[Vo]:Over unity at MIT

2012-02-28 Thread Jones Beene
Did you ever think you would hear MIT bragging about overunity?
Thermoelectrically Pumped Light-Emitting Diodes Operating
above Unity Efficiency
http://link.aps.org/doi/10.1103/PhysRevLett.108.097403 
Parthiban Santhanam, Dodd Joseph Gray, Jr., and Rajeev J.
Ram
Phys. Rev. Lett. 108, 097403 (2012)
http://link.aps.org/doi/10.1103/PhysRevLett.108.097403  Published February
27, 2012

Physicists have known for decades that, in principle, a
semiconductor device can emit more light power than it consumes
electrically. Experiments published in Physical Review Letters finally
demonstrate this in practice, though at a small scale.

It is clear that the Joule thief and Joule ringer experiments that
pepper the internet can produce more light from LEDs than should be
available from the electrical input. The best I have seen is 50 uwatts going
in to light an LED (that's micro- not milli-). This is 1000 times lower than
the DC rating.

If you have been around Vortex for a while you may remember 5-6 years ago
there was a vocal proponent of using Silicon chip-making equipment
(microlithography) to fabricate a dedicated ambient-to-electric converter -
the so-called giga-diode TEG array. A interesting fellow named Charles M.
Brown, from Hawaii, was the major proponent of this.

He seems to have faded from view around 2007 but he claimed to have a fab
lined up to produce such an array. His patent goes pack 37 years. In his
last postings, he said this was to be GaAs or GaSb and have several billion
diodes. He was going to enter this device in the Virgin alternative energy
competition and according to this message - he did arrange to have a few
produced. This is an interesting thread but the output is low. Apparently
this is Paul Lowrance's site (former vortician)

http://www.globalfreeenergy.info/2009/06/18/new-diode-setup-plans/

There is old info up on Sterling Allan's site (with Brown's patent
reference), but it seems to have not been updated in a while:

http://peswiki.com/index.php/Directory:Charles_M._Brown%27s_Thermal_Electric
_Chip

Jones


BTW- Lowrance adds, Low leakage *undisturbed* diodes typically produce 0.2
to 0.5 volts DC. Piezos typically produce 1 to 7 volts DC. The key is in not
disturbing the diode. The effect is extremely sensitive. Once disturbed, the
passive component can take weeks to months to recover. 

[why should undisturbed matter? Does making a connection to ZPE require
some kind of local stability?]

The effect has baffled some of the best academic scientists. The unknown
effect appears to be based on E-fields, and nothing to do with diode
rectification. Within the diode is an intense E-field at the junction.
Passive piezo elements have an intense internal E-field. Tests replicated by
numerous academic scientists clearly show that highly shielded (both
electrical and thermal) and undisturbed piezos produce DC voltage, and
current when loaded.

This effect is seen in various types of diodes and piezo elements. Low
leakage components are recommended for best results. Experiments were
conducted in rural areas, under-ground, up to three layers of metal
shielding, in oil baths, up to 2 feet of thermal insulation. Dozens of
different types of meters were used, including 100% passive tests void of
all power  active components.


attachment: winmail.dat

Re: [Vo]:Over unity at MIT

2012-02-28 Thread Daniel Rocha
Pay attention at this:

 Experiments directly confirm for the first time that this behavior
continues beyond the conventional limit of unity electrical-to-optical
power conversion efficiency.

It is above the conventional, not that it produces energy out of nothing.
This is just a way of saying that it exceeded expectation of light emission
for a LED.

2012/2/28 Jones Beene jone...@pacbell.net

 Did you ever think you would hear MIT bragging about overunity?
Thermoelectrically Pumped Light-Emitting Diodes Operating
 above Unity Efficiency
 http://link.aps.org/doi/10.1103/PhysRevLett.108.097403
Parthiban Santhanam, Dodd Joseph Gray, Jr., and Rajeev J.
 Ram
Phys. Rev. Lett. 108, 097403 (2012)
 http://link.aps.org/doi/10.1103/PhysRevLett.108.097403  Published
 February
 27, 2012

Physicists have known for decades that, in principle, a
 semiconductor device can emit more light power than it consumes
 electrically. Experiments published in Physical Review Letters finally
 demonstrate this in practice, though at a small scale.

 It is clear that the Joule thief and Joule ringer experiments that
 pepper the internet can produce more light from LEDs than should be
 available from the electrical input. The best I have seen is 50 uwatts
 going
 in to light an LED (that's micro- not milli-). This is 1000 times lower
 than
 the DC rating.

 If you have been around Vortex for a while you may remember 5-6 years ago
 there was a vocal proponent of using Silicon chip-making equipment
 (microlithography) to fabricate a dedicated ambient-to-electric converter -
 the so-called giga-diode TEG array. A interesting fellow named Charles M.
 Brown, from Hawaii, was the major proponent of this.

 He seems to have faded from view around 2007 but he claimed to have a fab
 lined up to produce such an array. His patent goes pack 37 years. In his
 last postings, he said this was to be GaAs or GaSb and have several billion
 diodes. He was going to enter this device in the Virgin alternative energy
 competition and according to this message - he did arrange to have a few
 produced. This is an interesting thread but the output is low. Apparently
 this is Paul Lowrance's site (former vortician)

 http://www.globalfreeenergy.info/2009/06/18/new-diode-setup-plans/

 There is old info up on Sterling Allan's site (with Brown's patent
 reference), but it seems to have not been updated in a while:


 http://peswiki.com/index.php/Directory:Charles_M._Brown%27s_Thermal_Electric
 _Chip

 Jones


 BTW- Lowrance adds, Low leakage *undisturbed* diodes typically produce 0.2
 to 0.5 volts DC. Piezos typically produce 1 to 7 volts DC. The key is in
 not
 disturbing the diode. The effect is extremely sensitive. Once disturbed,
 the
 passive component can take weeks to months to recover.

 [why should undisturbed matter? Does making a connection to ZPE require
 some kind of local stability?]

 The effect has baffled some of the best academic scientists. The unknown
 effect appears to be based on E-fields, and nothing to do with diode
 rectification. Within the diode is an intense E-field at the junction.
 Passive piezo elements have an intense internal E-field. Tests replicated
 by
 numerous academic scientists clearly show that highly shielded (both
 electrical and thermal) and undisturbed piezos produce DC voltage, and
 current when loaded.

 This effect is seen in various types of diodes and piezo elements. Low
 leakage components are recommended for best results. Experiments were
 conducted in rural areas, under-ground, up to three layers of metal
 shielding, in oil baths, up to 2 feet of thermal insulation. Dozens of
 different types of meters were used, including 100% passive tests void of
 all power  active components.





-- 
Daniel Rocha - RJ
danieldi...@gmail.com


RE: [Vo]:Over unity at MIT

2012-02-28 Thread Jones Beene
From: Daniel Rocha 

Pay attention at this:

 Experiments directly confirm for the first time that this
behavior continues beyond the conventional limit of unity
electrical-to-optical power conversion efficiency.

It is above the conventional, not that it produces energy
out of nothing. This is just a way of saying that it exceeded expectation of
light emission for a LED.

Yes of course - these guys have to protect tenured positions at MIT, so they
would never mention ZPE nor any of the other possibilities that we like to
toss around here ... 

... as Mel Brooks would say we must protect our phony baloney jobs
attachment: winmail.dat

Re: [Vo]:Over unity at MIT

2012-02-28 Thread Harry Veeder
On Tue, Feb 28, 2012 at 11:57 AM, Daniel Rocha danieldi...@gmail.com wrote:
 Pay attention at this:

  Experiments directly confirm for the first time that this behavior
 continues beyond the conventional limit of unity electrical-to-optical power
 conversion efficiency.

 It is above the conventional, not that it produces energy out of nothing.
 This is just a way of saying that it exceeded expectation of light emission
 for a LED.


Yes. It uses electricity to change heat into light. The abstract:

A heated semiconductor light-emitting diode at low forward bias
voltage VkBT/q is shown to use electrical work to pump heat from the
lattice to the photon field. Here the rates of both radiative and
nonradiative recombination have contributions at linear order in V. As
a result the device’s wall-plug (i.e., power conversion) efficiency is
inversely proportional to its output power and diverges as V
approaches zero. Experiments directly confirm for the first time that
this behavior continues beyond the conventional limit of unity
electrical-to-optical power conversion efficiency.


however, wouldn't this require a violation of the second law of thermodynamics?

Harry



Re: [Vo]:Over unity at MIT

2012-02-28 Thread Daniel Rocha
I don't think it is a matter of protecting position because of crazy
claims. What they did was not unusual in the sense that there is no surplus
of energy, but more efficiency then expected.

2012/2/28 Jones Beene jone...@pacbell.net

 From: Daniel Rocha

Pay attention at this:

 Experiments directly confirm for the first time that this
 behavior continues beyond the conventional limit of unity
 electrical-to-optical power conversion efficiency.

It is above the conventional, not that it produces energy
 out of nothing. This is just a way of saying that it exceeded expectation
 of
 light emission for a LED.

 Yes of course - these guys have to protect tenured positions at MIT, so
 they
 would never mention ZPE nor any of the other possibilities that we like to
 toss around here ...

 ... as Mel Brooks would say we must protect our phony baloney jobs




-- 
Daniel Rocha - RJ
danieldi...@gmail.com


Re: [Vo]:Over unity at MIT

2012-02-28 Thread Daniel Rocha
Why do you think it would violate the 2nd law? I don't understand.

2012/2/28 Harry Veeder hveeder...@gmail.com

 On Tue, Feb 28, 2012 at 11:57 AM, Daniel Rocha danieldi...@gmail.com
 wrote:
  Pay attention at this:
 
   Experiments directly confirm for the first time that this behavior
  continues beyond the conventional limit of unity electrical-to-optical
 power
  conversion efficiency.
 
  It is above the conventional, not that it produces energy out of nothing.
  This is just a way of saying that it exceeded expectation of light
 emission
  for a LED.


 Yes. It uses electricity to change heat into light. The abstract:

 A heated semiconductor light-emitting diode at low forward bias
 voltage VkBT/q is shown to use electrical work to pump heat from the
 lattice to the photon field. Here the rates of both radiative and
 nonradiative recombination have contributions at linear order in V. As
 a result the device’s wall-plug (i.e., power conversion) efficiency is
 inversely proportional to its output power and diverges as V
 approaches zero. Experiments directly confirm for the first time that
 this behavior continues beyond the conventional limit of unity
 electrical-to-optical power conversion efficiency.


 however, wouldn't this require a violation of the second law of
 thermodynamics?

 Harry




-- 
Daniel Rocha - RJ
danieldi...@gmail.com


Re: [Vo]:Over unity at MIT

2012-02-28 Thread Harry Veeder
According to the second law you can only get a system to do work  if
parts of the system are at different temperatures. In this situation
the system is a diode and it does work by converting heat into light.
It is hard to tell from the description, but I am guessing the entire
diode is at an  elevated temperature.

harry

On Tue, Feb 28, 2012 at 12:20 PM, Daniel Rocha danieldi...@gmail.com wrote:
 Why do you think it would violate the 2nd law? I don't understand.

 2012/2/28 Harry Veeder hveeder...@gmail.com

 On Tue, Feb 28, 2012 at 11:57 AM, Daniel Rocha danieldi...@gmail.com
 wrote:
  Pay attention at this:
 
   Experiments directly confirm for the first time that this behavior
  continues beyond the conventional limit of unity electrical-to-optical
  power
  conversion efficiency.
 
  It is above the conventional, not that it produces energy out of
  nothing.
  This is just a way of saying that it exceeded expectation of light
  emission
  for a LED.


 Yes. It uses electricity to change heat into light. The abstract:

 A heated semiconductor light-emitting diode at low forward bias
 voltage VkBT/q is shown to use electrical work to pump heat from the
 lattice to the photon field. Here the rates of both radiative and
 nonradiative recombination have contributions at linear order in V. As
 a result the device’s wall-plug (i.e., power conversion) efficiency is
 inversely proportional to its output power and diverges as V
 approaches zero. Experiments directly confirm for the first time that
 this behavior continues beyond the conventional limit of unity
 electrical-to-optical power conversion efficiency.


 however, wouldn't this require a violation of the second law of
 thermodynamics?

 Harry




 --
 Daniel Rocha - RJ
 danieldi...@gmail.com




RE: [Vo]:Over unity at MIT

2012-02-28 Thread Mark Iverson-ZeroPoint
The key wording is here:

 

A heated semiconductor light-emitting diode at low forward bias voltage
VkBT/q is shown to use electrical work 

*to pump heat from the lattice to the photon field.*

 

It is converting *heat* energy to light. not electricity-to-light!!!

 

Thus, as they *lower* the forward bias V,  *electrical* efficiency INCREASES
because it is not using electrical current for operation; as Jones said,
it's the E-field which ALLOWS the HEAT-to-LIGHT conversion.  If the material
is not very conductive, one can have a large E-field with miniscule current
flow. thus, very little ELECTRICAL power use.

 

-Mark

 

From: Daniel Rocha [mailto:danieldi...@gmail.com] 
Sent: Tuesday, February 28, 2012 9:21 AM
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Over unity at MIT

 

Why do you think it would violate the 2nd law? I don't understand.

2012/2/28 Harry Veeder hveeder...@gmail.com

On Tue, Feb 28, 2012 at 11:57 AM, Daniel Rocha danieldi...@gmail.com
wrote:
 Pay attention at this:

  Experiments directly confirm for the first time that this behavior
 continues beyond the conventional limit of unity electrical-to-optical
power
 conversion efficiency.

 It is above the conventional, not that it produces energy out of nothing.
 This is just a way of saying that it exceeded expectation of light
emission
 for a LED.



Yes. It uses electricity to change heat into light. The abstract:

A heated semiconductor light-emitting diode at low forward bias
voltage VkBT/q is shown to use electrical work to pump heat from the
lattice to the photon field. Here the rates of both radiative and
nonradiative recombination have contributions at linear order in V. As
a result the device's wall-plug (i.e., power conversion) efficiency is
inversely proportional to its output power and diverges as V
approaches zero. Experiments directly confirm for the first time that

this behavior continues beyond the conventional limit of unity
electrical-to-optical power conversion efficiency.



however, wouldn't this require a violation of the second law of
thermodynamics?

Harry





 

-- 
Daniel Rocha - RJ

danieldi...@gmail.com

 



Re: [Vo]:Over unity at MIT

2012-02-28 Thread Daniel Rocha
The diode is working as a cooler.

2012/2/28 Harry Veeder hveeder...@gmail.com

 According to the second law you can only get a system to do work  if
 parts of the system are at different temperatures. In this situation
 the system is a diode and it does work by converting heat into light.
 It is hard to tell from the description, but I am guessing the entire
 diode is at an  elevated temperature.

 harry

 On Tue, Feb 28, 2012 at 12:20 PM, Daniel Rocha danieldi...@gmail.com
 wrote:
  Why do you think it would violate the 2nd law? I don't understand.
 
  2012/2/28 Harry Veeder hveeder...@gmail.com
 
  On Tue, Feb 28, 2012 at 11:57 AM, Daniel Rocha danieldi...@gmail.com
  wrote:
   Pay attention at this:
  
Experiments directly confirm for the first time that this behavior
   continues beyond the conventional limit of unity electrical-to-optical
   power
   conversion efficiency.
  
   It is above the conventional, not that it produces energy out of
   nothing.
   This is just a way of saying that it exceeded expectation of light
   emission
   for a LED.
 
 
  Yes. It uses electricity to change heat into light. The abstract:
 
  A heated semiconductor light-emitting diode at low forward bias
  voltage VkBT/q is shown to use electrical work to pump heat from the
  lattice to the photon field. Here the rates of both radiative and
  nonradiative recombination have contributions at linear order in V. As
  a result the device’s wall-plug (i.e., power conversion) efficiency is
  inversely proportional to its output power and diverges as V
  approaches zero. Experiments directly confirm for the first time that
  this behavior continues beyond the conventional limit of unity
  electrical-to-optical power conversion efficiency.
 
 
  however, wouldn't this require a violation of the second law of
  thermodynamics?
 
  Harry
 
 
 
 
  --
  Daniel Rocha - RJ
  danieldi...@gmail.com
 




-- 
Daniel Rocha - RJ
danieldi...@gmail.com


Re: [Vo]:Over unity at MIT

2012-02-28 Thread Harry Veeder
Some months ago I speculated that LENR might one day be used as a heat
source to generate light directly using a thermophotovoltaic effect.
This work suggests it might be feasible. I even mentioned it to Rossi,
on his blog but he just saw it as a means to generate electricty from
the light produced.

Harry

On Tue, Feb 28, 2012 at 12:45 PM, Mark Iverson-ZeroPoint
zeropo...@charter.net wrote:
 The key wording is here:



 A heated semiconductor light-emitting diode at low forward bias voltage
 VkBT/q is shown to use electrical work

 *to pump heat from the lattice to the photon field.*”



 It is converting *heat* energy to light… not electricity-to-light!!!



 Thus, as they *lower* the forward bias V,  *electrical* efficiency INCREASES
 because it is not using electrical current for operation; as Jones said,
 it’s the E-field which ALLOWS the HEAT-to-LIGHT conversion.  If the material
 is not very conductive, one can have a large E-field with miniscule current
 flow… thus, very little ELECTRICAL power use.



 -Mark



 From: Daniel Rocha [mailto:danieldi...@gmail.com]
 Sent: Tuesday, February 28, 2012 9:21 AM
 To: vortex-l@eskimo.com
 Subject: Re: [Vo]:Over unity at MIT



 Why do you think it would violate the 2nd law? I don't understand.

 2012/2/28 Harry Veeder hveeder...@gmail.com

 On Tue, Feb 28, 2012 at 11:57 AM, Daniel Rocha danieldi...@gmail.com
 wrote:
 Pay attention at this:

  Experiments directly confirm for the first time that this behavior
 continues beyond the conventional limit of unity electrical-to-optical
 power
 conversion efficiency.

 It is above the conventional, not that it produces energy out of nothing.
 This is just a way of saying that it exceeded expectation of light
 emission
 for a LED.

 Yes. It uses electricity to change heat into light. The abstract:

 A heated semiconductor light-emitting diode at low forward bias
 voltage VkBT/q is shown to use electrical work to pump heat from the
 lattice to the photon field. Here the rates of both radiative and
 nonradiative recombination have contributions at linear order in V. As
 a result the device’s wall-plug (i.e., power conversion) efficiency is
 inversely proportional to its output power and diverges as V
 approaches zero. Experiments directly confirm for the first time that

 this behavior continues beyond the conventional limit of unity
 electrical-to-optical power conversion efficiency.

 however, wouldn't this require a violation of the second law of
 thermodynamics?

 Harry





 --
 Daniel Rocha - RJ

 danieldi...@gmail.com





Re: [Vo]:Over unity at MIT

2012-02-28 Thread Daniel Rocha
What about heat -electricity - light?

2012/2/28 Mark Iverson-ZeroPoint zeropo...@charter.net

 The key wording is here:

 ** **

 A heated semiconductor light-emitting diode at low forward bias voltage
 VkBT/q is shown to use electrical work 

 **to pump heat from the lattice to the photon field.**”

 ** **

 It is converting **heat** energy to light… not electricity-to-light!!!

 ** **

 Thus, as they **lower** the forward bias V,  **electrical** efficiency
 INCREASES because it is not using electrical current for operation; as
 Jones said, it’s the E-field which ALLOWS the HEAT-to-LIGHT conversion.  If
 the material is not very conductive, one can have a large E-field with
 miniscule current flow… thus, very little ELECTRICAL power use.

 ** **

 -Mark

 ** **

 *From:* Daniel Rocha [mailto:danieldi...@gmail.com]
 *Sent:* Tuesday, February 28, 2012 9:21 AM
 *To:* vortex-l@eskimo.com
 *Subject:* Re: [Vo]:Over unity at MIT

 ** **

 Why do you think it would violate the 2nd law? I don't understand.

 2012/2/28 Harry Veeder hveeder...@gmail.com

 On Tue, Feb 28, 2012 at 11:57 AM, Daniel Rocha danieldi...@gmail.com
 wrote:
  Pay attention at this:
 
   Experiments directly confirm for the first time that this behavior
  continues beyond the conventional limit of unity electrical-to-optical
 power
  conversion efficiency.
 
  It is above the conventional, not that it produces energy out of nothing.
  This is just a way of saying that it exceeded expectation of light
 emission
  for a LED.

 

 Yes. It uses electricity to change heat into light. The abstract:

 A heated semiconductor light-emitting diode at low forward bias
 voltage VkBT/q is shown to use electrical work to pump heat from the
 lattice to the photon field. Here the rates of both radiative and
 nonradiative recombination have contributions at linear order in V. As
 a result the device’s wall-plug (i.e., power conversion) efficiency is
 inversely proportional to its output power and diverges as V
 approaches zero. Experiments directly confirm for the first time that

 this behavior continues beyond the conventional limit of unity
 electrical-to-optical power conversion efficiency.

 

 however, wouldn't this require a violation of the second law of
 thermodynamics?

 Harry



 

 ** **

 --
 Daniel Rocha - RJ

 danieldi...@gmail.com

 ** **




-- 
Daniel Rocha - RJ
danieldi...@gmail.com


RE: [Vo]:Over unity at MIT

2012-02-28 Thread Jones Beene
On the CoE balance sheet - we have light emission, which can be converted
into watts equivalent. 

 

If the electrical input were to be 60% of that value, and the rest is
assumed (correctly) to come from ambient heat, then there is no CoE
violation. This would be ultra high efficiency in the same way that a heat
pump is not OU, but is highly efficient since it removes heat from the
environment. (there are two distinct meanings for COP)

 

But until precise calorimetry proves that there is not a third input (in
addition to electrical and ambient heat) then the door is slightly ajar. 

 

No one is suggesting (yet) that there is an anomaly or a violation. 

 

But if you do not look for it carefully, instead of making assumptions -
then it cannot be found.

 

 

From: Daniel Rocha 

 

Why do you think it would violate the 2nd law? I don't understand.

 

 



Re: [Vo]:Over unity at MIT

2012-02-28 Thread Harry Veeder
If it is a cooler, it appears to violate the first law.
If it is an energy converter, it appears to violate the second law.

I guess the question is: what is it?



Harry

On Tue, Feb 28, 2012 at 12:58 PM, Daniel Rocha danieldi...@gmail.com wrote:
 The diode is working as a cooler.

 2012/2/28 Harry Veeder hveeder...@gmail.com

 According to the second law you can only get a system to do work  if
 parts of the system are at different temperatures. In this situation
 the system is a diode and it does work by converting heat into light.
 It is hard to tell from the description, but I am guessing the entire
 diode is at an  elevated temperature.

 harry

 On Tue, Feb 28, 2012 at 12:20 PM, Daniel Rocha danieldi...@gmail.com
 wrote:
  Why do you think it would violate the 2nd law? I don't understand.
 
  2012/2/28 Harry Veeder hveeder...@gmail.com
 
  On Tue, Feb 28, 2012 at 11:57 AM, Daniel Rocha danieldi...@gmail.com
  wrote:
   Pay attention at this:
  
Experiments directly confirm for the first time that this behavior
   continues beyond the conventional limit of unity
   electrical-to-optical
   power
   conversion efficiency.
  
   It is above the conventional, not that it produces energy out of
   nothing.
   This is just a way of saying that it exceeded expectation of light
   emission
   for a LED.
 
 
  Yes. It uses electricity to change heat into light. The abstract:
 
  A heated semiconductor light-emitting diode at low forward bias
  voltage VkBT/q is shown to use electrical work to pump heat from the
  lattice to the photon field. Here the rates of both radiative and
  nonradiative recombination have contributions at linear order in V. As
  a result the device’s wall-plug (i.e., power conversion) efficiency is
  inversely proportional to its output power and diverges as V
  approaches zero. Experiments directly confirm for the first time that
  this behavior continues beyond the conventional limit of unity
  electrical-to-optical power conversion efficiency.
 
 
  however, wouldn't this require a violation of the second law of
  thermodynamics?
 
  Harry
 
 
 
 
  --
  Daniel Rocha - RJ
  danieldi...@gmail.com
 




 --
 Daniel Rocha - RJ
 danieldi...@gmail.com




Re: [Vo]:Over unity at MIT

2012-02-28 Thread Nigel Dyer
The paper says that it is working at a temperature of 135 C, which is 
relatively elevated.


I agree that this does violate the second law, in that it is doing work 
but there is not a heat source and sink.  However, as my son, who knows 
more about physics than I do says, the second law is not so much a law, 
merely a guideline.  There are a number of situations where it does not 
hold, so we can add this to the list.


One Achilles heal of the second law would appear to be pumped Bose 
condensates such as lasers, so it is no great surprise to find an 
example here.


However, we only get over unity at less than 10E-10 watts, so its 
practical application at this point is somewhat limited.But maybe 
with a little more research


Nigel

On 28/02/2012 17:38, Harry Veeder wrote:

According to the second law you can only get a system to do work  if
parts of the system are at different temperatures. In this situation
the system is a diode and it does work by converting heat into light.
It is hard to tell from the description, but I am guessing the entire
diode is at an  elevated temperature.

harry

On Tue, Feb 28, 2012 at 12:20 PM, Daniel Rochadanieldi...@gmail.com  wrote:

Why do you think it would violate the 2nd law? I don't understand.

2012/2/28 Harry Veederhveeder...@gmail.com

however, wouldn't this require a violation of the second law of
thermodynamics?

Harry




--
Daniel Rocha - RJ
danieldi...@gmail.com







Re: [Vo]:Over unity at MIT

2012-02-28 Thread Daniel Rocha
That's right. The 2nd law is not valid for very simple systems or open
systems, which is the case above.

2012/2/28 Nigel Dyer l...@thedyers.org.uk

 The paper says that it is working at a temperature of 135 C, which is
 relatively elevated.

 I agree that this does violate the second law, in that it is doing work
 but there is not a heat source and sink.  However, as my son, who knows
 more about physics than I do says, the second law is not so much a law,
 merely a guideline.  There are a number of situations where it does not
 hold, so we can add this to the list.

 One Achilles heal of the second law would appear to be pumped Bose
 condensates such as lasers, so it is no great surprise to find an example
 here.

 However, we only get over unity at less than 10E-10 watts, so its
 practical application at this point is somewhat limited.But maybe with
 a little more research

 Nigel


 On 28/02/2012 17:38, Harry Veeder wrote:

 According to the second law you can only get a system to do work  if
 parts of the system are at different temperatures. In this situation
 the system is a diode and it does work by converting heat into light.
 It is hard to tell from the description, but I am guessing the entire
 diode is at an  elevated temperature.

 harry

 On Tue, Feb 28, 2012 at 12:20 PM, Daniel Rochadanieldi...@gmail.com
  wrote:

 Why do you think it would violate the 2nd law? I don't understand.

 2012/2/28 Harry Veederhveeder...@gmail.com

 however, wouldn't this require a violation of the second law of
 thermodynamics?

 Harry



 --
 Daniel Rocha - RJ
 danieldi...@gmail.com






-- 
Daniel Rocha - RJ
danieldi...@gmail.com


Re: [Vo]:Over unity at MIT

2012-02-28 Thread David Roberson

I think that systems have always radiated heat energy by the blackbody method.  
That is one way for a diode to act as a cooler, but this only works if the 
radiated energy is directed toward a cooler region of space.

In one way of looking at it:  All of the electrical energy dissipated by an 
insulated, lone diode in space would be emitted in one form of radiation or the 
other.  Light or infrared, etc. would be emitted in an amount equal to the 
power input.

Perhaps they have found a way to enhance the light part of the spectrum at the 
expense of the heat portion.

Dave



-Original Message-
From: Daniel Rocha danieldi...@gmail.com
To: vortex-l vortex-l@eskimo.com
Sent: Tue, Feb 28, 2012 12:58 pm
Subject: Re: [Vo]:Over unity at MIT


The diode is working as a cooler. 


2012/2/28 Harry Veeder hveeder...@gmail.com

According to the second law you can only get a system to do work  if
parts of the system are at different temperatures. In this situation
the system is a diode and it does work by converting heat into light.
It is hard to tell from the description, but I am guessing the entire
diode is at an  elevated temperature.

harry


On Tue, Feb 28, 2012 at 12:20 PM, Daniel Rocha danieldi...@gmail.com wrote:
 Why do you think it would violate the 2nd law? I don't understand.

 2012/2/28 Harry Veeder hveeder...@gmail.com

 On Tue, Feb 28, 2012 at 11:57 AM, Daniel Rocha danieldi...@gmail.com
 wrote:
  Pay attention at this:
 
   Experiments directly confirm for the first time that this behavior
  continues beyond the conventional limit of unity electrical-to-optical
  power
  conversion efficiency.
 
  It is above the conventional, not that it produces energy out of
  nothing.
  This is just a way of saying that it exceeded expectation of light
  emission
  for a LED.


 Yes. It uses electricity to change heat into light. The abstract:

 A heated semiconductor light-emitting diode at low forward bias
 voltage VkBT/q is shown to use electrical work to pump heat from the
 lattice to the photon field. Here the rates of both radiative and
 nonradiative recombination have contributions at linear order in V. As
 a result the device’s wall-plug (i.e., power conversion) efficiency is
 inversely proportional to its output power and diverges as V
 approaches zero. Experiments directly confirm for the first time that
 this behavior continues beyond the conventional limit of unity
 electrical-to-optical power conversion efficiency.


 however, wouldn't this require a violation of the second law of
 thermodynamics?

 Harry




 --
 Daniel Rocha - RJ
 danieldi...@gmail.com









-- 
Daniel Rocha - RJ
danieldi...@gmail.com





Re: [Vo]:Over unity at MIT

2012-02-28 Thread Terry Blanton
On Tue, Feb 28, 2012 at 11:47 AM, Jones Beene jone...@pacbell.net wrote:

 [why should undisturbed matter? Does making a connection to ZPE require
 some kind of local stability?]

Jones,

Maybe this is somehow related to the Aspden Effect?

http://www.haroldaspden.com/

T



RE: [Vo]:Over unity at MIT

2012-02-28 Thread Jones Beene
Terry - Not sure I follow. Are you saying that virtual inertia comes from
being undisturbed for a time? Please elaborate.


-Original Message-
From: Terry Blanton 

 [why should undisturbed matter? Does making a connection to ZPE require
 some kind of local stability?]

Jones,

Maybe this is somehow related to the Aspden Effect?

http://www.haroldaspden.com/

T





Re: [Vo]:Over unity at MIT

2012-02-28 Thread Terry Blanton
On Tue, Feb 28, 2012 at 7:28 PM, Jones Beene jone...@pacbell.net wrote:
 Terry - Not sure I follow. Are you saying that virtual inertia comes from
 being undisturbed for a time? Please elaborate.

I was thinking of an inverse of the Aspden Effect, ie if the aether is
left undisturbed for some amount of time a sort of energy
precipitant might occur.

After all, if you're not a part of the solution, you're a part of the
precipitant.

groan

Solly.

T



Re: [Vo]:Over unity at MIT

2012-02-28 Thread Harry Veeder
My first statement is only correct if the putative cooler is an active
cooling system. By that I mean it is behaving like the diode
equivalent of a heat pump. A heat pump requires an external input of
energy that is equal to or greater than the heat transferred out of
the system. In this system the input energy is electrical and is less
than the heat energy transferred out of the system so it qualifies as
OU.

OTOH, if it is a passive cooling system, which simply cools by
emitting radiation, it wouldn't qualify as OU.  However, as David
Roberson pointed out this cooling process  differs from how an ideal
black body is suppose to cool.

Harry


On Tue, Feb 28, 2012 at 1:09 PM, Harry Veeder hveeder...@gmail.com wrote:
 If it is a cooler, it appears to violate the first law.
 If it is an energy converter, it appears to violate the second law.

 I guess the question is: what is it?



 Harry



RE: [Vo]:Over unity at MIT

2012-02-28 Thread Mark Iverson-ZeroPoint
PDF was too large, so go get U.S. Patent No. 0119825, McFarland.

-Original Message-
From: Jones Beene [mailto:jone...@pacbell.net] 
Sent: Tuesday, February 28, 2012 4:29 PM
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Over unity at MIT

Terry - Not sure I follow. Are you saying that virtual inertia comes from
being undisturbed for a time? Please elaborate.


-Original Message-
From: Terry Blanton 

 [why should undisturbed matter? Does making a connection to ZPE 
 require some kind of local stability?]

Jones,

Maybe this is somehow related to the Aspden Effect?

http://www.haroldaspden.com/

T