That is the idea. However, why would only a few hydrons fuse leaving
just enough unreacted hydrons available to carry all the energy
without it producing energetic radiation? I would expect occasionally,
many hydrons would fuse leaving too few unreacted hydrons so that the
dissipated energy would have to be very energetic and easily
detected. Also, how is this mass-energy coupled to the unreacted
hydrons? The BEC is not stable at high temperatures, which would be
present inside the BEC when mass-energy was released. I would expect
this release would destroy the BEC, leaving the fused hydrons to
dissipate energy by the normal hot fusion method. The concept appears
to have many logical flaws.
Ed Storms
On May 27, 2013, at 10:08 AM, Kevin O'Malley wrote:
Then is that an explanation of why Gamma rays are not observed in
LENR? If 2 of the atoms inside a multi-atom BEC fuse together, the
incoming radiation (to the rest of the BEC) gets subdivided based
upon how many atoms have formed the BEC. Right?
On Mon, May 27, 2013 at 12:49 AM, Axil Axil <janap...@gmail.com>
wrote:
This paper verifies that a photon eradiated Bose-Einstein condensate
will cut the frequency of incoming photons by dividing that
frequency between N numbers of atoms.
http://arxiv.org/pdf/1203.1261v1.pdf
Rydberg excitation of a Bose-Einstein condensate
“The results of theoretical simulations are represented by the
continuous lines.
According to the super-atom picture the collective Rabi frequency
for the coherent excitation of N atoms is
frequency (collective) = square root(number of atoms) X
frequency(single);
Where the single-particle Rabi frequency (single) is app 2 pi x 200
kHz for our experimental parameters.”
