[algogeeks] Re: Probability Puzzle
I think there is some ambiguity in the question. (All this time you don't know you were tossing a fair coin or not). 1) Does the above statement mean that the thower don't know whether he or she threw a fair coin even after throwing? Or is the thrower not informed beforehand that one of them is not a fair coin? 2) Does the coin count reduce after every throw or should it be put back? 3) Depending on 1) and 2), there will be different answers. On Aug 9, 12:13 am, Maddy madhu.mitha...@gmail.com wrote: I think the answer is 17/80, because as you say the 5 trials are independent.. but the fact that a head turns up in all the 5 trials, give some information about our original probability of choosing the coins. in case we had obtained a tail in the first trial, we can be sure its the fair coin, and so the consecutive trials would become independent.. but since that is not the case, every head is going to increase the chance of choosing the biased coin(initially), and hence affect the probability of the next head.. before the first trial probability of landing a head is 3/5, but once u see the first head, the probability of landing a head on the second trial changes to 4/5*1/4+1/5, and so on..that is, there is a higher probability that we chose a biased coin, rather than the fair coin. hope its clear.. On Aug 7, 11:36 pm, sumit gaur sumitgau...@gmail.com wrote: (3/5) On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not).- Hide quoted text - - Show quoted text - -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
I'm little late but I too got 17/18. On Tue, Aug 16, 2011 at 10:47 PM, Jacob Ridley jridley2...@gmail.comwrote: I think there is some ambiguity in the question. (All this time you don't know you were tossing a fair coin or not). 1) Does the above statement mean that the thower don't know whether he or she threw a fair coin even after throwing? Or is the thrower not informed beforehand that one of them is not a fair coin? 2) Does the coin count reduce after every throw or should it be put back? 3) Depending on 1) and 2), there will be different answers. On Aug 9, 12:13 am, Maddy madhu.mitha...@gmail.com wrote: I think the answer is 17/80, because as you say the 5 trials are independent.. but the fact that a head turns up in all the 5 trials, give some information about our original probability of choosing the coins. in case we had obtained a tail in the first trial, we can be sure its the fair coin, and so the consecutive trials would become independent.. but since that is not the case, every head is going to increase the chance of choosing the biased coin(initially), and hence affect the probability of the next head.. before the first trial probability of landing a head is 3/5, but once u see the first head, the probability of landing a head on the second trial changes to 4/5*1/4+1/5, and so on..that is, there is a higher probability that we chose a biased coin, rather than the fair coin. hope its clear.. On Aug 7, 11:36 pm, sumit gaur sumitgau...@gmail.com wrote: (3/5) On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not).- Hide quoted text - - Show quoted text - -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- regards, chinna. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
A=p(biased coin/5 heads)=8/9 probability that the coin is biased given 5 heads (bayes theorem) B=p(unbiased coin/5 heads)=1/9 P(6th head)=A*1+B*1/2=17/18 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
@dave: yes it seems so that 17/18 is correct...I deduced it from the cond prob formula.. I have a minor doubt in general why prob( 2nd toss is a head given that a head occurred in the first toss ) doesnt seem same as p( head in first toss and head in second toss with fair coin) +p(head in first toss and head in second toss with unfair coin)? is it due to the fact that we are not looking at the same sample space in both cases?i am not able to visualise the difference in general..this is also the reason why most of the people said earlier 17/80 as the answer moreover, if the question was exactly the same except in that it was NOT mentioned that heads occurred previously , what would the prob of getting a head in the second toss? would it be P( of getting tail in first toss and head in second toss given that fair coin is chosen) +P( of getting head in first toss and head in second toss given that fair coin is chosen) +P( getting heads in first toss and heads in second toss given that unfair coin is chosen) ? this for any toss turns out to be 3/5 can u explain the logic abt why it always gives 3/5? On Tue, Aug 9, 2011 at 7:37 AM, raj kumar megamonste...@gmail.com wrote: plz reply am i right or wrong -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- People often say that motivation doesn't last. Well, neither does bathing - that's why we recommend it daily. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
it is (1/5)/( (4/5 *(1/2)^6) + (1/5 * 1)) = 80/85 = 16/17 On Aug 7, 10:54 pm, Nitish Garg nitishgarg1...@gmail.com wrote: Should be (4/5 *(1/2)^6) + (1/5 * 1) = 17/80 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
go through the posts before posting anything :) On Tue, Aug 9, 2011 at 6:29 PM, arpit.gupta arpitg1...@gmail.com wrote: it is (1/5)/( (4/5 *(1/2)^6) + (1/5 * 1)) = 80/85 = 16/17 On Aug 7, 10:54 pm, Nitish Garg nitishgarg1...@gmail.com wrote: Should be (4/5 *(1/2)^6) + (1/5 * 1) = 17/80 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
ans is 16/17 + 1/2*1/17 = 33/34 On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
@Arpit: No. The probability of getting 6 consecutive heads is 1/5 * 1 + 4/5 * (1/2)^6 ) = 17/80, while the probability of getting 5 consecutive heads is 1/5 * 1 + 4/5 * (1/2)^6 ) = 9/40. Thus, the probability of getting a head on the sixth roll given that you have gotten heads on all five previous rolls is (17/80) / (9/40), which is 17/18. Dave On Aug 9, 7:59 am, arpit.gupta arpitg1...@gmail.com wrote: it is (1/5)/( (4/5 *(1/2)^6) + (1/5 * 1)) = 80/85 = 16/17 On Aug 7, 10:54 pm, Nitish Garg nitishgarg1...@gmail.com wrote: Should be (4/5 *(1/2)^6) + (1/5 * 1) = 17/80 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
@Arun: The probability of getting a head on the first toss is 1/5 * 1 + 4/5 * (1/2) ) = 3/5, while the probability of getting 2 consecutive heads is 1/5 * 1 + 4/5 * (1/2)^2 ) = 2/5. Thus, the probability of getting a head on the second roll given that you have gotten a head on the first roll is (2/5) / (3/5), which is 2/3. If you didn't know the outcome of the first roll, the probability of heads on the second roll would still be 3/5. Dave On Aug 9, 2:57 am, Arun Vishwanathan aaron.nar...@gmail.com wrote: @dave: yes it seems so that 17/18 is correct...I deduced it from the cond prob formula.. I have a minor doubt in general why prob( 2nd toss is a head given that a head occurred in the first toss ) doesnt seem same as p( head in first toss and head in second toss with fair coin) +p(head in first toss and head in second toss with unfair coin)? is it due to the fact that we are not looking at the same sample space in both cases?i am not able to visualise the difference in general..this is also the reason why most of the people said earlier 17/80 as the answer moreover, if the question was exactly the same except in that it was NOT mentioned that heads occurred previously , what would the prob of getting a head in the second toss? would it be P( of getting tail in first toss and head in second toss given that fair coin is chosen) +P( of getting head in first toss and head in second toss given that fair coin is chosen) +P( getting heads in first toss and heads in second toss given that unfair coin is chosen) ? this for any toss turns out to be 3/5 can u explain the logic abt why it always gives 3/5? On Tue, Aug 9, 2011 at 7:37 AM, raj kumar megamonste...@gmail.com wrote: plz reply am i right or wrong -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- People often say that motivation doesn't last. Well, neither does bathing - that's why we recommend it daily. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
@dave- calculation mistake on my part - method is right. getting 17/18 only thanks anyways. On Aug 9, 6:26 pm, Dave dave_and_da...@juno.com wrote: @Arun: The probability of getting a head on the first toss is 1/5 * 1 + 4/5 * (1/2) ) = 3/5, while the probability of getting 2 consecutive heads is 1/5 * 1 + 4/5 * (1/2)^2 ) = 2/5. Thus, the probability of getting a head on the second roll given that you have gotten a head on the first roll is (2/5) / (3/5), which is 2/3. If you didn't know the outcome of the first roll, the probability of heads on the second roll would still be 3/5. Dave On Aug 9, 2:57 am, Arun Vishwanathan aaron.nar...@gmail.com wrote: @dave: yes it seems so that 17/18 is correct...I deduced it from the cond prob formula.. I have a minor doubt in general why prob( 2nd toss is a head given that a head occurred in the first toss ) doesnt seem same as p( head in first toss and head in second toss with fair coin) +p(head in first toss and head in second toss with unfair coin)? is it due to the fact that we are not looking at the same sample space in both cases?i am not able to visualise the difference in general..this is also the reason why most of the people said earlier 17/80 as the answer moreover, if the question was exactly the same except in that it was NOT mentioned that heads occurred previously , what would the prob of getting a head in the second toss? would it be P( of getting tail in first toss and head in second toss given that fair coin is chosen) +P( of getting head in first toss and head in second toss given that fair coin is chosen) +P( getting heads in first toss and heads in second toss given that unfair coin is chosen) ? this for any toss turns out to be 3/5 can u explain the logic abt why it always gives 3/5? On Tue, Aug 9, 2011 at 7:37 AM, raj kumar megamonste...@gmail.com wrote: plz reply am i right or wrong -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- People often say that motivation doesn't last. Well, neither does bathing - that's why we recommend it daily. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
The probability of getting n consecutive heads is P(n heads) = 1/5 * 1 + 4/5 * (1/2)^n, Thus, the probability of getting a head on the n+1st roll given that you have gotten heads on all n previous rolls is P(n+1 heads | n heads) = P(n+1) / P(n) = ( 1/5 * 1 + 4/5 * (1/2)^(n+1) ) / ( 1/5 * 1 + 4/5 * (1/2)^n ). Multiplying numerator and denominator by 5* 2^(n-1) and recognizing 4 as 2^2 gives P(n+1 heads | n heads) = (2^(n-1) + 1) / (2^(n-1) + 2). Dave On Aug 9, 12:30 am, programming love love.for.programm...@gmail.com wrote: @Dave: I guess 17/18 is correct. Since we have to *calculate the probability of getting a head in the 6th flip given that first 5 flips are a head*. Can you please explain how you got the values of consequent flips when you said this? *In fact, the probability is 3/5 for the first flip. After a head is flipped, the probability of a head is 2/3. After two heads have been flipped, it is 3/4. After 3 heads, it is 5/6. After 4 heads, the probability is 9/10, and after 5 heads, the probability is 17/18.* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
@dave - method is right, calculation mistake on my part, getting 17/18 only. thanks anyways. On Aug 9, 6:26 pm, Dave dave_and_da...@juno.com wrote: @Arun: The probability of getting a head on the first toss is 1/5 * 1 + 4/5 * (1/2) ) = 3/5, while the probability of getting 2 consecutive heads is 1/5 * 1 + 4/5 * (1/2)^2 ) = 2/5. Thus, the probability of getting a head on the second roll given that you have gotten a head on the first roll is (2/5) / (3/5), which is 2/3. If you didn't know the outcome of the first roll, the probability of heads on the second roll would still be 3/5. Dave On Aug 9, 2:57 am, Arun Vishwanathan aaron.nar...@gmail.com wrote: @dave: yes it seems so that 17/18 is correct...I deduced it from the cond prob formula.. I have a minor doubt in general why prob( 2nd toss is a head given that a head occurred in the first toss ) doesnt seem same as p( head in first toss and head in second toss with fair coin) +p(head in first toss and head in second toss with unfair coin)? is it due to the fact that we are not looking at the same sample space in both cases?i am not able to visualise the difference in general..this is also the reason why most of the people said earlier 17/80 as the answer moreover, if the question was exactly the same except in that it was NOT mentioned that heads occurred previously , what would the prob of getting a head in the second toss? would it be P( of getting tail in first toss and head in second toss given that fair coin is chosen) +P( of getting head in first toss and head in second toss given that fair coin is chosen) +P( getting heads in first toss and heads in second toss given that unfair coin is chosen) ? this for any toss turns out to be 3/5 can u explain the logic abt why it always gives 3/5? On Tue, Aug 9, 2011 at 7:37 AM, raj kumar megamonste...@gmail.com wrote: plz reply am i right or wrong -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- People often say that motivation doesn't last. Well, neither does bathing - that's why we recommend it daily. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
The statement You randomly pulled one coin from the bag and tossed tells that all the events of tossing the coin are independent hence ans is 3/5 On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
@Dave: Thanks for the explanation :) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
@Ritu: We are flipping one coin five times. Are you saying that you don't learn anything about the coin by flipping it? Would you learn something if any one of the five flips turned up tails? After a tails, would you say that the probability of a subsequent head is still 3/5? Dave On Aug 9, 11:19 am, ritu ritugarg.c...@gmail.com wrote: The statement You randomly pulled one coin from the bag and tossed tells that all the events of tossing the coin are independent hence ans is 3/5 On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
@dave: thank you.. nice explanation :) On Wed, Aug 10, 2011 at 3:24 AM, Dave dave_and_da...@juno.com wrote: @Ritu: We are flipping one coin five times. Are you saying that you don't learn anything about the coin by flipping it? Would you learn something if any one of the five flips turned up tails? After a tails, would you say that the probability of a subsequent head is still 3/5? Dave On Aug 9, 11:19 am, ritu ritugarg.c...@gmail.com wrote: The statement You randomly pulled one coin from the bag and tossed tells that all the events of tossing the coin are independent hence ans is 3/5 On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
@dave : nice explanationsthank you for pointing out :) On Wed, Aug 10, 2011 at 3:39 AM, Prakash D cegprak...@gmail.com wrote: @dave: thank you.. nice explanation :) On Wed, Aug 10, 2011 at 3:24 AM, Dave dave_and_da...@juno.com wrote: @Ritu: We are flipping one coin five times. Are you saying that you don't learn anything about the coin by flipping it? Would you learn something if any one of the five flips turned up tails? After a tails, would you say that the probability of a subsequent head is still 3/5? Dave On Aug 9, 11:19 am, ritu ritugarg.c...@gmail.com wrote: The statement You randomly pulled one coin from the bag and tossed tells that all the events of tossing the coin are independent hence ans is 3/5 On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards, Shachindra A C -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
(3/5) On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
@brijesh *first five times* is mentioned intentionally to mislead i think. I vote for 3/5. Moreover, 17/80 doesn't make sense also. Plz correct me if I am wrong. On Mon, Aug 8, 2011 at 12:06 PM, sumit gaur sumitgau...@gmail.com wrote: (3/5) On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards, Shachindra A C -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
I think 17/80 is wrong because if you say that while calculating the answer 3/5, you havent included the first 5 cases, then even after including it will only increase the probability of getting the biased coin in hand and thus increasing the overall probability of getting the heads and 17/80 is a way lesser than 3/5 although i am not sure about 3/5 even coz of the reasoning i just gave also, when you are calculating 4/5*1/2^6 you are not getting any benefit out of the first five tosses, like, they must have gave you some positive response towards that yes, you will get the head even next time, but doing this you are actually decreasing the probability as compared to the one you could have get without those 5 cases On Mon, Aug 8, 2011 at 1:06 PM, Shachindra A C sachindr...@gmail.comwrote: @brijesh *first five times* is mentioned intentionally to mislead i think. I vote for 3/5. Moreover, 17/80 doesn't make sense also. Plz correct me if I am wrong. On Mon, Aug 8, 2011 at 12:06 PM, sumit gaur sumitgau...@gmail.com wrote: (3/5) On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards, Shachindra A C -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- --- Puneet Goyal Student of B. Tech. III Year (Software Engineering) Delhi Technological University, Delhi --- -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
I think the answer is 17/80, because as you say the 5 trials are independent.. but the fact that a head turns up in all the 5 trials, give some information about our original probability of choosing the coins. in case we had obtained a tail in the first trial, we can be sure its the fair coin, and so the consecutive trials would become independent.. but since that is not the case, every head is going to increase the chance of choosing the biased coin(initially), and hence affect the probability of the next head.. before the first trial probability of landing a head is 3/5, but once u see the first head, the probability of landing a head on the second trial changes to 4/5*1/4+1/5, and so on..that is, there is a higher probability that we chose a biased coin, rather than the fair coin. hope its clear.. On Aug 7, 11:36 pm, sumit gaur sumitgau...@gmail.com wrote: (3/5) On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
The answer is 17 in 18, because flipping 5 heads in a row is evidence that the probability is high that we have the coin with two heads. Don On Aug 7, 12:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
@don: i too get yr answer 17/18 using conditional probability...does that make sense??i guess this is first new answer lol On Mon, Aug 8, 2011 at 9:29 PM, Don dondod...@gmail.com wrote: The answer is 17 in 18, because flipping 5 heads in a row is evidence that the probability is high that we have the coin with two heads. Don On Aug 7, 12:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- People often say that motivation doesn't last. Well, neither does bathing - that's why we recommend it daily. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
Consider the 5 * 64 possible outcomes for the selection of coin and six flips, each one happening with equal probability. Of those 320 possible outcomes, 4*62 are excluded by knowing that the first 5 flips are heads. That leaves 64 outcomes with the rigged coin and 2 outcomes with each of the fair coins, for a total of 72 outcomes. 68 of those are heads, so the answer to the puzzle is 68 of 72, or 17 of 18. Don On Aug 8, 2:36 am, Shachindra A C sachindr...@gmail.com wrote: @brijesh *first five times* is mentioned intentionally to mislead i think. I vote for 3/5. Moreover, 17/80 doesn't make sense also. Plz correct me if I am wrong. On Mon, Aug 8, 2011 at 12:06 PM, sumit gaur sumitgau...@gmail.com wrote: (3/5) On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards, Shachindra A C -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
answer is 3/5. 17/80 is the answer for 6 consecutive heads. On Tue, Aug 9, 2011 at 2:07 AM, Don dondod...@gmail.com wrote: Consider the 5 * 64 possible outcomes for the selection of coin and six flips, each one happening with equal probability. Of those 320 possible outcomes, 4*62 are excluded by knowing that the first 5 flips are heads. That leaves 64 outcomes with the rigged coin and 2 outcomes with each of the fair coins, for a total of 72 outcomes. 68 of those are heads, so the answer to the puzzle is 68 of 72, or 17 of 18. Don On Aug 8, 2:36 am, Shachindra A C sachindr...@gmail.com wrote: @brijesh *first five times* is mentioned intentionally to mislead i think. I vote for 3/5. Moreover, 17/80 doesn't make sense also. Plz correct me if I am wrong. On Mon, Aug 8, 2011 at 12:06 PM, sumit gaur sumitgau...@gmail.com wrote: (3/5) On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards, Shachindra A C -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
@shady: 3/5 can be the answer to such a question: what is prob of getting head on nth toss if we have 4 coins fair and one biased...then at nth toss u choose 4/5 1/5 prob and then u get 3/5 @shady , don: i did this: P( 6th head | 5 heads occured)= P( 6 heads )/ P( 5 heads) answr u get is 17/18..i cud be wrong please correct if so On Mon, Aug 8, 2011 at 10:45 PM, shady sinv...@gmail.com wrote: answer is 3/5. 17/80 is the answer for 6 consecutive heads. On Tue, Aug 9, 2011 at 2:07 AM, Don dondod...@gmail.com wrote: Consider the 5 * 64 possible outcomes for the selection of coin and six flips, each one happening with equal probability. Of those 320 possible outcomes, 4*62 are excluded by knowing that the first 5 flips are heads. That leaves 64 outcomes with the rigged coin and 2 outcomes with each of the fair coins, for a total of 72 outcomes. 68 of those are heads, so the answer to the puzzle is 68 of 72, or 17 of 18. Don On Aug 8, 2:36 am, Shachindra A C sachindr...@gmail.com wrote: @brijesh *first five times* is mentioned intentionally to mislead i think. I vote for 3/5. Moreover, 17/80 doesn't make sense also. Plz correct me if I am wrong. On Mon, Aug 8, 2011 at 12:06 PM, sumit gaur sumitgau...@gmail.com wrote: (3/5) On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards, Shachindra A C -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- People often say that motivation doesn't last. Well, neither does bathing - that's why we recommend it daily. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
Man, I feel so stupid. Yes, it is a case of conditional probability. We have to calculate the probability of six heads, given that 5 heads have occured. So answer is 17/18. On Tue, Aug 9, 2011 at 1:47 AM, Arun Vishwanathan aaron.nar...@gmail.comwrote: @shady: 3/5 can be the answer to such a question: what is prob of getting head on nth toss if we have 4 coins fair and one biased...then at nth toss u choose 4/5 1/5 prob and then u get 3/5 @shady , don: i did this: P( 6th head | 5 heads occured)= P( 6 heads )/ P( 5 heads) answr u get is 17/18..i cud be wrong please correct if so On Mon, Aug 8, 2011 at 10:45 PM, shady sinv...@gmail.com wrote: answer is 3/5. 17/80 is the answer for 6 consecutive heads. On Tue, Aug 9, 2011 at 2:07 AM, Don dondod...@gmail.com wrote: Consider the 5 * 64 possible outcomes for the selection of coin and six flips, each one happening with equal probability. Of those 320 possible outcomes, 4*62 are excluded by knowing that the first 5 flips are heads. That leaves 64 outcomes with the rigged coin and 2 outcomes with each of the fair coins, for a total of 72 outcomes. 68 of those are heads, so the answer to the puzzle is 68 of 72, or 17 of 18. Don On Aug 8, 2:36 am, Shachindra A C sachindr...@gmail.com wrote: @brijesh *first five times* is mentioned intentionally to mislead i think. I vote for 3/5. Moreover, 17/80 doesn't make sense also. Plz correct me if I am wrong. On Mon, Aug 8, 2011 at 12:06 PM, sumit gaur sumitgau...@gmail.com wrote: (3/5) On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards, Shachindra A C -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- People often say that motivation doesn't last. Well, neither does bathing - that's why we recommend it daily. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Shuaib http://www.bytehood.com http://twitter.com/ShuaibKhan -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
answer should be 3/5 think like that tossing 5 times will not help you predict the outcome of sixth toss. Therefore that information is meaningless. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
@Vinay: What if you tossed 100 consecutive heads? Would that be enough to convince you that you had the double-headed coin? If so, then doesn't tossing 5 consecutive heads give you at least an inkling that you might have it? Wouldn't you then think that there would be a higher probability of getting a head on the sixth toss than there was on the first toss (3/5)? Don's conditional probability answer 17/18 is the right answer. Dave On Aug 8, 5:04 pm, vinay aggarwal vinayiiit2...@gmail.com wrote: answer should be 3/5 think like that tossing 5 times will not help you predict the outcome of sixth toss. Therefore that information is meaningless. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
3/5. As the question doesn't ask anything about the sequence. Had the question been Find the probability that all 6 are H then it would have been 17/80. On 9 August 2011 04:07, Dave dave_and_da...@juno.com wrote: @Vinay: What if you tossed 100 consecutive heads? Would that be enough to convince you that you had the double-headed coin? If so, then doesn't tossing 5 consecutive heads give you at least an inkling that you might have it? Wouldn't you then think that there would be a higher probability of getting a head on the sixth toss than there was on the first toss (3/5)? Don's conditional probability answer 17/18 is the right answer. Dave On Aug 8, 5:04 pm, vinay aggarwal vinayiiit2...@gmail.com wrote: answer should be 3/5 think like that tossing 5 times will not help you predict the outcome of sixth toss. Therefore that information is meaningless. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- ___ Please do not print this e-mail until urgent requirement. Go Green!! Save Papers = Save Trees -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
@Dipankar: You are correct about the answer to your alternative question being 17/80, but your answer 3/5 says that you don't think you have learned anything by the five heads flips. Don has given a good explanation as to why the answer is 17/18, but you apparently refuse to accept it. There is none so blind as one who will not see. Dave On Aug 8, 9:26 pm, Dipankar Patro dip10c...@gmail.com wrote: 3/5. As the question doesn't ask anything about the sequence. Had the question been Find the probability that all 6 are H then it would have been 17/80. On 9 August 2011 04:07, Dave dave_and_da...@juno.com wrote: @Vinay: What if you tossed 100 consecutive heads? Would that be enough to convince you that you had the double-headed coin? If so, then doesn't tossing 5 consecutive heads give you at least an inkling that you might have it? Wouldn't you then think that there would be a higher probability of getting a head on the sixth toss than there was on the first toss (3/5)? Don's conditional probability answer 17/18 is the right answer. Dave On Aug 8, 5:04 pm, vinay aggarwal vinayiiit2...@gmail.com wrote: answer should be 3/5 think like that tossing 5 times will not help you predict the outcome of sixth toss. Therefore that information is meaningless. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- ___ Please do not print this e-mail until urgent requirement. Go Green!! Save Papers = Save Trees -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
it's 3/5 On Tue, Aug 9, 2011 at 8:29 AM, Dave dave_and_da...@juno.com wrote: @Dipankar: You are correct about the answer to your alternative question being 17/80, but your answer 3/5 says that you don't think you have learned anything by the five heads flips. Don has given a good explanation as to why the answer is 17/18, but you apparently refuse to accept it. There is none so blind as one who will not see. Dave On Aug 8, 9:26 pm, Dipankar Patro dip10c...@gmail.com wrote: 3/5. As the question doesn't ask anything about the sequence. Had the question been Find the probability that all 6 are H then it would have been 17/80. On 9 August 2011 04:07, Dave dave_and_da...@juno.com wrote: @Vinay: What if you tossed 100 consecutive heads? Would that be enough to convince you that you had the double-headed coin? If so, then doesn't tossing 5 consecutive heads give you at least an inkling that you might have it? Wouldn't you then think that there would be a higher probability of getting a head on the sixth toss than there was on the first toss (3/5)? Don's conditional probability answer 17/18 is the right answer. Dave On Aug 8, 5:04 pm, vinay aggarwal vinayiiit2...@gmail.com wrote: answer should be 3/5 think like that tossing 5 times will not help you predict the outcome of sixth toss. Therefore that information is meaningless. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- ___ Please do not print this e-mail until urgent requirement. Go Green!! Save Papers = Save Trees -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
@all those who gave Should be (4/5 *(1/2)^6) + (1/5 * 1) = 17/80 when it's already given that 5 heads have turned up already then why abut are you adding that probability you all are considering it as finding the probability of finding 6 consecutive heads. since all tosses are independent the answer should be 3/5. the point that 5 heads have turned up already may points that the coin selected is biased in that case pr(6)=1; now the answer depends on the interviewer according to me it should be 3/5 thanks -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
Pls check the ques 8th This may remove misunderstanding... http://www.folj.com/puzzles/difficult-logic-problems.htm On Tue, Aug 9, 2011 at 10:21 AM, raj kumar megamonste...@gmail.com wrote: @all those who gave Should be (4/5 *(1/2)^6) + (1/5 * 1) = 17/80 when it's already given that 5 heads have turned up already then why abut are you adding that probability you all are considering it as finding the probability of finding 6 consecutive heads. since all tosses are independent the answer should be 3/5. the point that 5 heads have turned up already may points that the coin selected is biased in that case pr(6)=1; now the answer depends on the interviewer according to me it should be 3/5 thanks -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- **Regards SAGAR PAREEK COMPUTER SCIENCE AND ENGINEERING NIT ALLAHABAD -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
@Coder: You (and others) are saying that the probability of a head is 3/5 on the first flip, and that it doesn't change after any number of heads are flipped. Notice, however, that if the first flip were tails, you wouldn't say that the probability of getting heads on the next flip is 3/5. You would have learned that one of the four fair coins was chosen. So even though the probability of a head was 3/5 on the first flip, it changes to 1/2 on all flips subsequent to a tail. Since the probabililty changes if a tail is flipped, what makes you think it doesn't change if a head is flipped. In fact, the probability is 3/5 for the first flip. After a head is flipped, the probability of a head is 2/3. After two heads have been flipped, it is 3/4. After 3 heads, it is 5/6. After 4 heads, the probability is 9/10, and after 5 heads, the probability is 17/18. Dave On Aug 8, 11:23 pm, coder dumca coder.du...@gmail.com wrote: it's 3/5 On Tue, Aug 9, 2011 at 8:29 AM, Dave dave_and_da...@juno.com wrote: @Dipankar: You are correct about the answer to your alternative question being 17/80, but your answer 3/5 says that you don't think you have learned anything by the five heads flips. Don has given a good explanation as to why the answer is 17/18, but you apparently refuse to accept it. There is none so blind as one who will not see. Dave On Aug 8, 9:26 pm, Dipankar Patro dip10c...@gmail.com wrote: 3/5. As the question doesn't ask anything about the sequence. Had the question been Find the probability that all 6 are H then it would have been 17/80. On 9 August 2011 04:07, Dave dave_and_da...@juno.com wrote: @Vinay: What if you tossed 100 consecutive heads? Would that be enough to convince you that you had the double-headed coin? If so, then doesn't tossing 5 consecutive heads give you at least an inkling that you might have it? Wouldn't you then think that there would be a higher probability of getting a head on the sixth toss than there was on the first toss (3/5)? Don's conditional probability answer 17/18 is the right answer. Dave On Aug 8, 5:04 pm, vinay aggarwal vinayiiit2...@gmail.com wrote: answer should be 3/5 think like that tossing 5 times will not help you predict the outcome of sixth toss. Therefore that information is meaningless. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- ___ Please do not print this e-mail until urgent requirement. Go Green!! Save Papers = Save Trees -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
@Raj. Granted that the first flip has a 3/5 probability of getting a head. But if it produces a tail, would you say that the second flip also has a 3/5 probability of getting a head? Or have you learned something from the tail? If you learn something from a tail, why don't you learn something from a head? Dave On Aug 8, 11:51 pm, raj kumar megamonste...@gmail.com wrote: @all those who gave Should be (4/5 *(1/2)^6) + (1/5 * 1) = 17/80 when it's already given that 5 heads have turned up already then why abut are you adding that probability you all are considering it as finding the probability of finding 6 consecutive heads. since all tosses are independent the answer should be 3/5. the point that 5 heads have turned up already may points that the coin selected is biased in that case pr(6)=1; now the answer depends on the interviewer according to me it should be 3/5 thanks -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
Just to resolve the issue what will be the probability of getting 6 consecutive heads -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
no then it will be 1/2 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
@Raj: After getting 5 consecutive heads, the probability of getting a 6th head is 17/18. Dave On Aug 9, 12:17 am, raj kumar megamonste...@gmail.com wrote: Just to resolve the issue what will be the probability of getting 6 consecutive heads -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
@Raj. Good. So now answer my last question? Dave On Aug 9, 12:21 am, raj kumar megamonste...@gmail.com wrote: no then it will be 1/2 -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
@Dave: I guess 17/18 is correct. Since we have to *calculate the probability of getting a head in the 6th flip given that first 5 flips are a head*. Can you please explain how you got the values of consequent flips when you said this? *In fact, the probability is 3/5 for the first flip. After a head is flipped, the probability of a head is 2/3. After two heads have been flipped, it is 3/4. After 3 heads, it is 5/6. After 4 heads, the probability is 9/10, and after 5 heads, the probability is 17/18.* -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
http://math.arizona.edu/~jwatkins/f-condition.pdf see this link now ithink the answer should be 65/66 bcoz the probability of selectting double headed coin after n heads =2^n/2^n+1 and fair coin is =1/2^n+1 so for 6th head it should be :2^n/2^n+1*1+((1/2^n+1)*1/2) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
plz reply am i right or wrong -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
0.6? On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
@algo: We can get head in two cases:- 1.) coin is biases 2.) coin is not biased P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5 P(head) for unbiased= 4/5*(1/2)^6 hence combined probability is what nitish has already mentioned. Hope you get the point. On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover algolear...@gmail.com wrote: Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
Even u dont get why u people are gettin 17/80...the probability that it will be a head 6th time will be same as the frst time...so it shud be 3/5... On Aug 7, 11:05 pm, Kunal Yadav kunalyada...@gmail.com wrote: @algo: We can get head in two cases:- 1.) coin is biases 2.) coin is not biased P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5 P(head) for unbiased= 4/5*(1/2)^6 hence combined probability is what nitish has already mentioned. Hope you get the point. On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover algolear...@gmail.com wrote: Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
If the coin is unbiased then probability of heads: 1/2 irrespective of whether it is first time or nth time. So answer should be 3/5. Aseem On Mon, Aug 8, 2011 at 12:39 AM, saurabh chhabra saurabh131...@gmail.comwrote: Even u dont get why u people are gettin 17/80...the probability that it will be a head 6th time will be same as the frst time...so it shud be 3/5... On Aug 7, 11:05 pm, Kunal Yadav kunalyada...@gmail.com wrote: @algo: We can get head in two cases:- 1.) coin is biases 2.) coin is not biased P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5 P(head) for unbiased= 4/5*(1/2)^6 hence combined probability is what nitish has already mentioned. Hope you get the point. On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover algolear...@gmail.com wrote: Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
Sixth toss is independent of previous tosses and dependent only on coin selection...! 1/5 + 4/5(1/2)= 3/5 is the correct answer we want to calc. probability of getting heads the sixth time only even if it would have been 100 th time...3/5 would be the answer only.. On 8/8/11, Prakash D cegprak...@gmail.com wrote: 1.) coin is fair 2.) coin is unfair P(head) for unfair coin= 1/5 * 1= 1/5 P(head) for fair coin= 4/5* 1/2 = 2/5 the probability at any instant that the tossed coin is a head is 3/5 17/80 is the probability to get head at all the six times. the soln. for this problem will be 3/5 On Mon, Aug 8, 2011 at 12:45 AM, aseem garg ase.as...@gmail.com wrote: If the coin is unbiased then probability of heads: 1/2 irrespective of whether it is first time or nth time. So answer should be 3/5. Aseem On Mon, Aug 8, 2011 at 12:39 AM, saurabh chhabra saurabh131...@gmail.comwrote: Even u dont get why u people are gettin 17/80...the probability that it will be a head 6th time will be same as the frst time...so it shud be 3/5... On Aug 7, 11:05 pm, Kunal Yadav kunalyada...@gmail.com wrote: @algo: We can get head in two cases:- 1.) coin is biases 2.) coin is not biased P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5 P(head) for unbiased= 4/5*(1/2)^6 hence combined probability is what nitish has already mentioned. Hope you get the point. On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover algolear...@gmail.com wrote: Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
On Mon, Aug 8, 2011 at 12:40 AM, Puneet Gautam puneet.nsi...@gmail.comwrote: Sixth toss is independent of previous tosses and dependent only on coin selection...! 1/5 + 4/5(1/2)= 3/5 is the correct answer we want to calc. probability of getting heads the sixth time only even if it would have been 100 th time...3/5 would be the answer only.. It is not independent. Re read the question. The first five times, it HAS to be heads. On 8/8/11, Prakash D cegprak...@gmail.com wrote: 1.) coin is fair 2.) coin is unfair P(head) for unfair coin= 1/5 * 1= 1/5 P(head) for fair coin= 4/5* 1/2 = 2/5 the probability at any instant that the tossed coin is a head is 3/5 17/80 is the probability to get head at all the six times. the soln. for this problem will be 3/5 On Mon, Aug 8, 2011 at 12:45 AM, aseem garg ase.as...@gmail.com wrote: If the coin is unbiased then probability of heads: 1/2 irrespective of whether it is first time or nth time. So answer should be 3/5. Aseem On Mon, Aug 8, 2011 at 12:39 AM, saurabh chhabra saurabh131...@gmail.comwrote: Even u dont get why u people are gettin 17/80...the probability that it will be a head 6th time will be same as the frst time...so it shud be 3/5... On Aug 7, 11:05 pm, Kunal Yadav kunalyada...@gmail.com wrote: @algo: We can get head in two cases:- 1.) coin is biases 2.) coin is not biased P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5 P(head) for unbiased= 4/5*(1/2)^6 hence combined probability is what nitish has already mentioned. Hope you get the point. On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover algolear...@gmail.com wrote: Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Shuaib http://www.bytehood.com http://twitter.com/ShuaibKhan -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
Think it like this. I have tossed a coin 5 times and it showed heads all the times. What is the probabilty of it shoing a HEADS now? Aseem On Mon, Aug 8, 2011 at 1:12 AM, Shuaib Khan aries.shu...@gmail.com wrote: On Mon, Aug 8, 2011 at 12:40 AM, Puneet Gautam puneet.nsi...@gmail.comwrote: Sixth toss is independent of previous tosses and dependent only on coin selection...! 1/5 + 4/5(1/2)= 3/5 is the correct answer we want to calc. probability of getting heads the sixth time only even if it would have been 100 th time...3/5 would be the answer only.. It is not independent. Re read the question. The first five times, it HAS to be heads. On 8/8/11, Prakash D cegprak...@gmail.com wrote: 1.) coin is fair 2.) coin is unfair P(head) for unfair coin= 1/5 * 1= 1/5 P(head) for fair coin= 4/5* 1/2 = 2/5 the probability at any instant that the tossed coin is a head is 3/5 17/80 is the probability to get head at all the six times. the soln. for this problem will be 3/5 On Mon, Aug 8, 2011 at 12:45 AM, aseem garg ase.as...@gmail.com wrote: If the coin is unbiased then probability of heads: 1/2 irrespective of whether it is first time or nth time. So answer should be 3/5. Aseem On Mon, Aug 8, 2011 at 12:39 AM, saurabh chhabra saurabh131...@gmail.comwrote: Even u dont get why u people are gettin 17/80...the probability that it will be a head 6th time will be same as the frst time...so it shud be 3/5... On Aug 7, 11:05 pm, Kunal Yadav kunalyada...@gmail.com wrote: @algo: We can get head in two cases:- 1.) coin is biases 2.) coin is not biased P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5 P(head) for unbiased= 4/5*(1/2)^6 hence combined probability is what nitish has already mentioned. Hope you get the point. On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover algolear...@gmail.com wrote: Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Shuaib http://www.bytehood.com http://twitter.com/ShuaibKhan -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To
Re: [algogeeks] Re: Probability Puzzle
On Mon, Aug 8, 2011 at 12:47 AM, aseem garg ase.as...@gmail.com wrote: Think it like this. I have tossed a coin 5 times and it showed heads all the times. What is the probabilty of it shoing a HEADS now? Aseem Well you are thinking about it the wrong way. Question asks that what is the probability that heads will show up the first five times, plus a sixth time. Not just the sixth time. The first five times head showing up is part of the question. On Mon, Aug 8, 2011 at 1:12 AM, Shuaib Khan aries.shu...@gmail.comwrote: On Mon, Aug 8, 2011 at 12:40 AM, Puneet Gautam puneet.nsi...@gmail.comwrote: Sixth toss is independent of previous tosses and dependent only on coin selection...! 1/5 + 4/5(1/2)= 3/5 is the correct answer we want to calc. probability of getting heads the sixth time only even if it would have been 100 th time...3/5 would be the answer only.. It is not independent. Re read the question. The first five times, it HAS to be heads. On 8/8/11, Prakash D cegprak...@gmail.com wrote: 1.) coin is fair 2.) coin is unfair P(head) for unfair coin= 1/5 * 1= 1/5 P(head) for fair coin= 4/5* 1/2 = 2/5 the probability at any instant that the tossed coin is a head is 3/5 17/80 is the probability to get head at all the six times. the soln. for this problem will be 3/5 On Mon, Aug 8, 2011 at 12:45 AM, aseem garg ase.as...@gmail.com wrote: If the coin is unbiased then probability of heads: 1/2 irrespective of whether it is first time or nth time. So answer should be 3/5. Aseem On Mon, Aug 8, 2011 at 12:39 AM, saurabh chhabra saurabh131...@gmail.comwrote: Even u dont get why u people are gettin 17/80...the probability that it will be a head 6th time will be same as the frst time...so it shud be 3/5... On Aug 7, 11:05 pm, Kunal Yadav kunalyada...@gmail.com wrote: @algo: We can get head in two cases:- 1.) coin is biases 2.) coin is not biased P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5 P(head) for unbiased= 4/5*(1/2)^6 hence combined probability is what nitish has already mentioned. Hope you get the point. On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover algolear...@gmail.com wrote: Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Shuaib http://www.bytehood.com http://twitter.com/ShuaibKhan -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group,
Re: [algogeeks] Re: Probability Puzzle
@Shuaib: **What is the probability that you toss *next time, heads turns up ***. Aseem On Mon, Aug 8, 2011 at 1:19 AM, Shuaib Khan aries.shu...@gmail.com wrote: On Mon, Aug 8, 2011 at 12:47 AM, aseem garg ase.as...@gmail.com wrote: Think it like this. I have tossed a coin 5 times and it showed heads all the times. What is the probabilty of it shoing a HEADS now? Aseem Well you are thinking about it the wrong way. Question asks that what is the probability that heads will show up the first five times, plus a sixth time. Not just the sixth time. The first five times head showing up is part of the question. On Mon, Aug 8, 2011 at 1:12 AM, Shuaib Khan aries.shu...@gmail.comwrote: On Mon, Aug 8, 2011 at 12:40 AM, Puneet Gautam puneet.nsi...@gmail.comwrote: Sixth toss is independent of previous tosses and dependent only on coin selection...! 1/5 + 4/5(1/2)= 3/5 is the correct answer we want to calc. probability of getting heads the sixth time only even if it would have been 100 th time...3/5 would be the answer only.. It is not independent. Re read the question. The first five times, it HAS to be heads. On 8/8/11, Prakash D cegprak...@gmail.com wrote: 1.) coin is fair 2.) coin is unfair P(head) for unfair coin= 1/5 * 1= 1/5 P(head) for fair coin= 4/5* 1/2 = 2/5 the probability at any instant that the tossed coin is a head is 3/5 17/80 is the probability to get head at all the six times. the soln. for this problem will be 3/5 On Mon, Aug 8, 2011 at 12:45 AM, aseem garg ase.as...@gmail.com wrote: If the coin is unbiased then probability of heads: 1/2 irrespective of whether it is first time or nth time. So answer should be 3/5. Aseem On Mon, Aug 8, 2011 at 12:39 AM, saurabh chhabra saurabh131...@gmail.comwrote: Even u dont get why u people are gettin 17/80...the probability that it will be a head 6th time will be same as the frst time...so it shud be 3/5... On Aug 7, 11:05 pm, Kunal Yadav kunalyada...@gmail.com wrote: @algo: We can get head in two cases:- 1.) coin is biases 2.) coin is not biased P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5 P(head) for unbiased= 4/5*(1/2)^6 hence combined probability is what nitish has already mentioned. Hope you get the point. On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover algolear...@gmail.com wrote: Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com . To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Shuaib
Re: [algogeeks] Re: Probability Puzzle
no fight.. lets mention both the answers :D On Mon, Aug 8, 2011 at 1:19 AM, Shuaib Khan aries.shu...@gmail.com wrote: On Mon, Aug 8, 2011 at 12:47 AM, aseem garg ase.as...@gmail.com wrote: Think it like this. I have tossed a coin 5 times and it showed heads all the times. What is the probabilty of it shoing a HEADS now? Aseem Well you are thinking about it the wrong way. Question asks that what is the probability that heads will show up the first five times, plus a sixth time. Not just the sixth time. The first five times head showing up is part of the question. On Mon, Aug 8, 2011 at 1:12 AM, Shuaib Khan aries.shu...@gmail.comwrote: On Mon, Aug 8, 2011 at 12:40 AM, Puneet Gautam puneet.nsi...@gmail.comwrote: Sixth toss is independent of previous tosses and dependent only on coin selection...! 1/5 + 4/5(1/2)= 3/5 is the correct answer we want to calc. probability of getting heads the sixth time only even if it would have been 100 th time...3/5 would be the answer only.. It is not independent. Re read the question. The first five times, it HAS to be heads. On 8/8/11, Prakash D cegprak...@gmail.com wrote: 1.) coin is fair 2.) coin is unfair P(head) for unfair coin= 1/5 * 1= 1/5 P(head) for fair coin= 4/5* 1/2 = 2/5 the probability at any instant that the tossed coin is a head is 3/5 17/80 is the probability to get head at all the six times. the soln. for this problem will be 3/5 On Mon, Aug 8, 2011 at 12:45 AM, aseem garg ase.as...@gmail.com wrote: If the coin is unbiased then probability of heads: 1/2 irrespective of whether it is first time or nth time. So answer should be 3/5. Aseem On Mon, Aug 8, 2011 at 12:39 AM, saurabh chhabra saurabh131...@gmail.comwrote: Even u dont get why u people are gettin 17/80...the probability that it will be a head 6th time will be same as the frst time...so it shud be 3/5... On Aug 7, 11:05 pm, Kunal Yadav kunalyada...@gmail.com wrote: @algo: We can get head in two cases:- 1.) coin is biases 2.) coin is not biased P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5 P(head) for unbiased= 4/5*(1/2)^6 hence combined probability is what nitish has already mentioned. Hope you get the point. On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover algolear...@gmail.com wrote: Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com . To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Shuaib http://www.bytehood.com
Re: [algogeeks] Re: Probability Puzzle
On Mon, Aug 8, 2011 at 12:51 AM, aseem garg ase.as...@gmail.com wrote: @Shuaib: **What is the probability that you toss *next time, heads turns up***. Well if you interpret it your way, then you are right. Otherwise, not. Aseem On Mon, Aug 8, 2011 at 1:19 AM, Shuaib Khan aries.shu...@gmail.comwrote: On Mon, Aug 8, 2011 at 12:47 AM, aseem garg ase.as...@gmail.com wrote: Think it like this. I have tossed a coin 5 times and it showed heads all the times. What is the probabilty of it shoing a HEADS now? Aseem Well you are thinking about it the wrong way. Question asks that what is the probability that heads will show up the first five times, plus a sixth time. Not just the sixth time. The first five times head showing up is part of the question. On Mon, Aug 8, 2011 at 1:12 AM, Shuaib Khan aries.shu...@gmail.comwrote: On Mon, Aug 8, 2011 at 12:40 AM, Puneet Gautam puneet.nsi...@gmail.com wrote: Sixth toss is independent of previous tosses and dependent only on coin selection...! 1/5 + 4/5(1/2)= 3/5 is the correct answer we want to calc. probability of getting heads the sixth time only even if it would have been 100 th time...3/5 would be the answer only.. It is not independent. Re read the question. The first five times, it HAS to be heads. On 8/8/11, Prakash D cegprak...@gmail.com wrote: 1.) coin is fair 2.) coin is unfair P(head) for unfair coin= 1/5 * 1= 1/5 P(head) for fair coin= 4/5* 1/2 = 2/5 the probability at any instant that the tossed coin is a head is 3/5 17/80 is the probability to get head at all the six times. the soln. for this problem will be 3/5 On Mon, Aug 8, 2011 at 12:45 AM, aseem garg ase.as...@gmail.com wrote: If the coin is unbiased then probability of heads: 1/2 irrespective of whether it is first time or nth time. So answer should be 3/5. Aseem On Mon, Aug 8, 2011 at 12:39 AM, saurabh chhabra saurabh131...@gmail.comwrote: Even u dont get why u people are gettin 17/80...the probability that it will be a head 6th time will be same as the frst time...so it shud be 3/5... On Aug 7, 11:05 pm, Kunal Yadav kunalyada...@gmail.com wrote: @algo: We can get head in two cases:- 1.) coin is biases 2.) coin is not biased P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5 P(head) for unbiased= 4/5*(1/2)^6 hence combined probability is what nitish has already mentioned. Hope you get the point. On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover algolear...@gmail.com wrote: Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to
Re: [algogeeks] Re: Probability Puzzle
abe yaar kya farak padta hai... 3/5=0.6 , other one may be 0.4 ya 0.3, 0.3 ke difference ke liye lad rahe ho... Chill guys... On 8/8/11, Shuaib Khan aries.shu...@gmail.com wrote: On Mon, Aug 8, 2011 at 12:51 AM, aseem garg ase.as...@gmail.com wrote: @Shuaib: **What is the probability that you toss *next time, heads turns up***. Well if you interpret it your way, then you are right. Otherwise, not. Aseem On Mon, Aug 8, 2011 at 1:19 AM, Shuaib Khan aries.shu...@gmail.comwrote: On Mon, Aug 8, 2011 at 12:47 AM, aseem garg ase.as...@gmail.com wrote: Think it like this. I have tossed a coin 5 times and it showed heads all the times. What is the probabilty of it shoing a HEADS now? Aseem Well you are thinking about it the wrong way. Question asks that what is the probability that heads will show up the first five times, plus a sixth time. Not just the sixth time. The first five times head showing up is part of the question. On Mon, Aug 8, 2011 at 1:12 AM, Shuaib Khan aries.shu...@gmail.comwrote: On Mon, Aug 8, 2011 at 12:40 AM, Puneet Gautam puneet.nsi...@gmail.com wrote: Sixth toss is independent of previous tosses and dependent only on coin selection...! 1/5 + 4/5(1/2)= 3/5 is the correct answer we want to calc. probability of getting heads the sixth time only even if it would have been 100 th time...3/5 would be the answer only.. It is not independent. Re read the question. The first five times, it HAS to be heads. On 8/8/11, Prakash D cegprak...@gmail.com wrote: 1.) coin is fair 2.) coin is unfair P(head) for unfair coin= 1/5 * 1= 1/5 P(head) for fair coin= 4/5* 1/2 = 2/5 the probability at any instant that the tossed coin is a head is 3/5 17/80 is the probability to get head at all the six times. the soln. for this problem will be 3/5 On Mon, Aug 8, 2011 at 12:45 AM, aseem garg ase.as...@gmail.com wrote: If the coin is unbiased then probability of heads: 1/2 irrespective of whether it is first time or nth time. So answer should be 3/5. Aseem On Mon, Aug 8, 2011 at 12:39 AM, saurabh chhabra saurabh131...@gmail.comwrote: Even u dont get why u people are gettin 17/80...the probability that it will be a head 6th time will be same as the frst time...so it shud be 3/5... On Aug 7, 11:05 pm, Kunal Yadav kunalyada...@gmail.com wrote: @algo: We can get head in two cases:- 1.) coin is biases 2.) coin is not biased P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5 P(head) for unbiased= 4/5*(1/2)^6 hence combined probability is what nitish has already mentioned. Hope you get the point. On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover algolear...@gmail.com wrote: Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message
[algogeeks] Re: Probability Puzzle
@Puneet: So are you saying that 100 heads in a row wouldn't convince you that you had the unfair coin? How many heads in a row would it take? Dave On Aug 7, 2:40 pm, Puneet Gautam puneet.nsi...@gmail.com wrote: Sixth toss is independent of previous tosses and dependent only on coin selection...! 1/5 + 4/5(1/2)= 3/5 is the correct answer we want to calc. probability of getting heads the sixth time only even if it would have been 100 th time...3/5 would be the answer only.. On 8/8/11, Prakash D cegprak...@gmail.com wrote: 1.) coin is fair 2.) coin is unfair P(head) for unfair coin= 1/5 * 1= 1/5 P(head) for fair coin= 4/5* 1/2 = 2/5 the probability at any instant that the tossed coin is a head is 3/5 17/80 is the probability to get head at all the six times. the soln. for this problem will be 3/5 On Mon, Aug 8, 2011 at 12:45 AM, aseem garg ase.as...@gmail.com wrote: If the coin is unbiased then probability of heads: 1/2 irrespective of whether it is first time or nth time. So answer should be 3/5. Aseem On Mon, Aug 8, 2011 at 12:39 AM, saurabh chhabra saurabh131...@gmail.comwrote: Even u dont get why u people are gettin 17/80...the probability that it will be a head 6th time will be same as the frst time...so it shud be 3/5... On Aug 7, 11:05 pm, Kunal Yadav kunalyada...@gmail.com wrote: @algo: We can get head in two cases:- 1.) coin is biases 2.) coin is not biased P(head) for biased= 1/5 *1*1*1*1*1*1= 1/5 P(head) for unbiased= 4/5*(1/2)^6 hence combined probability is what nitish has already mentioned. Hope you get the point. On Sun, Aug 7, 2011 at 11:29 PM, Algo Lover algolear...@gmail.com wrote: Can anyone explain the approach how to solve this . I think all tosses are independent so it should be 3/5. why is this in- correct On Aug 7, 10:55 pm, saurabh chhabra saurabh131...@gmail.com wrote: sry...its wrong On Aug 7, 10:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kunal Yadav (http://algoritmus.in/) -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
I think 17/80 is right answer.. otherwise no use of mentioning *first five times* specifically in the question. ! though m not sure -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To view this discussion on the web visit https://groups.google.com/d/msg/algogeeks/-/1aMP_RgRaDYJ. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
[algogeeks] Re: Probability Puzzle
1/5+1/2^6 On Aug 7, 8:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
i think the answer will be 1/5+ 4/5*1/2=3/5 coz the question is saying what is the probability of getting head* sixth time*(when 5 heads were already there).. it is not saying what is the probability of getting heads* 6 times*..(in this case answer will be 17/180) On Mon, Aug 8, 2011 at 9:54 AM, D.B. sylve...@gmail.com wrote: 1/5+1/2^6 On Aug 7, 8:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards, Kamakshi kamakshi...@gmail.com -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
Re: [algogeeks] Re: Probability Puzzle
I think the answer is 3/5, becoz all the trails/tossing coins are independent events. So even when it is 100th time the answer is 3/5. On 8 August 2011 09:05, Kamakshii Aggarwal kamakshi...@gmail.com wrote: i think the answer will be 1/5+ 4/5*1/2=3/5 coz the question is saying what is the probability of getting head* sixth time*(when 5 heads were already there).. it is not saying what is the probability of getting heads* 6 times*..(in this case answer will be 17/180) On Mon, Aug 8, 2011 at 9:54 AM, D.B. sylve...@gmail.com wrote: 1/5+1/2^6 On Aug 7, 8:34 pm, Algo Lover algolear...@gmail.com wrote: A bag contains 5 coins. Four of them are fair and one has heads on both sides. You randomly pulled one coin from the bag and tossed it 5 times, heads turned up all five times. What is the probability that you toss next time, heads turns up. (All this time you don't know you were tossing a fair coin or not). -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards, Kamakshi kamakshi...@gmail.com -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en. -- Regards Kumar Raja M.Tech(SIT) IIT Kharagpur, 10it60...@iitkgp.ac.in 7797137043. 09491690115. -- You received this message because you are subscribed to the Google Groups Algorithm Geeks group. To post to this group, send email to algogeeks@googlegroups.com. To unsubscribe from this group, send email to algogeeks+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
