Re: Optimizing InnoDB tables

2014-06-25 Thread Andre Matos
Have a look at this:

https://rtcamp.com/tutorials/mysql/enable-innodb-file-per-table/

--
Andre Matos
andrema...@mineirinho.org


On Jun 25, 2014, at 2:22 AM, Antonio Fernández Pérez 
antoniofernan...@fabergames.com wrote:

 ​Hi again,
 
 I have enabled innodb_file_per_table (Its value is on).
 I don't have clear what I should to do ...
 
 Thanks in advance.
 
 Regards,
 
 Antonio. ​


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Collate issue

2011-06-01 Thread Andre Matos
Hello,

I have a file that contains some SQL statements including CREATE TABLE, INSERT, 
UPDATE and specially CREATE VIEW. This file is used to apply changes into the 
database.

All databases  tables use the 'DEFAULT CHARSET=latin1 
COLLATE=latin1_General_CS', so when creating views, the fields that exists in 
the table I am querying will have the same collation. However, new fields 
created by the SELECT do not use the collation I want: 'latin1_General_CS'.

The first line of this file is: SET NAMES latin1 COLLATE latin1_general_cs;

So, when running - mysql -u myuser -p testdb  settings.sql

The views are created using the 'latin1_General_CS'.

However, when I try to do the same in the MySQL installed on our servers 
(5.0.51a-3ubuntu5.5 and 5.0.32-Debian_7etch1), the views do not get created as 
they were on my local computer. Some fields are created using 
'latin1_swedish_ci',  some as 'latin1_bin', and others without any.

Is there any known issue with previous versions of the MySQL 5.0.x regarding 
this?

Is there a way I can do this so all applicable fields on my view uses the 
collation I want?

Thanks for any help!

Andre

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Using RAND to get a unique ID that has not been used yet

2010-05-28 Thread Andre Matos
Hi All,

I have a table that uses auto_increment to generate the Id automatically 
working fine. However, I need to create a new table where the Id must be a 
number generated randomly, so I cannot use the auto_increment. 

MySQL has a function RAND. So I could use something like this:

SELECT FLOOR(RAND() * COUNT(*)) AS RandId FROM mytable

But, let's suppose that the RandId is a number that was already used in the 
table. Then I need to run the SELECT again and again until I find a number that 
hasn't been used.

Is there a way to have this SELECT to loop until it finds a number that hasn't 
been used?

The RandId must be only numbers and length of 6 (from 1 to 99). No other 
character is allowed.

Thanks for any help!

Andre

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Re: Using RAND to get a unique ID that has not been used yet

2010-05-28 Thread Andre Matos
It seems to be a good approach, although I was trying to get this by querying 
the table without creating another table to keep the Ids.

Thanks,

Andre

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On 2010-05-28, at 12:15 PM, Steven Staples wrote:

 If you wanted to use/go that route, then why not select a random limit 1
 from that table, and then delete that row?
 
 SELECT `column` FROM `table` ORDER BY RAND() LIMIT 1;
 
 
 On a side note, I would use the auto-inc field still, and store this number
 in another field.
 
 Steven Staples
 
 
 
 -Original Message-
 From: Jim Lyons [mailto:jlyons4...@gmail.com]
 Sent: May 28, 2010 11:49 AM
 To: Andre Matos
 Cc: mysql@lists.mysql.com
 Subject: Re: Using RAND to get a unique ID that has not been used yet
 
 If your specs are that specific (IDs must be between 1 and 99)
 then you could create a 99-row table with one integer column and
 prefill it with the numbers 1 to 99 in random order.
 
 Then you could write a function that would select and return the first
 number in the table, then delete that record so you would not reuse
 it.
 
 Once you've done the work of sorting 99 numbers in random order
 (which can be done anywhich way) it's easy and you don't have to loop
 an indeterminant number of times.  You would be looping an increasing
 number of times as you begin to fill up the table.
 
 Jim
 
 On Fri, May 28, 2010 at 10:38 AM, Andre Matos andrema...@mineirinho.org
 wrote:
 Hi All,
 
 I have a table that uses auto_increment to generate the Id automatically
 working fine. However, I need to create a new table where the Id must be a
 number generated randomly, so I cannot use the auto_increment.
 
 MySQL has a function RAND. So I could use something like this:
 
 SELECT FLOOR(RAND() * COUNT(*)) AS RandId FROM mytable
 
 But, let's suppose that the RandId is a number that was already used in
 the table. Then I need to run the SELECT again and again until I find a
 number that hasn't been used.
 
 Is there a way to have this SELECT to loop until it finds a number that
 hasn't been used?
 
 The RandId must be only numbers and length of 6 (from 1 to 99). No
 other character is allowed.
 
 Thanks for any help!
 
 Andre
 
 --
 Andre Matos
 andrema...@mineirinho.org
 
 
 
 
 
 --
 MySQL General Mailing List
 For list archives: http://lists.mysql.com/mysql
 To unsubscribe:
  http://lists.mysql.com/mysql?unsub=jlyons4...@gmail.com
 
 
 
 
 
 --
 Jim Lyons
 Web developer / Database administrator
 http://www.weblyons.com
 
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 MySQL General Mailing List
 For list archives: http://lists.mysql.com/mysql
 To unsubscribe:http://lists.mysql.com/mysql?unsub=sstap...@mnsi.net
 
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 02:25:00
 
 
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Re: Using RAND to get a unique ID that has not been used yet

2010-05-28 Thread Andre Matos
When I mentioned having everything in the Query, I was thinking about this. I 
don't want to have a loop repeating the query until I get a unique Id. This is 
ridicules and imagine how many queries I might end up running. No way!

Thanks for the warning and feedback!

Andre

--
Andre Matos
andrema...@mineirinho.org




On 2010-05-28, at 1:51 PM, Jerry Schwartz wrote:

 
 -Original Message-
 From: Andre Matos [mailto:andrema...@mineirinho.org]
 Sent: Friday, May 28, 2010 1:44 PM
 To: Steven Staples
 Cc: mysql@lists.mysql.com
 Subject: Re: Using RAND to get a unique ID that has not been used yet
 
 It seems to be a good approach, although I was trying to get this by querying
 the table without creating another table to keep the Ids.
 
 [JS] That would be a VERY bad idea. My predecessor designed our system that 
 way: it would generate a random key, check to see if that key were in use, 
 and 
 either use it or try again.
 
 As you would expect, the whole process get slower and slower as we ran out 
 of unique keys. Eventually the whole application became unusable.
 
 Regards,
 
 Jerry Schwartz
 Global Information Incorporated
 195 Farmington Ave.
 Farmington, CT 06032
 
 860.674.8796 / FAX: 860.674.8341
 
 www.the-infoshop.com
 
 
 
 
 Thanks,
 
 Andre
 
 --
 Andre Matos
 andrema...@mineirinho.org
 
 
 
 
 On 2010-05-28, at 12:15 PM, Steven Staples wrote:
 
 If you wanted to use/go that route, then why not select a random limit 1
 from that table, and then delete that row?
 
 SELECT `column` FROM `table` ORDER BY RAND() LIMIT 1;
 
 
 On a side note, I would use the auto-inc field still, and store this number
 in another field.
 
 Steven Staples
 
 
 
 -Original Message-
 From: Jim Lyons [mailto:jlyons4...@gmail.com]
 Sent: May 28, 2010 11:49 AM
 To: Andre Matos
 Cc: mysql@lists.mysql.com
 Subject: Re: Using RAND to get a unique ID that has not been used yet
 
 If your specs are that specific (IDs must be between 1 and 99)
 then you could create a 99-row table with one integer column and
 prefill it with the numbers 1 to 99 in random order.
 
 Then you could write a function that would select and return the first
 number in the table, then delete that record so you would not reuse
 it.
 
 Once you've done the work of sorting 99 numbers in random order
 (which can be done anywhich way) it's easy and you don't have to loop
 an indeterminant number of times.  You would be looping an increasing
 number of times as you begin to fill up the table.
 
 Jim
 
 On Fri, May 28, 2010 at 10:38 AM, Andre Matos andrema...@mineirinho.org
 wrote:
 Hi All,
 
 I have a table that uses auto_increment to generate the Id automatically
 working fine. However, I need to create a new table where the Id must be a
 number generated randomly, so I cannot use the auto_increment.
 
 MySQL has a function RAND. So I could use something like this:
 
 SELECT FLOOR(RAND() * COUNT(*)) AS RandId FROM mytable
 
 But, let's suppose that the RandId is a number that was already used in
 the table. Then I need to run the SELECT again and again until I find a
 number that hasn't been used.
 
 Is there a way to have this SELECT to loop until it finds a number that
 hasn't been used?
 
 The RandId must be only numbers and length of 6 (from 1 to 99). No
 other character is allowed.
 
 Thanks for any help!
 
 Andre
 
 --
 Andre Matos
 andrema...@mineirinho.org
 
 
 
 
 
 --
 MySQL General Mailing List
 For list archives: http://lists.mysql.com/mysql
 To unsubscribe:
 http://lists.mysql.com/mysql?unsub=jlyons4...@gmail.com
 
 
 
 
 
 --
 Jim Lyons
 Web developer / Database administrator
 http://www.weblyons.com
 
 --
 MySQL General Mailing List
 For list archives: http://lists.mysql.com/mysql
 To unsubscribe:http://lists.mysql.com/mysql?unsub=sstap...@mnsi.net
 
 No virus found in this incoming message.
 Checked by AVG - www.avg.com
 Version: 9.0.819 / Virus Database: 271.1.1/2895 - Release Date: 05/28/10
 02:25:00
 
 
 --
 MySQL General Mailing List
 For list archives: http://lists.mysql.com/mysql
 To unsubscribe:
 http://lists.mysql.com/mysql?unsub=andrema...@mineirinho.org
 
 
 
 --
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 To unsubscribe:
 http://lists.mysql.com/mysql?unsub=andrema...@mineirinho.org
 


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SELECT through many databases

2008-11-21 Thread Andre Matos

Hello,

Let's suppose I have 5 database: db1, db2, db3, db4, and db5. They all  
have the same structure but different data.


I would like perform this select

SELECT TaskDoneOn, TaskDoneBy
FROM {database}
WHERE TaskDoneOn IS NOT NULL

and collect the data from all 5 database. However, I would like to  
avoid doing something like this:


SELECT TaskDoneOn, TaskDoneBy
FROM db1
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db2
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db3
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db4
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db5
WHERE TaskDoneOn IS NOT NULL


Today I have 5, but tomorrow I can have 50 and I don't want to forget  
any database.


Thanks for any help.

Andre





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Re: SELECT through many databases

2008-11-21 Thread Andre Matos
I was trying to avoid both since the SELECT statement is not fixed.  
Time to time, users want different information.


Thanks,

Andre

On 21-Nov-08, at 12:59 PM, Peter Brawley wrote:


Andre Matos wrote:

Today I have 5, but tomorrow I can have 50 and I don't want to  
forget any database.


Do it in an app language or as a PREPARED statement in an sproc.

PB

---

Andre Matos wrote:

Hello,

Let's suppose I have 5 database: db1, db2, db3, db4, and db5. They  
all have the same structure but different data.


I would like perform this select

SELECT TaskDoneOn, TaskDoneBy
FROM {database}
WHERE TaskDoneOn IS NOT NULL

and collect the data from all 5 database. However, I would like to  
avoid doing something like this:


SELECT TaskDoneOn, TaskDoneBy
FROM db1
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db2
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db3
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db4
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db5
WHERE TaskDoneOn IS NOT NULL


Today I have 5, but tomorrow I can have 50 and I don't want to  
forget any database.


Thanks for any help.

Andre








Internal Virus Database is out of date.
Checked by AVG - http://www.avg.com Version: 8.0.175 / Virus  
Database: 270.9.0/1777 - Release Date: 11/9/2008 9:53 AM





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Re: SELECT through many databases

2008-11-21 Thread Andre Matos
Sounds interesting, but does the MERGER support complex SELECT  
statements and LEFT JOIN?


Andre


On 21-Nov-08, at 1:45 PM, Brent Baisley wrote:

On Fri, Nov 21, 2008 at 12:44 PM, Andre Matos [EMAIL PROTECTED] 
 wrote:

Hello,

Let's suppose I have 5 database: db1, db2, db3, db4, and db5. They  
all have

the same structure but different data.

I would like perform this select

SELECT TaskDoneOn, TaskDoneBy
FROM {database}
WHERE TaskDoneOn IS NOT NULL

and collect the data from all 5 database. However, I would like to  
avoid

doing something like this:

SELECT TaskDoneOn, TaskDoneBy
FROM db1
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db2
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db3
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db4
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db5
WHERE TaskDoneOn IS NOT NULL


Today I have 5, but tomorrow I can have 50 and I don't want to  
forget any

database.

Thanks for any help.

Andre


Create a MERGE table that is all those tables combined. Then you just
need to do 1 select as if it was one table. Just be sure to update the
MERGE table description when ever you add a table.

Brent Baisley


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Re: SELECT through many databases

2008-11-21 Thread Andre Matos

Thanks everyone for the help.

I was trying to use any API (e.g. PHP, Java, etc). I just gave up  
because unfortunately the time fly and the user needs this asap. I am  
doing via script.


Thanks!

Andre


On 21-Nov-08, at 2:34 PM, Jerry Schwartz wrote:

Many MySQL APIs (such as PHP) allow you to treat the result  
returned from a
SHOW statement as you would a result set from a SELECT; see Chapter  
22, APIs
and Libraries, or your API documentation for more information. In  
addition,

you can work in SQL with results from queries on tables in the
INFORMATION_SCHEMA database, which you cannot easily do with results  
from

SHOW statements. See Chapter 20, The INFORMATION_SCHEMA Database.

You should be able to refresh your MERGE table using a programming
language. Get a list of the databases, then construct a CREATE TABLE  
or what

have you.


-Original Message-
From: Andre Matos [mailto:[EMAIL PROTECTED]
Sent: Friday, November 21, 2008 2:11 PM
To: [EMAIL PROTECTED]
Cc: mysql@lists.mysql.com
Subject: Re: SELECT through many databases

I was trying to avoid both since the SELECT statement is not fixed.
Time to time, users want different information.

Thanks,

Andre

On 21-Nov-08, at 12:59 PM, Peter Brawley wrote:


Andre Matos wrote:


Today I have 5, but tomorrow I can have 50 and I don't want to

forget any database.

Do it in an app language or as a PREPARED statement in an sproc.

PB

---

Andre Matos wrote:

Hello,

Let's suppose I have 5 database: db1, db2, db3, db4, and db5. They
all have the same structure but different data.

I would like perform this select

SELECT TaskDoneOn, TaskDoneBy
FROM {database}
WHERE TaskDoneOn IS NOT NULL

and collect the data from all 5 database. However, I would like to
avoid doing something like this:

SELECT TaskDoneOn, TaskDoneBy
FROM db1
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db2
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db3
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db4
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db5
WHERE TaskDoneOn IS NOT NULL


Today I have 5, but tomorrow I can have 50 and I don't want to
forget any database.

Thanks for any help.

Andre





-

---



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Checked by AVG - http://www.avg.com Version: 8.0.175 / Virus
Database: 270.9.0/1777 - Release Date: 11/9/2008 9:53 AM




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Re: SELECT through many databases

2008-11-21 Thread Andre Matos
The reason for having many databases with the same structure but  
with different data is because for regulatory and compliance  
requirements. Each database belongs to a separate company: company  
specific database. The applications (some written in PHP4 and others  
in J2EE) are unique and they can access one database each time.  
Connect to one database and then disconnect to connect to a different  
one.


The issue is when I need to collect some data for statistics purpose.  
Unfortunately, I cannot have an official application to go through all  
database or even use the MERGE table as suggested here in the list. I  
am not allowed to. That's why I was thinking to use only a SELECT  
statement to do the job as I have been doing.


Thanks,

Andre




On 21-Nov-08, at 3:16 PM, Olexandr Melnyk wrote:


Hello Andre,

I would recommend you to rethink your criteria (if there's any) for
splitting data into multiple tables.

Because now. the more tables you add, the more of a performance  
problem it

may cause.

--
Sincerely yours,
Olexandr Melnyk
http://omelnyk.net/


On Fri, Nov 21, 2008 at 9:58 PM, Andre Matos [EMAIL PROTECTED] 
wrote:



Thanks everyone for the help.

I was trying to use any API (e.g. PHP, Java, etc). I just gave up  
because
unfortunately the time fly and the user needs this asap. I am doing  
via

script.

Thanks!

Andre



On 21-Nov-08, at 2:34 PM, Jerry Schwartz wrote:

Many MySQL APIs (such as PHP) allow you to treat the result  
returned from

a
SHOW statement as you would a result set from a SELECT; see  
Chapter 22,

APIs
and Libraries, or your API documentation for more information. In
addition,
you can work in SQL with results from queries on tables in the
INFORMATION_SCHEMA database, which you cannot easily do with  
results from

SHOW statements. See Chapter 20, The INFORMATION_SCHEMA Database.

You should be able to refresh your MERGE table using a programming
language. Get a list of the databases, then construct a CREATE  
TABLE or

what
have you.

-Original Message-

From: Andre Matos [mailto:[EMAIL PROTECTED]
Sent: Friday, November 21, 2008 2:11 PM
To: [EMAIL PROTECTED]
Cc: mysql@lists.mysql.com
Subject: Re: SELECT through many databases

I was trying to avoid both since the SELECT statement is not fixed.
Time to time, users want different information.

Thanks,

Andre

On 21-Nov-08, at 12:59 PM, Peter Brawley wrote:

Andre Matos wrote:


Today I have 5, but tomorrow I can have 50 and I don't want to



forget any database.

Do it in an app language or as a PREPARED statement in an sproc.

PB

---

Andre Matos wrote:


Hello,

Let's suppose I have 5 database: db1, db2, db3, db4, and db5.  
They

all have the same structure but different data.

I would like perform this select

SELECT TaskDoneOn, TaskDoneBy
FROM {database}
WHERE TaskDoneOn IS NOT NULL

and collect the data from all 5 database. However, I would like  
to

avoid doing something like this:

SELECT TaskDoneOn, TaskDoneBy
FROM db1
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db2
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db3
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db4
WHERE TaskDoneOn IS NOT NULL
UNION
SELECT TaskDoneOn, TaskDoneBy
FROM db5
WHERE TaskDoneOn IS NOT NULL


Today I have 5, but tomorrow I can have 50 and I don't want to
forget any database.

Thanks for any help.

Andre





-


---






Internal Virus Database is out of date.
Checked by AVG - http://www.avg.com Version: 8.0.175 / Virus
Database: 270.9.0/1777 - Release Date: 11/9/2008 9:53 AM




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Re: Deployment of Database in a DEB package.

2008-10-02 Thread Andre Matos
Just be aware about the security. I use shell or perl scripts to make  
automatic dumps (backups) or updates/changes in the database.  
Unfortunately, because they are automatic scripts, I need to add the  
username and password inside the scripts and if someone else have  
access to these scripts (e.g., read access), he/she will see this  
information.


Andre


On 2-Oct-08, at 11:57 AM, Heston James - Cold Beans wrote:


Dave,

This looks like a perfect solution. We can indeed use a shell script  
for the
task in hand and knowing that we an action the .sql script so simply  
from

the command line like that makes life very simple indeed :-)

I can't see this will cause too many challenges.

Thanks Dave, I appreciate it a great deal.

Heston

-Original Message-
From: Ellison, David [mailto:[EMAIL PROTECTED]
Sent: 02 October 2008 07:24
To: mysql@lists.mysql.com
Subject: RE: Deployment of Database in a DEB package.

I know nothing of DEB packages. However, when we need to change /  
make a
database etc on automatic scripts. We would write the script and  
save it
to a .sql file on console. We would then create a shell script that  
had

something like:

mysql -u username -p etc  yourinsertsql.sql

Essentially the username would have the ability to create tables/ 
db's if

the DB does not exist already, so make sure the user exists first.

If you wanted to remove the DB afterwards, although if a DEB can do  
it,

ask first if you want to remove the DB. Have another .sql script with
essentially dropping the database. Then same again a shell that:

mysql -u username -p etc  yourremovesql.sql

This is of course assuming you can refer to a shell script in a DEB
package. But from what I have seen when using them, I would guess they
are used.

Hope this helped.

Dave

-Original Message-
From: Heston James - Cold Beans [mailto:[EMAIL PROTECTED]
Sent: 01 October 2008 15:22
To: mysql@lists.mysql.com
Subject: Deployment of Database in a DEB package.

Afternoon All,



I'm hoping you'll have some recommendations for me on this little
challenge.
I have an application which we're preparing to deploy in a DEB package
using APT on Debian based systems, although I would imagine this very
same rule/process applies to other packaging methods.



On the back end of my application we have a MySQL Database which needs
to be created as part of the deployment process, which is automated  
in a

script, usually SHELL or Perl, something like that.



How would you deploy the database using an automated script? Would you
have a SQL script which you action through the console to create the
database?
What's the simplest way to action a SQL script to run on the local
server?
Do we need to keep in mind what permissions/users are assigned to the
database?



In addition to this create script, we'll also need to have an  
automated,

scripted process for removing the database if the package is removed,
I'd be interested to get your thoughts on that too.



Thanks in advance for any suggestions guys,



Heston



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Complex SELECT

2008-09-22 Thread Andre Matos

Hello,

I need help with a SQL Select statement:

I have three tables: report, category, and optional

a) report table has 3 fields:

ReportId, CategoryId, ReportDesc

b) category table has 2 fields:

CategoryId, CategoryDesc

c) optional table has three fields:

OptionalId, CategoryId, OptionalDesc


I would like to have something like this:

---
| ReportId | CategoryDesc |  OptionalDesc   | ReportDesc|
---
|   0001 | Example 1| late, query, test |  report desc abc |
|   0002 | Example 2| query  | test  
123|
|   0003 | Example 3| | test  
xzy |
|   0004 | Example 1| late, test |  report  
desc abc |

---

However, when performing my SELECT using LEFT JOIN, I am getting  
something like this:


---
| ReportId | CategoryDesc |  OptionalDesc   | ReportDesc|
---
|   0001 | Example 1| late  |  report  
desc abc |
|   0001 | Example 1| query  |  report  
desc abc |
|   0001 | Example 1| test  |  report  
desc abc |
|   0002 | Example 2| query  | test  
123|
|   0003 | Example 3| | test  
xzy |
|   0004 | Example 1| late |  report  
desc abc |
|   0004 | Example 1| test |  report  
desc abc |

---


Is it possible to have the column OptionalDesc as showed in the  
first table above?


Thanks for any help.

Andre

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Re: Complex SELECT

2008-09-22 Thread Andre Matos

It worked like a charm.

Thanks for the help!

Andre


On 22-Sep-08, at 2:58 PM, Jim Lyons wrote:

look at using the group_concat function on OptionalDesc and group  
by the other fields.


On Mon, Sep 22, 2008 at 1:40 PM, Andre Matos [EMAIL PROTECTED] 
 wrote:

Hello,

I need help with a SQL Select statement:

I have three tables: report, category, and optional

a) report table has 3 fields:

ReportId, CategoryId, ReportDesc

b) category table has 2 fields:

CategoryId, CategoryDesc

c) optional table has three fields:

OptionalId, CategoryId, OptionalDesc


I would like to have something like this:

---
| ReportId | CategoryDesc |  OptionalDesc   | ReportDesc|
---
|   0001 | Example 1| late, query, test |  report desc  
abc |
|   0002 | Example 2| query  | test  
123|
|   0003 | Example 3| | test  
xzy |
|   0004 | Example 1| late, test |  report  
desc abc |

---

However, when performing my SELECT using LEFT JOIN, I am getting  
something like this:


---
| ReportId | CategoryDesc |  OptionalDesc   | ReportDesc|
---
|   0001 | Example 1| late  |   
report desc abc |
|   0001 | Example 1| query  |  report  
desc abc |
|   0001 | Example 1| test  |   
report desc abc |
|   0002 | Example 2| query  | test  
123|
|   0003 | Example 3| | test  
xzy |
|   0004 | Example 1| late |  report  
desc abc |
|   0004 | Example 1| test |  report  
desc abc |

---


Is it possible to have the column OptionalDesc as showed in the  
first table above?


Thanks for any help.

Andre

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InnoDB Transaction and LAST_INSERT_ID()

2006-11-28 Thread Andre Matos
Hi List,

Let's suppose I have these two tables:

CREATE TABLE `changes` (
  `ID` int(12) unsigned NOT NULL auto_increment,
  `Key` varchar(25) collate latin1_general_cs NOT NULL default '',
  `Table` varchar(25) collate latin1_general_cs NOT NULL default '',
  `Value` text collate latin1_general_cs NOT NULL default '',
  PRIMARY KEY (`ID`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 COLLATE=latin1_general_cs
AUTO_INCREMENT=1;


CREATE TABLE `staff` (
  `ID` int(3) unsigned NOT NULL auto_increment,
  `Name` varchar(35) collate latin1_general_cs NOT NULL default '',
  PRIMARY KEY  (`ID`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 COLLATE=latin1_general_cs
AUTO_INCREMENT=1;

The idea is to have a audit trail to record the changes made. So, I want to
insert a new record in the staff table and right after this, insert a
record in the changes table.

SET AUTOCOMMIT=0;
START TRANSACTION;
INSERT INTO staff (`Name`) VALUES ('ABC');
INSERT INTO changes (`Key`, `Table`, `Value`) VALUES (LAST_INSERT_ID(),
'staff', 'ABC');
COMMIT;
SET AUTOCOMMIT=1;

This works fine in my test environment, however what about many users doing
at the same time. Does the LAST_INSERT_ID() get the correct ID for each
user?

Is there a better way to do this or this is fine? I will be using this with
PHP4.

Thanks for any help.

Andre




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Re: InnoDB Transaction and LAST_INSERT_ID()

2006-11-28 Thread Andre Matos
Thanks Mike. 

I understand the possible gaps that I might have if I use the ROLLBACK.
This is acceptable in my case.

What I really want to avoid is what I am doing now: open one transaction to
insert, or update, or delete certain information and close with the commit.
Then, I get the LAST_INSERT_ID() and open another transaction to write my
audit trail. However, if the first one went through ok but if I got a
problem at the second transaction, I need to delete the inserted or updated
or move back the deleted information. This doesn't work well.


Let's expand my staff and change tables to have this structure to
simulate my problem:

++--++
| ID | Name | Gender |
++--++

++-+---+---+---+
| ID | Key | Table | Field | Value |
++-+---+---+---+

And do this:

SET AUTOCOMMIT=0;
START TRANSACTION;

INSERT INTO staff (`Name`, `M`) VALUES ('ABC');

INSERT INTO changes (`Key`, `Table`, `Field`, `Value`) VALUES
(LAST_INSERT_ID(), 'Staff', 'ID', LAST_INSERT_ID());
INSERT INTO changes (`Key`, `Table`, `Field`, `Value`) VALUES
(LAST_INSERT_ID(), 'Staff', 'Name', 'ABC');
INSERT INTO changes (`Key`, `Table`, `Field`, `Value`) VALUES
(LAST_INSERT_ID(), 'Staff', 'Gender', 'M');

COMMIT;
SET AUTOCOMMIT=1;


I will get something like this:

mysql select * from staff;
++--++
| ID | Name | Gender |
++--++
|  1 | ABC  | M  |
++--++
1 row in set (0.00 sec)

mysql select * from changes;
++-+---+---+---+
| ID | Key | Table | Field | Value |
++-+---+---+---+
|  1 | 1   | staff | ID| 1 |
++-+---+---+---+
|  2 | 1   | staff | Name  | ABC   |
++-+---+---+---+
|  3 | 2   | staff | Gender| M |
++-+---+---+---+
3 row in set (0.00 sec)

See that I have a problem in the third line at the Key column where I
should have 1 but I got 2 instead. This happened because of
LAST_INSERT_ID() used the ID from the changes table instead of the desired
staff table.

Is there any way to avoid this? What about the mysql_insert_id()?

Andre




On 11/28/06 7:50 PM, Mike Kruckenberg [EMAIL PROTECTED] wrote:

 Andre Matos wrote:
 SET AUTOCOMMIT=0;
 START TRANSACTION;
 INSERT INTO staff (`Name`) VALUES ('ABC');
 INSERT INTO changes (`Key`, `Table`, `Value`) VALUES (LAST_INSERT_ID(),
 'staff', 'ABC');
 COMMIT;
 SET AUTOCOMMIT=1;
 
 This works fine in my test environment, however what about many users doing
 at the same time. Does the LAST_INSERT_ID() get the correct ID for each
 user?
 
 Is there a better way to do this or this is fine? I will be using this with
 PHP4.
   
 To further clarify (my initial reply didn't give much detail), when an
 auto increment value is created for inserting it is in the scope of the
 current connection, and is not changed by the outcome of the transaction.
 
 If you follow the string of SQL statements against your tables you'll
 see that the ID assigned to the record is not released on a rollback,
 the second insert gets a new auto increment value.
 
 mysql SET AUTOCOMMIT=0;
 Query OK, 0 rows affected (0.00 sec)
 
 mysql START TRANSACTION;
 Query OK, 0 rows affected (0.00 sec)
 
 mysql INSERT INTO staff (`Name`) VALUES ('ABC');
 Query OK, 1 row affected (0.00 sec)
 
 mysql INSERT INTO changes (`Key`, `Table`, `Value`) VALUES
 (LAST_INSERT_ID(),
 - 'staff', 'ABC');
 Query OK, 1 row affected (0.00 sec)
 
 mysql select * from staff;
 ++--+
 | ID | Name |
 ++--+
 |  1 | ABC  |
 ++--+
 1 row in set (0.00 sec)
 
 mysql select * from changes;
 ++-+---+---+
 | ID | Key | Table | Value |
 ++-+---+---+
 |  1 | 1   | staff | ABC   |
 ++-+---+---+
 1 row in set (0.00 sec)
 
 mysql select last_insert_id();
 +--+
 | last_insert_id() |
 +--+
 |1 |
 +--+
 1 row in set (0.00 sec)
 
 mysql rollback;
 Query OK, 0 rows affected (0.26 sec)
 
 mysql select * from staff;
 Empty set (0.00 sec)
 
 mysql select * from changes;
 Empty set (0.00 sec)
 
 mysql INSERT INTO staff (`Name`) VALUES ('ABC');
 Query OK, 1 row affected (0.00 sec)
 
 mysql INSERT INTO changes (`Key`, `Table`, `Value`) VALUES
 (LAST_INSERT_ID(),
 - 'staff', 'ABC');
 Query OK, 1 row affected (0.00 sec)
 
 mysql select * from staff;
 ++--+
 | ID | Name |
 ++--+
 |  2 | ABC  |
 ++--+
 1 row in set (0.00 sec)
 
 mysql select * from changes;
 ++-+---+---+
 | ID | Key | Table | Value |
 ++-+---+---+
 |  2 | 2   | staff | ABC   |
 ++-+---+---+
 1 row in set (0.00 sec)
 




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Re: InnoDB Transaction and LAST_INSERT_ID()

2006-11-28 Thread Andre Matos
Thanks for all your help Mike.

Problem solved. I divided to process in two parts: one write the
insert/update/delete and then write the changes in the audit trail. All this
inside one transaction. If the first part fails, ROLLBACK. If the second
part fails, ROLLBACK, otherwise, if both were done ok, then COMMIT.

I just wanted to have all this in only one part, but that's fine. It's
working fine.

Final question: Can I create an audit trail using TRIGGER in MySQL 5? This
would be the best because any changes in the database (insert/update/delete)
will start the trigger which will be responsible for writing the audit
trail.

Thanks again!!!

Andre


On 11/28/06 9:22 PM, Mike Kruckenberg [EMAIL PROTECTED] wrote:

 Andre Matos wrote:
 Thanks Mike. 
 
 I understand the possible gaps that I might have if I use the ROLLBACK.
 This is acceptable in my case.
 
 What I really want to avoid is what I am doing now: open one transaction to
 insert, or update, or delete certain information and close with the commit.
 Then, I get the LAST_INSERT_ID() and open another transaction to write my
 audit trail. However, if the first one went through ok but if I got a
 problem at the second transaction, I need to delete the inserted or updated
 or move back the deleted information. This doesn't work well.
 
 
 Let's expand my staff and change tables to have this structure to
 simulate my problem:
 
 ++--++
 | ID | Name | Gender |
 ++--++
 
 ++-+---+---+---+
 | ID | Key | Table | Field | Value |
 ++-+---+---+---+
 
 And do this:
 
 SET AUTOCOMMIT=0;
 START TRANSACTION;
 
 INSERT INTO staff (`Name`, `M`) VALUES ('ABC');
 
 INSERT INTO changes (`Key`, `Table`, `Field`, `Value`) VALUES
 (LAST_INSERT_ID(), 'Staff', 'ID', LAST_INSERT_ID());
 INSERT INTO changes (`Key`, `Table`, `Field`, `Value`) VALUES
 (LAST_INSERT_ID(), 'Staff', 'Name', 'ABC');
 INSERT INTO changes (`Key`, `Table`, `Field`, `Value`) VALUES
 (LAST_INSERT_ID(), 'Staff', 'Gender', 'M');
 
 COMMIT;
 SET AUTOCOMMIT=1;
 
 
 I will get something like this:
 
 mysql select * from staff;
 ++--++
 | ID | Name | Gender |
 ++--++
 |  1 | ABC  | M  |
 ++--++
 1 row in set (0.00 sec)
 
 mysql select * from changes;
 ++-+---+---+---+
 | ID | Key | Table | Field | Value |
 ++-+---+---+---+
 |  1 | 1   | staff | ID| 1 |
 ++-+---+---+---+
 |  2 | 1   | staff | Name  | ABC   |
 ++-+---+---+---+
 |  3 | 2   | staff | Gender| M |
 ++-+---+---+---+
 3 row in set (0.00 sec)
 
 See that I have a problem in the third line at the Key column where I
 should have 1 but I got 2 instead. This happened because of
 LAST_INSERT_ID() used the ID from the changes table instead of the desired
 staff table.
 
 Is there any way to avoid this? What about the mysql_insert_id()?
   
 I see. In this case you could make it two operations and use the
 mysql_insert_id() to capture the id from the first insert, setting a
 variable to that in PHP and using that variable to ensure the same number.
 
 What I would consider is setting a database variable inside the
 transaction to store the id - the @ signifies it's a session variable
 that is specific to this connection:
 
 SET AUTOCOMMIT=0;
 START TRANSACTION;
 
 INSERT INTO staff (`Name`, `Gender`) VALUES ('ABC','M');
 
 SET @staff_id = LAST_INSERT_ID();
 
 INSERT INTO changes (`Key`, `Table`, `Field`, `Value`) VALUES
 (@staff_id, 'Staff', 'ID', @staff_id);
 INSERT INTO changes (`Key`, `Table`, `Field`, `Value`) VALUES
 (@staff_id, 'Staff', 'Name', 'ABC');
 INSERT INTO changes (`Key`, `Table`, `Field`, `Value`) VALUES
 (@staff_id, 'Staff', 'Gender', 'M');
 
 COMMIT;
 SET AUTOCOMMIT=1;
 
 
 So you store the value after the first insert and then reuse. You can
 see it in the following string of SQL commands to demonstrate:
 
 mysql INSERT INTO staff (`Name`, `Gender`) VALUES ('ABC','M');
 Query OK, 1 row affected (0.01 sec)
 
 mysql SET @staff_id = LAST_INSERT_ID();
 Query OK, 0 rows affected (0.01 sec)
 
 mysql SELECT @staff_id;
 +---+
 | @staff_id |
 +---+
 | 3 |
 +---+
 1 row in set (0.00 sec)
 
 mysql INSERT INTO changes (`Key`, `Table`, `Value`) VALUES
 (LAST_INSERT_ID(), 'staff', 'ABC');
 Query OK, 1 row affected (0.01 sec)
 
 mysql INSERT INTO changes (`Key`, `Table`, `Value`) VALUES
 (LAST_INSERT_ID(), 'staff', 'ABC');
 Query OK, 1 row affected (0.00 sec)
 
 mysql select LAST_INSERT_ID();
 +--+
 | LAST_INSERT_ID() |
 +--+
 |5 |
 +--+
 1 row in set (0.00 sec)
 
 mysql SELECT @staff_id;
 +---+
 | @staff_id |
 +---+
 | 3 |
 +---+
 1 row in set (0.00 sec)



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Insert and Update together

2006-02-11 Thread Andre Matos
Hi List,

I would like to know if it is possible to combine Insert and Update in one
SQL instruction. This is what I want to do:

I have two tables: one where I will perform and Update replacing m0 by
scr. If MySQL find a m0, it will need to perform an insert into a log
table including the information updated.

I am trying to avoid writing a php4 program to do this. I am using MySQL 4.1

Thanks for any help.

Andre

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Re: Insert and Update together

2006-02-11 Thread Andre Matos
No George. I took a look there before sent this email to the mysql list. My
case it is not a duplicate record. What I want is that if the update in one
table happen, it will be proceed by an insert in another table like a log of
changes.

Andre


On 2/11/06 12:48 PM, George Law [EMAIL PROTECTED] wrote:

 Andre,
 
 I tried this a couple weeks ago... I think you want the on duplicate
 option for the INSERT query.
 
 depends what version you have... I think this was introduced in mysql 4.1
 
 insert into  values () on duplicate key update set x=2,y=5;
 
 unfortunately, the server I was testing this on was running 4.0.x so I
 couldn't use it.
 
 
 http://dev.mysql.com/doc/refman/5.0/en/insert.html
 
 
 
 - Original Message -
 From: Andre Matos [EMAIL PROTECTED]
 To: mysql@lists.mysql.com
 Sent: Saturday, February 11, 2006 10:54 AM
 Subject: Insert and Update together
 
 
 Hi List,
 
 I would like to know if it is possible to combine Insert and Update in one
 SQL instruction. This is what I want to do:
 
 I have two tables: one where I will perform and Update replacing m0 by
 scr. If MySQL find a m0, it will need to perform an insert into a log
 table including the information updated.
 
 I am trying to avoid writing a php4 program to do this. I am using MySQL
 4.1
 
 Thanks for any help.
 
 Andre
 
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MySQL 4.1.15 or 5.0.15

2005-11-07 Thread Andre Matos
Hi List,

I am current using MySQL 4.1.9 and I want to upgrade it, but which one,
4.1.15 or 5.0.15?

Any suggestions?

Andre






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RE: Tracking changes in the database

2005-10-13 Thread Andre Matos
It did not work Daniel. I added this into my.cnf file:

[mysqld]
log-bin=/var/log/mysql/binary.log

and saved the file in two places:

/etc/my.cnf
/usr/local/mysql/my.cnf

Then, I restart the server:

sudo /Lybrary/StartupItems/MySQLCOM restart


I also did two UPDATE, one INSERT, and one DELETE, but the binary.log file
was not created.

Note: I am using Mac OS X.

Andre

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-Original Message-
From: Daniel Kasak [mailto:[EMAIL PROTECTED] 
Sent: Thursday, October 13, 2005 2:33 AM
To: Andre Matos; mysql@lists.mysql.com
Subject: Re: Tracking changes in the database

Andre Matos wrote:

I am using InnoDB and replication, is there any issues?

Thanks.

Andre
  

It depends what you're doing. If you use the binary log, there are no 
issues - in replication uses the binary log to achieve it's goals.
Since the plain-text log is depreciated, you probably should learn to 
use the binary log. As I noted before, the plain-text log has some 
issues. I'm not sure what all of them are, but I've encountered issues 
when using plain-text logs and temporary tables ( eg 2 users create 
temporary tables - in the plain text log, it looks like the 1 user ).

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Tracking changes in the database

2005-10-12 Thread Andre Matos
Hi List,

I need to track the changes made in the database using the insert, update
and delete statements in MySQL 4.1.9. Can I use the Binary Log to get this
information or is there another better solution?

Thanks for any help.

Andre

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RE: Tracking changes in the database

2005-10-12 Thread Andre Matos
I am using InnoDB and replication, is there any issues?

Thanks.

Andre

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-Original Message-
From: Daniel Kasak [mailto:[EMAIL PROTECTED] 
Sent: Thursday, October 13, 2005 1:01 AM
To: Andre Matos; 'mysql@lists.mysql.com '
Subject: Re: Tracking changes in the database

Andre Matos wrote:

Hi List,

I need to track the changes made in the database using the insert, update
and delete statements in MySQL 4.1.9. Can I use the Binary Log to get
this
information or is there another better solution?

Thanks for any help.

Andre

  

The binary log is the recommended way. There's also a plain-text log, 
but you'll run into issues if you're using temporary tables, amongst 
other things. Also, the plain text log has been removed from 5.0.x ( I 
believe ). You can enable either with startup switches or with entries 
in the my.cnf file.

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IT Developer
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Level 5, 77 Pacific Highway
North Sydney, NSW, Australia 2060
T: (+61) 2 9922-7676 / F: (+61) 2 9922 7989
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PHP MySQL connection problem

2005-06-10 Thread Andre Matos
Hi list,

I am getting slow connections between php4 and MySQL 4.1.9.

There are some connections that are very fast, but others can take from 5 to
20 second or more (usually it takes less than 0.1 second to create a new
connection). I tried to identify if there is a pattern but it seems that it
does not exist, in other words, it can create 5 connections and then the 6th
takes too much time. In another time, it process 13 connections fast and the
14th is slow again.

Does anyone has any idea what is going on? Can this be related to the MySQL
connections limit?

Thanks for any help.

Andre
 
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Collation latin1_general_cs

2005-05-02 Thread Andre Matos
Hi List,

I was checking the list of collations for a character set latin that I
have in my MySQL version 4.1.10-standard running on Mac OS X 10.4.

Below is the that I have and does not include latin1_general_cs. What
will happen if I force to use it when I create a database, tables and
fields? Will it work or not?


mysql SHOW COLLATION LIKE 'latin1%';
+---+-++-+--+-+
| Collation | Charset | Id | Default | Compiled | Sortlen |
+---+-++-+--+-+
| latin1_german1_ci | latin1  |  5 | |  |   0 |
| latin1_swedish_ci | latin1  |  8 | Yes | Yes  |   1 |
| latin1_danish_ci  | latin1  | 15 | |  |   0 |
| latin1_german2_ci | latin1  | 31 | | Yes  |   2 |
| latin1_bin| latin1  | 47 | | Yes  |   1 |
| latin1_general_ci | latin1  | 48 | |  |   0 |
| latin1_general_cs | latin1  | 49 | |  |   0 |
| latin1_spanish_ci | latin1  | 94 | |  |   0 |
+---+-++-+--+-+

Thanks for any help.

Andre

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Re: Collation latin1_general_cs

2005-05-02 Thread Andre Matos
Hi Paul,

It does appear in the list, but there is no Yes in the column Compiled
and that's why my concern. I am using the Collation latin1_general_cs
since I moved from version 3.x to 4.1.10. Is it really working without
compiled?

Andre


On 5/2/05 4:04 PM, Paul DuBois [EMAIL PROTECTED] wrote:

 At 15:28 -0400 5/2/05, Andre Matos wrote:
 Hi List,
 
 I was checking the list of collations for a character set latin that I
 have in my MySQL version 4.1.10-standard running on Mac OS X 10.4.
 
 Below is the that I have and does not include latin1_general_cs. What
 will happen if I force to use it when I create a database, tables and
 fields? Will it work or not?
 
 I don't understand what you mean by stating that the list doesn't
 include latin1_general_cs.  It does appear in the list.
 
 
 
 mysql SHOW COLLATION LIKE 'latin1%';
 +---+-++-+--+-+
 | Collation | Charset | Id | Default | Compiled | Sortlen |
 +---+-++-+--+-+
 | latin1_german1_ci | latin1  |  5 | |  |   0 |
 | latin1_swedish_ci | latin1  |  8 | Yes | Yes  |   1 |
 | latin1_danish_ci  | latin1  | 15 | |  |   0 |
 | latin1_german2_ci | latin1  | 31 | | Yes  |   2 |
 | latin1_bin| latin1  | 47 | | Yes  |   1 |
 | latin1_general_ci | latin1  | 48 | |  |   0 |
 | latin1_general_cs | latin1  | 49 | |  |   0 |
 | latin1_spanish_ci | latin1  | 94 | |  |   0 |
 +---+-++-+--+-+
 

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Re: Collation latin1_general_cs

2005-05-02 Thread Andre Matos
Ok Paul. 

Do you have any idea why phpMyAdmin removed the latin1_general_cs from the
collation pop-up list?

I have the same problem like this one (except that I am using Mac OS X):
http://forums.mysql.com/read.php?11,21462,21462

I looked at the release notes for the version 2.6.2 (it was working up to
version 2.6.1-pl3), and I found this: Do not offer unavailable collations.

Does this means that if the MySQL is not compiled with the
latin1_general_cs it will not work even if MySQL loaded it at runtime?

Andre


On 5/2/05 4:44 PM, Paul DuBois [EMAIL PROTECTED] wrote:

 At 16:15 -0400 5/2/05, Andre Matos wrote:
 Hi Paul,
 
 It does appear in the list, but there is no Yes in the column Compiled
 and that's why my concern. I am using the Collation latin1_general_cs
 since I moved from version 3.x to 4.1.10. Is it really working without
 compiled?
 
 Yes.  Some character set information is loaded at runtime.
 
 
 
 Andre
 
 
 On 5/2/05 4:04 PM, Paul DuBois [EMAIL PROTECTED] wrote:
 
  At 15:28 -0400 5/2/05, Andre Matos wrote:
  Hi List,
 
  I was checking the list of collations for a character set latin that I
  have in my MySQL version 4.1.10-standard running on Mac OS X 10.4.
 
  Below is the that I have and does not include latin1_general_cs. What
  will happen if I force to use it when I create a database, tables and
  fields? Will it work or not?
 
  I don't understand what you mean by stating that the list doesn't
  include latin1_general_cs.  It does appear in the list.
 
 
 
  mysql SHOW COLLATION LIKE 'latin1%';
  +---+-++-+--+-+
  | Collation | Charset | Id | Default | Compiled | Sortlen |
  +---+-++-+--+-+
  | latin1_german1_ci | latin1  |  5 | |  |   0 |
  | latin1_swedish_ci | latin1  |  8 | Yes | Yes  |   1 |
  | latin1_danish_ci  | latin1  | 15 | |  |   0 |
  | latin1_german2_ci | latin1  | 31 | | Yes  |   2 |
  | latin1_bin| latin1  | 47 | | Yes  |   1 |
  | latin1_general_ci | latin1  | 48 | |  |   0 |
  | latin1_general_cs | latin1  | 49 | |  |   0 |
  | latin1_spanish_ci | latin1  | 94 | |  |   0 |
 +---+-++-+--+-+
 

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Collation latin1_general_cs

2005-05-01 Thread Andre Matos
Hi List,

I was checking the list of collations for a character set latin that I
have in my MySQL version 4.1.10-standard running on Mac OS X 10.4.

The list that I have, bellow, does not include latin1_general_cs. What
will happen if I force to use it when I create a database, tables and
fields? Will it work or not?


mysql SHOW COLLATION LIKE 'latin1%';
+---+-++-+--+-+
| Collation | Charset | Id | Default | Compiled | Sortlen |
+---+-++-+--+-+
| latin1_german1_ci | latin1  |  5 | |  |   0 |
| latin1_swedish_ci | latin1  |  8 | Yes | Yes  |   1 |
| latin1_danish_ci  | latin1  | 15 | |  |   0 |
| latin1_german2_ci | latin1  | 31 | | Yes  |   2 |
| latin1_bin| latin1  | 47 | | Yes  |   1 |
| latin1_general_ci | latin1  | 48 | |  |   0 |
| latin1_general_cs | latin1  | 49 | |  |   0 |
| latin1_spanish_ci | latin1  | 94 | |  |   0 |
+---+-++-+--+-+

Thanks for any help.

Andre

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Slow access Apache + PHP + MySQL

2005-03-26 Thread Andre Matos
Hi List,

I have 4 web based systems developed using PHP4 and MySQL accessed for 10
users. The Web Server and Database Server were running ok on a Mac OS X 10.3
G4 dual. However, since we move to a new server, the access becomes very
slow. This was not expected since we move to a 64 bits high performance
machine.

Now, we are using MySQL version 4.1.9 with Apache 2.0.52 and PHP 4.3.10, all
compiled and running on a Linux Fedora X86_64.

My first thought was the systems, but since I have not changed 3 of the 4
systems, I start to look to the database. I monitored the MySQL using MySQL
Administrator, but I couldn't identify any problem. It looks ok, but not
completely sure if really is.

The system administrator told me that could be the PHP session, but again,
he also was not complete sure about this.

It is a big problem since I need to check in 3 places: MySQL, Apache, or
PHP.

Does anyone had this kind of problem or has any suggestion or direction to
help me to identify and solve this issue?

Any help will be appreciated!!!

Thanks.

Andre

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InnoDB and Transactions

2005-02-07 Thread Andre Matos
Hi List,

Let's suppose that I have this sequence of events:

- create a connection 1
-- start a transaction
--- create a new connection 2
 insert a new record named B
--- close the connection 2
--- insert a new record named A
-- rollback
- close the connection 1

This sequence will be written in PHP4. My question is:

Will the record named B be written in the database or it will be rollback
with the record named A?
 
Thanks for any help!!!

Andre

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Symchronization problem

2005-02-03 Thread Andre Matos
Hi List,

A have two MySQL 4.1.9 installed into two Linux servers and synchronized
them, so I have now a master and slave.

My problem is that since I synchronized them, I am receiving comments from
my users that the speed is not good as before the synchronization. Is this
possible? If yes, how and where can I check this?

Thanks for any help.

Andre

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Re: utf8 x latin

2005-02-01 Thread Andre Matos
Thanks for your help Gabriel.

I will use the latin1 with case sensitive.

Andre


On 1/31/05 7:32 AM, Gabriel PREDA [EMAIL PROTECTED] wrote:

 I think you should use: latin1_general_ci  and on columns with spanish you
 should use latin1_spanish_ci.
 
 English, French, Portuguese not having a separate collation I believe that
 they are included into latin1_general_ci ?
 
 Please observe the last part from a collation name: case sensitive (_cs) ...
 case insensitive (_ci) ... and binary (_bin) !
 
 UTF8 consumes more space on disk !
 If you issue a SHOW CHARACTER SET command
 
 mysql SHOW CHARACTER SET;
 
 You will notice the last column named Maxlen that defines how many bytes
 takes to store a letter.
 
 On utf8_general_ci you will notice 3... as on latin1__xx you will only
 see 1...
 Although these values represent a MAX value... what you need will use at
 most 2 bytes per letter in UTF-8... but in latin1_xxx_xx will, for sure,
 will use one byte... on long texts this will count !
 
 In my opinion you should stick to latin1_xxx_xx !
 
 Afther some thought and aditional computation I declared myself satisfied
 with:
 latin2 - ISO 8859-2 Central European - latin2_general_ci - 1byte
 
 but I'm having Romanian + English + French columns.
 
 Try to read http://dev.mysql.com/doc/mysql/en/charset.html with no
 distraction arround you !
 
 Gabriel
 
 - Original Message -
 From: Andre Matos [EMAIL PROTECTED]
 To: mysql@lists.mysql.com
 Sent: Sunday, January 30, 2005 9:29 PM
 Subject: utf8 x latin
 
 
 Hi list,
 I was wondering which one is better to use, utf8_general_ci or
 latin1_general_cs, with English, French, Portuguese, and Spanish?
 Thanks.
 Andre
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utf8 x latin

2005-01-30 Thread Andre Matos
Hi list,

I was wondering which one is better to use, utf8_general_ci or
latin1_general_cs, with English, French, Portuguese, and Spanish? 

Thanks.

Andre

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Server crached problem

2005-01-27 Thread Andre Matos
Hi List,

Today the hard drive from my server where MySQL was running crashed. I have
a dump from yesterday night but I would like to save the work for today
before the crash. I saved the full directory of the MySQL
(/usr/local/mysql).

Is my data inside the frm file or in another file? How can I access and
retrieve my data?

Thanks for any help.

Andre

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Rollback and INSERT_ID() or LAST_INSERT_ID()

2005-01-17 Thread Andre Matos
Hi List,

I have a field in one of my tables that uses auto-increment from MySQL
4.1.8-nt (Windows XP).

My problem is to get the last insert ID when the insert fails and I use
rollback. The MySQL is still incrementing the field. How can I avoid this if
it is possible? I am trying to avoid to use the function MAX() to get the
last ID inserted.

Thanks for any help.

Andre

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Re: Rollback and INSERT_ID() or LAST_INSERT_ID()

2005-01-17 Thread Andre Matos
Thanks Eric, but I can let it increment because I cannot have a gave in the
numbers. I think I will need to use MAX() in this case.

Thanks.

Andre



On 1/17/05 8:14 PM, Eric Bergen [EMAIL PROTECTED] wrote:

 Just let it increment. Keeping it incremented is MySQL's way ot
 insuring that the same id doesn't get used twice for different
 records. It's doing everything correctly.
 
 -Eric
 
 On Mon, 17 Jan 2005 19:06:45 -0500, Andre Matos
 [EMAIL PROTECTED] wrote:
 Hi List,
 
 I have a field in one of my tables that uses auto-increment from MySQL
 4.1.8-nt (Windows XP).
 
 My problem is to get the last insert ID when the insert fails and I use
 rollback. The MySQL is still incrementing the field. How can I avoid this if
 it is possible? I am trying to avoid to use the function MAX() to get the
 last ID inserted.
 
 Thanks for any help.
 
 Andre
 
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Re: Rollback and INSERT_ID() or LAST_INSERT_ID()

2005-01-17 Thread Andre Matos
Yes, I know about this. What I plan is to remove the auto_increment. I will
do this by hand locking the entire table just right before inserting the
field. Actually, it is running like this. I am just upgrading the PHP.

I will keep the auto_increment in other tables that does not have this kind
of problem.

Thanks a lot for your help.

Andre

On 1/17/05 9:53 PM, Paul DuBois [EMAIL PROTECTED] wrote:

 At 21:27 -0500 1/17/05, Andre Matos wrote:
 Thanks Eric, but I can let it increment because I cannot have a gave in the
 numbers. I think I will need to use MAX() in this case.
 
 Using MAX() won't guarantee that you won't have gaps.
 
 What you're describing cannot be achieved in the general case.
 Consider this scenario:
 
 - Transaction T1 begins, generates an AUTO_INCREMENT value n.
 - Transaction T2 begins, generates an AUTO_INCREMENT value n+1.
 - Transaction T2 commits.
 - Transaction T1 rolls back.
 
 You now have a gap at value n, and a used value of n+1.
 MAX() at this point returns n+1, not n, so that won't
 help you reuse n.
 
 With more than two transactions running simultaneously, each
 of which can roll back or commit, the situation becomes more
 complex.
 
 Might be worth reconsidering whether you really require no
 gaps.  It's generally better to try to design an application
 not to have that dependency.
 
 
 Thanks.
 
 Andre
 
 
 
 On 1/17/05 8:14 PM, Eric Bergen [EMAIL PROTECTED] wrote:
 
  Just let it increment. Keeping it incremented is MySQL's way ot
  insuring that the same id doesn't get used twice for different
  records. It's doing everything correctly.
 
  -Eric
 
  On Mon, 17 Jan 2005 19:06:45 -0500, Andre Matos
  [EMAIL PROTECTED] wrote:
  Hi List,
 
  I have a field in one of my tables that uses auto-increment from MySQL
  4.1.8-nt (Windows XP).
 
  My problem is to get the last insert ID when the insert fails and I use
  rollback. The MySQL is still incrementing the field. How can I
 avoid this if
  it is possible? I am trying to avoid to use the function MAX() to get the
  last ID inserted.
 
  Thanks for any help.
 
 Andre
 

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Grant question

2005-01-05 Thread Andre Matos
Hi list,

I have many databases on my MySQL server such as:

dbexample
dbexample_clients_abc
dbexample_clients_def
dbexample_clients_ghi
dbexample_local_abc
dbexample_local_def
dbexample_local_ghi

Is it possible to grant all these databases in just one GRANT instruction
such as:

GRANT SELECT,INSERT,UPDATE,DELETE ON dbexample*.* TO 'user'@'localhost' BY
'password';

I tried this instruction but did not work. Is someone knows how to do if it
is possible?

Thanks for any help.

Andre

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MySQL configuration file on Mac OS X

2004-11-29 Thread Andre Matos
Hi List,

I installed the MySQL 4.1.7 on my Windows XP and for that I have used the
my.ini to set the startup configuration for using a different language and
to use the old_password.

Now I am installing on my Mac and I am wondering if there is any my.ini
or my.cnf on Mac OS X.

Does anyone knows about this?

Thanks for any help.

Andre

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Re: MySQL configuration file on Mac OS X

2004-11-29 Thread Andre Matos
I just have finished to install the version 4.1.7 on my Mac and I looked at
these directories below and I couldn't find the file my.cnf as described
on the like that you gave me:

/etc/my.cnf
DATADIR/my.cnf
~/.my.cnf

Do I need to create it or MySQL is suppose to do the job?

Thanks.

Andre


On 11/29/04 1:55 PM, Michael Stassen [EMAIL PROTECTED] wrote:

 Mac OS X is Unix, so you follow the directions for Unix, which means you use
 my.cnf.  See the manual for details
 http://dev.mysql.com/doc/mysql/en/Option_files.html.
 
 Michael
 
 Andre Matos wrote:
 
 Hi List,
 
 I installed the MySQL 4.1.7 on my Windows XP and for that I have used the
 my.ini to set the startup configuration for using a different language and
 to use the old_password.
 
 Now I am installing on my Mac and I am wondering if there is any my.ini
 or my.cnf on Mac OS X.
 
 Does anyone knows about this?
 
 Thanks for any help.
 
 Andre
 

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MySQL 4.1 and PHP5 with old client

2004-11-26 Thread Andre Matos
Hi,

I have installed MySQL 4.1.7-nt + Apache 2 + PHP 5.0.2 + PHPMyAdmin
2.6.0-pl1 on my Windows XP Pro SP2. I am trying to solve the problem with
MySQL PHP Old Clients using OLD_PASSWORD instead of just PASSWORD.

How can I set on my.ini to start MySQL using as a default the
OLD_PASSWORD? 

I tried to insert:
[mysqld]
--old-passwords 

and

[mysqld]
old-passwords

but both didn't work.

Does anybody know how to do this? Is any other better way to make PHP5 work
with the new password format without recompiling (It is easy on Linux/Unix
but not on Windows XP).

Thanks for any help.

Andre
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Re: SELECT question

2004-09-21 Thread Andre Matos
Hi Roger,

I took the suggestion from Brad Eacker and use BETWEEN and now works without
problem. However, I decided to do a couple more tests and what I found was
that the problem occurs on MySQL version 4.0.18-standard using InnoDB on
Linux but does not occur on Mac OS X using the same MySQL version.

Andre


On 9/20/04 5:52 PM, Roger Baklund [EMAIL PROTECTED] wrote:

 * Andre Matos
 I am performing a SELECT and I am getting 0 rows when I run the SELECT
 direct in the MySQL database and getting 1 when I run using PHP.
 This is my
 select:
 
 SELECT * FROM scan WHERE TimePointID = 3 AND ScanQCResult = 'n' AND
 (ScanStatusID  90 OR ScanStatusID  98);
 
 Looks ok.
 
 I realized latter analyzing this select that I made a mistake using OR at
 this point: (ScanStatusID  90 OR ScanStatusID  98), it should be AND.
 
 Are you sure about that?
 
 However, in both cases, I am still getting 0 rows from the database, which
 is correct.
 
 My problem is using the PHP to run the SELECT, if I use OR using
 the PHP, I
 got 1 as a result, and if I use AND I got 0 as a result.
 
 This is correct, if you have one record with ScanStatusID in the range
 90-98.
 
 Is anyone can tell me what is going on?
 
 You seem to be misinterpreting how logical expressions work. A SQL select
 statement is a description of the (sub-)set of data you wish to retrieve
 from the database. This description often includes a WHERE clause,
 describing wanted records, which again often includes a logical expression.
 The expression is built up by operands and operators. The logical operators
 relevant in SQL is AND, OR and NOT. NOT is a negation, this operator takes
 one operand, the the result is the opposite of the operand. NOT true is
 false, and NOT false is true. The other two operators, AND and OR, need two
 operands, one on each side. For the AND operator, BOTH sides of the operator
 must be true for this part of the expression to be true. For the OR
 operator, ANY of the sides of the operator must be true for that part of the
 expression to be true.
 
 So, for your expression above, you can not say ...ScanStatusID  90 AND
 ScanStatusID  98..., because ScanStatusID can not be below 90 AND above 98.
 ScanStatusID is a single number, it can be below 90 OR above 98. Not both at
 the same time.
 
 --
 Roger

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SELECT question

2004-09-20 Thread Andre Matos
Hi List,

I am performing a SELECT and I am getting 0 rows when I run the SELECT
direct in the MySQL database and getting 1 when I run using PHP. This is my
select:

SELECT * FROM scan WHERE TimePointID = 3 AND ScanQCResult = 'n' AND
(ScanStatusID  90 OR ScanStatusID  98);

I realized latter analyzing this select that I made a mistake using OR at
this point: (ScanStatusID  90 OR ScanStatusID  98), it should be AND.
However, in both cases, I am still getting 0 rows from the database, which
is correct.

My problem is using the PHP to run the SELECT, if I use OR using the PHP, I
got 1 as a result, and if I use AND I got 0 as a result.

Is anyone can tell me what is going on?

Thanks in advance for any help.

Andre

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Scripts

2004-07-08 Thread Andre MATOS
Hi List,

Let's suppose that I have a script to create one database (tables, 
indexes, etc).

How can I call another script from this script? For example:

DROP DATABASE test;
CREATE DATABASE test;

(here call another script)

back to the previous script



Thanks.

Andre

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RE: Scripts - ERROR

2004-07-08 Thread Andre MATOS
Hi,

I tried but didn't work. Here is my script:

# 
# @Name : NTT_dbcreator.2004-06-07.v1-001.andre.sql
# @DESCRIPTION  : NTT Database Creator
# @CREATED  : Jun 07, 2004 by Andre Matos - [EMAIL PROTECTED]
# @VERSION  : 1.01
# 

SET FOREIGN_KEY_CHECKS=0;

DROP DATABASE IF EXISTS `database1`;
CREATE DATABASE `database1`;
commit;
SOURCE ntt_dbcreator.2004-06-07.v1-001.andre.sql;
commit;

DROP DATABASE IF EXISTS `database2`;
CREATE DATABASE `database2`;
commit;
SOURCE ntt_dbcreator.2004-06-07.v1-001.andre.sql;
commit;


DROP DATABASE IF EXISTS `database3`;
CREATE DATABASE `database3`;
commit;
SOURCE ntt_dbcreator.2004-06-07.v1-001.andre.sql;
commit;


DROP DATABASE IF EXISTS `database4`;
CREATE DATABASE `database4`;
commit;
SOURCE ntt_dbcreator.2004-06-07.v1-001.andre.sql;
commit;


DROP DATABASE IF EXISTS `database5`;
CREATE DATABASE `database5`;
commit;
SOURCE ntt_dbcreator.2004-06-07.v1-001.andre.sql;
commit;


DROP DATABASE IF EXISTS `database6`;
CREATE DATABASE `database6`;
commit;
SOURCE ntt_dbcreator.2004-06-07.v1-001.andre.sql;
commit;


SET FOREIGN_KEY_CHECKS=0;


# end of the script


NB: ntt_dbcreator.2004-06-07.v1-001.andre.sql is another script that is 
responsable for creating the tables, indexes, relations, etc...

This is the error when I tried to run the main script using phpMyAdmim:

 Database mysql  running on localhost

Error

SQL-query : 

SOURCE ntt_dbcreator.2004 -06 - 07.v1 - 001.andre.sql

MySQL said:

#1064 - You have an error in your SQL syntax.  Check the manual that 
corresponds to your MySQL server version for the right syntax to use near 
'SOURCE ntt_dbcreator.2004-06-07.v1-001.andre.sql' at line 1


Thanks.

Andre



On Thu, 8 Jul 2004, Victor Pendleton wrote:

 Have you tried writing the script using the source command?
 drop database;
 create database;
 source populate_db;
 
 
 -Original Message-
 From: Andre MATOS
 To: [EMAIL PROTECTED]
 Sent: 7/8/04 12:20 PM
 Subject: Scripts
 
 Hi List,
 
 Let's suppose that I have a script to create one database (tables, 
 indexes, etc).
 
 How can I call another script from this script? For example:
 
 DROP DATABASE test;
 CREATE DATABASE test;
 
 (here call another script)
 
 back to the previous script
 
 
 
 Thanks.
 
 Andre
 
 

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Re: ER Diagrams with mysql

2004-07-06 Thread Andre MATOS
Hi,

Have you tried DBDesigner4? Take a look, it's an OpenSource.

http://www.fabforce.net/dbdesigner4/

Andre


On Tue, 6 Jul 2004, Daniel Kasak wrote:

 Leandro Melo wrote:
 
 Hi,
 i created a database with around 20 tables. However i
 created the tables by script writting all create table
 statements, create constraints, etc...
 
 I need now a Entity Relationship diagram so i have a
 visual information about my database.
 
 I tried MySQL Comand Center but i doens't have such
 tool.
 Does any one know either a tool i can throw a database
 creation script and it gives me the relationship
 diagram or a mysql tool that can use my installed
 database and generate the relationship diagrams???
 
 Thanks,
 
   
 
 Data Architect, by 'The Kompany' does ER diagrams.
 
 http://www.thekompany.com/products/dataarchitect/
 
 It has a 'reverse engineer' feature that lets you suck a schema from a 
 DB server. It also outputs a schema in SQL scripts. I'm not sure if you 
 can feed it SQL scripts, but it seems like a logical function for it to 
 have. I haven't used it for quite some time...
 
 It's not free. I don't know of any free ER tools. Or at least none I've 
 found and investigated were good enough to remember.
 
 

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Subtracting two Dates and getting days

2004-05-23 Thread Andre MATOS
Hi,

How can I subtract two dates and get the number of days?

(date1 - date2) = days

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Re: Subtracting two Dates and getting days - SOLVED

2004-05-23 Thread Andre MATOS
Hi All,

I found a function named TO_DAYS that solved my problem.

Thanks.

Andre

On Sun, 23 May 2004, Andre MATOS wrote:

 Hi,
 
 How can I subtract two dates and get the number of days?
 
 (date1 - date2) = days
 
 Thanks.
 
 

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Sub-SELECT

2004-05-14 Thread Andre MATOS
Hi list,

does MySQL accept a SELECT inside another SELECT, like this:

SELECT t.Trial_ID_Code AS Trial, 
CONCAT(s.Site_Primary_Investigator_Title,  , 
s.Site_Primary_Investigator_Last_Name) AS 'Investigator', 
CONCAT(sc.Site_ID_Number, -, s.Site_ID_Code, -, sc.Scanner_ID_Number) 
AS Site, 
sc.Scan_Subject_ID AS 'SubjectInitials', 
sc.Scan_Screening_ID AS 'ScreeningNumber', 
tp.TimePoint_Code AS 'TimePoint', 
sc.Scan_Acquired_On AS 'ScanAcquiredOn', 
IF(sc.QCResult_ID_Number = 2, 'Passed', 'Faild') AS 'QCResult', 
IF(sc.Scan_Screening_Result='n', 'Failed', 'Passed') AS 
'GDScreeningResult'
(SELECT Scan_Screening_Result FROM ScanQuantification WHERE 
sc.Trial_ID_Number = Trial_ID_Number AND sc.Site_ID_Number = 
Site_ID_Number AND sc.Scanner_ID_Number = Scanner_ID_Number AND 
sc.Scan_ID_Number = Scan_ID_Number AND sq.Quantification_ID_Number = 1 AND 
ProcessType_ID_Number = 5) AS 'GDScreeningValue'
FROM Scan sc, Trial t, Site s, TimePoint tp
WHERE sc.Trial_ID_Number = t.Trial_ID_Number AND sc.Site_ID_Number = 
s.Site_ID_Number AND sc.TimePoint_ID_Number = tp.TimePoint_ID_Number AND 
sc.TimePoint_ID_Number = 8 
AND (sc.Scan_Receipt_On = '2004-05-10' AND sc.Scan_Receipt_On = 
'2004-05-14') AND sc.QCResult_ID_Number  1 
ORDER BY sc.Site_ID_Number

 
Thanks.

Andre

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Case Sensitive

2004-05-12 Thread Andre MATOS
Hi List,
  
I have three MySQL servers. One is running on Windows XP, another on MacOS 
X, and finally one on Linux. All servers have the same version: 4.0.18.
  
Every time when I create tables on the servers Windows XP and MacOS, MySQl 
creates the database without creating problems with the tables names (is 
not case sensitive). However, in the Linux I have problems (it follows 
exactly the name  uppercase and lowercase  is case sensitive).

So, for example:
On Windows/Mac: TestABC is created as testabc
On Linux: TestABC is created as TestABC
 
1) How can I disable this in the MySQL server running on Linux?
 
2) What is better? Disable or enable the others two?

By the way, I have the same problem with the usernames and passwords. How 
can I enable/disable MySQL case sensitive for data?

Thanks.
  
Andre

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SELECT HELP

2004-04-30 Thread Andre MATOS
Hi,

Is it possible to create a Select performing a math formula? For example:

First I need to add two values come from the same table but from different 
records. The result will be divided from one number got from another 
table. Now, the new result will be added with another value got from 
another table creating the final result. Like this:

((value_from_record_1_from_table_A + value_from_record_15_from_table_A) / 
value_from_table_B ) + value_from_table_C

Is this possible? Is there anyone who can help me to create this SELETC?

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Re: SELECT HELP

2004-04-30 Thread Andre MATOS
Hi Robert,

the criteria for the record_1 and record_15 is that both are in the same 
table, but in different records and to find each one it is necessary to 
perform a WHERE clause.

Let's I give you the real example: 

My problem is while inserting a new record in my table named 
ScanQuantification, I will need to update another table named Scan, IF 
a value from the field ScanQuantificationValue from table 
ScanQuantification is equal or greater than a calculate value.

The calculate value comes from this formula:

( ( A + B ) / 2 +  C) 

where:

A is a value find from the field ScanQuantificationValue from table 
ScanQuantification where the TimePoint = 8

B is a value find from the field ScanQuantificationValue from table 
ScanQuantification where the TimePoint = 9

C is a value find from the field TrialBaseValue from table Trial


This is easy to do using the PHP language. However I will have different 
Trials and each one has different formula. That's why I want to put the 
SELECT to work for me.

Thanks

Andre



On Fri, 30 Apr 2004, Robert J Taylor wrote:

 Andre MATOS wrote:
 
 Hi,
 
 Is it possible to create a Select performing a math formula? For example:
 
 First I need to add two values come from the same table but from different 
 records. The result will be divided from one number got from another 
 table. Now, the new result will be added with another value got from 
 another table creating the final result. Like this:
 
 ((value_from_record_1_from_table_A + value_from_record_15_from_table_A) / 
 value_from_table_B ) + value_from_table_C
 
   
 
 Not knowing what the criteria for selecting the different records from
 table_A (1 and 15), I'll forgo a join clause and just illustrate a
 simple alias with where clause:
 
 SELECT (( a1.value + a2.value ) /  b.value ) + c.value AS final_result
 FROM
 table_A a1, table_A a2, table_B b, table_C c
 WHERE
 a1.key = 1 AND a2.key = 15 AND
 /* guessing here */
 b.key = a1.key AND c.key = a2.key
 AND a1.key  a2.key
 AND a2.key IS NOT NULL
 AND a1.key IS NOT NULL;
 
 That's not correct as I am guessing your actual criteria, etc., but it
 gives the idea. Can you be more specific on the criteria for relating
 (joining) tables A, records 1 and 15, with themselves and with tables B
 and C?
 
 Is this possible? Is there anyone who can help me to create this SELETC?
 
 Thanks.
 
   
 
 HTH,
 
 Robert Taylor
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The MySQL data folder can be an virtual link?

2004-03-22 Thread Andre MATOS
Hi,

Is it possible to move the folder data where there are all databases to 
another hard driver and then create a virtual link using ln -s? If yes, 
is it just shutdown the MySQL server and then move the folder, create the 
link and finally start up the server?

Thanks!

Andre

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How can I upload dumped data

2004-03-19 Thread Andre MATOS
Hi List,

Once I have dumped my database using mysqldump how can I upload the data 
again using the mysql command line (MySQL in ansi mode)?

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How can I upload dumped data (fwd)

2004-03-19 Thread Andre MATOS

Hi List,

Once I have dumped my database using mysqldump how can I upload the data 
again using the mysql command line (MySQL in ansi mode)?

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Re: How can I upload dumped data

2004-03-19 Thread Andre MATOS

I tried it, but it didn't work.

ERROR 1217 at line 3483: Cannot delete or update a parent row: a foreign 
key constraint fails

I am using InnoDB... that's my problem...

Thanks.

Andre


On Fri, 19 Mar 2004, Egor Egorov wrote:

 Andre MATOS [EMAIL PROTECTED] wrote:
  Hi List,
  
  Once I have dumped my database using mysqldump how can I upload the data 
  again using the mysql command line (MySQL in ansi mode)?
  
 
   mysql -u user_name -p database_name  dump_file.sql
 
 
 
 

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Re: MySQL Backup advice

2004-03-04 Thread Andre MATOS
Hi Ware Adams,

thanks for your answer. Here's another question:

Is it possible to set MySQL to save all the changes that can happen, for 
example, if some one insert a new record into table X, MySQL save a log 
about this task performed and all data that was inserted. I another person 
update one field from table Y, MySQL save all the information about this 
change. So, If something happens after the backup, we can recover the 
database without go back and perform again the insert and the update?

If yes, where can I find documentation about this?

Thansk a lot.

Andre


On Wed, 3 Mar 2004, Ware Adams wrote:

 Andre MATOS wrote:
 
 What is the best way to make a good and trustable backup from a live
 database, in other words, without shutdown the database? Is there any
 free open source tool for this also?
 
 There's no free/open source tool that makes a true hot backup when
 you're using InnoDB.
 
 mysqldump can be scripted to only dump one table at a time, but that
 means the tables will not be consistent.  You can dump the entire
 dataset, but that will lock out other users.  mysqldump files are easily
 readable and if you backup a table at a time you can restore only a
 single table.
 
 InnoDB Hot Backup makes a consistent backup across all tables without
 disturbing users.  It's not free and you can only restore the entire
 data set (to which you could then apply binlogs from the backup time
 forward to bring the data set up to current time).  You also cannot view
 or edit the files with a text editor.  Also, InnoDB Hot Backup only
 backs up the InnoDB table space and logs.  You must also back up your
 table definitions and binlogs separately.
 
 This is all described in the InnoDB manual at http://www.innodb.com/
 
 We use both methods as they are helpful under different circumstances.
 
 Good luck,
 Ware Adams
 

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Re: Client connection error

2004-03-03 Thread Andre MATOS
Hi Sasha,

after I sent this email for the list, I did some tests and I realized that 
the problem could be my firewall, so I just turned off for some tests and 
it worked. Now I need to reconfigure the firewall to permit access for the 
MySQL.

Thanks a lot.

Andre

On Tue, 2 Mar 2004, Sasha Pachev wrote:

 Andre MATOS wrote:
  Hi,
  
  I am trying to connect from one computer that has MySQL installed 
  (client) in another one that also has MySQL (server). Using this command:
  
  C:\mysql\binmysql.exe -u root -h server.com -p
  Enter password: *
  ERROR 2003: Can't connect to MySQL server on 'server.com' (10060)
  
  
  However I am also using Apache+PHP and it is working withou problem.
  
  Does anyone know what is the problem?
 
 The error means connection timed out. Possibly a restrictive firewall?
 
 

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MySQL Backup advice

2004-03-03 Thread Andre MATOS
Hi,

I am using MySQL 4.0.18 with InnoDB and I would to have some suggestions 
about how can I backup the data. I read in this list that some people are 
using mysqldump, others are using some tools such as Hot Backup.

What is the best way to make a good and trustable backup from a live 
database, in other words, without shutdown the database? Is there any free 
open source tool for this also?

Thanks.

Andre

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Inserting and Grant users

2004-03-02 Thread Andre MATOS
Hi,

I insert a new user to access the MySQL database. I have 4 databases plus 
the mysql database. I want that this user can run the select instruction 
just into one database, so I did this:

[prompt]$ mysql u root p
Welcome to the MySQL monitor.  Commands end with ; or \g.
Your MySQL connection id is 3147 to server version: 4.0.18-standard

Type 'help;' or '\h' for help. Type '\c' to clear the buffer.

mysql USE mysql;
Reading table information for completion of table and column names
You can turn off this feature to get a quicker startup with -A

Database changed
INSERT INTO user (Host, User, Password, Select_priv) VALUES ('%', 
'myuser', password('hispassword'), 'Y');
mysql GRANT ALL ON database2.* TO myuser;
mysql FLUSH PRIVILEGES; 
mysql quit;


However, when I log using this new user myuser, I still can see the others 
database and a can insert, update and delete records into all databases 
instead of just have the rights to select in the database2. What I did was 
correct or it is missing something?

Best Regards,

Andre

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MySQL speed problem

2004-03-02 Thread Andre MATOS
Hi,

I faced a speed access problem today with the MySQL. In the morning was 
working well and fast, but after lunch when I tried to access the MySQl 
using Apache+PHP it was terrible. For just a select, it took 2 a 3 minutes 
to process. I checked the log files from Apache and PHP and I could not 
find any problem. The unique thing that I found was the hard-drive space. 
It was 1.7 GB. I am using Mac OS 10.3. So I cleaned and I got 3.1 GB and 
after 1 hour the fast speed came back.

Does MySQL use a lot the swap area? I am using Innodb.

Where I can find a tutorial or a good documentation that can help to set 
up a good MySQL environment, because I will hold a lot of data in near 
future.

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Re: Inserting and Grant users

2004-03-02 Thread Andre MATOS
On Tue, 2 Mar 2004, Michael Stassen wrote:
 
 Andre MATOS wrote:
 
  Hi,
  
  I insert a new user to access the MySQL database. I have 4 databases plus 
  the mysql database. I want that this user can run the select instruction 
  just into one database, so I did this:
  
  [prompt]$ mysql u root p
  Welcome to the MySQL monitor.  Commands end with ; or \g.
  Your MySQL connection id is 3147 to server version: 4.0.18-standard
  
  Type 'help;' or '\h' for help. Type '\c' to clear the buffer.
  
  mysql USE mysql;
  Reading table information for completion of table and column names
  You can turn off this feature to get a quicker startup with -A
  
  Database changed
  INSERT INTO user (Host, User, Password, Select_priv) VALUES ('%', 
  'myuser', password('hispassword'), 'Y');
  mysql GRANT ALL ON database2.* TO myuser;
  mysql FLUSH PRIVILEGES; 
  mysql quit;
  
  
  However, when I log using this new user myuser, I still can see the others 
  database and a can insert, update and delete records into all databases 
  instead of just have the rights to select in the database2. What I did was 
  correct or it is missing something?
  
  Best Regards,
  
  Andre
  
 

Great! Works well now. Thanks Michael!!!

 This is why it's best to use GRANT and REVOKE instead of trying to 
 manually edit the mysql tables.  You gave global select privilege in 
 your insert into user.  The correct (and simpler) way to have done this 
 would have been the one statement
 

I heard about this, but I was following a tutorial. It's clear now that 
the tutorial is not good.


GRANT ALL ON database2.* TO myuser IDENTIFIED BY 'hispassword';
 
 That will create the user entry, if necessary, and grant the specified 
 privileges (ALL on database2.*).  It also handles the FLUSH for you.
 
 There are a couple ways to fix what you have.  I'd suggest
 
REVOKE ALL PRIVILEGES,GRANT OPTION FROM myuser;
GRANT ALL ON database2.* TO myuser;
 
 See http://www.mysql.com/doc/en/GRANT.html for more.
 
 Michael
 

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Client connection error

2004-03-02 Thread Andre MATOS
Hi,

I am trying to connect from one computer that has MySQL installed 
(client) in another one that also has MySQL (server). Using this command:

C:\mysql\binmysql.exe -u root -h server.com -p
Enter password: *
ERROR 2003: Can't connect to MySQL server on 'server.com' (10060)


However I am also using Apache+PHP and it is working withou problem.

Does anyone know what is the problem?

Thanks a lot.

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Join two tables with Select

2004-02-26 Thread Andre MATOS
Hi List,

I need to create a complex Select joining 2 tables.

Table Product, I have these fields:

Code (PK)
Description

Records:
01  Product A
02  Product B


Table Price, I have these fields:

Code (PK/FK)
Sequence (PK)
Price

Records:
01  1   10.00
01  2   12.00
01  3   14.00
01  4   15.00
02  1   20.00
02  2   22.00
03  3   23.00
04  4   24.00

I need to combine these two tables to have this layout:

Product First Price Second PriceThird Price Forth Price
Product A   10.00   12.00   13.00   14.00
Product B   20.00   22.00   23.00   24.00


Is this possible to do if the Select instruction? If yes, is anyone can 
help me to build this Select?

Thanks a lot.


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Database user access

2004-02-15 Thread Andre MATOS
Hi,

Is it possible to allow one user to access MySQL using for example PHP but 
stop him when he tried to access MySQL directly?

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Database user access

2004-02-15 Thread Andre MATOS
Hi,

Is it possible to allow one user to access MySQL using for example PHP but 
stop him when he tried to access MySQL directly?

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Field name length

2004-02-12 Thread Andre MATOS
Hi,

Is there any length limit for the field name or it is not good to define 
a field name like my_field_name_is_this_size_plus_a_little_bit_more ?

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Privileges

2004-02-06 Thread Andre MATOS
Hi List,

Is it possible to GRANT an USER to just UPDATE one specific FIELD instead 
of the entire TABLE? 

Is it also possible to create a GROUP with all GRANTs and then create the 
USERs linked with a specific GROUP?

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Record only readable

2004-01-29 Thread Andre MATOS
Hi List,

Is anybody knows how to lock (make just readable) a field from a record or 
the whole record?

This is the idea: I need to create a table that some people will insert 
records. One person will access a record to validate the values 
inserted into it. Once a field was validated, nobody else can change the 
value again. The people can still look it, but just look.

If it is not possible to make readable the fields, is it possible the 
whole record?
 
Is this possible to do in MySQL? If it is, how can I do it and which 
version of MySQL should I use?

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