Re: NET START MYSQL QUESTION?

2013-05-12 Thread shawn green

Hello Reindl,

On 5/11/2013 11:52 AM, Reindl Harald wrote:

...  virtually
nonofy is using mysql on windows seriously as i have
not touched windows since 2006 at all



Your experience is not indicative of the population as a whole. Many 
important and mission-critical installations exist on Windows.


You may not, or ever, choose to use Windows as a base platform but many 
people do and do superbly with their choice of OS.


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RE: [Suspected Spam][Characteristics] Re: NET START MYSQL QUESTION?

2013-05-12 Thread Robinson, Eric
 why not answer the question another user made hours ago?
 under which account do you try to start mysqld?
 

Agreed. Chances are good that if he goes into the Windows Services control 
panel and gets the properties of the mysql service, he will find that it is 
configured to start under a Windows account other than the System account, and 
that the Windows account in question either does not have the required 
privileges or it is locked. I'd probably just change it to start under the 
System account.

--Erio


 

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Re: NET START MYSQL QUESTION?

2013-05-11 Thread Reindl Harald

Am 11.05.2013 16:50, schrieb SIVASUTHAN NADARAJAH:
 I want to start the mysql from command prompt using NET START MYSQLBUT 
 the server not started. It display an error message. 
 C:\Users\PC NET START MySQLSystem error 5 has occurred.
 Access is denied.
 could you please help me, how to start the Mysql service FROM command prompt? 
   

what about look in the mysqld-log and verify which account
is used by the windows service? there is no difference between
the GUI and net start, a service works or not

* log-files
* service details (useraccount, credentials..)
* permissions to logfiles / datadir.

btw: do not use uppercase letters in your whole subject!




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Re: NET START MYSQL QUESTION?

2013-05-11 Thread Reindl Harald
DO NOT REPLY OFF-LIST

there is no step by step guidance and virtually
nonofy is using mysql on windows seriously as i have
not touched windows since 2006 at all

understand how services on your used OS are working
or hire someone who does

Am 11.05.2013 17:44, schrieb SIVASUTHAN NADARAJAH:
 Sorry I could not understand your answer. please give me the step by step 
 guidance.
 thank you so much...
 
 Date: Sat, 11 May 2013 16:58:16 +0200
 From: h.rei...@thelounge.net
 To: mysql@lists.mysql.com
 Subject: Re: NET START MYSQL QUESTION?


 Am 11.05.2013 16:50, schrieb SIVASUTHAN NADARAJAH:
  I want to start the mysql from command prompt using NET START MYSQLBUT 
  the server not started. It display an
 error message.
  C:\Users\PC NET START MySQLSystem error 5 has occurred.
  Access is denied.
  could you please help me, how to start the Mysql service FROM command 
  prompt?

 what about look in the mysqld-log and verify which account
 is used by the windows service? there is no difference between
 the GUI and net start, a service works or not

 * log-files
 * service details (useraccount, credentials..)
 * permissions to logfiles / datadir.

 btw: do not use uppercase letters in your whole subject!



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Re: NET START MYSQL QUESTION?

2013-05-11 Thread Mimiko

On 11.05.2013 17:50, SIVASUTHAN NADARAJAH wrote:

C:\Users\PC NET START MySQL System error 5 has occurred.
Access is denied.


Run command window from elevated permission.

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Re: NET START MYSQL QUESTION?

2013-05-11 Thread Reindl Harald

Am 11.05.2013 20:04, schrieb Mimiko:
 On 11.05.2013 17:50, SIVASUTHAN NADARAJAH wrote:
 C:\Users\PC NET START MySQL System error 5 has occurred.
 Access is denied.
 
 Run command window from elevated permission

wow - you mean he *really* tried to start a service as
restricted user and instead read the basic manuals
posted to the application list?

hopefully not...




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Re: NET START MYSQL QUESTION?

2013-05-11 Thread hsv
 2013/05/11 20:50 +0600, SIVASUTHAN NADARAJAH 
I want to start the mysql from command prompt using NET START MYSQLBUT 
the server not started. It display an error message. 
C:\Users\PC NET START MySQLSystem error 5 has occurred.
Access is denied.
could you please help me, how to start the Mysql service FROM command prompt?   
SIVASUTHAN- Consultant Trainer

Well, ordinarily the MySQL service is started by Windows along with all the 
rest: After installing MySQL under Windows one runs MySQL Instance 
Configuration Wizard--the only MySQL program on my system that runs from 
Start. (If you cannot do this on the machine where mysqld.exe is to run I 
do not know what to say.)

If the service, with program mysqld.exe, quits, to start it one enters
start mysqld -b... from the command line, with the directory where my.ini 
is kept entered for  Of course, if mysqld.exe started and quit, as 
Reindl Harald suggested study the logs and find out why. It is not started 
through the client, mysql.exe.


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Re: NET START MYSQL QUESTION?

2013-05-11 Thread Reindl Harald

Am 11.05.2013 21:49, schrieb h...@tbbs.net:
 2013/05/11 20:50 +0600, SIVASUTHAN NADARAJAH 
 I want to start the mysql from command prompt using NET START MYSQLBUT the 
 server not started. It display an error message. 
 C:\Users\PC NET START MySQLSystem error 5 has occurred.
 Access is denied.
 could you please help me, how to start the Mysql service FROM command prompt? 
   

why not answer the question another user made hours ago?
under which account do you try to start mysqld?

hence you need FULL ADMIN PRIVILEGES on every OS to start services

or use the system settings which at least come up with a UAC request
alternative: use a proper operating system with a package-manager

google: windows system error 5
https://www.google.com/search?q=windows+system+error+5

thid *is not* a MySQL problem
please ask windows questions at windows forums

 It is not started through the client, mysql.exe

why should the client start a server?



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Re: NET START MYSQL QUESTION?

2013-05-11 Thread hsv
 2013/05/11 22:58 +0200, Reindl Harald 
why not answer the question another user made hours ago?
under which account do you try to start mysqld? 

Well, I learnt something here.

When I had the problem of (under Vista) starting mysqld, from command prompt 
I always did this, start mysqld -b... (here start is like Unix s trailing 
), and never had a problem. It showed up running on the service list. Maybe 
something like Unix s set-user-id is in effect in mysqld.exe.

Now for the first time I learn of command NET, and its options. I do not 
remember seeing net start MySQL in MySQL s help when I installed it, only 
that which I above described.

This is not so much an OS problem, but a problem at the point where the OS s 
peculiarities and a big package s nature intersect.


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Fw: General MySQL Question

2009-07-07 Thread christudas dai




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From: MySQL Web Team webmas...@mysql.com
To: christudas_...@yahoo.com
Sent: Wednesday, July 8, 2009 3:46:09
Subject: Re:General MySQL Question

Thank you for contacting MySQL,

You are likely to get a more detailed response to your question if you
ask on the forums site at http://forums.mysql.com/ or on an appropriate
mailing list at http://lists.mysql.com/

Hope this helps,

MySQL Web Team

===
Your query was:
Hi,

I have an existing database for one of our elearning portals. This
support request is to give us information on how an already existing
database can be encrypted? Is there a query that can encrypt the
database? we are planning to use the ENCODE() and DECODE()for encoding
the data into the database and decrypting the data while retrieving
information from database.

Pls do let us know.

Thanks  Regards,
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RE: PHP-MYSQL Question

2009-04-07 Thread abdulazeez alugo


Yeah I used the mysql_error and it returned Can't create table 
'.\website\table2.frm' (errno: 150). So what does that say?

 

 


 Date: Tue, 7 Apr 2009 17:38:59 +0400
 From: evge...@kosov.su
 To: defati...@hotmail.com
 CC: mysql@lists.mysql.com
 Subject: Re: PHP-MYSQL Question
 
 Perhaps you don't have permissions to create tables?
 
 It would have been much clearer if your script was like this:
 
 $result=mysql_query($your_create_table_statement);
 if($result){ printSuccessful;}
 else {print Unsuccessful: .mysql_error()}
 
 
 abdulazeez alugo wrote:
  Hi guys,
  
  Please can anyone tell me what I'm doing wrong with the code below? It keep 
  returning unsuccessful.
  
  $result=mysql_query(CREATE TABLE table2(table2_id INT NOT NULL PRIMARY KEY 
  AUTO_INCREMENT,
  table1_id INT NOT NULL,
  name VARCHAR(100) NOT NULL,
  school VARCHAR(100) NOT NULL,
  comment TEXT NOT NULL,
  entrydate TIMESTAMP NOT NULL,
  FOREIGN KEY(table1_id) REFERENCES table1(table1_id))
  ENGINE = INNODB );
  
  if($result){ printSuccessful;}
  else {print Unsuccessful;}
  
  Thanks in advance. Cheers.
  
  Alugo Abdulazeez.
  
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Re: PHP-MYSQL Question

2009-04-07 Thread Eugene Kosov

# perror 150
MySQL error code 150: Foreign key constraint is incorrectly formed

What does table1 look like?

abdulazeez alugo wrote:


Yeah I used the mysql_error and it returned Can't create table 
'.\website\table2.frm' (errno: 150). So what does that say?

 

 




Date: Tue, 7 Apr 2009 17:38:59 +0400
From: evge...@kosov.su
To: defati...@hotmail.com
CC: mysql@lists.mysql.com
Subject: Re: PHP-MYSQL Question

Perhaps you don't have permissions to create tables?

It would have been much clearer if your script was like this:

$result=mysql_query($your_create_table_statement);
if($result){ printSuccessful;}
else {print Unsuccessful: .mysql_error()}


abdulazeez alugo wrote:

Hi guys,

Please can anyone tell me what I'm doing wrong with the code below? It keep 
returning unsuccessful.


$result=mysql_query(CREATE TABLE table2(table2_id INT NOT NULL PRIMARY KEY 
AUTO_INCREMENT,

table1_id INT NOT NULL,
name VARCHAR(100) NOT NULL,
school VARCHAR(100) NOT NULL,
comment TEXT NOT NULL,
entrydate TIMESTAMP NOT NULL,
FOREIGN KEY(table1_id) REFERENCES table1(table1_id))
ENGINE = INNODB );

if($result){ printSuccessful;}
else {print Unsuccessful;}

Thanks in advance. Cheers.

Alugo Abdulazeez.

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RE: PHP-MYSQL Question

2009-04-07 Thread abdulazeez alugo

Table1 is as below:

 

CREATE TABLE table1(table1_id INT UNSIGNED NOT NULL AUTO_INCREMENT,
PRIMARY KEY(table1_id),
entrytitle VARCHAR(100) NOT NULL,
entrytext TEXT NOT NULL,
entrydate TIMESTAMP NOT NULL) );

 

I did not put the engine. Could that be the problem?
 
 Date: Tue, 7 Apr 2009 17:48:16 +0400
 From: evge...@kosov.su
 To: defati...@hotmail.com
 CC: mysql@lists.mysql.com
 Subject: Re: PHP-MYSQL Question
 
 # perror 150
 MySQL error code 150: Foreign key constraint is incorrectly formed
 
 What does table1 look like?
 
 abdulazeez alugo wrote:
  
  Yeah I used the mysql_error and it returned Can't create table 
  '.\website\table2.frm' (errno: 150). So what does that say?
  
  
  
  
  
  
  Date: Tue, 7 Apr 2009 17:38:59 +0400
  From: evge...@kosov.su
  To: defati...@hotmail.com
  CC: mysql@lists.mysql.com
  Subject: Re: PHP-MYSQL Question
 
  Perhaps you don't have permissions to create tables?
 
  It would have been much clearer if your script was like this:
 
  $result=mysql_query($your_create_table_statement);
  if($result){ printSuccessful;}
  else {print Unsuccessful: .mysql_error()}
 
 
  abdulazeez alugo wrote:
  Hi guys,
 
  Please can anyone tell me what I'm doing wrong with the code below? It 
  keep 
  returning unsuccessful.
 
  $result=mysql_query(CREATE TABLE table2(table2_id INT NOT NULL PRIMARY 
  KEY 
  AUTO_INCREMENT,
  table1_id INT NOT NULL,
  name VARCHAR(100) NOT NULL,
  school VARCHAR(100) NOT NULL,
  comment TEXT NOT NULL,
  entrydate TIMESTAMP NOT NULL,
  FOREIGN KEY(table1_id) REFERENCES table1(table1_id))
  ENGINE = INNODB );
 
  if($result){ printSuccessful;}
  else {print Unsuccessful;}
 
  Thanks in advance. Cheers.
 
  Alugo Abdulazeez.
 
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Re: PHP-MYSQL Question

2009-04-07 Thread Eugene Kosov

Perhaps you don't have permissions to create tables?

It would have been much clearer if your script was like this:

$result=mysql_query($your_create_table_statement);
if($result){ printSuccessful;}
else {print Unsuccessful: .mysql_error()}


abdulazeez alugo wrote:

Hi guys,
 
Please can anyone tell me what I'm doing wrong with the code below? It keep 
returning unsuccessful.
 
$result=mysql_query(CREATE TABLE table2(table2_id INT NOT NULL PRIMARY KEY 
AUTO_INCREMENT,

table1_id INT NOT NULL,
name VARCHAR(100) NOT NULL,
school VARCHAR(100) NOT NULL,
comment TEXT NOT NULL,
entrydate TIMESTAMP NOT NULL,
FOREIGN KEY(table1_id) REFERENCES table1(table1_id))
ENGINE = INNODB );
 
if($result){ printSuccessful;}

else {print Unsuccessful;}
  
Thanks in advance. Cheers.
 
Alugo Abdulazeez.


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Re: PHP-MYSQL Question

2009-04-07 Thread Eugene Kosov
I suppose the problem is that table1.table1_id and table2.table1_id are 
of different types. The first one is INT UNSIGNED and the second is just 
INT.



abdulazeez alugo wrote:

Table1 is as below:
 
CREATE TABLE table1(table1_id INT UNSIGNED NOT NULL AUTO_INCREMENT,

PRIMARY KEY(table1_id),
entrytitle VARCHAR(100) NOT NULL,
entrytext TEXT NOT NULL,
entrydate TIMESTAMP NOT NULL) );
 
I did not put the engine. Could that be the problem?
 
  Date: Tue, 7 Apr 2009 17:48:16 +0400

  From: evge...@kosov.su
  To: defati...@hotmail.com
  CC: mysql@lists.mysql.com
  Subject: Re: PHP-MYSQL Question
 
  # perror 150
  MySQL error code 150: Foreign key constraint is incorrectly formed
 
  What does table1 look like?
 
  abdulazeez alugo wrote:
  
   Yeah I used the mysql_error and it returned Can't create table 
'.\website\table2.frm' (errno: 150). So what does that say?

  
  
  
  
  
  
   Date: Tue, 7 Apr 2009 17:38:59 +0400
   From: evge...@kosov.su
   To: defati...@hotmail.com
   CC: mysql@lists.mysql.com
   Subject: Re: PHP-MYSQL Question
  
   Perhaps you don't have permissions to create tables?
  
   It would have been much clearer if your script was like this:
  
   $result=mysql_query($your_create_table_statement);
   if($result){ printSuccessful;}
   else {print Unsuccessful: .mysql_error()}
  
  
   abdulazeez alugo wrote:
   Hi guys,
  
   Please can anyone tell me what I'm doing wrong with the code 
below? It keep

   returning unsuccessful.
  
   $result=mysql_query(CREATE TABLE table2(table2_id INT NOT NULL 
PRIMARY KEY

   AUTO_INCREMENT,
   table1_id INT NOT NULL,
   name VARCHAR(100) NOT NULL,
   school VARCHAR(100) NOT NULL,
   comment TEXT NOT NULL,
   entrydate TIMESTAMP NOT NULL,
   FOREIGN KEY(table1_id) REFERENCES table1(table1_id))
   ENGINE = INNODB );
  
   if($result){ printSuccessful;}
   else {print Unsuccessful;}
  
   Thanks in advance. Cheers.
  
   Alugo Abdulazeez.
  
   _
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PHP-MYSQL Question

2009-04-07 Thread abdulazeez alugo

Hi guys,
 
Please can anyone tell me what I'm doing wrong with the code below? It keep 
returning unsuccessful.
 
$result=mysql_query(CREATE TABLE table2(table2_id INT NOT NULL PRIMARY KEY 
AUTO_INCREMENT,
table1_id INT NOT NULL,
name VARCHAR(100) NOT NULL,
school VARCHAR(100) NOT NULL,
comment TEXT NOT NULL,
entrydate TIMESTAMP NOT NULL,
FOREIGN KEY(table1_id) REFERENCES table1(table1_id))
ENGINE = INNODB );
 
if($result){ printSuccessful;}
else {print Unsuccessful;}
  
Thanks in advance. Cheers.
 
Alugo Abdulazeez.

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RE: PHP-MYSQL Question

2009-04-07 Thread abdulazeez alugo

I've tried it  and i still got the same error. I even dropped table1 and 
recreated it to include the ENGINE=InnoDB and it was successful but table2 
remains unsuccessful.
 
 Date: Tue, 7 Apr 2009 17:56:49 +0400
 From: evge...@kosov.su
 To: defati...@hotmail.com
 CC: mysql@lists.mysql.com
 Subject: Re: PHP-MYSQL Question
 
 I suppose the problem is that table1.table1_id and table2.table1_id are 
 of different types. The first one is INT UNSIGNED and the second is just 
 INT.
 
 
 abdulazeez alugo wrote:
  Table1 is as below:
  
  CREATE TABLE table1(table1_id INT UNSIGNED NOT NULL AUTO_INCREMENT,
  PRIMARY KEY(table1_id),
  entrytitle VARCHAR(100) NOT NULL,
  entrytext TEXT NOT NULL,
  entrydate TIMESTAMP NOT NULL) );
  
  I did not put the engine. Could that be the problem?
  
   Date: Tue, 7 Apr 2009 17:48:16 +0400
   From: evge...@kosov.su
   To: defati...@hotmail.com
   CC: mysql@lists.mysql.com
   Subject: Re: PHP-MYSQL Question
  
   # perror 150
   MySQL error code 150: Foreign key constraint is incorrectly formed
  
   What does table1 look like?
  
   abdulazeez alugo wrote:
   
Yeah I used the mysql_error and it returned Can't create table 
  '.\website\table2.frm' (errno: 150). So what does that say?
   
   
   
   
   
   
Date: Tue, 7 Apr 2009 17:38:59 +0400
From: evge...@kosov.su
To: defati...@hotmail.com
CC: mysql@lists.mysql.com
Subject: Re: PHP-MYSQL Question
   
Perhaps you don't have permissions to create tables?
   
It would have been much clearer if your script was like this:
   
$result=mysql_query($your_create_table_statement);
if($result){ printSuccessful;}
else {print Unsuccessful: .mysql_error()}
   
   
abdulazeez alugo wrote:
Hi guys,
   
Please can anyone tell me what I'm doing wrong with the code 
  below? It keep
returning unsuccessful.
   
$result=mysql_query(CREATE TABLE table2(table2_id INT NOT NULL 
  PRIMARY KEY
AUTO_INCREMENT,
table1_id INT NOT NULL,
name VARCHAR(100) NOT NULL,
school VARCHAR(100) NOT NULL,
comment TEXT NOT NULL,
entrydate TIMESTAMP NOT NULL,
FOREIGN KEY(table1_id) REFERENCES table1(table1_id))
ENGINE = INNODB );
   
if($result){ printSuccessful;}
else {print Unsuccessful;}
   
Thanks in advance. Cheers.
   
Alugo Abdulazeez.
   
_
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Re: PHP-MYSQL Question

2009-04-07 Thread Spiros Papadopoulos
it is not the ENGINE as Eugene mentioned above, is that you need to use
UNSIGNED when creating the second table

CREATE TABLE table2 ( table2_id INT NOT NULL PRIMARY KEY AUTO_INCREMENT,
table1_id INT UNSIGNED NOT NULL,
name VARCHAR(100) NOT NULL,
school VARCHAR(100) NOT NULL,
comment TEXT NOT NULL,
entrydate TIMESTAMP NOT NULL,
FOREIGN KEY(table1_id) REFERENCES table1(table1_id))
ENGINE = INNODB

2009/4/7 abdulazeez alugo defati...@hotmail.com


 I've tried it  and i still got the same error. I even dropped table1 and
 recreated it to include the ENGINE=InnoDB and it was successful but table2
 remains unsuccessful.

  Date: Tue, 7 Apr 2009 17:56:49 +0400
  From: evge...@kosov.su
  To: defati...@hotmail.com
  CC: mysql@lists.mysql.com
  Subject: Re: PHP-MYSQL Question
 
  I suppose the problem is that table1.table1_id and table2.table1_id are
  of different types. The first one is INT UNSIGNED and the second is just
  INT.
 
 
  abdulazeez alugo wrote:
   Table1 is as below:
  
   CREATE TABLE table1(table1_id INT UNSIGNED NOT NULL AUTO_INCREMENT,
   PRIMARY KEY(table1_id),
   entrytitle VARCHAR(100) NOT NULL,
   entrytext TEXT NOT NULL,
   entrydate TIMESTAMP NOT NULL) );
  
   I did not put the engine. Could that be the problem?
  
Date: Tue, 7 Apr 2009 17:48:16 +0400
From: evge...@kosov.su
To: defati...@hotmail.com
CC: mysql@lists.mysql.com
Subject: Re: PHP-MYSQL Question
   
# perror 150
MySQL error code 150: Foreign key constraint is incorrectly formed
   
What does table1 look like?
   
abdulazeez alugo wrote:

 Yeah I used the mysql_error and it returned Can't create table
   '.\website\table2.frm' (errno: 150). So what does that say?






 Date: Tue, 7 Apr 2009 17:38:59 +0400
 From: evge...@kosov.su
 To: defati...@hotmail.com
 CC: mysql@lists.mysql.com
 Subject: Re: PHP-MYSQL Question

 Perhaps you don't have permissions to create tables?

 It would have been much clearer if your script was like this:

 $result=mysql_query($your_create_table_statement);
 if($result){ printSuccessful;}
 else {print Unsuccessful: .mysql_error()}


 abdulazeez alugo wrote:
 Hi guys,

 Please can anyone tell me what I'm doing wrong with the code
   below? It keep
 returning unsuccessful.

 $result=mysql_query(CREATE TABLE table2(table2_id INT NOT NULL
   PRIMARY KEY
 AUTO_INCREMENT,
 table1_id INT NOT NULL,
 name VARCHAR(100) NOT NULL,
 school VARCHAR(100) NOT NULL,
 comment TEXT NOT NULL,
 entrydate TIMESTAMP NOT NULL,
 FOREIGN KEY(table1_id) REFERENCES table1(table1_id))
 ENGINE = INNODB );

 if($result){ printSuccessful;}
 else {print Unsuccessful;}

 Thanks in advance. Cheers.

 Alugo Abdulazeez.

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RE: PHP-MYSQL Question

2009-04-07 Thread abdulazeez alugo


 I've done that but it still gives the same error message.

 


Date: Tue, 7 Apr 2009 16:25:15 +0200
Subject: Re: PHP-MYSQL Question
From: spa...@googlemail.com
To: defati...@hotmail.com
CC: mysql@lists.mysql.com


it is not the ENGINE as Eugene mentioned above, is that you need to use 
UNSIGNED when creating the second table


CREATE TABLE table2 ( table2_id INT NOT NULL PRIMARY KEY AUTO_INCREMENT,
table1_id INT UNSIGNED NOT NULL,
name VARCHAR(100) NOT NULL,
school VARCHAR(100) NOT NULL,
comment TEXT NOT NULL,
entrydate TIMESTAMP NOT NULL,
FOREIGN KEY(table1_id) REFERENCES table1(table1_id))
ENGINE = INNODB



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RE: PHP-MYSQL Question

2009-04-07 Thread abdulazeez alugo

Alright guys,

I just solved the problem. I read from somewhere that if you're using a foreign 
key, it should be the either the primary key in the table or the index so since 
I already used auto increment on table2_id and I've already made it my Primary 
key, I just made table1_id the index and it returned successful. So that was 
the problem all along.

Thanks for your suggestions.

Best regards

Alugo Abdulazeez.
 
 From: defati...@hotmail.com
 To: spa...@googlemail.com
 CC: mysql@lists.mysql.com
 Subject: RE: PHP-MYSQL Question
 Date: Tue, 7 Apr 2009 15:32:25 +0100
 
 
 
 I've done that but it still gives the same error message.
 
 
 
 
 Date: Tue, 7 Apr 2009 16:25:15 +0200
 Subject: Re: PHP-MYSQL Question
 From: spa...@googlemail.com
 To: defati...@hotmail.com
 CC: mysql@lists.mysql.com
 
 
 it is not the ENGINE as Eugene mentioned above, is that you need to use 
 UNSIGNED when creating the second table
 
 
 CREATE TABLE table2 ( table2_id INT NOT NULL PRIMARY KEY AUTO_INCREMENT,
 table1_id INT UNSIGNED NOT NULL,
 name VARCHAR(100) NOT NULL,
 school VARCHAR(100) NOT NULL,
 comment TEXT NOT NULL,
 entrydate TIMESTAMP NOT NULL,
 FOREIGN KEY(table1_id) REFERENCES table1(table1_id))
 ENGINE = INNODB
 
 
 
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mysql question.

2007-04-03 Thread Me2resh Lists

hi
i need help regarding a sql query in my php app.

the query is :
   $SQL = SELECT DISTINCT(EMail) FROM mena_guests WHERE Voted = 'yes'
LIMIT $startingID,$items_numbers_list;

i want to sort this query by the number of the repeated EMail counts.
can anyone help me with that please ?


Re: mysql question.

2007-04-03 Thread Mogens Melander
Hmmm, using distinct email in a query where you want
to count email won't work.

select mail, count(mail) as mailcnt from guest
where voted='yes'
group by mail
order by mailcnt;

should do the trick.

On Tue, April 3, 2007 12:51, Me2resh Lists wrote:
 hi
 i need help regarding a sql query in my php app.

 the query is :
 $SQL = SELECT DISTINCT(EMail) FROM mena_guests WHERE Voted = 'yes'
 LIMIT $startingID,$items_numbers_list;

 i want to sort this query by the number of the repeated EMail counts.
 can anyone help me with that please ?

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Re: General MySQL Question: Ed Reed (CA, United States ofAmerica) Medium

2007-01-30 Thread Eric Braswell
Great idea!  Tips on how to get around, good local restaurants (if you 
like Vietnamese, San Jose is the place), and other things to do when you 
need a break...  There is really a great deal just a short distance 
away, but you have to know how to get there. It's possible there was 
something like this last year, but I live in the area so I didn't look 
for it.


I'm in full agreement that a conference is just that much better when it 
includes a little variety, a chance to get away from the drab convention 
hall, and a chance to socialize a little.


One thing I suggest is to attend the Quiz Show (Wed 8pm) or other after 
hours activities. Great fun, and a good way to hook up with people for 
dinner or drinks away from the center.


Eric


--
Eric Braswell
Web Manager MySQL AB
Cupertino, USA



Mike Wexler wrote:
The area by the Santa Clara convention center is pretty dead, but you 
can take the light rail to downtown San Jose and there is a pretty 
lively nightlife there, lots of interesting restaurants, The Tech Museum 
and other things depending on you interests.
Also there are lots more interesting places to eat than sizzler within 
in  5 minute drive of the convention center.


Perhaps what is needed is either a nice cheatsheet of what to do and 
where to go?
Or perhaps some of the locals could volunteer to be ambassadors and 
take people with similar interests to local activities, restaurants or 
points of interest.






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Re: General MySQL Question: Ed Reed (CA, United States of America) Medium

2007-01-30 Thread mizioumt

Hi Ed,

the subject line of your message indicates you live in California
in which case Santa Clara won't add much to the experience,
but most other people could enjoy visiting California a lot
especially if they don't mind dedicating entire day driving to Sierra 
Nevada.

One off the beaten path route is to cross the Sierra on hwy 108,
pass by Lake Mono
and return on hwy 120 through Yosemite.
Even around Santa Clara there are some possibilities for a good drive,
try to get to the observatory in San Jose (hwy 103 or 104),
or just cross the Coastal range around Santa Clara and take hwy 1 North
to San Francisco.
Other than the natural beauty the place is pretty sterile
but from my experience it applies to most of the country anyway.
The clubs in downtown San Jose are decent especially if you manage
to find one with live music.
I'd consider visiting one of mysql conferences if they had one
in a nice place like Panama City (in Panama, not in Florida).

Thanks,
Michael

-Original Message-
From: [EMAIL PROTECTED]
To: mysql@lists.mysql.com; [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Sent: Mon, 29 Jan 2007 4:57 PM
Subject: Re: General MySQL Question: Ed Reed (CA, United States of 
America) Medium


I just didn't enjoy the location. When it was in Orlando a few years 
ago, it was
great. There were plenty of things to do and see; different places to 
eat every
night. I had a really good time. Then the following year I went to 
Santa Clara
and there was nothing to do. I went to the movies one night. Had dinner 
at
Sizzler three times. I drove 45 minutes to find a place I could buy a 
shirt. The
rest of the time I stayed in the hotel and watched crappy tv. If you 
folks want
me to be away from my family and friends for five days you've gotta 
give me a
reason to wanna go besides the great technical information. I didn't go 
to last
years, I'm not going to this years and I probably won't go to any 
future ones
held in Santa Clara. When I came home from the last one, my kids asked 
what I
got them from my trip and I had nothing for them. It was just a boring 
place to
go and I don't wanna go back. I'd just like to see it held someplace 
new every

year.

Thanks for replying to my comment



Lenz Grimmer [EMAIL PROTECTED] 1/25/07 2:21 AM 

-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1

Hi Ed,

thank you for your message!

On Thu, 18 Jan 2007, Ed Reed has filled out the MySQL Contact Form with 
a

General MySQL Question:

Can someone tell me you folks are going to hold all future User 

Conferences
in Santa Clara? I would like to go this year but I didn't enjoy 

myself at the
last one I went to in Santa Clara in '05 and I don't wanna go back. 

If you
folks plan to hold all future conferences there I'd like to know so I 

can
resign myself to the fact that it's never gonna change instead of 

hoping that

it's gonna be somewhere else every year.


To be honest, it's not entirely clear yet if we will change the 
location for
upcoming events. But could you explain why you didn't enjoy yourself at 
the

last one? How can we improve?

Bye,
LenZ
- --
Lenz Grimmer [EMAIL PROTECTED]
Community Relations Manager, EMEA
MySQL GmbH, http://www.mysql.de/, Hamburg, Germany
Visit the MySQL Forge at http://forge.mysql.com/
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RE: General MySQL Question: Ed Reed (CA, United States ofAmerica) Medium

2007-01-30 Thread Jerry Schwartz
If you are into ancient Egypt, check out the Rosicrucian museum in San Jose.

Regards,

Jerry Schwartz
Global Information Incorporated
195 Farmington Ave.
Farmington, CT 06032

860.674.8796 / FAX: 860.674.8341


 -Original Message-
 From: Eric Braswell [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, January 30, 2007 3:02 AM
 To: Mike Wexler
 Cc: Ed Reed; mysql@lists.mysql.com; [EMAIL PROTECTED]
 Subject: Re: General MySQL Question: Ed Reed (CA, United
 States ofAmerica) Medium

 Great idea!  Tips on how to get around, good local
 restaurants (if you
 like Vietnamese, San Jose is the place), and other things to
 do when you
 need a break...  There is really a great deal just a short distance
 away, but you have to know how to get there. It's possible there was
 something like this last year, but I live in the area so I
 didn't look
 for it.

 I'm in full agreement that a conference is just that much
 better when it
 includes a little variety, a chance to get away from the drab
 convention
 hall, and a chance to socialize a little.

 One thing I suggest is to attend the Quiz Show (Wed 8pm) or
 other after
 hours activities. Great fun, and a good way to hook up with
 people for
 dinner or drinks away from the center.

 Eric


 --
 Eric Braswell
 Web Manager MySQL AB
 Cupertino, USA



 Mike Wexler wrote:
  The area by the Santa Clara convention center is pretty
 dead, but you
  can take the light rail to downtown San Jose and there is a pretty
  lively nightlife there, lots of interesting restaurants,
 The Tech Museum
  and other things depending on you interests.
  Also there are lots more interesting places to eat than
 sizzler within
  in  5 minute drive of the convention center.
 
  Perhaps what is needed is either a nice cheatsheet of what
 to do and
  where to go?
  Or perhaps some of the locals could volunteer to be
 ambassadors and
  take people with similar interests to local activities,
 restaurants or
  points of interest.
 
 
 

 --
 MySQL General Mailing List
 For list archives: http://lists.mysql.com/mysql
 To unsubscribe:
 http://lists.mysql.com/[EMAIL PROTECTED]






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To unsubscribe:http://lists.mysql.com/[EMAIL PROTECTED]



Getting OT re San Jose (was RE: General MySQL Question: Ed Reed (CA, United States of America) Medium)

2007-01-30 Thread Steve Edberg

I'd second the Rosicrucian Egyptian Museum:

   http://www.egyptianmuseum.org/

Also the Computer History Museum (located in the former SGI 
International Sales Office, I believe) is HIGHLY recommended by 
me...one of the docents there the last time I visited was Gene 
Amdahl! They have a working PDP-1, Cray 1, 2, 3 and Y-MP, and one of 
Google's first server racks, among tons of other stuff. They're in 
Mountain View, but it's not far, and would amply justify a carpool:


   http://www.computerhistory.org/

Intel's museum is in Santa Clara (never been there myself):

   http://www.intel.com/museum/index.htm

And the San Jose Museum of Art:

   http://www.sjmusart.org/

I found this exhibition to be quite interesting:


http://www.sjmusart.org/content/exhibitions/current/exhibition_info.phtml?itemID=324

And if you have kids with you (including inner children...), there's

   http://www.cdm.org/

Never been there, though, so I can't vouch for it. Interested in 
aviation/space?


   http://www.moffettfieldmuseum.org/

   http://www.nasa.gov/centers/ames/home/exploration.html

   http://www.hiller.org/


steve, museum nerd




At 10:16 AM -0500 1/30/07, Jerry Schwartz wrote:

If you are into ancient Egypt, check out the Rosicrucian museum in San Jose.

Regards,

Jerry Schwartz
Global Information Incorporated
195 Farmington Ave.
Farmington, CT 06032

860.674.8796 / FAX: 860.674.8341



 -Original Message-
 From: Eric Braswell [mailto:[EMAIL PROTECTED]
 Sent: Tuesday, January 30, 2007 3:02 AM
 To: Mike Wexler
 Cc: Ed Reed; mysql@lists.mysql.com; [EMAIL PROTECTED]
 Subject: Re: General MySQL Question: Ed Reed (CA, United
 States ofAmerica) Medium

 Great idea!  Tips on how to get around, good local
 restaurants (if you
 like Vietnamese, San Jose is the place), and other things to
 do when you
 need a break...  There is really a great deal just a short distance
 away, but you have to know how to get there. It's possible there was
 something like this last year, but I live in the area so I
 didn't look
 for it.

 I'm in full agreement that a conference is just that much
 better when it
 includes a little variety, a chance to get away from the drab
 convention
 hall, and a chance to socialize a little.

 One thing I suggest is to attend the Quiz Show (Wed 8pm) or
 other after
 hours activities. Great fun, and a good way to hook up with
 people for
 dinner or drinks away from the center.

 Eric


 --
 Eric Braswell
 Web Manager MySQL AB
 Cupertino, USA



 Mike Wexler wrote:
  The area by the Santa Clara convention center is pretty
 dead, but you
  can take the light rail to downtown San Jose and there is a pretty
  lively nightlife there, lots of interesting restaurants,
 The Tech Museum
  and other things depending on you interests.
  Also there are lots more interesting places to eat than
 sizzler within
  in  5 minute drive of the convention center.
 
  Perhaps what is needed is either a nice cheatsheet of what
 to do and
  where to go?
  Or perhaps some of the locals could volunteer to be
 ambassadors and
  take people with similar interests to local activities,
 restaurants or

   points of interest.
 



--
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| Steve Edberghttp://pgfsun.ucdavis.edu/ |
| UC Davis Genome Center[EMAIL PROTECTED] |
| Bioinformatics programming/database/sysadmin (530)754-9127 |
+ said t e lawrence, picking up his fork +

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Re: General MySQL Question: Ed Reed (CA, United States of America) Medium

2007-01-29 Thread Ed Reed
I just didn't enjoy the location. When it was in Orlando a few years ago, it 
was great. There were plenty of things to do and see; different places to eat 
every night. I had a really good time. Then the following year I went to Santa 
Clara and there was nothing to do. I went to the movies one night. Had dinner 
at Sizzler three times. I drove 45 minutes to find a place I could buy a shirt. 
The rest of the time I stayed in the hotel and watched crappy tv. If you folks 
want me to be away from my family and friends for five days you've gotta give 
me a reason to wanna go besides the great technical information. I didn't go to 
last years, I'm not going to this years and I probably won't go to any future 
ones held in Santa Clara. When I came home from the last one, my kids asked 
what I got them from my trip and I had nothing for them. It was just a boring 
place to go and I don't wanna go back. I'd just like to see it held someplace 
new every year.
 
Thanks for replying to my comment
 

 Lenz Grimmer [EMAIL PROTECTED] 1/25/07 2:21 AM 
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1

Hi Ed,

thank you for your message!

On Thu, 18 Jan 2007, Ed Reed has filled out the MySQL Contact Form with a 
General MySQL Question:

 Can someone tell me you folks are going to hold all future User Conferences
 in Santa Clara? I would like to go this year but I didn't enjoy myself at the
 last one I went to in Santa Clara in '05 and I don't wanna go back. If you
 folks plan to hold all future conferences there I'd like to know so I can
 resign myself to the fact that it's never gonna change instead of hoping that
 it's gonna be somewhere else every year. 

To be honest, it's not entirely clear yet if we will change the location for
upcoming events. But could you explain why you didn't enjoy yourself at the
last one?  How can we improve?

Bye,
LenZ
- -- 
Lenz Grimmer [EMAIL PROTECTED]
Community Relations Manager, EMEA
MySQL GmbH, http://www.mysql.de/, Hamburg, Germany
Visit the MySQL Forge at http://forge.mysql.com/ 
-BEGIN PGP SIGNATURE-
Version: GnuPG v1.4.5 (GNU/Linux)
Comment: For info see http://quantumlab.net/pine_privacy_guard/ 

iD8DBQFFuISeSVDhKrJykfIRAsJxAJ9hLkjhA10B68OHpw97x6QHbSqjLACePQym
m9lEE93nxdC+K//cQsL658Q=
=W/8N
-END PGP SIGNATURE-


[OT] Re: General MySQL Question: Ed Reed (CA, United States of America) Medium

2007-01-29 Thread Joshua J. Kugler
On Monday 29 January 2007 12:57, Ed Reed wrote:
 I just didn't enjoy the location. When it was in Orlando a few years ago,
 it was great. There were plenty of things to do and see; different places
 to eat every night. I had a really good time. Then the following year I
 went to Santa Clara and there was nothing to do. I went to the movies one
 night. Had dinner at Sizzler three times. I drove 45 minutes to find a
 place I could buy a shirt. The rest of the time I stayed in the hotel and
 watched crappy tv. If you folks want me to be away from my family and
 friends for five days you've gotta give me a reason to wanna go besides the
 great technical information. I didn't go to last years, I'm not going to
 this years and I probably won't go to any future ones held in Santa Clara.
 When I came home from the last one, my kids asked what I got them from my
 trip and I had nothing for them. It was just a boring place to go and I
 don't wanna go back. I'd just like to see it held someplace new every year.

 Thanks for replying to my comment

That's funny...when I go to a technical conference, I usually go for the 
conference, and couldn't care less if there is other stuff to do in the area 
during the off hours.

j

-- 
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Lead System Admin -- Senior Programmer
http://www.eeinternet.com
PGP Key: http://pgp.mit.edu/  ID 0xDB26D7CE
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Re: General MySQL Question: Ed Reed (CA, United States ofAmerica) Medium

2007-01-29 Thread Ed Reed
I understand that. I go there for the same thing. My point was that, the 
conference needs the attendees as much we want the conference. When I go I'm 
going for the conference stuff but I have a life and they're asking us to give 
up that life for maybe 6 days. After a the second day things start to get a 
little monotonous and we need a break. After the third or fourth day the brain 
is fried. There needs to be some kind of other activity that takes your mind 
off of the same hotel walls. Let's put it another way. When you go to work do 
you stay there for 5 days straight? Probably not. You go home, you go out to 
dinner. You see friends. You do other things to take your mind away from work 
because you have to recharge your batteries. It's the same thing at the 
conferences. Unless you're a robot you have to get out and see the sights and 
be entertained so that you can go back the next day and absorb the next days 
meetings.

I just liked it better when it felt like it was gonna be held at a different 
location every year. I made this same complaint last year and it never got this 
much attention. 
 
- cheers
 Joshua J. Kugler [EMAIL PROTECTED] 1/29/07 4:36 PM 
That's funny...when I go to a technical conference, I usually go for the 
conference, and couldn't care less if there is other stuff to do in the area 
during the off hours.

j

-- 
Joshua Kugler   
Lead System Admin -- Senior Programmer
http://www.eeinternet.com ( http://www.eeinternet.com/ )
PGP Key: http://pgp.mit.edu/  ID 0xDB26D7CE
PO Box 80086 -- Fairbanks, AK 99708 -- Ph: 907-456-5581 Fax: 907-456-3111


 Ed Reed [EMAIL PROTECTED] 1/29/07 1:57 PM 
I just didn't enjoy the location. When it was in Orlando a few years ago, it 
was great. There were plenty of things to do and see; different places to eat 
every night. I had a really good time. Then the following year I went to Santa 
Clara and there was nothing to do. I went to the movies one night. Had dinner 
at Sizzler three times. I drove 45 minutes to find a place I could buy a shirt. 
The rest of the time I stayed in the hotel and watched crappy tv. If you folks 
want me to be away from my family and friends for five days you've gotta give 
me a reason to wanna go besides the great technical information. I didn't go to 
last years, I'm not going to this years and I probably won't go to any future 
ones held in Santa Clara. When I came home from the last one, my kids asked 
what I got them from my trip and I had nothing for them. It was just a boring 
place to go and I don't wanna go back. I'd just like to see it held someplace 
new every year.

Thanks for replying to my comment


 Lenz Grimmer [EMAIL PROTECTED] 1/25/07 2:21 AM 
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1

Hi Ed,

thank you for your message!

On Thu, 18 Jan 2007, Ed Reed has filled out the MySQL Contact Form with a 
General MySQL Question:

 Can someone tell me you folks are going to hold all future User Conferences
 in Santa Clara? I would like to go this year but I didn't enjoy myself at the
 last one I went to in Santa Clara in '05 and I don't wanna go back. If you
 folks plan to hold all future conferences there I'd like to know so I can
 resign myself to the fact that it's never gonna change instead of hoping that
 it's gonna be somewhere else every year. 

To be honest, it's not entirely clear yet if we will change the location for
upcoming events. But could you explain why you didn't enjoy yourself at the
last one?  How can we improve?

Bye,
LenZ
- -- 
Lenz Grimmer [EMAIL PROTECTED]
Community Relations Manager, EMEA
MySQL GmbH, http://www.mysql.de/, Hamburg, Germany
Visit the MySQL Forge at http://forge.mysql.com/ 
-BEGIN PGP SIGNATURE-
Version: GnuPG v1.4.5 (GNU/Linux)
Comment: For info see http://quantumlab.net/pine_privacy_guard/ 

iD8DBQFFuISeSVDhKrJykfIRAsJxAJ9hLkjhA10B68OHpw97x6QHbSqjLACePQym
m9lEE93nxdC+K//cQsL658Q=
=W/8N
-END PGP SIGNATURE-


Re: General MySQL Question: Ed Reed (CA, United States ofAmerica) Medium

2007-01-29 Thread Mike Wexler
The area by the Santa Clara convention center is pretty dead, but you 
can take the light rail to downtown San Jose and there is a pretty 
lively nightlife there, lots of interesting restaurants, The Tech Museum 
and other things depending on you interests.
Also there are lots more interesting places to eat than sizzler within 
in  5 minute drive of the convention center.


Perhaps what is needed is either a nice cheatsheet of what to do and 
where to go?
Or perhaps some of the locals could volunteer to be ambassadors and 
take people with similar interests to local activities, restaurants or 
points of interest.




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Re: mysql question regarding distinct/group by...

2007-01-04 Thread ViSolve DB Team

Hi,

dog
fooID int
size int
id int

dog
 fooIDsizeid
   1   2  1
   2   5  2
   1   5  3

if i do a query
 select * from dog where fooID='1';

 i get
 1,2,1
 1,5,3


Try,

select * from dog where fooID=1 group by fooID;

- which retrieves the first instance;
resulting in,

1,2,1

Thanks
ViSolve DB Team

- Original Message - 
From: bruce [EMAIL PROTECTED]

To: mysql@lists.mysql.com
Sent: Thursday, January 04, 2007 6:07 AM
Subject: mysql question regarding distinct/group by...



hi...

i've asked something similar before.. but it appears something is going
wrong... so, back to basics...

i have the following test tbl.

dog
fooID int
size int
id int

dog
 fooIDsizeid
   1   2  1
   2   5  2
   1   5  3

if i do a query
 select * from dog where fooID='1';

 i get
 1,2,1
 1,5,3

how can i do a distinct/group by select such that if i do a select on
fooID=1, i'll only get '1,2,1', or '1,5,3', meaning that i don't get both
of
the items where fooId=1.

thanks...



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Re: mysql question regarding distinct/group by...

2007-01-04 Thread Arun Kumar PG

SELECT * FROM Dog GROUP BY FooId HAVING FooId = 1;

This should also work.


On 1/5/07, ViSolve DB Team [EMAIL PROTECTED] wrote:


Hi,
 dog
 fooID int
 size int
 id int

 dog
  fooIDsizeid
1   2  1
2   5  2
1   5  3

 if i do a query
  select * from dog where fooID='1';

  i get
  1,2,1
  1,5,3

Try,

select * from dog where fooID=1 group by fooID;

- which retrieves the first instance;
resulting in,

1,2,1

Thanks
ViSolve DB Team

- Original Message -
From: bruce [EMAIL PROTECTED]
To: mysql@lists.mysql.com
Sent: Thursday, January 04, 2007 6:07 AM
Subject: mysql question regarding distinct/group by...


 hi...

 i've asked something similar before.. but it appears something is going
 wrong... so, back to basics...

 i have the following test tbl.

 dog
 fooID int
 size int
 id int

 dog
  fooIDsizeid
1   2  1
2   5  2
1   5  3

 if i do a query
  select * from dog where fooID='1';

  i get
  1,2,1
  1,5,3

 how can i do a distinct/group by select such that if i do a select on
 fooID=1, i'll only get '1,2,1', or '1,5,3', meaning that i don't get
both
 of
 the items where fooId=1.

 thanks...



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 For list archives: http://lists.mysql.com/mysql
 To unsubscribe:
 http://lists.mysql.com/[EMAIL PROTECTED]



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mysql question regarding distinct/group by...

2007-01-03 Thread bruce
hi...

i've asked something similar before.. but it appears something is going
wrong... so, back to basics...

i have the following test tbl.

dog
 fooID int
 size int
 id int

dog
  fooIDsizeid
1   2  1
2   5  2
1   5  3

if i do a query
  select * from dog where fooID='1';

  i get
  1,2,1
  1,5,3

how can i do a distinct/group by select such that if i do a select on
fooID=1, i'll only get '1,2,1', or '1,5,3', meaning that i don't get both of
the items where fooId=1.

thanks...



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Re: mysql question regarding distinct/group by...

2007-01-03 Thread Dan Nelson
In the last episode (Jan 03), bruce said:
 i've asked something similar before.. but it appears something is going
 wrong... so, back to basics...
 
 i have the following test tbl.
 
 dog
  fooID int
  size int
  id int
 
 dog
   fooIDsizeid
 1   2  1
 2   5  2
 1   5  3
 
 if i do a query
   select * from dog where fooID='1';
 
   i get
   1,2,1
   1,5,3
 
 how can i do a distinct/group by select such that if i do a select on
 fooID=1, i'll only get '1,2,1', or '1,5,3', meaning that i don't get both of
 the items where fooId=1.

How about just asking for the first matching record with LIMIT 1?

-- 
Dan Nelson
[EMAIL PROTECTED]

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Re: Install mysql question

2005-05-20 Thread Gleb Paharenko
Hello.



See:

  http://dev.mysql.com/doc/mysql/en/can-not-connect-to-server.html





Dear there,

I have some problems when installing mysql under rpm.  Hope some people

can give me help. 

I install MySQL-server-4.1.12-0.i386 package and

MySQL--client--4.1.12-0.i386   package

under root account. Under the root account, I can start the mysql and it

seems working

fine. However, when I change the root account to user account, it give

me error report

Can't connect to local MySQL server through the socket

/var/lib/mysql/mysql.sock .

But the mysql.sock file is already in this directory when I checked. I

try a lot way to

solve it, unfornately, it fails.

Could some people give me some idea? I have to say I am just beginner. 

I am really appreciated any suggestions!



Ying Sun [EMAIL PROTECTED] wrote:



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Install mysql question

2005-05-19 Thread Ying Sun
Dear there,

I have some problems when installing mysql under rpm.  Hope some people can 
give me help. 
I install MySQL-server-4.1.12-0.i386 package and MySQL--client--4.1.12-0.i386   
package under root account. Under the root account, I can start the mysql and 
it seems working fine. However, when I change the root account to user account, 
it give me error report Can't connect to local MySQL server through the socket 
/var/lib/mysql/mysql.sock . But the mysql.sock file is already in this 
directory when I checked. I try a lot way to solve it, unfornately, it fails.
Could some people give me some idea? I have to say I am just beginner. 
I am really appreciated any suggestions!

Best
Ying


RE: Python related MySQL question

2005-04-26 Thread mathias fatene
Look at db.use_result() and db.store_result() here :
http://www.birgerblixt.com/doc/packages/python-mysql/MySQLdb-2.html#ss2.
2

Best Regards

Mathias FATENE
 
Hope that helps
*This not an official mysql support answer
 


-Original Message-
From: Smelly Socks [mailto:[EMAIL PROTECTED] 
Sent: mardi 26 avril 2005 06:20
To: mysql@lists.mysql.com
Subject: Re: Python related MySQL question


Hi!

I am porting a function library app I wrote in PHP to Python.  At work
they only use Python.  I've researched how to connect to a MySql
database using Python, and how to retrieve rows.  However, I am
wondering how to do the
following:

I can do this in Python =  $da=MYSQL_QUERY(select *  from prefs where
user_name='$user_name'  ); I can do this in Python =
$peek=mysql_fetch_array($da);

I cannot do the following:
$title   =$peek[4];  //title window
$logic   =$peek[5];  //logic window

Can anyone shed light on how to get the pieces of the array and stick
them into variables?

Thanks very much!

Cheers!

-Warren




- Original Message -
From: Spenser [EMAIL PROTECTED]
To: David Bailey [EMAIL PROTECTED]
Cc: mysql@lists.mysql.com
Sent: Thursday, April 14, 2005 12:27 PM
Subject: Re: book advice


 Check out MySQL Tutorial by Luke Welling (MySQL Press).  It's easy 
 to understand and not overwhelming.


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Re: Python related MySQL question

2005-04-25 Thread Smelly Socks
Hi!

I am porting a function library app I wrote in PHP to Python.  At work they
only use Python.  I've researched how to connect to a MySql database using
Python, and how to retrieve rows.  However, I am wondering how to do the
following:

I can do this in Python =  $da=MYSQL_QUERY(select *  from prefs where
user_name='$user_name'  );
I can do this in Python =  $peek=mysql_fetch_array($da);

I cannot do the following:
$title   =$peek[4];  //title window
$logic   =$peek[5];  //logic window

Can anyone shed light on how to get the pieces of the array and stick them
into variables?

Thanks very much!

Cheers!

-Warren




- Original Message -
From: Spenser [EMAIL PROTECTED]
To: David Bailey [EMAIL PROTECTED]
Cc: mysql@lists.mysql.com
Sent: Thursday, April 14, 2005 12:27 PM
Subject: Re: book advice


 Check out MySQL Tutorial by Luke Welling (MySQL Press).  It's easy to
 understand and not overwhelming.


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DBI mysql question.

2005-03-16 Thread Richard Reina
Dear MySQL Developers and Enthusiasts,

when I run these lines of code :

my $T_NO = 12569;
use DBI;
my $dbh =
DBI-connect(DBI:mysql:database=carr_search;192.168.0.1,user,password);

my $q = CREATE TABLE IF NOT EXISTS CS_? (
ID_NO MEDIUMINT,
NAME VARCHAR(30),
TYPE CHAR(1)
);
my $sth = $dbh-prepare($q);
$sth-execute($T_NO);

from w/in a program I get:

DBD:mysql::st execute failed: You have an error in
your SQL syntax near '12569 ( 
ID_NO MEDIUMINT,
NAME VARCHAR(30),
TYP' at line 2 at ./carr_s.pl line 36.
 
However if I cut and paste the exact same code and
make it it's own program then execute it, it works
perfectly. Can anyone tell me what's happening and how
I can fix it?

Thanks,

Richard

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Re: DBI mysql question.

2005-03-16 Thread Gary Richardson
Hey,

The placeholders (?) are safely escaped by the DBI library -- your
query that gets submitted to the server actually looks like:

CREATE TABLE IF NOT EXISTS CS_ 12569 (
ID_NO MEDIUMINT,
NAME VARCHAR(30),
TYPE CHAR(1)
)

I think it puts the space in, but it might actually be quoting it.

I would do something like:

$dbh-do(sprintf(CREATE TABLE IF NOT EXISTS CS_%d (
ID_NO MEDIUMINT,
NAME VARCHAR(30),
TYPE CHAR(1)
), $T_NO));

out.

On Wed, 16 Mar 2005 10:10:39 -0800 (PST), Richard Reina
[EMAIL PROTECTED] wrote:
 Dear MySQL Developers and Enthusiasts,
 
 when I run these lines of code :
 
 my $T_NO = 12569;
 use DBI;
 my $dbh =
 DBI-connect(DBI:mysql:database=carr_search;192.168.0.1,user,password);
 
 my $q = CREATE TABLE IF NOT EXISTS CS_? (
 ID_NO MEDIUMINT,
 NAME VARCHAR(30),
 TYPE CHAR(1)
 );
 my $sth = $dbh-prepare($q);
 $sth-execute($T_NO);
 
 from w/in a program I get:
 
 DBD:mysql::st execute failed: You have an error in
 your SQL syntax near '12569 (
 ID_NO MEDIUMINT,
 NAME VARCHAR(30),
 TYP' at line 2 at ./carr_s.pl line 36.
 
 However if I cut and paste the exact same code and
 make it it's own program then execute it, it works
 perfectly. Can anyone tell me what's happening and how
 I can fix it?
 
 Thanks,
 
 Richard
 
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[mysql] Question about the reference manual

2004-08-04 Thread rdo mail list address

Is the MySQL Reference Manual, by Widenius and Axmark (the one to which
there is a link on the Documentation page of the mysql website, for sale by
Barnes and Noble) the same reference manual that you can download?

The PDF version has 1310 pages, the softcover book has 712 pages, and I'm
not sure that they're the same.  I like to have an actual book so that I
can take it with me and study in places where I have to waste some time
waiting.

But I suspect the online manual is more up to date than the published book,
and wanted to confirm whether that is true.

rdo


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Re: [mysql] Question about the reference manual

2004-08-04 Thread Jim Winstead
On Wed, Aug 04, 2004 at 02:46:50PM -0500, rdo mail list address wrote:
 Is the MySQL Reference Manual, by Widenius and Axmark (the one to which
 there is a link on the Documentation page of the mysql website, for sale by
 Barnes and Noble) the same reference manual that you can download?
 
 The PDF version has 1310 pages, the softcover book has 712 pages, and I'm
 not sure that they're the same.  I like to have an actual book so that I
 can take it with me and study in places where I have to waste some time
 waiting.
 
 But I suspect the online manual is more up to date than the published book,
 and wanted to confirm whether that is true.

The MySQL Reference Manual published by O'Reilly is the same reference
manual as the website -- as it existed when it was published in June
2002. The manual has been updated quite extensively since then.

Two new books have just been published under the MySQL Press imprint that 
are derived from the online manual. You can find more information about
them at http://www.mysqlpress.com/

Jim Winstead
MySQL AB

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Re: Quick mysql question

2004-03-24 Thread Victor Medina
4.0.18 is the latest stable!
On Tue, 2004-03-23 at 19:08, [EMAIL PROTECTED] wrote:

 Hi,
 
 A quick question, which is the most stable version of mysql to run on a very busy 
 and commercial website(s)?
 
 4.0 or is 4.1 stable enough?
 
 Thanks,
 -R.A

-- 

 |...|
 |  _    _|Victor Medina M   |
 |\ \ \| |  _ \ / \   |Linux - Java - MySQL  |
 | \ \ \  _| | |_) / _ \  |Dpto. Sistemas - Ferreteria EPA   |
 | / / / |___|  __/ ___ \ |[EMAIL PROTECTED]  |
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Quick mysql question

2004-03-23 Thread ryan

Hi,

A quick question, which is the most stable version of mysql to run on a very busy and 
commercial website(s)?

4.0 or is 4.1 stable enough?

Thanks,
-R.A



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Re: Quick mysql question

2004-03-23 Thread dan
4.1 seems stable enough, been running it since it was released.
in production, busy, commercial, enterprise environment.
plus it fixes some bugs in 4.0 and adds some (could be potentially)
necessary functions

Dan.

On Tue, 23 Mar 2004 [EMAIL PROTECTED] wrote:

 
 Hi,
 
 A quick question, which is the most stable version of mysql to run on a very busy 
 and commercial website(s)?
 
 4.0 or is 4.1 stable enough?
 
 Thanks,
 -R.A
 
 
 
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Re: Quick mysql question

2004-03-23 Thread Lokesh
[EMAIL PROTECTED] wrote:

Hi,

A quick question, which is the most stable version of mysql to run on a very busy and commercial website(s)?

4.0 or is 4.1 stable enough?

Thanks,
-R.A

4.0 is a released and stable version.
4.1 is a developement version which is alpha, but quite stable :)
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MySQL Question

2004-01-15 Thread Melton, Blair
We are a developer of Point of Sale software and are launching a Linux based
product shortly.  We wanted to know if there were any plans for MySQL to
support eSQL any time soon.  Thanks.

Regards,

Blair M. Melton
Vice President, Grocery and Merchandise Division
Sweda Corporation
(416) 246-5487





Php mysql question please help

2003-12-25 Thread cohenstudio
I just started working with mysql and I'm very novice
Created a simple database and programmed php to connect as follows...

?php
include (webvars.inc);
// webvars file is this
//?php$user = ???;$hostname = ???;$password = pass;
//$db=cs?
$link= mysql_connect($hostname,$user,$password)or die (_something is
whong);
mysql_select_db($db,$link);
$query =SELECT * FROM projects;
$result = mysql_query($query);
$array = mysql_fetch_array($result);
$usercount = mysql_num_rows($result);
mysql_close($link);
? 

Question 1 
I put the files created from mysql(MYI ,MYD,frm) in the correct
directory at my site  
Is this correct or do they need some kind of compilling? 

Question 2 
How do I Grant my host name and user name 
I'm comfused..It gives me an error message Can't connect because of host
and user mistake..

Thanks Aaron



Re: Can't connect to local MySQL question

2003-08-14 Thread Andreas
I forwarded your mail to the mysql list so that everyone who cares knows 
what is going.

Bill Hernandez wrote:
The error log shows:

030810 14:52:48  mysqld started
030810 14:52:49  InnoDB: Started
030810 14:52:49  Fatal error: Can't open privilege tables: Table
'mysql.host' doesn't exist
030810 14:52:49  Aborting
Ah that sounds familiar.  :(

1) If you don't know what InnoDB is, comment all the lines out that have 
innodb options in your  /etc/my.cnf

2) InnoDB provides transactions and referential integrity. Neat things 
that you probaply not know about, yet.

3) I bet the file /usr/local/mysql/data/mysql/mysql.host exists but 
InnoDB isn't allowed to see it by wrong directory/file permissions of 
your file system (not MySQL !)


I've bought several books on php/mysql and they all get right into the
programming aspects
Thats the point of PHP. They have to suppose you allready know to handle 
the DBMS.

www.php.net
www.devshed.net
www.php.net
Don't miss the PEAR extensions. --  pear.php.net
Start with PHP's mysql standard functions to get a basic understanding.
When you think you got that move up to the PEAR-DB classes.
http://pear.php.net/manual/en/package.database.php

 and what I probably need to look for is a book that
talks about the architecture.
well, not really.
Knowledge on dead trees is only good provided you have the time or 
motivation to actually read the book and of course some are crap anyway.
Then there are those which fill 1000 pages with more or less important 
stuff but your specific problem is no where to be found.
I hate it especially to read a chapter that stops right before the point 
where I need further info stating that from here it's too specific for 
this book.  =8-O

I bought lots of books which I should have read completely but just 
couldn't get the hang of. Buy it, take it home, put it on shelf, feel 
good that now all problems can come ... not quite.

1) Look in the (searchable!) online docu. Some with readers's comments.
2) Look at google. Real issues tend show up elsewhere and probaply are 
solved and documented allready.
3) Ask on a list.
4) Books ? Usually decorative at best though there are good ones, too.


I can see that the first thing I really need to do, is get a good
understanding of is all the pieces that make mysql work, what they do, how 
when they get created. What tools to use, preferably GUI tools.
that can't hurt   ;)

I like phpMyAdmin as maintenance client.
mysql and mysqladmin in texmode ain't that bad either when you know 
what's going on.

Then there is mysqlcc from mysql.com. GUI but I don't know if they build 
it for apples.


...and I have no clue why mysqld is unhappy about Table 'mysql.host'
doesn't exist. Where in the install, etc, process was it supposed to get
created, and by which piece?
/usr/local/mysql/scripts/mysql_install_db

Your problem are the permissions not the lack of the file.


I think I need to take three steps back, and figure out where the beginning
is? Thanks for the help...
no problem ...

Andreas
Germany
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[Fwd: Re: Can't connect to local MySQL question]

2003-08-14 Thread Andreas
 ---BeginMessage---
On 8/9/03 11:20 PM, Andreas [EMAIL PROTECTED] wrote:


Andreas,

Thanks for the help...

The error log shows:

030810 14:52:48  mysqld started
030810 14:52:49  InnoDB: Started
030810 14:52:49  Fatal error: Can't open privilege tables: Table
'mysql.host' doesn't exist
030810 14:52:49  Aborting

030810 14:52:49  InnoDB: Starting shutdown...
030810 14:52:51  InnoDB: Shutdown completed
030810 14:52:51  /usr/local/mysql/bin/mysqld: Shutdown Complete

030810 14:52:51  mysqld ended

I've bought several books on php/mysql and they all get right into the
programming aspects, and what I probably need to look for is a book that
talks about the architecture.

I can see that the first thing I really need to do, is get a good
understanding of is all the pieces that make mysql work, what they do, how 
when they get created. What tools to use, preferably GUI tools.

I followed the instructions on the install, and re-installed, the deleted
everything  installed again.

...and I have no clue why mysqld is unhappy about Table 'mysql.host'
doesn't exist. Where in the install, etc, process was it supposed to get
created, and by which piece?

I think I need to take three steps back, and figure out where the beginning
is? Thanks for the help...

Bill Hernandez
Plano, Texas

BTW, your comment about mysqld  being a daemon, and mysql is the client
really helped, puts things in perspective. Sort of client - server which I
can relate to...



 Bill Hernandez wrote:
 
 I followed the install instructions at http://entropy.ch , and was able to
 get mySql  php installed on my G4 - (OSX 10.2.6) last night. I downloaded
 Navicat and setup a password for the mysql user. I created a connection
 called myDatabase_connection to a database called myDatabase. I was able to
 get everything running OK.
 
 Did the server start and could you connect ?
 
 
 Today when I restarted the machine, I tried to launch the php program that I
 was running last night, and kept getting an error 2002 below.
 
 1) Have the mysql daemon running
 2) connect with a client
 
 
 [Home:/usr/local/mysql] justMe# ./bin/mysqld_safe 
 [1] 479
 [Home:/usr/local/mysql] justMe# Starting mysqld daemon with databases from
 /usr/local/mysql/data
 030809 20:04:58  mysqld ended
 
 there is an error.log in the data directory.
 Look there for mysql's complaints.
 
 
 HERE I HIT RETURN TO GET THE PROMPT AGAIN (Should I have typed the name of
 the database here, then hit return?)
 
 no
 You are mixing up the server and client process.
 mysqld is the server. It runs in the background and stores databases in
 it's data directory. There can be many separate databases.
 You'll select one of them later when you connect with the client.
 
 mysql  -- no d (=daemon)  is the textmode client that comes with the
 mysql package.
 
 
 [1]Done  ./bin/mysqld_safe
 [Home:/usr/local/mysql] justMe# ./bin/mysql myDatabase
 ERROR 2002: Can't connect to local MySQL server through socket
 '/tmp/mysql.sock' (2)
 
 Without running server-process there is no socket to connect to.
 
 
 start by looking at the err-file in the data-dir.
 
 You can run mysqld_save without the  to see more output. Sometimes the
 server comes up that way. Then you wont regain access to the shell where
 you ran mysqld_save.
 
 I had a hard time getting this kind of error.
 One day I figured out, that mc caused the hick-up. mc is a textmode
 filemanager I really use often.
 mysqld started and died at once again.
 
 If mc produces this effect then perhaps other filemanaging tools do, too.
 Use pure bash or xterm.
 
 Better yet, install mysql as a service to have it started at boot time.
 
 



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Can't connect to local MySQL question

2003-08-10 Thread Bill Hernandez
Hi,

I've been writing software on the mac since 1987, but am brand new at
unix/php/mysql, and that's where I'm headed so I'm reading everything I can
get my hands on, but like anything else there's going to be a learning
curve, that having been said...

I followed the install instructions at http://entropy.ch , and was able to
get mySql  php installed on my G4 - (OSX 10.2.6) last night. I downloaded
Navicat and setup a password for the mysql user. I created a connection
called myDatabase_connection to a database called myDatabase. I was able to
get everything running OK.

Today when I restarted the machine, I tried to launch the php program that I
was running last night, and kept getting an error 2002 below.

Could someone take a look at the syntax below and see if you could spot what
I am doing wrong?

Thank you very much...

Bill Hernandez




Last login: Sat Aug  9 20:00:07 on console
Welcome to Darwin!
[Home:~] justMe% su
Password:

[Home:/Users/justMe] justMe# cd /usr/local/mysql
[Home:/usr/local/mysql] justMe# chown -R mysql data/
[Home:/usr/local/mysql] justMe# echo
[Home:/usr/local/mysql] justMe# ./bin/mysqld_safe 
[1] 479
[Home:/usr/local/mysql] justMe# Starting mysqld daemon with databases from
/usr/local/mysql/data
030809 20:04:58  mysqld ended

HERE I HIT RETURN TO GET THE PROMPT AGAIN (Should I have typed the name of
the database here, then hit return?)

[1]Done  ./bin/mysqld_safe
[Home:/usr/local/mysql] justMe# ./bin/mysql myDatabase
ERROR 2002: Can't connect to local MySQL server through socket
'/tmp/mysql.sock' (2)

[Home:/usr/local] justMe# cd /

[Home:/] justMe# /usr/local/mysql/bin/mysql myDatabase
ERROR 2002: Can't connect to local MySQL server through socket
'/tmp/mysql.sock' (2)

[Home:/] justMe# mysql myDatabase
ERROR 2002: Can't connect to local MySQL server through socket
'/tmp/mysql.sock' (2)

[Home:/] justMe# 


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Re: Can't connect to local MySQL question

2003-08-10 Thread Eternal Designs, Inc


Andreas wrote:

Bill Hernandez wrote:

I followed the install instructions at http://entropy.ch , and was 
able to
get mySql  php installed on my G4 - (OSX 10.2.6) last night. I 
downloaded
Navicat and setup a password for the mysql user. I created a connection
called myDatabase_connection to a database called myDatabase. I was 
able to
get everything running OK.


Did the server start and could you connect ?


Today when I restarted the machine, I tried to launch the php program 
that I
was running last night, and kept getting an error 2002 below.


1) Have the mysql daemon running
2) connect with a client

[Home:/usr/local/mysql] justMe# ./bin/mysqld_safe 
[1] 479
[Home:/usr/local/mysql] justMe# Starting mysqld daemon with databases 
from
/usr/local/mysql/data
030809 20:04:58  mysqld ended


there is an error.log in the data directory.
Look there for mysql's complaints.

HERE I HIT RETURN TO GET THE PROMPT AGAIN (Should I have typed the 
name of
the database here, then hit return?)


no
You are mixing up the server and client process.
mysqld is the server. It runs in the background and stores databases 
in it's data directory. There can be many separate databases.
You'll select one of them later when you connect with the client.

mysql  -- no d (=daemon)  is the textmode client that comes with the 
mysql package.


[1]Done  ./bin/mysqld_safe
[Home:/usr/local/mysql] justMe# ./bin/mysql myDatabase
ERROR 2002: Can't connect to local MySQL server through socket
'/tmp/mysql.sock' (2)


Without running server-process there is no socket to connect to.

start by looking at the err-file in the data-dir.

You can run mysqld_save without the  to see more output. Sometimes 
the server comes up that way. Then you wont regain access to the shell 
where you ran mysqld_save.
I think it is mysqld_safe!

I had a hard time getting this kind of error.
One day I figured out, that mc caused the hick-up. mc is a textmode 
filemanager I really use often.
mysqld started and died at once again.

If mc produces this effect then perhaps other filemanaging tools do, too.
Use pure bash or xterm.
Better yet, install mysql as a service to have it started at boot time.



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Eternal Designs Inc.,
+1(617)344-8023 (fax  voicemail)


Re: Can't connect to local MySQL question

2003-08-09 Thread Andreas
Bill Hernandez wrote:

I followed the install instructions at http://entropy.ch , and was able to
get mySql  php installed on my G4 - (OSX 10.2.6) last night. I downloaded
Navicat and setup a password for the mysql user. I created a connection
called myDatabase_connection to a database called myDatabase. I was able to
get everything running OK.
Did the server start and could you connect ?


Today when I restarted the machine, I tried to launch the php program that I
was running last night, and kept getting an error 2002 below.
1) Have the mysql daemon running
2) connect with a client

[Home:/usr/local/mysql] justMe# ./bin/mysqld_safe 
[1] 479
[Home:/usr/local/mysql] justMe# Starting mysqld daemon with databases from
/usr/local/mysql/data
030809 20:04:58  mysqld ended
there is an error.log in the data directory.
Look there for mysql's complaints.

HERE I HIT RETURN TO GET THE PROMPT AGAIN (Should I have typed the name of
the database here, then hit return?)
no
You are mixing up the server and client process.
mysqld is the server. It runs in the background and stores databases in 
it's data directory. There can be many separate databases.
You'll select one of them later when you connect with the client.

mysql  -- no d (=daemon)  is the textmode client that comes with the 
mysql package.


[1]Done  ./bin/mysqld_safe
[Home:/usr/local/mysql] justMe# ./bin/mysql myDatabase
ERROR 2002: Can't connect to local MySQL server through socket
'/tmp/mysql.sock' (2)
Without running server-process there is no socket to connect to.

start by looking at the err-file in the data-dir.

You can run mysqld_save without the  to see more output. Sometimes the 
server comes up that way. Then you wont regain access to the shell where 
you ran mysqld_save.

I had a hard time getting this kind of error.
One day I figured out, that mc caused the hick-up. mc is a textmode 
filemanager I really use often.
mysqld started and died at once again.

If mc produces this effect then perhaps other filemanaging tools do, too.
Use pure bash or xterm.
Better yet, install mysql as a service to have it started at boot time.



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Perl/mysql question

2003-07-30 Thread Howell, Scott
Has anyone written a perl script to get records from another database and
write it to a file on mysql's LOAD DATA INFILE format? I just need some
pointers in perl so a LOAD DATA INFILE will be read correctly.

For example, a perl script:
Select * from emp from a Progress database
Will write to a text file called emp.txt in the LOAD DATA INFILE format,
Then,
I can to a direct LOAD DATA INFILE into my mysql database.

I tried doing direct select/inserts in perl but found dumping to a text file
and doing a LOAD DATA to be MUCH faster.

Am I missing something here?

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RE: Perl/mysql question

2003-07-30 Thread Dan Muey
 Has anyone written a perl script to get records from another 
 database and write it to a file on mysql's LOAD DATA INFILE 
 format? I just need some pointers in perl so a LOAD DATA 
 INFILE will be read correctly.


You might want to check out Perl's DBI module at search.cpan.org
I use that all the time to interact with mysql.
Simple quick and just as sexxy as mysql itself!

HTH

DMuey

 
 For example, a perl script:
 Select * from emp from a Progress database
 Will write to a text file called emp.txt in the LOAD DATA 
 INFILE format, Then, I can to a direct LOAD DATA INFILE into 
 my mysql database.

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Re: Perl/mysql question

2003-07-30 Thread Joel Fentin
Howell, Scott wrote:

Has anyone written a perl script to get records from another database and
write it to a file on mysql's LOAD DATA INFILE format? I just need some
pointers in perl so a LOAD DATA INFILE will be read correctly.
For example, a perl script:
Select * from emp from a Progress database
Will write to a text file called emp.txt in the LOAD DATA INFILE format,
Then,
I can to a direct LOAD DATA INFILE into my mysql database.
I tried doing direct select/inserts in perl but found dumping to a text file
and doing a LOAD DATA to be MUCH faster.
Am I missing something here?

Download data from mysql to pipe delimited text file; whole table.
SELECT * FROM table1 INTO OUTFILE 'c:/test.txt' FIELDS TERMINATED BY |;
Same download with perl/cgi
my $statement = 'SELECT * FROM table1 INTO OUTFILE \'C:/test.txt\' 
FIELDS TERMINATED BY |';
$dbh-do($statement) or die tilt\n;

Upload data from pipe delimited text file. Loads whole table.
LOAD DATA LOCAL INFILE [path with front slashes] filename.txt INTO 
TABLE tablename
FIELDS TERMINATED BY |;

Note that some service providers don't like this and won't permit it.
--
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Re: Perl/mysql question

2003-07-30 Thread Octavian Rasnita
Hi all,

I am using DBI and DBD::mysql to connect to a MySQL database from perl and I
would like to get the execution time period after a query, like MySQL
standard client shows.

Sometimes when I work in the standard console client it tells me that there
are x wornings.
How can I see which are those warnings?

Thank you.



Teddy,
Teddy's Center: http://teddy.fcc.ro/
Email: [EMAIL PROTECTED]

- Original Message -
From: Howell, Scott [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, July 30, 2003 6:38 PM
Subject: Perl/mysql question


Has anyone written a perl script to get records from another database and
write it to a file on mysql's LOAD DATA INFILE format? I just need some
pointers in perl so a LOAD DATA INFILE will be read correctly.

For example, a perl script:
Select * from emp from a Progress database
Will write to a text file called emp.txt in the LOAD DATA INFILE format,
Then,
I can to a direct LOAD DATA INFILE into my mysql database.

I tried doing direct select/inserts in perl but found dumping to a text file
and doing a LOAD DATA to be MUCH faster.

Am I missing something here?

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Re: [MYSQL] Question about 'SHOW PROCESSLIST' output columns

2003-06-25 Thread Egor Egorov
PAUL MENARD [EMAIL PROTECTED] wrote:
 
 I'm having an intermittent problem with a MySQL server that I have running on a 
 Windows 2000 Advance server systems. This issue occurs every few days depending on 
 the load of the system. 
 
 Here are the details.
 
 MySQL version 3.23.42-nt (I know I need to upgrade. Soon).
 Machine:
 Windows 2000 Advanced Server
 2G memory
 36G disk space.
 
 I have a Web page that allows my operators to monitor various process tasks on this 
 server. Sometimes they receive an error that PHP cannot connect to MySQL. If this 
 happens during the day they call me. I log into the server and bring up the 
 WinMySQLadmin 3.1 client and click on the 'Process' tab. There are a few (maybe 250 
 attached processes). I know there are many machines connecting to this database to 
 feed updates from enterprise applications. So I bumped up the 'max_connections' 
 limit to 1000. This just seems to delay the limit and the phone call.
 
 My question is in looking at the output form the 'Process' tab I see the columns 
 'Command' and 'Time'. In all of the rows for 'Command' the value is 90% 'Sleep'. 
 This would tell me I have some processes out there that are not dis-connecting 
 (right?). In the 'Time' column is see numbers ranging from 150 to 1000+. I'm 
 guessing this is the time the connection is idle (correct?). What I would like to do 
 is define my parameters so that these dead processes will be disconnected by MySQL 
 after a shorter time but not sure which variable to change. Advice?

You can decrease value of wait_timout variable:
http://www.mysql.com/doc/en/SHOW_VARIABLES.html



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Re: update to 4.0 mySQL question

2003-06-24 Thread Roman Neuhauser
# [EMAIL PROTECTED] / 2003-06-23 11:11:28 -0400:
 I have updated mySQL to the 4.0.13-standard and had no problems UNTIL I
 attempted to run mysql_fix_privileges. This is the error I get:
 
   ERROR 2002: Can't connect to local MySQL server through socket
 '/tmp/mysql.sock' (2)
 
 /tmp is:
   drwxrwxrwt6 root root 4096 Jun 23 11:21 tmp
 
 and mysql.sock is ACTUALLY located in /var/lib/mysql.
 
 Where do I need to look to change the location from /tmp to /var/lib/mysql
 for this particular file?

Looks like you have either not upgraded you client (server puts the
socket in /var/lib/mysql, but the client expects it in /tmp), and/or
you have conflicting definitions my my.cnf file(s).

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Re: update to 4.0 mySQL question

2003-06-24 Thread Victoria Reznichenko
Susan Ator [EMAIL PROTECTED] wrote:
 I have updated mySQL to the 4.0.13-standard and had no problems UNTIL I
 attempted to run mysql_fix_privileges. This is the error I get:
 
ERROR 2002: Can't connect to local MySQL server through socket
 '/tmp/mysql.sock' (2)
 
 /tmp is:
drwxrwxrwt6 root root 4096 Jun 23 11:21 tmp
 
 and mysql.sock is ACTUALLY located in /var/lib/mysql.
 
 Where do I need to look to change the location from /tmp to /var/lib/mysql
 for this particular file?

Use --socket option of mysqld:
http://www.mysql.com/doc/en/Command-line_options.html


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[MYSQL] Question about 'SHOW PROCESSLIST' output columns

2003-06-24 Thread PAUL MENARD
Hello All,
 
I'm having an intermittent problem with a MySQL server that I have running on a 
Windows 2000 Advance server systems. This issue occurs every few days depending on the 
load of the system. 
 
Here are the details.
 
MySQL version 3.23.42-nt (I know I need to upgrade. Soon).
Machine:
Windows 2000 Advanced Server
2G memory
36G disk space.
 
I have a Web page that allows my operators to monitor various process tasks on this 
server. Sometimes they receive an error that PHP cannot connect to MySQL. If this 
happens during the day they call me. I log into the server and bring up the 
WinMySQLadmin 3.1 client and click on the 'Process' tab. There are a few (maybe 250 
attached processes). I know there are many machines connecting to this database to 
feed updates from enterprise applications. So I bumped up the 'max_connections' limit 
to 1000. This just seems to delay the limit and the phone call.
 
My question is in looking at the output form the 'Process' tab I see the columns 
'Command' and 'Time'. In all of the rows for 'Command' the value is 90% 'Sleep'. This 
would tell me I have some processes out there that are not dis-connecting (right?). In 
the 'Time' column is see numbers ranging from 150 to 1000+. I'm guessing this is the 
time the connection is idle (correct?). What I would like to do is define my 
parameters so that these dead processes will be disconnected by MySQL after a shorter 
time but not sure which variable to change. Advice?
 
Paul



update to 4.0 mySQL question

2003-06-23 Thread Susan Ator
I have updated mySQL to the 4.0.13-standard and had no problems UNTIL I
attempted to run mysql_fix_privileges. This is the error I get:

ERROR 2002: Can't connect to local MySQL server through socket
'/tmp/mysql.sock' (2)

/tmp is:
drwxrwxrwt6 root root 4096 Jun 23 11:21 tmp

and mysql.sock is ACTUALLY located in /var/lib/mysql.

Where do I need to look to change the location from /tmp to /var/lib/mysql
for this particular file?

susan

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Colonel in Cuba with MySQL question

2003-03-10 Thread dpgirago


I inadvertantly deleted the colonel's question, which I believe concerned
winmysqladmin.
  Please give us more info. You should be able to see your databse(s) under the
database tab.

David



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PHP / MYSQL Question

2003-02-21 Thread Mike Walth
Not sure if this can be done with just a MYSQL Query or if it needs to be
done in conjunction with a PHP script.  What I am trying to do is build a
dynamic FAQ section with PHP.  Here are the two tables

Topics
===
TopicID
TopicTitle
TopicDESC

FAQS
===
FAQID
Question
Answer
Topic

I'm trying to get it to display like this

Topic1
   Question1
   Question2
   Question3
   Question4

Topic2
   Question1
   Question2

So each topic would be listed with its set of questions below it.

Any help would be appreciated.

Mike Walth
CinoFusion



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perl dbi and mysql question

2002-11-08 Thread Shon Stephens
i am using perl dbi with dbd::mysql. i know that using the dbi function,
$dbh-tables (), will list all the tables in a database. is there a function
that will show all the databases on a server?

thanks,
shon

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RE: perl dbi and mysql question

2002-11-08 Thread Shon Stephens
eureka! i found it!

@dbs = $dbh-func('_ListDBs');

-Original Message-
From: Shon Stephens [mailto:sstephens;corp.goamerica.net]
Sent: Friday, November 08, 2002 9:45 AM
To: '[EMAIL PROTECTED]'
Subject: perl dbi and mysql question


i am using perl dbi with dbd::mysql. i know that using the dbi function,
$dbh-tables (), will list all the tables in a database. is there a function
that will show all the databases on a server?

thanks,
shon

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Re: perl dbi and mysql question

2002-11-08 Thread stibs-pi
No clue of dbi/dbd but the query SHOW DATABASES does what it tells.

STIBS

- Original Message -
From: Shon Stephens [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Friday, November 08, 2002 3:44 PM
Subject: perl dbi and mysql question


 i am using perl dbi with dbd::mysql. i know that using the dbi function,
 $dbh-tables (), will list all the tables in a database. is there a
function
 that will show all the databases on a server?

 thanks,
 shon

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 Before posting, please check:
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 To request this thread, e-mail [EMAIL PROTECTED]
 To unsubscribe, e-mail [EMAIL PROTECTED]
 Trouble unsubscribing? Try: http://lists.mysql.com/php/unsubscribe.php



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RE: perl dbi and mysql question

2002-11-08 Thread Grigor, Peter
Of course, you could have also used:

$stmt = $db-prepare(show databases);

Peter
^_^

-Original Message-
From: Shon Stephens [mailto:sstephens;corp.goamerica.net]
Sent: Friday, November 08, 2002 9:50 AM
To: Shon Stephens; '[EMAIL PROTECTED]'
Subject: RE: perl dbi and mysql question


eureka! i found it!

@dbs = $dbh-func('_ListDBs');

-Original Message-
From: Shon Stephens [mailto:sstephens;corp.goamerica.net]
Sent: Friday, November 08, 2002 9:45 AM
To: '[EMAIL PROTECTED]'
Subject: perl dbi and mysql question


i am using perl dbi with dbd::mysql. i know that using the dbi function,
$dbh-tables (), will list all the tables in a database. is there a function
that will show all the databases on a server?

thanks,
shon

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RE: perl dbi and mysql question

2002-11-08 Thread Shon Stephens
yeah, but i was looking for a function. mostly just to see if a matching
function to dbh-tables() existed.

-Original Message-
From: Grigor, Peter [mailto:pgrigor;aseedge.com]
Sent: Friday, November 08, 2002 10:07 AM
To: 'Shon Stephens'; '[EMAIL PROTECTED]'
Subject: RE: perl dbi and mysql question


Of course, you could have also used:

$stmt = $db-prepare(show databases);

Peter
^_^

-Original Message-
From: Shon Stephens [mailto:sstephens;corp.goamerica.net]
Sent: Friday, November 08, 2002 9:50 AM
To: Shon Stephens; '[EMAIL PROTECTED]'
Subject: RE: perl dbi and mysql question


eureka! i found it!

@dbs = $dbh-func('_ListDBs');

-Original Message-
From: Shon Stephens [mailto:sstephens;corp.goamerica.net]
Sent: Friday, November 08, 2002 9:45 AM
To: '[EMAIL PROTECTED]'
Subject: perl dbi and mysql question


i am using perl dbi with dbd::mysql. i know that using the dbi function,
$dbh-tables (), will list all the tables in a database. is there a function
that will show all the databases on a server?

thanks,
shon

-
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Another Defining Relationships in MySQL Question

2002-11-08 Thread tmb
In MS Access you define relationships between Key ID
fields by dragging a line on the screen from the
parent table to the child table.

So, if you are enforcing referential integrity you
can not delete data that is referred to by another
table or mess up the basic db structure... (think I
have this about right :)

When you first create a db in MySQL... how do you tell
MySQL which Key field in table A is related to a field
in table B?

Thanks for any help - tmb


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Re: Another Defining Relationships in MySQL Question

2002-11-08 Thread Michael T. Babcock
tmb wrote:


In MS Access you define relationships between Key ID
fields by dragging a line on the screen from the
parent table to the child table.
 


Read up on referential integrity and InnoDB tables in the online docs at 
http://www.mysql.com/doc/en

--
Michael T. Babcock
C.T.O., FibreSpeed Ltd.
http://www.fibrespeed.net/~mbabcock



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RE: a mysql question

2002-10-17 Thread Alan McDonald

I think you need to give us the SQL you are using to do the search - we'll
ba ble to see what your are trying to do better
Alan

 -Original Message-
 From: µÑ ¶Ì [mailto:[EMAIL PROTECTED]]
 Sent: Thursday, 17 October 2002 15:37
 To: [EMAIL PROTECTED]
 Subject: a mysql question


 I'm a chinese software engineer, and I has use mysql
 for three years ago.Now,I get a matter from it.
 recently,I'm deal big data use mysql first.every
 table's data is one million,so user search the data
 will use long time.now ,if some user search one table
 togeter,the table is dead , and I find the connection
 to the mysql cann't close,my God,I only restart it.

 my develop language is JAVA.But I can't think the
 error is in JAVA code.my question is wheather mysql
 can't support a lot of connection search one table
 together?

 I want get a help or an advance for you ,thanks.

 _
 Do You Yahoo!?
 ÐÂÏʵ½µ×,ÓéÀÖµ½¼Ò - ÑÅ»¢ÍƳöÃâ·ÑÓéÀÖµç×ÓÖܱ¨!
 http://cn.ent.yahoo.com/newsletter/index.html

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Re: a mysql question

2002-10-17 Thread Dicky Wahyu Purnomo

Pada Thu, 17 Oct 2002 13:36:58 +0800 (CST)
µÑ ¶Ì [EMAIL PROTECTED] menulis:

 I'm a chinese software engineer, and I has use mysql
 for three years ago.Now,I get a matter from it.
 recently,I'm deal big data use mysql first.every
 table's data is one million,so user search the data
 will use long time.now ,if some user search one table
 togeter,the table is dead , and I find the connection
 to the mysql cann't close,my God,I only restart it.
 
 my develop language is JAVA.But I can't think the
 error is in JAVA code.my question is wheather mysql
 can't support a lot of connection search one table
 together?
 
 I want get a help or an advance for you ,thanks.

Please create index on your table and it depends on your queries ... :D
It will improve your query performance.

My server is now have more than 2 million records per table and a lot of connections, 
it's really depend on your table design and also my.cnf configuration.

-- 
Dicky Wahyu Purnomo - System Administrator
PT FIRSTWAP: Jl Kapt. Tendean No. 34 - Jakarta Selatan (12790)
Phone: +62 21 79199577 - HP: +62 8158787286 - Web: http://1rstwap.com


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a mysql question

2002-10-16 Thread

I'm a chinese software engineer, and I has use mysql
for three years ago.Now,I get a matter from it.
recently,I'm deal big data use mysql first.every
table's data is one million,so user search the data
will use long time.now ,if some user search one table
togeter,the table is dead , and I find the connection
to the mysql cann't close,my God,I only restart it.

my develop language is JAVA.But I can't think the
error is in JAVA code.my question is wheather mysql
can't support a lot of connection search one table
together?

I want get a help or an advance for you ,thanks.

_
Do You Yahoo!? 
ÐÂÏʵ½µ×,ÓéÀÖµ½¼Ò - ÑÅ»¢ÍƳöÃâ·ÑÓéÀÖµç×ÓÖܱ¨!
http://cn.ent.yahoo.com/newsletter/index.html

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Re: a mysql question

2002-10-16 Thread Niclas Hedhman


Sorry, but it is hard to understand what you are actually asking, but I'll 
try.

If you are returning too large resultset, it is possibly a JDBC driver 
problem, since it will retrieve all into Java objects, which could take 
forever.

If you know your SELECT statement, just issue it in the mysql client, and you 
will know the number of records returned as well as how long it takes. 

But I think you are trying to say something about multi-threading on 
connections. If I am not mistaken, you are not allowed to re-use the same 
connection with more than one query at a time. You either need an exclusion 
mechanism or a connection pool to distribute available connections among 
users, i.e. different threads.

Niclas

On Thursday 17 October 2002 13:36, µÑ ¶Ì wrote:
 I'm a chinese software engineer, and I has use mysql
 for three years ago.Now,I get a matter from it.
 recently,I'm deal big data use mysql first.every
 table's data is one million,so user search the data
 will use long time.now ,if some user search one table
 togeter,the table is dead , and I find the connection
 to the mysql cann't close,my God,I only restart it.

 my develop language is JAVA.But I can't think the
 error is in JAVA code.my question is wheather mysql
 can't support a lot of connection search one table
 together?

 I want get a help or an advance for you ,thanks.

 _
 Do You Yahoo!?
 ÐÂÏʵ½µ×,ÓéÀÖµ½¼Ò - ÑÅ»¢ÍƳöÃâ·ÑÓéÀÖµç×ÓÖܱ¨!
 http://cn.ent.yahoo.com/newsletter/index.html

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Re: MySQL Question

2002-10-08 Thread Roger Baklund

* David M. Gonzalez Salinas 
 Does anybody knoy what is equivalent stmt in MySQL? 
 select * from table1 where col1 in (select col1 from table2)

This is called a subselect, and it is explained in the manual:

 URL: http://www.mysql.com/doc/en/ANSI_diff_Sub-selects.html 

-- 
Roger

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re: MySQL Question

2002-10-08 Thread Victoria Reznichenko

David,
Tuesday, October 08, 2002, 2:01:46 AM, you wrote:

DMGS Does anybody knoy what is equivalent stmt in MySQL? select * from table1 
DMGS where col1 in (select col1 from table2)

You can re-write without subselects:
http://www.mysql.com/doc/en/ANSI_diff_Sub-selects.html


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MySQL Question

2002-10-07 Thread David M. Gonzalez Salinas

Hi everybody...

Does anybody knoy what is equivalent stmt in MySQL? select * from table1 
where col1 in (select col1 from table2)

thanks in advance.

David.




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phpMyAdmin/MySQL Question

2002-09-25 Thread Easton, William

Maybe someone else can come up with an answer for me on this question. I am
getting the following error when I try to run my index.php file. I think I
have configured it correctly, but obviously I haven't. And my host basically
told to go shove it.

Welcome to phpMyAdmin 2.3.1-rc1
Error
MySQL said: 
Can't connect to local 
MySQL server through socket
'/var/lib/mysql/mysql.sock' (111)
Does anyone have any suggestions on this one? My config file looks like
this in the areas I think I may have screwed up:

$cfg['PmaAbsoluteUri'] = 'http://www.iaacc.org/phpMyAdmin/';

$cfg['PmaAbsoluteUri_DisableWarning'] = FALSE;

$cfg['PmaNoRelation_DisableWarning']  
= FALSE;

/**
 * Server(s) configuration
 */
$i = 0;
$i++;
$cfg['Servers'][$i]['host']  = 'localhost';
$cfg['Servers'][$i]['port']  
= '';  
$cfg['Servers'][$i]['socket']= '';
$cfg['Servers'][$i]['connect_type']  = 'tcp';  
$cfg['Servers'][$i]['controluser'] 
  = ''; 

$cfg['Servers'][$i]['controlpass']   = '';  
  
 
$cfg['Servers'][$i]['auth_type'] = 'config';
$cfg['Servers'][$i]['user']  = '***';   
$cfg['Servers'][$i]['password']   
   = '***';   
   
$cfg['Servers'][$i]['only_db']   = '';
   
   
$cfg['Servers'][$i]['verbose']   = '';
$cfg['Servers'][$i]['pmadb'] = '';  
   
   
$cfg['Servers'][$i]['bookmarktable'] = '';
$cfg['Servers'][$i]['relation']  = '';
$cfg['Servers'][$i]['table_info']= ''; 
$cfg['Servers'][$i]['table_coords']  = ''; 
$cfg['Servers'][$i]['pdf_pages']   
  = '';  
   
$cfg['Servers'][$i]['column_comments']  = '';  
$cfg['Servers'][$i]['AllowDeny']['order']  = '';
$cfg['Servers'][$i]['AllowDeny']['rules']  = array();

I have my login and password 
entered into the user/password area. Also, the
actually database is online at mysql.iaacc.org and that might be different.

If anyone can help, I would REALLY appreciate it.

Thanks

-Bill


 William Easton
 Creative Media Group
 The University of Iowa
 Room 1185 Westlawn
 Iowa City, IA 52242
 
 319/353-3022 voice
 319/335-9127 fax
 [EMAIL PROTECTED]
 http://www.medicine.uiowa.edu/creative
 http://telemed.medicine.uiowa.edu
 
 Notice: This e-mail (including attachments) is covered by the Electronic
 Communications Privacy Act, 18 U.S.C. 2510-2521, is confidential and may
 be legally privileged.  If you are not the intended recipient, you are
 hereby notified that any retention, dissemination, distribution, or
 copying of this communication is strictly prohibited.  Please reply to the
 sender that you have received the message in error, then delete it.  Thank
 you.

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RE: phpMyAdmin/MySQL Question

2002-09-25 Thread SELPH,JASON (HP-Richardson,ex1)

I believe you need to change the socket to the location in your /etc/my.cnf
file.

I usually add both sections in it just to kep things straight.

[client]
socket=path-for-socket-file

[mysqld]
socket=path-for-socket-file
I used /ldata/mysql/tmp/mysql.sock

my.cnf isn't automatically there so you may have to create it.

then change 
$cfg['Servers'][$i]['socket']= '';

to
$cfg['Servers'][$i]['socket']= 'path-used-in-my.cnf';

I am probably wrong, but its something that you can try without any danger
of screwing up everything.

If it doesn't work, simply remove the socket information and lines from the
my.cnf file.

Jason

-Original Message-
From: Easton, William [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, September 25, 2002 12:55 PM
To: '[EMAIL PROTECTED]'
Subject: phpMyAdmin/MySQL Question


Maybe someone else can come up with an answer for me on this question. I am
getting the following error when I try to run my index.php file. I think I
have configured it correctly, but obviously I haven't. And my host basically
told to go shove it.

Welcome to phpMyAdmin 2.3.1-rc1
Error
MySQL said: 
Can't connect to local MySQL server through socket
'/var/lib/mysql/mysql.sock' (111)
Does anyone have any suggestions on this one? My config file looks like
this in the areas I think I may have screwed up:

$cfg['PmaAbsoluteUri'] = 'http://www.iaacc.org/phpMyAdmin/';

$cfg['PmaAbsoluteUri_DisableWarning'] = FALSE;

$cfg['PmaNoRelation_DisableWarning']  = FALSE;

/**
 * Server(s) configuration
 */
$i = 0;
$i++;
$cfg['Servers'][$i]['host']  = 'localhost';
$cfg['Servers'][$i]['port']  = '';  
$cfg['Servers'][$i]['socket']= '';
$cfg['Servers'][$i]['connect_type']  = 'tcp';  
$cfg['Servers'][$i]['controluser']   = ''; 

$cfg['Servers'][$i]['controlpass']   = '';  
   
$cfg['Servers'][$i]['auth_type'] = 'config';
$cfg['Servers'][$i]['user']  = '***';   
$cfg['Servers'][$i]['password']  = '***';   
   
$cfg['Servers'][$i]['only_db']   = '';
   
   
$cfg['Servers'][$i]['verbose']   = '';
$cfg['Servers'][$i]['pmadb'] = ''; 
   
$cfg['Servers'][$i]['bookmarktable'] = '';
$cfg['Servers'][$i]['relation']  = '';
$cfg['Servers'][$i]['table_info']= ''; 
$cfg['Servers'][$i]['table_coords']  = ''; 
$cfg['Servers'][$i]['pdf_pages'] = '';  
   
$cfg['Servers'][$i]['column_comments']  = '';  
$cfg['Servers'][$i]['AllowDeny']['order']  = '';
$cfg['Servers'][$i]['AllowDeny']['rules']  = array();

I have my login and password entered into the user/password area. Also, the
actually database is online at mysql.iaacc.org and that might be different.

If anyone can help, I would REALLY appreciate it.

Thanks

-Bill


 William Easton
 Creative Media Group
 The University of Iowa
 Room 1185 Westlawn
 Iowa City, IA 52242
 
 319/353-3022 voice
 319/335-9127 fax
 [EMAIL PROTECTED]
 http://www.medicine.uiowa.edu/creative
 http://telemed.medicine.uiowa.edu
 
 Notice: This e-mail (including attachments) is covered by the Electronic
 Communications Privacy Act, 18 U.S.C. 2510-2521, is confidential and may
 be legally privileged.  If you are not the intended recipient, you are
 hereby notified that any retention, dissemination, distribution, or
 copying of this communication is strictly prohibited.  Please reply to the
 sender that you have received the message in error, then delete it.  Thank
 you.

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RE: phpMyAdmin/MySQL Question

2002-09-25 Thread Don Buckley

Yes, please, someone please tell how that mysql.sock file is working. I get
the same general thing as well when I try to connect using just mysqladmin.

Don B.

-Original Message-
From: Easton, William [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, September 25, 2002 10:55 AM
To: ''
Subject: phpMyAdmin/MySQL Question


Maybe someone else can come up with an answer for me on this question. I am
getting the following error when I try to run my index.php file. I think I
have configured it correctly, but obviously I haven't. And my host basically
told to go shove it.

Welcome to phpMyAdmin 2.3.1-rc1
Error
MySQL said:
Can't connect to local MySQL server through socket
'/var/lib/mysql/mysql.sock' (111) Does anyone have any suggestions on this
one? My config file looks like
this in the areas I think I may have screwed up:

$cfg['PmaAbsoluteUri'] = 'http://www.iaacc.org/phpMyAdmin/';

$cfg['PmaAbsoluteUri_DisableWarning'] = FALSE;

$cfg['PmaNoRelation_DisableWarning']  = FALSE;

/**
 * Server(s) configuration
 */
$i = 0; $i++;
$cfg['Servers'][$i]['host']  = 'localhost';
$cfg['Servers'][$i]['port']  = '';
$cfg['Servers'][$i]['socket']= '';
$cfg['Servers'][$i]['connect_type']  = 'tcp';
$cfg['Servers'][$i]['controluser']   = '';

$cfg['Servers'][$i]['controlpass']   = '';

$cfg['Servers'][$i]['auth_type'] = 'config';
$cfg['Servers'][$i]['user']  = '***';
$cfg['Servers'][$i]['password']  = '***';

$cfg['Servers'][$i]['only_db']   = '';


$cfg['Servers'][$i]['verbose']   = '';
$cfg['Servers'][$i]['pmadb'] = '';

$cfg['Servers'][$i]['bookmarktable'] = '';
$cfg['Servers'][$i]['relation']  = '';
$cfg['Servers'][$i]['table_info']= '';
$cfg['Servers'][$i]['table_coords']  = '';
$cfg['Servers'][$i]['pdf_pages'] = '';

$cfg['Servers'][$i]['column_comments']  = '';
$cfg['Servers'][$i]['AllowDeny']['order']  = '';
$cfg['Servers'][$i]['AllowDeny']['rules']  = array();

I have my login and password entered into the user/password area. Also, the
actually database is online at mysql.iaacc.org and that might be different.

If anyone can help, I would REALLY appreciate it.

Thanks

-Bill


 William Easton
 Creative Media Group
 The University of Iowa
 Room 1185 Westlawn
 Iowa City, IA 52242

 319/353-3022 voice
 319/335-9127 fax
 [EMAIL PROTECTED]
 http://www.medicine.uiowa.edu/creative
 http://telemed.medicine.uiowa.edu

 Notice: This e-mail (including attachments) is covered by the Electronic
 Communications Privacy Act, 18 U.S.C. 2510-2521, is confidential and may
 be legally privileged.  If you are not the intended recipient, you are
 hereby notified that any retention, dissemination, distribution, or
 copying of this communication is strictly prohibited.  Please reply to the
 sender that you have received the message in error, then delete it.  Thank
 you.

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Multiple concurrent MySQL question?

2002-09-22 Thread Paul Maine

I desire to configure MySQL in such a way that it will permit me to have two
different PHP/MySQL e-commerce applications running concurrently on my
development system. The table names and table structure are the same on both
applications(and databases). I have received a SQL backup from the new
client and would just like to be able to restore it to a directory and start
up another copy of MySQL and point it to the new location. I know that I
could create two different databases to accomplish what I desire however, I
would have to change all of the security tables for the new database.

What are your suggestions to solve this issue?

Thank You
Paul


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RE: Multiple concurrent MySQL question?

2002-09-22 Thread Andrew Braithwaite

Paul,

You need to run another server on a different port with a different socket
path. 

See http://www.mysql.com/doc/en/Multiple_servers.html

And http://www.mysql.com/doc/en/mysqld_multi.html to manage multiple MySQL
servers.

Cheers,

Andrew

-Original Message-
From: Paul Maine [mailto:[EMAIL PROTECTED]] 
Sent: Sunday, 22 September 2002 12:26
To: MySQL MySQL
Subject: Multiple concurrent MySQL question?


I desire to configure MySQL in such a way that it will permit me to have two
different PHP/MySQL e-commerce applications running concurrently on my
development system. The table names and table structure are the same on both
applications(and databases). I have received a SQL backup from the new
client and would just like to be able to restore it to a directory and start
up another copy of MySQL and point it to the new location. I know that I
could create two different databases to accomplish what I desire however, I
would have to change all of the security tables for the new database.

What are your suggestions to solve this issue?

Thank You
Paul


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MySQL Question

2002-09-10 Thread Mark S Lowe

I have to do an insert and need to nest a select inside. I have tons of 
documentation on a very simple version of this, however my requirements 
are one step beyond that. Here is what I'd like to do in MySQL:

insert into

table1

(column1, column2)

values
(select column1a from table2 where [something],
valueFromMemory)

If you'll notice, I want one column from a select and one column 
outside the select. Is this possible in MySQL? All the documentation 
I've read about MySQL says it can't be done.

Thank you in advance!

Mark


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Re: MySQL Question

2002-09-10 Thread Nicholas Stuart

From my experince this is not possible.
Is there any reason why you can not simply do two inserts following each
other?
INSERT INTO table1(column1) SELECT column1a FROM table2 WHERE [something]
INSERT INTO table1(column2) VALUES(valueFromMemory)
(as if you didnt know that already)  =D
There should be no reason why you couldnt do this as there is nothing that
ties the two columns together (that I can see here).
Maybe explain a bit more and we might be able to give you more info.

-Nick

 I have to do an insert and need to nest a select inside. I have tons of
 documentation on a very simple version of this, however my requirements
 are one step beyond that. Here is what I'd like to do in MySQL:

 insert into

 table1

 (column1, column2)

 values
 (select column1a from table2 where [something],
 valueFromMemory)

 If you'll notice, I want one column from a select and one column
 outside the select. Is this possible in MySQL? All the documentation
 I've read about MySQL says it can't be done.

 Thank you in advance!

 Mark


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Re: MySQL Question

2002-09-10 Thread Paul DuBois

At 17:16 -0700 9/10/02, Mark S Lowe wrote:
I have to do an insert and need to nest a select inside. I have tons 
of documentation on a very simple version of this, however my 
requirements are one step beyond that. Here is what I'd like to do 
in MySQL:

insert into

table1

(column1, column2)

values
(select column1a from table2 where [something],
valueFromMemory)

If you'll notice, I want one column from a select and one column 
outside the select. Is this possible in MySQL? All the documentation 
I've read about MySQL says it can't be done.

It depends.  What is the second value and where does it come from?
If it's some expression that you can calculate on the fly, there's
no reason it can't be done.


Thank you in advance!

Mark


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Re: MySQL Question

2002-09-10 Thread Nicholas Stuart

The optimization is understandable but I'm not sure how much it would
affect it if you did the select outside the insert statment vs inside.
Either way you are selecting the same thing but I dont know which way is
better.
Well just playing around with it for a bit I think I found something.
The value from memory is a variable of some sort right? I dont know what
language you are using so I'm not sure what it will hold.
Anyways you could do something like the following:
INSERT INTO table1(col1, col2) SELECT table2.col1a, variablehere FROM
table2 WHERE [blah];

This will work becuase if you do a SELECT 5 you get 5 back. So if you do
it with SELECT variable(aka some literial) you will get the
variable(literial) back and you will have two cols to match your
table1(col1, col2).
HTH
-Nick

 Sorry...yes...both columns have a NOT NULL constraint which makes
 inserting a blank a problem. My only other option is to do the SELECT
 first, then push the result into the INSERT with the other memory only
 variable. I'm doing this for a system that will undergo high volumes,
 and want to do what I can to optimize the number of individual selects.

 I'm probably going to have to do the alternate technique regardless. =\

 On Tuesday, September 10, 2002, at 05:23  PM, Nicholas Stuart wrote:

 From my experince this is not possible.
 Is there any reason why you can not simply do two inserts following
 each
 other?
 INSERT INTO table1(column1) SELECT column1a FROM table2 WHERE
 [something]
 INSERT INTO table1(column2) VALUES(valueFromMemory)
 (as if you didnt know that already)  =D
 There should be no reason why you couldnt do this as there is nothing
 that
 ties the two columns together (that I can see here).
 Maybe explain a bit more and we might be able to give you more info.

 -Nick

 I have to do an insert and need to nest a select inside. I have tons
 of
 documentation on a very simple version of this, however my
 requirements
 are one step beyond that. Here is what I'd like to do in MySQL:

 insert into

 table1

 (column1, column2)

 values
 (select column1a from table2 where [something],
 valueFromMemory)

 If you'll notice, I want one column from a select and one column
 outside the select. Is this possible in MySQL? All the documentation
 I've read about MySQL says it can't be done.

 Thank you in advance!

 Mark


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MySQL Question involving AUTO INCREMENT and PRIMARY IDs. - sql

2002-06-27 Thread jason wesley upton

EXPLANATION:

here's the pertinent piece of my sql create statement:

ID INT NOT NULL  AUTO_INCREMENT, PRIMARY KEY (ID));

i have used this create statement numerous times without this problem.  in the past, 
let's say i inserted 3 entries: A, B, and C.  their IDs were 1,2, and 
3.  then i delete C from the database.  when i then insert D its ID is 4.  leaving 
1,2, and 4 in the database.  seems like this is safe and as it should be.

all this morning, using the above example with a deviation...after i delete C and then 
insert D...D's ID is 3. if i delete B and C, then insert D and E...their 
ID's are 2 and 3.  

i was under the impression that once an ID had been used (in auto increment and as 
primary) it was gone.  must i also make the ID unique? i can see 
why a primary key might need to be not UNIQUE (for concatenation of entries...etc), 
but i don't think i've done it iN the past (when it has incremented 
correctly).   



thanks ahead of time.  query sql for the filter.



jason wesley upton







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MySQL Question involving AUTO INCREMENT and PRIMARY IDs. - sql

2002-06-27 Thread jason wesley upton

EXPLANATION:

here's the pertinent piece of my MySQL create statement:

ID INT NOT NULL  AUTO_INCREMENT, PRIMARY KEY (ID));

i have used this create statement numerous times without this problem.  in the past, 
let's say i inserted 3 entries: A, B, and C.  their IDs were 1,2, and 
3.  then i delete C from the database.  when i then insert D its ID is 4.  leaving 
1,2, and 4 in the database.  seems like this is safe and as it should be.

all this morning, using the above example with a deviation...after i delete C and then 
insert D...D's ID is 3. if i delete B and C, then insert D and E...their 
ID's are 2 and 3.  

i was under the impression that once an ID had been used (in auto increment and as 
primary) it was gone.  must i also make the ID unique? i can see 
why a primary key might need to be not UNIQUE (for concatenation of entries...etc), 
but i don't think i've done it iN the past (when it has incremented 
correctly).   



thanks ahead of time.  



jason wesley upton



a dropped query fancy table opens mysql queries from an sql integer with some happy 
pants that'll join unless union = a less enthusiastic return from the VARCHAR 
pleasant. - for the spam filter 
that hates my guts.




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Re: MySQL Question involving AUTO INCREMENT and PRIMARY IDs. - sql

2002-06-27 Thread Gerald Clark

That is a difference in the behavior of
isam and myisam tables.

jason wesley upton wrote:

EXPLANATION:

here's the pertinent piece of my sql create statement:

ID INT NOT NULL  AUTO_INCREMENT, PRIMARY KEY (ID));

i have used this create statement numerous times without this problem.  in the 
past, let's say i inserted 3 entries: A, B, and C.  their IDs were 1,2, and 
3.  then i delete C from the database.  when i then insert D its ID is 4.  leaving 
1,2, and 4 in the database.  seems like this is safe and as it should be.

all this morning, using the above example with a deviation...after i delete C and 
then insert D...D's ID is 3. if i delete B and C, then insert D and E...their 
ID's are 2 and 3.  

i was under the impression that once an ID had been used (in auto increment and as 
primary) it was gone.  must i also make the ID unique? i can see 
why a primary key might need to be not UNIQUE (for concatenation of entries...etc), 
but i don't think i've done it iN the past (when it has incremented 
correctly).   



thanks ahead of time.  query sql for the filter.



jason wesley upton







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Re: MySQL Question involving AUTO INCREMENT and PRIMARY IDs. - sql

2002-06-27 Thread William R. Mussatto

On Thu, 27 Jun 2002, jason wesley upton wrote:

 Date: Thu, 27 Jun 2002 14:05:34 -0500
 From: jason wesley upton [EMAIL PROTECTED]
 To: [EMAIL PROTECTED]
 Subject: MySQL Question involving AUTO INCREMENT and PRIMARY IDs. - sql
 
 EXPLANATION:
 
 here's the pertinent piece of my sql create statement:
 
 ID INT NOT NULL  AUTO_INCREMENT, PRIMARY KEY (ID));
 
 i have used this create statement numerous times without this problem.  in the 
past, let's say i inserted 3 entries: A, B, and C.  their IDs were 1,2, and 
 3.  then i delete C from the database.  when i then insert D its ID is 4.  leaving 
1,2, and 4 in the database.  seems like this is safe and as it should be.
 
 all this morning, using the above example with a deviation...after i delete C and 
then insert D...D's ID is 3. if i delete B and C, then insert D and E...their 
 ID's are 2 and 3.  
 
 i was under the impression that once an ID had been used (in auto increment and as 
primary) it was gone.  must i also make the ID unique? i can see 
 why a primary key might need to be not UNIQUE (for concatenation of entries...etc), 
but i don't think i've done it iN the past (when it has incremented 
 correctly).   
Depends a bit on table type: ISAM files will reuse the ID if the deleted 
record has the highest ID in the database.  MYISAM does not AFAIK.

 
 
 
 thanks ahead of time.  query sql for the filter.
 
 
 
 jason wesley upton
 
 
 
 
 
 
 
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Sincerely,

William Mussatto, Senior Systems Engineer
CyberStrategies, Inc
ph. 909-920-9154 ext. 27


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Mysql Question - urgent help needed pls

2002-06-26 Thread rprabha

Hi,
  Could any of you help me in getting a Performance Comparison document for
MySQL on different architectures (Intel linux or S390 linux).

Regards,
prabha



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RE: MYSQL question - Urgent

2002-04-30 Thread Gurhan Ozen

Hi Lucia..

1- The answers might/will be depent on what type of installation you are
planning to do. Will you compile source code, or install binaries, or ,
since you said you would be installing on Linux, will you install from RPMs?

2 - Yes , you need to do the installation as root .

3 - There is no special account to create InnoDB tables, but you need to
make sure that your MySQL server supports InnoDB tables.. Once the server
supports it, anyone who has privileges to create tables, can create InnoDB
tables. To ensure that you will have InnoDB support right after
installation, make sure to download mysql-version*MAX* files. The files with
the MAX word in it come with InnoDB support if InnoDB is available for
that platform, and in your case, for Linux, yes it is.

4 - Data files (the database/table files) are owned by mysql .

5 - If you download and install *MAX* binaries for Linux, you'll already
have InnoDB support .

6 - Those are the really databases. Those are same as what you define as the
database name after '@' in oracle.

 The most recommended book on MySQL is MySQL by Paul Dubois, see its web
page: http://www.kitebird.com/mysql-book/ . As for the user group, don't
restrict yourself to the area you are living in, this list is a global user
list of MySQL :)

Make sure to visit the following pages:
http://www.mysql.com/doc/L/i/Linux-RPM.html
http://www.mysql.com/doc/I/n/Installing_binary.html
http://www.mysql.com/doc/P/o/Post-installation.html


Gurhan Ozen
MCI WorldCom
Quality Assurance Team
[EMAIL PROTECTED]
ph:   703-449-4754
Vnet: 228-4754
1-800-PAGE-MCI pin: 1927052
AIM:  Greywolf1923

-Original Message-
From: Lucia DeMeester [mailto:[EMAIL PROTECTED]]
Sent: Monday, April 29, 2002 11:19 PM
To: [EMAIL PROTECTED]
Subject: MYSQL question - Urgent
Importance: High


I am an Oracle DBA and need to create a MYSQL database on Thursday.

Can you answer my questions?  (I have not had chance to read the manual yet.
Just a quick search, I can not find my answer.)
I plan to use InnoDB and I find it is quite similar to Oracle.  However, in
Oracle we install the software and create the instance and database as
oracle but I can not find any place describe what user I should use to
create mysql database.

We use Linux.

Questions:
- Do I use root account to install the software?
- What account do I use to create Innodb?
- Who owns the data files?  root or mysql
- Any suggestion of the owner and group for the mysql files?
- I think the process is to load the mysql software, then configure the
Innodb. Once the Innodb is configured, when you mean startup or shutdown
mysql server is this the same as shutdown the Innodb?
- When I query show databases, it give me mysql, test1, test2.  Are they
really databases or they are like schema owners in Oracle and Innodb is like
instance in Oracle.

P.S.  What is a good book to buy for the MYSQL database and any user group
in the United States I can belong.

Thanks very much.

Lucia DeMeester
New Media Merchants
858-882-8500 ext. 2314


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Re: MYSQL question - Urgent

2002-04-30 Thread Benjamin Pflugmann

Hi.

Sorry, but I beg to differ. I think it is not a good idea to recommend
to others to run the MySQL server as root. The manual explicitly
recommends otherwise.

On Mon, Apr 29, 2002 at 10:15:31PM -0600, [EMAIL PROTECTED] wrote:
 
 Questions:
 - Do I use root account to install the software?
 Yes to compile the source or do an RPM as seen below.
 See http://www.mysql.com/doc/L/i/Linux-RPM.html

The usual approch is to create an UNIX user mysql and give all files
to him (of course, you need the root account to do so). If you use a
reasonable distribution and can use the packaged MySQL, the package
manager will do this for you (e.g. Debian, Mandrake,... don't know of
others). 

Then you either start MySQL as mysql. Or as root and tell MySQL (via
command line option) to run as mysql.

This is surely described somewhere in the installation sections. Read
it! It seems big but if you pick the parts relevant to your system,
it's only some pages. And you will save a lot of hassle you would get
later.

 - What account do I use to create Innodb?
 Same - I am guessing here but I do all installs as root then give
 the needed permissions to others.

Maybe I am not up to date here, but usually you only need a database
login to create a database and that has nothing at all to do with the
UNIX root.

 - Who owns the data files?  root or mysql
 Root - See http://www.mysql.com/doc/P/r/Privilege_system.html

The user the MySQL daemon runs as.

I can only second the rest of the advices.
[...]

Bye,

Benjamin.

-- 
[EMAIL PROTECTED]

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MYSQL question - Urgent

2002-04-29 Thread Lucia DeMeester

I am an Oracle DBA and need to create a MYSQL database on Thursday.

Can you answer my questions?  (I have not had chance to read the manual yet.
Just a quick search, I can not find my answer.)
I plan to use InnoDB and I find it is quite similar to Oracle.  However, in
Oracle we install the software and create the instance and database as
oracle but I can not find any place describe what user I should use to
create mysql database.

We use Linux.

Questions:
- Do I use root account to install the software?
- What account do I use to create Innodb?
- Who owns the data files?  root or mysql
- Any suggestion of the owner and group for the mysql files?
- I think the process is to load the mysql software, then configure the
Innodb. Once the Innodb is configured, when you mean startup or shutdown
mysql server is this the same as shutdown the Innodb?
- When I query show databases, it give me mysql, test1, test2.  Are they
really databases or they are like schema owners in Oracle and Innodb is like
instance in Oracle.

P.S.  What is a good book to buy for the MYSQL database and any user group
in the United States I can belong.

Thanks very much.

Lucia DeMeester
New Media Merchants
858-882-8500 ext. 2314


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RE: MYSQL question - Urgent

2002-04-29 Thread Mike


Questions:
- Do I use root account to install the software?
Yes to compile the source or do an RPM as seen below.
See http://www.mysql.com/doc/L/i/Linux-RPM.html

- What account do I use to create Innodb?
Same - I am guessing here but I do all installs as root then give the needed
permissions to others.

- Who owns the data files?  root or mysql
Root - See http://www.mysql.com/doc/P/r/Privilege_system.html

- Any suggestion of the owner and group for the mysql files?
See http://www.mysql.com/doc/P/r/Privilege_system.html

- I think the process is to load the mysql software, then configure the
Innodb. Once the Innodb is configured, when you mean startup or shutdown
mysql server is this the same as shutdown the Innodb?
see http://www.mysql.com/doc/I/n/InnoDB_overview.html for some help on this


- When I query show databases, it give me mysql, test1, test2.  Are they
really databases or they are like schema owners in Oracle and Innodb is like
instance in Oracle.
Yes they are real. The MySQL one holds your user permissions
See http://www.mysql.com/doc/P/r/Privilege_system.html

P.S.  What is a good book to buy for the MYSQL database and any user group
in the United States I can belong.

Number one is Paul DuBois - Search Amazon or Ask Paul hereG

Your in the Best Mysql NewsgroupG There are some heavy users here and they
can help out but Please try and read the manualG
http://www.mysql.com/doc/index.html

Also for commercial use you should take a look at
http://www.mysql.com/doc/B/u/Business_Services_Commercial_licenses.html

These are only my opinions but they work hereG

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Re: [PHP] MySQL question...not sure if this is the correct forum to ask.

2002-02-16 Thread DL Neil

Luie,

 Wouldn't replace change all the entries in your table row, same effect as update?
 I believe the question is how to test which entry in a form has a new value and 
replace/update only that value
in the table.
 If I have a form...

  __
 |Employee Record Update|
 |  |
 |ID No:   1234 |
 |Name:_|
 |Address: _|
 |Status:  Married  |
 |  |
 |Submit|
  --

 If I have this table...
  _
 |idnonameaddressstatus|
 |-|
 |1234Peter45 street Single|
 |_|

 Which means I only want to replace the status and the name and address remains the 
same.
 How do you test w/c entries in the form have new values and change only those 
entries in the table?

 Peter, this is basically what your asking, right?
 I actually need to figure this one out myself so I would appreciate any info.


Do not use REPLACE if the table uses an AUTO_INCREMENT id, because if you do, any 
other tables linking into the
id column will need to be changed/become dislocated. Even if this is not the case, 
under these circumstances a
REPLACE is two db operations (DELETE followed by INSERT) and should be 'costed' 
accordingly.

In order to populate the form you must have first performed a SELECT to retrieve the 
data from the db. So from
there you can figure out what the data used to be - if you want/need to. You already 
have/send the existing data
values in/to the form (and can have it return form values as normal, and include the 
'original values' in
invisible fields - if you have to go that far).

When the form response comes back you have two choices:

1 PHP: use PHP to compare the ex-db values and the values returned from the form, then 
dynamically construct a
precise UPDATE statement (tailoring the SET clauses to the requisite column name and 
data value pairs). This is
a bit fiddly - and becomes more so as the number of form fields increases.

2 MySQL: use the intelligence of the MySQL UPDATE command (RTFM: MySQL only changes 
those values which need to
be changed) and issue a command which appears to UPDATE every possible-form-affected 
column (regardless of
whether is needs to be updated - according to 'form-thinking', because MySQL will 
decide for you and do the
'database-thinking')

Regards,
=dn


 What about REPLACE?
 
 http://www.mysql.com/doc/R/E/REPLACE.html
 
 'REPLACE works exactly like INSERT, except that if an old record in the
 table has the same value as a new record on a unique index, the old record
 is deleted before the new record is inserted'
 

 
  Hi,
 
  Can the UPDATE statement have conditional check embedded in it?  I
  have a page that displays a record (in a FORM format) that the user can
  change the information on each column.  I want to check each column and
  see which has been changed and update the table for entries that were
  changed only.
 
  for each column data {
if column is changed
then update;
else
do nothing;
  }
 
  Maybe I am making this too complicated than it needs and just go ahead
  and update all of the columns regardless with the new values, regardless
  they are actually different or not.
 
  Thanks in advance,
  -Peter



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RE: [PHP] MySQL question...not sure if this is the correct forum to ask.

2002-02-15 Thread Luie


Wouldn't replace change all the entries in your table row, same effect as update?
I believe the question is how to test which entry in a form has a new value and 
replace/update only that value in the table.
If I have a form...

 __
|Employee Record Update|
|  |  
|ID No:   1234 |  
|Name:_|
|Address: _|
|Status:  Married  | 
|  |  
|Submit|
 --  

If I have this table...
 _
|idnonameaddressstatus|
|-|
|1234Peter45 street Single|
|_|

Which means I only want to replace the status and the name and address remains the 
same.
How do you test w/c entries in the form have new values and change only those entries 
in the table?
  
Peter, this is basically what your asking, right?
I actually need to figure this one out myself so I would appreciate any info.

thanks...

luie


What about REPLACE?

http://www.mysql.com/doc/R/E/REPLACE.html

'REPLACE works exactly like INSERT, except that if an old record in the
table has the same value as a new record on a unique index, the old record
is deleted before the new record is inserted'



 Hi,

 Can the UPDATE statement have conditional check embedded in it?  I
 have a page that displays a record (in a FORM format) that the user can
 change the information on each column.  I want to check each column and
 see which has been changed and update the table for entries that were
 changed only.

 for each column data {
   if column is changed
   then update;
   else
   do nothing;
 }

 Maybe I am making this too complicated than it needs and just go ahead
 and update all of the columns regardless with the new values, regardless
 they are actually different or not.

 Thanks in advance,
 -Peter


__
www.edsamail.com

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FW: [PHP] MySQL question...not sure if this is the correct forum to ask.

2002-02-14 Thread Rick Emery

-Original Message-
From: Peter Ruan [mailto:[EMAIL PROTECTED]]
Sent: Thursday, February 14, 2002 4:04 PM
To: [EMAIL PROTECTED]
Subject: [PHP] MySQL question...not sure if this is the correct forum to
ask.


Hi,

Can the UPDATE statement have conditional check embedded in it?  I
have a page that displays a record (in a FORM format) that the user can
change the information on each column.  I want to check each column and
see which has been changed and update the table for entries that were
changed only.

for each column data {
  if column is changed
  then update;
  else
  do nothing;
}

Maybe I am making this too complicated than it needs and just go ahead
and update all of the columns regardless with the new values, regardless
they are actually different or not.

Thanks in advance,
-Peter




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RE: [PHP] MySQL question...not sure if this is the correct forum to ask.

2002-02-14 Thread Daniel Rosher

What about REPLACE?

http://www.mysql.com/doc/R/E/REPLACE.html

'REPLACE works exactly like INSERT, except that if an old record in the
table has the same value as a new record on a unique index, the old record
is deleted before the new record is inserted'

Regards,
Dan

 -Original Message-
 From: Rick Emery [mailto:[EMAIL PROTECTED]]
 Sent: Friday, 15 February 2002 11:10 a.m.
 To: [EMAIL PROTECTED]
 Cc: '[EMAIL PROTECTED]'
 Subject: FW: [PHP] MySQL question...not sure if this is the correct
 forum to ask.


 -Original Message-
 From: Peter Ruan [mailto:[EMAIL PROTECTED]]
 Sent: Thursday, February 14, 2002 4:04 PM
 To: [EMAIL PROTECTED]
 Subject: [PHP] MySQL question...not sure if this is the correct forum to
 ask.


 Hi,

 Can the UPDATE statement have conditional check embedded in it?  I
 have a page that displays a record (in a FORM format) that the user can
 change the information on each column.  I want to check each column and
 see which has been changed and update the table for entries that were
 changed only.

 for each column data {
   if column is changed
   then update;
   else
   do nothing;
 }

 Maybe I am making this too complicated than it needs and just go ahead
 and update all of the columns regardless with the new values, regardless
 they are actually different or not.

 Thanks in advance,
 -Peter




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 [EMAIL PROTECTED]
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