r...@i.frys.com wrote:
Soham Das wrote:
int a[125];
for(i=0;i125;i++)
a[i]=0;
my @array;
$array[$_] = 0 for 0..125;
s/125/124/
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Soham Das wrote:
a... How do I initialise an array of a definite size with zero. Say the C
equivalent of such a statement will be:
int a[125];
for(i=0;i125;i++)
a[i]=0;
You easily can, but why would you?
It is often a sign of
Soham Das wrote:
Hello All,
I wanted some guidance with these questions of mine:
a.. How do I initialise an array of a definite size with
zero. Say the C equivalent of such a statement will be:
int a[125];
for(i=0;i125;i++)
a[i]=0;
Date sent: Mon, 28 Sep 2009 09:11:02 -0700
Subject:Re: Arrays, Dates, Indexing and Initialisation
From: r...@i.frys.com
To: Soham Das soham...@yahoo.co.in
Copies to: beginners@perl.org
Soham Das wrote:
Hello All
Soham Das wrote:
a.. How do I initialise an array of a definite size with zero. Say the C
equivalent of such a statement will be:
int a[125];
for(i=0;i125;i++)
a[i]=0;
Not needed. Perl assume zero if a non-existing element is
Wow! sweet!
Hi Jenda, thanks for the help.
And I guess, for the dates problem I have to use hashes, eh?
Soham
- Original Message
From: Jenda Krynicky je...@krynicky.cz
To: beginners@perl.org
Sent: Monday, 28 September, 2009 9:50:40 PM
Subject: Re: Arrays, Dates, Indexing
Thanks Shawn, yes hashes I guess will be the way to go forward.
Soham
- Original Message
From: Shawn H Corey shawnhco...@gmail.com
To: Soham Das soham...@yahoo.co.in
Cc: beginners@perl.org
Sent: Monday, 28 September, 2009 9:50:18 PM
Subject: Re: Arrays, Dates, Indexing
JK == Jenda Krynicky je...@krynicky.cz writes:
a.. How do I initialise an array of a definite size with
zero. Say the C equivalent of such a statement will be:
my @array;
$array[$_] = 0 for 0..125;
JK my @array = (0) x 126;
and a question for the OP is why do you need
SHC == Shawn H Corey shawnhco...@gmail.com writes:
SHC Soham Das wrote:
a.. How do I initialise an array of a definite size with zero. Say the C
equivalent of such a statement will be:
int a[125];
for(i=0;i125;i++)a[i]=0;
SHC Not needed. Perl assume zero if a
Uri Guttman wrote:
only for ++/-- and +=/-= will that work with no warnings. if he uses an
undef value in another arithmetic expression it will warn.
Also, undef values work in if/unless and while/until conditions.
Usually when you see indexes used with arrays, it is because the
programmer
Message
From: Shawn H Corey shawnhco...@gmail.com
To: Uri Guttman u...@stemsystems.com
Cc: Soham Das soham...@yahoo.co.in; beginners@perl.org
Sent: Monday, 28 September, 2009 10:45:33 PM
Subject: Re: Arrays, Dates, Indexing and Initialisation
Uri Guttman wrote:
only
Soham Das wrote:
My agenda actually is two pronged. I have read Beginning Perl and a bit of
Intermediate Perl, though was able to solve individual problems, but I was not
sure,if I can code myself out of a wet paperbag.
So I thought, lets chuck theory. Its better to get hands dirty with some
On 10/29/07, Tom Phoenix [EMAIL PROTECTED] wrote:
An array is the kind of variable which holds
a list; a list is the kind of data which is stored in an array. You
can use the list contained in an array, and you can store a list into
an array. But the array is the container, and the list is
Bryan Harris wrote:
Hi,
I'm not sure I understand why this is happening. Maybe someone can
explain it to me. No matter how many times I use the chomp() function
on my array, when I print the array it always prints the newlines.
But I have another array, which will print without the newlines.
Bryan Harris wrote:
I'm not sure I understand why this is happening. Maybe someone can
explain it to me. No matter how many times I use the chomp() function
on my array, when I print the array it always prints the newlines.
But I have another array, which will print without the newlines.
In
On 7/30/07, Rob Dixon [EMAIL PROTECTED] wrote:
Bryan Harris wrote:
I'm not sure I understand why this is happening. Maybe someone can
explain it to me. No matter how many times I use the chomp() function
on my array, when I print the array it always prints the newlines.
But I have
Thanks guys, I've almost got it. I need to save the title and URL of
each result in the array to a different scratch variable so I can
use it outside of the script. The following works great, but of
course it only saves the last set of results from the loop.
foreach my
On Mon, 14 Mar 2005 03:50:19 +0100, John Doe
[EMAIL PROTECTED] wrote:
Am Montag, 14. März 2005 03.30 schrieb Grant:
Thanks guys, I've almost got it. I need to save the title and URL of
each result in the array to a different scratch variable so I can
use it outside of the script.
Am Sonntag, 13. März 2005 23.47 schrieb Grant:
I've got an array returned from Google's API and I need to get the
data out of it. The best I can do right now is:
ARRAY(0x8262e088)
What you got is an reference to an array (an arrayref); printed out it looks
linke something above.
To access
Grant mailto:[EMAIL PROTECTED] wrote:
: I've got an array returned from Google's API and I need to
: get the data out of it. The best I can do right now is:
:
: ARRAY(0x8262e088)
:
: Can anyone help me out?
Looks like you are printing a reference to an array. You
can examine all its
I've got an array returned from Google's API and I need to get the
data out of it. The best I can do right now is:
ARRAY(0x8262e088)
What you got is an reference to an array (an arrayref); printed out it looks
linke something above.
To access the array referenced to it must be
Am Montag, 14. März 2005 02.16 schrieb Grant:
[...]
Thanks guys, I've almost got it. I need to save the title and URL of
each result in the array to a different scratch variable so I can
use it outside of the script. The following works great, but of
course it only saves the last set of
Thanks guys, I've almost got it. I need to save the title and URL of
each result in the array to a different scratch variable so I can
use it outside of the script. The following works great, but of
course it only saves the last set of results from the loop.
foreach my $result
Am Montag, 14. März 2005 03.30 schrieb Grant:
Thanks guys, I've almost got it. I need to save the title and URL of
each result in the array to a different scratch variable so I can
use it outside of the script. The following works great, but of
course it only saves the last set of
Hi Jeffrey.
There are several questions here, so I've answered in-line.
Jeffrey N Dyke wrote:
I had a simple array in mind, but as i got reacquainted with PERL, with the
help of the list, i realized i was thinking to small. (that's always
dangerous)
On the contrary, I think thinking BIG is
Hi Jeffrey.
There are several questions here, so I've answered in-line.
Rob, thanks a ton. that worked perfectly, as has the rest of the
processing of the larger hash. Thought i'd address the build portion
below, to see if i'm not utilizing PERL's strengths correctly. First PERL
i've
On Feb 19, 2004, at 1:25 PM, [EMAIL PROTECTED] wrote:
Thought i'd address the build portion below, to see if i'm not
utilizing PERL's strengths correctly. First PERL i've written in 3+
years.
Perl. The language you are relearning is called Perl, not PERL. ;)
James
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To unsubscribe,
PROTECTED]
Sent: Monday, August 04, 2003 11:50
To: [EMAIL PROTECTED]
Subject: Re: arrays
Hi,
if we have @routers.
you can do this
my ($c, $line);
$c=0;
foreach $line(@routers){
$line = $line. P *NULL*;
push @newrouters, $line;
}
or
to use the $c
foreach $line (@routers
@array = map {$_ P *NULL*} (@array);
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Monday, August 04, 2003 12:18 PM
To: [EMAIL PROTECTED]
Subject: arrays
Hi there,
I've got an array of lines, split up by spaces as follows:
Sun-router rack1.2 leeds
Hi,
if we have @routers.
you can do this
my ($c, $line);
$c=0;
foreach $line(@routers){
$line = $line. P *NULL*;
push @newrouters, $line;
}
or
to use the $c
foreach $line (@routers){
@routers[$c] = $line. P *NULL*;
$c++;
}
Jonathan Musto [EMAIL PROTECTED] wrote in
Hi,
sorry my last post
but actually this is quite good and better
@array = map {$_ P *NULL*} (@array);
Award
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[EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
: @array = map {$_ P *NULL*} (@array);
That solution makes a nice subroutine:
my @array = (
'Sun-router rack1.2 leeds',
'Cisco-router rack3.2 skem',
'Sun-switch rack2.3 manchester', );
concat_array( ' P *NULL*', [EMAIL PROTECTED] );
Jonathan Musto wrote:
Hi there,
Hello,
I've got an array of lines, split up by spaces as follows:
Sun-router rack1.2 leeds
Cisco-router rack3.2 skem
Sun-switch rack2.3 manchester
etc.
How can i add the following to the end of each line, P *NULL*?... e.g.
Sun-router rack1.2
R. Joseph Newton wrote:
Rob Dixon wrote:
James Edward Gray II wrote:
On Friday, June 6, 2003, at 03:32 AM, R. Joseph Newton wrote:
The player's name IS the number. No other numbering system is
needed. The players name is NEVER stored in the hash, AFAIK. The
name is used
R. Joseph Newton wrote:
Rob Dixon wrote:
James Edward Gray II wrote:
On Friday, June 6, 2003, at 03:32 AM, R. Joseph Newton wrote:
The player's name IS the number. No other numbering system is
needed. The players name is NEVER stored in the hash, AFAIK. The
name is used
On Friday, June 6, 2003, at 07:05 PM, R. Joseph Newton wrote:
The point here is that the essential purpose of the key is that of a
pointer, rather thanas data in itself.
There are applications of a Perl hash where one does not even need to
use the value, finding all the unique words in a
Stuart White wrote:
Right now my array is just like that, minus the
numbers. So what I want to do is assign the array to
a hash. If I were to do that, my understanding is
that the names would be keys and the numbers values,
and doing such an assignment in a loop would cause
some entries
Stuart White wrote:
Hey, thanks that worked!
--- James Edward Gray II [EMAIL PROTECTED]
wrote:
snip
I don't seen any reason to use the array at all, so
I've removed it.
If you had one that I just didn't know about, send
it on back.
That's how I tried to solve this piecewise, I
Stuart White wrote:
Ok, I think I get it. the $_ is printing the player
name, (though I don't know why I'm not using $1
$1 is a special-purpose variable used only in relation to regexes.
The default variable for looping structures will be contained in $_.
instead for that) and the
Stuart White wrote:
This does make it clearer, but not entirely. Is this
what is happening: the loop starts, and goes
immediately into the if statement. when the regex
finds a line with Jump Shot it stores that in $2,
and the player name in $1. The next thing it does,
and I'm not quite
On Friday, June 6, 2003, at 03:32 AM, R. Joseph Newton wrote:
The player's name IS the number. No other numbering system is
needed. The players name is NEVER stored in the hash, AFAIK. The
name is used to feed a hashing function, which renders an index into
the storage of the hash structure.
James Edward Gray II wrote:
On Friday, June 6, 2003, at 03:32 AM, R. Joseph Newton wrote:
The player's name IS the number. No other numbering system is
needed. The players name is NEVER stored in the hash, AFAIK. The
name is used to feed a hashing function, which renders an index into
R. Joseph Newton wrote:
Stuart White wrote:
This does make it clearer, but not entirely. Is this
what is happening: the loop starts, and goes
immediately into the if statement. when the regex
finds a line with Jump Shot it stores that in $2,
and the player name in $1. The next
James Edward Gray II wrote:
On Friday, June 6, 2003, at 03:32 AM, R. Joseph Newton wrote:
The player's name IS the number. No other numbering system is
needed. The players name is NEVER stored in the hash, AFAIK. The
name is used to feed a hashing function, which renders an index into
Rob Dixon wrote:
James Edward Gray II wrote:
On Friday, June 6, 2003, at 03:32 AM, R. Joseph Newton wrote:
The player's name IS the number. No other numbering system is
needed. The players name is NEVER stored in the hash, AFAIK. The
name is used to feed a hashing function,
On Monday, June 2, 2003, at 08:10 PM, Stuart White wrote:
Ok, I think I get it. the $_ is printing the player
name, (though I don't know why I'm not using $1
instead for that)
$1 contains the first capture of the last match we did. When you're
using match variables like that, store them
On Monday, June 2, 2003, at 10:06 PM, Stuart White wrote:
This does make it clearer, but not entirely. Is this
what is happening: the loop starts, and goes
immediately into the if statement. when the regex
finds a line with Jump Shot it stores that in $2,
and the player name in $1.
Yes, this
This is good explanation. Thanks.
Hi Stuart,
This is so useful and easy that it's worth really
understanding. Here's a
non-programming metaphor:
As each player makes a shot he calls out his name
($1): smith. The
scorekeeper says, ah, smith ($score{smith}) - let's
add 1 to Smith's
Since it seemed like a nice exercise to work on I played with this some
myself. Goals being to try to avoid global variables, use subroutines and
keep MAIN 'uncluttered' and pass arguments to subs as needed.
I think I did okay (holding breath), but I'm wondering about things like:
my
On Tue, Jun 03, 2003 at 08:36:05PM +0200 Kevin Pfeiffer wrote:
Since it seemed like a nice exercise to work on I played with this some
myself. Goals being to try to avoid global variables, use subroutines and
keep MAIN 'uncluttered' and pass arguments to subs as needed.
I think I did okay
In article [EMAIL PROTECTED], Tassilo Von Parseval wrote:
[...]
If you from then on referred to elements of the hash with something like
$score_ref-{ key };
then this would be it. It depends on what you want. By dereferencing the
whole data-structure you're essentially creating a copy.
On Monday, June 2, 2003, at 04:02 PM, Stuart White wrote:
Also, to get the numbers to the right of the colon,
I'd have to have a count for each occurrence of each
player, how might I do that?
Perhaps with something like:
my %hash;
$hash{ (split /:/, $_)[0] }++ foreach (@array);
That just walks
Hmm, this might actually be more productive I showed
less abstract example lines. (I couldn't do this
before as I didn't have the code in front of me.)
Here is an example of the lines that my code is
selecting and then extracting a player name and jump
shot attempt(working on this part) then
PROTECTED]To: [EMAIL PROTECTED]
m cc:
Subject: Re: arrays
:
Subject: Re: arrays and hashes
06/02/2003 05:12
You should probably use an array to keep the correct
order and a hash to
keep the count:
I don't really understand what you mean.
__
Do you Yahoo!?
Yahoo! Calendar - Free online calendar with sync to Outlook(TM).
http://calendar.yahoo.com
--
To
On Monday, June 2, 2003, at 05:12 PM, Stuart White wrote:
Hmm, this might actually be more productive I showed
less abstract example lines.
Not sure I understand perfectly yet, but I'll give it another go.
I don't seen any reason to use the array at all, so I've removed it.
If you had one
Hey, thanks that worked!
--- James Edward Gray II [EMAIL PROTECTED]
wrote:
snip
I don't seen any reason to use the array at all, so
I've removed it.
If you had one that I just didn't know about, send
it on back.
That's how I tried to solve this piecewise, I thought
an array was necessary,
Hey, thanks that worked!
--- James Edward Gray II [EMAIL PROTECTED]
wrote:
snip
I don't seen any reason to use the array at all, so
I've removed it.
If you had one that I just didn't know about, send
it on back.
That's how I tried to solve this piecewise, I thought
an array was necessary,
One more thing, if I want to sort the hash
alphabetically by key where do I put the sort
function?
I tried it before the while loop that does the
printing and on the each function
(sort(each(%linehash))) and that just gave me numbers
first, colon, player names. and I figure that it
wouldn't
On Monday, June 2, 2003, at 06:54 PM, Stuart White wrote:
I don't understand this syntax:
$linehash{$1}++;
Could you explain it to me?
Absolutely.
This is a common Perl technique, often used with a hash named '%seen'
because that's exactly what it's keeping track of. $1 is where you
were
Print it like this, it's easier:
print $_ : $linehash{$_}\n foreach (sort keys %linehash);
James
On Monday, June 2, 2003, at 07:03 PM, Stuart White wrote:
One more thing, if I want to sort the hash
alphabetically by key where do I put the sort
function?
I tried it before the while loop that
Ok, I think I get it. the $_ is printing the player
name, (though I don't know why I'm not using $1
instead for that) and the $linehash{$_} means, in
English, the value of the key stored in $_ is that
right?
Thanks for all your help.
--- James Edward Gray II [EMAIL PROTECTED]
wrote:
Print it
This does make it clearer, but not entirely. Is this
what is happening: the loop starts, and goes
immediately into the if statement. when the regex
finds a line with Jump Shot it stores that in $2,
and the player name in $1. The next thing it does,
and I'm not quite sure how, is it populates a
In article [EMAIL PROTECTED], Stuart
White wrote:
This does make it clearer, but not entirely. Is this
James wrote:
This is a common Perl technique, often used with a
hash named '%seen'
because that's exactly what it's keeping track of.
$1 is where you
were capturing your names, I just
John W. Krahn wrote at Mon, 02 Jun 2003 14:44:41 -0700:
You should probably use an array to keep the correct order and a hash to
keep the count:
Or to use Tie::IxHash.
Greetings,
Janek
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David Newman wrote:
Greetings. I have a newbie question about passing arrays into a subroutine
(and getting return values as well).
Hi David,
I can't help much as far as passing or returning whole arrays, but there is a much
better way to access arrays from inside a function. I'll show you
You need to pass the array to the function by reference, here's the fix.
spin([EMAIL PROTECTED]);
sub spin
{
$arr = shift;
for (; $count 0; $count--)
{
push(@$arr, $start++);
}
}
but if all you want to do is to populate your array with value between
1025 to 1035, here's a
Kris Gaethofs wrote:
Hi,
I could use some help with the following problem:
I have this input file that looks like this (after some processing):
%1%MO%1s%.%-.0003%.%.0003%.0002%.0006%-.0005%.0020%-.0035%.0006
%2%MO%1s%-.0001%-.0021%-.0003%.0018%.0015%.0042%-.0034%.0136%-.0234%.0042
I know I am missing a lot in my knowledge, but I'm trying to figure
something out seemingly am in a hole...
MySQL can do a lot of this for you, I believe...
You want a random record from the database and retrieve a particular field
from that record:
# Untested, but you would call this
here is an example of MySQL code to pick a random
record using some select criteria. i use it in a
homepage for an online store where my client has
random items from his catalog displayed as featured
items (really nothing more than picking a random
record from the 10,000+ items!)...
First I need to tell you that I am not a MySQL specialist and my opinion
might be wrong butI think that:
1. You'll better use where day=$day and where month=$month because it works
faster than using the like operator.
2. I think MySQL has a function for returning random numbers, so you better
-Original Message-
From: Tobin, Elliot [mailto:[EMAIL PROTECTED]]
Sent: Friday, September 06, 2002 9:55 AM
To: '[EMAIL PROTECTED]'
Subject: Arrays inside
I have the following as my data inside a package:
my $dataBlock = { isInsertable= $isInsertable,
see inline comments:
-Original Message-
From: Tobin, Elliot [mailto:[EMAIL PROTECTED]]
Sent: Friday, September 06, 2002 9:55 AM
To: '[EMAIL PROTECTED]'
Subject: Arrays inside
I have the following as my data inside a package:
my $dataBlock = { isInsertable=
On Friday, September 6, 2002, at 08:54 AM, Tobin, Elliot wrote:
I have the following as my data inside a package:
my $dataBlock = { isInsertable= $isInsertable,
fields = undef,
fields =
On Sep 6, Tobin, Elliot said:
sub setFields
{
my ($inBlock, @fieldList) = @_;
foreach my $i (@fieldList)
{
push($inBlock-{'fields'}, $i);
You'd need to say
push @{ $inBlock-{fields} }, $i;
}
return $inBlock;
}
But given your current function, it's far faster
I thank you will have to use substr since you have daffygoofy and you have
nothing to split on, so use substr to get the data.
Wags ;)
-Original Message-
From: Stuart Clark [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, February 26, 2002 19:57
To: perllist
Subject: arrays + split
On Feb 27, Stuart Clark said:
Hi All,
How do i gather an array of data from a line which has no delimiters.
The data is put into positions relative to the start of the line.
#string 1 will be position 1-5 on the line
#string 2 will be position 6-15 on the line
#string 3 will be position 16-23
On Feb 25, Carlo Sayegh said:
print \nPlease state below your duties as $function
adminstrator. Press enter then^D twice when done.\n\n;
while () {
if ( (/^DONE/) ) {
last;
}
}
@data1 = STDIN;
chomp (@data1);
Uh do you know what that while loop is
In article [EMAIL PROTECTED] wrote Ron
Goral
[EMAIL PROTECTED]:
Can someone please tell me why the following code only returns the last element in
the referenced
array? If I put the foreach routine inside the while loop, I get a printout of each
element in
both the $sqlRes reference and
On Tue, 12 Feb 2002, Steven M. Klass wrote:
Let's start off with some simple code..
my $arg = SomeFunction ( my @arry = qw/one two three/)
sub SomeFunction {
my @array = @_[0];
No, you are only grabbing the first element of @_. You should either pass
the array as a reference
Hi all,
Let's start off with some simple code..
my $arg = SomeFunction ( my @arry = qw/one two three/)
sub SomeFunction {
my @array = @_[0];
for (my $i =0; i @array; i ++ ) {
print $array[0][$i]
}
}
Ok now I understand what the problem is, but I don't
know how to fix it.
how does shift work? In other words what if I do this
Somefunction($var1, \@arry)
sub SomeFunction {
my $var = $_[0]
my $array = shift;
foreach(@{$array}) {
print $_\n;
}
}
How does the shift operator know which is which? I called it specifically
. McCoy
Cc: [EMAIL PROTECTED]
Subject: Re: Arrays 1x3 or 3x1 - The real questions
how does shift work? In other words what if I do this
Somefunction($var1, \@arry)
sub SomeFunction {
my $var = $_[0]
my $array = shift;
foreach(@{$array}) {
print $_\n
;
then $var2 will be an array reference to @arry.
HTH,
Tanton
- Original Message -
From: Steven M. Klass [EMAIL PROTECTED]
To: Brett W. McCoy [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Tuesday, February 12, 2002 4:20 PM
Subject: Re: Arrays 1x3 or 3x1 - The real questions
how does shift work
On Feb 12, Steven M. Klass said:
Somefunction($var1, \@arry)
sub SomeFunction {
my $var = $_[0];# XXX you were missing a ; here
my $array = shift;
Uh, $array and $var have the same value now. shift() removes the first
element from an array (defaulting to @_) and returns it.
[EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Tuesday, February 12, 2002 4:20 PM
Subject: Re: Arrays 1x3 or 3x1 - The real questions
how does shift work? In other words what if I do this
Somefunction($var1, \@arry)
sub SomeFunction {
my $var = $_[0]
my $array = shift;
foreach
On Jan 13, Keith Nasman said:
@a = qw/this is the text/;
$a = three;
print The third word is ${a}[2]\n;
print The third word is $a[2]\n;
produce this:
The third word is three[2]
The third word is the
The reason three is printed is because ${a}[2] is another way of
writing $a . [2] -- that is,
Prasanthi Tenneti wrote:
In my prog ,I have 6 different arrays.And all first elemnts should do something.ANd
all 2nd elements in arrays should do something and so on .
Iam unable to write code in perl for this.PLs help me.
Let's assume, the 6 different arrays are declared as array1 ..
On Sat, Sep 29, 2001 at 11:08:11AM -0400, Darfler, Jim (J.E.) wrote:
How would I go about sending to a file the volume names and dates sorted
by the date?
Open the file, iterate through your data structure, write what data you want
to the file, close the file.
I had thought to put the
Hi Jim,
I'm not entirely clear on what you have in the first array, but it sounds
like it won't be of much use since you already have a hash with all the
information you need.
You're probably going to have to create a new data structure that keys off
of the date so you can search/sort based on
On Sep 25, [EMAIL PROTECTED] said:
are there multi-dimensional arrays in perl?
There are multi-dimensional data structures (arrays and hashes) in Perl.
I wrote something for perl.com a while ago that you might want to read in
conjunction with the standard docs:
On Tue, 25 Sep 2001 [EMAIL PROTECTED] wrote:
are there multi-dimensional arrays in perl?
Yes, but not exactly, if you are thinking in terms of multi-dimensional
arrays as they are in C. In Perl, we build up complex data structures by
using references:
my @multiarray = ( [1, 2, 3, 4], [5, 6,
Troy Denkinger [EMAIL PROTECTED] wrote:
which indicates that the first array is empty. The problem is the undef of
@temp. What you've put into @array is a reference to @temp. When you undef
it, you're undefing the array that the reference in array points to.
In any event, I can't figure out
Michael Fowler [EMAIL PROTECTED] wrote:
@data[0] = (, , );
#and
@data[1] = (1, 2, 3);
This notation is almost certainly incorrect, what you probably meant to say
is:
$data[0] = [, , ];
$data[1] = [ 1, 2, 3];
You're right, I wrote a wrong syntax.
I want to make @data[0] on the
Can you explain what your trying to achieve??
You want an array called @data which consists of all the elements from
@dataumi2? Where does the second array with empty element values come from,
why is it needed?
to assign @data with all the elements from @dataumi2 do this
@data = @dataumi2;
On Jul 30, Matija Papec said:
my $i;
my (@datumi2) = (1..100);
my (@temp, @data);
# block for optimization
for $i (0..$#datumi2) { push @temp, }
push @data, \@temp;
undef @temp;
# end of block for optimization
push @data, \@datumi2;
You can use the length of an array with the x
On Monday 30 July 2001 12:05, Matija Papec wrote:
Program below works fine but I wander how to optimize this; it looks very
ugly. The final result have to be @data which contains two arrays. First
array have to be equal size of second array(@datumi2) and all their values
have to be .
Hmmm,
John Edwards [EMAIL PROTECTED] wrote:
Can you explain what your trying to achieve??
You want an array called @data which consists of all the elements from
@dataumi2? Where does the second array with empty element values come from,
why is it needed?
ok, to simplify let's suppose that
@datumi2 =
On Mon, Jul 30, 2001 at 08:02:58PM +0200, Matija Papec wrote:
ok, to simplify let's suppose that
@datumi2 = (1, 2, 3);
#so final result should look like this:
@data[0] = (, , );
#and
@data[1] = (1, 2, 3);
This notation is almost certainly incorrect, what you probably meant to say
is:
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