind Glomsrød
Red Hat, Inc.

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Re: Need help with mysql

2001-06-16 Thread Paul DuBois

At 6:23 PM -0400 6/16/01, Malkhaz Mangoshvili wrote:
Hello. I installed on my computer Red Hat Linux 7.0. After that I 
started configuring 
mysql. I upgraded  mysql, added all necessary packages and I wanted 
to run mysql server.

Are you using RedHat's MySQL RPMs?  If so, you should uninstall them and
start over with the RPMs from the MySQL site.

Whenever I type mysql it gives me such an error message: ERROR 
2002: Can't connect to MYSQL server through socket 
/var/lib/mysql/mysql.sock . I found out from the internet that I 
needed to change permission for the mysql.socket by typing chmod 777 
mysql.socket. For the first time this file didn't even exist, then 
it was created when I typed mysql_install_db, but it is empty. 
Version of this mysql is: 3.23.22-beta.
   I am very sorry about that, but I really need to get mysql running 
from the Linux platform, in order to use it in my C/C++ programs. 
Please if anybody could help me I would appreciate that. I'll wait 
for the answer. Thank you.

 
Mike


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RE: Need help on mysql/php

2001-06-07 Thread Adrian D'Costa

On Wed, 6 Jun 2001, Ian Ford wrote:

 Name your config file config.inc and if any of the below situations
 happen your password and username will not show up in plain text for the
 casual browser.
 (EXAMPLE:
 
   CONFIG.INC
   ?
   $DBname = 'test';
   $DBuser = 'imatest';
   $DBpass = 'Whatever';
   $DBhost = 'localhost';
   ?
 
   INDEX.PHP
   ?
   require(config.inc);
   $conn = mysql_connect($DBhost,$DBuser,$DBpass);
 mysql_select_db($DBname);
   ?
 
 END EXAMPLE)
 You can place the config.inc any where you want. My preference is in a
 includes folder...

Actually I tried this out sometime ago and found that it appears as a
plain text file.  This I believe is because the webserver know that .php
or .php3 should be treated as a php file and other in which ever way it
can display.


 
 -Original Message-
 From: Neil Zanella [mailto:[EMAIL PROTECTED]]
 Sent: Wednesday, June 06, 2001 12:09 PM
 To: Don Read
 Cc: Ed Peddycoart; Mysql@Lists. Mysql. Com; Jorge Oliveira
 Subject: RE: Need help on mysql/php
 
 
 
 On Tue, 5 Jun 2001, Don Read wrote:
 
  Better yet, put the file outside the $DOCUMENT_ROOT, in case your
 server is
  poorly configured.
 
  include($DOCUMENT_ROOT/../config.php);
 
 This is a very good idea. One day if the system administrator decides to
 back up all the user data and upgrade the web server and forgets to
 include support for PHP then all the PHP files become readable as plain
 text and casual web surfers could sniff your password. Another scenario
 where this could happen is if there are two web servers and your home
 directory is mounted on both via NFS or AFS and you may not be aware
 that
 the other web server does not have PHP support.
 
 If you are serving from /home/httpd/html then store your database access
 information including passwords in some directory like
 /home/httpd/secret
 and set the right ownerships for that directory and files therein. It is
 also a good idea to control extraneous access to the database by
 firewalling your site.
 
 Neil
 
 
 -
 Before posting, please check:
http://www.mysql.com/manual.php   (the manual)
http://lists.mysql.com/   (the list archive)
 
 To request this thread, e-mail [EMAIL PROTECTED]
 To unsubscribe, e-mail
 [EMAIL PROTECTED]
 Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php
 
 


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RE: Need help on mysql/php

2001-06-07 Thread Paul DuBois

At 2:13 PM +0530 6/7/01, Adrian D'Costa wrote:
On Wed, 6 Jun 2001, Ian Ford wrote:

  Name your config file config.inc and if any of the below situations
  happen your password and username will not show up in plain text for the
  casual browser.
  (EXAMPLE:

  CONFIG.INC
  ?
  $DBname = 'test';
  $DBuser = 'imatest';
  $DBpass = 'Whatever';
  $DBhost = 'localhost';
  ?

  INDEX.PHP
  ?
  require(config.inc);
  $conn = mysql_connect($DBhost,$DBuser,$DBpass);
mysql_select_db($DBname);
  ?

  END EXAMPLE)
  You can place the config.inc any where you want. My preference is in a
  includes folder...

Actually I tried this out sometime ago and found that it appears as a
plain text file.  This I believe is because the webserver know that .php
or .php3 should be treated as a php file and other in which ever way it
can display.

That only applies to the extension of the top-level file.  Included
files can have any extension.  You do, however, have to surround the
text of the included file with ?php ? or ? ? or whatever tags you
use.  That might have been your problem.

-- 
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RE: Need help on mysql/php

2001-06-06 Thread Sommai Fongnamthip

split code for use username and password to connect to MySQL into other 
file and use include in every php program instead have username and 
password code.

connect.inc.php
?
// define database connect variable
$hostname = localhost;
$username = root;
$password = password;
$tblname = yourtablename;
$dbName = yourdbname;
MYSQL_CONNECT($hostname, $username, $password)
 OR DIE(Unable to connect to database);
@mysql_select_db($dbName)
 or die(Unable to select database);
print Succesful connect...;
?

readfile.php
?
include (connect.inc.php);
...
other php code
...
?

Regards,
Sommai Fongnamthip

At 22:37 5/6/2001 +0100, Jorge Oliveira wrote:
Hi again,

You are right, your username and password will have to be on every PHP
script that needs to use database.

However, you don't have to be afraid because nobody can access the source of
your PHP scripts - unless they are a good hacker!

I think you should pay a visit to http://www.php.net to understand how PHP
works. Start with the basics and you will see that is reallY VERY simple.

Be cool,


Jorge Oliveira
[EMAIL PROTECTED]


© webfroggie.com - Recursos Online!
web: http://www.webfroggie.com
wap: http://www.webfroggie.com





-Mensagem original-
De: Ed Peddycoart [mailto:[EMAIL PROTECTED]]
Enviada: Quarta-feira, 6 de Junho de 2001 0:29
Para: Jorge Oliveira; Mysql@Lists. Mysql. Com
Assunto: RE: Need help on mysql/php


Thanks...this helped...Just had success in connecting to the MySQL server
and dumping the db contents to the screenOne worrisome bit though...My
username and password for connecting to the db on my host is my username and
password for the web account.  If I want to create dynamic webpages by
pulling data from my db, won't I have to put this information (usersname and
pw) in the php file and leave it on the server?  Sounds pretty darn scary to
me...maybe I am confused.
Ed

-Original Message-
From: Jorge Oliveira [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, June 05, 2001 12:47 PM
To: Mysql@Lists. Mysql. Com
Subject: RE: Need help on mysql/php


Hi,

Please refer to http://www.php.net/manual/en/ref.mysql.php


Jorge Oliveira
[EMAIL PROTECTED] mailto:[EMAIL PROTECTED]


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-Mensagem original-
De: Ed Peddycoart [mailto:[EMAIL PROTECTED]]
Enviada: Terça-feira, 5 de Junho de 2001 21:31
Para: [EMAIL PROTECTED]
Assunto: Need help on mysql/php


I recently move my website to FastWebServers.com.  MySQL and PHP is
provided.  I have a control panel which allows me to initialize MySQL for my
use.  The initialization creates a db, named celticblues_com (my domain is
celticblues.com).  So far, I have added a table to my database, and added
the neccessary fields.  Now I am at a total loss at what to do.  I want to
use PHP scripts to pull info from the db and search the db etc.  I have
contacted my support from FWS, but they point me to MySQL.com for Mysql
commands technical support.  Seems to me I would need to know how to set
username/password to access the db from script etc.   The bottom line
question is can someone point me to information on what I need to do to be
able to access(open/close) the db, retrieve/store information, etc. in this
type of environment (i.e. MySQL provide by my host service, not installed by
me)?
Ed


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Re: need help for a simple request

2001-06-06 Thread Rafal Jank

alexandre Roussel wrote:
 
 Hi,
 
 I have some problems with the following SQL request that I process with phpMyAdmin :
 select * from TABLE2 where FIELD not in (select FIELD from TABLE1);
 
 This request identify all records in TABLE2 which are not in TABLE1 (depending on 
value of FIELD).
 TABLE1 and TABLE2 have exactly the same sturcture.
 
 I currently use MySql 3.22.34 and phpMyAdmin 2.1.0
 
 What's wrong ?
 
You cannot use subqueries in MySQL. Try something like this:
select table2.field from table2 left join table1 on (table2.field=table1.field)
where table1.field is null;
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Re: need help for a simple request

2001-06-06 Thread MikemickaloBlezien

On Wed, 6 Jun 2001 11:52:14 +0200, alexandre Roussel
[EMAIL PROTECTED]   wrote:

subselects are not currently supported with MySQL.


Hi,

I have some problems with the following SQL request that I process with phpMyAdmin :
select * from TABLE2 where FIELD not in (select FIELD from TABLE1);

This request identify all records in TABLE2 which are not in TABLE1 (depending on 
value of FIELD).
TABLE1 and TABLE2 have exactly the same sturcture.

I currently use MySql 3.22.34 and phpMyAdmin 2.1.0

What's wrong ?

Thank you for your help.



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Mike(mickalo)Blezien

Thunder Rain Internet Publishing
Providing Internet Solutions that work!
http://www.thunder-rain.com
Tel: 1(225) 686-2002
=
















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RE: Need help on mysql/php

2001-06-06 Thread Paul DuBois

At 7:49 AM -0700 6/6/01, Ed Peddycoart wrote:
It is a shared server
Ed

Then you're vulnerable, unless the ISP can demonstrate otherwise.


-Original Message-
From: Paul DuBois [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, June 05, 2001 6:02 PM
To: Jorge Oliveira; Ed Peddycoart
Cc: Mysql@Lists. Mysql. Com
Subject: RE: Need help on mysql/php


At 10:37 PM +0100 6/5/01, Jorge Oliveira wrote:
Hi again,

You are right, your username and password will have to be on every PHP
script that needs to use database.

However, you don't have to be afraid because nobody can access the source
of
your PHP scripts - unless they are a good hacker!

Actually, anyone else on the Web server host that has permission to
install scripts for the Web server can access the source.

I couldn't tell from the original message whether the Web server is
shared with other people or not, but if you don't have your own
server, you're exposed.


I think you should pay a visit to http://www.php.net to understand how PHP
works. Start with the basics and you will see that is reallY VERY simple.

Be cool,


Jorge Oliveira
[EMAIL PROTECTED]


© webfroggie.com - Recursos Online!
web: http://www.webfroggie.com
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--
Paul DuBois, [EMAIL PROTECTED]


--
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RE: Need help on mysql/php

2001-06-06 Thread Kenneth Kopelson

Actually you are only exposed if you have not set up Apache to run with 
virtual hosts.  It is not difficult to configure Apache so that a person 
can only see the scripts that are in his/her directory, and is prevented 
from seeing or modifying the scripts in other peoples directories.  Also, 
it is wise to place your DB passwords in a separate small file, and then 
include the file in all your scripts.  You can place the password file in a 
directory that doesn't have any accessibility from anyone on the 
web.  Let's say we have a password file called dbpass.inc, and we place 
it in a directory called /var/protected off the root.  Only the webserver 
is set to have permission to access this directory.  The password file 
should look something like this:

?php
username=username;
password=password;
?

Then in all your scripts include the following line:

include ('/var/protected/dbpass.inc);

-Ken

At 08:02 PM 6/5/01 -0500, Paul DuBois wrote:
At 10:37 PM +0100 6/5/01, Jorge Oliveira wrote:
Hi again,

You are right, your username and password will have to be on every PHP
script that needs to use database.

However, you don't have to be afraid because nobody can access the source of
your PHP scripts - unless they are a good hacker!

Actually, anyone else on the Web server host that has permission to
install scripts for the Web server can access the source.

I couldn't tell from the original message whether the Web server is
shared with other people or not, but if you don't have your own
server, you're exposed.


I think you should pay a visit to http://www.php.net to understand how PHP
works. Start with the basics and you will see that is reallY VERY simple.

Be cool,


Jorge Oliveira
[EMAIL PROTECTED]


© webfroggie.com - Recursos Online!
web: http://www.webfroggie.com
wap: http://www.webfroggie.com


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RE: Need help on mysql/php

2001-06-06 Thread Neil Zanella


On Tue, 5 Jun 2001, Don Read wrote:

 Better yet, put the file outside the $DOCUMENT_ROOT, in case your server is
 poorly configured.

 include($DOCUMENT_ROOT/../config.php);

This is a very good idea. One day if the system administrator decides to
back up all the user data and upgrade the web server and forgets to
include support for PHP then all the PHP files become readable as plain
text and casual web surfers could sniff your password. Another scenario
where this could happen is if there are two web servers and your home
directory is mounted on both via NFS or AFS and you may not be aware that
the other web server does not have PHP support.

If you are serving from /home/httpd/html then store your database access
information including passwords in some directory like /home/httpd/secret
and set the right ownerships for that directory and files therein. It is
also a good idea to control extraneous access to the database by
firewalling your site.

Neil


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RE: Need help on mysql/php

2001-06-06 Thread Paul DuBois

At 10:35 AM -0700 6/6/01, Kenneth Kopelson wrote:
Actually you are only exposed if you have not set up Apache to run
with virtual hosts.  It is not difficult to configure Apache so that
a person can only see the scripts that are in his/her directory, and
is prevented from seeing or modifying the scripts in other peoples
directories.  Also, it is wise to place your DB passwords in a
separate small file, and then include the file in all your scripts.
You can place the password file in a directory that doesn't have any
accessibility from anyone on the web.  Let's say we have a password
file called dbpass.inc, and we place it in a directory called
/var/protected off the root.  Only the webserver is set to have
permission to access this directory.  The password file should look
something like this:

?php
username=username;
password=password;
?

Then in all your scripts include the following line:

include ('/var/protected/dbpass.inc);

Except that all scripts run by Apache run with the same file system access
privileges (namely, the privileges of the account under which Apache is
set to run).  So all scripts run by a given instance of the server have
equivalent access privileges.  If you and I have scripts run by that server,
my scripts can read yours.  I don't see that virtual hosts have much to do
with it.  (Unless you're talking about Apache 2.xx, which will solve this
problem by allowing different virtual hosts to be associated with distinct
user IDs.)


-Ken

At 08:02 PM 6/5/01 -0500, Paul DuBois wrote:
At 10:37 PM +0100 6/5/01, Jorge Oliveira wrote:
Hi again,

You are right, your username and password will have to be on every PHP
script that needs to use database.

However, you don't have to be afraid because nobody can access the source of
your PHP scripts - unless they are a good hacker!

Actually, anyone else on the Web server host that has permission to
install scripts for the Web server can access the source.

I couldn't tell from the original message whether the Web server is
shared with other people or not, but if you don't have your own
server, you're exposed.


I think you should pay a visit to http://www.php.net to understand how PHP
works. Start with the basics and you will see that is reallY VERY simple.

Be cool,


Jorge Oliveira
[EMAIL PROTECTED]


© webfroggie.com - Recursos Online!
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--
Paul DuBois, [EMAIL PROTECTED]

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RE: Need help on mysql/php

2001-06-06 Thread Ian Ford

Name your config file config.inc and if any of the below situations
happen your password and username will not show up in plain text for the
casual browser.
(EXAMPLE:

CONFIG.INC
?
$DBname = 'test';
$DBuser = 'imatest';
$DBpass = 'Whatever';
$DBhost = 'localhost';
?

INDEX.PHP
?
require(config.inc);
$conn = mysql_connect($DBhost,$DBuser,$DBpass);
  mysql_select_db($DBname);
?

END EXAMPLE)
You can place the config.inc any where you want. My preference is in a
includes folder...

Thank you,

Ian Ford
Northwest Link
Web Development

-Original Message-
From: Neil Zanella [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, June 06, 2001 12:09 PM
To: Don Read
Cc: Ed Peddycoart; Mysql@Lists. Mysql. Com; Jorge Oliveira
Subject: RE: Need help on mysql/php



On Tue, 5 Jun 2001, Don Read wrote:

 Better yet, put the file outside the $DOCUMENT_ROOT, in case your
server is
 poorly configured.

 include($DOCUMENT_ROOT/../config.php);

This is a very good idea. One day if the system administrator decides to
back up all the user data and upgrade the web server and forgets to
include support for PHP then all the PHP files become readable as plain
text and casual web surfers could sniff your password. Another scenario
where this could happen is if there are two web servers and your home
directory is mounted on both via NFS or AFS and you may not be aware
that
the other web server does not have PHP support.

If you are serving from /home/httpd/html then store your database access
information including passwords in some directory like
/home/httpd/secret
and set the right ownerships for that directory and files therein. It is
also a good idea to control extraneous access to the database by
firewalling your site.

Neil


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RE: Need help on mysql/php

2001-06-06 Thread Neil Zanella


On Wed, 6 Jun 2001, Ian Ford wrote:

 Name your config file config.inc and if any of the below situations
 happen your password and username will not show up in plain text for the
 casual browser.
 (EXAMPLE:

   CONFIG.INC
   ?
   $DBname = 'test';
   $DBuser = 'imatest';
   $DBpass = 'Whatever';
   $DBhost = 'localhost';
   ?

   INDEX.PHP
   ?
   require(config.inc);
   $conn = mysql_connect($DBhost,$DBuser,$DBpass);
 mysql_select_db($DBname);
   ?

 END EXAMPLE)
 You can place the config.inc any where you want. My preference is in a
 includes folder...

The config.inc file should still be placed outside of the document root
to guard against the security risks I described. If not then there is
nothing preventing the user from entering the full URL to config.inc.

Neil


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RE: Need help on mysql/php

2001-06-05 Thread Jorge Oliveira

Hi,

Please refer to http://www.php.net/manual/en/ref.mysql.php


Jorge Oliveira
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-Mensagem original-
De: Ed Peddycoart [mailto:[EMAIL PROTECTED]]
Enviada: Terça-feira, 5 de Junho de 2001 21:31
Para: [EMAIL PROTECTED]
Assunto: Need help on mysql/php


I recently move my website to FastWebServers.com.  MySQL and PHP is
provided.  I have a control panel which allows me to initialize MySQL for my
use.  The initialization creates a db, named celticblues_com (my domain is
celticblues.com).  So far, I have added a table to my database, and added
the neccessary fields.  Now I am at a total loss at what to do.  I want to
use PHP scripts to pull info from the db and search the db etc.  I have
contacted my support from FWS, but they point me to MySQL.com for Mysql
commands technical support.  Seems to me I would need to know how to set
username/password to access the db from script etc.   The bottom line
question is can someone point me to information on what I need to do to be
able to access(open/close) the db, retrieve/store information, etc. in this
type of environment (i.e. MySQL provide by my host service, not installed by
me)?
Ed


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Re: Need help on mysql/php

2001-06-05 Thread B. van Ouwerkerk

Great support..

Right.. take a look at www.devshed.com they've got a few nice tutorials.. 
if you plan to work a lot with MySQL you might want to buy the book called 
MySQL written by Paul DuBois or fill out the survey and hope you'll get one 
for free ;-)..

Other interesting websites: www.phpbuilder.com www.phpnewbie.com 
www.phpbeginner.com and many others can be found using your favorite 
searchengine.

Bye,

B.

At 13:30 5-6-01 -0700, Ed Peddycoart wrote:
I recently move my website to FastWebServers.com.  MySQL and PHP is
provided.  I have a control panel which allows me to initialize MySQL for my
use.  The initialization creates a db, named celticblues_com (my domain is
celticblues.com).  So far, I have added a table to my database, and added
the neccessary fields.  Now I am at a total loss at what to do.  I want to
use PHP scripts to pull info from the db and search the db etc.  I have
contacted my support from FWS, but they point me to MySQL.com for Mysql
commands technical support.  Seems to me I would need to know how to set
username/password to access the db from script etc.   The bottom line
question is can someone point me to information on what I need to do to be
able to access(open/close) the db, retrieve/store information, etc. in this
type of environment (i.e. MySQL provide by my host service, not installed by
me)?
Ed


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Re: Need help on mysql/php

2001-06-05 Thread Olexandr Vynnychenko

Hello Ed,

Tuesday, June 05, 2001, 11:30:36 PM, you wrote:

EP I recently move my website to FastWebServers.com.  MySQL and PHP is
EP provided.  I have a control panel which allows me to initialize MySQL for my
EP use.  The initialization creates a db, named celticblues_com (my domain is
EP celticblues.com).  So far, I have added a table to my database, and added
EP the neccessary fields.  Now I am at a total loss at what to do.  I want to
EP use PHP scripts to pull info from the db and search the db etc.  I have
EP contacted my support from FWS, but they point me to MySQL.com for Mysql
EP commands technical support.  Seems to me I would need to know how to set
EP username/password to access the db from script etc.   The bottom line
EP question is can someone point me to information on what I need to do to be
EP able to access(open/close) the db, retrieve/store information, etc. in this
EP type of environment (i.e. MySQL provide by my host service, not installed by
EP me)?
EP Ed


EP -
EP Before posting, please check:
EPhttp://www.mysql.com/manual.php   (the manual)
EPhttp://lists.mysql.com/   (the list archive)

EP To request this thread, e-mail [EMAIL PROTECTED]
EP To unsubscribe, e-mail [EMAIL PROTECTED]
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I don't uderstand exactly what you need...
If you don't know how to work with MySQL databases using PHP just
look at PHP Manual (http://www.php.net/docs.php) Chapter L. MySQL
functions (http://www.php.net/manual/en/ref.mysql.php). To
understand it quickly see function mysql_connect.

-- 
Best regards,
 Olexandrmailto:[EMAIL PROTECTED]



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RE: Need help on mysql/php

2001-06-05 Thread Ed Peddycoart

Thanks...this helped...Just had success in connecting to the MySQL server
and dumping the db contents to the screenOne worrisome bit though...My
username and password for connecting to the db on my host is my username and
password for the web account.  If I want to create dynamic webpages by
pulling data from my db, won't I have to put this information (usersname and
pw) in the php file and leave it on the server?  Sounds pretty darn scary to
me...maybe I am confused.
Ed

-Original Message-
From: Jorge Oliveira [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, June 05, 2001 12:47 PM
To: Mysql@Lists. Mysql. Com
Subject: RE: Need help on mysql/php


Hi,

Please refer to http://www.php.net/manual/en/ref.mysql.php


Jorge Oliveira
[EMAIL PROTECTED] mailto:[EMAIL PROTECTED]


© webfroggie.com - Recursos Online!
web: http://www.webfroggie.com
wap: http://www.webfroggie.com




-Mensagem original-
De: Ed Peddycoart [mailto:[EMAIL PROTECTED]]
Enviada: Terça-feira, 5 de Junho de 2001 21:31
Para: [EMAIL PROTECTED]
Assunto: Need help on mysql/php


I recently move my website to FastWebServers.com.  MySQL and PHP is
provided.  I have a control panel which allows me to initialize MySQL for my
use.  The initialization creates a db, named celticblues_com (my domain is
celticblues.com).  So far, I have added a table to my database, and added
the neccessary fields.  Now I am at a total loss at what to do.  I want to
use PHP scripts to pull info from the db and search the db etc.  I have
contacted my support from FWS, but they point me to MySQL.com for Mysql
commands technical support.  Seems to me I would need to know how to set
username/password to access the db from script etc.   The bottom line
question is can someone point me to information on what I need to do to be
able to access(open/close) the db, retrieve/store information, etc. in this
type of environment (i.e. MySQL provide by my host service, not installed by
me)?
Ed


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RE: Need help on mysql/php

2001-06-05 Thread Jorge Oliveira

Hi again,

You are right, your username and password will have to be on every PHP
script that needs to use database.

However, you don't have to be afraid because nobody can access the source of
your PHP scripts - unless they are a good hacker!

I think you should pay a visit to http://www.php.net to understand how PHP
works. Start with the basics and you will see that is reallY VERY simple.

Be cool,


Jorge Oliveira
[EMAIL PROTECTED]


© webfroggie.com - Recursos Online!
web: http://www.webfroggie.com
wap: http://www.webfroggie.com





-Mensagem original-
De: Ed Peddycoart [mailto:[EMAIL PROTECTED]]
Enviada: Quarta-feira, 6 de Junho de 2001 0:29
Para: Jorge Oliveira; Mysql@Lists. Mysql. Com
Assunto: RE: Need help on mysql/php


Thanks...this helped...Just had success in connecting to the MySQL server
and dumping the db contents to the screenOne worrisome bit though...My
username and password for connecting to the db on my host is my username and
password for the web account.  If I want to create dynamic webpages by
pulling data from my db, won't I have to put this information (usersname and
pw) in the php file and leave it on the server?  Sounds pretty darn scary to
me...maybe I am confused.
Ed

-Original Message-
From: Jorge Oliveira [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, June 05, 2001 12:47 PM
To: Mysql@Lists. Mysql. Com
Subject: RE: Need help on mysql/php


Hi,

Please refer to http://www.php.net/manual/en/ref.mysql.php


Jorge Oliveira
[EMAIL PROTECTED] mailto:[EMAIL PROTECTED]


© webfroggie.com - Recursos Online!
web: http://www.webfroggie.com
wap: http://www.webfroggie.com




-Mensagem original-
De: Ed Peddycoart [mailto:[EMAIL PROTECTED]]
Enviada: Terça-feira, 5 de Junho de 2001 21:31
Para: [EMAIL PROTECTED]
Assunto: Need help on mysql/php


I recently move my website to FastWebServers.com.  MySQL and PHP is
provided.  I have a control panel which allows me to initialize MySQL for my
use.  The initialization creates a db, named celticblues_com (my domain is
celticblues.com).  So far, I have added a table to my database, and added
the neccessary fields.  Now I am at a total loss at what to do.  I want to
use PHP scripts to pull info from the db and search the db etc.  I have
contacted my support from FWS, but they point me to MySQL.com for Mysql
commands technical support.  Seems to me I would need to know how to set
username/password to access the db from script etc.   The bottom line
question is can someone point me to information on what I need to do to be
able to access(open/close) the db, retrieve/store information, etc. in this
type of environment (i.e. MySQL provide by my host service, not installed by
me)?
Ed


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RE: Need help on mysql/php

2001-06-05 Thread Jorge Oliveira

Hi,

You are making a huge confusion...

PHP is a server side scripting language that is used mostly for generate
dynamic html pages.
For example, let's say you have a file named test.php like this:


?
$username=Me;
$password=mypass;
...
// slq queries here
...

echo htmlbodyThis is a testbody/html;

?


If you upload this file to your server and browse to it you will get this
page:

-
htmlbodyThis is a test/body/html
-

The variables $username and $password are not displayed...

Again, I recommend you to start reading on PHP and you will find it very
easy to understand.




Jorge Oliveira
[EMAIL PROTECTED]


© webfroggie.com - Recursos Online!
web: http://www.webfroggie.com
wap: http://www.webfroggie.com





-Mensagem original-
De: Ed Peddycoart [mailto:[EMAIL PROTECTED]]
Enviada: Quarta-feira, 6 de Junho de 2001 0:49
Para: Jorge Oliveira
Assunto: RE: Need help on mysql/php


I assume that you mean that they cannot access the scripts if the extension
of the file is .php3, but if I mix PHP within an HTML file, then all
security bets are off?
Ed

-Original Message-
From: Jorge Oliveira [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, June 05, 2001 2:38 PM
To: Ed Peddycoart
Cc: Mysql@Lists. Mysql. Com
Subject: RE: Need help on mysql/php


Hi again,

You are right, your username and password will have to be on every PHP
script that needs to use database.

However, you don't have to be afraid because nobody can access the source of
your PHP scripts - unless they are a good hacker!

I think you should pay a visit to http://www.php.net to understand how PHP
works. Start with the basics and you will see that is reallY VERY simple.

Be cool,


Jorge Oliveira
[EMAIL PROTECTED]


© webfroggie.com - Recursos Online!
web: http://www.webfroggie.com
wap: http://www.webfroggie.com





-Mensagem original-
De: Ed Peddycoart [mailto:[EMAIL PROTECTED]]
Enviada: Quarta-feira, 6 de Junho de 2001 0:29
Para: Jorge Oliveira; Mysql@Lists. Mysql. Com
Assunto: RE: Need help on mysql/php


Thanks...this helped...Just had success in connecting to the MySQL server
and dumping the db contents to the screenOne worrisome bit though...My
username and password for connecting to the db on my host is my username and
password for the web account.  If I want to create dynamic webpages by
pulling data from my db, won't I have to put this information (usersname and
pw) in the php file and leave it on the server?  Sounds pretty darn scary to
me...maybe I am confused.
Ed

-Original Message-
From: Jorge Oliveira [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, June 05, 2001 12:47 PM
To: Mysql@Lists. Mysql. Com
Subject: RE: Need help on mysql/php


Hi,

Please refer to http://www.php.net/manual/en/ref.mysql.php


Jorge Oliveira
[EMAIL PROTECTED] mailto:[EMAIL PROTECTED]


© webfroggie.com - Recursos Online!
web: http://www.webfroggie.com
wap: http://www.webfroggie.com




-Mensagem original-
De: Ed Peddycoart [mailto:[EMAIL PROTECTED]]
Enviada: Terça-feira, 5 de Junho de 2001 21:31
Para: [EMAIL PROTECTED]
Assunto: Need help on mysql/php


I recently move my website to FastWebServers.com.  MySQL and PHP is
provided.  I have a control panel which allows me to initialize MySQL for my
use.  The initialization creates a db, named celticblues_com (my domain is
celticblues.com).  So far, I have added a table to my database, and added
the neccessary fields.  Now I am at a total loss at what to do.  I want to
use PHP scripts to pull info from the db and search the db etc.  I have
contacted my support from FWS, but they point me to MySQL.com for Mysql
commands technical support.  Seems to me I would need to know how to set
username/password to access the db from script etc.   The bottom line
question is can someone point me to information on what I need to do to be
able to access(open/close) the db, retrieve/store information, etc. in this
type of environment (i.e. MySQL provide by my host service, not installed by
me)?
Ed


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RE: Need help on mysql/php

2001-06-05 Thread Don Read


On 05-Jun-01 Ed Peddycoart wrote:
 Thanks...this helped...Just had success in connecting to the MySQL server
 and dumping the db contents to the screenOne worrisome bit though...My
 username and password for connecting to the db on my host is my username and
 password for the web account.  If I want to create dynamic webpages by
 pulling data from my db, won't I have to put this information (usersname and
 pw) in the php file and leave it on the server?  Sounds pretty darn scary to
 me...maybe I am confused.
 Ed
 

No, you put it in a php file with nothing but defines / data,
say 'config.php' :

php

// Database   ***

define('DBHOST', 'localhost');
define('DBUSER', 'abc');
define('DBPASS', 'abc123');

---

and include('config.php') in your scripts.

If the webserver is configured properly, access to this file will evaluate as
php code; so nothing will get output.

Better yet, put the file outside the $DOCUMENT_ROOT, in case your server is
poorly configured.

include($DOCUMENT_ROOT/../config.php);

Regards,
-- 
Don Read   [EMAIL PROTECTED]
-- It's always darkest before the dawn. So if you are going to 
   steal the neighbor's newspaper, that's the time to do it.

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RE: Need help on mysql/php

2001-06-05 Thread Paul DuBois

At 10:37 PM +0100 6/5/01, Jorge Oliveira wrote:
Hi again,

You are right, your username and password will have to be on every PHP
script that needs to use database.

However, you don't have to be afraid because nobody can access the source of
your PHP scripts - unless they are a good hacker!

Actually, anyone else on the Web server host that has permission to
install scripts for the Web server can access the source.

I couldn't tell from the original message whether the Web server is
shared with other people or not, but if you don't have your own
server, you're exposed.


I think you should pay a visit to http://www.php.net to understand how PHP
works. Start with the basics and you will see that is reallY VERY simple.

Be cool,


Jorge Oliveira
[EMAIL PROTECTED]


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RE: Need help on mysql/php

2001-06-05 Thread Paul DuBois

At 7:42 PM -0500 6/5/01, Don Read wrote:
On 05-Jun-01 Ed Peddycoart wrote:
  Thanks...this helped...Just had success in connecting to the MySQL server
  and dumping the db contents to the screenOne worrisome bit though...My
  username and password for connecting to the db on my host is my username and
  password for the web account.  If I want to create dynamic webpages by
  pulling data from my db, won't I have to put this information (usersname and
  pw) in the php file and leave it on the server?  Sounds pretty darn scary to
  me...maybe I am confused.
  Ed


No, you put it in a php file with nothing but defines / data,
say 'config.php' :

php

// Database   ***

define('DBHOST', 'localhost');
define('DBUSER', 'abc');
define('DBPASS', 'abc123');

---

and include('config.php') in your scripts.

If the webserver is configured properly, access to this file will evaluate as
php code; so nothing will get output.

Better yet, put the file outside the $DOCUMENT_ROOT, in case your server is
poorly configured.

include($DOCUMENT_ROOT/../config.php);

However, if you and I both have virtual domains hosted by the same server,
I can write a script that will read your config.php file.

And then, for my next trick, I'll connect to your database and read
(or destroy) all your data. :-)


Regards,
--
Don Read   [EMAIL PROTECTED]
-- It's always darkest before the dawn. So if you are going to
steal the neighbor's newspaper, that's the time to do it.


-- 
Paul DuBois, [EMAIL PROTECTED]

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Re: need help

2001-05-17 Thread Peter L. Berghold

On Thu, May 17, 2001 at 06:36:23AM -0700, mansoor spake thusly:
*] i m new to mysql, how i can convert a string 28-MAR-2001 to date
*] 

In what language? 

-- 
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Peter L. Berghold[EMAIL PROTECTED]
Linux renders ships http://www.berghold.net
 NT renders ships useless   

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RE: need help on replication

2001-05-10 Thread David Shields

Joe:

AFAIR, as an ex NT4 sysadmin, system error 5 is access denied - you have a 
permissions problem somewhere.
On NT4 these can be a swine to solve. Check out your NT system error logs 
as a starting point.

HTH.

David

 By the way, I once first tried to set up the slave on a NT machine. But for
 unknown (means I donot know) reasons, I can not even net start mysql on
 that machine now. The error message is system error 5. Did you meet this
 problem? If so, how did you solve it?
 thanks alot,
 Joe




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Re: need help on replication

2001-05-09 Thread Jeremy Zawodny

On Wed, May 09, 2001 at 10:29:42AM -0600, Joseph Chow wrote:
 Hi, there,
 
 This is my first try on this mailing list.  I am a new user of mysql
 and need some help about replication on mysql 3.23.36.  I had
 followed the manual to set up master/slave server.  At the
 beginning, they are connected perfectly.  All the modifications
 (i.e. create databases, insert values ..) on the master server were
 mirrored by the slave server.  However, after I dumped some
 databases from the master to the slave, the bad things happened.
 The connection between the master and the slave was down.  I failed
 to reconnect them by shutting down and restarting the master and the
 slave a couple of times.

You'll need to look in the mysql error log on the slave and see what
it says. That should give us/you a good idea what may have happened.

Jeremy
-- 
Jeremy D. Zawodny, [EMAIL PROTECTED]
Technical Yahoo - Yahoo Finance
Desk: (408) 349-7878Fax: (408) 349-5454Cell: (408) 439-9951

MySQL 3.23.29: up 126 days, processed 780,401,285 queries (71/sec. avg)

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RE: need help on replication

2001-05-09 Thread Joseph Chow

Hi, Jeremy,

It is very nice to talk to you.  Thanks for your information.  It's working
now, but I did nothing but going over the procedure again.  I may make some
mistakes during my operations.  But it is really a good idea to keep an eye
on the err log for solutions.

By the way, I once first tried to set up the slave on a NT machine.  But for
unknown (means I donot know) reasons, I can not even net start mysql on
that machine now.  The error message is system error 5.  Did you meet this
problem?  If so, how did you solve it?

thanks alot,

Joe


-Original Message-
From: Jeremy Zawodny [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, May 09, 2001 10:33 AM
To: Joseph Chow
Cc: [EMAIL PROTECTED]
Subject: Re: need help on replication


On Wed, May 09, 2001 at 10:29:42AM -0600, Joseph Chow wrote:
 Hi, there,

 This is my first try on this mailing list.  I am a new user of mysql
 and need some help about replication on mysql 3.23.36.  I had
 followed the manual to set up master/slave server.  At the
 beginning, they are connected perfectly.  All the modifications
 (i.e. create databases, insert values ..) on the master server were
 mirrored by the slave server.  However, after I dumped some
 databases from the master to the slave, the bad things happened.
 The connection between the master and the slave was down.  I failed
 to reconnect them by shutting down and restarting the master and the
 slave a couple of times.

You'll need to look in the mysql error log on the slave and see what
it says. That should give us/you a good idea what may have happened.

Jeremy
--
Jeremy D. Zawodny, [EMAIL PROTECTED]
Technical Yahoo - Yahoo Finance
Desk: (408) 349-7878Fax: (408) 349-5454Cell: (408) 439-9951

MySQL 3.23.29: up 126 days, processed 780,401,285 queries (71/sec. avg)


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Re: need help on replication

2001-05-09 Thread Jeremy Zawodny

On Wed, May 09, 2001 at 11:18:14AM -0600, Joseph Chow wrote:
 Hi, Jeremy,
 
 It is very nice to talk to you.  Thanks for your information.  It's
 working now, but I did nothing but going over the procedure again.
 I may make some mistakes during my operations.  But it is really a
 good idea to keep an eye on the err log for solutions.

Indeed.

 By the way, I once first tried to set up the slave on a NT machine.
 But for unknown (means I donot know) reasons, I can not even net
 start mysql on that machine now.  The error message is system
 error 5.  Did you meet this problem?  If so, how did you solve it?

I can't help you much there. I really only use Windows when there are
not other options available to me, so I haven't seen this problem
before. Sorry.

Jeremy
-- 
Jeremy D. Zawodny, [EMAIL PROTECTED]
Technical Yahoo - Yahoo Finance
Desk: (408) 349-7878Fax: (408) 349-5454Cell: (408) 439-9951

MySQL 3.23.29: up 126 days, processed 780,513,289 queries (71/sec. avg)

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Re: Need help with 23.36

2001-04-24 Thread New Style MySQL Personnel



mysql use lum
Reading table information for completion of table and column names
You can turn off this feature to get a quicker startup with -A

Didn't find any fields in table 'users'
Database changed
mysql select * from users;
ERROR 1017: Can't find file: './lum/users.frm' (errno: 13)

  Please anyone. I really need some ideas.
  I copied my database files made with 23.29 to 23.26 and now I get this. I
  chowned mysql.mysql and chmoded 660.
  The location of the databases is good because I have some other databases
  created with 36 and they work fine. I copied ALL the database's files to
  /var/lib/mysql where the others are and I get this error. Any idea?
 
 Error code 13 means permission denied. How come your database is named 'lumina' and 
the directory it resides in (or at least the dir that mysql tries to find the tables 
in) is ./lum/ ?  Shouldn't it be looking under lumina?
 Check that you don't have your database directories messed up under ~mysql/var/


The files are in the right directory with the right permissions and still
I get the errors from above.


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