On Tue, Dec 22, 2015 at 10:25 AM, Bob Higgins <rj.bob.higg...@gmail.com> wrote:
How close would the hydrogen nucleus have to get to the Ni nucleus to > release 6 MeV in Coulombic repulsion? It would be an interesting > calculation. > This is the typical energy of a particle that is expelled from a nucleus. That suggests that the hydrogen anion would have to attain nuclear separations, e.g., ~ 1 fm. In order to attain that kind of potential energy, energy must be fed into the system in the form of kinetic energy. The screening in the anion might decrease things a little, but since it is 360 degrees around the proton and a small solid angle is subtended by the path between the anion and the Ni nucleus, I don't think you'd get anywhere close to -2e worth. Eric
