On Mon, May 27, 2013 at 10:03 AM, Edmund Storms <stor...@ix.netcom.com>wrote:
> That is the idea. However, why would only a few hydrons fuse leaving just > enough unreacted hydrons available to carry all the energy without it > producing energetic radiation? I would expect occasionally, many hydrons > would fuse leaving too few unreacted hydrons so that the dissipated energy > would have to be very energetic and easily detected > ***That would account for the very occasional neutron being observed, right? And it also would account for how few of them get observed as well. They only happen when a multiple-fusion event takes place inside the BEC and there isn't enough BEC infrastructure to absorb the energy. > . Also, how is this mass-energy coupled to the unreacted hydrons? The BEC > is not stable at high temperatures, which would be present inside the BEC > when mass-energy was released. I would expect this release would destroy > the BEC, leaving the fused hydrons to dissipate energy by the normal hot > fusion method. > ***I would expect it as well. Like an explosion taking place inside a house, the structure blocks much of the energy while it is momentarily in place. And then another BEC forms, 2 atoms fuse, and the reaction goes on & on. > The concept appears to have many logical flaws. > > Ed Storms > > On May 27, 2013, at 10:08 AM, Kevin O'Malley wrote: > > Then is that an explanation of why Gamma rays are not observed in LENR? > If 2 of the atoms inside a multi-atom BEC fuse together, the incoming > radiation (to the rest of the BEC) gets subdivided based upon how many > atoms have formed the BEC. Right? > > > On Mon, May 27, 2013 at 12:49 AM, Axil Axil <janap...@gmail.com> wrote: > >> This paper verifies that a photon eradiated Bose-Einstein condensate >> will cut the frequency of incoming photons by dividing that frequency >> between N numbers of atoms. >> >> >> http://arxiv.org/pdf/1203.1261v1.pdf >> >> >> Rydberg excitation of a Bose-Einstein condensate >> >> >> “The results of theoretical simulations are represented by the >> continuous lines. >> >> >> According to the super-atom picture the collective Rabi frequency for the >> coherent excitation of N atoms is >> >> >> frequency (collective) = square root(number of atoms) X >> frequency(single); >> >> >> Where the single-particle Rabi frequency (single) is app 2 pi x 200 kHz >> for our experimental parameters.” >> > > >
