Michael,

Thanks for posting an accurate compression constant for liquid water.  I 
should have known better than to grab something from the internet for a 
quick post (1 part in 5x10^7).  Nothing like being off by a few orders 
of magnitude!  I've since found a decent site on water, if you're 
curious: http://www.lsbu.ac.uk/water/explan2.html

Take care and God bless.

Michael Fitz wrote:
> Rodney,
>
> I deal with these problems all the time.  The sprinkler system MUST have
> some air in it or an expansion tank otherwise the pressure will "jack" up to
> high pressures.  We see this problem every time a check valve is installed
> in a domestic water system where there is a water heater downstream.  Cold
> water fills the system and is then heated, say from 50 to 130.  The
> volumetric expansion of water is very high when compared to the linear
> expansion of the copper water pipes (or the steel pipes of a sprinkler
> system) and the water will drain out of the PRV.  If it doesn't have one,
> something breaks as explained below.
>
> As with most real systems, it can be extremely complicated to exactly model
> and calculate precisely what happens.  Assume that water expands when
> heated, albeit a small amount. This amount is about .000207/degree C at 68F.
> For a 1% change in volume and assuming the factor is constant (it isn't), we
> would need to heat the water 48 degrees C or about 87 F.
>
> Also assume that water is somewhat compressible.  Table 5.4 of Eshbach's
> Handbook of Engineering Fundamentals, 4th Edition, lists the compressibility
> (K or Beta) of water at 68F as 318,000 PSI where dP=dV*K  This means for a
> 1% change in volume, the pressure would go up or down 3,180 PSI.
>
> IF we assume a completely sealed rigid container full of water, not too
> unlike a sprinkler system, then we just need to equate the thermal expansion
> of water to the compressibility of water.  This way, the change in volume
> cancels out.  In other words, if we heated the water 87F, then the pressure
> would rise 3,180 PSI.  This rough calculation indicates that the pressure
> would theoretically increase about 36 PSI per degree F.
>
> Now in real life, the pipes also expand because of the temperature rise (2X
> the linear expansion rate) AND because the pressure rise of the water
> stresses the material so it also elastically expands.  If there are any
> gaskets that allow the pipes to move a little in the groove, that changes
> things a little.  So you can see the actual pressure rise is difficult to
> calculate but what happens is that the actual pressure rise in a system is a
> lot less than that rigid container calculation shown above.  This is how we
> select expansion tanks, see
> http://www.watts.com/pro/divisions/watersafety_flowcontrol/learnabout/learna
> bout_thermexpansion.asp  It's a good explanation why it is so very dangerous
> to overfill a propane tank.  The liquid will expand until the tank goes
> "hydraulic" and then it burps over the PRV with a very little change in
> temperature.
>
> General rules of thumb:  Water compressibility 318,000 PSI, Glycerin =
> 630,000 PSI. Glycerin can exert twice the force assuming the same
> temperature change, another reason to have the right expansion tanks on an
> antifreeze system.
>
> Air (assuming ideal) P2 = P1*V1/V2.  Halve the volume, double the absolute
> pressure, quite compressible.
>   
> P2 = P1*T2/T1  Double the absolute temperature and you double the absolute
> pressure.  As an example, for a temperature rise of air in a rigid container
> from 68F to 98F and a system pressure of 75 PSIA, the pressure would
> increase to 75*(98+460)/(68+460) or 79.3 PSIA.   For those that read gauges,
> essentially from 60 to 64 PSI.
>
> Hope this clears up why trapped air pockets DON'T cause significant pressure
> increases with temperature and why air free systems "dangerously" increase
> in pressure with rises in temperature.
>
> Michael
>
> Michael M. Fitz, P.E., C.F.I.
> MDE Inc.
> 700 S. Industrial Way
> Seattle, WA  98108
> www.MDE.com
> 206-321-1804
>   

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