In reply to Stiffler Scientific's message of Sun, 26 Aug 2007 12:30:53 -0500: Hi, [snip] >I was not clear on this below > >@@ Eg - energy gain > >This is not to be considered Power, rather it is -I or negative current that >exceeds input and can be used to do a secondary operation. > >I also should have added that this at this time ranges from 13 -> 18% above >input. > >Hope that will make it somewhat clear. > [snip]
Just to muddy the waters a little, consider the following. In any cell there are capacitances and inductances present, such that the cell can be considered to be a tank circuit. When feeding a tank circuit with AC (or pulsed DC), it is possible to get a current flowing in the tank that considerably exceeds the input current, particularly when the frequency of the driving source lies near the resonance point of the tank circuit. Since the tank current also passes through the electrolyte, the Faraday efficiency may appear to be much higher than one would calculate based upon the power supply current. However for this to function, the power has to come from somewhere, and it comes from the voltage, as the resonant cell appears to have a high impedance resulting in the power supply needing to use a high voltage just to drive a small power supply current through the cell. This phenomenon may be what is taking place in the Meyer cells. Regards, Robin van Spaandonk The shrub is a plant.
