o go 3D, and the symmetry of our system would allow to
>> use a 2D cylindrical grid (r,z) - with zero flux at z=0 and z=L (and
>> r=0), and either Dirichlet/zero flux at r=R. Looking at the mailing list
>> archive and GitHub, it appears that cylindrical coordinates are at the
hive and GitHub, it appears that cylindrical coordinates are at the
> moment not working properly (missing factor)
Yes, that's correct. Sorry about that.
> Is this still the case?
>
> If so, I will start with a simple 3D Cartesian mesh, and then perhaps
> move to more adapted m
conditions).
Now I would like to go 3D, and the symmetry of our system would allow to
use a 2D cylindrical grid (r,z) - with zero flux at z=0 and z=L (and
r=0), and either Dirichlet/zero flux at r=R. Looking at the mailing list
archive and GitHub, it appears that cylindrical coordinates are at the
recipients of list
Betreff: Re: Gradient in cylindrical coordinates
Also, note that the "leastSquaresGrad" doesn't have this issue:
https://gist.github.com/wd15/fc34ccb2e57602fc6f9bea96d8160f4a#file-untitled-ipynb
See,
https://www.ctcms.nist.gov/fipy/fipy/generated/fipy
Leyton -
A compressible flow example contribution would be most welcome! Please submit a
[pull request](https://github.com/usnistgov/fipy/pulls) and we'll work with you
to get it integrated and released.
[don't hesitate to ask if you need help making the pull request]
- Jon
> On Jan 5, 2018,
First of all I would like to thank you for your amazing work! I love working
>> with fipy.
>>
>>
>>
>> I have a problem when I calculate the gradient of my variable in cylindrical
>> coordinates. You can see the code I used below this line.
>>
>>
&g
On Fri, Jan 5, 2018 at 7:23 PM, Munoz Leyton
wrote:
> Dear Fipy Team,
>
>
>
> First of all I would like to thank you for your amazing work! I love working
> with fipy.
>
>
>
> I have a problem when I calculate the gradient of my variable in cylindrical
> coordinates.
Dear Fipy Team,
First of all I would like to thank you for your amazing work! I love working
with fipy.
I have a problem when I calculate the gradient of my variable in cylindrical
coordinates. You can see the code I used below this line.
from fipy import *
from fipy import CellVariable
The "Volume" for a 2D mesh is the area of the cell. The "Volume" for a
1D mesh isthe length of the cell.
>
> The CylindricalGrid2D represents a wedge that subtends 1 rad.
>
Ah, I see now. Thank you for the clarification!
For what I want to do, I have actually found that the following few
On Jun 20, 2012, at 11:20 AM, Kendall Boniface wrote:
> I'm a bit confused about the getCellVolumes() function. Since I am using the
> 2D cylindrical grid, I assume it isn't actually giving me "volumes" so to
> speak. I've manually played around with some of my numbers and can't seem to
> figu
On Tue, Jun 19, 2012 at 1:04 PM, Jonathan Guyer wrote:
>
> On Jun 19, 2012, at 12:20 PM, Kendall Boniface wrote:
>
> > I am having a bit of trouble manipulating a 2D cylindrical mesh and was
> wondering if anyone has any helpful advice?
>
>
> > mesh = CylindricalGrid2D(dx=dx, dy=dy, nx=nx, ny=ny)
On Jun 19, 2012, at 12:20 PM, Kendall Boniface wrote:
> I am having a bit of trouble manipulating a 2D cylindrical mesh and was
> wondering if anyone has any helpful advice?
> mesh = CylindricalGrid2D(dx=dx, dy=dy, nx=nx, ny=ny) + ((0.0046,),)
> print mesh.getCellCenters()
>
> I want the z a
Hello again,
I am having a bit of trouble manipulating a 2D cylindrical mesh and was
wondering if anyone has any helpful advice?
I want a mesh that is 1.5 meters in the z direction and has an inner radius
of 0.0046 m and an outer radius of 0.00635 m (to model the wall of a pipe).
This is what I h
On Tue, Jun 5, 2012 at 1:08 PM, Kendall Boniface
wrote:
>
> Hi Daniel,
> I have set the edge lengths to 1 and placed the gmsh commands in a .geo file
> as you suggested. I've attached the .geo file to this message. I also
> removed the 4 lines and the last line of the gmsh commands as I think they
> I pasted the gmsh commands into a file and ran gmsh on it. It threw a
> weird error
>
> ** On entry to DGESVD parameter number 6 had an illegal value
>
> What error did you get? Did you adapt the gmsh commands from
> somewhere? Maybe we could work from that and check that those commands
> work
On Mon, Jun 4, 2012 at 2:01 PM, Kendall Boniface
wrote:
> I have tried to set up a 3D mesh using Gmsh, but have not been very
> successful. Could anyone offer some insight as to how I can set this up
> successfully?
I pasted the gmsh commands into a file and ran gmsh on it. It threw a
weird erro
conductivity of that material changes as a function of the
temperature. My previous post was just looking at a simple 1D problem (just
straight conduction through a slab of the material). Now I would like to
look at it in 3D cylindrical coordinates. We have an insulated 1.5m long
pipe with an inner and
On Jan 19, 2007, at 10:51 PM, Matt Koch wrote:
Rejected message: sent to fipy@nist.gov by [EMAIL PROTECTED] follows.
Reason for rejection: sender not subscribed.
---
Hi Jonathan,
I have to deal with both a cylinder
, if I am not too mistaken, I
might as well view this like modelling a slice of pie in cartesian
(rectangular) 3D space, and applying zero flux, etc., boundary
conditions to the two flanks (planes of constant theta) of the slice?
Exactly.
We really are talking about a 3D model then. No need
theta) of the slice?
Exactly.
We really are talking about a 3D model then. No need to talk about
cylindrical coordinates then, simply model an arbitrary shape (such
as a cylinder) in rectangular 3D space?
Not exactly. The slice of pie will only be one cell deep. It's only a
sliver o
are talking
about a 3D model then. No need to talk about cylindrical coordinates
then, simply model an arbitrary shape (such as a cylinder) in
rectangular 3D space? The question then is, how well will a mesh
approximate curved surfaces? Plus, no matter how thin the slice in 3D, a
computational
; in this case, I'm going to attempt to clarify (but will
probably fail miserably).
Let's take our cylindrical coordinates to be
r: radial distance from axis of cylinder
theta: azimuthal angle around axis of cylinder
z: distance along length of cylinder
It is
ell?
No. 2D mesh objects are really 2D. The reason you would have to do it
in the case of cylindrical coordinates
it to avoid making changes to the discretization of the equations. I
believe (needs to be confirmed) that changing the
cell volumes and face areas does in fact allow you to use c
eems to speak to the subject, but it is a little too advanced for me.
This exchange discusses wedge shaped meshes that are a requirement for
faking cylindrical coordinates using
Cartesian discretization. If you want to solve a 2D cylindrical
problem, you need to create a 3D wedge shaped mesh.
Th
it is a little too advanced
for me.
This exchange discusses wedge shaped meshes that are a requirement
for faking cylindrical coordinates using
Cartesian discretization. If you want to solve a 2D cylindrical
problem, you need to create a 3D wedge shaped mesh.
This may be possible in gmsh and
order to switch on
cylindrical coordinates? From the above entry, I am almost guessing that
one would have to implement their own divergences and such in
cylindrical coordinates by adding the radius in proper places of the
divergences and such in rectangular coordinates? That can't be
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