On Fri, Jan 1, 2016 at 9:31 PM, Peter Brawley
wrote:
> On 1/1/2016 19:24, Larry Martell wrote:
>>
>> On Fri, Jan 1, 2016 at 2:12 PM, Peter Brawley
>> wrote:
>>>
>>> On 12/31/2015 0:51, Larry Martell wrote:
I need to count the number of rows in a table that are grouped by a
list of
On Fri, Jan 1, 2016 at 2:12 PM, Peter Brawley
wrote:
> On 12/31/2015 0:51, Larry Martell wrote:
>>
>> I need to count the number of rows in a table that are grouped by a
>> list of columns, but I also need to exclude rows that have more then
>> some count when grouped by a different set of columns
On 12/31/2015 0:51, Larry Martell wrote:
I need to count the number of rows in a table that are grouped by a
list of columns, but I also need to exclude rows that have more then
some count when grouped by a different set of columns. Conceptually,
this is not hard, but I am having trouble doing th
On Tue, 1 Feb 2011 14:46:39 -0400
Paul Halliday wrote:
> I have a query (thanks to this list) that uses a join to add country
> information to an IP. It looks like this:
>
> SELECT COUNT(signature) AS count, INET_NTOA(src_ip), map1.cc as
> src_cc, INET_NTOA(dst_ip), map2.cc as dst_cc
> FROM even
Hi Paul!
Paul Halliday wrote:
> I have a query (thanks to this list) that uses a join to add country
> information to an IP. It looks like this:
>
> SELECT COUNT(signature) AS count, INET_NTOA(src_ip), map1.cc as
> src_cc, INET_NTOA(dst_ip), map2.cc as dst_cc
> FROM event LEFT JOIN mappings AS m
Thank you, that did the trick.
Simon
On 11 January 2011 12:09, Steve Meyers wrote:
> On 1/11/11 9:31 AM, Simon Wilkinson wrote:
>
>> select users.id from users where users.id in (select newletters.user_id
>> from
>> newletters left join articles on newletters.id = articles.newsletter_id
>> wher
On 1/11/11 9:31 AM, Simon Wilkinson wrote:
select users.id from users where users.id in (select newletters.user_id from
newletters left join articles on newletters.id = articles.newsletter_id
where articles.newsletter_id is null);
I think this would do what you require:
SELECT
u.id AS user_i
Sorry!!! I apoligized for being blind. Yes, in my small mind I was
thinking that I do not have records biggeer than 2008 but I do and my mind
refused to see the records for 2009 and 2010.
Sorry again for being so blind to the obvious.
:-(
On Mon, Dec 15, 2008 at 9:50 AM, Phil wrote:
> Am I
Am I totally missing something? Why do you believe the two queries should
return the same # of rows? First one has a qualification of proj_adv_date <
'2008-12-16' whilst the second one does not...
On Mon, Dec 15, 2008 at 12:12 PM, Néstor wrote:
> I have a char fiel where I am keeping dates forma
Are you sure those are the results to those queries? ¢,m
Your second query will return more because it includes values outside of
the date range specified in the first query.
In the second result set you have 2009 and 'invalid dates' that would
not be picked up by the first query.
Regards
Joh
Just do a left join with the delete query.
DELETE feed_tag FROM feed_tag LEFT JOIN feed ON
feed_tag.feed_id=feed.id WHERE feed.id IS NULL
That should do it. You can change "DELETE feed_tag" to "SELECT" and
test it first.
--
Brent Baisley
On Aug 13, 2008, at 4:51 PM, Daevid Vincent wrote
Hi Daevid
If you are using a foreign key you can set the reference as "cascade"
and when a row is deleted from feed it will be deleted from feed_tag.
http://dev.mysql.com/doc/refman/5.0/en/innodb-foreign-key-constraints.html
If you don't like it you can delete it easy with a query like this
del
you can do some thing like this.
create table new_table(id int, hair varchar(50),eyes varchar(50)) select
column1,column2,...from old_table;
On 7/3/08, axis <[EMAIL PROTECTED]> wrote:
>
> This question is strictly related to the mysql query not the php code.
> I need to either create a new tab
This question is strictly related to the mysql query not the php code.
I need to either create a new table from the old one or add columns.
The thing is don't know how to do it.
let me simplify things up:
I need a query to retrieve values from the table
PRODUCTS_TO_PRODUCTS_EXTRA_FIELDS to a ne
Your biggest problem is probably the subquery/IN your are performing.
You should change that to a join. And I don't know about using
SQL_CALC_FOUND_ROWS in a full text query that's not boolean, and you
shouldn't use it unless you have a LIMIT clause.
SELECT SQL_CALC_FOUND_ROWS table_1.id,ta
r does not endorse distribution to any party other than intended
recipient. Sender does not necessarily endorse content contained within this
transmission.> Date: Sun, 30 Dec 2007 13:54:32 +0100> From: [EMAIL PROTECTED]>
To: mysql@lists.mysql.com> Subject: Re: Help with query, (questi
Richard a écrit :
Sorry about my last email which was long and not clear.
This is what I want to do
Join two tables on "code table1" = "code table3" where messageid = for
example 28
table 1 contains :
message from messageid
--
Anders Norrbring wrote:
I'm trying to set up a query, but I don't really get the result I
expected, so can someone please help me out here?
The query I've built is this:
SELECT a1.username FROM accountuser AS a1
LEFT JOIN (freeaccounts AS f1, payments AS p1)
ON (a1.username = p1.username
AND p
Hi Ed,
Ed Curtis wrote:
I need to get some duplicate record information from a table and I
haven't found any way to do it yet. I figured there might be some type
of query I could do using a "for each" type command.
What I have is a table with names and companies. Some people have
multiple en
20, 2006 1:53 PM
To: [EMAIL PROTECTED]
Cc: mysql@lists.mysql.com
Subject: Re: help with query: select customers that ARO NOT
in orders table
On Fri, 20 Oct 2006, [EMAIL PROTECTED] wrote:
hi to all,
I have table customers (PK cust_id)
I have table orders (PK order_id, FK cust_id)
I need query t
, CT 06032
860.674.8796 / FAX: 860.674.8341
> -Original Message-
> From: Waldemar Jankowski [mailto:[EMAIL PROTECTED]
> Sent: Friday, October 20, 2006 1:53 PM
> To: [EMAIL PROTECTED]
> Cc: mysql@lists.mysql.com
> Subject: Re: help with query: select customers that ARO NOT
On Fri, 20 Oct 2006, [EMAIL PROTECTED] wrote:
Ok. Just found I gave wrong info. To make my life easier, the person who
created db named cust_id in 'orders' table as SoldTo
[EMAIL PROTECTED]
in this case,
select cust_id from customers
where cust_id not in
(select Soldto from orders);
will no
Ok. Just found I gave wrong info. To make my life easier, the person who
created db named cust_id in 'orders' table as SoldTo
[EMAIL PROTECTED]
in this case,
select cust_id from customers
where cust_id not in
(select Soldto from orders);
will not work
:(
> On Fri, 20 Oct 2006, [EMAIL P
On Fri, 20 Oct 2006, [EMAIL PROTECTED] wrote:
hi to all,
I have table customers (PK cust_id)
I have table orders (PK order_id, FK cust_id)
I need query that will selecct all customers from 'customers' they don't
have any order, there is not their cust_id in 'orders'.
couls somebody help me?
t
Hi,
Try with FULLTEXT search. Alter the table to make the search columns as
FULLTEXT columns, with MyISAM engine and retrieve the records using MATCH
keyword.
Ref:http://dev.mysql.com/doc/refman/5.0/en/fulltext-search.html
Thanks,
ViSolve DB Team.
- Original Message -
From: "Ed Curt
Have you dumped out your variables to make sure none of them is a
zero-length string? That would surely cause your problem.
Regards,
Jerry Schwartz
Global Information Incorporated
195 Farmington Ave.
Farmington, CT 06032
860.674.8796 / FAX: 860.674.8341
-Original Message-
From: Ed Curt
. I really appreciate your
help.
Jesse
- Original Message -
From: Douglas Sims
To: Jesse
Cc: MySQL List
Sent: Monday, August 21, 2006 12:07 PM
Subject: Re: Help with query
I think you are trying to use a regular expression in the like phrase. I
wasn't aware that MS SQL
I think you are trying to use a regular expression in the like
phrase. I wasn't aware that MS SQL can do regular expressions at
all? I've been using 2000 - perhaps the newer version can?
In MySQL, instead of saying:
LA.LastName LIKE '[A-E]%'
try this:
LA.LastName REGEXP '^[A-E]'
You can
Thanks Peter,
That looks pretty good to me. I never would have figured that out on
my own.
Dan T
On Jun 1, 2006, at 4:06 PM, Peter Brawley wrote:
Dan,
>I want to get a particular users 'rank' or row number from the query.
SELECT 1+COUNT(*) AS Rank
FROM results r1
INNER JOIN results r2 O
Dan,
>I want to get a particular users 'rank' or row number from the query.
SELECT 1+COUNT(*) AS Rank
FROM results r1
INNER JOIN results r2 ON r1.points
I have a regular query lets say:
SELECT user, points FROM results ORDER BY points DESC
so I get:
userpoints
---
john23
s
Dan wrote:
I have a regular query lets say:
Better to show the real query, rather than a simplified version. Simplified
requests get you simplified answers. What seems like a simplification to you,
may in fact hide a crucial piece of information, thus preventing anyone from
giving you a so
Kishore,
> We use Vbulletin for our message boards, and I have a
query which
>takes approximately 1.2 - 1.5 seconds to execute, on a table
('thread')
>having around 130,000 rows, it is as follows
>SELECT threadid
>FROM thread
>LEFT JOIN deletionlog
>ON ( thread.threadid = deletionlog
>how to achieve this?
>select table1.*, table2.*, table3.*, sum(table2.field3), sum(table2.field4)
>from table1, table2, table3 where table1.field1 = table2.field1 and
>table2.field1 = table3.field1
Your question as formulated has no answer. If you query aggregate
values like Sum on a table, y
Dear Reynier,
You can use JOIN on your both,
The JOIN have to run on the same feilds i.e IDA.
SELECT * FROM carro_de_compras LEFT JOIN os_articulo ON carro_de_compras.IDA
= os_articulo.IDA
This query returns all your users with their articles if any and you can
iterate on it.
but one note:
Use
Jay Paulson <[EMAIL PROTECTED]> wrote on 01/25/2006 10:09:36 AM:
> From the result set below I have 22 rows and the only difference is the
> date. I was wondering if there was a way to get all of these results
using
> GROUP BY instead of having to use LIMIT??
>
> As this table grows I'm going t
ja,
Your question is a little cryptic. If a questionid column value
identifies a particular question, and a vote column value contains a
user's vote (1,2,3, &c), can't you just write...
SELECT questionid, vote,count(vote)
FROM ...
GROUP BY questionid, vote
PB
-
[EMAIL PROTECTED] wrote:
<[EMAIL PROTECTED]> wrote on 10/22/2005 06:24:07 PM:
>
>
> I have a table of votes with four fields, a primary key, and userID,
> that are just there for tracking purposes. But then I have
> questionID and vote fields. For each question, a user could pick a
> number of it's importance from 1
Shawn,
- Original Message -
From: [EMAIL PROTECTED]
To: Dušan Pavlica
Cc: Michael Stassen ; list mysql
Sent: Wednesday, October 12, 2005 4:45 PM
Subject: Re: Help with query
Dušan Pavlica <[EMAIL PROTECTED]> wrote on 10/12/2005 10:00:53 AM:
> Thanks, Mi
ECTED]>
> To: "Dušan Pavlica" <[EMAIL PROTECTED]>
> Cc: "list mysql"
> Sent: Wednesday, October 12, 2005 2:54 PM
> Subject: Re: Help with query
>
>
> > Dušan Pavlica wrote:
> >> Hello,
> >>
> >> could someone help me
t want to write
querries for each DB system separately. Now I see that I will have to.
Dusan
- Original Message -
From: "Michael Stassen" <[EMAIL PROTECTED]>
To: "Dušan Pavlica" <[EMAIL PROTECTED]>
Cc: "list mysql"
Sent: Wednesday, October 12, 2
Dušan Pavlica wrote:
Hello,
could someone help me please to construct correct query or tell me what I'm
doing wrong?
I have three tables:
table products
table products_codes where some products could have assigned another additional codes
table products_prices
I want to get all rows from pro
On 04/10/2005, Jasper Bryant-Greene wrote:
> Kishore Jalleda wrote:
> > Could you kindly advice if this query can be made to run faster
> > SELECT title, template
> > FROM template
> > WHERE templateid IN
> > (608,2072,2073,1888,1898,1895,1897,1894,1896,1901,1903,1889,1900,189
> > 0,1891,1902,1904
Kishore Jalleda wrote:
Could you kindly advice if this query can be made to run faster
SELECT title, template
FROM template
WHERE templateid IN
(608,2072,2073,1888,1898,1895,1897,1894,1896,1901,1903,1889,1900,1890,1891,1902,1904,2104,624,625,2152,2212,1985,1996,614,1964,2103,2106,2113,1982,1983
Mathias,
To drop multiple IP, you can use distinct :
mysql> SELECT year, month, day, group_concat(distinct ip),count(*) AS
access
-> FROM access
-> WHERE year = 2005
-> AND month = 5
-> GROUP BY year, month,day
-> ORDER BY year, month, day;
+--+---+--+---
Hi Ronan,
I don't know if i understand your need, but your query gives something like that
:
mysql> SELECT year, month, day, ip, COUNT(*) AS access
-> FROM access
-> WHERE year = 2005
-> AND month = 5
-> GROUP BY year, month, day, ip
-> ORDER BY year, month, day;
+--
"Ronan Lucio" <[EMAIL PROTECTED]> wrote on 05/16/2005 04:21:17 PM:
> Mathias,
>
> > Hi,
> > look at group by ... with rollup at :
> > http://dev.mysql.com/doc/mysql/en/group-by-modifiers.html
>
> Thank you very much for your help.
>
> My needs aren´t this, exactly.
>
> GROUP BY WITH ROLLUP, re
Mathias,
Hi,
look at group by ... with rollup at :
http://dev.mysql.com/doc/mysql/en/group-by-modifiers.html
Thank you very much for your help.
My needs aren´t this, exactly.
GROUP BY WITH ROLLUP, returns me several lines of the
same day (one per IP), plus the total.
I need that every year-month-da
Hi,
look at group by ... with rollup at :
http://dev.mysql.com/doc/mysql/en/group-by-modifiers.html
Mathias
Selon Ronan Lucio <[EMAIL PROTECTED]>:
> Hello,
>
> I have a table where is saved all site´s access:
>
> access
>
> id
> year
> month
> day
> weekday
> hour
> minute
> ip
>
> Any colu
On Fri, 2005-02-04 at 09:19, Graham Cossey wrote:
> Could someone please offer a little help.
>
> I have a table like:
>
> Year, Month, Start_date
> 20041020041102
> 20041120041203
> 20041220050104
> 20050120050204
> 20050220050303
>
> I need to get the la
> > As I'm using 4.0.20 I can't use subqueries so how can I create
> a query that
> > does this?
> >
> > SELECT year, month
> > FROM `dc_months`
> > WHERE start_date = (SELECT MAX(start_date)
> > from dc_months
> > where start_date <= '20050204')
> >
Graham Cossey wrote:
Could someone please offer a little help.
I have a table like:
Year, Month, Start_date
20041020041102
20041120041203
20041220050104
20050120050204
20050220050303
I need to get the latest Year,Month for a given date, so for example today
(
Thanks for the advice Steven, I'll bear it in mind and do some reading.
Graham
> -Original Message-
> From: Steven Roussey [mailto:[EMAIL PROTECTED]
> Sent: 13 November 2004 02:52
> To: 'Graham Cossey'
> Cc: [EMAIL PROTECTED]
> Subject: RE: Help with qu
For production systems, I would never let the mysql optimizer guess a query
plan when there are joins of big tables and you know exactly how it should
behave. Once you think a query is finished, you should optimize it yourself.
Use STRAIGHT_JOIN and USE INDEX as found here in the manual:
http://de
It turns out that it appears to be a data discrepancy that caused the query
optimiser to, well, not optimise.
I thought the main table (r) with 3million records would be the problem, but
it was table p with 3100 records on the live server and 3082 records on my
dev pc that caused the problem. Alt
[snip]
>
> Have just run 'top' on the live server...
>
> Before running the query I get:
>
> 13:56:09 up 45 days, 11:47, 1 user, load average: 0.00, 0.28, 0.44
> 24 processes: 23 sleeping, 1 running, 0 zombie, 0 stopped
> CPU0 states: 0.0% user 0.0% system0.0% nice 0.0% iowait 100.0%
>
^ Does not look good to me !!
Comments?
Advice?
Thanks
Graham
> -Original Message-
> From: Jamie Kinney [mailto:[EMAIL PROTECTED]
> Sent: 11 November 2004 19:25
> To: Graham Cossey
> Cc: [EMAIL PROTECTED]; [EMAIL PROTECTED]
> Subject: Re: Help with query performance ano
How do the OS statistics look on both boxes. Do top, sar, vmstat or
iostat show any CPU, memory or I/O performance issues? Does anything
odd appear in the /var/log/messages file?
-Jamie
On Thu, 11 Nov 2004 18:42:48 -, Graham Cossey
<[EMAIL PROTECTED]> wrote:
>
>
> [big snip]
>
> >
> > Th
[big snip]
>
> These are two different plans. Your development machine is using
> the index
> yr_mn_pc on the r table and is joining that table last. On your
> production
> server, the r table is joined second and is joined by the index PRIMARY.
> Let me know how the ANALYZE TABLE I suggested in
Response at end
"Graham Cossey" <[EMAIL PROTECTED]> wrote on 11/11/2004 12:19:17 PM:
> > Thanks Shaun
> >
> > EXPLAIN shows the same 'possible keys' for each table but 'key' and
> > 'key-len' columns are different, as are the 'rows' as well of course.
> >
> > I guess this points to a probable
> Thanks Shaun
>
> EXPLAIN shows the same 'possible keys' for each table but 'key' and
> 'key-len' columns are different, as are the 'rows' as well of course.
>
> I guess this points to a probable difference in key definitions?
>
> Can 2 installations with the same table definitions produce differe
ke this? Maybe something in the configs?
>
> Thanks
>
> Graham
>
> > -Original Message-
> > From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
> > Sent: 11 November 2004 16:28
> > To: Graham Cossey
> > Cc: [EMAIL PROTECTED]
> > Subject: Re
le definitions produce different
results like this? Maybe something in the configs?
Thanks
Graham
> -Original Message-
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
> Sent: 11 November 2004 16:28
> To: Graham Cossey
> Cc: [EMAIL PROTECTED]
> Subject: Re: Help with
What does EXPLAIN show for the query on both systems? (I am wondering if
you may have an index on your development system that you do not have on
your production server.)
Shawn Green
Database Administrator
Unimin Corporation - Spruce Pine
"Graham Cossey" <[EMAIL PROTECTED]> wrote on 11/11/200
Shawn,
Thank you very for your answer.
Actually, I thought that a main SELECT couldn´t be filtered
by the WHERE clause refered to a field in a LEFT JOIN.
Now, looking better in the JOIN documentation I see this
issue.
Thank´s,
Ronan
This is a very FAQ:
SELECT t1.*
FROM TABLE_1 t1
LE
This is a very FAQ:
SELECT t1.*
FROM TABLE_1 t1
LEFT JOIN TABLE_2 t2
ON t1.id = t2.table1_id
WHERE t2.id is null
Shawn Green
Database Administrator
Unimin Corporation - Spruce Pine
"Ronan Lucio" <[EMAIL PROTECTED]> wrote on 10/27/2004 10:12:42 AM:
> Hi,
>
> I have two tables:
>
> TAB
SELECT `TABLE_1`.* FROM `TABLE_1` JOIN `TABLE_2` USING (`id`) WHERE
`TABLE_2`.`id` IS NULL
Asuming that the "reference" is the id field...
Regards, Jigal.
- Original Message -
From: "Ronan Lucio" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, October 27, 2004 3:12 PM
Subject
Shawn
> SELECT CityName, Count(ClientID) as ClientCount
> FROM City
> INNER JOIN Client
> on City.CityID = Client.CityID
> GROUP BY CityName
> HAVING ClientCount > 30;
Thank you very much,
It should solve by problem... :-)
Ronan
--
MySQL General Mailing List
For list archives: http:/
SELECT CityName, Count(ClientID) as ClientCount
FROM City
INNER JOIN Client
on City.CityID = Client.CityID
GROUP BY CityName
HAVING ClientCount > 30;
Shawn Green
Database Administrator
Unimin Corporation - Spruce Pine
"Ronan Lucio" <[EMAIL PROTECTED]> wrote on 09/10/2004 11:14:37 AM:
>
On 6 Feb 2004, at 14:38, Erich Beyrent wrote:
This seems really efficient, since the only large number of rows to
search against is the main listings table, if I read this right. Is
there any further optimization that I can do, or this as good as it
gets? Believe me, I am NOT complaining!!!
Yes,
the WHERE clause, right?
>
> Thanks!
>
> -Erich-
>
>
> -Original Message-
> From: Schwartz, Evelyn [mailto:[EMAIL PROTECTED]
> Sent: Friday, February 06, 2004 8:53 AM
> To: [EMAIL PROTECTED]; [EMAIL PROT
From: Erich Beyrent [mailto:[EMAIL PROTECTED]
Sent: Fri 2/6/2004 9:00 AM
To: [EMAIL PROTECTED]
Cc:
Subject: RE: Help with query
Hi Evelyn,
How would I do that - would something like this be what you had in mind?
, February 06, 2004 8:53 AM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: RE: Help with query
You will need parentheses around the 'or' clauses of your where clause.
You also don't seem to join the categories table with any other tables. If
you don't join tables you
You will need parentheses around the 'or' clauses of your where clause.
You also don't seem to join the categories table with any other tables. If you don't
join tables you will create what is called a 'cross product' query. If table A has 10
rows and table B has 20 rows then querying A and
Try single quotes around instead of double quotes.
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Jay Blanchard wrote:
[snip]
$query = "SELECT empnum,name,hdate,Photo,(YEAR(Curdate()) - YEAR(hdate))
as
timein FROM emp2 where mo
nth(hdate)=$mymonth and empnum < "" order by timein";
[/snip]
Change to single quotes around data
$query = "SELECT empnum,name,hdate,Photo,(YEAR(Curdate()) - YEA
[snip]
$query = "SELECT empnum,name,hdate,Photo,(YEAR(Curdate()) - YEAR(hdate))
as
timein FROM emp2 where mo
nth(hdate)=$mymonth and empnum < "" order by timein";
[/snip]
Change to single quotes around data
$query = "SELECT empnum,name,hdate,Photo,(YEAR(Curdate()) - YEAR(hdate))
as timein FR
Thanks, this works great in the MySQL server...I guess
I've never used temp tables before, but when I try to
run this in a PHP script, I get "table does not
exist". How do I do this?
--- Harald Fuchs <[EMAIL PROTECTED]>
wrote:
> In article
> <[EMAIL PROTECTED]>,
> Daren Cotter <[EMAIL PROTECTED]>
On Mon, Mar 17, 2003 at 10:47:09PM -0800, Daren Cotter wrote:
> This seems to be doing the same thing as the
> previously mentioned query...simply listing all
> mailing IDs, along with the # of members it was sent
> to. I've included both queries with their results
> below.
Hi Daren,
Heh. T
OK, attempt number two:
Let's see what you are after is the number of emails that a member
has received (say 25), and then you also want the number of members
that have received x-number (say 25) emails. Is this even close to
what you want?
I think the only way to answer the question(s) is to
This seems to be doing the same thing as the
previously mentioned query...simply listing all
mailing IDs, along with the # of members it was sent
to. I've included both queries with their results
below.
mysql> SELECT COUNT(member_id), COUNT(mailing_id) FROM
member_mailings GROUP BY mailing_id;
+--
On Mon, Mar 17, 2003 at 09:52:44PM -0800, Daren Cotter wrote:
> Jeff,
>
> That query simply gives me each mailing ID, along with
> the # of members associated with that mailing ID.
>
> What I NEED is to return the # of mailings sent to a
> member, and the number of members associated with that
>
Jeff,
That query simply gives me each mailing ID, along with
the # of members associated with that mailing ID.
What I NEED is to return the # of mailings sent to a
member, and the number of members associated with that
number.
I.e., if I do:
SELECT count(*) FROM member_mailings WHERE member_id
This should get you close:
SELECT mail_id, count(member_id) AS `# of members` FROM yourtable
GROUP BY mail_id;
At 18:44 -0800 3/17/03, Daren Cotter wrote:
I have a table that keeps track of when members of my
site are mailed. The important fields in the table
are: member_id, mail_id
I need to writ
* Justin French
> I have four (relevant) tables:
>
> category
> partner(pid,pname,etc)
> service(sid,sname,cid)
> sid2pid(sid,pid)
>
>
> This works fine, listing all services available within a category:
>
> SELECT service.sid,service.sname
> FROM service
> WHERE cid='3'
> ORDER BY service.sname AS
* Leonardo Javier Belén
> Thanks but actually I'm looking for a way to return all the relations
> upwards and downwards of a term. no matter the position (so I need general
> query to do that. Any ideas?
>
> >0100 - Rose tree
> >0101 - pink rose tree
> >0102 - red rose tree
> >0103 - rococo rose tr
nt: Tuesday, January 14, 2003 11:30 AM
Subject: Re: help with query
Hi Leo,
how about this:
select * from planttable where id like "01%" or id like "%02"
CH
Leonardo Javier Belén wrote:
>Thanks but actually I'm looking for a way to return all the relations
>upwar
ery to do that. Any ideas?
Thanks in advance. Leo.
- Original Message -
From: "Anthony Richardson" <
To: "Leonardo Javier BelÈn" <[EMAIL PROTECTED]>
Sent: Monday, January 13, 2003 9:52 PM
Subject: Re: help with query
Hi,
I do not clearly understand your q
o Javier BelÈn" <[EMAIL PROTECTED]>
Sent: Monday, January 13, 2003 9:52 PM
Subject: Re: help with query
Hi,
I do not clearly understand your question, but if it's looking for
query, please try the following:
select * from planttable
where substring(id, 1, 2)="01" and subs
>From you example, not quite sure what you are trying to do (I could if, for
example generic tree was 0199, and 01 was tree and last two characters were
color or something like that)
At any rate, you can use string functions to pull data from portions of
fields to build whatever you want to search
Hi,
SELECT LEFT(YOUR_COLUMN,2) FROM YOUR_TABLE.for position
SELECT RIGHT(YOUR_COLUMN,2) FROM YOUR_TABLE for type
Regards,
Gelu
_
G.NET SOFTWARE COMPANY
Permanent e-mail address : [EMAIL PROTECTED]
On Fri, 2002-06-14 at 18:16, Hathaway, Scott L wrote:
> I am trying to get something like the following:
>
> Title
> -
> topic #1
> sub topic #1.1
> topic #2
> sub topic #2.1
> sub topic #2.2
>
> from the following table (I am using php for scripting).
>
>
I think the best way to do this is to set up two tables. One for the main
topic list, then one for each sub topic. You may already have this but I
cant see it here. Anyways to get your selection order correct you could do
something like:SELECT * FROM forum ORDER BY parent_id, id
Have any exampls
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At Donnerstag, 4. April 2002 17:57 Hathaway, Scott L wrote:
> Yes, that should only cause a reordering within the group itself, but in my
> case, the group breaks into two groups!
Your 'group by' clause needs to have the same fields (and in the same
Yes, that should only cause a reordering within the group itself, but in my
case, the group breaks into two groups!
Scott
-Original Message-
From: Michael Zimmermann [mailto:[EMAIL PROTECTED]]
Sent: Thursday, April 04, 2002 8:58 AM
To: Hathaway, Scott L; Mysql (E-mail)
Subject: Re: help
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At Donnerstag, 4. April 2002 15:29 Hathaway, Scott L wrote:
> I have the following query:
>
> select *, max(event_date) as high, min(event_date) as low from schedule
> where event_date between '2002-03-01' and '2003-04-30' group by
> week_ending,meeti
Hmmm... Looks like you over did the query to me. This should work.
SELECT o.OrderID, c.CustomerFirst, c.CustomerLast, s.SalesRepFirst,
s.SalesRepLast
FROM Orders as o, Customers as C, SalesReps as s
WHERE O.CustomerPhone=c.CustomerPhone AND o.SalesRepID=s.SalesRepID
of course you don't need the
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