hello, i am working on my personal website wih php 5.4.16 / mysql 5.6.12 (my
system : windows 7 / wampserver 2).
i have a bug when i am running my connection to database webpage.
My error message is the following :
Erreur SQL : You have an error in your SQL syntax; check the manual
- Original Message -
From: florent larose florent.lar...@hotmail.com
Subject: sql syntax error
near ''membres2' WHERE
[...]
FROM 'espace_membre2'.'membres2' WHERE
You were on the right path - mysql is wibbly about quotes. Either remove the
quotes entirely ( espace_membre2
Hi,
Le 08/08/2014 17:48, Johan De Meersman a écrit :
As your code is french, I'll assume you're on Azerty; the backtick is Alt-Gr
plus the rightmost key (right next to return) on the middle row. Enjoy
spraining your fingers :-p
/johan
Alt-GR plus '7' for French keyboard layout ;)
[
I have 2 tables. Table A containing 2 fields. A user ID and a picture ID =
A(uid,pid) and another table B, containing 3 fields. The picture ID, an
attribute ID and a value for that attribute = B(pid,aid,value).
Table B contains several rows for a single PID with various AIDs and values.
On Wed, 2010-06-16 at 08:59 +0100, Nigel Wood wrote:
I'd use:
drop temporary table if exists AttSearchMatches;
select pid as targetPid, count(*) as criteraMatched from B where
userId=35 and ( (b.aid=1 and b.value 50) OR (b.aid=3 and b.value
=4) ) group by pid having criteraMatched = 2;
drop
Hi!
Daniel Brown wrote:
[Top-post.]
You'll probably have much better luck on the MySQL General list.
CC'ed on this email.
On Tue, Jun 15, 2010 at 20:58, Jan Reiter the-fal...@gmx.net wrote:
Hi folks!
[[...]]
I have 2 tables. Table A containing 2 fields. A user ID and a
[Top-post.]
You'll probably have much better luck on the MySQL General list.
CC'ed on this email.
On Tue, Jun 15, 2010 at 20:58, Jan Reiter the-fal...@gmx.net wrote:
Hi folks!
I'm kind of ashamed to ask a question, as I haven't followed this list very
much lately.
This isn't
Thanks, Scott.
I thought I couldn't have missed ','(comma) before. But today somehow it
works... ;;
I wasted hours figuring this out, but you saved me!
Maybe I'm still a complete newbie!
Thanks, again. Have a great day. :)
On Thu, Apr 30, 2009 at 12:52 PM, Scott Haneda talkli...@newgeo.com
Always echo out your SQL string, it will make it a lot more obvious.
You want to see the result. I php concatenated string can be
confusing at times.
Also, you are not escaping your data, so if you had a word of 'stops,
here' that would break it as well.
So in your case, you very well
, and only one
field can support that feature.
Please supply more data.
On Apr 28, 2009, at 2:18 PM, Antonio PHP wrote:
You have an error in your SQL syntax; check the manual that corresponds to
your MySQL server version for the right syntax to use near 'Created =
NOW(),
Updated = NOW
On Apr 29, 2009, at 11:29 AM, Antonio PHP wrote:
This is MySQL data structure. - I underlined where it causes the error
message. (datetime)
`id_Company` smallint(6) unsigned NOT NULL AUTO_INCREMENT,
`Name` varchar(50) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL
`Revenue` mediumint(6)
You have an error in your SQL syntax; check the manual that corresponds to
your MySQL server version for the right syntax to use near 'Created = NOW(),
Updated = NOW()' at line 8
'Created' and 'Updated' are set to datetime (InnoDB).
The same syntax works for some newly created tables
Can you please give the full table structure and query?
On Tue, Apr 28, 2009 at 23:18, Antonio PHP php.anto...@gmail.com wrote:
You have an error in your SQL syntax; check the manual that corresponds to
your MySQL server version for the right syntax to use near 'Created = NOW(),
Updated = NOW
We need to see your entire query and the table structure. timestamp
fields can have options set to auto update them, where order matters,
and only one field can support that feature.
Please supply more data.
On Apr 28, 2009, at 2:18 PM, Antonio PHP wrote:
You have an error in your SQL
- Original Message -
From: Scott Yamahata [EMAIL PROTECTED]
To: mysql@lists.mysql.com
Sent: Friday, December 29, 2006 1:29 AM
Subject: SQL syntax
Hi, I'm getting the following error message:
You have an error in your SQL syntax; check the manual that corresponds to
your MySQL
Hi Scott, all,
Scott Yamahata wrote:
Hi, I'm getting the following error message:
You have an error in your SQL syntax; check the manual that corresponds
to your MySQL server version for the right syntax to use near ' enabled
= '1'' at line 3INSERT INTO clf_cities SET cityname = 'Santa
Hi, I'm getting the following error message:
You have an error in your SQL syntax; check the manual that corresponds to
your MySQL server version for the right syntax to use near ' enabled = '1''
at line 3INSERT INTO clf_cities SET cityname = 'Santa Barbara', countryid =
, enabled = '1
Hi,
have you checked the 'enabled' field datatype or can you give the query.
Thanks
ViSolve DB Team.
- Original Message -
From: Scott Yamahata [EMAIL PROTECTED]
To: mysql@lists.mysql.com
Sent: Friday, December 29, 2006 11:59 AM
Subject: SQL syntax
Hi, I'm getting the following
the value of column
blank.
INSERT INTO clf_cities SET cityname = 'Santa Barbara', countryid =NULL ,
enabled = '1'
Thanks,
ViSolve DB Team
- Original Message -
From: Scott Yamahata [EMAIL PROTECTED]
To: mysql@lists.mysql.com
Sent: Friday, December 29, 2006 11:59 AM
Subject: SQL syntax
)|
as well as renaming it from |b| to |c|:
ALTER TABLE t2 MODIFY a TINYINT NOT NULL, CHANGE b c CHAR(20);
for changing the name of a column, right? So, why doesn't the below work?
mysql ALTER TABLE actors CHANGE director_id actor_id;
I get this,
ERROR 1064 (42000): You have an error in your SQL
At 0:09 +1000 8/6/06, Mark Sargent wrote:
ALTER TABLE t2 MODIFY a TINYINT NOT NULL, CHANGE b c CHAR(20);
for changing the name of a column, right? So, why doesn't the below work?
mysql ALTER TABLE actors CHANGE director_id actor_id;
I'm no great expert myself, but off the top of my head,
(42000): You have an error in your SQL syntax; check the
manual that corresponds to your MySQL server version for the right
syntax to use near '' at line 1
Sorry, little confused right about now, eh. Cheers.
Mark Sargent.
--
MySQL General Mailing List
For list archives: http://lists.mysql.com
: ERROR 1064 (42000): You have an error in your SQL syntax;
Hi All,
gee I really hate bugging you all for this. I looked at this page,
http://dev.mysql.com/doc/refman/5.0/en/alter-table.html
which has this,
To change column |a| from |INTEGER| to |TINYINT NOT NULL| (leaving the name
the same
At 15:19 +0100 7/6/06, Rob Desbois wrote:
With the CHANGE clause of ALTER TABLE statement, you must provide
the column definition, so something like this is what you need:
ALTER TABLE actors CHANGE director_id actor_id MEDIUMINT UNSIGNED NOT NULL;
or whatever your original definition is.
failed: You have an error in your SQL syntax. Check
the manual that corresponds to your MySQL server version for the right
syntax to use near 'WHERE dtSnapShot ='2005-06-26' AND fkJobPosting =
209689' at li at ./crawl-hot-jobs.pl line 686.
Use of uninitialized value in concatenation (.) or string
= 209689'
select='SELECT cJobTitle FROM jobtitlecount WHERE fkJobPosting = 209689
AND
dtSnapShot = '2005-06-26''Duplicate entry '209689-2005-06-26' for key 1
DBD::mysql::st execute failed: You have an error in your SQL syntax.
Check
the manual that corresponds to your MySQL server version
line 675.
How could this be?
Now here is another example where I detect a duplicate and delete the
statement before trying to insert:
DELETE jobtitlecount WHERE dtSnapShot ='2005-06-26' AND fkJobPosting =
211151
DBD::mysql::st execute failed: You have an error in your SQL syntax. Check
the manual
code (not an edited version).
Now here is another example where I detect a duplicate and delete the
statement before trying to insert:
DELETE jobtitlecount WHERE dtSnapShot ='2005-06-26' AND fkJobPosting =
211151
DBD::mysql::st execute failed: You have an error in your SQL syntax. Check
.
The following caused the same error of:
ERROR 1064: You have an error in your SQL syntax. Check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'select max(length(testName)) from test)' at line 1
select testName from test where length(testName) = (select
max
.
The following caused the same error of:
ERROR 1064: You have an error in your SQL syntax. Check the manual
that corresponds to your MySQL server version for the right syntax to
use near 'select max(length(testName)) from test)' at line 1
select testName from test where length(testName) = (select
max
Hello Users
does anyone know a tool or a way for validation sqlcode on the
command_line???
For example
./sqlsyntaxchecker select * f test
-- Error not valid sql syntax
thx christian
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:http
Dear list,
My ColdFusion server tells me I have an error in my query syntax, but I
can't work out what it is - because I'm working with code that someone
very kindly gave me and I only have a vague idea of what the first
line's doing! Can anyone see the problem here?
SELECT
Chris Kavanagh wrote:
My ColdFusion server tells me I have an error in my query syntax, but I
can't work out what it is - because I'm working with code that someone
very kindly gave me and I only have a vague idea of what the first
line's doing! Can anyone see the problem here?
SELECT
[snip]
My ColdFusion server tells me I have an error in my query syntax, but I
can't work out what it is - because I'm working with code that someone very
kindly gave me and I only have a vague idea of what the first line's doing!
Can anyone see the problem here?
SELECT DATEDIFF(leadtime_type,
Thanks very much for the replies, guys. My version is 4.1.7-max.
The error message I get is:
--
Error Executing Database Query.
Syntax error or access violation: You have an error in your SQL syntax;
check the manual that corresponds to your MySQL server version for the
right syntax to use near
I think datediff only takes two arguments and you have three listed.
---
Tom Crimmins
Interface Specialist
Pottawattamie County, Iowa
-Original Message-
From: Chris Kavanagh
Sent: Monday, January 31, 2005 5:33 PM
To: mysql@lists.mysql.com
Subject: Re: SQL syntax error: help a noob
On 31 Jan 2005, at 11:39 pm, Tom Crimmins wrote:
I think datediff only takes two arguments and you have three listed.
Nailed it! Thanks, Tom.
Best regards,
CK.
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
I have a problem.
1064 - You have an error in your SQL syntax near '(((specials INNER JOIN
(products_to_categories INNER JOIN categories ON products' at line 2
SELECT DISTINCT specials.specials_id, products_to_categories.products_id,
categories.parent_id, products_description.products_name
.
Are the different machines all running the exact same version of MySQL?
Rhino
- Original Message -
From: Daniel Sousa [EMAIL PROTECTED]
To: mysql@lists.mysql.com
Sent: Wednesday, January 26, 2005 6:45 AM
Subject: error in your SQL syntax
I have a problem.
1064 - You have an error
have an error in your SQL syntax near '(((specials INNER
JOIN (products_to_categories INNER JOIN categories ON products' at line
2
SELECT DISTINCT specials.specials_id, products_to_categories.
products_id, categories.parent_id, products_description.
products_name, products.products_price
: error in your SQL syntax
Here is your original query, reformatted merely so that we humans can read it
better:
SELECT DISTINCT specials.specials_id
, products_to_categories.products_id
, categories.parent_id
, products_description.products_name
: error in your SQL syntax
Thanks, works fines.
I use access because i don´t know a GUI tool that make SQL
querys more easy.
Thanks all again,
Daniel Sousa
- Original Message -
From: [EMAIL PROTECTED]
To: Daniel Sousa
Cc: mysql@lists.mysql.com
Sent
VendorJobs.Industry = '2','3','4','5'Query failed: You
have an error in your SQL syntax. Check the manual
that corresponds to your MySQL server version for the
right syntax to use near '.Industry = '2','3','4','5''
at line 2
The first is the printout of my statement followed by
the mysql_error .
Here
On Sat, Nov 13, 2004 at 12:30:43PM -0800, Stuart Felenstein wrote:
$sql = SELECT PostStart, JobTitle, Industry,
LocationState, VendorID
FROM VendorJobs;
echo $sql;
//if ($Ind)
$sql .= WHERE VendorJobs.Industry = $s_Ind;
As you can see above s_ind is an array , comma
delimited.
--- Jim Winstead [EMAIL PROTECTED] wrote:
You can't compare a column with a comma-delimited
list of numbers like
that...
What should the seperator be then ?
Thank you
Stuart
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:
On Sat, Nov 13, 2004 at 12:46:12PM -0800, Stuart Felenstein wrote:
--- Jim Winstead [EMAIL PROTECTED] wrote:
You can't compare a column with a comma-delimited
list of numbers like
that...
What should the seperator be then ?
My point was that you can't compare a column with an
--- Jim Winstead [EMAIL PROTECTED] wrote:
My point was that you can't compare a column with an
array
of numbers using the '=' operator. You have to use
the IN
operator, as in the line of code I posted:
Thank you Jim , it's working now!
Stuart
--
MySQL General Mailing List
For list
-Original Message-
From: David Blomstrom [mailto:[EMAIL PROTECTED]
Sent: Wednesday, November 10, 2004 4:08 PM
To: [EMAIL PROTECTED]
Subject: SQL Syntax Problem
$sql = 'SELECT
F.IDArea,
C.IDArea, C.Name, C.Pop, C.Nationality,
C.NationalityPlural, C.NationalityAdjective FROM
Think I found it. I made the changes with explanations of what I did.
If you have any further questions feel free to ask. Oh and this should
be on the list for others to see and maybe learn from
Respectfully,
Ligaya Turmelle
head[DATABASE CONNECTION]/head
body
div class=formdiv
--- Ligaya Turmelle [EMAIL PROTECTED] wrote:
Think I found it. I made the changes with
explanations of what I did.
If you have any further questions feel free to ask.
Oh and this should
be on the list for others to see and maybe learn
from
Wow, thanks so much for going to all that
This may be a purely PHP problem, but the error
message says SQL syntax. Check the manual that
corresponds to your MySQL server version...
More important, I haven't been able to find a solution
on any PHP forums. :)
This is the complete error message:
Failed to run SELECT F.IDArea, C.IDArea
It's not translating your vars to their respective values.
I didn't look to see why...
But MySQL doesn't know what
$_POST['order']
is.
David Blomstrom wrote:
This may be a purely PHP problem, but the error
message says SQL syntax. Check the manual that
corresponds to your MySQL server version
to their respective values.
I didn't look to see why...
But MySQL doesn't know what
$_POST['order']
is.
David Blomstrom wrote:
This may be a purely PHP problem, but the error
message says SQL syntax. Check the manual that
corresponds to your MySQL server version...
Failed to run SELECT F.IDArea
administration.
--
I can't decide if this is my code, or the SQL syntax. Would it be possible,
based on this statement, to have pulled back duplicates from the same
record?
- Eve
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:http
Over 10 years of HTML experience. 2 years networking
administration.
--
I can't decide if this is my code, or the SQL syntax. Would it be possible,
based on this statement, to have pulled back duplicates from the same
record?
- Eve
--
MySQL General Mailing List
For list archives: http
You have a cartesian join because you do not have join criteria between the
resume and candidate tables.
-Original Message-
From: Eve Atley
To: [EMAIL PROTECTED]
Sent: 8/17/04 12:22 PM
Subject: Assistance with SQL syntax: pulling duplicates back
I think this is an easy question...I've
network php Over 10 years of HTML experience. 2 years
networking
administration.
--
I can't decide if this is my code, or the SQL syntax. Would it be
possible,
based on this statement, to have pulled back duplicates from the same
record?
- Eve
--
MySQL
if this is my code, or the SQL syntax. Would it be
possible,
based on this statement, to have pulled back duplicates from the same
record?
- Eve
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]
Eve,
Best to keep threads on the list. Others may have better ideas, and future
readers may benefit.
The comparison
candidate.Location IN ('CA', 'California')
will match 'CA' and 'California', but will not match 'Cupertino, CA' because
it isn't either of those strings. To match that row as
-Heinz Schulz; [EMAIL PROTECTED]
Subject: Re: SQL Syntax Question
- Original Message -
From: Karl-Heinz Schulz [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, August 03, 2004 9:18 PM
Subject: SQL Syntax Question
I tried to get an answer on the PHP mailing list and I was told
Karl-Heinz Schulz wrote:
Thank you for trying to help me.
The output is wrong
I get either
Event 1
Event 2
Details 1 for event 1
Details 2 for event 1
Details 3 for event 1
that query is wrong :
$eventdetail_query = mysql_query(select informations, titles, file_name
from eventdetail, event where
]
Sent: Wednesday, August 04, 2004 5:52 AM
To: Karl-Heinz Schulz
Cc: [EMAIL PROTECTED]
Subject: Re: SQL Syntax Question
Karl-Heinz Schulz wrote:
Thank you for trying to help me.
The output is wrong
I get either
Event 1
Event 2
Details 1 for event 1
Details 2 for event 1
Details 3
- Original Message -
From: Karl-Heinz Schulz [EMAIL PROTECTED]
To: 'Philippe Poelvoorde' [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Wednesday, August 04, 2004 6:41 AM
Subject: RE: SQL Syntax Question
Philippe,
I changed my to the following but the result is now (I deleted
I tried to get an answer on the PHP mailing list and I was told that this
list would be quicker to get me a solution.
I have two tables Event and Eventdetails (structures dump can be found
at the end of the message).
I want to display all events and the related information from the
eventdetails
- Original Message -
From: Karl-Heinz Schulz [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Tuesday, August 03, 2004 9:18 PM
Subject: SQL Syntax Question
I tried to get an answer on the PHP mailing list and I was told that this
list would be quicker to get me a solution.
I have two
When I use this SQL statement, ...
--snip--
UPDATE BUSINESS_CATEGORY SET
(BUSINESS_CATEGORY.BUS_CAT,BUSINESS_CATEGORY.BUS_DESC) =
('JUNKKK','JUNK123KK') WHERE BUSINESS_CATEGORY.BUS_CAT_ID = '733788'
--snip--
I get the SQL syntax error saying,
--snip--
You have an error in your SQL syntax
From: Scott Fletcher [mailto:[EMAIL PROTECTED]
When I use this SQL statement, ...
--snip--
UPDATE BUSINESS_CATEGORY SET
(BUSINESS_CATEGORY.BUS_CAT,BUSINESS_CATEGORY.BUS_DESC) =
('JUNKKK','JUNK123KK') WHERE BUSINESS_CATEGORY.BUS_CAT_ID = '733788'
--snip--
I get the SQL syntax error
:
Fax to:
06/16/2004 04:08 Subject: MySQL -- SQL syntax
error
I'm using amavisd-new -20030616p9, RH 3.0 ES and mysql 3.23.58-1 trying
to do sql lookups for user prefs. I've done this before and have
compared my sql statements and can't figure out the problem.
When i start amavisd-new with the debug switch, here's what i get:
# /usr/local/sbin/amavisd
Struggling to get an INSERT to work, can anyone help?
Here's my scenario:
Students[table]
Student_ID [primary key, auto-increment]
Student_name
Student_sex
Extra_Credit[table]
EC_ID [primary key, auto-increment]
Student_ID
Points
First: INSERT INTO
Hi,
Then: INSERT INTO Extra_Credit (Student_ID, Points) SELECT MAX(Student_ID)
from Students,
(1) ...VALUE ('25');
or
(2) ... '25' as Points;
I think this is your query:
INSERT INTO Extra_Credit(Student_ID, Points) SELECT MAX(Student_ID), '25' from Students
Take care,
Aleksandar
As I understand it, you don't really want the MAX(Student_ID), you want
the actual Student_ID of the last insert. It is important to note that
they are not necessarily the same. If you insert Student 24, then I
insert Student 25, then you check MAX(Student_ID), you will get 25, not
24.
Hi All
I have been pushing my syslogs to the following mysql table
However whenever it sees lines with a ' (apostrophe) it complains about SQL syntax
Here are two lines with ' from my syslog:
Jan 1 03:58:15 dal-svcs-02.inet.qwest.net 203: *Jan 1 08:58:13.926
UTC: %PFINIT-SP-5-CONFIG_SYNC
Hi Asif,
Asif Iqbal wrote:
I have been pushing my syslogs to the following mysql table
However whenever it sees lines with a ' (apostrophe) it complains about SQL syntax
You need to escape those reserved characters, i.e. have ' replaced by \'
because otherwise mysql will treat the apostrophe
Hello, my name's Marlon. I have a question about sql and I need some help!
How can I do something like it using mysql?
update registre set (name='NewName' where lastname='OldLastName'),
(name='OldName' where lastname='NewLastName');
Tank you
Marlon
Hello, my name's Marlon. I have a question about sql and I need some help!
How can I do something like it using mysql?
update registre set (name='NewName' where lastname='OldLastName'),
(name='OldName' where lastname='NewLastName');
I _believe_ you can do it this way. I'm sure someone
ON onderneming.rubriek_ID_3 = r3.rubriek_ID
WHERE 1
ORDER BY officiele_naam
LIMIT 100
#1064 - You have an error in your SQL syntax near 'ON onderneming.bedrijfsnummer =
vestiging.bedrijfsnummer
LEFT JOIN rubrieken AS' at line 3
What exactly is the cause of this error here? Could it be that mysql3 does
not support
Hi All,
I'm programming a method to delete a parent record and all its children
in a child table in one go. This is what I have:
UPDATE item i, category_item ci
SET i.date_deleted = ?, ci.date_deleted = ?
WHERE ci.item_id = i.item_id
AND ci.category_id = ?
and it works. But then I realised that
These are tables that I did not design (and would not have in this fashion), but I
have to make do with them
Table 1 structure:
id_num number,
descr1 varchar(30),
descr2 varchar(30),
descr3 varchr(30)
Table 2 structure
id_name varchar(15),
ext_descr varchar(30)
Table 2 is a child of table 1
Contents are Direct Alliance Corporation CONFIDENTIAL
-
How do you type check in mysql. I have a column of type varchar(20) with
both floats and strings. Is there a way to check the type?
Example:
Select
If(is_float(col1), 'is a float', 'not a float') as
At 11:40 -0700 7/22/03, Cory Lamle wrote:
Contents are Direct Alliance Corporation CONFIDENTIAL
-
How do you type check in mysql. I have a column of type varchar(20) with
both floats and strings. Is there a way to check the type?
In this case, the type of the column as far as MySQL is concerned
Message-
From: Cory Lamle [mailto:[EMAIL PROTECTED]
Sent: Tuesday, July 22, 2003 2:40 PM
To: MySQL LIST
Subject: SQL Syntax
Contents are Direct Alliance Corporation CONFIDENTIAL
-
How do you type check in mysql. I have a column of type varchar(20) with
both floats and strings
On Sat 2003-02-01 at 10:35:46 -, [EMAIL PROTECTED] wrote:
Hi Benjamin,
Wow, that sure sorted that problem out... I had to rejig it slightly to
get it to work,
Oops... too much copypaste by me :-)
but this is the final working version:
Glad it worked out.
Bye,
Benjamin.
is the error message MySQL reports:
ERROR 1064: You have an error in your SQL syntax near '(product_options AS
product_options_1 RIGHT JOIN (basket_header INNER JOIN baske' at line 9
Seems MySQL doesn't like the RIGHT JOIN syntax. Any ideas to the correct
syntax?
Just give you a better idea
)=4));
:
: Here is the error message MySQL reports:
:
: ERROR 1064: You have an error in your SQL syntax near
: '(product_options AS
: product_options_1 RIGHT JOIN (basket_header INNER JOIN
: baske' at line 9
:
: Seems MySQL doesn't like the RIGHT JOIN syntax
,
basket.price, basket.quantity, total,
basket_header.basket_id, products.options
HAVING basket_header.basket_id=4;
Here is the error message MySQL reports:
ERROR 1064: You have an error in your SQL syntax near '(product_options AS
product_options_1 RIGHT JOIN (basket_header INNER
On Fri, Jan 31, 2003 at 02:07:11PM -, Kevin Smith wrote:
Hi All,
Can anyone help me get this query working in MySQL, this was created using
Access, but it doesn't port well for MySQL syntax:
SELECT b.id, p.part_code, p.product_type, p.description, po1.options,
b.price, b.quantity,
work out why I couldn't do that so I can better
understand it.
Kevin
- Original Message -
From: Benjamin Pflugmann [EMAIL PROTECTED]
To: Kevin Smith [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Saturday, February 01, 2003 4:32 AM
Subject: Re: SQL Syntax
Hi.
On Fri 2003-01-31 at 15:46
, b.price*b.quantity, bh.basket_id, p.options
HAVING (((bh.basket_id)=4));
Here is the error message MySQL reports:
You have an error in your SQL syntax near '(product_options AS po1 RIGHT
JOIN (basket_header AS bh INNER JOIN basket AS b O' at line 1
Any ideas to the correct syntax?
Thanks,
Kevin
MySQL reports:
ERROR 1064: You have an error in your SQL syntax near '(product_options AS
product_options_1 RIGHT JOIN (basket_header INNER JOIN baske' at line 9
Seems MySQL doesn't like the RIGHT JOIN syntax. Any ideas to the correct
syntax?
Thanks,
Kevin
: Friday, January 31, 2003 3:46 PM
Subject: SQL Syntax
Hi All,
Can anyone help me get this query working in MySQL, this was created using
Access, but it doesn't port well for MySQL syntax:
SELECT basket.id,
products.part_code,
products.product_type,
products.description
I don't know if i understood you very well, but here's a try..
mysql select * from Classes;
++-+
| ID | Name|
++-+
| 1 | XO-312 |
| 2 | PA-211a |
| 3 | XUL-001 |
++-+
3 rows in set (0.00 sec)
mysql select * from Workshops order by ClassID,Date;
.com
MySQL support: none
Synopsis: Replication halts with sql syntax error
Severity: serious
Priority: medium
Category: mysql
Class: sw-bug
Release: mysql-3.23.54 (Official MySQL RPM)
Server: /usr/bin/mysqladmin Ver 8.23 Distrib 3.23.54, for pc-linux on i686
First of, thanks to all who replied to my questions earlier!
Now I have another problem. I have a table of Classes and Workshops. Each
Class has a number of workshops. Each workshop has a date.
I have a query that gives me the date range of a class - the min and max
dates of its workshops.
You almost got it. Your syntax will be something like this:
UPDATE Table SET address=REPLACE(address,'#','Number') WHERE column
like%#%
When I am trying to figure out the syntax for something, I always add a
LIMIT 1 at the end so that only one record gets changed.
On Saturday, October 5,
Scott,
Saturday, October 05, 2002, 7:45:16 AM, you wrote:
SJ I have a db with slightly over 614,000 records of names and addresses. In
SJ the address column, there are quite a few records like
SJ 123 any rd # 2
SJ 319 w. 1st st # B
SJ 4321 test blvd # 42
SJ etc
SJ I want to replace all the
I have a db with slightly over 614,000 records of names and addresses. In
the address column, there are quite a few records like
123 any rd # 2
319 w. 1st st # B
4321 test blvd # 42
etc
I want to replace all the number signs with the actual word 'number'.
Is there a SQL command I can use for
the CLASS.UID field to the `GROUP`.ADMIN field (join them on
CLASS.CLI=`GROUP`.GRID) if CLASS.UID=2 and `GROUP`.GRID1.
What would that SQL syntax look like?
Thanks
SK
-
Before posting, please check:
http://www.mysql.com/manual.php
Pada Sun, 25 Aug 2002 22:04:13 +0200
David Durham [EMAIL PROTECTED] menulis :
update CompanyContacts
set ByEmailAddress = '[EMAIL PROTECTED]'
where Description like '%marve%'
If I say:
select * from CompanyContacts
where Description like '%marve%'
What was the error message displayed on
This may be a truly dumb question, but could someone please tell me why
this sql query/ statement does not work:
update CompanyContacts
set ByEmailAddress = '[EMAIL PROTECTED]'
where Description like '%marve%'
If I say:
select * from CompanyContacts
where Description like '%marve%'
I get the
1 - 100 of 147 matches
Mail list logo
