Just a note: the main site still reports version 4.0.25-0.
I dowloaded version 4.0.26 from a mirror, but it was necessary to tweak the URL.
Congratulations for this fantastic project,
Diana Soares
On 9/8/05, Joerg Bruehe [EMAIL PROTECTED] wrote:
Hi,
MySQL 4.0.26, a new version
= whatever LIMIT 0,1
\n
SELECT
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On Tue, 2004-08-31 at 23:00, Eamon Daly wrote:
Did anyone ever follow up on this question? I'm looking for
the answer, too.
Eamon Daly
- Original Message -
From: [EMAIL
You may use MERGE TABLES:
http://dev.mysql.com/doc/mysql/en/MERGE.html
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Diana Soares
On Tue, 2004-05-04 at 10:08, Ken Gieselman wrote:
Heya folks --
Trying to come up with a way to count across multiple tables, and failing
miserably. I need a simple way, preferably better than looped
) AS level,
member.photo_level
FROM member
LEFT JOIN network ON (network.from_id=101 AND network.to_id=member.id
AND network.level = member.photo_level)
ORDER BY member.last_login DESC
LIMIT 0,3
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= dvd.actr_id
and
acto.acto_id = dvd.acto_id
order by dvd.title;
(I used to put (+) at the end of the outer join line, but don't think this
will work in MYSQL - at least I don't see it in the manual.)
Thanks in advance for your kind help and sorry for the wordy question!
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for your kind help and sorry for the wordy question!
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.
Well, is there anything like above that I can use?
-thanks, Eli
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You could do something like (don't copy and paste, this is just for you
to have an ideia - i didn't understand your calculations with 0.063 and
others...):
SELECT IF (metric=cm, expression_in_centimeters, expression_in_inches)
, ...other_fields
FROM ...
where metric is the name of the table
with belligerent nationalism. -- The American
Heritage Dictionary Houghton Mifflin Company, 1983
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111 Dec 7 01:30 mw01-bin.036
drwxr-xr-x5 mysqlmysql4096 Dec 7 01:30 .
-rw-rw1 mysqlmysql 63 Dec 7 01:49 master.info
-rw-rw1 mysqlmysql861518654 Dec 8 17:53 mw01-bin.038
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simple - but then, as everyone keeps telling me, so am I.
If you can help, thanks in advance.
Iain.
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Try:
SELECT C.company_id, C.company_name
FROM companies C
LEFT JOIN company_group_intersect CG
ON (C.company_id=CG.company_id AND CG.group_id='1')
WHERE C.status='1' AND CG.company_id IS NULL
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Diana Soares
On Fri, 2003-12-05 at 15:08, Robert Hughes wrote:
I have the following 3 tables
where year='2003' and month='10');
Look at:
from var and var_cd not in
supposed to be:
from var where var_cd not in
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The != does not belong to that list of comparision operators...
Hope this helps!
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On Thu, 2003-11-20 at 16:12, [EMAIL PROTECTED] wrote:
Description:
a simple select on a large table does not use an indexed column when the WHERE
clause uses a != b
The same query
If you're using MySQL 4.1, you have the GROUP_CONCAT(expr) function.
If not, then... i think someone has already done an UDF about this...
Search the archives..or see this:
http://www.cwts.nl/buter/misc/my-mysql.html
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Diana Soares
On Wed, 2003-11-12 at 08:56, Ciprian Trofin wrote
I ensure to only get one of each? Distinct does not work.
Travis
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| blew |
+---+---+---+
You can do:
SELECT @a:=0;
SELECT @a:[EMAIL PROTECTED], blah, blew from table where blah 1;
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JOIN city ON city.state_id = state.id
LEFT JOIN zip ON zip.city_id = city.id
LEFT JOIN group ON group.zip = zip.zip
Hope this helps,
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On Tue, 2003-10-14 at 22:27, D. R. Hansen wrote:
Uberdumb question - but I'm still enough of a newbie that this is giving
me fits...
I
me on this? I'm using PHP 4.2.2 and MySQL 3.23.54 btw.
Thanks millions!
Jordan
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Maybe like:
SELECT something FROM tablename
WHERE date_column
DATE_SUB(CONCAT(YEAR(NOW()),'-',MONTH(NOW()),'-','01'), INTERVAL @n
MONTH)
@n is the number of months you want. If you want data from the current
month, @n would be 0.
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Diana Soares
On Mon, 2003-10-06 at 07:23, [EMAIL PROTECTED
are running on Linux (2.4.18) and we use mysql 4.014.
Thanks,
Harm de Laat
Informatiefabriek
The Netherlands
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)
thanx for your help.
Kraan Deufe
even more than Kojak ;)
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changed the user's name
from mysql to mysqladmin. I get the follow error when trying to create
a new database:
#1006 - Can't create database 'demo'. (errno: 13)
Does anyone know the fix to this?
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errno.- Invalid use of group function -
I don't want to pull out any rows where the SUM of time_hours_worked is
'0.00'...
I would be most grateful if anyone has any suggestions
Many thanks!
Cory
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two fields from two tables and see if they match
regardless of whether
one is upper,lower,mixed case. Also see if table1.field1 is a partial match
to another.
So,
JOHNATHAN would match Jon or Jonny.
thanks,
Darryl
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) NOT NULL default '',
`id_sprache` int(10) unsigned NOT NULL default '0',
PRIMARY KEY (`lfdnr`),
UNIQUE KEY `session` (`session`),
FULLTEXT KEY `session2` (`session`)
) TYPE=MyISAM;
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AND groups.type='Privileged'
AND groupmembers.memberid=users.id
ORDER BY name
And, it it possible to remove the case sensetivity of table names.
Read the first item that appears in MySQL manual if you search for case
sensitivity:
http://www.mysql.com/doc/en/Name_case_sensitivity.html
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Diana Soares
getting corrupted data in the file.
Thanks
---
Rob
**
Rob Cherry
mailto:[EMAIL PROTECTED]
+27 21 447 7440
Jam Warehouse RSA
Smart Business Innovation
http://www.jamwarehouse.com
**
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for substitute
appearances, one for starting appearances.
Any pointers would be greatly appreciated, and if I'm asking an
inappropriate question for the group please accept my apologies in
advance.
Many thanks
Gary Broughton
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the source and compile it with
.=rdynamic ?
Thank you very much,
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Cherry
mailto:[EMAIL PROTECTED]
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Jam Warehouse RSA
Smart Business Innovation
http://www.jamwarehouse.com
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p.id ) GROUP BY p.name
But it has not the efeect I want...
What is wrong?
I hope you understood my problem (sorry for the bad English) and can
send me your suggestions
Thanks in advance
Sorin Marti
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:
alter table xmlmd5 add index md5 (md5(10));
ERROR 1064: You have an error in your SQL syntax near 'md5(10))' at line 1
column definition of md5 is md5 varchar(32)
Fix:
when I use quoted version it is OK
alter table xmlmd5 add index md5 (`md5`(10));
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Diana
| BEHOBEN | 1970-01-01 | 1970-01-01 |1 | 9 |
+-+-+++--++
Either I'm stupid or it's impossible. Let's see which case is true. :)
cheers ThX for any help...
Chris
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v3.23.
Could anyone point me in the right direction?
/mac
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it for the MySQL
gurus or others that can help..
Michael Katzmann
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')
AND portlet.name not in (
SELECT portlet_fk FROM UserTabAssignment WHERE user_fk = 'guest' AND
portal_FK = 'mysqlPortal' AND tabNumber = 0 AND subtabName =
'firstSubtab')
thanks
Alice Farbles
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Diana Soares
change mysql server from
/var/lib/mysql to new external drive? Any other thing I need care about?
I look at the command mysqlhotcopy which only can copy existing database
for backup purpose not for working database? Anybody know how to do it?
Thanks a lot!
zhu liu
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, PNumber ??
thanks
jrt
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Apps RD
Cable and Wireless
-
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for any help,
--
MikemickaloBlezien
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
Thunder Rain Internet Publishing
Providing Internet Solutions that work!
http://www.thunder-rain.com
Tel: 1(985)902-8484
MSN: [EMAIL PROTECTED]
=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=
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fear, if I rebel against my Lord, the retribution of an Awful Day (The
Day of Resurrection) Al-Quran 6:15
http://docbook.sc-icc.org
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Paris 15
A this time I'm doing this sql syntax :
SELECT *
FROM town
ORDER BY town ASC
How can I do it ?
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This is what is in the database.
Bill 3620504670
John2630324846
Fred8740196242
This is what I want to be able to show:
Fred 87
Bill 70
John 48
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Diana Soares
to
use a join in the select statement.
ID1 ID2
11
22
33
This is what I want to be able to show:
John 21
Fred 20
Bill 16
MySQL
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new guy!!
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thought his mysql server was configured to have the sock file
there. :-)
Thanx,
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index for 2 or more columns in a table will I be able
to use it for a MATCH only against a single column (of the above) or do I
have to create additional FULLTEXT indices for each of these columns?
Thanks/h
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..
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runs in server-client system, and each host of clients are different
(i assume)
I didn't understand this...
Mustafa Yelmer
Software Engineer
+90 212 2128200-1228
[EMAIL PROTECTED]
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mysql before reboot the linux sytem. What can I do to
recover/reinstall/run the mysql server again? I didn't find
mysql.server,
but I do have mysql.server* on dir /usr/share/mysql. I'm running
Mandrake
9
and Mysql-323.54a (rpm).
Thank you in advance
Pedro
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),
substr( ItemHSCode, 6, 2 ), substr( ItemHSCode, 9, 2 ))
Thanks,
Don
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: 'ERROR 2003: Can't connect to MySQL server on 'localhost' (111)'
I tried with new, old and no password!
So?
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Mob: 0425 788-185
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://signup.getreal.co.uk
For our email disclaimer please see the url below.
http://www.getreal.co.uk/disclaimer.htm
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Hi,
Start the mysqld with --skip-grant-tables. This way the server will not
use the privilege tables... Then alter the data as you want and do a
mysqladmin flush-privileges (or reload) to restart using them.
More info:
http://www.mysql.com/doc/en/Privileges_options.html
On Fri, 2003-01-17 at
, this is my problem.
Thanks for your immediate reply
Thanks Regards,
Shripal.
- Original Message -
From: Diana Soares [EMAIL PROTECTED]
To: Shripal Shah [EMAIL PROTECTED]
Sent: Friday, January 17, 2003 6:48 PM
Subject: Re: Problem with mysqlimport
Hi,
What version of MySQL
that I might just plain be missing?
Many thanks in advance!
Jody Harris
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and the optimizer). You need to think in terms of what would
be equal to what between tables in the correct result row. So if you
would do a secondary sub-select of SELECT fk from table2 where ...
then you end up with a left join like above.
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://www.mysql.com/manual.php (the manual)
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On Mon, 2003-01-13 at 14:11, Stevens, Ryan wrote:
I understand the SQL statement in MySQL to be
SELECT sum(column name) FROM table; but I would like to get a
SUM of multiple columns. Is this possible??
Yes, you may use:
SELECT sum(c1+c2) FROM table;
or even:
SELECT sum(table1.v +
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-mpentium' 'CXX=gcc'
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On Wed, 2003-01-08 at 04:55, CM Miller wrote:
Have a new years resolution, to get MySQL to run
Here are the errors that I keep getting...
I don't understand what this is telling me?
from /var/log
021214 19:13:21 mysqld started
021214 19:13:21 /usr/local/libexec/mysqld: Can't find
the last name and the first
name in two seperate fields. I can make an SQL statement like Select * from
Students Where LastName Like Smith%;, but can I make something like
SELECT * FROM Students WHERE (LastName, , , FirstName) AS Name LIKE
Smith, J%;
?
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closing the connection, then it
should increment its counter of connection_errors. It tells that someone
opened a connection and did not close it.
It's only an opinion.
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Hi,
On Thu, 2002-07-25 at 20:40, Kevin wrote:
Hello,
I have a query that runs perfectly until one of the items has no value or is
set to 0:
SELECT
item.*, color.Name AS COLOR,
shapecode.Shape AS SHAPE,
clarity.Name AS CLARITY
FROM item, color, shapecode, clarity
WHERE
table test(ID int(4), Name varchar(20), Sex varchar(1));
Now I need to change the attribute NAME TO Full name, HOW?
Please help, Thanking in Advance.
Regards
Nitesh
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a certain criteria (i.e. field X = '1234') then
update the record. If the record doesn't exist then insert it.
For reasons too complex to go into at this stage using anything except SQL
is not possible.
Any and all suggestions welcome.
-Corey
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CHECK set to N.
Hi,
Try this:
SELECT ID,GRP,max(PRC) FROM tab_name
WHERE GRP IN (1,2,3) and CHECK='N' GROUP BY GRP;
Hope this helps,
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'
If the item.CLARITY_ID has no value or a value of 0 (which there is no
defined value for in the clarity table), then the query fails.
Can anything be done without adding more login in the code?
Thanks
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Hi, just sending a reply in case that someone else has the same problem.
I solved the problem by decreasing the key-buffer from 320M to 288M.
On Wed, 2002-07-03 at 12:24, Diana Soares wrote:
Hi,
I have 2 machine dual-processor Pentium III, with 1G of memory.
They have the same software
On Fri, 2002-07-26 at 18:43, Mike Wexler wrote:
Diana Soares wrote:
Hi, just sending a reply in case that someone else has the same problem.
I solved the problem by decreasing the key-buffer from 320M to 288M.
We tried that among many other things. It turns out that their is some
as
done at the same time when the value x='' for every clientid.I have
tried what you see but didin't help.
SELECT clientid FROM table_name WHERE datedone = 'max(datedone)' and done
= 'true' and x = '' group by clientid;
I am new to all this, so any help would be usefull
Thanks
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%' and
Pengarang.Pengarang like '%$lukito%' and Subjek.Subjek
like '%$computer%'
than's a lot.
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It shows some release dates.
-Original Message-
From: Diana Soares [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, July 16, 2002 3:22 AM
To: Bill Bernat
Cc: [EMAIL PROTECTED]
Subject: Re: mysqldump question
On Tue, 2002-07-16
with /tmp/dumps directory, 777 permissions, and it
worked.)
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Websolut - Soluções Internet
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'0.00' NOT NULL,
PRIMARY KEY(article, dealer));
Thank You !
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first example worked because the only column used to join was the
id (since you gave different names to the other column).
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use:
insert into rep (repid,submitid,lastactv,status)
select 88,submit_idx2.submitid,now(),1
from submit_idx2
order by submit_idx2.submitid asc
limit $var,10;
where $var will be:
* 0 for the first time you run the query,
* 10 for the second time,
* 20 for the third
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of error
messages and error numbers in the file `Docs/mysqld_error.txt'.
For me, those files are in:
/usr/include/mysql/errmsg.h
/usr/include/mysql/mysqld_error.h
/usr/src/redhat/BUILD/mysql-3.23.50/Docs/mysqld_error.txt
Is it possible perhaps in an sql query ?
I think it's not possible...
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handle_slave__FPv + 2309
(i don't understand what this means..)
Thank you for reading this, i hope someone can give me a light.
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Diana Soares
Websolut - Soluções Internet
Email: [EMAIL PROTECTED
Hi,
Is there a way of knowing with wich options mysql was compiled ?
Thanx,
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Diana Soares
(sql)
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http://lists.mysql.com
-Forwarded Message-
From: Diana Soares [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: Compile options
Date: 08 Feb 2002 15:35:57 +
Hi,
Is there a way of knowing with wich options mysql was compiled ?
Thanx,
--
Diana Soares
(sql
and owner on
/var/lib/mysql to root.
I think that, at least, the owner of /var/lib/mysql should be mysql.
This way, mysql can create the /var/lib/mysql/mysql.sock
Hope this helps..
Also, be shure that there is no other mysqld process runnig.
--
Diana Soares
(sql
-Forwarded Message-
From: Diana Soares [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Subject: Compile options
Date: 08 Feb 2002 15:35:57 +
Hi,
Is there a way of knowing with wich options mysql was compiled ?
Thanx,
--
Diana Soares
(sql
Hi,
Is there a way of knowing with wich options mysql was compiled ?
Thanx,
--
Diana Soares
(sql)
-
Before posting, please check:
http://www.mysql.com/manual.php (the manual)
http://lists.mysql.com
query avoid putting
another entry in author? I'll be using PHP for the front end.
You can always use INSERT for the content table and REPLACE for the
author table.
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Diana Soares
(sql)
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Before posting, please check:
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