Peter,
Thank you very much for your reply. Three weeks later I am realizing that
the 'NOT IN' solution I had above does not work after all. Accordingly, I
went back and looked at your solution and it is close but it only gives
NULL results I am looking for something that excludes challenges that
Cheers.
AB
-Original Message-
From: Richard Reina [mailto:gatorre...@gmail.com]
Sent: Saturday, 26 September 2015 1:09 AM
To: peter.braw...@earthlink.net
Cc: mysql@lists.mysql.com
Subject: Re: Trouble with LEFT JOIN
Peter,
Thank you very much for your reply. Three weeks later I am
I have the following two tables;
mysql> select * from challenge;
+++-++--+-+--+
| ID | PLR_ID | ACC_TYPE_ID | season | year | CHAR_ID |
+++-++--+-+--+
| 1 | 1 |
On 2015-09-04 9:40 AM, Richard Reina wrote:
I have the following two tables;
mysql> select * from challenge;
+++-++--+-+--+
| ID | PLR_ID | ACC_TYPE_ID | season | year | CHAR_ID |
2015-09-04 11:18 GMT-05:00 Peter Brawley :
> On 2015-09-04 9:40 AM, Richard Reina wrote:
>
>> I have the following two tables;
>>
>> mysql> select * from challenge;
>> +++-++--+-+--+
>> | ID | PLR_ID |
On 2015-09-04 11:39 AM, Richard Reina wrote:
2015-09-04 11:18 GMT-05:00 Peter Brawley >:
On 2015-09-04 9:40 AM, Richard Reina wrote:
I have the following two tables;
mysql> select * from challenge;
Hi Nitin
Thanks - I tried that and got 0 rows...
I have spent more time on describing my problem -- see below hopefully
this will make the issue more clear...
Rich
I have a MySQL database with a menu table and a product table.
- The products are linked to the menus in a one-to-many
Hello Rich,
On 8/27/2012 12:19 PM, rich gray wrote:
Hi Nitin
Thanks - I tried that and got 0 rows...
I have spent more time on describing my problem -- see below hopefully
this will make the issue more clear...
Rich
... snip ...
There are many resources out there that can tell you how to
I have a MySQL database with a menu table and a product table linked to
the menus *(each product can be linked to more than menu row)* and the
menus are nested.
The query is that when a user clicks on a menu entry then all products
linked to that entry *(there may be none)* will get displayed
that works.
Regards,
From: rich gray r...@richgray.com
To: mysql@lists.mysql.com
Sent: Monday, August 27, 2012 2:46 AM
Subject: Having trouble with SQL query
I have a MySQL database with a menu table and a product table linked to the
menus *(each product can
I really confussed about this. I don't know whether my mysql is 32bit or
64bit, so I just fresh installed mysql 5.5.27 for osx 10.6 64bit. And I did
reinstalled DBI and DBD::mysql
make give me a lot of warnings like warning: format not a string literal
and no format arguments
but make test did
On Wed, Aug 8, 2012 at 1:12 PM, Elim Qiu elim@gmail.com wrote:
But when I use browser for the system testing (perl_test.cgi and forum.pl),
both report me that DBD:mysql is not installed (or not available)
It's possible that DBD::mysql is installed in a place where it's not
in the library
responsabilité
pour le contenu fourni.
Date: Wed, 8 Aug 2012 13:28:42 -0400
Subject: Re: trouble with perl
From: per...@elem.com
To: elim@gmail.com
CC: mysql@lists.mysql.com
On Wed, Aug 8, 2012 at 1:12 PM, Elim Qiu elim@gmail.com wrote:
But when I use browser for the system
I can't find his phone number to call him.
-Original Message-
From: Martin Gainty [mailto:mgai...@hotmail.com]
Sent: Wednesday, August 08, 2012 12:22 PM
To: elim@gmail.com
Cc: mysql@lists.mysql.com
Subject: RE: trouble with perl
I know I had the same problem with PHP when mysql.dll
http://bixsolutions.net/forum/thread-18.html
-Original Message-
From: Elim Qiu [mailto:elim@gmail.com]
Sent: Monday, August 06, 2012 5:42 PM
To: mysql@lists.mysql.com
Subject: trouble with perl
To populate table for a perl forum, I got the following error:
aMac:mwf elim$ perl
Thanks Stillman Benjamin. The link is about the mismatch of 32/64 bit among
mysql, perl and os processor but I don't have that issues. My system is
missing DBD::mysql module, and I still have trouble with that.
On Tue, Aug 7, 2012 at 6:49 AM, Stillman, Benjamin
bstill...@limitedbrands.com
Hi,
This probably means you changed your MySQL libraries but didn't
recompile or reinstall DBD::mysql, Usually this kind of issue is
solved by reinstalling DBD::mysql in the same way that you previously
installed it, so it can build against your current libraries.
- Perrin
On Mon, Aug 6, 2012
To populate table for a perl forum, I got the following error:
aMac:mwf elim$ perl install.pl
dyld: lazy symbol binding failed: Symbol not found: _mysql_init
Referenced from:
/Library/Perl/5.10.0/darwin-thread-multi-2level/auto/DBD/mysql/mysql.bundle
Expected in: flat namespace
dyld: Symbol
2012/07/16 14:25 -0700, Rick James
Here's a different way to smooth numbers. It uses an exponential moving
average instead of the last 5.
SELECT Time,
@a := (9 * @a + Value) / 10 AS moving_avg
FROM tbl
JOIN ( SELECT @a := 0 ) AS x;
Notes:
* Make 10 larger or smaller, depending on
only the first few
rows.
-Original Message-
From: Hal?sz S?ndor [mailto:h...@tbbs.net]
Sent: Monday, July 16, 2012 8:25 PM
To: mysql@lists.mysql.com
Subject: RE: Trouble with Average
2012/07/16 14:25 -0700, Rick James
Here's a different way to smooth numbers. It uses
* @a := 0 should be changed to some reasonable starting value, else the graph
will be artificially low to start with.
-Original Message-
From: Hal?sz S?ndor [mailto:h...@tbbs.net]
Sent: Monday, July 09, 2012 7:48 PM
To: mysql@lists.mysql.com
Subject: Re: Trouble with Average
2012/07
2012/07/07 12:10 -0600, Albert Padley
I have a log file that captures data from various sensors every minute that
we use to draws graphs on our website.
The table looks like this:
CREATE TABLE `log` (
`id` int(14) NOT NULL auto_increment,
`VarName` varchar(255) NOT NULL,
`TimeString`
I have a log file that captures data from various sensors every minute that
we use to draws graphs on our website.
The table looks like this:
CREATE TABLE `log` (
`id` int(14) NOT NULL auto_increment,
`VarName` varchar(255) NOT NULL,
`TimeString` datetime NOT NULL,
`VarValue`
Hey list,
Got another strange problem.
I'm in the process of migrating a 4.1 server to a 5.1. Replication is not
compatible between them, so I have an intermediate 5.0 server. Setup is
thus:
4.1 - 5.0 - 5.1
The server-id is different on all servers. It's been soft-set, followed by a
flush
Darn, it's not working after all.
SELECT
people.*,
COUNT ( DISTINCT cars.car_id ) AS car_count,
COUNT ( DISTINCT pets.pet_id ) AS pet_count,
SUM ( IF ( pets.date_bought NOW() - INTERVAL 7 DAY, 1, 0 ) ) AS
new_pet_count
WHERE...etc
car_count and pet_count are calculating correctly, but
You are asking for all records form all tables. So, If 1 person has 1 car
and 1 pet, there will be 2 records returned for that 1 person.
You'll need to use SUM() instead of COUNT():
SELECT people.*,
SUM(IF(cars.id IS NULL,0,1)) AS car_count,
SUM(IF(pets.id IS NULL,0,1)) AS pet_count,
Thanks, this solved it!
On Nov 2, 2009, at 12:37 AM, Michael Dykman wrote:
I suspect 'distinct' might help you out here.
SELECT
people.*,
count(distinct cars.car_id) as car_count,
count(distinct pets.pet_id) as pet_count
--
MySQL General Mailing List
For list archives:
Johnny - Your solution might actually help me solve my next step,
which is to also return a count of pets bought only within the last 7
days. Something like this:
SELECT people.*,
SUM(IF(cars.id IS NULL,0,1)) AS car_count,
SUM(IF(pets.id IS NULL,0,1)) AS pet_count,
SUM ( IF (
Yes, I don't see why that wouldn't work...
On Mon, Nov 2, 2009 at 11:09 AM, Brian Dunning br...@briandunning.comwrote:
Johnny - Your solution might actually help me solve my next step, which is
to also return a count of pets bought only within the last 7 days. Something
like this:
Hi all -
I have a table of PEOPLE, and a table of CARS owned by various people,
and a table of PETS owned by various people. Each person may have 0 or
more pets, and each person may have 0 or more cars. I'm trying to
return a list of all the people, showing how many pets each person
has,
Hi Martin,
Sorry, I am not able to understand this. Can you explain in detail
please?
-Karthik
From: Martin Gainty [mailto:[EMAIL PROTECTED]
Sent: Wednesday, October 15, 2008 6:56 PM
To: Krishna Chandra Prajapati; Karthik Pattabhiraman
Cc: mysql@lists.mysql.com
Subject: RE: Trouble
: Re: Trouble with large data in MySql
Hi Karthik,
You have many columns in a single table (although you can). But, if you
break the below table into two tables ( Vertical partitioning). It will
help you to run your query faster. You haven't shown join_buffer_size
and sort_buffer_size.
Secondly
: Trouble with large data in MySql
Hi Karthik,
You have many columns in a single table (although you can). But, if you
break the below table into two tables ( Vertical partitioning). It will help
you to run your query faster. You haven't shown join_buffer_size and
sort_buffer_size.
Secondly
with this?
I have 6GB RAM, 2 cores and 7200 RPM disk with 1TB size.
Thanks in advance
Karthik
*From:* Krishna Chandra Prajapati [mailto:[EMAIL PROTECTED]
*Sent:* Wednesday, October 15, 2008 3:43 PM
*To:* Karthik Pattabhiraman
*Cc:* mysql@lists.mysql.com
*Subject:* Re: Trouble
:[EMAIL PROTECTED]
Sent: Wednesday, October 15, 2008 3:43 PM
To: Karthik Pattabhiraman
Cc: mysql@lists.mysql.com
Subject: Re: Trouble with large data in MySql
Hi,
It depends on your query using join and sort. Also, on how much ram you
have. You can refer to huge_my.cnf
You can find huge_my.cnf
records
per month. We are having trouble getting results from MySql as it takes
about 4-5 hours to complete for each query. We are using this primarily
for reporting purposes.
My table schema is as follows
SMAS Table:
Column Name
Type
Key
adnetwork
for such large
datasets.
Hope this helps!
John
We have 4 tables in which we have approximately 40 Million records
per month. We are having trouble getting results from MySql as it
takes about 4-5 hours to complete for each query. We are using this
primarily for reporting purposes
with explain.
On Wed, Oct 8, 2008 at 4:00 PM, Karthik Pattabhiraman
[EMAIL PROTECTED] wrote:
Hi,
We have 4 tables in which we have approximately 40 Million records
per month. We are having trouble getting results from MySql as it takes
about 4-5 hours to complete for each query. We are using
@lists.mysql.com
Subject: Trouble with large data in MySql
Hi,
We have 4 tables in which we have approximately 40 Million records
per month. We are having trouble getting results from MySql as it takes
about 4-5 hours to complete for each query. We are using this primarily
for reporting purposes.
My
Hi,
We have 4 tables in which we have approximately 40 Million records
per month. We are having trouble getting results from MySql as it takes
about 4-5 hours to complete for each query. We are using this primarily
for reporting purposes.
My table schema is as follows
SMAS Table
Eben, all,
I'm very sorry this got out of sight for so long :-(
When I first read your mail, I had no idea, and then it was hidden.
Just now, I check it again and detect what may explain this.
I quote nearly the full mail leading to this, so that you readers need
not scan your archives.
Hi Eben, all !
Eben schrieb:
I have the following tables:
table1
---
id1
some_field
table2
---
id
id1
score
table3
---
id
id1
score
I then have the following query:
SELECT table1.id,SUM(table2.score) as table2_score
FROM table1, table2
WHERE table1.some_field = 'value'
AND
Hi Joerg,
Joerg Bruehe wrote:
Hi Eben, all !
Eben schrieb:
I have the following tables:
table1
---
id1
some_field
table2
---
id
id1
score
table3
---
id
id1
score
I then have the following query:
SELECT table1.id,SUM(table2.score) as table2_score
FROM table1, table2
WHERE
I have the following tables:
table1
---
id1
some_field
table2
---
id
id1
score
table3
---
id
id1
score
I then have the following query:
SELECT table1.id,SUM(table2.score) as table2_score
FROM table1, table2
WHERE table1.some_field = 'value'
AND table2.id1 = table1.id
GROUP BY
What you need, basically, is to combine two queries, one of which addresses
t1 and t2 while the other addresses t1 and t3. Create two views similar to
your first query and then join the two views on t1.id and you'll get what
you're after.
hth,
Arthur
On Thu, Jun 5, 2008 at 3:44 PM, Eben [EMAIL
Eben [EMAIL PROTECTED] wrote on 06/05/2008 02:44:42 PM:
I have the following tables:
table1
---
id1
some_field
table2
---
id
id1
score
table3
---
id
id1
score
I then have the following query:
SELECT table1.id,SUM(table2.score) as table2_score
FROM table1,
Hi Edward,
(see below)
Edward Corbett wrote:
Hi,
I am trying to join a bunch of tables together. I want a row for each
learner, and on the row, I want some user, centre, client and
centreManager information if there is any. Thus, I am trying to outer join
from the learner table to 4 other
Hi,
I am trying to join a bunch of tables together. I want a row for each
learner, and on the row, I want some user, centre, client and
centreManager information if there is any. Thus, I am trying to outer join
from the learner table to 4 other tables. The query I have so far is below
but it
Hi,
I hope this finds itself as an answer to my last post. I'm new to this email
message format of lists.
It turns out that the problem with the join was that I had a column being
selected that I removed from my posting example for brevity which was
causing the select to fail. The extra
Hi,
I'm trying to write a query which returns a single record which contains
concatenated values for referencing records:
SELECT tickets.id AS id,
CAST(GROUP_CONCAT(tags.name SEPARATOR ' ') AS CHAR) AS tags,
CAST(GROUP_CONCAT(events.value SEPARATOR ' ') AS CHAR) AS text
FROM
Hi,
Morten wrote:
Hi,
I'm trying to write a query which returns a single record which contains
concatenated values for referencing records:
SELECT tickets.id AS id,
CAST(GROUP_CONCAT(tags.name SEPARATOR ' ') AS CHAR) AS tags,
CAST(GROUP_CONCAT(events.value SEPARATOR ' ') AS
Baron Schwartz wrote:
I'm tempted to solve this using a view or two, but would like to know
if there's a better way.
GROUP_CONCAT() takes an optional DISTINCT modifier, and that might do
what you're looking for.
It sure does the trick. I'll use that, I was afraid that I was missing
Martin Gainty wrote:
Good Morning-
Good afternoon :-)
http://www.mysqlperformanceblog.com/2006/09/04/group_concat-useful-group-by-
extension/
I did'nt see your where clause ?
I'm probably missing your point here. But there's no where clause
because I want all records from the tickets
trouble storing monetary values...
Rick Faircloth wrote:
Hi, all.
I'm having trouble storing monetary values.
When MySQL 5.0 stores the entered value of 5.23,
it storing it as 5, dropping off the values after the decimal.
The field is the decimal type with 2 specified as the number
To: Rick Faircloth
Cc: MySQL List
Subject: Re: Having trouble storing monetary values...
Hi Rick,
(I'm CCing the list in again -- keeping the discussion on-list lets
everyone see it and potentially solve their own problems by searching
archives in future).
It looks to me like it ought
Hi, all.
I'm having trouble storing monetary values.
When MySQL 5.0 stores the entered value of 5.23,
it storing it as 5, dropping off the values after the decimal.
The field is the decimal type with 2 specified as the number
of values to store after the decimal.
Can anyone
Rick Faircloth wrote:
Hi, all.
I'm having trouble storing monetary values.
When MySQL 5.0 stores the entered value of 5.23,
it storing it as 5, dropping off the values after the decimal.
The field is the decimal type with 2 specified as the number
of values to store after
Morning All-
I connect to Mysql 4.0.13 using mysql_connect AND returned handle is not
false
then I call access to mysql_select_db which always returns NULL and causes
Exception
I also tried mysql_connect with supplied 4th param as DB with no joy
The DB name is uppercase..does this matter?
Has anyone else been having problems sending mail to mysql-
[EMAIL PROTECTED]
I tried it with two mail accounts (one at work and also GMail)
I get this as a response...for some reason it doesn't seem to be
getting to the list at all. The mail servers are somehow taking that
address and
At 12:26 PM -0400 9/14/07, Martin Gainty wrote:
Morning All-
I connect to Mysql 4.0.13 using mysql_connect AND returned handle is not false
then I call access to mysql_select_db which always returns NULL and
causes Exception
I also tried mysql_connect with supplied 4th param as DB with no
I have a mysql v 5.0 server running on Suse Linux 10.1. It has been
running steadily and properly for several months now. However, when I
came in this morning, my network card in the machine was bad. I
replaced the card and reconfigured the network, but ever since then, I
can only connect to
At 11:36 AM 4/23/2007, Drew Burchett wrote:
I have a mysql v 5.0 server running on Suse Linux 10.1. It has been
running steadily and properly for several months now. However, when I
came in this morning, my network card in the machine was bad. I
replaced the card and reconfigured the network,
@lists.mysql.com
Subject: Re: Trouble connecting to server
At 11:36 AM 4/23/2007, Drew Burchett wrote:
I have a mysql v 5.0 server running on Suse Linux 10.1. It has been
running steadily and properly for several months now. However, when I
came in this morning, my network card in the machine was bad
I have two tables I just what the data from the 1 table that is not in the
2 table So in this example I what row formelements_id 22 and 23. I have
tried different sql statements one is below
SELECT customformelements.formelements_id
Hi!
I'm a rookie, so bear with me...
Keep getting:
Starting mysqld daemon with databases from /opt/mysql/mysql/data
Stopping server from pid file /opt/mysql/mysql/data/unknown.pid
061228 17:16:04 mysqld ended
After this command bin/safe_mysqld --user=mysql
Very open to suggestions
Check for .err text log files .. they are probably in
/opt/mysql/mysql/data/
called servername.err
servername is the hostname of your box.
On Thu, 28 Dec 2006, Jeff Jones wrote:
Hi!
I'm a rookie, so bear with me...
Keep getting:
Starting mysqld daemon with databases from
]
To: Jeff Jones [EMAIL PROTECTED]
CC: mysql@lists.mysql.com
Subject: Re: trouble starting mysqld daemon
Date: Sun, 31 Dec 2006 14:23:53 -0500 (EST)
Check for .err text log files .. they are probably in
/opt/mysql/mysql/data/
called servername.err
servername is the hostname of your box
Hi
I moved a lot of databases from a 3.23 system to a new 5.0 system that
was taking over because of hardware upgrades. I had no major problems
until the last database.
This query:
SELECT a.id, a.nr, a.parent_id, a.designation, a.designation2,
a.short_description, a.road_desc,
!!!
- Original Message -
From: nocturnal [EMAIL PROTECTED]
To: mysql@lists.mysql.com
Sent: Wednesday, October 18, 2006 10:31:13 AM GMT-0500 US/Eastern
Subject: Some trouble with a Join after upgrade from 3.23 to 5.0
Hi
I moved a lot of databases from a 3.23 system to a new 5.0 system
I read the documentation on this link:
http://dev.mysql.com/doc/refman/5.0/en/join.html
and found the section describing changes made to MySQL 5.0.12.
The problems is that i couldn't find any errors in the query when i
read about the new JOIN syntax described.
The info you need is in that
This is due to a change in MySQL 5.0.12 that was done to align with
SQL:2003. Here, we started to be more conservative regarding what could
go into the ON clause. The whole thing is documented here:
http://dev.mysql.com/doc/refman/5.0/en/join.html
In your case, the JOIN would look something
I have a 17,000,000 record table that I'm trying to duplicate in
order to make some changes and improvements, then I'll rename it and
drop the original table. So I need this duplicate to be a live table
in the same database as the original.
I tried the copy table function in the Operations
At 11:01 AM 9/30/2006, you wrote:
I have a 17,000,000 record table that I'm trying to duplicate in
order to make some changes and improvements, then I'll rename it and
drop the original table. So I need this duplicate to be a live table
in the same database as the original.
I tried the copy
First off, I apologize for the fact that I'm not more versed in the inner
workings of GCC and linking libraries and etc, I'm a web developer and I'm
just using C to try to cut down on some speed problems.
This is my little test program:
#include stdio.h
#include stdlib.h
#include math.h
#include
Chris wrote:
Chris White wrote:
On Monday 07 August 2006 12:13 pm, William DeMasi wrote:
I meant to have it say :
select * from c2iedm_dev2.act where act_id IN (select obj_act_id from
c2iedm_dev2.act_functl_assoc where subj_act_id =24);
What does the output of (the subselect):
select
hi guys:
I'm not the sharpest tack in the box. I'm having
trouble making a trigger work.
CREATE TRIGGER update_calldate BEFORE INSERT ON
contacts
FOR EACH ROW
UPDATE contacts SET calldate=2006-08-15 where
calldate NOT IN ('2006-08-15')
;
The trigger accepts in so far as it creates the
trigger
The select statement I am trying to run is:
select * from c2iedm_dev2.act where act_id =(select obj_act_id from
c2iedm_dev2.act_functl_assoc where subj_act_id =24);
But I get the error below:
You have an error in your SQL syntax. Check the manual that corresponds to
your MySQL server version for
On Monday 07 August 2006 12:02 pm, William DeMasi wrote:
The select statement I am trying to run is:
select * from c2iedm_dev2.act where act_id =(select obj_act_id from
c2iedm_dev2.act_functl_assoc where subj_act_id =24);
Well the problem I'm seeing is that you're not using IN anywhere in the
On Monday 07 August 2006 12:13 pm, William DeMasi wrote:
I meant to have it say :
select * from c2iedm_dev2.act where act_id IN (select obj_act_id from
c2iedm_dev2.act_functl_assoc where subj_act_id =24);
What does the output of (the subselect):
select obj_act_id
from
Chris White wrote:
On Monday 07 August 2006 12:13 pm, William DeMasi wrote:
I meant to have it say :
select * from c2iedm_dev2.act where act_id IN (select obj_act_id from
c2iedm_dev2.act_functl_assoc where subj_act_id =24);
What does the output of (the subselect):
select obj_act_id
from
Hello,
I'm trying to set up a replication slave as read-only, but the read-only
part doesn't seem to be working.
Replication between the master and the slave works fine. I have added the
read-only keyword to the slave's my.cnf, and looking at the output of show
variables indicates that
Are you inserting rows as a root user? The root user will be able to
write to tables even if read-only is set to 'ON'.
--Ravi
Rod Heyd wrote:
Hello,
I'm trying to set up a replication slave as read-only, but the read-only
part doesn't seem to be working.
Replication between the master and
On 6/14/06, ravilr [EMAIL PROTECTED] wrote:
Are you inserting rows as a root user? The root user will be able to
write to tables even if read-only is set to 'ON'.
Ah, yes. That was it. I forgot about that.
Thanks.
-Rod
Rod Heyd wrote:
Hello,
I'm trying to set up a replication slave as read-only, but the read-only
part doesn't seem to be working.
Replication between the master and the slave works fine. I have added the
read-only keyword to the slave's my.cnf, and looking at the output of show
variables
I'm having some trouble writing this trigger and wasn't sure what I'm
doing wrong. My goal is after a row has been added to tcphdr it will
pull data from several other tables based on the NEW rows event.cid and
event.timestamp and insert it into acid_event. However I'm not sure how
to tell
Hello everybody,
I'm using mysql in an clustered environment:
Several loadbalanced webservers get the requests from the users' clients
and query the needed information from several webservers. Every webserver
connects to every database-server. So in this case the webservers are the
mysql-clients.
Hi everybody,
I have Windows XP computer and I've installed Apache, and MySQL 5.0.18. I
downloaded MySQL from:
http://www.softpedia.com/progDownload/MySQL-for-Windows-Download-2668.html
but the following problem occurs.
According to the instructions in php and mysql for dummies (I'm a newbee) I
Bibi,
WinMySqlAdmin has been disocntinued. Try
mysql/bin/MySqlInstqanceConfig.exe.
Getting PHP to work with MySQL under Windows is a bit tricky at first,
but once set up it's solid. For setup have a look at
http://forums.mysql.com/read.php?52,70381,70628#msg-70628.
PB
I've been running MySQL 4.0.20 on Mac OS 10.3.5 for some months and had been
working on a custom client. It was working well until I upgraded by computer to
10.4.3 and MySQL to 5.0.18. My client can not longer connect - I get an error
message: Client does not support authentication protocol
this refers to a new password scheme used in mysql 4.1 and above. see
here to fix this...
http://dev.mysql.com/doc/refman/5.0/en/old-client.html
b
John Hoover wrote:
I've been running MySQL 4.0.20 on Mac OS 10.3.5 for some months and had been working on a
custom client. It was working well
oh i forgot to mention,
the new passwords are stored in the database already. you need to reset
the password with the OLD_PASSWORD() function. they detail that in the
documentation
b
Brandon Ooi wrote:
this refers to a new password scheme used in mysql 4.1 and above. see
here to fix
On Tuesday 17 January 2006 14:37, Gleb Paharenko wrote:
This is a bug:
http://bugs.mysql.com/bug.php?id=15965
Have a look here as well:
http://bugs.mysql.com/bug.php?id=15151
Most probable you will have to install the latest development source,
which has this bug fixed:
Trux wrote:
Hi!
Sorry for my english, im russian.
I have trouble with starting mysql-4.1.16. I compiled it from source, and
when
i run:
# mysql_install_db --user=mysql
i've got:
-
ERROR: 1064 You have an error in your SQL syntax; check the manual that
corresponds to your MySQL
On Tuesday 17 January 2006 14:37, Gleb Paharenko wrote:
This is a bug:
http://bugs.mysql.com/bug.php?id=15965
Have a look here as well:
http://bugs.mysql.com/bug.php?id=15151
Most probable you will have to install the latest development source,
which has this bug fixed:
What about next release in 4.1.x? May be it will fix this bug?
I hope it will.
Trux wrote:
On Tuesday 17 January 2006 14:37, Gleb Paharenko wrote:
This is a bug:
http://bugs.mysql.com/bug.php?id=15965
Have a look here as well:
http://bugs.mysql.com/bug.php?id=15151
Most probable
Hi!
Sorry for my english, im russian.
I have trouble with starting mysql-4.1.16. I compiled it from source, and when
i run:
# mysql_install_db --user=mysql
i've got:
-
ERROR: 1064 You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version
Lewis,
As you already have perl installed, an easier way of getting modules
is by way of CPAN (www.cpan.org). Give this a try, as superuser:
cpan install DBI
Regards,
Imran
--
http://www.EjectDisc.com
Get your Digital Identity - Domain Names, Web Space, E-mail More!
--
MySQL General Mailing
Rasnita wrote:
From: Lewis Ashley Foster [EMAIL PROTECTED]
I'm trying to get mySQL installed on my machine but im having a bit of
trouble, obviously :)
When i come to install mySQL server as below:
rpm -ivh MySQL-server-standard-5.0.16-0.rhel3.i386.rpm
I get this result:
warning: MySQL
Hello.
the first error, cant find Time/HiRes.pmthen later on 56/56 tests
Now it is rather a pure Perl problem than MySQL. However, have you
installed Time/HiRes.pm? As far as I know, you can use 'force install
...' instead of just 'install' command in the cpan shell. This should
trying to get mySQL installed on my machine but im having a bit of
trouble, obviously :)
When i come to install mySQL server as below:
rpm -ivh MySQL-server-standard-5.0.16-0.rhel3.i386.rpm
I get this result:
warning: MySQL-server-standard-5.0.16-0.rhel3.i386.rpm: V3 DSA
signature:
NOKEY
1 - 100 of 482 matches
Mail list logo