another one could be some sort of hashing logic modulo n. Get request,
create hash , compute modulo n. check assign cache and return. This will
make sure of even distribution but with additional cost of hash computation.
Regards,
Vikash
8121873513
On Sun, Dec 14, 2014 at 5:07 PM,
question unclear ?What is to be minimize ?
in given example:
ca*d*bch
abc
what is role of d ?
On Monday, 6 October 2014 22:52:10 UTC+5:30, Rishav wrote:
Hi everyone,
I was asked this question recently in an interview: Given two strings of
unequal length, you have to pad the smaller
. Then based on the answer, remove any
orders from the list which are not consistent with that answer. Repeat the
process until you have only one order remaining.
Don
On Tuesday, July 1, 2014 12:15:14 PM UTC-4, vikas wrote:
One of my friend posted this question to me and I am unable to get
One of my friend posted this question to me and I am unable to get
anywhere. Could you guys please help
A game of cards has 5 colors and 5 values. Thus a total of 25 cards are
possible. Player 1 will choose n cards and tell you exactly , what all
cards he has. Then he will spread cards in
you should contact Indian Embassy, they will help you out.
On Tuesday, 13 November 2012 15:02:39 UTC+5:30, Virag wrote:
Hello, I hope this e-mail reaches well. Just to let you know that I'm
presently in Spain for an Agricultural Conference but I'm in a serious fix;
I was mugged and lost
values equal
42 except the rightmost node which is 43, these approaches will take a
very long time. Any ideas on how to improve performance in such cases?
Don
On Oct 25, 3:09 am, vikas vikas.rastogi2...@gmail.com wrote:
How about this
Stacktree* st;
CheckSubtree(tree *bigTree
) = numberofElementPresentInArray*sizeof(dataType)
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still there is no improvement, compiler will generate the code to compare
with zero here. what you have accomplished is , hide it from human eyes
On Monday, 1 October 2012 15:25:09 UTC+5:30, Navin Kumar wrote:
@atul:
still it won't compare 0 th element. Slight modification in your code:
not sure what interviewer meant here, does not look like compiler dependent
code,
and BTW, last recurrence yield 5 :) and not 8,
one possible def is, you have a function with no return and compiler
is independent for choosing what to return in this case, just a guess. Not
sure about cpp
There is a set of 9 students and 3 schools Every school can be alloted
atmax 3 students .Every school and student has its coordinates .Now we have
to allot student in such a way that the sum of distance from all the
student to the school should be minimum.
We have to solve this in less than O(n^3)
he is right.
On Tue, Jul 10, 2012 at 3:13 PM, rahul sharma rahul23111...@gmail.comwrote:
yeahu r ryt
On Tue, Jul 10, 2012 at 10:01 AM, Firoz Khursheed
firozkhursh...@gmail.com wrote:
Well, when i compiled the code the output ie i is alway i=2,
http://ideone.com/AFljo
Hi I have one year experience and have interview scheduled on monday.
Pease help me with your experience or knowledge regarding questions,
strategy and
any misc aspect.
Thanks in advance
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Given matrix(screen black n white)..where 1 represents black dot and
0=white.
there can b many images/objects in it..return list of coordinates for each
obkect..(Hint do BFS)
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couldn't understand the question :(
On Apr 19, 1:32 pm, tech coder techcoderonw...@gmail.com wrote:
determine whether the given string is of form pZq.
p and q can contain only X and Y.
like if p=XXYX then z will be XYXX
for ex XXYXXXYXX is valid
the limitation is that you can read only
Hey Arun, IIya,
the GPUs are faster because of
1. designed for graphics processing, which involves a lot of matrix
processing capabilities , simple example transformation of matrices in
to various view (projection, model and viewport , some times needed
even in real time) so these computation
verticalSum( node * root, List * sum)
{
if(root == null) return;
sum-data += root-data;
verticalSum(root-left, sum-left);
verticalSum(root-right, sum-right);
}
1
/ \
2 3
/ \/ \
4 5 6 7
a b c d e
Vsum(1, c) c= 1
Vsum (2,
Graph
take up, right and bottom as nodes connected to current and do find
max path.
On Dec 13, 3:44 pm, Azhar Hussain azhar...@gmail.com wrote:
We have apples arranged in a mxn matrix. We start from the upper left
corner and have to reach bottom right corner with maximum apples. We can
only
parse the document for the words and maintain a position table
position table should be like this:
w1- p1 p2 p3pn
w2-x1 x2 x3 xn
k lists
O(n) if hashing is used
now go to begining of list and findout the maximum position say
'start' O(k)
similarly from end of all list , check for the
wrote:
@vikas will u please elaborate ur answer.
@atul yeah thats true, target will be the words from the dictionary but we
dont have a specific target, here it will be brute force if we check newly
form word with each of the word in dictionary.
On Sat, Nov 26, 2011 at 9:15 PM, atul
this is well known problem, use the BFS traversal / Backtracking
On Nov 26, 3:54 pm, tech coder techcoderonw...@gmail.com wrote:
i think edit distance algorithm can not be used here because in edit
distance problem we have a target string and a source string. Here we dont
have any target word.
allOnes(row, column, len)
so allone(i, 0, k) will check if A[i][0] to A[i][k] has all the ones
similarly another allone should check for all column values.
so algo is if you come across any i, j which is '1' , then check for
sq ending at i-1, j-1 and all the borders , if all are ones, store the
opengl is graphics spec , what hell it has to do with dijkstra ?
On Nov 26, 1:49 pm, naveen ms naveenms...@gmail.com wrote:
hi all
Any one has the OPengl implementation of dijiktras algorithm.or
any idea how to implement it..
With regards
Naveen
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char arr[] = {'a', 'b', 'e', 'f', 'd', 'g', 'h', 'i'};
calculate the point where array is not sorted , in this case arr[4] =
'd'
calulate k in array[5..n] such that k 4 arr[k] d , take the min =
min{ arr[k] }
same thing for max from reverse
use quick /selection sort to identify the correct
that is normal in embedded systems, what you should do is , put the
logs in the particular module, which can be enabled by choice. Another
option is to store the stack traces. using such techniques , you will
be able to find the problem, at least you will be able to reach near
to it.
On Nov 13,
seems like quesion of permutation, it will take all the permutation to
check which one can lead to answer, there will be always be more than
one solution
complexity ((n-1)!)
anyone for better solution ??
On Nov 12, 4:27 pm, surender sanke surend...@gmail.com wrote:
@myself
if number of
nopes , they are not connected, it is just a chance you are getting
the same values and nothing is overwritten there: basically these are
DANGLING POINTERS . Now you should keep practising something like this
#define FREE(N) { free(N); N=NULL;}
to avoid such mistakes
On Nov 11, 3:41 pm, shady
wrote:
Can you explain how a heap helps get the answer? Just to put the
elements in a heap requires O ( N^2 log (N) ) time.
On Nov 7, 4:12 pm, vikas vikas.rastogi2...@gmail.com wrote:
I think the best we can have is nlogn solution with the heap approach.
On Nov 6, 10:27 pm, Dave
I think the best we can have is nlogn solution with the heap approach.
On Nov 6, 10:27 pm, Dave dave_and_da...@juno.com wrote:
@Mohit: Here is a counterexample:
10 11 52 53 54
20 21 112 113 114
30 31 122 123 124
40 41 132
@ Above
no need to have another array or nything
binTreeToBST(node *root)
{
if(!root )return;
node *newRoot;
binTreeToBSTConv(root, newRoot);
}
binTreeToBSTConv(node *old, node *new)
{
if(!old ) return;
binTreeToBSTConv(old-left, new);
, I did not get your idea of reducing complexity , can you describe
it in detail ?
On Nov 4, 8:41 am, surender sanke surend...@gmail.com wrote:
@vikas
ur algo will search for 1st element of 1d in whole 2d array,
on worst case u'll search it in n^2, then search for all 1d elements
in 2d in O(n
try this:
sq(i, j)= k is maximum sqare possible ending at i, j and has
length k in the matrix iXj
sq(i, j) = k if {sq( i -1, j-1) AllOnes(i,0,
k) AllOnes(0, j, k)}
= 1 if sq(i, j) == 1
= 0 otherwise
On
@Vikas,
I think the brute force here will be combinatorial , you need to
calculate all the combinations of lucky say 4, 7, 47, 74 and then
try to find all of the moves combination which maximize this lucky
array index, may be from last to first, just for little optimization.
A bit tough
byte stuffing
On Nov 2, 2:17 am, SAMMM somnath.nit...@gmail.com wrote:
As we all know that the new and delete operator , they are inherited
and tell call constructor and destructor respectively . Now Suppose I
have One Integer variable for the base class and one more Integer
variable for the
what do you mean by subset of 1D present in the 2D array? is it
something like 3245 , the search may be 3245/ 24/ 45/ all 16
subsets need to be searched?
On Oct 28, 12:02 pm, SAMMM somnath.nit...@gmail.com wrote:
How do u plan to implement it ???
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:-
2d array ::
1 2 3 4 5 6
7 8 9 10 11 12
13 14 15 16 17 18
19 20 21 22 23 24
we hav 1d array as :-- 13 2 21 10 23 12
So the 1d array is a subset of 2d array ...
On 11/1/11, vikas vikas.rastogi2...@gmail.com wrote:
what do you mean by subset of 1D present in the 2D array
There are a number of integer ranges say [ L, R]i denoting left and
right of segment i, lets says we are given K such segments and we
define one operation as move which makes our chosen segment to move
either +1 or -1 so after
move(i, +1) segment i will be [L+1, R+1]. There are some particular
The question was from startup company verego (may be misspelled),
you understood it in correct way.
We are given 'k' number of ranges in the fashion L, R
they are all integers in big ranges , (assume long long for the case)
then we are given move operation defined as
move( i, +1/-1) : so range
for next larger number
check for 1st bit set
x = n~(n-1)
e.g. n = 10100 = 20
n -1 = 10011
x = 10100 01100 = 100
for next larger number check for 1st 0 and set the bit
thus y = ~x
n = y ~(y-1)
x |= n
x = 10101 = 21
y = 01010 = 10
y-1 = 01001 = 9
n = 1010
@Sunny, good catch, k X k approach wont work
lets try to use matrix itself as heap
heapify(int cr, int cc, int Nr, int Nc){
mr = cr; mc = cc;
if(cr+1 Nr)
mr = cr+1 mc = cc;
if(cc + 1 Nc min A[cc+1][cr])
mr = cr; mc = cc+1;
if(A[cr][cc] A[mr][mc]){
swap(A[cr][cc]
@Shiva, not necessarily in upper half
take the transpose of example put by Dave and see by yourself
There are few observations for this question:
1. kth smallest will always lie in first k*k matrix
2. it wont be part of sqrt(k)*sqrt(k) matrix
Thus rest all need to be searched
well , I tried to solve it from Maths
though half way through only :(
N = number required i.e. (10^k -1)/9
given n = 10x + 3
by eq
(10x + 3) * m = N= (10^k - 1)/9
implies
k = 2log 3 + log m + log(10x + 3)
i.e.
k 1 + log n
This gives the lowerbound on minimum number of 1 to be start with,
use All Pair Shortest Path
On Oct 6, 11:11 am, Nitin Nizhawan nitin.nizha...@gmail.com wrote:
hi,
given a tree with N nodes find the node such that its average total
distance from each other node is smallest
i.e. if nodes are labeled 0N-1 then
find i such that [
a simple one is rabit-tortoise method, and using stackless traversal,
facing a lot of corner cases in coding this, can someone check this as
well?
On Sep 27, 6:41 pm, anshu mishra anshumishra6...@gmail.com wrote:
its not o(n) it is O(max height of tree) :P
i have not seen the constraint.
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simple graph question,
graph is given as list , just check the dependancy
On Sep 25, 6:25 pm, siva viknesh sivavikne...@gmail.com wrote:
thanks a lot yogesh...
On Sep 25, 2:23 pm, Yogesh Yadav medu...@gmail.com wrote:
T1-T2-T3-T6
T1-T2-T4-T7
T1-T2-T5-T8
2 Processor:
(T1-T2) ..2
if this is simple BST then only preorder will suffice
On Sep 24, 10:16 pm, wetheart gumnaamsm...@yahoo.com wrote:
You can put the array representation of binary tree directly, with
some obvious modifications ofcourse :)
On Sep 24, 5:38 pm, asdqwe ayushgoel...@gmail.com wrote:
you can put
97!! in whatever sequene rule, it can not print 97.
probably you want to say 27 :))
On Sep 23, 4:59 pm, Kunal Yadav kunalyada...@gmail.com wrote:
+1 dave
Its giving 97 in my compiler.
On Fri, Sep 23, 2011 at 4:22 PM, vishwa vishwavam...@gmail.com wrote:
its 21 .
On Fri,
redbook, free available ebook
On Sep 20, 9:28 pm, punnu punnu.gino...@gmail.com wrote:
please somebody suggest some good tutorial in animation in opengl
using c++..
thanks in advance
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hmm, nice questions, can we create an efficient DS to query the
strings ??
tried using trie but memory prints are very large ( O(n^2) )? :-((
On Sep 18, 12:59 pm, Anup Ghatage ghat...@gmail.com wrote:
For the mentioned scenario, it seems to be the only feasible solution.
On Sun, Sep 18,
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nill xt xt
nill
so you see here water used after 6t time is 2xt + 2*2xt +3*2xt + 2xt =
14 xt or 7 cups
here 4th level too have half cups filled , please correct me if
something is wrong in calculations.
On Sep 12, 3:01 am, Dave dave_and_da...@juno.com wrote:
@Vikas: I think I have it covered
regarding detection of mouth:
detect the face and then,try finding the mouth pattern,
validate that it is mouth indeed
for validation check for eyes, nose at some rational
distance ..
|
---
On Sep 11, 1:11 pm, Anup Ghatage ghat...@gmail.com wrote:
^ Thats correct,
@Dave,
should not rate of filling be considered here ? if you note , the
side cups are filling in half of rate than to rest of cups in row.
On Sep 11, 10:01 am, bharatkumar bagana bagana.bharatku...@gmail.com
wrote:
what is M?
On Sat, Sep 10, 2011 at 8:10 PM, Ishan Aggarwal
DON's solution will work
On Sep 3, 11:28 am, Abhishek Yadav algowithabhis...@gmail.com wrote:
this solution works if parent pointer is given.
1. Start moving up from both the nodes (if two nodes become equal, fine this
is the common ancestor) till you reach the root node and in between count
f(19222)
|
|
f(1922) -11 -2 =-13
|
|
f(192) = -9 -2 = -11
|
|
f(19) = f(1) - 9 = -9
|
|
f(1) = 0
output -9 -11 -13
On Sep 3, 10:29 pm, teja bala pawanjalsa.t...@gmail.com wrote:
Find the output of the following code - plzzz xplain the o/p
int find(int j)
{
if(j1)
{
@ above, a third string is used, s3 which is strlen(s2)+ strlen(s1)
and thus in O(n) space
I guess qs calls out for O(1) space.
besides , if we have O(n) space , this question simply reduces to
finding the number of permutation of string s1+s2
I doubt we can do it in O(1) space, any idea guys
regarding q2:
if we have all the points , I guess we need to move through left
to right and scan the loop
sort this array during scan using Y-distance.
now you have the array which will have probable of max diameter
from end to end and problem reduce to find out if circle can be
Must watch Videos for every Indian
http://www.daijiworld.com/tvdaijiworld/tvhome.asp?category=livetv_id=1767
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oops
On Aug 28, 7:09 pm, Decipher ankurseth...@gmail.com wrote:
@vikas - As i said earlier think in 3D . The correct answer is (sqrt(3) -
1)R/(sqrt(3) + 1) = r
Using 3D coordinate geometry if (R,R,R) and (r,r,r) are the coordinates of
center of large and small sphere . Then , make
yep, I realized the mistake.
thanks for the clarification.
BTW, what approach will be suitable in Bin Tree, extensible to MST .
On Aug 29, 11:49 am, prashant thorat prashantnit...@gmail.com wrote:
@vikas :
you can use recursive approach to draw tree here we go:
6 4 3 5 7 8 11 12
1
lol
On Aug 27, 1:44 am, icy` vipe...@gmail.com wrote:
Other than making little loops and risking the fall on the first trip
down, I dont think the rope question has an answer. NVIDIA just
wanted to see if you were suicidal =D
On Aug 26, 3:36 pm, Piyush Grover
no corner cases .. :D
On Aug 26, 5:43 pm, Vikram Singh singhvikram...@gmail.com wrote:
i m writing just a pseudocode...
// root is the root of tree and node is the node whose
predecessor is to be found
predecessor(root, node)
{
parent=NULL;
if(root==NULL)
return ;
@Dhriti
how about this one
6
4 7
3 5 8
1112
your preorder is
6 4 3 5 7 8 11 12
try reconstruction
@ Sagar, level order can be stored but you need to remember the nulls
always
On Aug 29, 12:06 am, sagar pareek sagarpar...@gmail.com wrote:
level order traversal is best for this case :)
On Sun, Aug 28, 2011 at 11:53 PM, prashant thorat
prashantnit...@gmail.comwrote:
only preorder
think in 2d and I assume that both the sphere are touching each other.
it should be simple 2d maths now :)
On Aug 25, 8:32 pm, rakesh kumar rockey.rav...@gmail.com wrote:
Could you explain the solution for shere problem
On Thu, Aug 25, 2011 at 3:49 PM, vikas vikas.rastogi2...@gmail.com
@ All,
1. build a interval tree using startpoints as the key
2. augment this tree such that each interval contains the number of
ppl arrived, in this case 1.
3. use this tree and traverse , use this check, if start/end of tree
node is inbetween the interval you are searching, person was
5th qs
r = R(3-2sqrt(2))
On Aug 25, 1:56 pm, vikas vikas.rastogi2...@gmail.com wrote:
@ All,
1. build a interval tree using startpoints as the key
2. augment this tree such that each interval contains the number of
ppl arrived, in this case 1.
3. use this tree and traverse , use
yep, trie needs to be built
On Aug 24, 10:49 pm, Ankur Garg ankurga...@gmail.com wrote:
It means when u call that func u get the next word in the document
Regards
Ankur
On Wed, Aug 24, 2011 at 6:59 PM, vikas vikas.rastogi2...@gmail.com wrote:
what do you mean by a function
http://linuxconfig.org/get-started-with-android-application-development-using-linux-and-android-sdk
this link will definitly gonna give you running HELLO ANDROID app on ua
machine.
;)
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email:
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shyguy1
it is O(n) and complex unnecessary
On Aug 24, 3:58 pm, Ankit Minglani ankit.mingl...@gmail.com wrote:
How about this :
We use a divide and conquer approach and since the array is sorted.
We find the middle element and check its value with its immediate left and
right element .. it must match
use this
verticalSum(node *root, List *l)
{
if(root == null) return;
root-n += l-n;
// check for l-left, l-right and if null, allocate and link them
verticalSum(root-left, l-left);
verticalSum(root-right, l-right);
}
On Aug 25, 8:20 pm, Anup Ghatage ghat...@gmail.com wrote:
what do you mean by a function for finding the next word is given ?
On Aug 22, 1:56 am, Ankur Garg ankurga...@gmail.com wrote:
Question-- Given a document containing some words ...and a function
for finding the next word is given .design a code which efficiently
search
the word
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shyguy1...@gmail.com
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I need to know, What's the Recruitment Procedure in college of CA
Technologies.. Any Link, any info.. Plz Provide it ASAP..
Thanks in Advance :)
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On Wed, Aug 24, 2011 at 8:25 PM, praneethn praneeth...@gmail.com wrote:
*max=(ab)*a+(ba)*b;*
Not allowed ;) Read the constraints applied.
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nopes, you need to know where the hell it ends even if this is a
string , it ends with convention of ending 0. in case it is stream ,
we know the data length. in case of array, above mentioned approach
should work. sizeof(arr)/sizeof(arr[0])
if you are given only a pointer and no length, you
It seems Dipankar Algo is appropriate at this point of time.
each time successor and predecessor check needs to be done at each
node and the value need to be updated, This is O(log n) approach
because once we check, we move into particular direction.
On Aug 21, 4:59 pm, rahul aravind
using interval tree/segment tree will solve this in straightforward
fashion
On Aug 22, 12:41 pm, Jagannath Prasad Das jpdasi...@gmail.com wrote:
for the stick prob is the stick length required?
On Mon, Aug 22, 2011 at 12:48 PM, Jagannath Prasad Das
jpdasi...@gmail.comwrote:
i think
why to bother this much...? just count the elements when popping and
output the middle one .
while(!s.empty()){
e= s.pop()
count++
q.enq(e);
}
count = 2;
while(count){
e = q.deq();
s.push(e);
count --;
}
output s.top()
while(!q.empty()){
e = q.deq();
s.push(e);
}
On Aug 22, 4:27 pm, Shravan
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MCA- final year
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Write a program to find the empirical formulae from physical formulae
ex: ch3((oh)2(nh3)2)5
has empirical formulae
c1 h43 o2 n10
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expect the PADDING would be.. try it..!
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bytes
short u :3;
ans=2 bytes
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email:
vikas.singh1...@gmail.com
shyguy1...@gmail.com
http://smrit.wordpress.com
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struct demo
{
char c;
double d;
int s;
};
what wud be the size of struct demo object?
if you get the concept, then try this one... just one student asked this in
other thread :) :)
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Thanks and Regards
VIKAS SINGH
MCA- final year
NIT DURGAPUR
email:
vikas.singh1
continuous execution of your code
struct node
{
char c;
double d;
int s;
};
int main(){
struct node a;
struct node *p;
p=a;
printf(size = %d \t address=%u, sizeof(a), p);
}
I don't know why you said 24 in the thread.. is it compiler dependent ??
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Thanks and Regards
VIKAS
on dev c++.. i m getting correct out put as 24.
when i hav executed ur code on turbo version it shows 11 ,i.e it is doing
no padding at all..
On Sat, Aug 6, 2011 at 7:21 PM, vikas singh shyguy1...@gmail.com wrote:
@sandeep
size = 16 address=3220095484
size = 16 address=3220598412
size
Hi,
To keep pace with the expanding opportunities, we are constantly
looking for “the brightest minds” to join Nagarro at various levels(in
Gurgaon(india) branch). There are various post for experienced and
fresher level guys(asp.net, WPF,Windows,JAVA,FLEX,SHAREPOINT 2010 and
SHAREPOINT 2007).
Hi,
To keep pace with the expanding opportunities, we are constantly
looking for “the brightest minds” to join Nagarro at various levels(in
Gurgaon(india) branch). There are various post for experienced and
fresher level guys(asp.net, WPF,Windows,JAVA,FLEX,SHAREPOINT 2010 and
SHAREPOINT 2007).
correction : ans should be :)
10
\
15
/ \
Q1 - write a generic macro to swap two values (int,float,double,pointers as
well )
Q2 - Implement your own malloc() and free() function
Q3 - Two unsigned ints given a, b you have add these numbers and return
the sum ...Make sure in case of overflow return error.
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Thanks very much for recommending. By the way, Solutions to any problem
posted by anybody, will be available in some or other book. I also knows KR
is a good book.
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very nice link for questions of type Q9.
http://pw1.netcom.com/~tjensen/ptr/ch9x.htm
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These all were asked cumulatively in five interviews, one after another.
Q1 given 2 string A ,B. write a code to find all character of A exists in B
or not?
Q2. A puzzle at http://mathforum.org/library/drmath/view/56756.html
Q3. Find a 8-digit number, where the first figure defines the count
My program for Q4.
// recursively find if a given string is palindrome
bool IsPalindrome(string s, int start, int start2, bool flag)
{
bool flag1 = flag;
if (start = 0 start2 (s.Length))
{
char c1 = s[start];
Sum of all the digits should be 8
But it was not said by the interviewer i think we must print all possible
combinations for the question
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1. write iterative program to find if a binary tree is binary search tree or
not.
2. write iterative program to convert a binary tree into its mirror image.
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for 1 i did implement exactly the same algorithms.
and for 2 i donot know why but at that time i was not able to implement it
iteratively and hense implemented its recursive version only.
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for 2nd part of 1st question, when array has become sorted
for ex: 3 5 10 16 17 35 40 56 67 and num is 33
becomes : 3 5 10 16 16 ..
make array of 17 elements s[0,0,1,2..]
s[16] = 2 means we find a duplicate hense resultu
int m = (num%2==1)?(num/2+1):(num/2)
for (int
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