On Thu, May 30, 2013 at 11:00 AM, Edmund Storms <stor...@ix.netcom.com>wrote:
> Harry, imagine balls held in line by springs. If the end ball is pull away > with a force and let go, a resonance wave will pass down the line. Each > ball will alternately move away and then toward its neighbor. If outside > energy is supplied, this resonance will continue. If not, it will damp out. > At this stage, this is a purely mechanical action that is well understood. > > > In the case of the Hydroton, the outside energy is temperature. The > temperature creates random vibration of atoms, which is focused along the > length of the molecule. Again, this is normal and well understood behavior. > > The strange behavior starts once the nuclei can get within a critical > distance of each other as a result of the resonance. This distance is less > than is possible in any other material because of the high concentration of > negative charge that can exist in this structure and environment. The > barrier is not eliminated. It is only reduced enough to allow the distance > to become small enough so that the two nuclei can "see" and respond. The > response is to emit a photon from each nuclei because this process lowers > the energy of the system. > > Ed, With each cycle energy of the system is only lowered if the energy of the emitted photon is greater than the work done by the "random vibration of atoms" on the system. The change is analogous to an exothermic chemical reaction which requires some activation energy to initiate but the reaction products are in a lower energy state. Because of the shape of the coulomb "hill" the hill can only be climbed if the energy emitted increases with each cycle. > The Hydroton allows the Coulomb barrier to be reduced enough for the > nuclei to respond and emit excess energy. Because the resonance immediately > increases the distance, the ability or need to lose energy is lost before > all the extra energy can be emitted. If the distance did not increased, hot > fusion would result. The distance is again reduced, and another small burst > of energy is emitted. This process continues until ALL energy is emitted > and the intervening electron is sucked into the final product. > > In your model, the coulomb barrier appears to be like a hill in a uniform gravitational field. It is possible to climb such a barrier in steps by emitting the same amount of energy with each cycle, but this barrier does not correspond with the actual barrier that exists between protons. Climbing a genuine coulomb barrier requires more energy with each cycle, so that requires more energy be emitted with each cycle. The extra energy emitted heats the lattice even more and produces more powerful vibrations of the lattice which can push the protons even closer together. > I might add, all theories require a similar process. All theories require > a group of hydron be assembled, which requires emission of Gibbs energy. > Once assembled, the fusion process must take place in stages to avoid the > hot fusion result, as happens when the nuclei get close using a muon and > without the ability to limit the process. Unfortunately, the other theories > ignore these requirements. > > The proton has nothing to do with the work done at each step. This work > comes from the temperature. The photon results because the assembly has too > much mass-energy for the distance between the nuclei. If the nuclei > touched, the assembly would have 24 MeV of excess mass-energy if they were > deuterons. If they are close but not touching, the stable mass-energy > would be less. At a critical distance short of actually touching, the > nuclei can "know" that they have too much mass energy. How they know this > is the magic that CF has revealed. > Here is the magic: they share an electron and it is through this "common ground" that they know. If they don't share an electron they won't give up any excess mass-energy until they are touching at which point they give it up all at once which is what happens in hot fusion. Harry
