Ah, glad to know that it is a known issue at least and not a new
problem. Thanks for the info.
On Oct 29, 9:07 pm, Malcolm Tredinnick <[EMAIL PROTECTED]>
wrote:
> On Mon, 2007-10-29 at 20:58 +0000, Kevin wrote:
> > I'm trying to figure out how to chain filters for a many-
oo bad
for each particular use case, but just thought it would be pretty neat
if I there existed a way to extend/hack the admin interface to do
something similar in a more generic fashion.
Thanks!
Kevin
--~--~-~--~~~---~--~~
You received this message because you are su
On the recommendation that ljworld uses swish-e [1], I incorporated
that into my django powered site. The Python interface I use is [2].
Here's the code my search view uses:
handle = SwishE.new(SEARCH_INDEX_FILE)
results = handle.query(terms)
ids = [int(x.getproperty('swishdocpath')) for x in
I run django (and Swish-E) under linux so I can't provide any advise on
how to compile it for windows.
I do run swish-e with the -S prog option and I wrote a python script
that reads all of the models from the database and writes out xml
(actually html) that corresponds with the values that I'm i
My use of swish-e is clearly different that yours. The indexer part of
swish-e is run only periodically (say, nightly) with a `swish-e -S prog
-i ./generate_index.py`
this creates an index file that the SwishE python api queries
--~--~-~--~~~---~--~~
You rec
I'm trying to use the manipulator framework to generate a multi-part
form. It's for an online shopping engine where the customer goes
through a few steps entering their shipping and credit card info, etc.
Anyways, I created some model classes, eg ContactInfo (phone #, email,
etc), Address and Cr
The base class, Manipulator, just throws a NotImplementedException for
it's save() method. Is there a more concrete example I can view to see
how to override storing to the database.
PS. I'm converting an existing PHP site to django, it's so nice having
all these validation/admin stuff just "ta
I'm working on a similar script to convert a legacy database. Just a
hint from a tough lesson learned, you work the opposite order that OO
may teach you and you save() first, then aggregate.
So example:
class PhoneNumber(meta.Model):
number = meta.CharField()
class Contact(meta.Model):
In my code, I have:
zip_code = meta.CharField(maxlength=9)
But when it's rendered as a form, it's always given a SIZE="30". Now I
saw that sub-classes like USStateField override the length parameter in
the TextField.__init__ method, but I really don't want to go creating
all kinds of sub-classe
Is there a reason you can't do this:
{% for items in dictionary.items %}
... be able to use {{ items.0 }} and "{{ items.1 }}"...
{% endfor %}
this is equivalent to the python:
for key, value in dictionary.items()
but since for loops in the template language can only create one
variable, you nee
I'm converting a PHP application over to django and one thing I took
for granted was PHPs conversion of inputs with the name "input[]" into
an array automatically. Since django nor python seem to support that
conversion, what do people suggest for receiving 1 to N inputs on a
request.POST?
In my
Unfortunately, I believe they're necessary. My exact code is a list of
radio inputs, in template lanaguage and radio buttons use the input
name as a way of grouping.
My Models would be:
class OptionSet(Model):
name = CharField()
class Option(Model):
name = CharField
option_set = Foreig
I understand, and that's what I'm really doing at the moment, but I was
just curious if there's a better way to retrieve these POST values than
just:
options = []
for name, value in request.POST.items():
if(name.startswith("option")):
options.append(value)
I decided to try writing a generic array converter as a middleware:
import re
class ParamsMiddleware:
patt = re.compile("^([a-zA-Z_]\w*)\[\(d*)\]$")
LARGE_INT = 2**30
def process_request(self, request):
if(request.POST):
post = requ
Excellent, time to `svn switch` back to trunk
I'd prefer to see a two stage approach to contributing applications to
Django where newly contributed apps are in some sub-directory like
django.extras instead of django.contrib that contains more
standardized and popular applications like admin.
I'm thinking of KDE as a model with there kdenonb
Hey guys, got myself stumped and I'm hoping you could help me figure
this one out. In my code I've got a hierarchical category structure
for my model that's intended to roughly analogize a filesystem, eg:
class Album(meta.Model):
location = meta.SlugField()
name = meta.CharField()
pa
Yeah, after more experimenting, I came to the same conclusion and
globbed the whole path and tokenized the names in the view.
Thanks for the help.
Is there any builtin protection against SQL Injection in django? Let
me present a common case I use:
class Article(meta.Model):
name = meta.SlugField()
title = meta.CharField()
text = meta.TextField()
# my url conf
(r'^articles/(?P.*)/$', 'mydomain.views.view_article')
# my view
d
I'm converting my custom PHP e-commerce site over to django. It's a
dream writing in a true MVC framework with the python language and
django's ORM and template language.
I do all my payment processing offline, so I can't help on that topic.
It's much easier to develop a product catalog with the
Could anyone provide some hints on how they have implemented search
functionality on their web site? Did you do it django or use another
middleware (eg, Lucene)? If you did it django, did you bypass the ORM
and use direct SQL to take advantage of full text search?
I'm currently trying to build
That would be great. I think it would a strong benefit to many django
users as search is such a common problem.
For this exact use I created the following custom filter. It converts
a list into a two-dimensional table:
def tabularize(value, cols):
"""modifies a list to become a list of lists
eg [1,2,3,4] becomes [[1,2], [3,4]] with an argument of 2"""
try:
cols = in
Because without the map(None + ), your last row will be short
elements if it doesn't divide pefectly.
So, if you're cols was 3, you'd get:
[(1,2,3), (4,)]
and of course, that could create bad html:
1
2
3
4
So, now with the Map, the left over cells are set to None, so that's
why the te
I'm sure this has been asked before, but googling didn't turn up a
solution.
I have the following class:
class ContactInfo(meta.Model):
name = meta.CharField()
phone = meta.PhoneNumberField(blank=True)
email = meta.EmailField(blank=True)
And I'm trying to present a form to the user
I think the question at hand is not where to store and serve the media
files, but how to write an app that can easily support accessing media
files from different urls. I had this same issue between my
development and production apache servers:
Dev Site
localhost/mysite/images/whatever.gif
Prod
I think the problem is that urlconf provides a url => view mapping.
Really though, for creating the links, we need the reverse mapping. We
usually know the view we want to display, but don't know it's URL.
For example, you have a bulletin board app:
urls.py:
urlpatterns = patterns(''
'^comm
I ran into this problem as well. The issue is that super() expects the
child class not the parent class (the documentation is wrong), so try
this:
super(DahlBookManager, self).get_query_set()..
instead of
super(Manager, self).get_query_set()
In addition, it wouldn't let me create the Manage
is set?
Thanks
-Kevin
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to django-users+unsubscr...@googlegroups.com.
To view this discussion on the web visit
Thanks Boris & Allan,
I was able to research the problem further and found that my header was
being set entirely correctly, and the Django csrf middleware does in fact
require both the cookie AND the header to be set. It's not an either/or,
and there is an explicit error message for when either
There is a list of all Python-based build tools on the python.org
wiki:
http://wiki.python.org/moin/ConfigurationAndBuildTools
I haven't used any of them with Django, but for managing Zope, Plone
and Grok based web apps, zc.buildout is the current preferred tool.
It's a configuration-based build
On Sep 12, 10:06 am, "Matt Conrad" <[EMAIL PROTECTED]> wrote:
> On Fri, Sep 12, 2008 at 11:15 AM, Jeff Anderson
>
> <[EMAIL PROTECTED]> wrote:
> > You can influence what this list is, by setting the PYTHONPATH
> > environmental variable. All you need to do is set your PYTHONPATH
> > appropriatel
dont use MEDIA_ROOT, you can define a new label. e.g : mediaroot .
On Oct 5, 3:19 am, mrsource <[EMAIL PROTECTED]> wrote:
> I can upload images on the right place in the file system, but then
> django don't serve them.
> I'm using the development server and the current SVN version of
> django.
>
Hey everyone,
Quick summary of what I'm trying to do:
There are images stored in an ImageField. I need to be able to edit
this image (I'm using ImageDraw from the PIL), put it into a separate
ImageField in the same entry, so that it's also accessible from the
front-end.
I, however, am having pro
I think there are two issues at play here:
1. Separate your site or application into multiple Python projects to
promote re-usability, maintainability, extensibility.
2. Place your packages within a top-level package to prevent
namespace collisions to increase re-usability.
Note there is a di
/mysql.sock' (2)")
I'm not exactly sure what this socket is or why django can't find it.
One thought is that I installed LAMP on my machine using XAMPP, which
puts everything in the /Applications/xampp directory. Poking around, I
managed to find a mysql.sock file here:
/Applications
I found the solution in the archives: I changed DATABASE_HOST to
127.0.0.1 from ''
Kevin
On Feb 4, 9:41 am, Kevin Audleman wrote:
> Hello everyone,
>
> I am running through the tutorial and setting up my first django
> project. Quite exciting! However I have run into
Filemaker where I have the ability to
auto-populate fields on creation through relationships, but django is
a new world unto me.
Thanks for your help,
Kevin Audleman
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
&qu
rking across the relationship?
Cheers,
Kevin
On Feb 6, 9:46 am, Alex Gaynor wrote:
> On Fri, Feb 6, 2009 at 12:43 PM, Kevin Audleman
> wrote:
>
>
>
>
>
> > I'm building a simple time tracker. It has a table Clients and a table
> > Projects and there is a one
Wow, that is very cool. I implemented it and it works! Django is
definitely a very impressive framework.
Thanks for your help!
Kevin
On Feb 6, 10:31 am, Alex Gaynor wrote:
> On Fri, Feb 6, 2009 at 12:58 PM, Kevin Audleman
> wrote:
>
>
>
>
>
> > Thanks Alex!
>
when I view it, I see AL. How do I
get django to display the human readable name?
I would prefer to do this on the template level, as I'm using a view
from a contributed app that I can't modify.
Thanks,
Kevin
--~--~-~--~~~---~--~~
You received thi
Thanks Alex, however this is a solution at the View level, and I'm
using a view that I didn't write. Is there also a way to do this at
the template level?
Thanks again,
Kevin
On Feb 10, 1:24 pm, Alex Gaynor wrote:
> On Tue, Feb 10, 2009 at 4:23 PM, Kevin Audleman
> wrote:
I could've swore I tried that before posting my question and it didn't
work, but I tried it this time and it did. Anyhow, a long winded way
of apologizing for asking a simple question. Thank you for taking the
time to answer!
Kevin
On Feb 10, 3:41 pm, Alex Gaynor wrote:
> On Tue,
I have the same session. Django has been so slick so far I would
imagine it has a way to access session variables from a template. Have
you found the solution?
Kevin
On Jan 17, 1:15 pm, dahpgjgamgan wrote:
> Hi,
>
> A simple scenario:
> - A generic object detail view, on whic
ilter = ('is_staff', 'is_superuser')
inlines = [ProfileInline]
admin.site.register(User, UserAdmin)
Is there a way to do this?
Thanks,
Kevin Audleman
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"
ay
to add a related field to the list_display or list_filter sets for the
User object?
Cheers,
Kevin
On Feb 16, 3:45 pm, Alex Gaynor wrote:
> On Mon, Feb 16, 2009 at 6:27 PM, Kevin Audleman
> wrote:
>
>
>
>
>
> > I've created a custom profile per the instructions in
eturn self.myprofile_set.all()[0].payment_status
However I am working with the core User object which I didn't write.
Am I SOL, or is there some way I can do this.
Thanks,
Kevin
On Feb 16, 4:02 pm, Alex Gaynor wrote:
> On Mon, Feb 16, 2009 at 6:59 PM, Kevin Audleman
> wrote:
>
>
>
>
>
&g
'display_profile_status',
)
On Feb 16, 4:15 pm, Alex Gaynor wrote:
> On Mon, Feb 16, 2009 at 7:13 PM, Kevin Audleman
> wrote:
>
>
>
>
>
> > Alex,
>
> > I feel like I'm one step closer to getting this to work. From the
> &g
Hey, that's great! I did indeed discover that the change password page
didn't work but didn't know what to do about it. Thanks for your
excellent and thorough help =)
Kevin
On Feb 16, 6:30 pm, Karen Tracey wrote:
> On Mon, Feb 16, 2009 at 8:19 PM, Kevin Audleman
>
You should probably change the order of operations in the
__init__function to call the super classes __init__ function first.
Kevin
On Feb 16, 8:49 am, peterandall wrote:
> Hi all,
>
> I'm trying to access a list of users in forms.py I'm creating two
> lists and m
Passing both the form and the object is the solution I use. It may not
be completely DRY, but I can't see how it's bad. You need access to
the data in an object so you pass the object. Much more sensible than
trying to extract those values from a more complicated data
structure.
Kevin
} else {
document.getElementById("pleasewait").style.display = "block";
}
}
//-->
And your HTML code looks like this:
Please wait while your request is being processed...
Cheers,
Kevin Audleman
On Feb 18, 2:52 pm,
this in your request
show_range = (current_show - 4, current_show + 4)
shows = Show.objects.filter(show_order__range=show_range)
FYI I haven't tested this and my Python is not good enough that I can
guarantee my syntax.
Kevin Audleman
On Feb 18, 4:06 pm, Sean Brant wrote:
> Is there a simple
Django.
Hopefully somebody out there has a more flushed out idea.
Kevin
On Feb 19, 2:20 am, Alan wrote:
> Hi There,
>
> We have Plone/Zope site for CMS and users registration. It came before
> django for us. But now we are developing portal applicatons done with django
> (much be
django to append a /directory/ to the beginning
of each url it creates?
Kevin
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googleg
Hi Alex,
I did exactly as you suggested with no luck. Any other suggestions?
Kevin
On May 25, 12:27 pm, Alex Koshelev wrote:
> Hi, Kevin.
>
> You can try to set FORCE_SCRIPT_NAME = '/directory' [1] settings
> variable. Or setup your web server to provide valid SCR
here.
If I submit a correctly formed comment, it brings up the "Thank you for
your comment" template but doesn't redirect back to the original object.
I've tried removing the hidden field and doing
and have the same problem - is this a known problem, or is it d
On Thu, May 28, 2009 01:50, Eric Abrahamsen wrote:
>
> On May 28, 2009, at 4:02 AM, Kevin Fullerton wrote:
>
>>
>> I'm working with django.contrib.comments at the moment, and so far
>> most
>> things are working as expected.
>
> It's a known p
9
The code I'm using to submit the comment looks similar to
{% get_comment_form for object as form %}
http://blog.kenwa-solutions.co.uk/"; method="POST">
So I'm not sure why the default preview form isn't picking it up
Many thanks
Kevin
--~--~--
on2.5'] + sys.path"
SetEnv DJANGO_SETTINGS_MODULE CasaCasa.settings
SetHandler python-program
PythonOption SCRIPT_NAME
PythonOption django.root "/directory"
On May 25, 1:02 pm, Kevin Audleman wrote:
> Hi Alex,
>
> I did exactly as you suggested with no luck. Any
in the admin section for edit pages.
I can click on a model to see a list of its records, I can click on a
record to edit it, but when I click Save it takes me to a URL that is
missing the django.root (of course the page doesn't exist on the
server so I get a 404).
This seems like a django bu
) with base 10: 'add/form_url'
I wondered if it might have to do with any of the changes I had made
though defining an admin.py in my app, so I removed it and went back
to the stock admin site. The error persists. The full trace is below.
Any he
On Jun 10, 9:27 am, Paolo Corti wrote:
> Hi
> is it possible to update an object with a dictionary?
>
> I tried something like this:
> myobject.save(force_update=True, **my_dict)
>
> getting an error, though:
> TypeError at ...
> save() got an unexpected keyword argument 'myfieldname'
>
> I wou
__dict__ is an attribute of every Python object. It's typically only
an internal detail, and generally not accessed directly. One area
where __dict__ modification would differ from attribute access is with
an attribute that's a property. Modifying the __dict__ would ignore
the property getter/sett
exist. If the value is simply blank, the page will work. If, however
the name of the variable is printed it won't work. See this ticket for
more info:
http://code.djangoproject.com/ticket/3579
The solution was to comment out those two settings and like magic it
works.
Kevin
On Jun 8, 6:32
Presumably you already have all of the data required to generate a
chart on the server? If so, then store the chart data in a model, and
just reference it by id. e.g.
(or w/ a pretty URL: )
And create a Chart object and store it before sending out the HTML
response. Then update your chart view
Yes, how many times have you followed the practice of:
1. write some new code
2. (re)start dev server and/or update dev database
3. tab over to your browser and click away
4. tab back to terminal to see the traceback when you hit an error
With a functional test suite, it becomes sooo much
ques.
Is there another, simpler way of doing it?
Thanks,
Kevin Audleman
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroup
Great idea, I'll do that.
Thanks!
Kevin
On Feb 23, 11:30 am, Daniel Roseman
wrote:
> On Feb 23, 7:19 pm, Kevin Audleman wrote:
>
>
>
> > Hello,
>
> > I am using the excellent django-profiles module provided by
> > Ubernostrum which gives my site the
dels.Model):
username = models.OneToOneField(User, parent_link=False)
address = ... etc
--
Any pointers would be appreciated. Thanks.
--
Kevin Coyner GnuPG key: 1024D/8CE11941
--~--~-~--~~~---~--~~
You received this message because
t. This is preferrable over rolling your own as django will
automatically populate request.user with the fields from your profile
module.
The previous response identifies how to get it to show up in the
admin. Namely, you overwrite the User object to display the related
record.
Cheers,
Kevin
On Feb 2
27;, {'document_root': '/mesa'}),
Mind you, I don't know if this will fix anything...
Kevin
On Feb 25, 4:26 am, Adonis wrote:
> Hello,
> I am having some trouble serving static files when i try to pass an
> optional parameter.
> For url: appname.mainpage/,
What about the following?
qset = Q(author__in=[u"Foo", u"Bar"])
Kevin
On Feb 25, 10:03 am, Peter Bengtsson wrote:
> This works:
>
> >>> from django.db.models import Q
> >>> qset = Q(author__iexact=u"Foo") | Q(author__iexact=u"
Ah, gotcha.
Maybe django should include a iin function =)
Kevin
On Feb 25, 10:37 am, Alex Gaynor wrote:
> On Wed, Feb 25, 2009 at 1:34 PM, Kevin Audleman
> wrote:
>
>
>
>
>
> > What about the following?
>
> > qset = Q(author__in=[u"Foo", u"
On Feb 25, 3:33 pm, Horst Gutmann wrote:
> Or you could leave the versioning to dedicated tools like bzr and git
> and use django-rcsfield :-)
>
> http://code.google.com/p/django-rcsfield/
>
I'm not sure what you gain from using a VCS for storing versions?
They're designed for a pretty differe
The __file__ attribute of a module can be used as a starting point for
getting at data files within a python package. However, packages can
be installed in zipped format, so if you need to account for this you
can use the pkg_resources module in setuptools:
http://peak.telecommunity.com/DevCenter
On Mar 4, 12:21 pm, ruffeo wrote:
> Does anyone know how to develop a complex django project in a 3 tiered
> network environment, still using the MCV architecture?
>
> I.E. Web Server (view and control code), App Server (model code), and
> Database Server
You have to distinguish between "archi
exptend it in Python as I need)? like a CMS?
Would it help if I explained the concept in more detail or if I asked this in a
different Python mailing list?
Thanks,
Kevin
_
Windows Live™ SkyDrive: Get 25 GB of free online s
Hi,
First let me say I've looked at documentation, but feel a bit dyslexic
when it comes to this stuff.
The situation: I have three tables: a service provider table with
city, state abbreviation and country abbreviation (among other other
info), a states table with state names, abbreviations, an
And... Never mind. Not sure how I missed it before, but it appears
select_related() gets me what I want. I think...
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send em
On Apr 14, 6:32 pm, Daniel Roseman
wrote:
> On Apr 14, 6:11 pm, Kevin Cole wrote:
> > Hi,
>
> > First let me say I've looked at documentation, but feel a bit dyslexic
> > when it comes to this stuff.
>
> > The situation: I have three tables: a servi
a or no there are
serious drawbacks to this approach -- greatly appreciated!
Cheers,
Kevin
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@g
To answer the question in terms of Python packaging (typically
consuming Django apps isn't going to differ from consuming any other
python package) ...
On Apr 21, 11:44 am, Bryan Wheelock wrote:
> I have a question about using Pluggable apps with Django.
>
> My question is about best practices.
n't find a solution, I'll look into lighthttpd.
Cheers,
Kevin
On Apr 21, 12:46 pm, Oli Warner wrote:
> You could, but as you say you would have to script it to daemonise.
>
> If resources are what's putting you off running something like Apache, you
> should know th
king for, after
all:
the error:
"Reverse for 'proyName.view_aboutPage' with arguments '()' and keyword
arguments '{}' not found."
I have solved most of my URL problems this way.
Cheers,
Kevin
--~--~-~--~~~---~--~~
You received t
As is often the case in django, they have already provided a mechanism
for what you are trying to do the hard way: Formsets.
http://docs.djangoproject.com/en/dev/topics/forms/formsets/
Cheers,
Kevin
On Apr 29, 7:18 am, MarcoS wrote:
> Hi all,
> I post a problem, hoping someone can h
ase directory appended to
MEDIA_ROOT; you might want to rename that. Then in your model, define
your image field as so:
photo_1 = models.ImageField(upload_to=upload_location, blank=True)
Cheers,
Kevin
On Apr 29, 8:12 am, Julián C. Pérez wrote:
> thanks...
> but...
> how can i make that attri
reate back buttons on each page, which you might find more
difficult if you are trying to pass form data (I think you'd have to
write extra code to pass the form backwards).
Cheers,
Kevin
On Apr 28, 5:40 pm, TheCorp wrote:
> As a note, I found this post which basically describes
somewhere else.
Kevin
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com
To unsubscribe from this group, send email to
dj
quirements correctly). This way the logic for each
"project" would be contained in its own directory complete with views,
models, etc. They will live in the same Django project and share a
settings.py file, urls.py file and can easily talk to each other.
Kevin
On Apr 30, 7:47 am, "eric.f
a Django app and these reverse url's will no longer
plague me.
Cheers,
Kevin
--~--~-~--~~~---~--~~
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@
s a challenge to put all the pieces together
myself.
Kevin
On May 1, 11:28 am, Malcolm Tredinnick
wrote:
> On Fri, 2009-05-01 at 11:13 -0700, Kevin Audleman wrote:
>
> > > I can't explain any of this, but I've been thinking about your
> > > question since
about-users
Kevin
On May 1, 8:20 am, CrabbyPete wrote:
> I created the following:
>
> class Profile(models.Model):
> user = models.ForeignKey(User, unique=True)
> phone = models.CharField(max_length=15, blank = True, null
> = True, unique = True)
>
rror was: 'module' object has no attribute
'json_command'
this is my login URL:
url(r'^accounts/login/$','django.contrib.auth.views.login',
{'template_name': 'main/login.html', }),
--
Thanks
Kevin Anthony
www.NoSideRacing.com
--
You
rra wrote:
> Kevin,
>
> Please open your views.py module located inside the rchip module and
> you will see there is no view named json_send_command.
>
> Please refer to that app's documentation to find more about the
> correct setup for your urls.
>
> Cheers,
> AT
I found the best way to do this is
python manage.py < script.py
On Jul 21, 2011 8:00 PM, "Gelonida N" wrote:
> On 07/18/2011 04:33 PM, bruno desthuilliers wrote:
>> On Jul 18, 3:33 pm, Alexander Crössmann
>> wrote:
>>> Hi Malcom,
>>>
>>> I am not sure the management commands are what I want
>>
>>
has the same href="https://github.com/jdriscoll/django-imagekit/issues/16";>bug
> as django-stdimage.
I suspect the above known bugs are related to a known bug in Django:
https://Docs.DjangoProject.com/en/1.3/releases/1.2.5/#filefield-no-longer-deletes-files
which many consider a featu
, is there
any reading material on it?
--
Thanks
Kevin Anthony
www.NoSideRacing.com
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com.
To unsubscribe from this group, sen
ter i delete it, i need to serialize the data to JSON
Thanks
Kevin Anthony
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to django-users@googlegroups.com.
To unsubscribe from this group, send email t
jango/contrib/admin/media/
directly, after all I don't copy the templates over unless I want to
override them (and yes, I realise that means I really should have
spotted django had a default static directory).
Basically static files is just an easier way to copy the admin
css/js/etc. to the pr
101 - 200 of 467 matches
Mail list logo
