- Original Message -
> From: "David Lerer"
>
> Have you tried to set city = null (i.e. without the quotes)?
Spot on, I'd think.
NULL values are not a string with "NULL" in it - that's only what it looks like
in query results :-) An empty string ('') is to strings what 0 (zero) is for
Ahhh... Thank you, that was exactly what the problem was. I will fix the
code that is setting the value of these new records to 'NULL'.
Thank you.
2012/3/9 David Lerer
> Have you tried to set city = null (i.e. without the quotes)? David.
>
>
>
> -Original Message-
> From: Richard
Have you tried to set city = null (i.e. without the quotes)? David.
-Original Message-
From: Richard Reina [mailto:gatorre...@gmail.com]
Sent: Friday, March 09, 2012 4:24 PM
To: mysql@lists.mysql.com
Subject: query problem with null
When I do the following query:
SELECT * FROM
On Wed, Apr 16, 2008 at 4:35 AM, sivasakthi <[EMAIL PROTECTED]> wrote:
> Hi all,
>
> Iam having the one table name called AccessDetails and data inside that
> tables is following,
>
[snip=schema]
>
> In that , I need to calculate the number of total sites , number of
> total Accessed Sites,num
> how do I return a single row per property even if it has 3 or 4 images
> attached to it.
Please reply to the list instead of directly to me.
You could do a:
select p.from properties p where exists (select i.* from images i
where i.property_id = p.property_id)
> > >I have a table of propert
No I want all the properties only one regardless of how many images are
attached to them. Think I need a distinct in there somewhere,
- Original Message -
From: "Jon Ribbens" <[EMAIL PROTECTED]>
To:
Sent: Wednesday, May 09, 2007 6:56 PM
Subject: Re: Query problem
On Wed, May 09, 2007 at 07:14:38PM +0200, Martijn Tonies wrote:
> >I have a table of properties that is linked to a table f images with a one
> property to many images relationship. I >have manged this with nested
> queries but want to try and do it on one line. My current query
> >
> >$query = "S
>I have a table of properties that is linked to a table f images with a one
property to many images relationship. I >have manged this with nested
queries but want to try and do it on one line. My current query
>
>$query = "SELECT * FROM images, properties WHERE images.property_id =
properties.prop
On 8/3/06, André Hänsel <[EMAIL PROTECTED]> wrote:
Hi Dan, hi Obed,
of course I have no specific username, I want the last 5 downloads of each
distinct username in the table. :)
i was thinking a lot... and i can't find the solution but maybe yo
can do somthing like this
select user,downl
At 03:08 PM 8/3/2006, André Hänsel wrote:
Hi,
I have a table logging downloads (time, username, download).
Now I'd like to have the last 5 downloads per user.
Can someone tell me a solution (or what to search for)?
Regards,
André
--
MySQL General Mailing List
For list archives: http://list
For a specific username:
SELECT username, time, download
FROM table
WHERE username = 'someusername'
ORDER BY time DESC
LIMIT 5
Dan
On 8/3/06, André Hänsel <[EMAIL PROTECTED]> wrote:
Hi,
I have a table logging downloads (time, username, download).
Now I'd like to have the last 5 downloads per
On 8/3/06, André Hänsel <[EMAIL PROTECTED]> wrote:
Hi,
I have a table logging downloads (time, username, download).
Now I'd like to have the last 5 downloads per user.
Can someone tell me a solution (or what to search for)?
SELECT download FROM table WHERE username='user' ORDER BY time DES
Rhino wrote:
- Original Message - From: "John Meyer" <[EMAIL PROTECTED]>
To: "List: MySQL"
Sent: Tuesday, May 30, 2006 5:09 PM
Subject: Query problem
Setup
TITLES:
TITLE_ID
AUTHORS:
AUTHOR_ID
TITLE_AUTHOR:
(TITLE_ID,AUTHOR_ID)
Problem:
Given a title, I need to find all the aut
- Original Message -
From: "John Meyer" <[EMAIL PROTECTED]>
To: "List: MySQL"
Sent: Tuesday, May 30, 2006 5:09 PM
Subject: Query problem
Setup
TITLES:
TITLE_ID
AUTHORS:
AUTHOR_ID
TITLE_AUTHOR:
(TITLE_ID,AUTHOR_ID)
Problem:
Given a title, I need to find all the authors who are
>
To: "'Luke'" <[EMAIL PROTECTED]>;
Sent: Wednesday, May 24, 2006 2:16 AM
Subject: RE: Query problem: UNION in subquery
Hi Luke..
Try this
SELECT ObjectId FROM
(SELECT f15.Form15SampleTube1RnaBarcode AS ObjectId,
f15.Form15PatientID AS PtId FROM form15 f15
WHER
Hi Luke..
Try this
SELECT ObjectId FROM
(SELECT f15.Form15SampleTube1RnaBarcode AS ObjectId,
f15.Form15PatientID AS PtId FROM form15 f15
WHERE f15.Form15SampleTube1RnaBarcode IN ('01D2V','01DH6')
UNION
SELECT f15.Form15SampleTube6RnaBarcode AS ObjectId,
f15.Form15PatientID AS PtId
On Wed, 8 Mar 2006 10:12:22 - <[EMAIL PROTECTED]> wrote:
> but I have two other filters which may or may not be chosen. (area, and
> interest).
>
> $query = "SELECT * FROM $table_name WHERE sname LIKE '$search_string%' AND
> area='area' AND interest='interest' ORDER BY fname $type";
>
>
[EMAIL PROTECTED] wrote:
I am fairly new to sql and am now getting into the area of slightly
more complex queries.
At present my query is
$query = "SELECT * FROM $table_name WHERE sname LIKE '$search_string%'
ORDER BY fname $type";
but I have two other filters which may or may not be chosen
On 3/8/06, Adrian Bruce <[EMAIL PROTECTED]> wrote:
> one solution (may not be the best but would work) would be to use 'like'
> instead of '=' and then put wildcards %%$var % around the variable so
> that if it is not there then it wount effect the query.
>
Yeah, I use this kind of "trick" for SEL
one solution (may not be the best but would work) would be to use 'like'
instead of '=' and then put wildcards %%$var % around the variable so
that if it is not there then it wount effect the query.
Ade
[EMAIL PROTECTED] wrote:
I am fairly new to sql and am now getting into the area of slight
Sheeri,
Thanks for the help. I tried your sample queries, but they dont really
return what I'm looking for. I think I've found a solution though.
Given the contents of a case, I'm looking for a unique case id, basicially I
want to search for a case if it exists once I've decided the configuration
You originally mention your UNION "doesn't work" but you did not
specify the query. This is a simple or query, or union. You can do
either:
select CaseType_idCaseType,Sizes_idsizes,qty from CaseType_has_Sizes
where (qty=1 and Sizes_idsizes=2) or (qty=1 and Sizes_idsizes=4);
or
select CaseType_
Sheeri,
The table I'm searching on has a composite primary key since it's mapping an
N:M relationship between Cases and Sizes.
Here's the create statement for the table I'm searching on:
DROP TABLE IF EXISTS `CaseType_has_Sizes`;
CREATE TABLE `CaseType_has_Sizes` (
`CaseType_idCaseType` int(10
Hi Conor,
The table you showed us has 2 primary keys, which is not possible.
Can you do a SHOW CREATE TABLE on *each* table?
-Sheeri
On 2/8/06, Conor McTernan <[EMAIL PROTECTED]> wrote:
> Hello, I'm having a hell of a time figuring this query out, maybe someone
> can point me in the right direc
Ok, Thanks for all Roger.
-Mensaje original-
De: Roger Baklund [mailto:[EMAIL PROTECTED]
Enviado el: viernes, 22 de abril de 2005 4:06
Para: Dto. Sistemas de Unitel
CC: mysql@lists.mysql.com
Asunto: Re: Query Problem
Dto. Sistemas de Unitel wrote:
> You don't understand me, I re
Dto. Sistemas de Unitel wrote:
You don't understand me, I refer that if in a table I use productos.prod_id
and in other table indexes.id if I can use this two fields like the same
index, because when I named the two equal, the index start to work fine.
There should be no problem with joining two ta
EMAIL PROTECTED]
Enviado el: jueves, 21 de abril de 2005 18:17
Para: mysql@lists.mysql.com
CC: Dto. Sistemas de Unitel
Asunto: Re: Query Problem
Dto. Sistemas de Unitel wrote:
> Hi Roger,
>
> You are ok, there was an index problem in one table, they name of the rows
> wasn't equal and
Dto. Sistemas de Unitel wrote:
Hi Roger,
You are ok, there was an index problem in one table, they name of the rows
wasn't equal and MySQL didn't recognize they as the same index. I have
changed the row name and now is working fine, but I have a little question,
How can I use indexes with different
's tables?
Thanks for your help, you have been very helpful for me.
Roberto
-Mensaje original-
De: Roger Baklund [mailto:[EMAIL PROTECTED]
Enviado el: miércoles, 20 de abril de 2005 18:30
Para: mysql@lists.mysql.com
CC: Dto. Sistemas de Unitel
Asunto: Re: Query Problem
Dto. Sistemas
Dto. Sistemas de Unitel wrote:
Hi Roger,
That was just I need. The order isn’t like you say:
++-+---++---+-+-
++---+-+
| id | select_type | table | type | possible_k
Hi Roger,
That was just I need. The order isnt like you say:
++-+---++---+-+-
++---+-+
| id | select_type | table | type | possible_keys | key | key_len
| ref
Dto. Sistemas de Unitel wrote:
[...]
something like
/indexes.id=productos.prod_id and indexes.id_termino=terminos.id_termino
and termino="computer" and termino=”intel”/ I know that is impossible,
but maybe there is another way to make that).
Yes, there is another way. You _can_ join the same tab
o be printed again...
Any ideas?
From: sol beach <[EMAIL PROTECTED]>
Reply-To: sol beach <[EMAIL PROTECTED]>
To: Xristos Karvouneas <[EMAIL PROTECTED]>
Subject: Re: Query Problem
Date: Tue, 15 Mar 2005 12:33:24 -0800
http://www.catb.org/~esr/faqs/smart-questions.html
It would
get it in the format specified in the message, i.e.
if
> the title is the same, I do not want it to be printed again...
>
> Any ideas?
>
> >From: gerald_clark <[EMAIL PROTECTED]>
> >To: Xristos Karvouneas <[EMAIL PROTECTED]>
> >CC: mysql@lists.mysql.
message, i.e. if
the title is the same, I do not want it to be printed again...
Any ideas?
From: gerald_clark <[EMAIL PROTECTED]>
To: Xristos Karvouneas <[EMAIL PROTECTED]>
CC: mysql@lists.mysql.com
Subject: Re: Query Problem
Date: Tue, 15 Mar 2005 14:49:45 -0600
Xristos Karvouneas
message, i.e. if
the title is the same, I do not want it to be printed again...
Any ideas?
From: sol beach <[EMAIL PROTECTED]>
Reply-To: sol beach <[EMAIL PROTECTED]>
To: Xristos Karvouneas <[EMAIL PROTECTED]>
Subject: Re: Query Problem
Date: Tue, 15 Mar 2005 12:33:24 -0800
h
Xristos Karvouneas wrote:
Dear All,
I am faced with the following problem: I have got three tables -
book,author and authorbook - containing information about books and
authors (some books have multiple authors). I want to do a query that
would print information like:
Title 1 Author 1
Did you want
WHERE Name LIKE 'sandy'
OR (main_data.Display_In_Search = 1
AND main_data.Expiry_Date >= CurDate())
OR
WHERE main_data.Expiry_Date >= CurDate()
AND (Name LIKE 'sandy'
OR main_data.Display_In_Search = 1 )
-Original Message
On Tuesday 08 February 2005 17:03, Coz Web wrote:
>
> This will (as I believe Daniel suggested) keep things relatively
> simple, avoiding an overly complex query that you cannot maintain in
> the future.
Well, my solution was, as you'll have observed, vastly over-complicated. I
think I'd misunder
Your not getting a valid result from your query. Add
if (!$result) { echo 'Bad query - message: ' . mysql_error();}
I think it will give you a syntax error on your query. MySQL syntax for
the LIMIT clause is:
[quote]
The LIMIT clause can be used to constrain the number of rows returned by
the SEL
On Tue, 08 Feb 2005 15:52:02 +0100, Joachim Klöfers
<[EMAIL PROTECTED]> wrote:
> Oh, oh, Joachim,
> not able to calculate, but asking questions about queries.
>
> Coz , of course its supposed to be 1955 (id 13 & 47)
>
> Joachim
>
>
> Coz Web schrieb:
> Just to confirm, is amount2 for region 1
On Tue, 8 Feb 2005 11:37:20 +, [EMAIL PROTECTED]
<[EMAIL PROTECTED]> wrote:
> On Tuesday 08 February 2005 08:09, Joachim Klöfers wrote:
> > Hi, all
> >
> > I hope somebody can help me.
>
>
> >
> > Many thanks in advance
> > Joachim
>
> That is a very thorny problem. May I observe that you wi
Just to confirm, is amount2 for region 1 supposed to be 1630 (id 47)
or 1955 (ids 13 & 47)?
Coz
> What I would like to have is a result like this:
> ++---+--+
> | region | sum(amount1) if current=J | sum(amount2) |
> ++---
On Tuesday 08 February 2005 08:09, Joachim Klöfers wrote:
> Hi, all
>
> I hope somebody can help me.
>
> Many thanks in advance
> Joachim
That is a very thorny problem. May I observe that you will find things much
easier, if you add unique primary keys to tables 2 & 3, thus:
ALTER TABLE ADD p
Schalk Neethling wrote:
I run the following type of query against it:
SELECT * FROM documents WHERE MATCH (content) AGAINST
('demyer Padgham robinson') AND doctype = 'Motion' AND jstate =
'California:
State Court' OR jdistrict = 'Circuit Court: Federal, California'
SELECT * FROM documents WHERE
Hey there
I have the following table structure:
CREATE TABLE documents (
id int(11) NOT NULL auto_increment,
user varchar(50) NOT NULL default '',
olduser varchar(50) NOT NULL default '',
username varchar(100) NOT NULL default '',
uploaddate timestamp(14) NOT NULL,
docdate varchar(100) NOT NU
06/30/2004 02:22 cc: [EMAIL PROTECTED]
PM Fax to:
Subject: Re: query p
Actually, i figured it out. don't know why it was so hard to see it.
all i did was change:
LEFT JOIN outbound_fax_info b on ucase(a.barcode) = ucase(b.barcode)
to:
LEFT JOIN outbound_fax_info b on (b.barcode != '' and ucase(a.barcode =
b.barcode).
if barcode was blank in outbound (b) then the
Eliminate the rows from outbound_fax_info where the barcode is blank. The
result of the JOIN will be all of the rows of inbound_fax_info matched up
to:
a) information form outbound_fax_info except where the barcodes match
b) blank columns where the barcodes didn't match.
Use the COALE
Post the table structure, what that query it returning and what you
think it should return.
-Eric
On Sun, 27 Jun 2004 23:33:55 +0200, Schalk <[EMAIL PROTECTED]> wrote:
>
> Why is the following query retuning doctype's different to what is asked
> for?
> SELECT * FROM documents WHERE jstate = 'Ca
Why is the following query retuning doctypes different to what is asked
for?
SELECT * FROM documents WHERE jstate = 'California: State Court' AND doctype
= 'Verdict'
Any ideas? As far as I can see it should only return a document if it is a
Verdict and matches the state California: State Court.
I understand why we would want these to be in relational forms but in this
situation it isn't practical for a number of reasons. Normally that would
be what I would do.
However in this case the nature of the application is such that doing this
would cause an enormous load on the system as we wo
I understand how these lists come into existence (trust me I have had to
deal with enough of them). However, it is standard practice when working
with _relational_ databases to split those lists of numbers into unique
record pairs in a separate table. Your original source data was not
relational,
I believe you could do:
SELECT *
FROM Table
WHERE FIND_IN_SET(number, comma_delimited_field)
but this will be /very/ slow. This query is forced to
examine each and every row to determine whether or not your
number is in the field.
The better solution is to break up that field, which is
generally
You probably shouldn't have setup your database structure like that.
You should always break out multiple values into a separate table, each
value being stored in one record, then "link" them through a common
record id. A one to many relation.
As far as the database is concerned, those aren't de
Hi,
You need:
select job,avg(sal) from emp group by 1 order by 2 limit 1;
Cheers,
Andrew
-Original Message-
From: Edouard Lauer [mailto:[EMAIL PROTECTED]
Sent: Saturday 31 January 2004 19:23
To: [EMAIL PROTECTED]
Subject: Query problem
Hello,
I would like to query the littlest aver
* Edouard Lauer
> I would like to query the littlest average salary. I have a table with
> employees and their salary like that:
>
> +---+--+
> | job | sal |
> +---+--+
> | CLERK | 800 |
> | SALESMAN | 1600 |
> | SALESMAN | 1250 |
> | MANAGER | 2975 |
> | S
John Wards wrote:
I have this query:
SELECT *
FROM news_category
LEFT JOIN news_x_cat ON news_category.id = news_x_cat.cat_id
WHERE (
news_x_cat.news_id = 9 OR news_x_cat.news_id IS NULL
)
Which gives me this output:
id title perm show news_id cat_id
1 About Us 1
You have not shown us anything that would indicate that your output is
not correct.
If you think something is missing you have to show us what is missing,
and why you think
it should not be.
John Wards wrote:
I have this query:
SELECT *
FROM news_category
LEFT JOIN news_x_cat ON news_category.
sage -
> From: "Nils Valentin" <[EMAIL PROTECTED]>
> To: "Sparky Kopetzky" <[EMAIL PROTECTED]>; "My Sql List"
> <[EMAIL PROTECTED]>
> Sent: Sunday, June 01, 2003 19:52
> Subject: Re: Query problem
>
> > Hi everybody,
> &
<[EMAIL PROTECTED]>
Sent: Sunday, June 01, 2003 19:52
Subject: Re: Query problem
> Hi everybody,
>
>
> I hope ASAFP stands for something like AS Soon AS Feasable Possible ;-)
>
> We are not going to swear are we ?
>
> Best regards
>
> Nils Valentin
>
> 200
Hi everybody,
I hope ASAFP stands for something like AS Soon AS Feasable Possible ;-)
We are not going to swear are we ?
Best regards
Nils Valentin
2003年 6月 2日 月曜日 07:30、Sparky Kopetzky さんは書きました:
> I have a view I need to create from several tables where I'm looking up one
> value from a tabl
Hi,
Sounds like you will need to use subqueries which is available at MySQL
4.1 and above ..
See: http://www.mysql.com/doc/en/Nutshell_4.1_features.html
Hope this helps.
Gurhan
On Sun, 2003-06-01 at 18:30, Sparky Kopetzky wrote:
> I have a view I need to create from several tables where I'm lookin
Jon,
> Where can I look to see the Warnings?
MySQL 4.1 will come with an enhanced error/warnings reporting system
where you can use SHOW ERRORS and SHOW WARNINGS (see
http://www.mysql.com/doc/en/SHOW_WARNINGS.html for details).
If you don't have 4.1 (as most of us) you can tell the server to log
> -Original Message-
> From: Jon Miller [mailto:[EMAIL PROTECTED]]
> Sent: Monday, January 20, 2003 1:49 PM
> To: [EMAIL PROTECTED]
> Subject: query problem
>
>
> I ran a query as follows:
> Insert Into db_test.tbl_dbaddr (Client, Contact, Addr,
> OfcPhone) SELECT Client AS Client, Bus
nd him."
G. K. Chesterton - Illustrated London News, 1/14/11
-Original Message-
From: Tom Emerson [mailto:[EMAIL PROTECTED]]
Sent: Thursday, September 05, 2002 11:43 AM
To: [EMAIL PROTECTED]
Subject: RE: query problem
I am by no means an "SQL-expert", but I'll give this a sh
I am by no means an "SQL-expert", but I'll give this a shot... :)
> -Original Message-
> From: Richard Brenner [mailto:[EMAIL PROTECTED]]
> Subject: query problem
>
> I have two tables with the following structure:
>
> Users:
> | Field| Type
> | id | int(10) unsigned
> |
Hello!
Almar van Pel wrote:
>Hello,
>
>I was trying to create a simple perl program, where my domains where listed
>followed by there DNS records.
>But It loops once, and then ends with error DBD::mysql::st fetch failed:
>fetch() without execute() at test.cgi line 61.
>
>I thougt this was the ea
On Mon, 2002-09-02 at 11:37, Harald Fuchs wrote:
> In article <1030961610.8175.5.camel@pascal>,
> Martin Waite <[EMAIL PROTECTED]> writes:
>
> > Hi,
> > You need to use two separate database and statement handles - you can
> > only have one active query per handle.
>
> > eg.
>
> > $dbh1 = DBI-
Hi,
You need to use two separate database and statement handles - you can
only have one active query per handle.
eg.
$dbh1 = DBI->connect(...);
$dbh2 = DBI->connect(...);
$sth1 = $dbh1->prepare( ... );
$sth1->execute(...);
while ( $sth1->fetch() ) {
$sth2 = $dbh2->prepare( ... );
Change your query for:
select red,green,blue from colorchanger INNER JOIN
jobattributekit ON colorcode = value where
attributekit = "Color" and jobnumber =
"28200124RB4-001" and scenario="JN75K";
Also remember that MySQL does not allow sub-queries.
--- Amit Lonkar <[EMAIL PROTECTED]> wrote:
>
In the last episode (Aug 12), duo fu said:
> I have just created a small web site with php/mysql. I do a query
> into one of my tables whose ".MYI=338K " and ".MYD=7.6M". I could
> only retrieve some part of the data and then the browser just died
> there. My query is " select * from Forces". The
* saraswathy saras
> i have a problem with query.I have no idea about it,whether it
> can be done
> or not.i want to query out name order by alphabet,The range is
> provided like
> Aa - Ad.
> so the result should be like this:-
>
> Browse Aa to Ac
>
> Name
>
> A
...hm... 'A' is not in the ra
Forget everything i said, now i realize that i didn't understand the
problem very well.
Francisco Reinaldo is right, use LEFT JOIN.
Sorry for having replied that!
On Thu, 2002-07-25 at 20:40, Kevin wrote:
> Hello,
>
> I have a query that runs perfectly until one of the items has no value or is
>
Hi,
On Thu, 2002-07-25 at 20:40, Kevin wrote:
> Hello,
>
> I have a query that runs perfectly until one of the items has no value or is
> set to 0:
>
> SELECT
> item.*, color.Name AS COLOR,
> shapecode.Shape AS SHAPE,
> clarity.Name AS CLARITY
> FROM item, color, shapecode, clarity
Hi,
Use LEFT JOIN instead of =. In a 1:m relationship,
only records that match in both tables are selected.
With L.J., the master is always selected even if the
record is not present in the child.
Master
Id
1
2
3
4
5
Children
FK_id Value
1 V1
1 V2
2 V3
Select id, value from Master,
Hi,
If you want the last date, isn't it just:
SELECT clientid,max(datedone)
FROM table_name
WHERE done = 'true' and x = ''
GROUP BY clientid;
? Hope it helps,
On Fri, 2002-07-26 at 08:27, Nixarlidis Aris wrote:
> Hi,
> I face the following situation.I have a number of clients-each with a
+--+
>
> I hope this helps you to better understand my problem.
> If I could touch the database I would split BASIC_DATA into two different
> tables AUTHORS and PUBLISHERS. But I cannot touch the DB structure.
>
> Gigi
>
> -Messaggio originale
Hello, Gigi,
By "decoded", do you mean that you want the words "Author" and "Publisher"
to appear in your table instead of "1" and "2"? And you can't create or
modify tables? Short of replacing the codes in the columns, it seems to me
that you'd need to have a decode table. Something like:
+
Now it has transformed into this:
");
}
else{
print( "Non riesco a connettermi al server.");
exit;
}
$user=$_POST['user'];
$password=$_POST['password'];
$query=(mysql_query("select * from admin where User='%$user%'",$link));
$row = mysql_fetch_array($query);
if($row["user"]==$user
On Sat, 01 Jun 2002 11:58:38 +0200
Claire Forchheimer <[EMAIL PROTECTED]> wrote:
I know the answer to the first part at least. I think you want to use two columns in
the order by clause, and leave out the group by clause. As in:
select * from tbl order by apt, name;
I'm afraid its too late a
[EMAIL PROTECTED] ("Daren Cotter") wrote:
>I am having major troubles creating this query...ok here's some
>background info:
>
>I have three tables: members, which contains info about the member, such
>as city, state, zip, marital status, etc; interests, which stores just
>an interest_id and name
mailto:[EMAIL PROTECTED]]
Sent: Thursday, May 23, 2002 10:31 PM
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Subject: RE: Query Problem
Okay, I think I'm -almost- there:
I have these tables:
tracks
albums
artists
Each with an id MEDIUMINT NOT NULL PRIMARY KEY and a track, album, or artist
column.
T
TED]]
Sent: Thursday, May 23, 2002 9:34 PM
To: Jason Soza; [EMAIL PROTECTED]
Subject: RE: Query Problem
Other than it is uglier than a Hut?
The higest ideals of a database is to separate data into tables that keep
track
of data for the same objects. Some databases break these rules (oh and h
nherent flaws with this design that you guys can point
> out for me? Or is this actually a little more efficient than the
> current way?
>
> Jason Soza
>
> - Original Message -
> From: "Opus" <[EMAIL PROTECTED]>
> Date: Thursday, May 23, 2002 4:50 pm
&g
Or is this actually a little more efficient than the
current way?
Jason Soza
- Original Message -
From: "Opus" <[EMAIL PROTECTED]>
Date: Thursday, May 23, 2002 4:50 pm
Subject: RE: Query Problem
> Jason,
>
> First, as to the structure of the database. I agree
albums.id = albums_artists.album_id
> AND artists.id = albums_artists.artist_id
>
> I get 718 returns instead of 614. If more than one artist is linked to one
> album, only the song from the first artist shows in the tracks column and it
> shows for all artists (no other songs by t
I'm wondering if anyone has a response for the query question I posted
last night regarding my Songs/Albums/Artists database and related
linking tables.
I'm new to this list, so I'm not sure what kind of response time to
expect. I'm still unable to solve this problem on my own, and searches
o
lto:[EMAIL PROTECTED]]On Behalf Of Sammy Lau
Sent: Wednesday, May 22, 2002 8:18 PM
To: Jason Soza
Cc: [EMAIL PROTECTED]
Subject: Re: Query Problem
to make it easier for others to help you. you should have posted the
create table statement, insert statement for a small set of data so that
anyone of
to make it easier for others to help you. you should have posted the
create table statement, insert statement for a small set of data so that
anyone of us could easier reproduce your problem.
btw, are you sure you need 3 links between those 3 tables. please
correct me if i'm wrong. i think 2 link
Hi,
This might work for you:
select @tempvar := max(datecolumn) from tablename group by datecolumn order
by datecolumn desc limit 3;
select * from tablename where datecol >= @tempvar order by datecolumn desc;
Anvar.
At 06:12 AM 02/05/2002 +, you wrote:
>hi everyboby,
>
>How to select lates
Uhm, 3?
Didn't you wrote 5?
If you want just 3 do this: SELECT name,date FROM dates ORDER BY date LIMIT
0,3
regars,
Jan
- Original Message -
From: "saraswathy saras" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, May 02, 2002 8:12 AM
Subject: query problem
> hi everyboby
* saraswathy saras
> How to select latest 3 days records from the table according to the
> latests date.
> The data is like this:-
>
> name date
> a 02-03-01
> b 02-03-15
> c 02-03-20
> d 02-03-20
> e 02-04-28
> f 02-04-28
> g 02-04-30
>
> The result should be lik
Hi,
This might work for you:
select @tempvar := max(datecolumn) from tablename group by datecolumn order
by datecolumn desc limit 3;
select * from tablename where datecol >= @tempvar order by datecolumn desc;
Anvar.
At 06:12 AM 02/05/2002 +, you wrote:
>hi everyboby,
>
>How to select lates
Thanks guys, works a treat. Yip, it was the Alias thing... interesting.
- Original Message -
From: "Roger Baklund" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Cc: "asherh" <[EMAIL PROTECTED]>
Sent: Wednesday, February 27, 2002 2:39 PM
Subject: RE
* asherh
> An example of the record output I was after is...
>
> ProjectIDProjectOwnerProjectManager
> A12345 Bob Smith John Smith
>
> from tables:
>
> User -
> UserIdFullName
> 1Bob Smith
> 2John Smith
>
> Project -
> ProjectIdProj
Hi Ash,
> I have tried all sorts of joins and statements without much success... I can
> obtain one name or both names if they are the same... but not different
> names together in the one record.
=how about some example code showing what you are doing?
At the very least it gives me a 'starting
joins you are talking
about. I think I must be missing something fundamental here.
Chrs,
Ash
- Original Message -
From: "DL Neil" <[EMAIL PROTECTED]>
To: "asherh" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Wednesday, February 27, 2002 9:12 AM
Su
Hi Ash,
> I am using MySQL 3.22.32 and are trying to accomplish the following (without
> going into too much detail, this is an example of the exact situation)...
>
> 1) I have two tables:
>
> a) User table containing: UserID, FullName
> b) Project table containing: ProjectID, ProjectManagerID
From: <[EMAIL PROTECTED]>
> >>My query
> select * from table1,table2 WHERE table1.ID = table2.code
> >> Query results
> 1 2 2
>
> >> Desired results
> 1 2
Try:
SELECT * FROM table1,table2
WHERE table1.ID = table2.code
GROUP BY table2.code
You'll find this someplace in:
http://ww
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