Algebraically, E = [z(a/2) / SQRT(n)] x SD, so it must be that the margin of
error (maximum error as you called it) is a multiple of the population
standard deviation. Keep in mind what these values represent. E is the
margin of error of the estimate of mu, the population mean. SD
i think you are asking the wrong question ... because, as far as i know ...
there is only really one standard deviation concept ... square root of the
variance (average of squared deviations around the mean in a set of data) ...
perhaps what you are really interested in is HOW should
On Sun, 11 Nov 2001 01:30:27 +1100, David Muir
[EMAIL PROTECTED] wrote:
Presently the Gaming Industry of Australia is attempting to define various
new 'definitions of Standard Deviation'...in a concept to define infield
metrics for the analysis of machines in terms which imply whether
Presently the Gaming Industry of Australia is attempting to define various
new 'definitions of Standard Deviation'...in a concept to define infield
metrics for the analysis of machines in terms which imply whether a machine
is being operated with respect to its defined percentage or in fact
Edward Dreyer wrote:
A colleague of mine - not a subscriber to this helpful list - asked me if
it is possible for the standard deviation
to be larger than the mean. If so, under what conditions?
Of course - for example, if you analyse mean-corrected data...
It can even happen with data
Well, yes. the mean and standard deviation are not 'linked' for data with a
Normal distribution.
Dale Glaser asked:
Well, what about the standard normal distribution: N(0,1)?
The mean is 0, the standard deviation, 1.
If you add the restriction that the data not be less than 0, and allow
possible for
the SD to be larger than the mean, but the distribution will then be not
symmetric.
Alan
Edward Dreyer wrote:
A colleague of mine - not a subscriber to this helpful list - asked me if
it is possible for the standard deviation
to be larger than the mean. If so, under what
A colleague of mine - not a subscriber to this helpful list - asked me if
it is possible for the standard deviation
to be larger than the mean. If so, under what conditions?
At first blush I do not think so - but then I believe I have seen
some research results in which standard
Title: RE: Mean and Standard Deviation
Edward Dreyer writes:
A colleague of mine - not a subscriber to this helpful
list - asked me if it is possible for the standard deviation
to be larger than the mean. If so, under what conditions?
At first blush I do not think so - but then I
At 04:32 PM 10/12/01 -0500, you wrote:
A colleague of mine - not a subscriber to this helpful list - asked me if
it is possible for the standard deviation
to be larger than the mean. If so, under what conditions?
what about z scores??? mean = 0 and sd = 1
At first blush I do not think so
In article [EMAIL PROTECTED], Edward
Dreyer [EMAIL PROTECTED] wrote:
A colleague of mine - not a subscriber to this helpful list - asked me if
it is possible for the standard deviation
to be larger than the mean. If so, under what conditions?
Easily. Any highly skewed distribution
Title: RE: Mean and Standard Deviation
Well, what
about the standard normal distribution: N(0,1)?
Dale N. Glaser, Ph.D.
Pacific Science
Engineering Group
6310 Greenwich
Drive; Suite 200
San Diego, CA
92122
Phone: (858)
535-1661 Fax: (858) 535-1665
http://www.pacific-science.com
hat if we wanted to be within 3 points of mu with our sample mean
the
population standard deviation or sigma were 15?
n = ((1.96 * 5) / 3)^2 = about 11 ...
only would take a SRS of about 11 to be within 3 points of the true mu
value in your 95% confidence interval
Donald,
I totally agree w/your point about the stratification of the sample. My
facts were set up merely for simplicity's sake notwithstanding their clear
artificiality.
The only instances of multiple samples I have seen are in textbooks to prove
the CLT; that w/increasing numbers of sample
On Sun, 30 Sep 2001 00:34:40 GMT, John Jackson
[EMAIL PROTECTED] wrote:
Here is my solution using figures which are self-explanatory:
Sample Size Determination
pi = 50% central area 0.99
confid level= 99%
8 Sep 2001, John Jackson wrote in part:
My formula is a rearrangement of the confidence interval formula shown
below for ascertaining the maximum error.
E = Z(a/2) x SD/SQRT N
The issue is you want to solve for N, but you have no standard
deviation value.
Oh, but you do. In the proble
On Sun, 30 Sep 2001, John Jackson wrote:
Here is my solution using figures which are self-explanatory:
Sample Size Determination
pi = 50% central area 0.99
confid level= 99% 2 tail area 0.5
sampling
On Fri, 28 Sep 2001, John Jackson wrote in part:
My formula is a rearrangement of the confidence interval formula shown
below for ascertaining the maximum error.
E = Z(a/2) x SD/SQRT N
The issue is you want to solve for N, but you have no standard
deviation value
maximum error.
E = Z(a/2) x SD/SQRT N
The issue is you want to solve for N, but you have no standard
deviation value.
Oh, but you do. In the problem you formulated, unless I
misunderstood egregiously, you are seeking to estimate the proportion of
defective (or pirated, or whatever) CDs in a
* sigma) / e
but, we don't want sqrt n ... we WANT n!
n = ((1.96 * sigma)/ e) ^2
so, what if we wanted to be within 3 points of mu with our sample mean the
population standard deviation or sigma were 15?
n = ((1.96 * 5) / 3)^2 = about 11 ...
only wo
Really sorry.
My formula is a rearrangement of the confidence interval formula shown below
for ascertaining the maximum error.
E = Z(a/2) x SD/SQRT N
The issue is you want to solve for N, but you have no standard deviation
value.
The formula then translates into n = (Z(a/2)*SD)/E)^2Note
? we can rearrange the formula ...
sqrt n = (1.96 * sigma) / e
but, we don't want sqrt n ... we WANT n!
n = ((1.96 * sigma)/ e) ^2
so, what if we wanted to be within 3 points of mu with our sample mean the
population standard deviation or sigma were 15
? What's it a formula for?
could you express E as a % of a standard deviation .
What's E? The above formula doesn't have a (capital) E.
What is Z? n? e?
In other words does a .02 error translate into .02/1 standard deviations,
assuming you are dealing w/a normal distribution?
? How does thi
re: the formula:
n = (Z?/e)2
This formula hasn't come over at all well. Please note that newsgroups
work in ascii. What's it supposed to look like? What's it a formula for?
could you express E as a % of a standard deviation .
What's E? The above formula doesn't have a (capital) E.
re: the formula:
n = (Z?/e)2
could you express E as a % of a standard deviation .
In other words does a .02 error translate into .02/1 standard deviations,
assuming you are dealing w/a normal distribution
Thanks for the formula, but I was really interested in knowing what % of a
standard deviation corresponds to E.
In other words does a .02 error translate into .02/1 standard deviations?
Graeme Byrne [EMAIL PROTECTED] wrote in message
9orn26$m80$[EMAIL PROTECTED]">news:9orn26$m8
At 04:49 PM 9/26/01 +, John Jackson wrote:
re: the formula:
n = (Z?/e)2
could you express E as a % of a standard deviation .
In other words does a .02 error translate into .02/1 standard deviations,
assuming you are dealing w/a normal distribution?
well, let's see ... e
If you have a confidence level of 90% and an error estimate of 4% and don't
know the std deviation, is there a way to express the error estimate as a
fraction of a std deviation?
=
Instructions for joining and leaving this list
Referring your example:
variance = 2_nd moment - (1_st moment),
that is:
2_nd moment = 0^2 * 0.2 + 1^2 * 0.3 + 2^2 * 0.2 + 3^2 * 0.2 + 4^2 * 0.1 =
4.5
1_st moment = 0 * 0.2 + 1 * 0.3 + 2 * 0.2 + 3 * 0.2 + 4 * 0.1 = 1.7
then
variance = 4.5 - (1.7)^2 = 1.61
then
standard deviation = sqrt(1.61
Chris Chiu wrote:
Dear friends:
Does anyone know / remember how to obtain the standard deviation of a set
of numbers given only a frequency table?
e.g.,
xf(x)
00.2
10.3
20.2
30.2
40.1
(0) This is not a frequency table, it's a relative frequency
Dear friends:
Does anyone know / remember how to obtain the standard deviation of a set
of numbers given only a frequency table?
e.g.,
xf(x)
00.2
10.3
20.2
30.2
40.1
Many thanks.
Chris
=
Instructions
as the X values are fixed ... and the p values ... then you could
do it that way ... of course, without the X values .. you are lost
At 09:35 AM 1/6/01 -0500, Chris Chiu wrote:
Dear friends:
Does anyone know / remember how to obtain the standard deviation of a set
of numbers given only a frequency
Chris Chiu wrote:
Dear friends:
Does anyone know / remember how to obtain the standard deviation of a set
of numbers given only a frequency table?
e.g.,
xf(x)
00.2
10.3
20.2
30.2
40.1
Many thanks.
Chris
calculate average value "a"
change
QUESTIONS
Dear friends:
Does anyone know / remember how to obtain the standard deviation of a set
of numbers given only a frequency table?
e.g.,
xf(x)
00.2
10.3
20.2
30.2
40.1
Many thanks.
Chris
ONE POSSIBLE ANSWER:
Here is a worked solution. I used the Windows
, bad game protection, etc..
The data I have is for each day, I have the calculated hold percentage for
each of the individual table games. There are multiple table games of each
type, for example there are 7 blackjack tables.
Q: I want to calculate the standard deviation and confidenc
Mark Solberg [EMAIL PROTECTED] wrote:
I've had some statistics coursework, probably just enough to be dangerous.
Here's my problem. By the way this is an actual problem, not theoretical.
I need to analyze the hold percentage on certain table games in the casino I
work at.
I should think that
Glen Barnett wrote:
In article [EMAIL PROTECTED],
Neil [EMAIL PROTECTED] wrote:
I was wondering what the standard deviation means exactly?
I've seen the equation, etc., but I don't really understand
what st dev is and what it is for.
I'm going to take a different tack
On Mon, 22 May 2000 13:24:25 +1000, "Glen Barnett"
[EMAIL PROTECTED] wrote:
I assume you're talking about sample standard deviations,
not population standard deviations (though interpretation
of what it represents is similar).
...
Note that the standard deviation can't exceed half
In article [EMAIL PROTECTED],
Neil [EMAIL PROTECTED] wrote:
I was wondering what the standard deviation means exactly?
I've seen the equation, etc., but I don't really understand
what st dev is and what it is for.
I am not a statistician as you can tell...
Even if you were, you might know
There are a couple of (practical) features of the standard deviation that are
worth noting.
First, as a *descriptor* of the variation in a distribution, it is generally not
very good. I mean this is the sense that if you want to visualise the amount of
variation in a distribution the SD is only
In article mtAB4.8354$[EMAIL PROTECTED],
[EMAIL PROTECTED] says...
My daughter has asked me if there are any tools / software programs that can
resolve standard deviations, while Excel can determine a standard deviation
of the Population, what formula is used for the
(A) 5th Standard Deviation
Robert A. Meyer asked what is / which software calculates
(A) 5th Standard Deviation
(B) 10th Standard Deviation
(C) 25th Standard Deviation
(D) 40'th Standard Deviation
and T.S. Lim answered,
I think you're looking for PERCENTILES.
I would say that there actually a related thing in robust
On Tue, 21 Mar 2000, Robert Meyer wrote:
My daughter has asked me if there are any tools / software programs
that can resolve standard deviations; while Excel can determine a
standard deviation of the Population, what formula is used for the
(A) 5th Standard Deviation
(B) 10th Standard
My daughter has asked me if there are any tools / software programs that can
resolve standard deviations, while Excel can determine a standard deviation
of the Population, what formula is used for the
(A) 5th Standard Deviation
(B) 10th Standard Deviation
(C) 25th Standard Deviation
(D) 40'th
In article mtAB4.8354$[EMAIL PROTECTED],
[EMAIL PROTECTED] says...
My daughter has asked me if there are any tools / software programs that can
resolve standard deviations, while Excel can determine a standard deviation
of the Population, what formula is used for the
There doesn't exist
How do I calculate pooled standard deviation? I have
study with group of exercisers following forward over
time. I want look at weight by category of calorie
intake. I look at standard deviation for weight for
each calorie group but want one overall standard
deviation. Is this valid? Thank
an omnibus anova, and take the square root of it.
Just curious: What are you planning to do with a pooled standard deviation?
Anna Geyer wrote:
How do I calculate pooled standard deviation? I have
study with group of exercisers following forward over
time. I want look at weight by category
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